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Parametric Curves

Mathematics 54–Elementary Analysis 2

Institute of Mathematics University of the Philippines-Diliman

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What are parametric equations?

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What are parametric equations?

The curve cannot be expressed as the graph of an equation of the form y=f(x).

Sometimes, it’simpossibleto find an equation relating thexand ycoordinates of the particle.

But we canexpressthexand theycomponent of the particle’s position as functions of timet, i.e.

x = x(t)

y = y(t)

In this process, we say that we areparametrizingthe curve above.

The equations definingxandyas functions oftare calledparametric

equations, andtis called aparameter.

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Parametric Curves

Example

Sketch the curve defined byC :x=t,y=t2, wheret∈R.

t (x,y)

−2 (2, 4) −1 (1, 1) 0 (0, 0) 1 (1, 1) 2 (2, 4) 3 → (3, 9)

Indeed, if we relatexandydirectly by eliminatingt, we havey=x2.

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Parametric Curves

Example

Sketch the curve defined byx=costandy=sint, where 0ÉtÉ2π.

t (x,y)

0 → (1, 0)

π

4 → (

p 2 2,

p 2 2 ) π

2 → (0, 1)

π → (−1, 0)

3π

2 → (0,−1)

2π (1, 0)

Indeed, if we relatexandydirectly, eliminatingt, we havex2+y2=1. The direction of trace is known as thedirection of increasing parameter. In this case, it’s counterclockwise.

The point corresponding tot=0 is theinitial point. The point corresponding tot=2πis theterminal point.

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Parametric Curves

Remark

The functiony=f(x) can be parametrized as

½

x = t

y = f(t)

Example

Parametrize the line connecting the points (0, 1) and (3, 7).

Using the two-point form of a line,

y1=7−1

3−0(x−0) ⇔ y=2x+1

Hence, we can parametrize the line as

½

x = t

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Examples

Parametrization of circles...

x = sint

y = cost

tÉ2π

’clockwise’ circle

x = 2 cost

y = 2 sint

tÉ2π

’counterclockwise’ circle of radius 2 units

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Examples

x = h+rcost

y = k+rsint

tÉ2π

circle of radiusrcentered at (h,k)

x = cos 2t

y = sin 2t

tÉπ

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Interesting Examples

x = sin 2t

y = sin 3t

Lissajous curves

x = cost+0.5 cos 7t+

µ1

3

sin 17t

y = sint+0.5 sin 7t+

µ1

3

cos 17t

0ÉtÉ2π

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Examples

Consider the curve defined by

x=sect

y=tant

π 2 <t<

π 2.

Note that

x2=sec2t

y2=tan2t Thus,

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Exercises

1 Describe the curve given by the parametric equationsx=2 costand

y=3 sint.

2 GivenA(2, 0) andB(1, 1). Give a parametrization for 1 the line containgAandB.

2 the line segment connectingAandB.

3 What can be said about the parametric equationsx=cost,y= −sint

andx=cos 2t,y= −sin 2t?

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Slope of Parametric Curves

Smooth Curve

A parametric curveC:x=f(t),y=g(t) is said to besmoothiff andgare differentiable and no value oftsatisfiesf0(t)=g0(t)=0.

IfCis a smooth curve, then its slopedydxis given by

dy dx=

dy dt dx dt

Also, the concavityd2y

dx2 is given by

d2y dx2=

d³dydx´

dt dx dt

6=y

00(t)

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Tangent Lines to Parametric Curves

Example

Find the equation of the tangent line to the right branch of the hyperbola x=sect,y=tant, where−π2<t<π2, at the point (p2, 1).

Solution: Note that the point (p2, 1) corresponds tot=π4. Thus,

dy dx=

dy/dt dx/dt=

sec2t

secttant=csct

dy dx

¯ ¯ ¯

(p2,1)=csct ¯ ¯ ¯

t=π/4=

p 2

Hence, the equation is

y1=p2³xp2´

y=p2x−1

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Concavity

Example

Findddx2y2 ifx=tt2,y=tt3.

Solution: dy dx=

1−3t2 12t Thus,

d2y dx2 =

d³1−3t2

1−2t ´

dt dx dt

=

(1−2t)(−6t)−(1−3t2)(−2) (1−2t)2

12t

= 6t

2

−6t+2 (1−2t)3

t<12 t>12

Caution

d2y dt2

d2x=

−6t −2 =3t6=

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Length of a Parametric Curve

Length of Arc

LetC:x=x(t),y=y(t),aÉtÉb, be a smooth curve traced exactly once. Then the length ofCis given by

L= Zb a s µdx dt ¶2 + µdy dt ¶2 dt

Proof.The length of arc of the smooth curvey=F(x), fromt=atot=b, is given by L= Z b a s 1+ µdy dx ¶2 dx.

Using differentials, we transform the integrand such that

s 1+ µdy dx ¶2 dx= v u u u

t1+

Ãdy dt dx dt !2 dx dt·dt=

s µdx dt ¶2 + µdy dt ¶2 dt.

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Arc Length

Example

Find the length of theastroid

x=cos3t

y=sin3ttÉ2π

L = 8

Zπ/4 0

q

(3 cos2tsint)2+(3 sin2tcost)2dt

= 8

Zπ/4 0

3 costsint dt

= 12

Z π/4 0

sin 2t dt

= −6 cos 2t¯¯ ¯

π/4 0

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Arc Length

Example

Set-up the necessary definite integral that will solve the following.

1 Perimeter of the circlex=4 cost,y=4 sint. 2 Perimeter of the ellipsex=2+9 cost,y=14 sint. 3 Arclength of the curvex=4et,y=5t2, witht[1, 3].

Solution:

1

Z 2π 0

p

(−4 sint)2+(4 cost)2dt

2

Z 2π 0

p

(−9 sint)2+(4 cost)2dt

3

Z 3 1

p

16e2t+4t2dt

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Exercises

1 Find the slope of the curve with parametric equations

x= 1 t2,y=t

35tat the point (1,4).

2 Find the concavity of the curvex=t24t,y=5t3+t3 whent=2.

3 Set-up the necessary definite integral that will solve the following. 1 Perimeter of the hypocycloid

 

x = 2 cost−3 cos

³

2t 3

´

y = 2 sint+3 sin

³

2t 3

´

witht∈[0, 2π].

References

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