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Volume 2011, Article ID 752341,25pages doi:10.1155/2011/752341

Research Article

Some Properties of Certain Multivalent Analytic

Functions Involving the C ˘atas Operator

E. A. Elrifai, H. E. Darwish, and A. R. Ahmed

Department of Mathematics, Faculty of Science, University of Mansoura, Mansoura 35516, Egypt

Correspondence should be addressed to H. E. Darwish,[email protected]

Received 2 March 2011; Accepted 8 May 2011

Academic Editor: Marco Squassina

Copyrightq2011 E. A. Elrifai et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We introduce a certain subclass of multivalent analytic functions by making use of the principle of subordination between these functions and C˘atas operator. Such results as subordination and superordination properties, convolution properties, inclusion relationships, distortion theorems, inequality properties, and sufficient conditions for multivalent starlikeness are provide. The results presented here would provide extensions of those given in earlier works. Several other new results are also obtained.

1. Introduction

LetApndenote the class of functions of the following form:

fz zp

kn

apkzpk

p, nN:{1,2,3, . . .}, 1.1

which are analytic in the open unit diskU:{z:z∈Cand |z|<1}. For simplicity, we write

Ap1:Ap, A11 A. 1.2

A functionfzApnis said to be in the classSp,nγofp-valent starlike functions of order

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Re

zfz

fz

> γ 0≤γ < p;zU. 1.3

LetHa, nbe the class of analytic functions of the following form:

Fz aanznan1zn1· · · zU. 1.4

Letf, gApn, wherefzis given by1.1andgzis defined by

gz zp

kn

bpkzpk. 1.5

Then the Hadanard productor convolutionfgof the functionsfzandgzis defined by

fgz:zp

kn

apkbpkzpk:

gfz. 1.6

We consider the following multiplier transformations.

Definition 1.1see1. LetfzApn. Forp, nN, δ, λ ≥ 0, ≥ 0, define the multiplier

transformationsIpδ, λ, onApnby the following infinite series:

Ipδ, λ, fz:zp

kn

pλk

p

δ

akpzkp. 1.7

It is easily verified from1.7, that

pIpδ1, λ, fz p1−λ

Ipδ, λ, fz λz

Ipδ, λ, fz

. 1.8

It should be remarked that the class of multiplier transforms Ipδ, λ, is a generalization of several other linear operators considered, in earlier investigationssee2–

12.

Iffzis given by1.1, then we have

Ipδ, λ, fz

fϕδp,λ,z, 1.9

where

ϕδ

p,λ,z zp

kn

pλk

p

δ

(3)

In particular, we set

I1δ, λ, fz:Iδ, λ, fz. 1.11

For two functions fz and gz, analytic in U, we say that the function fz is subordinate togzin U, and writefzgz zUif there exists a Schwarz function

wz, which is analytic in U with

w0 0, |wz|<1 zU 1.12

such that

fz gwz zU. 1.13

Indeed, it is known that

fzgz, zUf0 g0, fUgU. 1.14

Furthermore, if the function g is univalent in U, then we have the following equivalence:

fzgz, zU⇐⇒f0 g0, fUgU. 1.15

By making use of the linear operator Ipδ, λ, and the above-mentioned principle of subordination between analytic functions, we introduce and investigate the following subclass of the classApnofp-valent analytic functions.

Definition 1.2. A functionfzApnis said to be in the class ßα,βp δ, λ, , n;A, Bif it satisfies

the following subordination condition:

1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

≺ 1Az

1Bz zU,

1.16

whereand throughout this paper unless otherwise mentionedthe parametersα, β, p, n, λ, δ, , A, andBare constrained as follows:

α∈C,Reβ>0, λ, ≥0, λ, R, δ≥0, −1≤B≤1, A /BR, p, nN. 1.17

For simplicity, we write

ß111,1,1; 1; 1,−1 ßβ. 1.18

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If we setδ 0, λ p 1 in the class ßα,βp δ, λ, , n;A, B, which was studied by Liu13. In particular, Zhu14determined the sufficient conditions such that ßnα, β, A,0⊂

Sp,nρ.

C˘atas 1, 5, 15, Cho and Srivastava 6, Cho and Kim 7, and Kumar et al. 10

obtained many interesting results associated with the multiplier operator.

In the present paper, we aim at proving such results as subordination and super-ordination properties, convolution properties, inclusion relationships, distortion theorems, inequality properties, and sufficient conditions for multivalent starlikeness of the class

ßα,βp δ, λ, , n;A, B. The results presented here would provide extensions of those given in

earlier works. Several other new results are also obtained.

2. Preliminary Results

In order to establish our main results, we need the following definition and lemmas.

Definition 2.1 see 16. Denote by Q the set of all functions fz that are analytic and

injective onUEf, where

Ef

ε∂U: lim

zεfz

, 2.1

and such thatfε/0 forε∂UEf.

Lemma 2.2see17. Let the functionhbe analytic and univalent (convex) inUwithh0 1.

Suppose also that the functionkgiven by

kz 1cnzncn1zn1· · · 2.2

is analytic inU. If

kz zkz

ζhz Reζ>0; ζ /0; zU, 2.3

then

kzχz ζ

nz

ζ/n

z

0

tζ/n−1htdthz zU, 2.4

andχzis the best dominant of2.3.

Lemma 2.3see18. Letqzbe a convex univalent function inUand letσ, η∈Cwith

Re

1zq

z

qz

>max

0,−Re

σ η

(5)

If the functionpis analytic inUand

σpz ηzpzσqz ηzqz, 2.6

thenpzqzandqzis the best dominant.

Lemma 2.4see16. Letqbe convex univalent inUandkC. Further assume that Rek>0 if

pzH q0,1∩Q, 2.7

andpz kzpzis univalent inU, then

qz kzqzpz kzpz 2.8

implies thatqzpzandqzis the best subdominant.

Lemma 2.5Jach’s Lemma19. Letwzbe a noncostant analytic function inUwithw0 0.

If|w|attains its maximum value on the circle|z|r <1 atz0, then

z0wz0 kwz0, 2.9

wherek1 is a real number.

Lemma 2.6see20. LetFbe analytic and convex inU. Iffz, gzAandfz, gzFz;

then

λfz 1−λgzFz 0≤λ≤1. 2.10

Lemma 2.7see21,22. Letk, v∈C. Suppose also that m is convex and univalent inUwith

m0 1, Rekmz v>0 zU. 2.11

Ifuis analytic inUwithu0 1, then the following subordination:

uz zu

z

kuz vmz, zU 2.12

implies that

uzmz zU. 2.13

Lemma 2.8see23. Letfz 1∞k1akzkanalytic inUandgz 1∞k1bkzkbe analytic

(6)

Lemma 2.9see24. Letδ /0, δR, v/δ >0,0≤ρ <1, pH1, n, andpz≺1kzk:

vM/nδv, where

M:Mn

δ, ν, ρ

1−ρ|δ|1nδ/v

1δρδ1 nδ/v2. 2.14

IfqzH1, nsatisfies the following subordination condition:

pz 1−δδ1−ρqz ρ≺1Mz, 2.15

then

Reqz>0 zU. 2.16

3. Main Results

We begin by presenting our first subordination property given by Theorem3.1below.

Theorem 3.1. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0. Then

Ipδ, λ, fz

zp

β

λnα

1

0

1Azu

1Bzuu

pβ/λnα−1du 1Az

1Bz zU. 3.1

Proof. Define the functionPzby

Pz:

Ipδ, λ, fz

zp

β

zU. 3.2

ThenPzis analytic inUwithP0 1. By taking the derivatives in the both sides in equality

3.2and using1.8, we get

1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

Pz λαzPz

βp

1Az

1Bz zU.

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An application of Lemma2.2to3.3yields

Ipδ, λ, fz

zp

β

λnα z

pβ/λnα

z

0

tpβ/λnα−11At

1Btdt

ζ

n

1

0

uζ/n−11Azu

1Bzudu

1Az

1Bz zU,

3.4

where

ζ

λα . 3.5

The proof of Theorem3.1is thus completed.

Theorem 3.2. Letqzbe univalent inU, 0/α∈C. Suppose also thatqzsatisfies

Re

1zq

z

qz

>max

0,−Re

λα

. 3.6

IffzApnsatisfying the following subordination:

1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

qz αλzq

z

pβ,

3.7

then

Ipδ, λ, fz

zp

β

qz, 3.8

andqzis the best dominant.

Proof. Let the functionPzbe defined by3.2. We know that3.3holds true. Combining

3.3and3.7, we find that

Pz λαzP

z

qz

λαzqz

pβ. 3.9

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Takingqz 1Az/1Bzin Theorem3.2, we get the following result.

Corollary 3.3. Letα∈Cand−1 ≤B < A1. Suppose also that1Az/1Bzsatisfies the

condition3.6. IffzApnsatisfies the following subordination:

1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

≺ 1Az

1Bz

λαABz

1Bz2,

3.10

then

Ipδ, λ, fz

zp

β

≺ 1Az

1Bz, 3.11

and1Az/1Bzis the best dominant.

Iffzis subordinate toFz, thenFzis superordinate tofz. We now derive the following

superordination result for the class ßα,βp δ, λ, ;n;A, B.

Theorem 3.4. Letqzbe convex univalent inU, α∈C, with Reα>0. Also let

Ipδ, λ, fz

zp

β

H q0,1∩Q,

1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β 3.12

be univalent inU. If

qz λαzq

z

≺1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

,

3.13

then

qz

Ipδ, λ, fz

zp

β

, 3.14

(9)

Proof. Let the functionPzbe defined by3.2. Then

qz λαzq

z

≺1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

Pz λαzP z

pβ.

3.15

An application of Lemma2.4yields the assertion of Theorem3.4.

Takingqz 1Az/1Bzin Theorem3.4, we get the following corollary.

Corollary 3.5. Letqzbe convex univalent inUand−1≤B < A≤1, α∈Cwith Reα>0. Also

let

Ipδ, λ, fz

zp

β

H q0,1∩Q,

1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β 3.16

be univalent inU. If

1Az

1Bz

λαABz

1Bz2

≺1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

,

3.17

then

1Az

1Bz

Ipδ, λ, fz

zp

β

, 3.18

and1Az/1Bzis best subdominant.

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Corollary 3.6. Letq1zbe convex univalent and letq2zbe univalent inU,α∈C, Reα>0. Let

q2zsatisfies3.6. If

0/

Ipδ, λ, fz

zp

β

H q10,1

Q,

1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β 3.19

is univalent inU, also

q1z

λαzq1z

≺1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

q2z

λαzq2z

pβ,

3.20

then

q1z

Ipδ, λ, fz

zp

β

q2z, 3.21

andq1z, q2zare, respectively, the best subordinate, and dominant.

Theorem 3.7. LetfzApn, ξ∈C\ {0}, and 0γ <1. Also let the functionϕbe defined by

ϕz

zIpδ1, λ, fz/Ipδ, λ, fz

Ipδ, λ, fz/zp

β 1

Ipδ1, λ, fz/Ipδ, λ, fz

Ipδ, λ, fz/zp

β

1 zU.

3.22

Ifϕsatisfies one of the following conditions:

Reϕz

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

< 1

|ξ|2Reξ Reξ>0, /

0 Reξ 0,

> 1

|ξ|2Reξ Reξ<0,

(11)

or

Iϕz

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

>− 1

|ξ|2 Iξ>0, /

0 0,

<− 1

|ξ|2 Iξ<0,

3.24

then

⎛ ⎝

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

−1

⎞ ⎠

ξ

<1−γ. 3.25

Proof. We define the functionφzby

⎛ ⎝

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

−1

⎞ ⎠

ξ

1−γφz 0≤γ <1;ξ∈C\ {0};zU.

3.26

It is easy to see that the functionφis analytic inUwithφ0 0.

Differentiating both sides of3.26with respect tozlogarithmically, we get

zφz

φz

ξ

zIpδ1, λ, fz/Ipδ, λ, fz

Ipδ, λ, fz/zp

β 1

Ipδ1, λ, fz/Ipδ, λ, fz

Ipδ, λ, fz/zp

β

1 zU;ξ∈C\ {0}.

3.27

We now consider the functionϕdefined by

ϕ: ξ

|ξ|2

zφz

φz zU, ξ∈C\ {0}. 3.28

Assume that there exists a pointz0∈Usuch that

max

|z|≤|z0|

φzφz01, 3.29

by Lemma2.5, we know that

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If follows from3.28and3.30that

Reϕz0

Re

ξ

|ξ|2

zφz0

φz0

k

|ξ|2Re

ξ

k |ξ|2Reξ

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

≥ 1

|ξ|2 Reξ Reξ>0,

0 Reξ 0

≤ 1

|ξ|2 Reξ Reξ<0,

3.31

Iϕz0

I

ξ

|ξ|2

zφz0

φz0

k

|ξ|2I

ξ

k |ξ|2

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

≤ − 1

|ξ|2 Iξ>0,

0 0,

≥ − 1

|ξ|2 Iξ<0.

3.32

But the inequalities in3.31and3.32contradict, respectively, the inequalities in3.23and

3.24. Therefore, we can conclude that

φz<1 zU, 3.33

which implies that

⎛ ⎝

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

−1

⎞ ⎠

ξ

1−γφz<1−γ. 3.34

We thus complete the proof of Theorem3.7.

From Theorem3.7, we easily get the following result for the class ßβ of Bazileviˇc functions of typeβ.

Corollary 3.8. LetfzA, δ0, pλξ1, andγ 0. Also let the functionϕbe defined

by3.22. Ifϕsatisfies one of the following conditions:

Reϕz<1 or Iϕz/0, 3.35

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Theorem 3.9. Let Reα > 0, β > 0, and fz ∈ ßp0,βδ, λ, ;n; 1−2ρ,−1 0 ≤ ρ < 1. Then

fz∈ßα,βp δ, λ, ;n,1−2ρ,−1for|z|< Rα, β, , λ, p, where

Rα, β, , λ, pλα

λ2α2p2β2

ρβ . 3.36

The boundRα, β, , λ, pis the best possible.

Proof. Suppose that

Ipδ, λ, fz

zp

β

ρ1−ρhz zU; 0≤ρ <1, 3.37

wherehis analytic and has a positive real part inU. By taking the derivatives in the both sides in equality3.37and using1.9, we get

Re

⎛ ⎝1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

ρ

1−ρRe

hz λαzh

z

≥1−ρRe

hzλα|zhz|

.

3.38

By making use of the following well-known estimatesee25:

zhz≤ 2r

1−r2 Rehz |z|r <1 3.39

in3.38, we obtain that

Re

⎡ ⎣1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

ρ

⎤ ⎦

1−ρ

1− 2λαr

1−r2

Rehz>0

3.40

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To show that the boundRα, β, , λ, pis the best possible, we consider the function

fzApndefined by

Ipδ, λ, fz

zp

β

ρ1−ρ1z

1−z zU. 3.41

By noting that

Re

⎛ ⎝1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

ρ

1−ρRe

1z

1−z

2λα

z

1−z2

0

3.42

forz Rα, β, , λ, p, we conclude that the bound is the best possible. Theorem3.9is thus

proved.

Theorem 3.10. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0. Then

fz

zp

1Awz

1Bwz

1

zp

kn

pλk

p

δ

zkp

, 3.43

wherewzis analytic inUwithw0 0 and|wz|<1 zU.

Proof. Suppose thatfz∈ßα,βp δ, λ, ;n;A, B. It follows from3.1that

Ipδ, λ, fz

zp

β

1Awz

1Bwz, 3.44

wherewzis analytic inUwithw0 0 and|wz|<1zU. By virtue of3.44, we easily find that

Ipδ, λ, fz zp

1Awz

1Bwz

1

. 3.45

Combining1.10,1.16, and3.45, we have

zp

kn

pλk

p

δ

zkp

fz zp

1Awz

1Bwz

1

. 3.46

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Theorem 3.11. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0. Then

1

z

#

1Biθ1

zp

kn

pλk

p

δ

zkp

fzzp1Aeiθ1

$

/

0 zU; 0< θ <2π.

3.47

Proof. Suppose thatfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0. We know that3.1holds true,

which implies that

Ipδ, λ, fz

zp

β

/

1Aeiθ

1Beiθ zU; 0< θ <2π. 3.48

It is easy to see that the condition3.48can be written as follows:

1

z

Ipδ, λ, fz

1Beiθ1zp1Aiθ1

/

0 zU; 0< θ <2π. 3.49

Combining1.9,1.10, and3.49, we easily get the convolution property3.47asserted by Theorem3.11.

Theorem 3.12. Letα2≥α1≥0 and−1≤B1≤B2 < A2< A1≤1. Then

ßα2

p δ, λ, ;n;A2, B2⊂ß1,βδ, λ, ;n;A1, B1. 3.50

Proof. Suppose thatfzβα2

p δ, λ, ;n;A2, B2. We know that

1−α2

Ipδ, λ, fz

zp

β

α2

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

≺ 1A2z

1B2z .

3.51

Since−1≤B1B2< A2A1≤1, we easily find that

1−α2

Ipδ, λ, fz

zp

β

α2

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

≺ 1A2z

1B2z

1A1z

1B1z

3.52

that is,fz∈ßα2

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Ifα2 > α1 ≥ 0, by Theorem3.1and3.52, we know thatfz∈ß0p,βδ, λ, ;n;A1, B1,

that is,

Ipδ, λ, fz

zp

β

≺ 1A1z

1B1z

. 3.53

At the same time, we have

1−α1

Ipδ, λ, fz

zp

β

α1

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

1−α1

α2

I

pδ, λ, fz

zp

β

α1 α2

⎡ ⎣1−α2

Ipδ, λ, fz

zp

β

α2

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

.

3.54

Moreover, since 0≤α1/α2<1 andh1z: 1A1z/1B1z, is analytic and convex in

U. Combining3.52–3.54and Lemma2.6, we find that

1−α1

Ipδ, λ, fz

zp

β

α1

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

≺ 1A1z

1B1z,

3.55

that is,fz∈ßα1

p δ, λ, ;n;A1, B1, which implies that the assertion3.50of Theorem3.12

holds.

Letρdenote the class of functions of the following form:

tz 1

kn

tkzk nN, 3.56

which are analytic and convex inUand satisfy the following condition:

Retz>0 zU. 3.57

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Sp,nμ, φ:

fApn:

1

pμ

zfz

fzμ

φzφρ; 0≤μ < p;zU,

Cp,n

μ;φ

fzApn:

1

pμ

1zf

z

fzμ

φzφρ; 0≤μ < p;zU.

3.58

Next, by using the operator defined by 1.7, we define the following two subclasses

Sp,nδ, λ, ;μ;φandCp,nδ, λ, ;μ;φof the classApn:

Sp,n

δ, λ, ;μ;φ:%fzApn:Ipδ, λ, fzSp,n

μ;φ&,

Cp,n

δ, λ, ;μ;φ:'fzApn:Ipδ, λ, fzCp,n

μ;φ(.

3.59

Clearly, we know that

fCp,n

δ, λ, ;μ;φ⇐⇒ zf

z

pSp,n

δ, λ, ;μ;φ. 3.60

We now derive some inclusion relationships for the classes Sp,nδ, λ, ;μ;φ and

Cp,nδ, λ, ;μ;φ, by similarly applying the method of proof of Proposition 1 obtained by Cho

et al.26and Wang et al.27.

Theorem 3.13. Let 0μ < p, λ >p, andφρwith

Reφz>max

0,δμ

pμ,

λμp

pμ

zU. 3.61

Then

Sp,n

δ1, λ, ;μ;φSp,n

δ, λ, ;μ;φSp,n

δ, λ1, ;μ;φ. 3.62

Theorem 3.14. Let 0μ < p, λ >pandφρwith3.61holds. Then

Cp,n

δ1, λ, ;n;μ;φCp,n

δ, λ, ;μ;φCp,n

δ, λ1, ;μ;φ. 3.63

Proof. By virtue of3.60and Theorem3.13, we observe that

fzCp,n

δ1, λ, ;μ;φ⇐⇒Ipδ1, λ, fzCp,n

μ;φ

⇐⇒z

Ipδ1, λ, fz

pS

p,n

μ;φ

⇐⇒Ipδ1, λ,

zfz

p

Sp,nμ;φ

zfz

pSp,n

(18)

⇐⇒zfz

pSp,n

δ, λ, ;μ;φ

⇐⇒Ipδ, λ,

zfz

p

Sp,nμ, φ

⇐⇒z

Ipδ, λ, fz

pS

p,n

μ;φ

⇐⇒Ipδ, λ, fzCp,n

μ;φ

⇐⇒fzCp,n

δ, λ, ;μ;φ,

fzCp,n

δ, λ, ;μ;φ⇐⇒zf

z

pSp,n

δ, λ, ;μ;φ

zfz

pSp,n

δ, λ1, ;μ;φ

⇐⇒z

Ipδ, λ1, fz

pS

p,n

μ;φ

⇐⇒Ipδ, λ1, fzCp,n

μ;φ

⇐⇒fzCp,n

δ, λ1, ;μ;φ.

3.64

From3.64, we conclude that the assertion of Theorem3.14holds true.

Takingφz 1Az/1Bzin Theorems3.13and3.14, we get the following results.

Corollary 3.15. Let 0μ < p, λ >p, and−1≤B < A1. Then

Sp,n

δ1, λ, ;μ;1Az

1Bz

Sp,n

δ, λ, ;μ,1Az

1Bz

Sp,n

δ, λ1, ;μ;1Az

1Bz

,

Cp,n

δ1, λ, ;μ;1Az

1Bz

Cp,n

δ, λ, ;μ,1Az

1Bz

Cp,n

δ, λ1, ;μ;1Az

1Bz

.

3.65

Theorem 3.16. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0 and−1≤B < A1. Then

λnα

1

0

1−Au

1−Buu

pβ/λnα−1du < Re

Ipδ, λ, fz

zp

β

<

λnα

1

0

1Au

1Buu

pβ/λnα−1du.

(19)

The extremal function of 3.66is defined by

Ipδ, λ, Fα,β,A,Bz zp

λαn

1

0

1Azu

1Bzuu

pβ/λnα−1du

1

. 3.67

Proof. Letfz∈ ßα,βp δ, λ, ;n;A, Bwith Reα> 0. From Theorem3.1, we know that3.1

holds, which implies that

Re

Ipδ, λ, fz

zp

β

<sup

zU Re

λαn

1

0

1Azu

1Bzuu

pβ/λnα−1du

λnα

1

0

sup zU

Re

1Azu

1Bzu

upβ/λnα−1du

<

λnα

1

0

1Au

1Buu

pβ/λnα−1du,

Re

Ipδ, λ, fz

zp

β

> inf

zURe

λnα

1

0

1Azu

1Bzuu

pβ/λnα−1du

λnα

1

0

inf zURe

1Azu

1Bzuu

pβ/λnα−1du

>

λnα

1

0

1−Au

1−Buu

pβ/λnα−1du.

3.68

Combining both equations of 3.68, we get 3.66. By noting that the function Ipδ, λ,

Fα,β,A,Bz defined by 3.67 belongs to the class ßα,βp δ, λ, ;n;A, B, we obtain that the equality3.66is sharp. The proof of Theorem3.16is evidently completed.

By similarly applying the method of proof of Theorem3.16, we easily get the following result.

Corollary 3.17. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0 and−1≤A < B1. Then

λnα

1

0

1Au

1Buu

pβ/λnα−1du

<Re

Ipδ, λ, fz

zp

β

<

λnα

1

0

1−Au

1−Buu

pβ/λnα−1du.

3.69

The extremal function of 3.69is defined by3.67.

(20)

Corollary 3.18. Letfz ∈ ßα,βp δ, λ, ;n;A, Bwith Reα > 0 and−1 ≤ B < A1. Then for

|z|r <1, we have

rp

λnα

1

0

1−Aur

1−Buru

pβ/λnα−1du

1

<Ipδ, λ, fz< rp

λnα

1

0

1Aur

1Buru

pβ/λnα−1du

1

.

3.70

The extremal function of 3.70is defined by3.67.

Corollary 3.19. Letfz ∈ ßα,βp δ, λ, ;n;A, Bwith Reα > 0 and−1 ≤ A < B1. Then for

|z|r <1, we have

rp

λnα

1

0

1Aur

1Buru

pβ/λnα−1du

1

<Ipδ, λ, fz< rp

λnα

1

0

1−Aur

1−Buru

pβ/λnα−1du

1

.

3.71

The extremal function of 3.71is defined by3.67.

By noting that

Reν1/2≤Reν1/2≤ |ν|1/2 ν∈C; Reν≥0. 3.72

From Theorem3.16and Corollary3.17, we easily get the following results.

Corollary 3.20. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0 and−1≤B < A1. Then

λnα

1

0

1−Au

1−Buu

pβ/λnα−1du

1/2

<Re

Ipδ, λ, fz

zp

β/2 <

λnα

1

0

1−Au

1−Buu

pβ/λnα−1du

1/2 .

3.73

Corollary 3.21. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0 and−1≤A < B1. Then

λnα

1

0

1Au

1Buu

pβ/λnα−1du

1/2

<Re

Ipδ, λ, fz

zp

β/2 <

λnα

1

0

1−Au

1−Buu

pβ/λnα−1du

1/2 .

(21)

Theorem 3.22. Let

fz zp

kn

apkzpk∈ßpα,βδ, λ, ;n;A, B. 3.75

Then

apn

1

pλnδ

AB

pβλnα

. 3.76

The inequality3.76is sharp, with extremal function defined by3.67.

Proof. Combining1.16and3.75, we obtain

1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

1

1 λnα

pλn

p

δ

βapnzn· · · ≺ 1Az 1Bz.

3.77

An application of Lemma2.8to3.77yields

1 λnα

pλn

p

δ

βapn

≤ |AB|. 3.78

Thus, from3.78, we easily arrive at3.76asserted by Theorem3.22.

Theorem 3.23. Let 0∈R, β∈R, β/α >0, λ >pand 0ρ <1. Iffz∈ßα,βp δ, λ, ;n;A,0

with

AAn

α, β, λ, ρ, p

1−ρ|α|1λnα/pβ

1αρα1

1λnα/pβ2

, 3.79

then

Ipδ, λ, fzSp,n

ρp−1−ρλ. 3.80

Proof. Suppose thatfz∈ßα,βp δ, λ, ;n;A,0. By definition, we have

1−α

Ipδ, λ, fz

zp

β

α

Ipδ1, λ, fz

Ipδ, λ, fz

Ipδ, λ, fz

zp

β

≺1Az zU.

(22)

Let the functionPzbe defined by3.2. We then find from3.1and3.81that

Pz

λnα z

pβ/λnα

z

0

1Attpβ/λnα−1dt1

pβA

λnαpβz. 3.82

We now suppose that

Ipδ1, λ, fz

Ipδ, λ, fz

1−ρqz ρ 0≤ρ <1; zU. 3.83

ThenqzH1, n. It follows from3.81and3.83that

Pz'1−α α 1−ρqz ρ(≺1Az zU. 3.84

An application of Lemma2.9to3.84yields

Reqz>0 zU. 3.85

Combining3.83and3.85, we find that

Re

Ipδ1, λ, fz

Ipδ, λ, fz

1−ρReqzρ > ρ zU. 3.86

The assertion of Theorem3.23can now easily be derived from1.8and3.86.

Theorem 3.24. Letfz ∈ßα,βρ δ, λ, ;n;A,0withβ >0, A >0,Reα >0, and|α|nRep

β/λα> Apβ/λ. Then

zIpδ, λ, fz

Ipδ, λ, fz

p< A

λ|α|nRepβ/λαpβ

λ|α| λ|α|nRepβ/λαApβ . 3.87

Proof. Let the functionPzbe defined by3.2. It follows from3.3that

pz λαzp

z

1Awz, 3.88

where

wz

kn

wkzk nN 3.89

(23)

pz 1A

λα

1

0

tpβ/λα−1wtzdt

1A

λα

kn

1

kpβ/λαwkz

k.

3.90

It follows from3.90that

zpz1A

λα

kn

k1

kpβ/λαwkz

k

1A

λα

kn

1

kpβ/λαwkz

k

A

λα

wz

λα

1

0

tp/λα−1wtzdt

.

3.91

We next find from3.90and3.91that

zpz A

λα

wz

λα

1

0

tpβ/λα−1wtzdt

A

λα

kn

k

kpβ/λαwkz

k.

3.92

Now from3.88we get

zppzz< nRe

pβ/λαpβ/λ|α|

pz , 3.93

and from3.90we get

pz 1A

λα

kn

1

kpβ/λαwkz

k

> λ|α|

nRepβ/λαApβ

λ|α|nRepβ/λα ,

3.94

from3.93and3.94, we get

zppzz< A

λ|α|nRepβ/λαpβ

λ|α| λ|α|nRepβ/λαApβ . 3.95

(24)

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(26)

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