Volume 2011, Article ID 915629,17pages doi:10.1155/2011/915629
Research Article
Iterative Algorithms for Finding Common
Solutions to Variational Inclusion Equilibrium and
Fixed Point Problems
J. F. Tan and S. S. Chang
Department of Mathematics, Yibin University, Yibin, Sichuan 644007, China
Correspondence should be addressed to S. S. Chang,[email protected]
Received 30 October 2010; Accepted 9 November 2010
Academic Editor: Qamrul Hasan Ansari
Copyrightq2011 J. F. Tan and S. S. Chang. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
The main purpose of this paper is to introduce an explicit iterative algorithm to study the existence problem and the approximation problem of solution to the quadratic minimization problem. Under suitable conditions, some strong convergence theorems for a family of nonexpansive mappings are proved. The results presented in the paper improve and extend the corresponding results announced by some authors.
1. Introduction
Throughout this paper, we assume thatHis a real Hilbert space with inner product·,·and norm · ,Cis a nonempty closed convex subset ofH, andFT {x∈H :Tx x}is the set of fixed points of mappingT.
A mappingS:C → Cis called nonexpansive if
Sx−Sy≤x−y, ∀x, y∈C. 1.1
Let A : H → H be a single-valued nonlenear mapping andM : H → 2H be a multivalued mapping. The so-called quasivariational inclusion problemsee1–3is to find
u∈Hsuch that
θ∈Au Mu. 1.2
Special Cases
IIfM∂φ:H → 2H, whereφ:H → Ê∪{∞}is a proper convex lower semi-continuous
function and∂φis the subdifferential ofφ, then the quasivariational inclusion problem1.2 is equivalent to findingu∈Hsuch that
Au, y−uφy−φu≥0, ∀y∈H, 1.3
which is called the mixed quasivariational inequalitysee4.
IIIfM ∂δC, whereCis a nonempty closed convex subset of H andδC : H →
0,∞is the indicator function ofC, that is,
δCx
⎧ ⎨ ⎩
0, x∈C,
∞, x /∈C, 1.4
then the quasivariational inclusion problem1.2is equivalent to findingu∈Csuch that
Au, v−u ≥0, ∀v∈C. 1.5
This problem is called the Hartman-Stampacchia variational inequalitysee5. The set of solutions to variational inequality1.5is denoted by VIA, C.
LetB : C → H be a nonlinear mapping andF : C×C → Ê be a bifunction. The
so-called generalized equilibrium problem is to find a pointu∈Csuch that
Fu, yBu, y−u ≥0, ∀y∈C. 1.6
The set of solutions to1.6is denoted by GEPsee5,6. IfB0, then1.6reduces to the following equilibrium problem: to findu∈Csuch that
Fu, y≥0, ∀y∈C. 1.7
The set of solutions to1.7is denoted by EP.
Iterative methods for nonexpansive mappings and equilibrium problems have been applied to solve convex minimization problemssee7–9. A typical problem is to minimize a quadratic function over the set of the fixed points of a nonexpansive mapping on a real Hilbert spaceH:
min x∈F
1 2x
2, 1.8
whereFis the fixed point set of a nonexpansive mappingTonH.
In 2010, Zhang et al.see10proposed the following iteration method for variational inclusion problem1.5and equilibrium problem1.6in a Hilbert spaceH:
Under suitable conditions, they proved the sequence {xn} generated by 1.9 converges strongly to the fixed pointx∗, which solves the quadratic minimization problem1.8.
Motivated and inspired by the researches going on in this direction, especially inspired by Zhang et al.10, the purpose of this paper is to introduce an explicit iterative algorithm to studying the existence problem and the approximation problem of the solution to the quadratic minimization problem 1.8 and prove some strong convergence theorems for a family of nonexpansive mappings in the setting of Hilbert spaces.
2. Preliminaries
LetHbe a real Hilbert space, andCbe a nonempty closed convex subset ofH. For anyx∈H, there exists a unique nearest point inC, denoted byPCx, such that
x−PCx ≤x−y, ∀y∈C. 2.1
Such a mappingPC fromHontoCis called the metric projection. It is well-known that the metric projectionPC :H → Cis nonexpansive.
In the sequel, we usexn xandxn → xto denote the weak convergence and the strong convergence of the sequence{xn}, respectively.
Definition 2.1. A mappingA:H → His calledα-inverse strongly monotone if there exists anα >0 such that
Ax−Ay, x−y ≥αAx−Ay2, ∀x, y∈H. 2.2
A multivalued mappingM:H → 2His called monotone if∀x, y∈H, u∈Mx, v∈My,
u−v, x−y ≥0. 2.3
A multivalued mappingM:H → 2His called maximal monotone if it is monotone and for anyx, u∈H×H, when
u−v, x−y ≥0 for everyy, v∈GraphM, 2.4
thenu∈Mx.
Proposition 2.2see11. LetA: H → Hbe anα-inverse strongly monotone mapping. Then, the following statements hold:
iAis an1/α-Lipschitz continuous and monotone mapping;
Lemma 2.3see12. LetXbe a strictly convex Banach space,Cbe a closed convex subset ofX, and{Tn :C → C}be a sequence of nonexpansive mappings. Suppose∞n1FTn/∅. Let{λn}be a
sequence of positive numbers withΣ∞n1λn1. Then the mappingS:C → Cdefined by
Sx Σ∞
n1λnTnx, x∈C 2.5
is well defined. And it is nonexpansive and
FS ∞
n1
FTn. 2.6
Definition 2.4. Let H be a Hilbert space and M : H → 2H be a multivalued maximal monotone mapping. Then, the single-valued mappingJM,λ:H → Hdefined by
JM,λu IλM−1u, u∈H 2.7
is called theresolvent operator associated withM, whereλis any positive number andIis the identity mapping.
Proposition 2.5see11. iThe resolvent operatorJM,λassociated withMis single-valued and
nonexpansive for allλ >0, that is,
JM,λx−JM,λ
y≤x−y, ∀x, y∈H, ∀λ >0. 2.8
iiThe resolvent operatorJM,λis 1-inverse strongly monotone, that is,
JM,λx−JM,λy2≤x−y, J
M,λx−JM,λy , ∀x, y∈H. 2.9
Definition 2.6. A single-valued mappingA:H → His said to be hemicontinuous if for any
x, y, z∈H, functiont→ Axty, zis continuous at 0.
It is well-known that every continuous mapping must be hemicontinuous.
Lemma 2.7see13. Let{xn}and{yn}be bounded sequences in a Banach spaceX. Let{βn}be a
sequence in0,1with
0<lim inf
n→ ∞ βn ≤lim supn→ ∞ βn<1. 2.10
Suppose that
xn1
1−βnynβnxn, ∀n≥0,
lim sup n→ ∞
yn1−yn− xn1−xn
Then,
lim
n→ ∞yn−xn0. 2.12
Lemma 2.8see14. LetXbe a real Banach space,X∗be the dual space ofX,T :X → 2X∗be a maximal monotone mapping, andP :X → X∗be a hemicontinuous bound monotone mapping with
DP X. Then, the mappingSTP :X → 2X∗is a maximal monotone mapping.
Lemma 2.9see15. LetXbe a uniformly convex Banach space, letCbe a nonempty closed convex subset ofX, andT :C → Cbe a nonexpansive mapping with a fixed point. Then,I−Tis demiclosed in the sense that if{xn}is a sequence inCsatisfying
xn x, I−Tn−→0, 2.13
then
I−Tx0. 2.14
Throughout this paper, we assume that the bifunction F : C×C → Ê satisfies the
following conditions:
H1Fx, x 0 for allx∈C;
H2Fis monotone, that is,
Fx, yFy, x≤0, ∀x, y∈C, 2.15
H3for eachx, y, z∈C,
lim t↓0 F
tz 1−tx, y≤Fx, y, 2.16
H4for eachx∈C,y→Fx, yis convex and lower semi-continuous.
Lemma 2.10see16. LetHbe a real Hilbert space,Cbe a nonempty closed convex subset ofH, andF:C×C → Êbe a bifunction satisfying the conditions (H1)–(H4). Letμ >0andx∈H. Then,
there exists a pointz∈Csuch that
Fz, y 1
μ
y−z, z−x ≥0, ∀y∈C. 2.17
Moreover, ifTμ:H → Cis a mapping defined by
Tμx
z∈C:Fz, y1
μ
y−z, z−x ≥0, ∀y∈C
, x∈H, 2.18
iTμis single-valued and firmly nonexpansive, that is, for anyx, y∈H,
Tμx−Tμy2≤T
μx−Tμy, x−y , 2.19
iiEPis closed and convex, andEPFTμ.
Lemma 2.11. i see11u∈His a solution of variational inclusion1.2if and only if
uJM,λu−λAu, ∀λ >0, 2.20
that is,
VIH, A, M FJM,λu−λAu, ∀λ >0. 2.21
ii see10u∈Cis a solution of generalized equilibrium problem1.6if and only if
uTμu−μBu, ∀μ >0, 2.22
that is,
GEPFTμu−μBu, ∀μ >0. 2.23
iii see10LetA:H → Hbe anα-inverse strongly monotone mapping andB:C → H
be aβ-inverse strongly monotone mapping. Ifλ ∈ 0,2αandμ ∈ 0,2β, thenVIH, A, Mis a closed convex subset inHand GEP is a closed convex subset inC.
Lemma 2.12see17. Assume that{an}is a sequence of nonnegative real numbers such that
an1≤1−γnanδn, ∀n≥1, 2.24
where{γn}is a sequence in0,1and{δn}is a sequence such that:
i∞n1γn∞;
iilim supn→ ∞δn/γn≤0or∞n1|δn|<∞.
Then,limn→ ∞an0.
3. Main Results
Theorem 3.1. LetHbe a real Hilbert space,Cbe a nonempty closed convex subset ofH,A:H → H
mapping. LetM : H → 2H be a maximal monotone mapping,{Tn : C → C}be a sequence of
nonexpansive mappings with∞n1FTn/∅,S : C → Cbe the nonexpansive mapping defined by
2.5, andF:C×C → Êbe a bifunction satisfying conditions (H1)–(H4). Let{xn}be the sequence
defined by
xn1αnxn 1−αn
SPC1−tnJM,λI−λATμI−μBxn, 3.1
where the mappingTμ:H → Cis defined by2.18, andλ, μare two constants withλ∈0,2α, μ∈
0,2β, and
tn∈0,1, tn−→0n−→ ∞, ∞
n1
tn∞, 0< a < αn< b <1. 3.2
If
Ω:FS∩VIH, A, M∩GEP/∅, 3.3
whereVIH, A, Mand GEP is the set of solutions of variational inclusion1.2and generalized equilibrium problem1.6, respectively, then the sequence{xn}defined by3.1converges strongly to
x∗∈Ω, which is the unique solution of the following quadratic minimization problem:
x∗2min
x∈Ωx 2.
3.4
Proof. We divide the proof ofTheorem 3.1into four steps.
Step 1The sequence{xn}is bounded. Set
unTμI−μBxn, ynJM,λI−λAun, znSPC1−tnyn. 3.5
Takingz∈Ω, then it follows fromLemma 2.11that
zTμz−μBzJM,λz−λAz SPCz. 3.6
un−z2 TμI−μBxn−Tμz−μBz2
≤I−μBxn−z−μBz2
≤ xn−z2μμ−2βBxn−Bz2,
3.7
yn−z2 J
M,λI−λAun−JM,λz−λAz2
≤ I−λAun−z−λAz2
≤ un−z2λλ−2αAun−Az2
≤ xn−z2λλ−2αAun−Az2μμ−2βBxn−Bz2.
3.8
This implies that
yn−z≤ un−z ≤ xn−z. 3.9
It follows from3.1and3.9that
xn1−zαnxn 1−αnSPC1−tnyn−z
αnxn−z 1−αnSPC1−tnyn−SPCz
≤αnxn−z 1−αnSPC1−tnyn−SPCz
≤αnxn−z 1−αn1−tnyn−z
≤αnxn−z 1−αn1−tnyn−ztnz
≤αnxn−z 1−αn1−tnxn−ztnz
≤1−tn1−αnxn−ztn1−αnz
≤max{xn−z,z}
≤max{xn−1−z,z}
≤ · · · ≤max{x1−z,z}M,
3.10
whereMmax{x1−z,z}. This shows that{xn}is bounded. Hence, it follows from3.9 that the sequence{un}and{yn}are also bounded.
It follows from3.5,3.6, and3.9that
zn−zSPC1−tnyn−SPCz≤1−tnyn−z
≤1−tnyn−ztnz ≤1−tnxn−ztnz ≤M.
3.11
Step 2. Now, we prove that
lim
n→ ∞xn−unnlim→ ∞un−ynnlim→ ∞xn−yn0, lim
n→ ∞xn−Sxn0.
3.12
SinceSPCis nonexpansive, from3.5and3.9, we have that
yn1−yn≤ un1−un ≤ xn1−xn, 3.13
zn1−znSPC1−tn1yn1
−SPC1−tnyn
≤1−tn1yn1−1−tnyn
1−tn1
yn1−yn 1−tn1−1−tnyn
≤1−tn1yn1−yn|tn1−tn|yn
≤yn1−yn|tn1−tn|yn
≤ un1−un|tn1−tn|yn
≤ xn1−xn|tn1−tn|yn.
3.14
Letn → ∞in3.14, in view of conditiontn → 0n → ∞, we have
lim
n→ ∞zn1−zn − xn1−xn 0. 3.15
By virtue ofLemma 2.7, we have
lim
n→ ∞xn−zn0. 3.16
This implies that
lim
We derive from3.17that
lim n→ ∞
xn−z2− xn1−z2
lim n→ ∞
xn−xn122xn−xn1, xn1−z
≤ lim n→ ∞
xn−xn122xn−xn1 · xn1−z
0.
3.18
From3.1and3.8, we have
xn1−z2≤
αnxn−z 1−αn1−tnyn−z2
≤αnxn−z2 1−αn1−tnyn−z−tnz2
αnxn−z2 1−αn
1−tn2yn−z2−2tn1−tnz, yn−z t2nz2
≤αnxn−z2 1−αnyn−z2tnM1
≤αnxn−z2 1−αn
×xn−z2λλ−2αAun−Az2μμ−2βBxn−Bz2tnM1
xn−z2 1−αn
λλ−2αAun−Az2μμ−2βBxn−Bz2tnM1
,
3.19
where
M1sup n
z22λu
n−ynμxn−yn<∞, 3.20
that is,
1−αn
λ2α−λAun−Az2μ2β−μBxn−Bz2
≤ xn−z2− xn1−z2 1−αntnM1.
3.21
Letn → ∞, noting the assumptions thatλ ∈ 0,2α,μ ∈ 0,2β, from3.2and 3.18, we have
lim
By virtue ofLemma 2.10iand3.1, we have
un−z2Tμxn−μBxn−Tμz−μBz2
≤xn−μBxn−z−μBz, un−z
1
2
xn−μBxn−z−μBz2un−z2
−xn−z−μBxn−Bz−un−z2
≤ 1
2
xn−z2un−z2−xn−un−μBxn−Bz2
1
2
xn−z2un−z2− xn−un2
2μxn−un, Bxn−Bz −μ2Bxn−Bz2
.
3.23
Simplifying it, we have
un−z2≤ xn−z2− xn−un22μxn−un, Bxn−Bz −μ2Bxn−Bz2
≤ xn−z2− xn−un22μxn−un · Bxn−Bz
≤ xn−z2− xn−un2M1Bxn−Bz.
3.24
Similarly, in view ofProposition 2.5iiand3.1, we have
yn−z2J
M,λun−λAun−JM,λz−λAz2
≤un−λAun−z−λAz, yn−z
1
2
un−λAun−z−λAz2yn−z2
−un−λAun−z−λAz−yn−z2
≤ 1
2
un−z2yn−z2−un−yn−λAun−Az2
1
2
un−z2yn−z2−un−yn2
2λun−yn, Aun−Az −λ2Aun−Az2
.
Simplifying it, from3.24, we have
yn−z2≤ u
n−z2−un−yn22λun−yn, Aun−Az −λ2Aun−Az2
≤ un−z2−un−yn22λun−yn· Aun−Az
≤ xn−z2− xn−un2M1Bxn−Bz −un−yn2
M1Aun−Az.
3.26
From3.19and3.26, we have
xn1−z2≤αnxn−z2 1−αnyn−z2tnM1
≤αnxn−z2 1−αn
×xn−z2− xn−un2−un−yn2M1Bxn−BzAun−Aztn
xn−z2 1−αn
×M1Bxn−BzAun−Aztn− xn−un2−un−yn2
.
3.27
Letn → ∞nd in view of3.18and3.22, we have
lim n→ ∞
xn−un2un−yn2
0. 3.28
This shows that
lim
n→ ∞xn−unnlim→ ∞un−yn0, lim
n→ ∞xn−yn0.
3.29
Then, we have
xn1−Sxn1xn1−SxnSxn−Sxn1 ≤ xn1−SxnSxn−Sxn1
SPC1−tnyn−SPCxnSxn−Sxn1 ≤1−tnyn−xntnxnxn−xn1 −→0n−→ ∞.
Step 3sequence{xn}converges strongly tox∗ ∈Ω. Because{xn}is bounded, without loss of generality, we can assume thatxn x∗ ∈H. In view of3.12, it yields thatun x∗and
yn x∗. FromLemma 2.9and3.30, we know thatx∗ ∈FS. Next, we prove thatx∗∈GEP∩VIH, A, M.
SinceunTμxn−μBxn, we have
Fun, y 1μy−un, un−xn−μBxn ≥0, ∀y∈C. 3.31
It follows from conditionH2that
1
μ
y−un, un−xn−μBxn ≥Fy, un, ∀y∈C. 3.32
Therefore,
y−un,un−μxn Bxn
≥Fy, un, ∀y∈C. 3.33
For anyt∈0,1andy∈C, thenytty 1−tx∗∈C. From3.33, we have
yt−un, Byt ≥ yt−un, Byt −
yt−un, un−μxn Bxn
Fyt, un
yt−um, Byt−Bum yt−un, Bun−Bxn
−
yt−un,un−μxn
Fyt, un.
3.34
SinceBisβ-inverse strongly monotone, fromProposition 2.2iand3.12, we have
Bun−Bxn ≤ β1un−xn −→0 n−→ ∞,
yt−un, Byt−Bun ≥βByt−Bun2≥0.
3.35
Letn → ∞in3.34, in view of conditionH4andun x∗, we have
yt−x∗, Byt ≥Fyt, x∗. 3.36
It follows from conditionsH1,H4and3.36that
0Fyt, yt≤tFyt, y 1−tFyt, x∗
≤tFyt, y 1−tyt−x∗, Byt
tFyt, y 1−tty−x∗, Byt ,
that is,
0≤Fyt, y 1−ty−x∗, Byt . 3.38
Lettto 0 in3.38, we have
Fx∗, yy−x∗, Bx∗ ≥0, ∀y∈C. 3.39
This shows thatx∗∈GEP.
Step 4now, we prove thatx∗ ∈VIH, A, M. SinceAisα-inverse strongly monotone, from Proposition 2.2i, we know thatAis an 1/α-Lipschitz continuous and monotone mapping andDA H, whereDAis the domain ofA. It follows fromLemma 2.8thatMAis maximal monotone. Letv, f∈GraphMA, that is,f−Av∈Mv. SinceynJM,λun−
λAun, we haveun−λAun∈IλMyn, that is, 1/λun−yn−λAun∈Myn. By virtue of the maximal monotonicity ofM, we have
v−yn, f−Av−1λun−yn−λAun≥0. 3.40
Therefore we have
v−yn, f ≥
v−yn, Avλ1un−yn−λAun
v−yn, Av−AynAyn−Aun 1λun−yn.
3.41
SinceAis monotone, this implies that
v−yn, f ≥0v−yn, Ayn−Aun
v−yn,λ1un−yn.
3.42
Since
un−yn−→0, Aun−Ayn−→0, yn x∗, n−→ ∞, 3.43
from3.42, we have
lim
n→ ∞v−yn, f
v−x∗, f ≥0. 3.44
Summing up the above arguments, we have proved that
x∗∈Ω:FS∩VIH, M, A∩GEP. 3.45
On the other hand, for anyz∈Ω, we have
zn−z2SPC1−tnyn−SPCz2
≤1−tnyn−z2yn−z−tnyn2
yn−z2−2tnyn, yn−zt2nyn2
yn−z2−2tnyn−z, yn−z −2tnz, yn−zt2nyn2
1−2tnyn−z22tnz, z−ynt2nyn2
≤1−2tnxn−z22tnz, z−ynt2nyn2,
3.46
and so we have
xn1−z2αnxn−z 1−αnzn−z2
≤αnxn−z2 1−αn
1−2tnxn−z22tnz, z−yn t2nyn2
1−2tn1−αnxn−z221−αntnz, z−yn t2nyn2
≤1−2tn1−bxn−z221−αntnz, z−yn t2nyn2.
3.47
Putzx∗in3.47, we have
xn1−x∗2≤
1−γnxn−x∗2δn, 3.48
whereγn 2tn1−bandδn 21−αntnx∗, x∗−yntn2yn2. Sinceyn x∗, it is easy to see thatn∞1γn∞and limn→ ∞δn/γn 0. ByLemma 2.12, we conclude thatxn → x∗as
n → ∞, wherex∗is the unique solution of the following quadratic minimization problem:
x∗2min
x∈Ωx 2.
3.49
This completes the proof ofTheorem 3.1.
In Theorem 3.1, if T Tn ∀n ≥ 1, then the following corollary can be obtained immediately.
Corollary 3.2. LetHbe a real Hilbert space,Cbe a nonempty closed convex subset ofH,A:H →
mappings withFT/∅. LetF : C×C → Ê be a bifunction satisfying conditions (H1)–(H4). Let
{xn}be the sequence defined by
xn1 αnxn 1−αn
TPC1−tnJM,λI−λATμI−μBxn 3.50
where the mappingTμ:H → Cis defined by2.18, andλ, μare two constants withλ∈0,2α, μ∈
0,2β, and
tn∈0,1, tn−→0n−→ ∞, ∞
n1
tn∞, 0< a < αn< b <1. 3.51
If
Ω1:FT∩VIH, A, M∩GEP/∅, 3.52
whereVIH, A, Mand GEP are the sets of solutions of variational inclusion1.2and generalized equilibrium problem1.6, then the sequence{xn}defined by3.50converges strongly tox∗ ∈Ω1,
which is the unique solution of the following quadratic minimization problem:
x∗2min
x∈Ω1 x2.
3.53
InTheorem 3.1, ifM ∂δC : H → 2H, whereδC : H → 0,∞is the indicator function of C, then the variational inclusion problem 1.2 is equivalent to variational inequality 1.5, that is, to find u ∈ C such that Au, v−u ≥ 0, for all v ∈ C. Since
M∂δC, JM,λPC. Consequently, we have the following corollary.
Corollary 3.3. LetHbe a real Hilbert space,Cbe a nonempty closed convex subset ofH,A:H →
Hbe anα-inverse strongly monotone mapping andB: C → Hbe aβ-inverse strongly monotone mapping. LetM∂δC :H → 2Hand{T :C → C}be a nonexpansive mappings withFT/∅.
LetF:C×C → Êbe a bifunction satisfying conditions (H1)–(H4). Let{xn}be the sequence defined
by
xn1 αnxn 1−αn
T1−tnPCI−λATμI−μBxn, 3.54
where the mappingTμ:H → Cis defined by2.18, andλ, μare two constants withλ∈0,2α, μ∈
0,2β, and
tn∈0,1, tn−→0n−→ ∞, ∞
n1
tn∞, 0< a < αn< b <1. 3.55
If
whereVIA, C and GEP are the sets of solutions of variational inclusion 1.5 and generalized equilibrium problem1.6, then the sequence{xn}defined by3.54converges strongly tox∗ ∈Ω2,
which is the unique solution of the following quadratic minimization problem:
x∗2min
x∈Ω2 x2.
3.57
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