ISSN Online: 2327-4379 ISSN Print: 2327-4352
DOI: 10.4236/jamp.2018.612217 Dec. 26, 2018 2600 Journal of Applied Mathematics and Physics
The Existence and Uniqueness of Positive
Solutions for a Singular Nonlinear Three-Point
Boundary Value Problems
Yao Dong, Baoqiang Yan
*School of Mathematical Sciences, Shandong Normal University, Jinan, China
Abstract
Using the method of lower and upper solutions, we study the following sin-gular nonlinear three-point boundary value problems:
( ) ( ) ( ) ( ), (0,1),
(0) 0, (1) ( ),
q p
x t K t x t x t t
x x ax
λ
η
−
′′− + = ∈
= =
, where K C∈ [0,1], 0< <a 1,
0< <η 1 and λ is a positive parameter and present the existence,
unique-ness, and the dependency on parameters of the positive solutions under vari-ous assumptions. Our result improves those in the previvari-ous literatures.
Keywords
Three-Point Boundary Value Problem, Positive Solution, Lower and Upper Solutions, Eigenvalue and Eigenfunction
1. Introduction and Main Results
In this paper, we consider the three-point boundary value problem
( ) ( ) ( ) ( ), (0,1),
(0) 0, (1) ( ),
q p
x t K t x t x t t
x x ax
λ
η
−
′′− + = ∈
= =
(1.1)
where K C∈ [0,1], 0< <a 1, 0< <η 1, and λ is a positive parameter.
The m-point boundary value problem for linear second-order ordinary diffe-rential equations was initiated by Ilin and Moiseev [1] [2]. Since then, there are many results on the existence of general nonlinear multi-point boundary value problems, see [3] [4] [5] [6] and their references. For examples, in [6], Rynne studied the $m$-point boundary value problem
How to cite this paper: Dong, Y. and Yan, B.Q. (2018) The Existence and Uniqueness of Positive Solutions for a Singular Nonli-near Three-Point Boundary Value Prob-lems. Journal of Applied Mathematics and Physics, 6, 2600-2620.
https://doi.org/10.4236/jamp.2018.612217
DOI: 10.4236/jamp.2018.612217 2601 Journal of Applied Mathematics and Physics 2
1
( ), (0,1), ,
(0) 0, (1) m i ( ),i
i
u f u on u R X
u u − α ηu
= ′′
− = ∈ ×
= =
∑
where m≥3, η ∈i (0,1), α >i 0 with
2
1 1
m i i
α
− =
<
∑
and presented the existenceof the sign changing solutions by Rabinowitz bifurcation theorem. Especially, Rynne ([7]) discussed the three-point boundary value problem
( ) , (0,1),
(0) 0, (1) ( ),
u f u h on u u α ηu
′′
− = +
= =
and showed the solvability and non-solvability results from either the half-eigenvalue or the Fucik spectrum approach. As we known, the method of upper and lower solutions is very important for the study of the boundary val-ue problems, see [8]-[18]. Therefore, establishing the method of upper and lower solutions for three-point boundary value problems is necessary and im-portant.
In [19], when f is nondecreasing on x, Du and Zhao got the methods of upper and lower solutions of
( ) ( , ( )), (0,1),
(0) ( ), (1) 0,
x t f t x t t x axη x
′′
− = ∈
= =
and used iterative techniques to study the existence of positive solutions. And in [3] when f is decreasing on u, Du and Zhao considered the existence and uni-queness of positive solutions of the problem
2
1
( ) ( , ( )), (0,1),
(0) m i ( ),i (1) 0
i
u t f t u t t
u − α ηu u
= ′′
− = ∈
= =
∑
by constructing lower and upper solutions. Wei ([15]) constructed the method of upper and lower solutions for three-point boundary value problems and gave the sufficient and necessary conditions for the existence of positive solutions of the problem
( ) ( , ( )), (0,1),
(0) ( ), (1) 0.
x t f t x t t x axη x
′′
− = ∈
= =
On the other hand, singular boundary problems arise in the contexts of chemical heterogeneous catalysts, non-Newtonian fluids and also the theory of heat conduction in electrically conducting materials, see [20]-[25] for a detailed discussion. An interesting result comes from [25], in which, using method of upper and lower solutions, Shi and Yao discussed the following problem
( ) , ,
( ) 0, ,
| 0,
q p
u K x u u x u x x
u
λ
−
∂Ω
−∆ + = ∈ Ω
> ∀ ∈ Ω
=
where K C∈ 2,β( )Ω , p q, ∈(0,1) and λ is a positive parameter. Under
DOI: 10.4236/jamp.2018.612217 2602 Journal of Applied Mathematics and Physics
uniqueness of classical solutions.
Motivated by above works, under various appropriate assumptions on p, q
and K t( ), we will obtain the existence and uniqueness of positive solution of problem (1.1) for λ in different circumstances. In our proof, the upper and
lower solutions theorem (see [16]) plays an important role in the paper. Define
[0,1]
*
* [0,1]
max ( ), min ( ).
t t
K K t K K t
∈ ∈
= =
The main results of this paper are stated in the following theorems.
Theorem 1.1. When K*>0,
1) If 0< p q, <1,thereexists λ >0 suchthattheproblem (1.1) hasatleast oneC[0,1]positivesolution x tλ( ) for λ λ> .
2) For λ λ> , (1.1) has amaximal solution x tλ( ) and x tλ( ) is increasing
withrespectto λ.
Theorem1.2. When K*<0,
1) If 0< p<1,0<q, (1.1) has at least one C[0,1] positive solution for all
0
λ> .
2) If 0< p q, <1, (1.1) hasanunique C1[0,1] positivesolution x t( ) λ forall
0
λ> .
3) x tλ( ) in (2) isincreasingwithrespectto λ.
Theorem1.3. When *
* 0
K < <K ,
1) If 0< p q, <1, there exists a λ >* 0 such that the problem (1.1) has at
leastoneC[0,1] posit-ivesolution x tλ( ) for λ λ> *.
2) For λ λ> *, x tλ( ) in (1) isincreasingwithrespectto λ.
Remark 1.1: Note K t( ) 0> in Theorem (1.1). This is different from the
conditions in [3] [15] [19] because K t( ) 0< in these references.
Remark 1.2: The unique result in Theorem 1.2 is different from that in [3] because we remove the monotonicity of nonlinearity f in x.
Remark 1.3: Note K t( ) is sigh-changing in Theorem 1.3. This is different from the conditions in [3] [15] [19] because K t( ) 0< in these references and is
different from conditions in [1] [2] [4] [5] [6] [7] [26] because f is continuous at 0
x= in these references.
This paper is organised as follows. Some preliminary lemmas are stated and proved in Section 2. And Section 3 is devoted to prove the results.
2. Preliminaries
In this section, we first consider the following problem ( ) ( , ( ), ( )), (0,1),
(0) 0, ( ) (1),
x t f t x t x t t x xη ax
′′ ′
− = ∈
= =
(2.1)
where η ∈(0,1), 0< <a 1 and f ∈[0,1]× × .
Let C1[0,1] { :[0,1]= x →| ( )x t is differential continuous on [0,1]} with
DOI: 10.4236/jamp.2018.612217 2603 Journal of Applied Mathematics and Physics
|| || max{| | ,| | }x = x ∞ x′∞ ,
where | | max | ( ) |[0,1] t
x′ =∞ ∈ x t . Obviously, C1[0,1] is a Banach space. Now we give the definitions of lower and upper solutions for problem (2.1).
Definition 2.1. A function α( )t is called a lower solution to the problem (2.1), if α( )t ∈C[0,1]∩C2(0,1) and satisfies
( ) ( , ( ), ( )), (0,1),
(0) 0, (1) ( ).
t f t t t t a
α α α
α α α η
′′ ′
− ≤ ∈
≤ ≤
(2.2)
Upper solution is defined by reversing the above inequality signs in problem (2.2).
If there exists a lower solution α( )t and an upper solution β( )t to problem (2.1) such that α( )t ≤β( )t , then ( ( ), ( ))α t β t is called a couple of upper and lower solutions of problem (2.1).
Set Dβ {( , ) (0,1)t x , ( )t x ( ),t t (0,1)}.
α = ∈ ×+ α ≤ ≤β ∈
We list a lemma for the eigenvalues and eigenfunctions for the following li-near problem
( ) ( ), (0,1),
(0) 0, (1) ( ).
x t x t t x x ax
λ
η
′′
− = ∈
= =
(2.3)
Lemma 2.1. (see [6]) The spectrum σ( )L of problem (2.3) consists of a
strictly increasing sequence ofeigenvalues λ >k 0, k=1, 2,, with
eigenfuc-tions sin( 12 )
k kt
φ = λ . Inaddition,
1) lim k
k→+∞λ = +∞;
2) φk( )t has exact k−1 simple zeros in (0,1), k=2,3, and φ1 is
strictlypositiveon (0,1).
Lemma 2.2. Supposethat h L∈ 1(0,1). Then, foreach λ>0, theproblem
( ) ( ), (0,1),
(0) 0, ( ) (1)
x t x h t t x x x
λ
η α
′′
− + = ∈
= =
(2.4)
hasanuniquesolutioninC[0,1].
Proof. Assume that v t1( ) and v t2( ) satisfies that
( ) ( ), (0,1),
(0) 0, (0) 1
x t x h t t x x
λ
′′
− + = ∈
= ′ =
and
( ) ( ), (0,1),
(1) 0, (1) 1
x t x h t t x x
λ
′′
− + = ∈
= ′ = −
respectively. Define
2 1
1 1
( ) ( ), 0 1,
1 ( , )
( ) ( ), 0 1,
v t v s s t G t s
v t v s t s
ω
≤ ≤ ≤
= ≤ ≤ ≤
and
1 1 1
0 0
1 1
( )
( ) ( , ) ( ) ( , ) ( ) , [0,1].
(1) ( )
e t
x t G t s h s ds G s h s ds s
e α ηe α η
= + ∈
−
∫
∫
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( ) ( )
( ) ( )
1 0
2 1 1 2
1
2 1 1 2
1 1
0
1 1
2 1 1 2
1
1 1
( ) ( ) ( ) ( ) ( ) ( ) ]''
''( ) ( , ) ( )
(1) ( )
( ) ( ,
1
''( ) ( ) [
( )
1 [ '( ) ( ) '( ) ( )] ( )
1 [ ( ) (
) (1) ( ) ] ) 0 t t t
x t x t
x t
v t v t v t v t h t t
v t v s h s ds v t v s
v t v s h s ds v t v
h s d s h s ds
e t G s h s ds
e e
e t G
e s s h e λ α ω λ ω λ λ ω η α η
λ α η
α η − + = − = − − − + − + − + − −
∫
∫
∫
∫
∫
1 02 1 1 2
1 1 0 1 0 1 1 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ] ( ) ( , ) ( ) ( ) 1 ( ) [ ( ) ( ),
(1) ( )
(0,1)
t t
s ds
v t v s h s ds v t v s h s ds
x t
h t
x t
h t
e t G s h s ds
e e
t
λ
λ ω
λ α η λ
α η + + − = − − = ∈ +
∫
∫
∫
∫
and1 1 1
0 0
1 1
1 1 1
0 0 1 1 1 1 0 1 1
1 1 1
0 0
1 1
(1)
(1) ( ) (1, ) ( ) ( , ) ( )
(1) ( )
( )
[ ( , ) ( ) ( , ) ( ) ]
(1) ( )
(1) ( , ) ( )
(1) ( )
( )
[ ( , ) ( ) ( , ) ( ) ]
(1) ( )
e
x x G s h s ds G s h s ds
e e
e
G s h s ds G s h s ds
e e
e G s h s ds
e e
e
G s h s ds G s h s ds
e e
α η α η
α η η
α η α η
α η
α η
α η
η
α η α η
α η − = + − − + − = − − + −
∫
∫
∫
∫
∫
∫
∫
0. =Hence, x t( ) is a C[0,1] solution to problem(2.4). Since λ>0, Lemma 2.1 guarantees that problem (2.4) has an unique C[0,1] solution. The proof is com-plete.
Theorem 2.1. Let
α
and β∈C([0,1])∩C1(0,1) be lower anduppersolu-tions of (2.1) such that α β≤ . Let ψ∈L1[0,1] and φ : + → +0
be a conti-nuousfunctionthatsatisfies
0
1 .
( )s ds
φ ∞
= +∞
∫
(2.5)Suppose f D: β
α× → isan L1-Carathéodory-functionsuchthat
| ( , , ) |f t x v ( ) (| |), ( , )t v t x Dβ, v .
α ψ φ
≤ ∀ ∈ ∈ (2.6)
Thentheproblem (2.1) hasatleastonesolution x C∈ 1[0,1] suchthatforall [0,1]
t∈ ,
( )t x t( ) ( ).t
α ≤ ≤β
Proof. The proof proceeds in five steps.
Step 1. We consider a new modified problem. From (2.5), there is an R>0 be large enough so that
1 0
1 || || .
( ) R
ds
s ψ
φ >
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And (2.6) guarantees that there is an N t( ) with N L∈ 1[0,1] such that
| ( , , ) |f t x v N t( ), ( , )t x Dβ, | |v R.
α
≤ ∀ ∈ ≤ (2.8)
Define then
( ), ( ),
( , ) , ( ) ( ),
( ), ( )
t if x t t x x if t x t
t if x t
α α
χ α β
β β
<
= ≤ ≤
>
(2.9)
and
( , , ) max{min{ ( , ( , ), ), ( )}, ( )}.
g t x v = f t χ t x v N t −N t (2.10) Choose a λ >0 and consider the new boundary value problem
( ) ( , ( ), ( )) ( , ( )), (0,1),
(0) 0, (1) ( ),
x t x g t x t x t t x t t x x ax
λ λχ
η
′′ ′
− + = + ∈
= =
(2.11)
where 0< <a 1, 0< <η 1.
Step 2. We discuss the existence of a C1[0,1] solution of (2.11).
Now Lemma 2.2 guarantees that for each h L∈ 1[0,1], the linear problem
( ) , (0,1),
(0) 0, (1) ( )
x t x h t x x ax
λ
η
′′
− + = ∈
= =
has an unique C[0,1] solution
1 1 1
0 0
1 1
( )
( ) ( , ) ( ) ( , ) ( ) , [0,1].
(1) ( )
e t
v t G t s h s ds a G s h s ds s
e ae η η
= + ∈
−
∫
∫
For x C∈ 1[0,1], define
( )( )Fx t =g t x t x t( , ( ), ( ))′ +λχ( , ( )),t x t t∈[0,1] and
1 1 1
0 1 1 0
( )
( )( ) ( , )( )( ) ( , )( )( ) , [0,1].
(1) ( )
η
η
= + ∈
−
∫
e t∫
Tx t G t s Fx s ds a G s Fx s ds s
e ae
From (2.9) and (2.10), we have
[0,1] [0,1]
| ( , ( ), ( )) ( , ( )) | ( ) max{sup | ( ) |, sup | ( ) |},
t t
g t x t x t
λχ
t x t N tλ
α
tβ
t∈ ∈
′ + ≤ + which
implies that the functions belonging to {( )( ) :Tx t x C∈ 1[0,1]} and 1
{( ) ( ) :Tx t x C′ ∈ [0,1]} are bounded and equicontinuous. The Arzela-Ascoli Theorem guarantees that TC1[0,1] is relatively compact. The proof of the
con-tinuity of T is standard. Using the Schauder’s fixed point theorem, we assert that
T has at least one fixed point x C∈ 1[0,1].
Step 3. The solution x of (2.11) is such that α( )t ≤x t( )≤β( )t .
We prove that x t( )≤β( )t for t∈[0,1] only. In fact, suppose that there ex-ist a t0∈[0,1) such that x t( )0 >β( )t0 . Since x(0) 0= ≤β(0), t0>0. Let
( ) ( ) ( )
w t =x t −β t , t∈[0,1]. Then w(0) 0≤ and w t( ) 00 > .
Let t∗=sup{∣t w s( ) 0,> s t t∈[ , ]}0 , t∗=inf{∣t w s( ) 0,> s t t∈[ , ]}.0
It is obvious that w t( ) 0> for all * *
( , )
t∈ t t , w t( ) 0* = and w t( ) 0* ≥ . If *
( ) 0
w t = , then there exists a *
*
( , )
t′∈ t t such that *
*
[ , ]
( ) max ( )
t t t
w t w t
∈
DOI: 10.4236/jamp.2018.612217 2606 Journal of Applied Mathematics and Physics *
( ) 0
w t > , obviously t*=1 and w(1)=x(1)−β(1 0)> . Since
1 1
( ) ( ) ( ) ( (1) (1)) (1) (1)
w x x w w
a a
η = η −β η = −β = > , there exists *
*
( , )
t′∈ t t
such that *
*
[ , ]
( ) max ( )
t t t
w t w t
∈
′ = also. Hence, w t′ ′ =( ) 0 (i.e., β ′ ′( )t =x t′ ′( )) and ( ) 0
w t′′ ′
− ≥ . On the other hand, since
( ) ( ) ( )
( , ( ), ( )) ( , ( ), ( )) ( , ( )) ( )
( , ( ), ( )) max{min{ ( , ( ), ( )), ( )}, ( )}
( ) ( )
( , ( ), ( )) ( , ( ), ( )) ( )
w t t x t
f t t t g t x t x t t x t x t f t t t f t t t N t N t
t x t
f t t t f t t t t
β
β β λχ λ
β β β β
λβ λ
β β β β λβ
′′ ′ ′′ ′ ′′ ′
− = −
′ ′ ′ ′ ′ ′ ′ ′ ′
≤ − + + −
′ ′ ′ ′ ′ ′ ′
= − + −
′ ′
+ −
′ ′ ′ ′ ′ ′ ′ ′ ′
= − + + ( )
( ( ) ( )) 0.
x t t x t
λ λ β
′ −
′ ′
= − <
This is a contradiction.
A similar argument holds to prove x t( )≤β( )t for all t∈[0,1]. Hence, from (2.10), one know that x satisfies that
( ) ( , ( ), ( )) max{min{ ( , ( ), ( )), ( )}, (0,1),
(0) 0, (1) ( ).
x t g t x t x t f t x t x t N t t
x x ax
η
′′ ′ ′
− = = ∈
= =
(2.12)
Step 4. The solution x of (2.11) is such that | |x′ ≤∞ R.
On the contrary, suppose that there is a t′∈(0,1) such that | ( ) |x t′ ′ >R. Without loss of generality, we assume that x t′ ′ >( ) R. Since x(0) 0= and
(1) ( )
x =axη with 0< <a 1, there is a t0∈(0,1) such that x t′( ) 00 = . Without
loss of generality, we assume that x t′( ) 0> for all ( , )t t′ 0 . Observe that, for all
( , )t x Dβ α
∈ , v∈,
max{min{ ( , , ), ( )},f t x v N t −N t( )}≤ψ φ( ) (| |).t v
Then, from (2.12), one has
0
0
0 0
0 0
( )
0 ( )
1
1 | 1 | | 1 ( ) |
( ) ( ) ( ( ))
( ) ( , ( ), ( ))
| | | |
( ( )) ( ( ))
( ) ( ( )) ( ) || || .
( ( ))
R x t t
x t t
t t
t t
t t
t t
ds ds dx t
s s x t
x t dt g t x t x t dt x t x t t x t dt t dt
x t
φ φ φ
φ φ
ψ φ ψ ψ
φ
′ ′
′ ′
′ ′
′ ′
′
= =
′
′′ ′
= =
′ ′
′
= = =
′
∫
∫
∫
∫
∫
∫
∫
This contradicts to (2.7).
Hence | ( , ( ), ( )) |f t x t x t′ ≤N t( ), which together with u∈[ , ]α β guarantees that
( , ( ), ( )) ( , ( ), ( )), (0,1).
g t x t x t′ = f t x t x t′ ∀ ∈t
Step 5. We claim that x t( ) satisfies (2.1).
Since | |x′ ≤∞ R and α( )t ≤x t( )≤β( )t , by (2.8), (2.10) and (2.12), we have
( ) max{min{ ( , ( ), ( )), ( )} ( , ( ), ( )), (0,1),
(0) 0, (1) ( ),
x t f t x t x t N t f t x t x t t
x x ax
η
′′ ′ ′
− = = ∈
= =
that is, x t( ) is a C1[0,1] solution of (2.1). The proof is complete.
Now we consider the following problem
( ) ( , ( )), (0,1),
(0) 0, ( ) (1),
x t f t x t t x xη ax
′′
− = ∈
= =
DOI: 10.4236/jamp.2018.612217 2607 Journal of Applied Mathematics and Physics
where η ∈(0,1), 0< <a 1 and f ∈[0,1]× × .
Now we give the definitions of lower and upper solutions for problem (2.13). Definition 2.2. (see [16]) A function α( )t is called a lower solution to the problem (2.13), if α( )t ∈C[0,1]∩C2(0,1) and satisfies
( ) ( , ( )), (0,1),
(0) 0, (1) ( ).
t f t t t a
α α
α α α η
′′
− ≤ ∈
≤ ≤
(2.14)
Upper solution is defined by reversing the above inequality signs in problem (2.14).
By Theorem 2.1, we have following result.
Corollary 2.1. Suppose that there exists a lower solution α( )t and an upper solution β( )t of problem (2.1) such that α( )t ≤β( )t , t∈[0,1] and there ex-ists F L∈ 1[0,1] such that | ( , ) |f t x ≤F t( ) for all ( , )t x Dβ
α
∈ . Then the problem
(2.13) has at least one C[0,1] solution x t( ) satisfies α( )t ≤x t( )≤β( )t ,
[0,1]
t∈ .
Remark 2.1: This result can be found in [15]. So our theorem improves the works in the previous literature.
Lemma 2.3. Suppose that f : (0,1) [0,× +∞ →) is a continuous functions such that s f t s−1 ( , ) is strictly decreasing for s>0 at each t∈(0,1). Let
2
, [0,1] (0,1)
w v C∈ ∩C satisfies:
1) w′′+ f t w( , ) 0≤ ≤ +v′′ f t v( , ), t∈(0,1);
2) w v, >0, t∈(0,1) and w(0)≥v(0), w(1)≥aw( )η , v(1)≤av( )η ;
3) v′′∈L1[0,1].
Then w t( )≥v t( ), t∈[0,1].
Proof. By v′′∈L1(0,1), we know that v′ +(0 ) and v′ −(1 ) exist and then 1[0,1]
v C∈ .
Suppose conversely v t( )≤/w t( ) on [0,1]. We may assume without loss of ge-nerality that there exists t0∈(0,1) such that v t( )0 −w t( ) max( ( )0 = 0≤ ≤t 1 v t −w t( )) 0> .
Let
* inf{ | 01 1 0, ( ) ( ), ( , )},1 0
t = t ≤ <t t v t >w t t∈ t t
*
2 0 2 0 2
sup{ | 1, ( ) ( ), ( , )}.
t = t t ≤ <t v t >w t t∈ t t
It’s obvious that *
*
0≤ < ≤t t 1 and v t( )* =w t( )* , v t′ + ≥( )* D w t+ ( )*+ , where
D+ denote Dini derivatives.
For t*≤1, there are three cases.
1) t*<1. Then v t( )* =w t( )* , v t′( )* ≤w t′( )* , v t( )>w t( ) for all * *
( , )
t∈ t t .
2) t*=1 and v t( )* =w t( )* , v t(* ) D w t(* )
−
′ − ≤ − , v t( )>w t( ) for all
* *
( , )
t∈ t t , where D− denotes Dini derivatives.
3) t*=1 and v t( )* >w t( )* , v t( )>w t( ) for all * *
( , ]
t∈ t t . Since
(1) (1) ( ( ) ( )) ( ) ( )
v −w ≤a vη −wη <vη −wη , then there is t′∈[ ,1]η such that
( ) ( ) 0, ( ( ) ( )) 0.
v t′ −w t′ > v t′ −w t′ ′<
Combining above (1), (2) and (3), there is a t′ >t* such that
* * * *
( ) ( ), ( ) ( ), ( ) ( ), ( ) ( ),
v t w t v t D w t+ v t w t v t D w t
−
′ ′ ′ ′ ′ ′
DOI: 10.4236/jamp.2018.612217 2608 Journal of Applied Mathematics and Physics
and
*
( ) ( ), ( , ).
v t >w t ∀ ∈t t t′
Let y t( )=v t w t w t v t′( ) ( )− ′( ) ( ), t∈( , )t t* ′ . Then we have
*
lim inf ( ) 0 lim sup ( ).
t t→ + y t ≥ ≥t t→ −′ y t (2.15)
On the other hand,
( ) ( ) ( ) ( ) ( )
( ) ( , ( ) ( ) ( , ( ))
( , ( )) ( , ( ))
( ) ( )( )
( ) ( )
0
y t w t v t w t v t
w t f t v t v t f t w t
f t w t f t v t
w t v t
w t v t
′ = ′′ − ′′
= − +
= −
≥
for t∈( , )t t* ′ and y t′( ) 0≡/ on ( , )α β . This implies y t( )′ > y t( )* . This
con-tradicts (2.15), so v t( )≤w t( ). The proof is complete.
By analogous methods in [19], we establish the following maximal theorem, which can be used in the proof of the uniqueness of positive solutions.
Lemma 2.4. (maximal theorem) Suppose that 0< <η 1, and
2
{ [0,1] (0,1), (1) ( ) 0, (0) 0}
F = x C∈ ∩C x −axη ≥ x ≥ , if x t( )∈F such that
''( ) 0 x t
− ≥ for t∈(0,1), then x t( ) 0≥ for t∈[0,1].
3. Proofs of Main Theorems
In this section, we’ll always assume that f t x( , )=λxp−K t x( ) −q.
(A) The proof of Theorem 1.1. Proof.
1) We consider the problem
( ) ( ) ( ) ( ), (0,1),
(0) 0, (1) ( ),
q p
x t K t x t x t t
x x ax
λ
η
−
′′− + = ∈
= =
(3.1.1)
where 0<q p, <1, K C∈ [0,1], K*>0, 0< <a 1, 0< <η 1 and λ is a
positive parameter.
In [19], when f t x( , ) is increasing in x, the problem
( ) ( , ), (0,1),
(0) ( ), (1) 0
x t f t x t x axη x
′′
− = ∈
= =
has an unique C1[0,1] positive solution. From that, suppose that *( )
x t is an unique C1[0,1] positive solution of the problem
( ) ( ), (0,1),
(0) 0, (1) ( ),
p
x t x t t
x x ax
η
′′− = ∈
= =
(3.1.2)
where 0< <a 1, 0< <η 1. Set
1 1
*
( )t px t( )
β
=λ
− . Then1
1 1
* *
1
1 1
* * *
1 1
*
( ) ( ) ( ) ( ) ( ) ( )
( ) ( )
( ),
q
q p p q
q q
p p
p p
t K t t x t K t x t
x t K x t
x t
β β λ λ
λ λ
λ
−
− − − −
− −
− −
− ′′
− + = +
> +
DOI: 10.4236/jamp.2018.612217 2609 Journal of Applied Mathematics and Physics 1
1 *
( ) ( ).
p t px tp
λβ
=λ
−Thus −β′′( )t +K t( )β−q( )t >λβp( ).t Combining it with (3.1.2) we obtain
( ) ( ) ( ) ( ), (0,1),
(0) 0, (1) ( ).
q p
t K t t t t
a
β
β
λβ
β
β
β η
−
− ′′ + > ∈
= =
Consequently, β( )t is a upper solution of (3.1.1). Set
2 1 1
( )t M q
α
=ϕ
+ , where M is a positive constant and 1ϕ is the first eigen-function. Then 1 1 2 1 2 2 1 1 2 1 2 1 2 1
1 1 2
2 1 1 1
2 1
1 1 2
2 1 1 2 * 1 1 2 2 1 1 1
2(1 ) | ' |
2 ( )
''( ) ( ) ( ) ( ) ''( )
1
(1 )
2(1 ) | ' |
2 ( )
1
(1 )
2(1 ) | ' |
2 . (1 ) q q q q q q q q q q q q q q q q q q q q q M
M K t
t K t t t t
q
q M
q M
M K t
q M q q M M K M q ϕ
α α ϕ ϕ
ϕ ϕ
ϕ
λ ϕ ϕ
ϕ ϕ λ ϕ ϕ ϕ − + + + + + + − + + + − − + = − + − + + − = + − + + −
< + −
+
By Lemma 2.1 we have
ϕ
1( ) sin(t =λ
1t),ϕ
1( )t =λ
1cos(λ
1t). Thus thereexists δ >0 0 and b∈(0,1) such that
1' 1 1 0
| ( ) | |
ϕ
t =λ
cos(λ
t) |>δ
, t∈[0, ),b1 1 0
| ( ) | | sin(
ϕ
t =λ
t) |>δ
, t b∈[ ,1].a) On [0, )b , choosing
1 2 * 1 1 2 0 (1 ) [ ] 2(1 ) q q K M M q
δ
+ + ≥ =− , then we have
2 * 1 1 1 2 1 1 1 q q q q M K q M λ ϕ ϕ + + ≤ + .
b) On [ ,1]b , choosing
1 2 * 1 2 2 0 (1 ) [ ] 2(1 ) q q K M M q
δ
+ + ≥ =− , then we have
2 * 1 1 1 2 1 1 . 1 q q q q M K q M λ ϕ ϕ + + ≤ +
Fixing M=max{ ,M M1 2}, then
2 1 1 1 3 ( ) ( ) ( ) 1
q M q
t K t t
q
λ
α
′′α
−ϕ
+− + ≤ + and 2 1 1 ( ) . q
p t Mp q
λα
=λ
ϕ
+Set
2 2 1
1 0 31 | |1
p q q M q
λ
ϕ
− − + ∞ =DOI: 10.4236/jamp.2018.612217 2610 Journal of Applied Mathematics and Physics
2 2
1 1
1
1 1 0
3 , .
1
p p
q q
M M
q
λ
ϕ
+ <λ
ϕ
+ ∀ >λ λ
+
Hence, −α′′( )t +K t( )α−q( )t <λαp( )t ,
0 λ λ
∀ > .
It follows from Lemma (2.1) that
2 1 1
(0) M q(0) 0
α
=ϕ
+ =and
2 2 2 2 2
1 1 1 1 1
1 1 1 1
(1) M q(1) M a[ ( )] q Ma q q( ) aM q( ) a ( ).
α
=ϕ
+ =ϕ η
+ = +ϕ
+η
<ϕ
+η
=α η
Set
1 1 1 1
2 1
*
( | | | | )
q p q M
x
ϕ
λ
ϕ
− − +
∞ ∞
= . Then 12 11
1 *
( )t M q( )t px t( ) ( )t
α
=ϕ
+ ≤λ
− =β
forall λ λ> 2. Thus we choose λ =max{ , }λ λ0 2 and λ λ> , then ( ( ), ( ))α t β t is
a couple of upper and lower solutions of (3.1.1).
We choose F t( )=λβp+K*β−q, then | ( , ) |f t x ≤F t( ) for all ( , )t x Dβ α
∈ . It’s easy to see that F t( )∈L1[0,1]. From Corollary 2.1, the problem (3.1.1) has at
least one C[0,1] positive solution x t( ) satisfying α( )t ≤x t( )≤β( )t for λ λ> . 2) (Existence of the maximal solution) We observe the problem
( ) ( ), (0,1),
(0) 0, (1) ( ).
p
x t x t t
x x ax
λ
η
′′− = ∈
= =
(3.1.3)
From [19], we note the unique solution of (3.1.3) is w tλ( ) for any λ>0. In (1) we obtained the solution x tλ( ) of (3.1.1) then we have
( ) ( ) 0 ( ) (
' ' )
' p ' p
w tλ +λw tλ = <x tλ +λx tλ
and x f t x1 ( , ) xp 1( )t λ λ
− = − is decreasing in x. Noting that x t( ) L1[0,1]
λ ∈ by (1).
From Lemma 2.3, we have x tλ( )≤w tλ( ). Let
0
1
[ ,1)
j i j
Ω =
+ , j=1, 2, and w tj( ) be the solution of
1 1
1
0
( ) ( ) ( ) ( ), ,
1
( ) ( ), [0, ),
(1) ( )
q p
j j j
j
x t K t w t w t t
x t w t t
i j
x ax
λ
η −
− −
−
′′− + = ∈ Ω
= ∈
+
=
(3.1.4)
for j=1, 2,, with w t0( )=w tλ( ) defined in (3.1.3). Let x tλ( ) be a solution
of (3.1.1).
In (3.1.4), letting j=1 we have
1 1
1
0
1 1
( ) ( ) ( ) ( ), ,
1
( ) ( ), [0, ),
(1) ( ).
q p
w t K t w t w t t
w t w t t
i j
w aw
λ λ
λ
λ
η −
− ′′ + = ∈ Ω
= ∈
+
=
(3.1.5)
Combining (3.1.5) with (3.1.3) we have w t w t1''( )− λ''( ) 0≥ for t∈ Ω1. By
maximum principle, we have w t1( )≤w t0( )=w tλ( ). Similarly, we can obtain that
1( ) ( ) ( )
j j
DOI: 10.4236/jamp.2018.612217 2611 Journal of Applied Mathematics and Physics
Furthermore, we observe problem (3.1.1)
( ) ( ) ( ) ( ), (0,1),
(0) 0, (1) ( ).
q p
x t K t x t x t t
x x ax
λ
η
−
′′− + = ∈
= =
Combining it with (3.1.5) we have
1''( ) ''( ) ( )( q( ) q( )) ( ( )p p( )) 0,
w t x tλ K t w tλ− x tλ− λ w tλ x tλ
− + + − = − ≥
thus x t w tλ''( )− 1''( )≥0 for t∈ Ω1. It’s easy to verify that x tλ( )≤w t1( ) for [0,1]
t∈ by maximum principle. By similar method we can obtain
1
( ) j ( ) j( ) ( )
x tλ ≤w+ t ≤w t ≤w tλ for t∈[0,1].
Furthermore, we have { ( )}w tj j N∈ is bounded from below by x tλ( ).
Because w tj( ) is a solution to (3.1.3),
1 1
1 * 1
1 * 1
1 *
( ) ( ) ( ) ( )
( ) ( )
[ ( ) ] ( )
[ ( )
''
] ( ).
p q
j j j
p q
j j
p q q
j j
p q q
j j
w t w t K t w t
w t K w t
w t K w t
w t K w t
λ λ λ λ
−
− −
−
− −
+ −
− −
+ −
−
− = −
≤ −
≤ −
≤ −
Suppose that t0∈(0,1), w tj( ) max ( )0 = 0≤ ≤t 1w tj , then w tj'( )0 =0 and w tj( ) is
increasing on ( , )t t0 . By integration of −w tj''( ) from t to t0, we have
0 0
1 *
''( ) [ ( ) ] ( )
t t p q q
j j j
t w s ds t λw s K w s ds
+ −
−
− ≤ −
∫
∫
.So w t w tj'( ) ( )qj ≤
λ
wjp q−+1( )t0 −K*. Similarly, by integration of −w tj''( ) from0
t to t, we can obtain |w t w tj'( ) ( ) |j ≤
λ
wjp q−+1( )t0 −K*. For giving t t1 2, ∈[0,1],we have
2 2 2
1 1 1
'
1 0 *
'( ) ( ) | ( ) ( ) | [ ( ) ] .
t q t q t p q
j j j j j
t w s w s ds t w s w s ds t
λ
w t K ds+ −
≤ ≤ −
∫
∫
∫
We can find K large such that |
λ
wp qj−+1 ( )t0 −K*|<K. Then2
1 '( ) ( ) | 2 1|
t q
j j
t w s w s ds K t t≤ −
∫
, 1 12 1 2 1
| q ( ) q ( ) | | | .
j j
w + t −w + t ≤K t t−
(3.1.4)
We define an operator I w( )=wq+1, then
1 1( ) q 1
I w− =w + . It follows from
(3.1.4) that { ( ( ))}I w tj j N∈ is a uniformly bounded and equicontinuous
func-tions in [0,1]. Obviously, I−1 is uniformly continuous in a bounded and closed
domain Ω, i.e., for all ε >0, there exists a δ >0 such that when w1,
2
w ∈ Ω , |w w1− 2|<δ , we have 1 1
1 2
|I w− ( )−I w− ( ) |<ε . Since 0
0<w tj( )<w t( ), there exists a M >0 such that w tj( ) (0, ]∈ M . From (3.1.4),
for the above δ >0, there exists δ′ >0 such that when |t t1− <2| δ ′, we have
1 1
2 1
| q ( ) q ( ) |
j j
w + t −w+ t <
δ
.Therefore, for all ε >0, there exists δ′ >0 such that when |t t1− <2| δ ′, we
have
1 1 1 1
2 1 2 1
| ( ) ( ) | | ( q ( )) ( q ( )) |
j j j j
w t −w t = I w− + t −I w− + t <
ε
.Thus { ( )}w tj j N∈ is equicontinuous. Using Arzela-Ascoli theorem, there
ex-ists a subsequence {w tjk( )}jk∈{ }i such that jklim→+∞w tjk( )=x tλ( ). Without loss of
DOI: 10.4236/jamp.2018.612217 2612 Journal of Applied Mathematics and Physics
lim j( ) ( ), [0,1].
j→+∞w t =x tλ t∈ (3.1.5)
In the following, we shall show that x tλ( ) is a C[0,1] positive solution of (3.1.1).
Fixing (0,1)( 1)
2
t∈ t≠ , then w tj( ) can be stated
1 1 1
2
1 1 1
( ) ( ) ( )( ) ( )[ ( ) ( ) ( )] .
2 ' 2 2
t q p
j j j j j
w t w w t s t K s w− s λw s ds
− −
= + − +
∫
− − (3.1.6)Fixing j N∈ , by Lagrange mean value theorem, there exists ( ,1)1 2
n
t ∈ such
that xλ(1)−wj( )12 ≤wj(1)−wj( )21 =w tj′( )(1n −21)<w0(1).
So there exists M1>0 such that |w tj′( ) | 2n < M1 . Since { ( )}w tj j N∈ is
bounded in [0,1], we may assume that m w t< j( )<M2, t∈[ , ]12 tn ,
''
1 1 1 1
2 2
1 1 * 1
2
*
| ( ) | | [ ( ) ( ) ( )] |
| [ ( ) ( )] |
.
n n
n
t t p q
j j j
t p q
j j
p q
w s ds w s K s w s ds
w s K w s ds
M K m
λ
λ
λ
−
− −
−
− −
−
− = −
≤ −
≤ −
∫
∫
∫
Thus
* 2
1 1
| '( ) | | '( ) | | '( ) '( ) |
2 2 p q
j j n j j n
w − w t ≤ w −w t ≤λM −K m−
i.e.,
*
1 2
1
| ( ) | 2 .
2
' p q
j
w ≤ M +λM −K m−
Thus both { ( )}1 2 '
j j N
w ∈ and { ( )}wj 12 j N∈ are bounded. Then they all have a
convergence subsequence. Without loss of generality, we note the subsequences are 1
{ ( )} 2
j j N
w ∈ and{wj'( )}12 j N∈ . And fixing j N∈ , we assume limj→∞wj' 1( )2 =r0.
In equation (3.1.6), letting j→ ∞ we have
1 0
2
1 1
( ) ( ) ( ) ( )[ ( ) ( ) ( )]
2 2
t q p
x tλ =xλ +r t− +
∫
s t K s x− λ− s −λx s dsλfor t∈(0,1), i.e., x t''( ) K t x t( ) q( ) x tp( )
λ λ− λ λ
− + = . Therefore x tλ( ) is a C[0,1]
positive solution of (3.1.1). Therefore x tλ( ) is the maximal solution of (3.1.1). Next we shall verify the dependence on λ of maximal solution x tλ( ). Let H = {µ>0: (3.1.1) has a C[0,1] positive solution with λ µ= }.
Obviously, by (1), H ≠ ∅. Let λ ∈1 H. and x tλ( ) be the corresponding maximal solution of (3.1.1) for λ λ= 1 . Then for any λ2 >λ1>λ ,
1''( ) 1 1( ) 0, (0,1)
p
xλ t +λx tλ ≥ t∈ . By Lemma (2.3), x tλ1( )≤w tλ2( ) in [0,1]. Just
re-placing x tλ( ) by x tλ1( ) in above proof. We can easily find that
1 1 1 1
2 2 2
''
1 2
''
2
( ) ( ) ( ) , (0,1),
( ) ( ) ( ) ( ).
q p p
q p
x t K t x t x x t w t K t w t w t
λ λ λ λ
λ λ λ
λ λ
λ
− −
− + = ≤ ∈
− + ≥
DOI: 10.4236/jamp.2018.612217 2613 Journal of Applied Mathematics and Physics
Combining it with boundary conditions, we can obtain that ( ( ),x t w tλ1 λ2( )) is a couple of lower and upper solutions of (3.1.1) for λ λ= 2 >λ1. One can be
prove that there is a solution x tλ2( ) of (3.1.1) with λ λ= 2 such that
1( ) 2( ) 2( ).
x tλ ≤x tλ ≤w tλ
Therefore λ ∈2 H. Moreover, by (ii), for any λ2 >λ1≥λ, x tλ2( )≥x tλ1( ). This completes the proof of Theorem 1.1.
(B) The proof of Theorem 1.2. Proof. 1) We consider the problem
''( ) ( ) ( ) ( ), (0,1),
(0) 0, (1) ( ),
q p
x t K t x t x t t
x x ax
λ
η
−
− + = ∈
= =
(3.2.1)
where q>0,0< p<1, K t( )∈C[0,1], K*<0, 0< <a 1, 0< <η 1 and λ
is a positive parameter.
Now we consider an approximate problem of (3.2.1) as follows
''( ) ( ) ( ) ( ), (0,1),
1 1
(0) , (1) ( ) ,
q p
x t K t x t x t t
x x ax
n n
λ
η −
− + = ∈
= = +
(3.2.2)
where 0< <a 1, 0< <η 1, n≥1.
Let
ε
very small. We’ll verify that n( )t 1( )t 1 nα =εϕ + is a lower solution of
(3.2.2). Indeed, when n is big enough, we can obtain that εϕ1( )t +1n is close to
0. Since 1 (0, 2) π
λ ∈ (see [6]), we can deduce
1 1 1 1
1 1 1
1
1 1 1
( ) ( ) ( ) ( )
1 1
( ) ( )( ( ) ) ( (
'
) )
1
( ) ( ( ) )
1
( )[ ( ( ) ) ]
0,
' q p
n n n
q p
p
p
t K t t t
t K t t t
n n
t t
n
t t
n
α α λα
λ εϕ εϕ λ εϕ
λ εϕ λ εϕ
εϕ λ λ εϕ
−
−
−
− + −
= + + − +
< − +
< − +
<
1
1
(0) (0) 0
n n
α − =εϕ =
and αn(1) [− aα ηn( )+n1]=ε ϕ ηa 1( )+ −1n aεϕ η1( )− − <an n1 0, which imply that
( ) n t
α is a lower solutions of (3.2.2).
In the following, we’ll construct an upper solution of (3.2.2). Let
2
( )t Mt (M aM t M)
β = − + + + ,
where M is big enough for
1
1 1
{(2 ) , }
(1 )
p M
n a
λ
− >DOI: 10.4236/jamp.2018.612217 2614 Journal of Applied Mathematics and Physics 2
*
''( ) ( ) ( ) 2 ( )[ ( ) ]
2 ,
q q
q
t K t t M K t Mt M aM t M M K M
M
β β− −
−
− + = + − + + +
> +
>
2
2
( ) [ ( ) ]
(1 )
[ ]
4 (2 ) ,
p p
p
p
t Mt M aM t M M a M
M
λβ λ
λ
λ
= − + + +
+
< +
<
( )t K t( ) q( )t p( ),t
β′′ β− λβ
− + ≥
2
1 1
(1) ( ( ) ) ( 1) [ ( ) ]
1
( 1) 2
1
0
a a M a M M aM M
n n
a M aM n M aM
n
β − β η + = + − − η + + η+ −
> + − −
= − −
>
and (0) 1 M 1 0
n n
β − = − > . It’s easy to see that β( )t is na upper solution of
(3.2.2).
Choosing F tn( )=λβp−K*αn−q, then | ( , ) |f t x ≤F tn( ), for all ( , )t x Dn β α
∈ . It’s
easy to verify that ( ) 1[0,1]
n
F t ∈L . Because that
ε
is small and n is big enough,( ) ( )
n t t
α ≤β . From Corollary 2.1, ( ( ), ( ))αn t β t is a couple of upper and lower solutions of (3.2.2). And for all n N∈ , (3.2.2) has at least one C[0,1] positive solution x tn( ) such that αn( )t ≤x tn( )≤β( )t .
In the following, we shall obtain a result as follows, there exists a subsequence { ( )}x tnk and x t( ) such that lim k( ) ( )
k n
n→∞x t =x t .
Since β( )t ∈C[0,1]∩C2(0,1), β( )t is bounded. Therefore { ( )}
n n N
x t ∈ is a
uniformly bounded sequence of functions in [0,1]. Because x tn( ) is a C[0,1] positive solution of (3.2.2), x tn( ) satisfies
*
*
( ) ( ) ( ) ( )
( ) ( )
[ ( ) ] (
''
).
p q
n n n
p q
n n
p q q
n n
x t x t K t x t
x t K x t
x t K x t
λ λ λ
−
−
+ −
− = −
≤ −
≤ −
Suppose that t0∈(0,1),
0 1
0
( ) max ( )
t
n n
x t x t
≤ ≤
= , then x tn'( )0 =0 and x tn( ) is increasing on ( , )t t0 . By integration of −x tn''( ) from t to t0, we have
0 0
*
''( ) [ ( ) ] ( ) .
t t p q q
n n n
t x s ds t λx s K x s ds
+ −
− ≤ −
∫
∫
So n'( ) q1( )[ np q( )0 *]
n
x t x t K
x t λ
+
≤ − . We can find a K>0 such that
) ( '( q )
n n
x t x t ≤K. And by integration of −x tn( ) from t0 to t, we have
0 0
*
''( ) [ ( ) ] ( ) .
t t p q q
n n n
t x s ds t λx s K x s ds
+ −
− ≤ −
∫
∫
So n'( ) q1()[ np q( )0 *]
n
x t x t K
x t λ
+
− ≤ − . For above K, we have | '( ) ( )q |
n n
x t x t K
DOI: 10.4236/jamp.2018.612217 2615 Journal of Applied Mathematics and Physics i.e., | ' ) ( )( q |
n n
x t x t ≤K.
For giving t t1 2, ∈[0,1], we have
2 2 2
1 '( ) ( ) 1| ( ) ( ) |' 1 .
t q t q t
n n n n
t x s x s ds≤ t x s x s ds≤ t Kds
∫
∫
∫
Then 2
1 '( ) ( ) | 2 1|
t q
n n
t x s x s ds K t t≤ −
∫
. The above inequality can be rewritten as2
1
( ) 1 1
2 1 2 1 2 1
( )
| n ( ) ( ) | | |, | ( ) ( ) | | | .
n
x t q q q
n n n n
x t x s dx s K t t x t x t K t t
+ +
≤ − − ≤ −
∫
(3.2.3)We now define an operator I x( )=xq+1, then
1 1( ) q1
I x− =x + . It follows from
(3.2.3) that { ( ( ))}I x tn n N∈ is a uniformly bounded and equicontinuous
func-tions in [0,1]. Obviously, I−1 is uniformly continuous in a bounded and closed
domain Ω , i.e., for all ε >0 , there exists a δ >0 such that
1 1
1 2
|I x−( )−I x− ( ) |<ε for
1 2
|x x− |<δ , x x1, 2∈ Ω . Since 0<x tn( )<β( )t , there exists a M>0 such that x tn( ) (0, ]∈ M . From (3.2.3), for the above
0
δ > , there exists δ′ >0 such that 1 1
2 1
| q ( ) q ( ) |
n n
x + t −x+ t <δ for 1 2
|t t− <| δ ′.
Therefore, for all ε >0, there exists δ′ >0 such that
1 1 1 1
2 1 2 1
| ( ) ( ) | | ( q ( )) ( q ( )) |
n n n n
x t −x t = I x− + t −I x− + t <ε
for |t t1− <2| δ ′. Consequently, { ( )}x tn n N∈ is equicontinuous. Using
Arze-la-Ascoli theorem, there exists a subsequence { ( )}x tnk such that nklim→+∞x tnk( )=x t( ).
Without loss of generality, we assume that
lim ( )n ( ), [0,1].
n→+∞x t =x t t∈ (3.2.4)
In the following, we shall show that x t( ) is a C[0,1] positive solution of (3.2.1). Fixing (0,1)( 1)
2
t∈ t≠ , x tn( ) can be stated
1 2
1 1 1
( ) ( ) '( )( ) ( )[ ( ) ( ) ( )] .
2 2 2
t q p
n n n n n
x t =x +x t− +
∫
s t K s x s− − −λx s ds (3.2.5)Fixing n N∈ , by Lagrange mean value theorem, there exists ( ,1)1 2
n
t ∈ such
that (1) ( )1 (1) ( )1 '( )(1 1) (1)
2 2 2
n xn xn xn x tn n
α − ≤ − = − ≤β .
So there exists M1>0 such that |x tn'(n) |≤2M1. Since { ( )}x tn n N∈ is
bounded in [0,1], we may assume that m x t≤ n( )≤M2, t∈[ , ]12 tn .
''
1 1
2 2
| tn ( ) | | [tn p( ) ( ) q( )] | .
n n n
x s ds λx s K s x s ds−
− = −
∫
∫
We can obtain
2 * 2
1
| ( ) '( ) |
2
' p q
n n n
x t x λM K M−
− + ≤ − and |xn'( ) | 212 ≤ M1+λM2p−K M* 2−q.
Therefore both { ( )}1 2
n n N
x ∈ and { ( )}xn' 12 n N∈ are bounded. They all have a
convergence subsequence. Without loss of generality, we note the subsequences are { ( )}1
2
n n N
DOI: 10.4236/jamp.2018.612217 2616 Journal of Applied Mathematics and Physics
From (3.2.5), letting n→ ∞, we obtain
1 0
2
1 1
( ) ( ) ( ) ( )[ ( ) ( ) ( )] .
2 2
t q p
x t =x +r t− +
∫
s t K s x s− − −λx s dsBy derivation twice of x t( ), we have
( ) ( ) q( ) p( ).
x t′′ K t x t− λx t
− + =
Combining it with (3.2.4), we can obtain that x t( ) is a C[0,1] positive solu-tion of (3.2.1).
2) We study the uniqueness of C1[0,1] positive solution of problem (3.2.1).
Let F t( )=λβp−K*(εϕ1)−q. Obviously, when 0< <q 1, F t( ) is integrable
over (0,1). Since | ( ) |x t′′ ≤F t( ), x t( ) is absolutely integrable over (0,1). Then both x′ +(0 ) and x′ −(1 ) exist, i.e., x t( )∈C1[0,1].
Suppose conversely that x t1( ), x t2( ) are two C1[0,1] positive solutions of
the problem (3.2.1), x t1( )≡/x t2( ) on [0,1]. We may assume without loss of
ge-nerality that there exists t*∈(0,1) such that
* *
2( ) 1( ) max( ( )0t1 2 1( )) 0
x t x t x t x t
≤ ≤
− = − > . Let
* *
1 1 2 1 1
inf{ | 0t t t x t, ( ) x t t( ), ( , )},t t
α= ≤ < > ∈
* *
2 2 2 1 2
sup{ |t t t 1, ( )x t x t t( ), ( , )}.t t
β = ≤ < > ∈
It’s obvious that 0≤α β< ≤1 and
1 2 1 2 1 2
1 2 1 2
( ) ( ), ( ) ( ), ( ) ( ),
( ) ( ), ( ) ( ),
' '
' ' ( , ).
x x x x x x x x x t x t t
α α α α β β
β β α β
= ≤ ≤
+ ≥ + < ∈
Let y t( )=x t x t1( ) ( )2' −x t x t t2( ) ( ),1' ∈( , )α β . Then we have
lim inf ( ) 0 lim sup ( ).
t→ +α y t ≥ ≥t→ +β y t (3.2.6)
On the other hand,
'' '' 1 2 2 1
1 2 2 2 1 1
1 2 1 2 1 2 1 2
1 1 1 1
1 2 2 1 1 2 1 2
'( )
( ) ( )
( ) ( )
0
q p p q
q p p q
q q p p
y t x x x x
x Kx x x x Kx
Kx x x x x x Kx x
Kx x x x x x x x
λ λ
λ λ
λ
− −
− −
− − − − − −
= −
= − + −
= − + −
= − + −
≥
for t∈( , )α β and y t′( ) 0≡/ on ( , )α β . This implies y( )β− > y( )α+ ,
contra-dicts (3.2.6), so x t1( )≡x t2( ). Thus the C1[0,1] positive solution of (3.2.6) is
unique.
3) We assume that 0<λ1<λ2 and x tλ1( ), x tλ2( ) are the corresponding unique C1[0,1] positive solutions to (3.2.1). Obviously,
1
1
( ) [
'' 0, ]1
xλ t ∈L . In
(3.2.1), f t x( , )=λx tp( )−K t x t( ) −q( ) is continuous. Since p q, ∈(0,1), K*<0, it’s easy to see that
1 ( , ) p1( ) ( ) q1( )
x f t x− =λx − t −K t x− − t is decreasing for x>0 at each t∈[0,1].
2''( ) ( ) 2( ) 2 2( ) 0 1''( ) ( ) 1( ) 2 1()
q p q p
xλ t −K t x tλ− +λ x tλ = <xλ t −K t x tλ− +λ x tλ
for t∈(0,1),
2(0) 1(0)