VOL. 18 NO. 4 (1995) 665-676
ON THE NACHBIN
COMPACTIFICATION
OF
PRODUCTS
OF TOTALLY
ORDERED SPACES
D.C. KENT, DONGMEI LIU
Department
ofMathematics WashingtonState UniversityPullman,
Washington, 99164-3113and
T.A. RICHMOND
Department
of MathematicsWestern
KentuckyUniversityBowling
Green,
Kentucky42101(Received October 18, 1993)
ABSTRACT.
Necessary
and sufficient conditions aregiven foro(X
Y)
oX
xoY,
whereX
andY
aretotallyordered spacesandoX
denotes the Nachbin(or Stone-ech ordered)
com-pactificatio ofX.
KEY
WORDSAND
PHRASES. Nachbincompactification, Wallmanordered compactification,totallyordered space, maximalc-filter,strictly firstcountablespace.
1980AMS
SUBJECT CLASSIFICATION
CODES:54D
35, 54F
05,54B
10.1.
INTRODUCTION.
If
X
is aT3.5-ordered
space(i.e.,
anordered topologicalspace which is %ompletely regular ordered" inthesenseofNachbin[8]},
thenX
hasalargestT2-ordered
compactificationoX
which iscalled the Nachbin(or Stone-ech ordered)
compactification. Thiscompactification, introducedin
[8],
hasbeen investigatedinallofourreferencesexcept
[5].
We
are interested in determining wheno(X
xY}
oX
oY,
a problem which has not previously received attention in the literature. The methods used by Glicksberg[5]
to solve the corresponding problem for theStone-(ech
compactification do notappeartobefruitful when applied to theNachbincompactification.Therefore,
atthispreliminary stage ofourinvestigation,wehavefocusedour attentionon the casewhere
X
andY
are "totally orderedspaces",
whereatotally orderedspace is definedtobe atotally ordered setwith aconvex,
T2-ordered
topologyOur solution to the aforementioned problem makes extensive useof the Wallman ordered compactification
woX,
introduced in[2].
In
Section3weshow thatforanyT3.-ordered
spaceX,
oX
canbe obtained fromwoX
via acertain quotientconstruction, andthisresult
is employedinthe proofofour maintheorem.
We
also makeuseof the fact thatwoX
[oX
foranytotally orderedspaceX.
We
firstproveapreliminary version ofourproducttheorem in Section 4under the assumptionthat thetotally orderedspaces
X
andY
are %trictlyfirstcountable".(A
totally orderedspace is definedtobe strictlyfirst
countableifeveryneighborhoodfilterandeverymaximal closed-convexfilterhasacountablefilter
base.)
Surprisingly,the condition which works" in the strictly firstcountablecase also works" in the general case
(see
Theorems 4.4 and5.6).
IfX
andY
arestrictlyfirst
countable,
theno(X
xY)
[oX
[oY
andWo(X
Y)
woX
woY
areequivalent statements.We
do not know ifthisequivalence holds for arbitrary totally orderedspacesX
andY.
2.
PRELIMINARIES.
Let
{X,_<)
be aposet.Fora
non-empty subsetA
ofX,
we defined(A)
{y
e
X
y<
xforsomex E
A}
to be the decreasing hull ofA;
the increasing hulli(A)
is defined dually.We
shallwrited(x}
andi(x}
in place ofd({x}}
andi({x}}.
A
setA
is i,creasing(respectively,
decreasing)
ifA
i(A}
(respectively,
A
d(A}};
asetwhich is either increasingordecreasing is said tobe monotone.For
anyA
C_X,
A
^
i(A}
Nd(A}
iscalled the convexhull ofA,
andA
is convexifA
A^.
Let
F(X)
denote the set of allfilters on asetX. We
alwaysuse the termfilter
o
mean aproper set filter.
If
.T
and.
arefilters onX
such thatF n
G
#
,
for allF
EY
andG
C.,
thenr
y denotes thefiltergenerated by(F
NG"F
e ’,
Ge .);
if,ontheotherhand,
containdisjoint sets,wesay that"
v
.
[ails
to exist.A
filter"
is]tee
ifthereis nopointcommonto allthe sets in
.T.
A
filter which is notfreeis said tobe fixed; in particular, thesymbol willdenote thefixed ultrafiltergeneratedbyx G
X.
For
any filterY
onX,
the filter’^
generated
bysetsofthe form
{F
^
F
E.T}
iscalled the convexhullof’.
An
orderedterpalogicalspace,orsimplyan orderedspace, isatriple(X, _<, r),
where(X, <)
is aposer
andr a eanvextopologyon(X, <_}
(i.e.,
r is atopology whichhas
a subbase consistingofmonotone open
ets).
Note
that every ordered spaceis locally convexin the sense thatevery neighborhood filterhasabase ofconvexopen sets. Whenthereis nodanger of confusion,werefer tothe ordered space(X,
<, r}
simply asX.
IfX
andY
areorderedspaces,amapf
X
Y
isincreasing
(respectively, decreasing)
if x<
y inX
impliesf(x) <_
f(y) (respectively,
in
Y.
A
continuous,increasing map iscalled anordered topological morphism, ormorebrieflyamorphisrn.
A
b]jective morphism whoseinverse isalsoamorphismiscalled anordered $opologicalisomorphism, or morebrieflyanisomorphism.
Let
VI’(X)
(respectively,
CD’(X))
denote thesetof all morphisms
(respectively,
continuous,decreasingmaps}
fromanorderedspaceX
into[0, 1].
An
ordered spaceX
isT-ordercd
ifi(x}
andd(x}
areclosed sets, forall xX;
X
isT-ardered
if the partial orderrelation
_<
isclosedinX
xX. An
orderedspaceX
isT.s-ordered
(completely
regular orderedin
[8])
if thefollowing conditionsare satisfied:(1}
IfxX, A
is aclosed subset ofX,
and xA,
then there isf
CI’(X)
and gCD’(X)
such thatf(x)
g(x}
0andf(y) v
g(y)
1, for all y EA;
(2)
Ifx yinX,
there isf
CI’(X)
such that/(y}
0 andf(x)
1. TheT3.-ordered
spaces are precisely thosewhich allowT-ordered
compactifications(see
[3]
and[8]}.
An
ordered spaceX
is normally ordered(see
[8]}
if, wheneverA
andB
arewith b increasing andV decreasing, such that
A
C_ U andB
C_ V.An
ordered space which isboth normallyordered and
Tl-ordered
issaidto beT4-ordered.
Given a
Ts.s-ordered
spaceX,
thereis alargestT2-ordered
compactification ofX
called the Naehbin(or Stone-ech ordered)
cornpaetification,denotedby[3oX.
Thestandardconstructionof/9oX
involvesembeddingX
in the "ordered cube"[0,
1]
ct’(x)where the latter space has theusualproductorder and topology. Thiscompactificationischaracterizedbythe followingwell-known
exnion
orem
Oee
[]
or[]).
THEOREM
2.1. IfX
isaTs.s-ordered
space,Y
isacompact,T2-ordered
space,andf
X
Y
isamorphism, then thereis aunique morphism j-r
./oX
y
such that the diagramX
ex
\ Y
commutes,
whereex X --/3oX
is thecanonicalembedding.We
next review the construction ofthe Wallman ordered compactification.Let
X
be anoderdp=e
ana
X;
e
()
(repey,
())
bh ml dod,
dr=.g(re-spectively,
closed,
increasing)
set that containsA.Let
A
aI(A)
qD(A);
ifA
A
a thenA
is calleda e-set.One
mayverify that thecollection of alle-sets onX
is closed under arbitraryintersections.
It
is obviousthat e-sets are dosed and convex, but not allclosed,
convexsubsets ofX
aree-sets. IfjrGF(X),
letD(jr) (respectively, I(jr))
denote thefilter onX
generatedby{D(F)
F
Gjr} (respectively,
{I(F)
F
jr}).
The filter jra1(jr) v D(jr)
isgenerated bysetsof the form
ava,
for av jr; ifjrjra,
thenjr iscalled ae-filter.
One may easily verify(using
Zorn’s
Lernma)
that every e-filter iscoarserthan amaximal e-filter.Let
X
beaTrordered
space, andletWoX
be thesetof allmaximal e-filtersonX. A
partialorder
"<"
forWoX
is definedasfollows: jr<
=
I(jr)
C#
andD()
jr.We
also assign towoX
the topologywithclosed subbaseg
{A
A
aa},
whereA
Then
woX,
withthe order and topologyjustdescribed,is anorderedspace which iscompactandT
(but
generallynotT-ordered).
Ifx
X
WoX
isdefinedbyx(z)
5,
for all zGX,
thenx
is anisomorphic embedding,and consequently(WoX, x)
is anorderedeompactificationofX. Furthermore,
wehavethefollowingextensionproperty(see
[2]
or[6]).
THEOREM
2.2.Let X
beaT-ordered
space,Y
acompact,T2-ordered
space,andf
X
--
Y
amorphism. Thenthereisaunique morphismjz. w,X
Y
such that the diagramX
Ox
woX
\
Y
commutes.
An
orderedspaceX
isdefined tobeac-spaceifi(A)
andd(A)
areclosed subsets ofX
when-ever
A
_C
X
is ac-set. The next theoremisprovedin[6].
(I)
woX
isT-ordered
()
,,,ox
oX
(3)
X
isaT4-ordered
c-space. 3./oX
ASA QUOTIENT OF
woX.
Throughout this section,
X
will denote an arbitraryTs.s-ordered
space and(woX,)
theWallmanorderedcompactificationof
X.
If
f
ECI’(X)
then there exists, byTheorem 2.2, a unique morphismf^
woX
[0,
1]
extending
f.
We
define an equivalence relation onwoX
as follows:{(r, )
EwoX
xwoX
f^(’)
f^(.),
forallf
CI’(X)}.
The set{[}’]
"
6woX}
of E-equivalenceclasses is denotedby
woX/;
let awoX
woX/
be the canonical projection map.We
en-dowwoX/
with the quotient topology derived fromwoX
and a, and with the partial order[Y’]
5
[.]
=>
f^()
<_
f^(.)
in[0,1],
for allf
6CI’(X).
ThesetwoX/,
with this order andtopology,is anordered spacewhich,forconvenience,weshallcall#oX.
One easily verifies thata"woX
oX
is amorphism.LEMMA
3.1.oX
isacompact,T-ordered
space.PROOF.
Obviously,#oX
iscompact.We
recall(see
[8])
thatanorderedspace isT-ordered
wheneverz y, there are disjoint neighborhoodsU
andV
ofxand y, respectively, such thatU
isincreasing andV
isdecreasing.For
eachf
CI’(X),
definef’:
oX
[0, 1]
byf’([])
fA(),
for all[ff]
6oX;
it is eyto verify thatf’
is awelldefinedmorphism, nd therefore(f’:
f
UI*(X))
CI*(oX).
[]
[],
there isf
UI’(X)
such thatf()
f()
in[0, 1],
d hencef’([Y])
>
f’([])
in[0, 1].
Let
f’([])- f’([])
>
0, d letU
(ff)-((ff([])- e/3,1])
andV
(f’)-([0, ff([])
+
e/3)).
ThenU
dV
edisjointopennieghborhoods separating[Y]
and[]
such thatU
is increing dV
decreeing. ThereforepoX
isTz-ordered.
By
Theorem 1.2, thereis aunique morphism’woX
oX
suchthat the diagram/
x
\
oX
coutes.
Also,
for yf
CI’(X),
thereisauniquef
CI’(oX)
such thatf
f
oe.Note
that
fA
f
o,
sincetheemaps agreeonthe dense subspace(X)
ofwoX,
d henceonwoX.
LEMMA
3.2. ForY’,
.
woX,
(Y’,
)
.(Y’)
(.).
PROOF.
If(.,,)
,
thenf^(r)
f^(Q),
for allf
C!(X),
and hencef(())
/(())
for allf
CI’(X).
This implieseCY)
(),
sinceoX
isT3.s-ordered
and henceeI’(ZoX)
{f
f
uP(X)}
separates points inoX.
Conversely, if()
(),
thenfA()
f(@()) =/(())
fA()
for allf
CI’(X),
which implies(, )
.
PROOF. Let
e’’#oX
floX
be definedbye’([’])
g’(’),
for allwoX.
woX
-&
#oX
x
/
%
I"
%
ox
I
follows from Lemma 3.2 tha"
is a well-defined bijection. Since#oX
h the quotienttopology inducedby and
"
o iscontinuous, e" iscontinuous. Since#oX
iscompac
andoX
isT,
"
is ahomeomorphism.To
cheekthate’isanorder-isomorphism, let[Y]
[]
in#oX.
Then,
for allI
CCI’(X), ()
I()
i[0, 1,
a
h[(())
((5)),
foI
cI’(X).
Th()
()
ioX,
andconsequently
e’Ca(7))
e’([T])
e’([])
e’Ca()).
This argument is reversible, andconsequently both e" d
(e’)
-
are increing maps.4.
A PRELIMINARY PRODUCT
THEOREM.Compactificationsoftotallyordered spacesarestudied in
[I]
and[7],
andwebegin this sectionbysummarizingsomerelevent results from
[7].
We
defineatotall!/ordered
spaceX
to be aT2-orderedspace whose partial order is atotal order
(i.e.,
ifz,/EX,
then z<_
/or l/_<
z).
It
iseasy toshowthatatotally orderedspace isa
T4-ordered
c-space in which the c-sets areprecisely theclosed,
convexsets. Consequently, by Theorem 2.3, the compactificationswoX
andfloX
ofatotally orderedspace
X
exist andareequal.Furthermore,
everyT2-ordered
compactificationofatotally orderedspace is itselfa totally orderedspace.
For
atotally orderedspaceX,
we usethe equivalence offloX
andwoX
to describethe com-pactification pointsof[3oX
asmaximal c-filters.It
isshownin[7]
that,
inatotally orderedspaceX,
themaximal c-filters arepreciselytheconvexhulls of ultrafilters; the non-convergentmaximal c-filtersonX
arecalled singularities. Givenasingularity,
letT
t3{FT
F
E7},
whereF
denotes the set ofupperbounds of
F,
andyt
U{Ft
F
C},
whereF
is the set oflower boundsof’.
Theconvexsets and)’t partitionX,
andsoexactlyoneof these sets is in7.
If’t
"
(respectively,
’t
’)
wesay that.
isa decreasing(respectively, increasing)
singularit!t.A
totally ordered spaceX
isstrictll
first
countable if every neighborhood filter and everysingularity has acountablefilter base. If
.
is an increasingsingularitywith a countablefilterbase,
thenthere is astrictly increasingsequence Zl<
z
<
z3<
inX
such that is theconvexhull of thefilterofsectionsof
(z);
similarly, each decreasing singularitywithacountablefilter base is likewise derivedfromastrictlydecreasingsequence in
X.
If
X
andY
are totally ordered spaces, thenX
xY
(with
the product order and producttopology)
is aT3.s-ordered
space, but not generally a c-space. For instance, it is shown in[4]
thatif
X
is thereal line withthe usual order and topology andY
is anytotally orderedspacewhose underlying
poser
isthereal line, thenX
Y
isa c-space the topology forY
isthe usualtopology.Thus,
in general,wo(X
Y)
fails tobeTz-ordered
and hencewo(X
xY)
and[3o(X
Y)
arenon-equivMent eompaetifieations(see
Theorem2.3).
The next twolemmasaredue toMargaret
A. Gamon.LEMMA
4.1. IfX
andY
aretotallyordered spaces,A
ac-set inX,
andB
ac-setinY,
thenA
B
isac-set inX
Y.
i(A
B)
I(a)
I(B)
is aclosed,
increasing set containingA
xB,
and hencei(a
B)
I(AB)
I(A)I(B).
Similarly,D(AxB)
D(A)D(B),
and thereforeI(AxB)nD(AB)
(I(A)
xI(B))63 (D(A)
D(B))
(I(A)n D(A))
(I(B) D(B))
A
B.
ThusA
x
B
is a c-set inX
xY.
LEMMA
4.2.Let
X
andY
be totally orderedspaces, and let jr be a singularityonX
and.
a singularityonY
suchthat either both are increasingsingularities or both are decreasingsingularities. Thenjr
.
isamaximalc-filteronX
Y.
PROOF.
Assume that jr and are both increasing singularities onX
andY,
respectively.By Lemma4.1,
jr6
is a c-filter onX
Y.
Let X
{x
EX
<
jrinwoX}
andY’
{y
EY
<
inToY}
be totally ordered subspaces ofX
andY,
respectively.Let
jr’ andbetherestrictionsofjr and
.
toX
andY,
respectively.It
is easy to verify that jr and.
are increasingsingularitiesonX’
andY’,
respectively,and that(jr,}r
(06’}r
0.
It
is alsoeasy to verify that jr.
is amaximal c-filteronX
Y
==
jrw6
is amaximal c-filteronX
Y.
Therefore weshall assume, without loss of generality, that jr and are increasing singularities onX
andY,
respectively, such that jrr0.
Let
be a c-filter onX
Y
such that jr.
C_ )/.Let H
)/ be a convex set, and let(a, b) H63(F G),where
F
jrandG.
For
anyeEXandd Ysuchthata<c
andb
<
d,wemusthave(c, d)
CH,
sinceotherwisei(c)
i(d)
would beamember ofjr.
disjoint fromH. This implies thati(a)
i(b)
C_ g.But
i(a)
i(b)
Cjr,
andso C_ jr.
It
follows that jr.,
andconsequently jr is amaximalc-filteronX
Y.In
general,the conclusionofLemma
4.2isnotvalid ifoneof the singularities is increasingand the other decreasing.Indeed,
the next lemmaestablishes that ifjr is anincreasingsingularityon
X
and,
adecreasing singularityonY,
bothwithcountablefilterbases,
thenjrx
.
isnota maximal c-filteronX
x Y.
LEMMA
4.3.Let
X
andY
be totally orderedspaces.Let
(x.)
be astrictly increasing se-quence inX
and(y,,)
astrictlydecreasingsequence inY.
Let S
{(x2r,-l,
y2,,_)’rt e
N)
andT
{(xz,
yz,.,)’n
GN}.
Then thereisge
CI’(X
Y)
such thatg(i(S))
1 andg(d(T))
O.PROOF.
Choosexo
X
suchthatXo<
x.
(In
casex
istheleast element ofX,
replace
the original sequence(x)
by(x’),
wherex
x.+,.)
SinceX
andY
arebothT4-ordered
spaces,we canapply Theorem 1, page30,[8]
to obtain, for each rt CN,
afunctionfzr,-
CI’(X)
such thatfz,.,-(a)
0 ifa<
x2._ andf,.,_(b)
1 if b>_
x._, and another functionf,.,
CI’(Y)
such that
f2,.,(c)
0ifc_<
yzandf(d)
1 ifdWe
nextdefineafamilyoffunctions inCI’(X
xY)
asfollows"H(,
)
(fxC)f())
^
H4Cx,
y)
[g(x,
y)
+
f3(x)f4(y)]
A 1H,,.,(x,
y)
For
k CN,
wedefineS2k-t{(xn-t,
Y2n-1)
n<
k)
andT
2t:((x._,.,,
y2.)
n<
Finally, let
(,
)
[((,
)
+
f+C)f+())
].
It
isclear thatg is an increasing mapfromX
Y
into[0,
1]
suchthatg(z, y)
1 if(z,
y)
Ei(S)
and(z,
y)
0if(z,
y)
Ed(T).
By
consideringthe possiblecases,onemayalso verify that forevery(z,
y)
X
Y,
#(z,
y)
is theinfimumofthe constant function 1 and afinitesumofcontinuousfunctions. Thusg
CI’(X
Y),
asdesired.In
the proof of the next theorem we willneed some additional notation.Let
X
andY
be totally orderedspaces, andconsiderthe following diagram:e
oCXxr)
#/z
woCXxY)
XxY /
a’
XxY
-a
oXxoY
’,
woXxwoY
where,
inthenotationof Section2,e exxY, aex
x er, #xxr,and #xx#r arethecanonicalembeddingmaps. Since
woX
oX
andwoY
oY,
oX
xfloY
woX
xwoY
is acompact,
T2-ordered
space, anda’
and 9 arethe unique,continuous,
increasing extension mapswhoseexistence is guaranteedin Theorems2.1 and2.2.
Observe that
/(X
xY)
/oX
x/og(respectively,
wo(X
xY)
woX
xwog)
o’
(respectively,
)
isaninjective map.THEOREM 4.4. If
X
andY
are strictly firstcountable,
totally ordered spaces, then thefollowing statementsareequivalent.
1)
woX
xwoY
wo(X
xY).
(2)
oX
xoY
:/o(X
xY).
(3)
IfeitherX
orY
hasanincreasing(or
decreasing)
singularity, then the other space con-tainsnostrictlydecreasing(or
strictlyincreasing)
sequence.PROOF.
(1)
=
(2).
For
totallyordered spacesX
andY,
IoX
woX
andoY
woY.
Thuswo(X
Y}
oX
oY,
and the latter space isT2-ordered.
By
Theorem2.3,wo(X
Y)
o(X
xY)
oX
xY.
(2)
=
(3).
Assume X
hasanincreasingsingularity.q
and thatY
containsastrictly decreasingsequence
(yn).
Note
that is acompactificationpoint inoX
woX.
If(y,)
converges to yo inY,
then wedefine "7(,or(yo));
if(y,)
fails to converge inY,
letN
be the decreasingsingularityin
Y
which isthe convexhull of thefilterofsectionsof(,),
and let7(.q,)/).
In
eithercase,"7 is acompactificationpointofoX
xoY.
Next,
let(z,)
be a strictly increasing sequence inX
obtainedby
choosingadenumerable,
nested filter base
{G,
:nEN}
for.
and choosing z, E,,
for all n6N,
such haz
<
z
<
za
<
Then clely isheconvhull of thefilerofsectionsof thesequence(z,).
Csiderhefiler ofaecfionsof he sequence
(z,,
y,)
onX
x
Y;
le behe filer generated by he subsequence(z,-t,
y-)
d he filergeneratedby
he subsequence(,,
y,).
If S{(2n-,, Y2n-1)
:
N}
dT
{(x,,
y,):n
N},
then S andT
6.
Regdless of whetherornot(y,)
converges inY,
a(Y) (d
hence alsoa(fa))
convergesto inoX
x
oY.
Let
1
d bemimal c-filtersonX
x
Y
such thata
anda
.
By
Lena
4.3, thereis g
e
CI*(X
x
Y)
such thatg(i(S))
1 dg(d(T))
0. Sinceg-l({1}) e 1
and-equiva|encec|asses
[i]
and[.12]
(defined
inthe second paragraphof Section3)
as elements offl0(X
xY).
Sinceg^(l) # gA(2)
(where
gA
CI’(wo(X
xY))
is the unique extension of gCI’(X
xY)),
[]
and[]
are distinct equivalencecloses(i.e.,
distinct elements ino(X
xY)).
But
a(,)
anda()
are both finer thana(a),
soboth ofthesefilters converge to infl0(X
xY).
Thusa’([])
a’([]),
andconsequentlya’
isnot injective.(3)
(1).
IfneitherX
norY
has a singularity, thenX
andY
are both compact, and soX
xY
woX
xToY
wo(X
xY).
Assume that
woX
xToY
contains a compactification point(,).
We
will show that-(q)
is asingletoninwo(X
xY),
implying that is injective. Therearethree possibleces to consider. If is a singularity inX
and a singularity inY,
then Condition(3)
and the sumptionofstrict firstcountabilityforX
andY
imply that and are either both incre-ing sincre-ingularitiesorbothdecreeing singularities.By
Lemma
4.2, x is amimal c-filteronX
x Y.
Thus-(q)
{7
x}
is a single compactification point inwo(X
x
Y).
If
is asingularity and
r(Y)
forsomeyY,
thenoneeilyverifiesthat7
x9
is anon-convergentmimal c-filteron
X
xY,
and-()
{
x9}
is again a singleton compactificationpoint inwo(X
xY).
Thesamereoning appliesif isasingularityinY
andx(x)
forsomexX.
We
conclude that the quotient map-’wo(X
Y)
woX
xToY
is injective, and thereforewo(X
x
Y)
woX
xwoY.
If
X
isthereal line with anyconvex,T2-ordered
topology andY
is anystrictlyfirstcountable,
totally orderedspace, it follows from thepreceding theoremthat
/o(X
xY)
oX
x/oY
iffY
is finite. IfN
is the set ofnatural numberswith the usualorder and the discrete topology,o(N
xN)
oN
x/oN
follows by Theorem 3.4; notethatN
xN
is notpseudo-compactandthus/(N
N)
N
x/N. If,
on the otherhand, N
is the set of negative integers with theirusualorderand thediscretetopology,/o(N
xN
)
/oN
x/oN
.
Indeed,
it is easy toseethat/oN
xoN
hascardinalitybo,whereasit canbeshownthat/o(N
xN
has cardinality 225.
THE
PRODUCT THEOREM.
Throughoutthissection,thesymbols
X
andY
willrepresentarbitrary totally orderedspaces.Ourmaintheorem
(Theorem 5.6)
establishesthat Condition(3)
of Theorem4.4(stated
inslightly differentterms)
is necessary and sufficientfor/o(X
xY)
oX
x/oY
in thegeneralcase. Theproof ofTheorem5.6 isbasedonfiverather technical
lemmas,
forwhichweneedsomeadditional notationandterminology.Let
"
be an increasing singularityonX
andf
anordinal number. Recall that"
is alsoacompactificationpoint in
woX
IoX.
We
saythat,z
has order ifthereis astrictly increasing net(x^)^<
onX
suchthat the net(^)^<
in/oX
converges tor,
and istheleast such ordinal. The order ofadecreasing singularityonX
isdefined dually. If is the order of any singularity onX,
then clearly isaninfinite ordinal andtheleast ordinalofitscardinality.In
astrictly firstcountable,
totally orderedspace,everysingularity has orderw, the leastinfinite ordinal.Next,
lety EY.
IfnostrictlyincreasingnetinY
convergesto y, we saythat yhasleft
order0. Ifforsomeordinal
,
there is a strictly increasing net(y^)^<
converging to y inY
and isthe least such ordinal,wesaythatyhas
left
order.
The right order fory is defineddually. Ifz EY
and y<
z, let[y,z]
{a
Y
"y<
a<_ z}, [y,z)
{a
Y
y<_
a<
z},
andnet converging to y, we denoteby
"l)t(y)
the filteronr
generated by{[y^,y]
A< p};
"lit(y)
iscalled the
left
neighborhoodfilter
aty,andwe set"t(y)
in case p 0. Likewise,if yhas rightorder
>
0 and(z^)^<
is astrictly decreasingnetconverging to y, the right neighborhoodfilter
V.(y)
is generated by{[y,z^]
A<
};
againwesetVr(y)
if 0.Furthermore,
if>
0 wedenote by);(y)
the filter onY
generatedby{(y,z^]
A<
}.
Note
that)t(y) n Yr(y)
isthe usual neighborhood filter at y.We
shall also needadditional interval notation pertaining to singularities.If
jrisanincreasing singularityonX
and zEX
is such that $<
jr inwoX,
we define[z,
jr)
{a
EX
z<
a inX
andh<
jr inwoX}
and(z,
jr)
[z,
jr)\{z}. In
ease is a decreasing singularityonY
andy
Y
is suchthat.
<
inwoY,
let(.,y]
{a
Y"
a<
y inY
and.
<
h inwoY}
and let(.q,y)
(.,y]\{y}.
Ifjr has order and(z^)^<
is astrictly increasing net suchthat(:^)^<
converges to jr in
woX,
theneachof the sets{Ix^,
jr)
A<
}
and{(z^,
jr)
A<
(}
is a filter basefor jr. Likewise, if.
has order rt and(y^)^<.
is a strictly decreasing net inY
such that(0h)^<.
converges to.
inwoY,
then each ofthesets{(.,U^]
A<
r/}
and{(.,U^)
A<
r/}
are filterbases for.
LEMMA
5.1.Let
jrbeanincreasingsingularityonX
oforder>
w,let.
beadecreasing sin-gularityonY
of orderr/> w,and assumethat every strictly increasing sequenceonX
and every strictlydecreasingsequenceonY
isconvergent. If/ and aremaximal c-filtersonX
Y,
both finerthanjrx6,
then for allf
CI(X
xY),
f()
andf()
convergetothesamelimit in[0, 1].
PROOF. Suppose
thereisf
CI’(X
xY)
suchthatf(}
converges toa,f()
converges tob,
anda b in[0,
1].
Let U
andV
be disjoint neighborhoodsofaandb,
respectively,and choose closed setsL
E andM
such thatf(L)
_CU
andf(M)
C_V. Then,
choosethefollowingpoints in
X
Y
Continuinginthis wayweobtainsequences
(a.,
b,.,)
inL
and(c., d.)
inM
suchthatao <
co <
al<
Cl<
< an < cn
<
bo
>
do
>
bl > d >
>
b,>
d,,>
Under the assumptions of the
lemma,
the sequence ao,co,al,cl, converges to some Xo inX,
and the sequence
bo,do,
b,d,..,
converges to some yo inY.
Thus(xo,
yo)
_
L
f3M,
contrary to the fact thatf(L)
f(M)
.
LEMMA
5.2.Let
jrbeanincreasing singularity of order>
wonX,
andlet yY
haverightorderr/>w.
Assume
thateverystrictlyincreasing sequenceonX
andeverystrictly decreasingsequenceon
Y
isconvergent.If and aremaximalc-filtersonX
Y,
bothfinerthanjrx)(y),
then forallf
CI(X
Y),
f(.)
andf(t)
converge tothesamelimit in[0, 1].
LEMMA
5.3. Let beanincreasing singularityonX
of order>
wand let yY
haveleftorder rt :> 0. If isamaximal c-filteron
X
Y
finer than27
e(y),
then.M
.T
.
PROOF.
Let
(Yu),<
beastrictly increasing netonY
converging toy; thus)t(Y)
hasafilterbase
{[Yu,Y]
#<
r/}.
Note
that27
hasafilter baseof the form{Ix^,
27)
A<
},
where(x^)^<
is astrictlyincreasingnetin
X.
Choose ac-set
M
.M
suchthat[Xo,.7")
[yo,y]
_
M. For
eachA<
and# <
r, there is(a^u,b^,)
M
N(Ix^,
:7)
[y,, y]).
Let
(a, b)
M
be arbitrary;weshall show that(a,
y)
M.
Ifb y there isnothingmoreto show,so assume the contrary,and chooseordinalsp
<
r/ andr
<
such that b<
yp
anda<
x,. Then(a, b) < (a,
b,p)
< (a,a, b,a),
andsobyconvexityofM,
(a,b,,)
M.
Sincey,
<_ b,.,, (a,y,,)
M.
Indeed this reasoning implies that(a, y,)
M
forall
<
rt suchthat p<
u.
SinceM
isclosed,
(a,
y)
M.
Using again the convexityofM,
wededucethat
[a,
27)
x{y}
C_M
and that[a,
27)
,v.
Thus.7
>
,
andsincebothare maximalc-filters,equality holds.
LEMMA
5.4.Let
"
be an increasing singularityonX
of order_>
w, and let yY
have right order rt>
w. If rt and is amaximalc-filteronXY
finerthan’x
r(y),
then,=
x
.
PROOF. Let
(x)<e
bea strictly increasing net inX
such that{[x,.v)
A <
}
is a filter base for’.
Let(Yv),<,
beastrictly decreasing netinY
converging toy such that{[y,y,]
<
isafilterbasefor"Vr(y).
Let M
)[ beaclosed,
convexsetsuch thatM
C_[Xo, .7)
[y,
yo].
CASE 1. rt
<
.
If0<_
A <
rt, choose(ax,b,)
M
N([xA,.T)
[y, yA])
such that isstrictly increasing inX
and(bx)A<
is strictly decreasingin Y.Next,
choose ordinal p such thatr
<
p<
,
and choose(aa,ba)
M
N[xa,
)
[y, yo]
such thata
<
ap, for allA
<
r/. LetA
{A
<
rt"bx <
ba}.
Using the convexity ofM,
(a,,b,)
M,
for allA
A
and(a,,b,)
M
implies that(a,,,bx)
M,
for allA
A. Since(bx)eA
converges to y inY
andM
isclosed,
(ap, y)
M. This reasoning leads to the conclusion thatIda, )
{y}
C_M,
and hence27
>:CASE 2.
<
ft. ForeachA
<
r,choose(a,,b,)
M
[Xo,’)
x[y,y,]
such that(bx)A<,
is strictly decreasing; thus(bx)<
nconvergestoy inY. ForeachA <
rt,letux
bethe least ordinalsuch that
a
<
x.
Note
that{
A
<
rt}
C_{p
p<
}.
Considering thenet(x,)<,
we observe thatsince each#<
,
there is some{A
A <
#}
suchthatthe termxa
occurstimes in the net
(x,)<,,
whereIrtl
isthe cardinalityofr.
Now
chooseapoint(a,
b)
M
suchthata>
xa.
Thena>
a,for allA
</suchthat p.
IrA-
{A
<
rt#A},
then]A
]r/]
and(b)eA
converges to y inY. We
shall showthat(a,y)
M.
Assumingb#
y,leth’=
{A
A’b
<
b};
thenIA’]
Irti
and(b,),e,,
converges to y inY.
Usingthenowfamiliar argument basedonM
beingclosed and convex,wededuce that(a,
y)
M.
This argumentcanagain be extended to show[a,
F)
x{y}
C_M,
where[a,
F)
andconsequently
"
x.
LEMMA
5.5.Let
27
beanincreasingsingularityonX
of order>
0,and letyY
have rightorder
.
If isamaximal c-filteronXY
finer than.7x’l)r(y),
then for allf
CI(XY), f(.M)
and
f(27
)
converge tothesamelimit in[0, 1].
PROOF. Assume
is
/
CI’(X
Y)
and #,i_>
r
r(y)
suchthatf(
)
converges to[0, I]
andconverges tosomepoint
n
[0, I]
other than.
Snce#
x,
t
follows that x().
We
shallobtaina contradictionbyconstructinga mmlc-filterx
()
suchthat,
for eachL
,
f(L)
ntersects
everyneghbhorhoodofan
[0,
I].
It
follows thatf()
converges ton
[0,
I]
andhence,
byLemma
5.2,()
converges to,
acontradiction.Let
{U
"m}
be a nestedneighborhoodbe for[0,
I],
where eachs
a closed nterval.Snce
y(
x)
converges toa andf
>
,
we canfind<
suchthat[z,
>
d[x,>
{}
C,
whereC
{U’
N}
is ac-setinX
r.
Let
A
{A’p
A <
}.
Let
()<
beastrictly decreeingnetconvergingto in.
For
eachA
A,
thereis p<
f
such that(z,z)
C,
for all z[,].
Choose astrictly decreeingnet()
such that,
[,)
for all
A
A;
then(y,)
converges toy and(z,,)
isa net in C.Let
be the filter ofsections ofthe net
(z,9,),
andlet be y mimal c-filter finerthI()
O().
SinceC isac-set, C and hence C
.
Thusf()
converges to a in[0,
1].
Since each set of the form[z,
Y>
x
[y, y],
for<
f,
containsanelementofthe net(z, 9),
is finerthanthe c-filter
Y
x(y),
andconsequentlyY
x().
To
completetheproof, it remains toshowthat#
Y
x,
andtherefore thatY
x(y).
Y
x,
then each S contains a set of the formF
x{y}
for someF
Let
SK
,
whereK
h the formK
{(z,y)
A
}
for some A. Ifaset of the form
F
x{y}
K
for someF
Y,
then there is an ordinal such that[z,>
F;
thus[z,Y)
{y}
K
.
Let be any ordinal such than<
<
f.
ThenO
{(z,z)
zz}
{(z,z)
zy,.}
isac-set inX
xY
containingK,
d thereforeK
O.But
[z, z)
x{y}
O,
dso[z,
>
x
{y}
K
.
The sumption thatY
x is hereby contradicted,dtheproofof the lena iscomplete.THEOREM
5.6. LetX
dY
betotally orderedspies. Theno(X
xY)
oX
xoY
the following condition
(.)
issatisfied:(*)
eitherX
orY
containsanincreing(or
decreeing)
singulity of order w,thenthe other spacecontainsnostrictly decreeing
(or
strictlyincreing)
sequence.
PROOF.
o(X
x
Y)
oX
x
oY,
the proof that(2)
(3)
inTheorem3.4 establishes condition(*).
Conversely,sume
(*)
andconsiderthe diagrmwo(XxY)
o(XxY)
XxY
To
showo(X
x
Y)
oX
x
oY,
it is sumcienttoshowthat(’)-’()
is asingleton for each comptification point inoX
oY.
Two
cesmustbe considered.CASE
1.(Y, 9),
whereY
d9
esingulitiesonX
dY,
rpectively.Y
d e eitherbothincreingorboth decreeing,itfollows byLena
4.2that(’)-()
isa singleton.So,
without loss of generality,sumethatY
is increingsingulity of orderf
and is adecreeing singulity of order
.
f
,
then the istenceofa decreeing singulityonY
impliesthe existenceofastrictly decreeingsequence in
Y,
contraryto condition(*).
Thus thereisnoloss ofgeneralityin suming
>
w;
wealsosume,inviewof(*),
that everystrictly increingsequenceonX
converges inX
deverystrictly decreeing sequenceonY
converges inY.
-l(a),
thenforallf
CI’(X
xY), f(/)
andf(31)
converge to thesamelimit in[0,
11.
Thus, byTheorem 3.3,e(/)
e(N)
ino(X
xY);
inotherwords,
(a’)-l(a)
isasingleton.CASE 2. a
(jr,.),
whereone member of this pair is a singularity and the other a fixed ultrafilter. Without loss of generality, we assume that jr is an increasing singularity of order_>
o, and),
where y EY
hasleft orderp_>
0and right order r/_>0.We
first observe thatJr
x)
is a maximal c-filteronX
xY
and obviouslyJr
xTo
complete the proof, it is sufficient to show that if 31 is any maximal c-filter onX
xY
finer thanJ"
x(4(y)C "l)t(y)),
thenf(31)
and/,(jr
x9)
converge to the samelimit in[0,
1]
for allf
CI’(XxY);
then thedesired conclusionthat(a’)-I (a)
isasingletonfollows,
asinCase
1,from Theorem3.3.Furthermore,
sinceq4(y)
and34(y)
areboth c-filtersonY,
3t
_>
)"x(4(y)
CVt(y))
implieseither
3t
>_
Jr
x3),(y)
or 31>_
Jr
x3)(y).
If3t isamaximal c-filter finer thanjr x
"l)(y),
itfollowsbyLemma
5.3thatN
jr x9,
and the conclusion is trivial.We
thusassume, forthe remainder of theproof,that 3l>_
jrxq4(y).
Ifr/ 0, then again
31
Jr
x)
and the proofis complete. Ifr/_>
w,
we observethatY
contains astrictly decreasing sequence; thus by condition(*),
>
w, andfurthermore everystrictly in-creasing sequenceonX
must converge. The existence of the increasing singularityJr
onX
also implies that every strictlydecreasingsequenceonY
must converge.We
nowapplyLemmas
5.4and5.5. If r,then
31
jrx 9, and ifr
>
w,thenf(31)
and/(jr
x9)
havethe same limit in[0,
11
forallf
e
CI’(X
xY).
Thus,
under allcircumstances,(a’)-’(a)
is a singleton, and the proofofthetheoremis complete.For
totally ordered spacesX
andY,
one canshow that ifX
xY
is pseudo-compact, then neitherX
norY
hasa singularity oforder w. Thus itfollowsbyTheorem 5.6that ifX x Y
ispseudo-compact,/oXx
BoY
o(X
xY).
The converseisfalse,
as we showedat the endof Section4.[ll
[21
[31
[4]
[5]
[6]
[7]
[8]
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Ordercompactificationsoftotallyorderedtopologicalspaces,J.ApproximationTheory
13(1975),
56-65.CHOE, T.and
PARK, Y.,
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LINDGREN, W.,
Quasi-uniformspaces,Lect. Notes inPureandAppl. Math.,Vol.77, Marcel Dekker,
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I.,
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On the Wallman ordered compactification,Pactfic
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