Integral estimates for the spectral shift function
A. B. Pushnitski
Abstract
The spectral shift function() is considered for the pair of operatorsH0,H0+V, where H0 is the Schrodinger operator with a variable Riemannian metric and an electro-magnetic eld, andV is the operator of multiplication by the potentialV(x).
For integrals of the typeR ()f()d, wheref() is a weight, the estimates in terms of the integral characteristics of the potentialV are obtained. These estimates are of an asymptotically \correct" order inand V; they will be used in a subsequent paper in the problem of asymptotics of () in the large coupling constant limit.
0 Introduction
0.1
Let H0 and H be selfadjoint operators in a Hilbert space H and let their dierence, V, be a trace-class operator:V :=H?H0 2
S
1(H): (0.1)Then the Lifshits|Krein trace formula holds [21, 19]:
Tr((H)?(H0)) =Z 1
?1
(;H;H0)0()d: (0.2) Here is any function of some class and (;H;H0) is the spectral shift function (SSF) for the pair H0,H, which is given by the Krein formula
(;H;H0) = 1"lim!+0argdet(I+V(H0?(+i")I)?1); a. e. 2
R
: (0.3)The branch of the argument in (0.3) is xed by the condition argdet(I+V(H0?zI)?1)! 0, Imz !+1. A historical review and description of the modern state of the SSF theory can be found in [8, 36]. Among the most important facts of the SSF theory are (see [19]) the Krein inequality Z
1
?1
j(;H;H0)jdkVkS1 (0.4)
submitted to Algebra i Analiz (St.Petersburg Math. J.)
1
and the monotonicity of the SSF:
V 0 ) (;H;H0)0: (0.5) It follows from (0.5) that
(;H0?V?;H0)(;H0+V;H0)(;H0+V+;H0); (0.6) where 2V=jVjV.
0.2
In applications, instead of (0.1), it is usually possible to check the inclusion h(H)?h(H0)2S
1(H); (0.7)where h :
R
!R
is a smooth enough monotonic function. In this case, the SSF for the pair H0,H is dened by the natural formula(;H;H0) := signh0(h();h(H);h(H0)): (0.8) The trace formula (0.2) is, of course, still valid; only the class of admissible functions has to be changed. The relation (0.5) sometimes can be also justied. But this problem is far from being trivial if the SSF is dened via (0.8). In [18] (see also [36, x8.10]), (0.5) has been proved for
h() = (?0)?k; k >0; 0 <inf((H0)[(H)) (0.9) for allk, 0 specied. This is sucient for most applications.
0.3
LetH0 =?4 inL2(
R
d); d1; V =V(x); H =H0+V: (0.10) If the potentialV decays at innity rapidly enough, then the inclusion (0.7) can be veried for the function h of the type (0.9). This enables one to dene the SSF via (0.8); the relations (0.5), (0.6) are valid in this case due to the results of [18].In [35], estimates for the SSF for the pairH0,H of the form (0.10) were studied. The potentialV was subjected to the condition
jV(x)j(1 +jxj)?; > d:
The following estimate (see [35, theorem 4.2]) was obtained:
(;H0+V;H0)C((d=2)+(d=2)?1(jlogj+ 1)); 8 > 0;c; (0.11) for V 0 it can be improved up to
(;H0+V;H0)C(d=2)?1(jlogj+ 1); 8 >0; c: (0.12) Here C, c are some positive numbers which do not depend on the spectral parameter and the coupling constant, but may depend onV (this dependence has not been studied in [35]).
2
Besides the estimates (0.11), (0.12), there are many results concerning the asymptotics of (;H0+V;H0) for !1 and xed (high energy asymptotics | here the initial results were obtained in [9]) and for ! 1 and ! 1 and xed = (semiclassical asymptotics) | see, e.g., [30] and references therein.
0.4
The above mentioned results on the pointwise estimates and asymptotics for the SSF of the pair (0.10) are based on the fact that the spectrum of H0 is absolutely con- tinuous and V is smooth with respect to H0 in some sense. In this paper we follow a dierent approach and consider the SSF entirely in the the framework of the trace class perturbation theory. Starting from the Krein inequality (0.4), we obtain integral estimates for the SSF. As an example, we present the weighted estimates for the SSF of the pair (0.10) for d3 (see Theorem 6.4(ii), Corollary 6.8(ii) below and (0.6)):Z
1
0
j(;H0+V;H0)jf()dC1Z 1
0
f()dZ V?d=2(x)dx+ +C2Z 1
0
(d=2)?1f()dZ jV(x)jdx; (0.13) if V 0, then, obviously, the rst term in the right hand side vanishes and we obtain
Z
1
0
(;H0+V;H0)f()dC2Z 1
0
(d=2)?1f()dZ V(x)dx: (0.14) Here f = f() is any nonnegative monotone decreasing function and C1, C2 are the constants which do not depend on , V, f. The precise statements are given in x6.2{6.3.
Obviously, the pointwise estimates (0.11), (0.12) are stronger than the integral ones (0.13), (0.14) (up to constants and a logarithmic factor). But our method of deriving the estimates is not \sensible" to the quality of the spectrum ofH0. This allows us to consider a wide class ofH0's (Schrodinger operators with a variable metric and an electromagnetic eld | seex5.2 below) and to avoid imposing too restrictive conditions onV. Besides, the estimates (0.13), (0.14), in contrast to (0.11), (0.12), explicitly indicate the dependence onV. We also obtain some analogues of (0.13), (0.14) forH0 = (?4)l in L2(
R
d), d1;here l is not necessarily an integer.
Note that in [12], for the quantities R0(t;H0 + V;H0)dt and R01e?t(;H0 + V;H0)d, related to the pair (0.10) for d = 3, the questions of concavity and subad- ditivity with respect toV were studied.
0.5
The present paper is mostly aimed at the applications to the problem of asymp- totics of the SSF in the large coupling constant limit (the asymptotics itself will be considered in the subsequent paper). To a large extent, this has determined the style of the paper. Let V 0; then for < inf(H0) the SSF (;H0?V;H0) equals minus the quantity N+(;H0;pV ;), which is the number of eigenvalues of H0?V, located on the left from the point on the real axis (see, e. g., [8]). The question of asymp- totics of N+(;H0;pV ;) as ! 1 is well studied in applications | see, e. g., [7]and references therein. In particular, a description of a class of perturbations V (regular perturbations), such that the leading term of the asymptotics does not depend on , is
3
known. For this reason, in order to study the SSF in the large coupling constant limit for regular perturbationsV 0, it is natural to consider the quantity
(;H0?V;H0) +N+(?;H0;pV ;); (0.15) for some xed ? <inf(H0). The initial estimates for (;H0?V;H0) are formulated in terms of this quantity (see Theorems 6.6, 6.9 below). From this follow inequalities of the form (0.13) (see Corollary 6.8).
0.6
In order to obtain estimates for the SSF, one can, due to (0.6), consider the case of perturbations of a denite sign. Here we use the following approach. Let a nonnegative operator V be factored as V = GG. In [25], the following new representation for the SSF was obtained (see Propositions 2.6, 2.7 below):(;H0V;H0) =N(;H0;G): (0.16) Here N(;H0;G) is an integral (see (2.4)) of a counting function of eigenvalues of a family of compact operators, related to G and to the resolvent of H0. The relation (0.16) is of an abstract character. In applications, it appears that the existence ofN can be established under somewhat more general and natural conditions than the existence of the SSF (see x6.1). For this reason, we consider the quantities N as a basic object and dene them independently of SSF. To analize N, we use a mixed approach: both straightforward analysis of the integral representation for N and the equality (0.16) together with the estimate (0.4) for \intermediate" objects are employed. This yields integral estimates for N(;H0;G). The corresponding inequalities for the SSF are ob- tained by using Propositions 2.6 and 2.7, which give sucient conditions for the validity of (0.16).
0.7
The paper is organized as follows. In x1 the necessary notation and denitions are introduced. In x2, the quantities N(;H0;G) are dened and their basic properties and connections with the SSF and the \counting function"N(;H0;G;) are discussed.The estimates for N are obtained in x3 and for the quantity (0.15) | in x4. The results of xx2{4 are of an abstract character. In x5, the Schrodinger and polyharmonic operators (which, in applications, play the part of H0) are introduced and some relevant statements on this operators are presented. Finally, in x6, on the basis of the results of
x3{4 the integral estimates forN(;H0;pV) are derived, whereH0 is the Schrodinger or polyharmonic operator andV is the operator of multiplication by the potentialV(x)0.
0.8 Acknowledgments
The author is deeply grateful to his scientic advisor M. Sh. Birman, who introduced him into the SSF theory, for many valuable discussions and remarks. The author is grateful to V. S. Buslaev, who attracted his attention to the question of integral estimates for the SSF. The author is grateful to A. Laptev and G. Rozenblioum for consultations and to N. D. Filonov for useful remarks on the text of the paper. Finally, the author expresses his gratitude to the Department of Mathemat- ics of the Royal Institute of Technology, Stockholm, for the hospitality and to the ISF foundation for the nancial support.4
1 Notation and preliminaries
1.1 Notation
1) Integral without the domain of integration explicitly indicated implies integration over
R
d. We denote !d := volfx2R
d jjxj1g. Statements with double indices (and) should be considered as a pair of statements, in one of which all the indices take the upper values, and in another | the lower ones. In the statements which involve upper estimates we suppose all the quantities (norms and integrals) in the right hand side to be nite. A constant which appears for the rst time in formula (i:j) is denoted by Ci:j.
2) Functions. The spaces Lp(
R
d), Lp;loc(R
d) are dened in a usual way. The space l1(Z
d;L2(Q
d)) consists of functions u2L2(R
d) such that the functionalkukl1(L2) := X
j2Zd
Z
Q d
+jjuj2dx1=2;
Q
d = (0;1)dR
d;is nite. For a real-valued functionF we put 2F :=jFjF. The characteristic function of a set M is denoted by M.
3) Operators. Below H, H1, H2 are separable Hilbert spaces. By DomA, RanA and KerA we denote the domain, range and kernel of a linear operator A; jAj:=pAA;I is the identity operator. For a selfadjoint operator A the symbols (A), (A) =
C
n(A) and EA() denote respectively spectrum, resolvent set and a spectral measure of a Borel setR
; 2A := jAj A. Resolvent of a selfadjoint operator H0 is denoted by R0(z) = (H0?zI)?1.By
S
1(H1;H2) we denote the space of compact operators acting from H1 into H2;S
1(H) :=S
1(H;H). For T = T 2S
1(H) and s > 0 we denote n(s;T) :=dimRanET(s;+1), and for T 2
S
1(H1;H2) we put n(s;T) := n+(s2;TT). For com- pact selfadjoint operators T1,T2 the following estimates hold (see, e.g., [3]):n(s1+s2;T1+T2)n(s1;T1) +n(s2;T2); s1;s2 >0; (1.1) which can be written as
n(s1;T1+T2)n(s1+s2;T1)?n(s2;T2); s1;s2>0: (1.2) For 1p <1 the Neumann-Schatten class
S
p(H1;H2)S
1(H1;H2) is dened as a set of operators V such that the normkTkSp :=pZ 1
0
sp?1n(s;T)ds1=p
is nite. In particular,
S
1 is the trace class,S
2 is the Hilbert{Schmidt class.1.2 Auxiliary facts of the perturbation theory
LetHbe a \basic" andK| an \auxiliary" Hibert space, H0 be a selfadjoint operator in H and G be a linear operator acting from H intoK. Assume that
G is closed; DomGDomjH0j1=2; G(jH0j+I)?1=2 2
S
1(H;K): (1.3)5
Forz 2(H0) dene the operator
T(z;H0;G) := (G(jH0j+I)?1=2)(jH0j+I)R0(z)(G(jH0j+I)?1=2); (1.4) which is compact in K. We shall write T(z) instead ofT(z;H0;G) if the choice of H0, G is clear from the context. On the dense inKset DomG the operatorT(z) can be dened by the expression
T(z) =GR0(z)G ; 2DomG: (1.5) It is easy to check that for all z 2
C
nR
the operator I T(z;H0;G) has a bounded inverse. LetV :=GG. Below we introduce the operator which corresponds to the formal sum H0V. For some z 2C
nR
dene a bounded operator R(z) inH byR(z) =R0(z)(GR0(z))(IT(z;H0;G))?1(GR0(z)): (1.6)
Proposition 1.1
(see [14] or [36]) The operator R(z) coincides with the resolvent of a selfadjoint in H operator H =H(H0;G) taken at the point z. This operator does not depend onz. For allz 2(H0)\(H) the operatorIT(z;H0;G) has a bounded inverse and the equality (1.6) holds true for R(z) = (H?zI)?1. If H0 is semibounded from below, thenH coincides with the sumH0V in the form sense. IfV isH0-bounded with the relative bound <1, then H =H0V in the sense of the Kato-Rellich theorem.It follows from (1.6) and (1.3) that the dierenceR(z)?R0(z) is compact; thus, the essential spectra ofHandH0coincide. It is easy to check thatH(H0;G) =H(H0;jGj).
Proposition 1.2
[17, Lemma 1] Let the conditions (1.3) hold true. Then, for every2(H0)\
R
,dimKer(H(H0;G)?I) = dimKer(T(;H0;G)I): (1.7) Proposition 1.2, in particular, implies that the eigenvalues of H(H0;pG), > 0, are monotonic functions of . For 2 (H0) \
R
and > 0 the \counting func- tion" N(;H0;G;) is dened as the number of eigenvalues (counting multiplicities) of H(H0;ptG), which cross the point as t grows monotonically in the interval (0;).From Proposition 1.2 follows the equality which is known as the Birman-Schwinger prin- ciple:
N(;H0;G;) =n(?1;T(;H0;G)); 2(H0)\
R
: (1.8)In this paper, the scope of applications is restricted to the semibounded from below operators H0 (Schrodinger and polyharmonic operator). In this case, H is dened as a form sum, which simplies the arguments. However, in the abstract part of the paper we do not suppose H0 to be semibounded from below (with the exception of x4, where it is dictated by the nature of the question).
Note that the condition of closedness ofGis introduced only for the sake of simplicity.
The contents of the present section, as well as that of x2{4, can be reformulated for the case of non-closable G's. It is only important that that the second and the third of the conditions (1.3) hold true.
6
2 The functions
N2.1 Denition of the functions
NIn this and the next two sections H is a \basic" and K | an \auxiliary" Hilbert space,H0 is a selfadjoint operator inH and G| the operator acting fromH into Kand satisfying conditions (1.3). Forz 2(H0) dene compact inK operatorsT(z;H0;G) (see (1.4)) and put
A(z;H0;G) := ReT(z;H0;G); K(z;H0;G) := ImT(z;H0;G): (2.1) We shall write A(z), K(z) instead of A(z;H0;G), K(z;H0;G) if the choice of H0, G is clear from the context. Suppose that for some 2
R
for a pair of operators H0, G the following condition holds.Condition 2.1
The limit"lim!+0T(+i";H0;G) =: T(+i0;H0;G); (2.2) exists in the operator norm and
K(+i0;H0;G)2
S
1(K): (2.3)Then dene
N
(;H0;G) := 1
Z
1
?1
1 +dtt2n(1;A(+i0) +tK(+i0)): (2.4) It is easy to see that under the condition (2.3) the integral (2.4) converges.
Lemma 2.2
Fix an open intervalR
and a number 2 and put G :=GEH0().Then Condition 2.1 at the point is satised (or not satised) for the pairs H0, G and H0, G simultaneously.
Proof
Denote ~G :=GEH0(R
n). Obviously, for every z 2(H0):T(z;H0;G) = T(z;H0;G) +T(z;H0;G~):
It is clear that the limit T( + i0;H0;G~) exists in the operator norm and K( + i0;H0;G~) = 0. From here follows the assertion of the lemma. 2
Lemma 2.3
For any 2R
Condition 2.1 is satised (or not satised) for the pairs H0, G and H0, jGj simultaneously andN
(;H0;G) =N(;H0;jGj): (2.5)
Proof
Let G = jGj be a polar decomposition of G; acts unitarily from RanjGj into RanG. It is easy to see thatT(z;H0;jGj) =T(z;H0;G); 8z 2(H0): 7
From here follows the rst assertion of the lemma and the equality
n(1;A(+i0;H0;G)+tK(+i0;H0;G)) =n(1;A(+i0;H0;jGj)+tK(+i0;H0;jGj)): Integrating the last equality over t with the weight ?1(1 +t2)?1, we arrive at (2.5). 2
Lemma 2.4
Let V1, V2 be selfadjoint operators in H such that 0 V1 V2 and suppose that for some 2R
Condition 2.1 holds for the pair H0, V21=2. Then it also holds for the pair H0, V11=2 andN
(;H0;V11=2)N(;H0;V21=2):
Proof
Write V1 = (BV21=2)BV21=2, where kBk1. ThenT(z;H0;V11=2) =BT(z;H0;V21=2)B; 8z 2(H0):
From here it follows that Condition 2.1 is satised for the pair H0,V11=2 and n(1;A(+i0;H0;V11=2) +tK(+i0;H0;V11=2))n(1;A(+i0;H0;V21=2) +
+tK(+i0;H0;V21=2)):
Integrating the last inequality over t with the weight ?1(1 +t2)?1, we get the desired result. 2
2.2 Connection between
Nand the \counting function"
NLet2(H0)\
R
. Comparing (1.8) and (2.4) and observing thatK(+i0;H0;G) = 0 and A(+i0;H0;G) = T(+i0;H0;G), we arrive at the followingProposition 2.5
For 2(H0)\R
N
(;H0;G) =N(;H0;G;1): (2.6)
2.3 Connection between
Nand the SSF
Here we formulate some results of [25] which will be used below.
1) Trace class perturbations.
Let H0 be a selfadjoint operator in H and G 2S
2(H;K). It is well-known that under these conditions for a.e. 2R
the limits (2.2) exist in the Hilbert-Schmidt norm and the inclusion (2.3) holds (see [2] or [36]).Proposition 2.6
[25] Let H0 be a selfadjoint operator in H and G2S
2(H;K); then(;H0GG;H0) =N(;H0;G); a. e. 2
R
: (2.7)2) Relatively trace class perturbations.
LetH0be a selfadjoint inHsemibounded from below operator:H0 =H0 in H; ?1<inf(H0): (2.8) Let the operatorG:H!K satisfy the conditions (1.3) and for some m >0
GRm0 ()2
S
2(H;K); <inf(H0): (2.9)8
Then for a. e. 2
R
Condition 2.1 holds for the pair H0, G (see, e. g., Corollary 3.8 below). Let H = H(H0;G) (see Proposition 1.1). In order to dene the SSF for the pair H0,H, assume that for some k >0 and 0 <inf((H0)[(H)) the inclusion(H?0I)?k?(H0?0I)?k 2
S
1(H) (2:10)holds. The inclusion (2.10) enables one to dene the SSF via (0.8) for h() = (?0)?k.
Proposition 2.7
[25] Let the conditions (1.3), (2.8){(2.10) hold true. Then(;H;H0) =N(;H0;G); a. e. 2
R
: (2.11)Finally, we need two sucient conditions for the inclusion (2.10).
Proposition 2.8
(i) Assume the conditions (1.3) and (2.9) for m = 1. Then, for all0 2(H0)\(H) and k= 1 the inclusion (2.10) holds.
(ii) Assume the conditions (1.3), (2.8) and for some m > 0 let
(GR01=2())(GRm0 ())2
S
1(H); <inf(H0): (2.12) Then for all integersk > m+12 and all large enough0 <inf((H0)[(H)) the inclusion (2.10) holds.(i) follows directly from the denition (1.6). (ii) has been proved in [28, Theorem XI.12].
3 Estimates for
NIn this section H0 is a selfadjoint operator in H and G is an operator which acts fromH into Kand satises the conditions (1.3).
3.1 Monotonicity estimates
For 2
R
letE() :=EH0(?1;); G?() :=GE(); G+() :=GEH0(;+1): (3.1)
Lemma 3.1
Let numbers , be such that (?)> 0. Then Condition 2.1 is satised (or not satised) for the pairs H0, G() and H0, G simultaneously and the following estimate holds:N
(;H0;G)N(;H0;G()): (3:2)
Proof
The rst assertion follows from Lemma 2.2. To be denite, let us prove (3:2?). It is easy to see thatA(+i0;H0;G)A(+i0;H0;G?(?)); K(+i0;H0;G) =K(+i0;H0;G?(?)): This gives (3:2?). 2
9
Corollary 3.2
For any 2R
the following estimate1 holds:Z
(t?)0N(t;H0;G)dtkG()k2S2: (3:3)
Proof
Using Lemma 3.1, Proposition 2.6 and inequality (0.4), we obtain the esti- mates:Z
(t?)0N(t;H0;G)dtZ
(t?)0N(t;H0;G())dt
=Z
(t?)0j(t;H0G()G();H0)jdtZ 1
?1
j(t;H0G()G();H0)jdt
kG()G()kS1 =kG()k2S2: 2
Lemma 3.3
Let the function f :R
![0;1) be such that f is nondecreasing. Then the following inequality holds:Z
1
?1 N
(;H0;G)f()dkGqf(H0)k2S2: (3:4)
Proof
To be denite, let us consider the case of the lower signs. First assume that f()!0 as !+1. Denotemax := sup suppf +1 (3.5)
Since Gqf(H0)2
S
2, one has G?()2S
2 for < max. Fix some numbers R1, R2 such that R1 < R2 < max (from what follows it is easy to see that for a bounded f, one can take R1 =?1). For 2 (R1;R2) put S() :=RR1N?(t;H0;G)dt (here the integral converges due to the inclusion G?() 2S
2 and the inequality (3:3?)). Integrating by parts, we get:Z R2
R1 N?(;H0;G)(f()?f(R2))d=ZRR2
1
(f()?f(R2))dS()
=?ZRR2
1
S()df()?ZRR2
1
kG?()k2S2df(); (3.6) where on the last step we have used the inequality (3:3?). Next, integrating by parts again, we nd:
? Z R2
R1 kG?()k2S2df() =?Tr(G?(R2)ZRR2
1
E()d(f()?f(R2))G?(R2))
= Tr(G?(R2)(f(R1)?f(R2))E(R1)G?(R2) +Tr(G?(R2)(f(H0)?f(R2)I)EH0(R1;R2)G?(R2))Tr(G?(R2)f(H0)E(R1)G?(R2))
+Tr(G?(R2)f(H0)G?(R2))kGqf(H0)E(R1)k2S2 +kGqf(H0)k2S2: (3.7)
1We remind that in the estimates from above all the quantities in the right hand side are supposed to be nite.
10
Combining (3.6) and (3.7), we see that
Z R2
R1 N?(;H0;G)(f()?f(R2))d kGqf(H0)k2S2 +kGqf(H0)E(R1)k2S2: TakingR1 !?1 and R2 !max in the last inequality, we arrive at (3:4?).
Now suppose lim!+1f() =: f(1) 6= 0. Then Gqf(H0) 2
S
2 implies G 2S
2.Hence, by Proposition 2.6 and inequality (0.4),
Z
1
?1 N
?(;H0;G)d kGGkS1 =kGk2S2: (3.8) Next, from the rst part of the proof it follows that
Z
1
?1 N
?(;H0;G)(f()?f(1))dkGqf(H0)?f(1)Ik2S2
= Tr(G(f(H0)?f(1)I)G) =kGqf(H0)k2S2 ?f(1)kGk2S2: Combining the last inequality with (3.8), we arrive at (3:4?). 2
The following result of [4] is very close to Lemma 3.3.
Proposition 3.4
Let H0 = H0 in H, V = V 2S
1(H) and H = H0 + V. Let f(), 2R
be a continuous2 nonnegative nonincreasing function. Then the following inequalities are valid:Tr(f(H)V)Z 1
?1
(;H;H0)f()dTr(f(H0)V):
It is easy to see that for trace-class perturbations of a denite sign and bounded functions f Proposition 3.4 and Lemma 3.3 are equivalent.
In some important special case the estimates of the type (3:4?) for the SSF can be proved straightforwardly, without usingN?.
Proposition 3.5
Let H0 0 be a selfadjoint operator in H, G satisfy the condition (1.3) and GR0(?1) 2S
2(H;K). Put H+ =H+(H0;G). Then for k = 1 and any 0 < 0 the inclusion (2:10+) holds; thus, the SSF for the pair H0, H+ is correctly dened. The following estimate holds:Z
1
?1
(?0)?2(;H+;H0)dkGR0(0)kS22 ; 80 <0: (3.9)
Proof
The inclusion (2:10+) (for k= 1) follows from (1.6). The SSF (;H+;H0) is dened on the basis of (2:10+) via (0.8) (withH =H+ andh() = (?0)?1). Applying (0.4) and taking into account the fact that T(0;H0;G)0, we ndZ
1
?1
(?0)?2(;H+;H0)dk(H+?0I)?1?(H0?0I)?1kS1
=k(GR0(0))(I+T(0;H0;G))?1(GR0(0))kS1 kGR0(0)k2S2: 2
2It is easy to see that the condition of continuity off can be dropped
11
3.2 Partition of spectrum
Let the Borel sets 1;2
R
, be such that (H0) 1[2. Introduce the notations Gj =GEH0(j), j = 1;2.Lemma 3.6
Let for some 2R
Condition 2.1 be satised for the pair of operators H0, Gj, j = 1;2. Then it is satised for the pair H0, G and the following estimates hold:N
(;H0;G)N(;H0;(1?)?1=2G1) +N(;H0;?1=2G2); 8 2(0;1); (3:10)
N
(;H0;G)N(;H0;(1 +)?1=2G1)?N(;H0;?1=2G2); 8 > 0: (3:11)
Proof
1. First suppose 1\2 =;. Clearly, for all z 2(H0), T(z;H0;G) =T(z;H0;G1) +T(z;H0;G2); A(z;H0;G) =A(z;H0;G1) +A(z;H0;G2);K(z;H0;G) =K(z;H0;G1) +K(z;H0;G2): (3.12) From here follows the rst assertion of the lemma. Using (3.12) and (1.1), we obtain
n(1;A(+i0;H0;G) +tK(+i0;H0;G))n(;A(+i0;H0;G1) +tK(+i0;H0;G1)) +n(1?;A(+i0;H0;G2) +tK(+i0;H0;G2)): Integrating the last inequality with respect to t with the weight ?1(1 +t2)?1, we arrive at (3.10). Similarly (using (1.2) instead of (1.1)) one proves (3.11).
2. The general case (1 \2 6= ;) can be reduced to the one considered above by using Lemma 2.4. Indeed, writing the estimate (3.10) for the pair of sets 1, 2 n1 and observing that 0 (GEH0(2n1))(GEH0(2 n1))(GEH0(2))(GEH0(2)), we nd
N
(;H0;G)N(;H0;(1?)?1=2G1) +N(;H0;?1=2GEH0(2 n1))
N
(;H0;(1?)?1=2G1) +N(;H0;?1=2G2): Similarly,
N
(;H0;G)N(;H0;(1 +)?1=2G1)?N(;H0;?1=2GEH0(2 n1))
N
(;H0;(1 +)?1=2G1)?N(;H0;?1=2G2): 2
Remark 3.7
Let us sketch another possible proof of Lemma 3.6, which claries the role of the fact that the perturbation has a denite sign. As above, suppose that1\2 =;. In order to prove (3.10), we rst observe that, as it is easy to check, for any 2(0;1)V =GG(1?)?1G1G1+?1G2G2 = ~GG;~
where the operator ~G = (1? )?1=2G1 ?1=2G2 acts from H into KK. Here the condition V 0 is essential. Next, use Lemma 2.4 (for V1 =V, V2 = ~GG~) and Lemma 2.3:
N
(;H0;G)N(;H0;( ~GG~)1=2) =N(;H0;G~)
=N(;H0;(1?)?1=2G1) +N(;H0;?1=2G2): 12
The proof of (3.11) is similar. Note also that Lemma 3.6 can be reformulated for the case of partition of the spectrum into an arbitrary nite number of sets j.
Corollary 3.8
Suppose that for some open intervalR
the following inclusion holds:GEH0()2
S
2(H;K): (3.13) Then for a. e. 2 for the pair H0, G Condition 2.1 holds andN
(;H0;G)2L1;loc(): (3.14) In particular, if (3.13) holds for any bounded interval
R
, thenN
(;H0;G)2L1;loc(
R
):Proof
To be denite, consider the case of upper signs. In (3:10+) take = 1=2, 1 =,2 =
R
n. Due to (3.13), Proposition 2.6 and the inequality (0.4), one hasN
+(;H0;p2G1) =?(;H0?2G1G1;H0)2L1(
R
):At the same time, it is easy to see that T( + i0;H0;G2) is selfadjoint and
N
+(;H0;p2G2) = n+(1;2T(+i0;H0;G2)) is a nonincreasing
Z
+{valued function of2 , possibly with a singularity at sup. From here it follows that N+(;H0;p2G2)2 L1;loc(), and we arrive at (3.14). 2
Note that the statement, analogous to Corollary 3.8, is false for the SSF. Namely, one can construct such operators H0, G and an interval , that the hypothesis of Corollary 3.8 holds true, but for some 2 C01() the dierence (H)?(H0) 62
S
1. Thus, the SSF for the pair H, H0 cannot be dened on the interval in any reasonable sense.4 Estimates for
N+ ? N+The contents of this section is aimed at the applications to the asymptotics of SSF in the large coupling constant limit. Operator H0 is supposed to be nonnegative; we are interested in N+(;H0;G). For < inf(H0) the question of asymptotics of
N
+(;H0;ptG) = N+(;H0;G;t) as t ! 1 is well studied in applications. For this reason, we estimate the dierence
Q(;?;) :=N+(;H0;G)?N+(?;H0;G;);
where ?<inf(H0) is xed and >0 is some auxiliary parameter. We dene Q(;?;) := (Q(;?;)):
We also use the notations (3.1) and set ~E() =I?E().
4.1 Local estimates
13