Volume 2011, Article ID 752341,25pages doi:10.1155/2011/752341
Research Article
Some Properties of Certain Multivalent Analytic
Functions Involving the C ˘atas Operator
E. A. Elrifai, H. E. Darwish, and A. R. Ahmed
Department of Mathematics, Faculty of Science, University of Mansoura, Mansoura 35516, Egypt
Correspondence should be addressed to H. E. Darwish,[email protected]
Received 2 March 2011; Accepted 8 May 2011
Academic Editor: Marco Squassina
Copyrightq2011 E. A. Elrifai et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
We introduce a certain subclass of multivalent analytic functions by making use of the principle of subordination between these functions and C˘atas operator. Such results as subordination and superordination properties, convolution properties, inclusion relationships, distortion theorems, inequality properties, and sufficient conditions for multivalent starlikeness are provide. The results presented here would provide extensions of those given in earlier works. Several other new results are also obtained.
1. Introduction
LetApndenote the class of functions of the following form:
fz zp
∞
kn
apkzpk
p, n∈N:{1,2,3, . . .}, 1.1
which are analytic in the open unit diskU:{z:z∈Cand |z|<1}. For simplicity, we write
Ap1:Ap, A11 A. 1.2
A functionfz∈Apnis said to be in the classS∗p,nγofp-valent starlike functions of order
Re
zfz
fz
> γ 0≤γ < p;z∈U. 1.3
LetHa, nbe the class of analytic functions of the following form:
Fz aanznan1zn1· · · z∈U. 1.4
Letf, g∈Apn, wherefzis given by1.1andgzis defined by
gz zp
∞
kn
bpkzpk. 1.5
Then the Hadanard productor convolutionf∗gof the functionsfzandgzis defined by
f∗gz:zp
∞
kn
apkbpkzpk:
g∗fz. 1.6
We consider the following multiplier transformations.
Definition 1.1see1. Letfz∈Apn. Forp, n ∈N, δ, λ ≥ 0, ≥ 0, define the multiplier
transformationsIpδ, λ, onApnby the following infinite series:
Ipδ, λ, fz:zp
∞
kn
pλk
p
δ
akpzkp. 1.7
It is easily verified from1.7, that
pIpδ1, λ, fz p1−λ
Ipδ, λ, fz λz
Ipδ, λ, fz
. 1.8
It should be remarked that the class of multiplier transforms Ipδ, λ, is a generalization of several other linear operators considered, in earlier investigationssee2–
12.
Iffzis given by1.1, then we have
Ipδ, λ, fz
f∗ϕδp,λ,z, 1.9
where
ϕδ
p,λ,z zp
∞
kn
pλk
p
δ
In particular, we set
I1δ, λ, fz:Iδ, λ, fz. 1.11
For two functions fz and gz, analytic in U, we say that the function fz is subordinate togzin U, and writefz ≺ gz z ∈ Uif there exists a Schwarz function
wz, which is analytic in U with
w0 0, |wz|<1 z∈U 1.12
such that
fz gwz z∈U. 1.13
Indeed, it is known that
fz≺gz, z∈U ⇒f0 g0, fU⊂gU. 1.14
Furthermore, if the function g is univalent in U, then we have the following equivalence:
fz≺gz, z∈U⇐⇒f0 g0, fU⊂gU. 1.15
By making use of the linear operator Ipδ, λ, and the above-mentioned principle of subordination between analytic functions, we introduce and investigate the following subclass of the classApnofp-valent analytic functions.
Definition 1.2. A functionfz∈Apnis said to be in the class ßα,βp δ, λ, , n;A, Bif it satisfies
the following subordination condition:
1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
≺ 1Az
1Bz z∈U,
1.16
whereand throughout this paper unless otherwise mentionedthe parametersα, β, p, n, λ, δ, , A, andBare constrained as follows:
α∈C,Reβ>0, λ, ≥0, λ, ∈R, δ≥0, −1≤B≤1, A /B∈R, p, n∈N. 1.17
For simplicity, we write
ß11,β1,1,1; 1; 1,−1 ßβ. 1.18
If we setδ 0, λ p 1 in the class ßα,βp δ, λ, , n;A, B, which was studied by Liu13. In particular, Zhu14determined the sufficient conditions such that ßnα, β, A,0⊂
S∗p,nρ.
C˘atas 1, 5, 15, Cho and Srivastava 6, Cho and Kim 7, and Kumar et al. 10
obtained many interesting results associated with the multiplier operator.
In the present paper, we aim at proving such results as subordination and super-ordination properties, convolution properties, inclusion relationships, distortion theorems, inequality properties, and sufficient conditions for multivalent starlikeness of the class
ßα,βp δ, λ, , n;A, B. The results presented here would provide extensions of those given in
earlier works. Several other new results are also obtained.
2. Preliminary Results
In order to establish our main results, we need the following definition and lemmas.
Definition 2.1 see 16. Denote by Q the set of all functions fz that are analytic and
injective onU−Ef, where
Ef
ε∈∂U: lim
z→εfz ∞
, 2.1
and such thatfε/0 forε∈∂U−Ef.
Lemma 2.2see17. Let the functionhbe analytic and univalent (convex) inUwithh0 1.
Suppose also that the functionkgiven by
kz 1cnzncn1zn1· · · 2.2
is analytic inU. If
kz zkz
ζ ≺hz Reζ>0; ζ /0; z∈U, 2.3
then
kz≺χz ζ
nz
−ζ/n
z
0
tζ/n−1htdt≺hz z∈U, 2.4
andχzis the best dominant of2.3.
Lemma 2.3see18. Letqzbe a convex univalent function inUand letσ, η∈Cwith
Re
1zq
z
qz
>max
0,−Re
σ η
If the functionpis analytic inUand
σpz ηzpz≺σqz ηzqz, 2.6
thenpz≺qzandqzis the best dominant.
Lemma 2.4see16. Letqbe convex univalent inUandk∈C. Further assume that Rek>0 if
pz∈H q0,1∩Q, 2.7
andpz kzpzis univalent inU, then
qz kzqz≺pz kzpz 2.8
implies thatqz≺pzandqzis the best subdominant.
Lemma 2.5Jach’s Lemma19. Letwzbe a noncostant analytic function inUwithw0 0.
If|w|attains its maximum value on the circle|z|r <1 atz0, then
z0wz0 kwz0, 2.9
wherek≥1 is a real number.
Lemma 2.6see20. LetFbe analytic and convex inU. Iffz, gz∈Aandfz, gz≺Fz;
then
λfz 1−λgz≺Fz 0≤λ≤1. 2.10
Lemma 2.7see21,22. Letk, v∈C. Suppose also that m is convex and univalent inUwith
m0 1, Rekmz v>0 z∈U. 2.11
Ifuis analytic inUwithu0 1, then the following subordination:
uz zu
z
kuz v≺mz, z∈U 2.12
implies that
uz≺mz z∈U. 2.13
Lemma 2.8see23. Letfz 1∞k1akzkanalytic inUandgz 1∞k1bkzkbe analytic
Lemma 2.9see24. Letδ /0, δ∈R, v/δ >0,0≤ρ <1, p∈H1, n, andpz≺1kzk:
vM/nδv, where
M:Mn
δ, ν, ρ
1−ρ|δ|1nδ/v
1−δρδ1 nδ/v2. 2.14
Ifqz∈H1, nsatisfies the following subordination condition:
pz 1−δδ1−ρqz ρ≺1Mz, 2.15
then
Reqz>0 z∈U. 2.16
3. Main Results
We begin by presenting our first subordination property given by Theorem3.1below.
Theorem 3.1. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0. Then
Ipδ, λ, fz
zp
β
≺
pβ
λnα
1
0
1Azu
1Bzuu
pβ/λnα−1du≺ 1Az
1Bz z∈U. 3.1
Proof. Define the functionPzby
Pz:
Ipδ, λ, fz
zp
β
z∈U. 3.2
ThenPzis analytic inUwithP0 1. By taking the derivatives in the both sides in equality
3.2and using1.8, we get
1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
Pz λαzPz
βp ≺
1Az
1Bz z∈U.
An application of Lemma2.2to3.3yields
Ipδ, λ, fz
zp
β
≺
pβ
λnα z
−pβ/λnα
z
0
tpβ/λnα−11At
1Btdt
ζ
n
1
0
uζ/n−11Azu
1Bzudu≺
1Az
1Bz z∈U,
3.4
where
ζ
pβ
λα . 3.5
The proof of Theorem3.1is thus completed.
Theorem 3.2. Letqzbe univalent inU, 0/α∈C. Suppose also thatqzsatisfies
Re
1zq
z
qz
>max
0,−Re
pβ
λα
. 3.6
Iffz∈Apnsatisfying the following subordination:
1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
≺qz αλzq
z
pβ,
3.7
then
Ipδ, λ, fz
zp
β
≺qz, 3.8
andqzis the best dominant.
Proof. Let the functionPzbe defined by3.2. We know that3.3holds true. Combining
3.3and3.7, we find that
Pz λαzP
z
pβ ≺qz
λαzqz
pβ. 3.9
Takingqz 1Az/1Bzin Theorem3.2, we get the following result.
Corollary 3.3. Letα∈Cand−1 ≤B < A ≤1. Suppose also that1Az/1Bzsatisfies the
condition3.6. Iffz∈Apnsatisfies the following subordination:
1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
≺ 1Az
1Bz
λαA−Bz
pβ1Bz2,
3.10
then
Ipδ, λ, fz
zp
β
≺ 1Az
1Bz, 3.11
and1Az/1Bzis the best dominant.
Iffzis subordinate toFz, thenFzis superordinate tofz. We now derive the following
superordination result for the class ßα,βp δ, λ, ;n;A, B.
Theorem 3.4. Letqzbe convex univalent inU, α∈C, with Reα>0. Also let
Ipδ, λ, fz
zp
β
∈H q0,1∩Q,
1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β 3.12
be univalent inU. If
qz λαzq
z
pβ ≺1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
,
3.13
then
qz≺
Ipδ, λ, fz
zp
β
, 3.14
Proof. Let the functionPzbe defined by3.2. Then
qz λαzq
z
pβ ≺1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
Pz λαzP z
pβ.
3.15
An application of Lemma2.4yields the assertion of Theorem3.4.
Takingqz 1Az/1Bzin Theorem3.4, we get the following corollary.
Corollary 3.5. Letqzbe convex univalent inUand−1≤B < A≤1, α∈Cwith Reα>0. Also
let
Ipδ, λ, fz
zp
β
∈H q0,1∩Q,
1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β 3.16
be univalent inU. If
1Az
1Bz
λαA−Bz
pβ1Bz2
≺1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
,
3.17
then
1Az
1Bz ≺
Ipδ, λ, fz
zp
β
, 3.18
and1Az/1Bzis best subdominant.
Corollary 3.6. Letq1zbe convex univalent and letq2zbe univalent inU,α∈C, Reα>0. Let
q2zsatisfies3.6. If
0/
Ipδ, λ, fz
zp
β
∈H q10,1
∩Q,
1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β 3.19
is univalent inU, also
q1z
λαzq1z
pβ ≺1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
≺q2z
λαzq2z
pβ,
3.20
then
q1z≺
Ipδ, λ, fz
zp
β
≺q2z, 3.21
andq1z, q2zare, respectively, the best subordinate, and dominant.
Theorem 3.7. Letfz∈Apn, ξ∈C\ {0}, and 0≤γ <1. Also let the functionϕbe defined by
ϕz
zIpδ1, λ, fz/Ipδ, λ, fz
Ipδ, λ, fz/zp
β− 1
Ipδ1, λ, fz/Ipδ, λ, fz
Ipδ, λ, fz/zp
β−
1 z∈U.
3.22
Ifϕsatisfies one of the following conditions:
Reϕz
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
< 1
|ξ|2Reξ Reξ>0, /
0 Reξ 0,
> 1
|ξ|2Reξ Reξ<0,
or
Iϕz
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
>− 1
|ξ|2Iξ Iξ>0, /
0 Iξ 0,
<− 1
|ξ|2Iξ Iξ<0,
3.24
then
⎛ ⎝
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
−1
⎞ ⎠
ξ
<1−γ. 3.25
Proof. We define the functionφzby
⎛ ⎝
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
−1
⎞ ⎠
ξ
1−γφz 0≤γ <1;ξ∈C\ {0};z∈U.
3.26
It is easy to see that the functionφis analytic inUwithφ0 0.
Differentiating both sides of3.26with respect tozlogarithmically, we get
zφz
φz
ξ
zIpδ1, λ, fz/Ipδ, λ, fz
Ipδ, λ, fz/zp
β− 1
Ipδ1, λ, fz/Ipδ, λ, fz
Ipδ, λ, fz/zp
β−
1 z∈U;ξ∈C\ {0}.
3.27
We now consider the functionϕdefined by
ϕ: ξ
|ξ|2
zφz
φz z∈U, ξ∈C\ {0}. 3.28
Assume that there exists a pointz0∈Usuch that
max
|z|≤|z0|
φzφz01, 3.29
by Lemma2.5, we know that
If follows from3.28and3.30that
Reϕz0
Re
ξ
|ξ|2
zφz0
φz0
k
|ξ|2Re
ξ
k |ξ|2Reξ
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
≥ 1
|ξ|2 Reξ Reξ>0,
0 Reξ 0
≤ 1
|ξ|2 Reξ Reξ<0,
3.31
Iϕz0
I
ξ
|ξ|2
zφz0
φz0
k
|ξ|2I
ξ
−k |ξ|2Iξ
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
≤ − 1
|ξ|2Iξ Iξ>0,
0 Iξ 0,
≥ − 1
|ξ|2Iξ Iξ<0.
3.32
But the inequalities in3.31and3.32contradict, respectively, the inequalities in3.23and
3.24. Therefore, we can conclude that
φz<1 z∈U, 3.33
which implies that
⎛ ⎝
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
−1
⎞ ⎠
ξ
1−γφz<1−γ. 3.34
We thus complete the proof of Theorem3.7.
From Theorem3.7, we easily get the following result for the class ßβ of Bazileviˇc functions of typeβ.
Corollary 3.8. Letfz∈A, δ0, pλξ1, andγ 0. Also let the functionϕbe defined
by3.22. Ifϕsatisfies one of the following conditions:
Reϕz<1 or Iϕz/0, 3.35
Theorem 3.9. Let Reα > 0, β > 0, and fz ∈ ßp0,βδ, λ, ;n; 1−2ρ,−1 0 ≤ ρ < 1. Then
fz∈ßα,βp δ, λ, ;n,1−2ρ,−1for|z|< Rα, β, , λ, p, where
Rα, β, , λ, p −λα
λ2α2p2β2
ρβ . 3.36
The boundRα, β, , λ, pis the best possible.
Proof. Suppose that
Ipδ, λ, fz
zp
β
ρ1−ρhz z∈U; 0≤ρ <1, 3.37
wherehis analytic and has a positive real part inU. By taking the derivatives in the both sides in equality3.37and using1.9, we get
Re
⎛ ⎝1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β⎞
⎠−ρ
1−ρRe
hz λαzh
z
pβ
≥1−ρRe
hz−λα|zhz|
pβ
.
3.38
By making use of the following well-known estimatesee25:
zhz≤ 2r
1−r2 Rehz |z|r <1 3.39
in3.38, we obtain that
Re
⎡ ⎣1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
−ρ
⎤ ⎦
1−ρ
1− 2λαr
pβ1−r2
Rehz>0
3.40
To show that the boundRα, β, , λ, pis the best possible, we consider the function
fz∈Apndefined by
Ipδ, λ, fz
zp
β
ρ1−ρ1z
1−z z∈U. 3.41
By noting that
Re
⎛ ⎝1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β⎞
⎠−ρ
1−ρRe
1z
1−z
2λα
pβ
z
1−z2
0
3.42
forz Rα, β, , λ, p, we conclude that the bound is the best possible. Theorem3.9is thus
proved.
Theorem 3.10. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0. Then
fz
zp
1Awz
1Bwz
1/β
∗
zp
∞
kn
pλk
p
−δ
zkp
, 3.43
wherewzis analytic inUwithw0 0 and|wz|<1 z∈U.
Proof. Suppose thatfz∈ßα,βp δ, λ, ;n;A, B. It follows from3.1that
Ipδ, λ, fz
zp
β
1Awz
1Bwz, 3.44
wherewzis analytic inUwithw0 0 and|wz|<1z∈U. By virtue of3.44, we easily find that
Ipδ, λ, fz zp
1Awz
1Bwz
1/β
. 3.45
Combining1.10,1.16, and3.45, we have
zp
∞
kn
pλk
p
δ
zkp
∗fz zp
1Awz
1Bwz
1/β
. 3.46
Theorem 3.11. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0. Then
1
z
#
1Biθ1/β
zp
∞
kn
pλk
p
−δ
zkp
∗fz−zp1Aeiθ1/β
$
/
0 z∈U; 0< θ <2π.
3.47
Proof. Suppose thatfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0. We know that3.1holds true,
which implies that
Ipδ, λ, fz
zp
β
/
1Aeiθ
1Beiθ z∈U; 0< θ <2π. 3.48
It is easy to see that the condition3.48can be written as follows:
1
z
Ipδ, λ, fz
1Beiθ1/β−zp1Aiθ1/β
/
0 z∈U; 0< θ <2π. 3.49
Combining1.9,1.10, and3.49, we easily get the convolution property3.47asserted by Theorem3.11.
Theorem 3.12. Letα2≥α1≥0 and−1≤B1≤B2 < A2< A1≤1. Then
ßα2,β
p δ, λ, ;n;A2, B2⊂ßpα1,βδ, λ, ;n;A1, B1. 3.50
Proof. Suppose thatfz∈βα2,β
p δ, λ, ;n;A2, B2. We know that
1−α2
Ipδ, λ, fz
zp
β
α2
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
≺ 1A2z
1B2z .
3.51
Since−1≤B1≤B2< A2≤A1≤1, we easily find that
1−α2
Ipδ, λ, fz
zp
β
α2
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
≺ 1A2z
1B2z ≺
1A1z
1B1z
3.52
that is,fz∈ßα2,β
Ifα2 > α1 ≥ 0, by Theorem3.1and3.52, we know thatfz∈ß0p,βδ, λ, ;n;A1, B1,
that is,
Ipδ, λ, fz
zp
β
≺ 1A1z
1B1z
. 3.53
At the same time, we have
1−α1
Ipδ, λ, fz
zp
β
α1
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
1−α1
α2
I
pδ, λ, fz
zp
β
α1 α2
⎡ ⎣1−α2
Ipδ, λ, fz
zp
β
α2
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β⎤
⎦.
3.54
Moreover, since 0≤α1/α2<1 andh1z: 1A1z/1B1z, is analytic and convex in
U. Combining3.52–3.54and Lemma2.6, we find that
1−α1
Ipδ, λ, fz
zp
β
α1
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
≺ 1A1z
1B1z,
3.55
that is,fz∈ßα1,β
p δ, λ, ;n;A1, B1, which implies that the assertion3.50of Theorem3.12
holds.
Letρdenote the class of functions of the following form:
tz 1
∞
kn
tkzk n∈N, 3.56
which are analytic and convex inUand satisfy the following condition:
Retz>0 z∈U. 3.57
S∗p,nμ, φ:
f∈Apn:
1
p−μ
zfz
fz −μ
≺φzφ∈ρ; 0≤μ < p;z∈U,
Cp,n
μ;φ
fz∈Apn:
1
p−μ
1zf
z
fz −μ
≺φzφ∈ρ; 0≤μ < p;z∈U.
3.58
Next, by using the operator defined by 1.7, we define the following two subclasses
Sp,nδ, λ, ;μ;φandCp,nδ, λ, ;μ;φof the classApn:
Sp,n
δ, λ, ;μ;φ:%fz∈Apn:Ipδ, λ, fz∈S∗p,n
μ;φ&,
Cp,n
δ, λ, ;μ;φ:'fz∈Apn:Ipδ, λ, fz∈Cp,n
μ;φ(.
3.59
Clearly, we know that
f∈Cp,n
δ, λ, ;μ;φ⇐⇒ zf
z
p ∈Sp,n
δ, λ, ;μ;φ. 3.60
We now derive some inclusion relationships for the classes Sp,nδ, λ, ;μ;φ and
Cp,nδ, λ, ;μ;φ, by similarly applying the method of proof of Proposition 1 obtained by Cho
et al.26and Wang et al.27.
Theorem 3.13. Let 0≤μ < p, λ >−p, andφ∈ρwith
Reφz>max
0,−δμ
p−μ,−
λμ−p
p−μ
z∈U. 3.61
Then
Sp,n
δ1, λ, ;μ;φ⊂Sp,n
δ, λ, ;μ;φ⊂Sp,n
δ, λ1, ;μ;φ. 3.62
Theorem 3.14. Let 0≤μ < p, λ >−pandφ∈ρwith3.61holds. Then
Cp,n
δ1, λ, ;n;μ;φ⊂Cp,n
δ, λ, ;μ;φ⊂Cp,n
δ, λ1, ;μ;φ. 3.63
Proof. By virtue of3.60and Theorem3.13, we observe that
fz∈Cp,n
δ1, λ, ;μ;φ⇐⇒Ipδ1, λ, fz∈Cp,n
μ;φ
⇐⇒z
Ipδ1, λ, fz
p ∈S
∗
p,n
μ;φ
⇐⇒Ipδ1, λ,
zfz
p
∈S∗p,nμ;φ
⇒ zfz
p ∈Sp,n
⇐⇒zfz
p ∈Sp,n
δ, λ, ;μ;φ
⇐⇒Ipδ, λ,
zfz
p
∈S∗p,nμ, φ
⇐⇒z
Ipδ, λ, fz
p ∈S
∗
p,n
μ;φ
⇐⇒Ipδ, λ, fz∈Cp,n
μ;φ
⇐⇒fz∈Cp,n
δ, λ, ;μ;φ,
fz∈Cp,n
δ, λ, ;μ;φ⇐⇒zf
z
p ∈Sp,n
δ, λ, ;μ;φ
⇒ zfz
p ∈Sp,n
δ, λ1, ;μ;φ
⇐⇒z
Ipδ, λ1, fz
p ∈S
∗
p,n
μ;φ
⇐⇒Ipδ, λ1, fz∈Cp,n
μ;φ
⇐⇒fz∈Cp,n
δ, λ1, ;μ;φ.
3.64
From3.64, we conclude that the assertion of Theorem3.14holds true.
Takingφz 1Az/1Bzin Theorems3.13and3.14, we get the following results.
Corollary 3.15. Let 0≤μ < p, λ >−p, and−1≤B < A≤1. Then
Sp,n
δ1, λ, ;μ;1Az
1Bz
⊂Sp,n
δ, λ, ;μ,1Az
1Bz
⊂Sp,n
δ, λ1, ;μ;1Az
1Bz
,
Cp,n
δ1, λ, ;μ;1Az
1Bz
⊂Cp,n
δ, λ, ;μ,1Az
1Bz
⊂Cp,n
δ, λ1, ;μ;1Az
1Bz
.
3.65
Theorem 3.16. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0 and−1≤B < A≤1. Then
pβ
λnα
1
0
1−Au
1−Buu
pβ/λnα−1du < Re
Ipδ, λ, fz
zp
β
<
pβ
λnα
1
0
1Au
1Buu
pβ/λnα−1du.
The extremal function of 3.66is defined by
Ipδ, λ, Fα,β,A,Bz zp
pβ λαn
1
0
1Azu
1Bzuu
pβ/λnα−1du
1/β
. 3.67
Proof. Letfz∈ ßα,βp δ, λ, ;n;A, Bwith Reα> 0. From Theorem3.1, we know that3.1
holds, which implies that
Re
Ipδ, λ, fz
zp
β
<sup
z∈U Re
pβ
λαn
1
0
1Azu
1Bzuu
pβ/λnα−1du
≤
pβ
λnα
1
0
sup z∈U
Re
1Azu
1Bzu
upβ/λnα−1du
<
pβ
λnα
1
0
1Au
1Buu
pβ/λnα−1du,
Re
Ipδ, λ, fz
zp
β
> inf
z∈URe
pβ
λnα
1
0
1Azu
1Bzuu
pβ/λnα−1du
≥
pβ
λnα
1
0
inf z∈URe
1Azu
1Bzuu
pβ/λnα−1du
>
pβ
λnα
1
0
1−Au
1−Buu
pβ/λnα−1du.
3.68
Combining both equations of 3.68, we get 3.66. By noting that the function Ipδ, λ,
Fα,β,A,Bz defined by 3.67 belongs to the class ßα,βp δ, λ, ;n;A, B, we obtain that the equality3.66is sharp. The proof of Theorem3.16is evidently completed.
By similarly applying the method of proof of Theorem3.16, we easily get the following result.
Corollary 3.17. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0 and−1≤A < B≤1. Then
pβ
λnα
1
0
1Au
1Buu
pβ/λnα−1du
<Re
Ipδ, λ, fz
zp
β
<
pβ
λnα
1
0
1−Au
1−Buu
pβ/λnα−1du.
3.69
The extremal function of 3.69is defined by3.67.
Corollary 3.18. Letfz ∈ ßα,βp δ, λ, ;n;A, Bwith Reα > 0 and−1 ≤ B < A ≤ 1. Then for
|z|r <1, we have
rp
pβ
λnα
1
0
1−Aur
1−Buru
pβ/λnα−1du
1/β
<Ipδ, λ, fz< rp
pβ λnα
1
0
1Aur
1Buru
pβ/λnα−1du
1/β
.
3.70
The extremal function of 3.70is defined by3.67.
Corollary 3.19. Letfz ∈ ßα,βp δ, λ, ;n;A, Bwith Reα > 0 and−1 ≤ A < B ≤ 1. Then for
|z|r <1, we have
rp
pβ
λnα
1
0
1Aur
1Buru
pβ/λnα−1du
1/β
<Ipδ, λ, fz< rp
pβ λnα
1
0
1−Aur
1−Buru
pβ/λnα−1du
1/β
.
3.71
The extremal function of 3.71is defined by3.67.
By noting that
Reν1/2≤Reν1/2≤ |ν|1/2 ν∈C; Reν≥0. 3.72
From Theorem3.16and Corollary3.17, we easily get the following results.
Corollary 3.20. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0 and−1≤B < A≤1. Then
pβ
λnα
1
0
1−Au
1−Buu
pβ/λnα−1du
1/2
<Re
Ipδ, λ, fz
zp
β/2 <
pβ
λnα
1
0
1−Au
1−Buu
pβ/λnα−1du
1/2 .
3.73
Corollary 3.21. Letfz∈ßα,βp δ, λ, ;n;A, Bwith Reα>0 and−1≤A < B≤1. Then
pβ λnα
1
0
1Au
1Buu
pβ/λnα−1du
1/2
<Re
Ipδ, λ, fz
zp
β/2 <
pβ
λnα
1
0
1−Au
1−Buu
pβ/λnα−1du
1/2 .
Theorem 3.22. Let
fz zp
∞
kn
apkzpk∈ßpα,βδ, λ, ;n;A, B. 3.75
Then
apn≤
pδ1
pλnδ
A−B
pβλnα
. 3.76
The inequality3.76is sharp, with extremal function defined by3.67.
Proof. Combining1.16and3.75, we obtain
1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
1
1 λnα
pβ
pλn
p
δ
βapnzn· · · ≺ 1Az 1Bz.
3.77
An application of Lemma2.8to3.77yields
1 λnα
pβ
pλn
p
δ
βapn
≤ |A−B|. 3.78
Thus, from3.78, we easily arrive at3.76asserted by Theorem3.22.
Theorem 3.23. Let 0/α∈R, β∈R, β/α >0, λ >−pand 0≤ρ <1. Iffz∈ßα,βp δ, λ, ;n;A,0
with
AAn
α, β, λ, ρ, p
1−ρ|α|1λnα/pβ
1−αρα1
1λnα/pβ2
, 3.79
then
Ipδ, λ, fz∈S∗p,n
ρp−1−ρλ. 3.80
Proof. Suppose thatfz∈ßα,βp δ, λ, ;n;A,0. By definition, we have
1−α
Ipδ, λ, fz
zp
β
α
Ipδ1, λ, fz
Ipδ, λ, fz
Ipδ, λ, fz
zp
β
≺1Az z∈U.
Let the functionPzbe defined by3.2. We then find from3.1and3.81that
Pz≺
pβ
λnα z
−pβ/λnα
z
0
1Attpβ/λnα−1dt1
pβA
λnαpβz. 3.82
We now suppose that
Ipδ1, λ, fz
Ipδ, λ, fz
1−ρqz ρ 0≤ρ <1; z∈U. 3.83
Thenqz∈H1, n. It follows from3.81and3.83that
Pz'1−α α 1−ρqz ρ(≺1Az z∈U. 3.84
An application of Lemma2.9to3.84yields
Reqz>0 z∈U. 3.85
Combining3.83and3.85, we find that
Re
Ipδ1, λ, fz
Ipδ, λ, fz
1−ρReqzρ > ρ z∈U. 3.86
The assertion of Theorem3.23can now easily be derived from1.8and3.86.
Theorem 3.24. Letfz ∈ßα,βρ δ, λ, ;n;A,0withβ >0, A >0,Reα >0, and|α|nRep
β/λα> Apβ/λ. Then
zIpδ, λ, fz
Ipδ, λ, fz −
p< A
pβ λ|α|nRepβ/λαpβ
λ|α| λ|α|nRepβ/λα−Apβ . 3.87
Proof. Let the functionPzbe defined by3.2. It follows from3.3that
pz λαzp
z
pβ 1Awz, 3.88
where
wz
∞
kn
wkzk n∈N 3.89
pz 1A
pβ
λα
1
0
tpβ/λα−1wtzdt
1A
pβ
λα
∞
kn
1
kpβ/λαwkz
k.
3.90
It follows from3.90that
zpz1A
pβ
λα
∞
kn
k1
kpβ/λαwkz
k
1A
pβ
λα
∞
kn
1
kpβ/λαwkz
k
A
pβ
λα
wz−
pβ
λα
1
0
tp/λα−1wtzdt
.
3.91
We next find from3.90and3.91that
zpz A
pβ
λα
wz−
pβ
λα
1
0
tpβ/λα−1wtzdt
A
pβ
λα
∞
kn
k
kpβ/λαwkz
k.
3.92
Now from3.88we get
zppzz< nRe
pβ/λαpβ/λ|α|
pz , 3.93
and from3.90we get
pz 1A
pβ
λα
∞
kn
1
kpβ/λαwkz
k
> λ|α|
nRepβ/λα−Apβ
−λ|α|nRepβ/λα ,
3.94
from3.93and3.94, we get
zppzz< A
pβ λ|α|nRepβ/λαpβ
λ|α| λ|α|nRepβ/λα−Apβ . 3.95
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