http://dx.doi.org/10.4236/am.2016.710104
How to cite this paper: Abdalmonem, A., Abdalrhman, O. and Tao, S.P. (2016) Boundedness of Fractional Integral with Va-riable Kernel and Their Commutators on VaVa-riable Exponent Herz Spaces. Applied Mathematics, 7, 1165-1182.
http://dx.doi.org/10.4236/am.2016.710104
Boundedness of Fractional Integral with
Variable Kernel and Their Commutators on
Variable Exponent Herz Spaces
Afif Abdalmonem
1,2, Omer Abdalrhman
1,3, Shuangping Tao
1*1College of Mathematics and Statistics, Northwest Normal University, Lanzhou, China 2Faculty of Science, University of Dalanj, Dalanj, Sudan
3College of Education, Shendi University, Shendi, Sudan
Received 25 April 2016; accepted 26 June 2016; published 29 June 2016
Copyright © 2016 by authors and Scientific Research Publishing Inc.
This work is licensed under the Creative Commons Attribution International License (CC BY).
http://creativecommons.org/licenses/by/4.0/
Abstract
In this paper, we study the boundedness of the fractional integral operator and their commutator on Herz spaecs with two variable exponents p
( ) ( )
⋅ ,q ⋅ . By using the properties of the variable ex-ponents Lebesgue spaces, the boundedness of the fractional integral operator and their commu-tator generated by Lipschitz function is obtained on those Herz spaces.Keywords
Fractional Integral, Variable Kernel, Commutator, Variable Exponent, Lipschitz Space, Herz Spaces
1. Introduction
Let 0< <
µ
n, Ω ∈L∞( ) ( )
n ×L Sr n−1(
r≥1)
is homogenous of degree zero on n , n1S − denotes the unit sphere in n. If
(i) For any x z, ∈n, one has Ω
(
x,λz)
= Ω( )
x z, ;(ii)
( ) ( )
1(
1(
)
( )
)
1
: sup , d
n r n n
n
r r
L L S s
x
x z σ z
∞ × − −
∈
′ ′
Ω =
∫
Ω < ∞
The fractional integral operator with variable kernel TΩ,µ is defined by
( )
(
) ( )
,
,
d ,
n n
x x y
T f x f y y
x y
µ µ
Ω −
Ω −
=
−
∫
The commutators of the fractional integral is defined by
( )
(
) ( ) ( )
(
)
( )
,
,
, n d ,
m m
n
x x y
b T f x b x b y f y y
x y
µ µ
Ω −
Ω −
= −
∫
−When
µ
≡1, the above integral takes the Cauchy principal value. At this timeµ
≡0, TΩ,µ is much moreclose related to the elliptic partial equations of the second order with variable coefficients. Now we need the further assumption for Ω
( )
x z, . It satisfies(
) ( )
1 , d 0,
n
n s−Ω x z′ σ z′ = ∀ ∈x
∫
For r≥1, we say Kernel function Ω
( )
x z, satisfies the Lr-Dini condition, if Ω meets the conditions (i), (ii) and( )
1
0 d
r ω δ
δ δ < ∞
∫
where ω δr
( )
denotes the integral modulus of continuity of order r of Ω defined by( )
(
1(
)
(
)
( )
)
1
,
sup n , , d
n
r r
r s
x
x z x z z
ρ δ
ω δ − ρ σ
∈ <
′ ′ ′
=
∫
Ω − Ω
where
ρ
is the a rotation in n1 sup
n
z S
z z
ρ ρ
−
′∈
′ ′
= −
when Ω ≡1, TΩ,µ is the fraction integral operator
( )
( )
, n n d .
f y
T f x y
x y
µ µ
Ω = −
−
∫
The corresponding fractional maximal operator with variable kernel is defined by
( )
(
)
,
0
1
sup n , d .
x y r r
M f x x x y y
r
µ µ
Ω = > −
∫
− < Ω −We can easily find that when Ω ≡1 MΩ,µ is just the fractional maximal operator
( )
( )
,
0
1
sup n d
x y r r
M f x f y y
r
µ µ
Ω − − < >
=
∫
Especially, in the case
µ
≡0, the fractional maximal operator reduces the Hardy-Littelewood maximal operator.Many classical results about the fractional integral operator with variable kernel have been achieved [1]-[5]. In 1971, Muckenhoupt and Wheeden [6] had proved the operator TΩ,µ was bounded from
p
L to Lq. In 1991, Kováčik and Rákosník [7] introduced variable exponents Lebesgue and Sobolev spaces as a new method for dealing with nonlinear Dirichet boundary value problem. In the last 20 years, more and more researchers have been interested in the theory of the variable exponent function space and its applications [8]-[14]. In 2012, Wu Huiling and Lan Jiacheng [15] proved the bonudedness property of TΩ,µ with a rough kernel on variable
exponents Lebesgue spaces.
Recently, Wang and Tao [16] introduced the class of Herz spaces with two variable exponents, and also studied the Parameterized Littlewood-Paley operators and their commutators on Herz spaces with variable exponents.
The main purpose of this paper is to discuss the boundedness of the fractional integral with variable kernel ,
TΩµ and their commutators , ,
m
b TΩµ
Throughout this paper E denotes the Lebesgue measure, χE means he characteristic function of a measurable set S⊂n. C always means a positive constant independent of the main parameters and may change from one occurrence to another.
2. Definition of Function Spaces with Variable Exponent
In this section we define the Lebesgue spaces with variable exponent and Herz spaces with two variable ex- ponent, and also define the mixed Lebesgue sequence spaces.
Let E be a measurable set in n with E >0. We first define the Lebesgue spaces with variable exponent. Definition 2.1. see [1] Let p
( )
⋅ :E→[
1,∞)
be a measurable function. The Lebesgue space with variable exponent Lp( )⋅( )
E is defined by( )
( )
( )
( )
is measurable : d for some constant 0
p x p
E
f x
L E f x η
η
⋅ = < ∞ >
∫
The space Lploc( )⋅
( )
E is defined by( )
( )
{
is measurable : ( )( )
for all compact}
p p
loc
L ⋅ E = f f ∈L ⋅ K K⊂E
The Lebesgue spaces Lp( )⋅
( )
E is a Banach spaces with the norm defined by( )( )
( )
( )
inf 0 : d 1
p
p x
L E E
f x
f η x
η ⋅
= > ≤
∫
We denote
( )
{
}
essinf : ,
p−= p x x∈E p+ =esssup
{
p x( )
:x∈E}
. Then ( )
E consists of all p( )
⋅ satisfying p−>1 and p+ < ∞.Let M be the Hardy-Littlewood maximal operator. We denote B
( )
E to be the set of all function( )
( )
p ⋅ ∈ E satisfying the M is bounded on Lp( )⋅
( )
E .Definition 2.2. see [17] Let p
( ) ( )
⋅ ,q ⋅ ∈( )
E . The mixed Lebesgue sequence space with variable exponent( )
( )
( )q p
l ⋅ L ⋅ is the collection of all sequences
{ }
0 j j
f ∞= of the measurable functions on n such that
{ }
0 ( )( )
( ) ( )( )
( )0
inf 0 : q p 1
q p
j j j
l L l L
j
f
f η Q
µ ⋅ ⋅ ⋅ ⋅
∞ ∞
=
=
= > ≤ < ∞
( )
( )
( )(
{ }
)
( )
( ) ( )
1 0
0
inf ; n d 1
q p
p x
j
j j j R
l L
j q x
j
f x
Q f µ x
µ ⋅ ⋅
∞ ∞
= =
= ≤
∑
∫
Noticing q+< ∞, we see that
( )
( )
( )(
{ }
)
( )
( ) ( )
0 0
p q p
q
q
j j j
l L L
j
Q f f ⋅
⋅ ⋅ ⋅
∞
∞ ⋅
= =
∑
=Let
{
n: 2k}
, \ 1, ,k k k k k Ck
B = x∈ x ≤ C =B B− χ =χ k∈
Definition 2.3. see [16] Let α∈,p
( ) ( )
⋅ ,q ⋅ ∈( )
n . The homogeneous Herz space with variable ex- ponent ( ),q( )( )
np
Kα⋅ ⋅ is defined by
( )( )
( )
{
( )(
{ }
)
( ),( )( )
}
,
\ 0 : q n
p
q n p n
Loc
p K
Kα f L f α ⋅ ⋅
⋅ ⋅
⋅ = ∈ < ∞
( )( )
( )
{
}
( )( )
( )( )
( ) ( )
,
0
2
2 inf 0 : 1
q n
p q p
p
q
q k
k k
k
K k
l L k
L
f
f α f
α
α χ η χ
η ⋅
⋅ ⋅ ⋅
⋅
⋅
⋅ ∞
∞
= =−∞
= = > ≤
∑
Remark 2.1. see [16] (1) If q1
( ) ( )
⋅ ,q2 ⋅ ∈( )
n satisfying( ) ( )
1 2
q +≤ q +, then
( ),q1( )
( )
n ( ),q2( )( )
np p
Kα⋅ ⋅ ⊂Kα⋅ ⋅
(2) If q1
( ) ( )
⋅ ,q2 ⋅ ∈( )
n and( ) ( )
1 2
q +≤ q +, then
( )
( )
( )
2
1
n
q q
⋅ ∈
⋅ and
( )
( )
2
1 1
q q
⋅ ≥
⋅ . Thus, by Lemma 3.7 and Remark 2.2, for any ( ),q( )
( )
np
f ∈Kα⋅ ⋅ , we have
( )
( ) ( )
( )
( )
( ) ( )( )
*
2 1 1
1
2 1
( )
2 2 2
1
h h
p
p p
q
q q
p
p p
q q q
k k k
k k k
k k k
L
L L
f f f
α χ α χ α χ
η ⋅ η ⋅ η ⋅
⋅
⋅ ⋅
⋅ ⋅ ⋅
∞ ∞ ∞
=−∞ =−∞ =−∞
≤ ≤ ≤
∑
∑
∑
where
( )
( )
( )
( )
2
1
2
1
2
, 1
2
, 1
k k
h k
k
f q
q p
f q
q
α
α
χ η
χ η
−
+
⋅
≤
⋅
= ⋅
>
⋅
0 *
0 min , 1 max , 1
h h
h
h
h h
h
h
p a p
p a ∞
∈ =
∞
∈ =
≤
=
>
∑
∑
This implies that ( ),q1( )
( )
n ( ),q2( )( )
np p
Kα⋅ ⋅ ⊂Kα⋅ ⋅ . Remark 2.2. Let h∈,ah≥0,1≤ph< ∞. then
*
0 0
p
h h
h h
a a
∞ ∞
= =
≤
∑
∑
where
0 *
0 min , 1 max , 1
h h
h h
h h
h
h
p a p
p a ∞
∈ =
∞
∈ =
≤
=
>
∑
∑
Definition 2.4. see [18] For 0< ≤
β
1, the Lipschitz space( )
nLipβ is defined by
( )
( )
( )
, ,
: sup
n
n
Lip
x y x y
f x f y
Lip f f
x y
β
β β
∈ ≠
−
= = < ∞
−
(1.1)
3. Properties of Variable Exponent
In this section we state some properties of variable exponent belonging to the class
( )
n
B and
( ) ( )
n r n1L∞ L S −
Ω ∈ × .
Proposition 3.1. see [1] If
( )
( )
np ⋅ ∈ satisfies
( )
( )
(
)
, 1 2log
C
p x p y x y x y
−
− ≤ − ≤
( )
( )
(
)
, logC
p x p y y x e x
− ≤ ≥
+ then, we have
( )
( )
np ⋅ ∈B .
Proposition 3.2. see [15] Suppose that p1
( )
⋅ ∈B( )
n , Ω ∈L∞( ) ( )
n ×L Sr n−1 . Let( )
10 n
p
µ
+
< ≤ , and
define the variable exponent p2
( )
⋅ by:( )
( )
1 2
1 1
=
p x p x n
µ
− . Then we have that for all f ∈Lp1( )⋅
( )
n ,( )
( )
1( )( )
2
, Lp n Lp n
TΩµf ⋅ ≤c f ⋅
Proposition 3.3. Suppose that 1
( )
( )
np ⋅ ∈B ,
( )
nb∈Lipβ , 0< ≤
β
1, Ω ∈L∞( ) ( )
n ×L Sr n−1 . Let( )
10 m n
p
µ β
+
< + ≤ , and define the variable exponent p2
( )
⋅ by:( )
( )
1 2
1 1 m
p x p x n
µ+ β
− = . Then
( )
( )
1( )( )
2,
, p n p n
m m
Lip L L
b T f C b f
β
µ ⋅ ⋅
Ω
≤
Proof
( )
(
) ( ) ( )
(
)
( )
(
) ( ) ( )
(
)
( )
(
) ( )
( )
,
,
,
, d
,
d
,
d
n
n
n
m m
n
m n
n m Lip
m Lip
x x y
b T f x b x b y f y y
x y
x x y
b x b y f y y
x y
x x y
C b f y y
x y
C b T f
β
β
µ µ
µ
µ β
µ β
Ω −
−
− −
Ω +
Ω −
= −
−
Ω −
≤ −
−
Ω −
≤
− ≤
∫
∫
∫
By Proposition 3.2, we get
( )
( )
( )
( ) 1( )( )
2 2
, ,
, p n p p n .
m m
m
Lip Lip L
L L
b T f C b T f C b f
β β
µ ⋅ µ β ⋅ ⋅
Ω Ω +
≤ ≤
Now, we need recall some lemmas
Lemma 3.1. see [13] Given
( )
: n[
1,)
p ⋅ → ∞ have that for all function f and g,
( ) ( )
d p( )( )
n p( )( )
nn f x g x x≤C f L ⋅ g L′⋅
∫
Lemma 3.2. see [19] Suppose that 0< <µ n, r>1, Ω ∈L∞
( ) ( )
n ×L Sr n−1 satisfies the rL -Dini con- dition. If there exists an 0<α0<1 2 such that y <α0R then
(
)
( )
( )
1
2
2
, ,
d d
r r
n n y R
r r
n n
R x R
y R
y x x y x x
x CR
R x y x
µ
µ µ
ω δ δ δ
− +
− −
< <
Ω − Ω
− ≤ +
−
∫
∫
Lemma 3.3. see [20] Suppose that x∈n, the variable function q x
( )
is defined by( )
( )
1 1 1
p x = +q q x ,
then for all measurable function f and g, we have
( ) ( )
p( )( )
n( )
q( )
n( )
q( )( )
nL L L
f x g x ⋅ ≤C g x f x ⋅
Lemma 3.4. see [21] Suppose that p
( )
⋅ ∈B( )
n1) For any cube and 2n
Q ≤ , all the
χ
∈Q, then: p( ) 1p x( )Q L Q
χ ⋅ ≈ 2) For any cube and Q ≥1, then p( ) 1
p Q L Q
χ ∞
⋅ ≈ where
( )
limx
p∞ = →∞ p x
Lemma 3.5. see [22] If
( )
( )
np ⋅ ∈B , then there exist constants δ δ1, 2,C>0 such that for all balls B in n
and all measurable subset S⊂R
( )
( )
( )
( )
( )
( )
( )
( )
( )
( )
( )
( )
1 1
1
2 1
1
, ,
p n p n
p
p n n
p n
p n
S
B L L
S L B L
S L
B L
B S
C C
S B
S C
B
δ
δ
χ χ
χ χ
χ χ
′
⋅ ⋅
′ ⋅ ⋅
⋅
⋅
≤ ≤
≤
Lemma 3.6. see [13] If p
( )
⋅ ∈B( )
n , there exist a constant C>0 such that for any balls B in n. we have( )
( )
( )( )
1
p n p n
B L B L C
B χ ⋅ χ ′⋅ ≤
Lemma 3.7. see [16] Let p
( ) ( )
⋅ ,q ⋅ ∈( )
n . If f∈Lp( ) ( )⋅q⋅ , then( ) ( ) ( ) ( )
(
)
( ) ( )(
( ) ( ) ( ) ( ))
min p q , p q max p q , p q
p
q q q q q
L L L L L
f +⋅ ⋅ f −⋅ ⋅ f ⋅ f +⋅ ⋅ f −⋅ ⋅
⋅
≤ ≤
4. Main Theorems and Their Proof
Theorem 1. Suppose that 0< <
µ
n, µ−nδ2< <α nδ1, Ω ∈L∞( ) ( )(
n ×L Sr n−1 r>p2+)
,( ) ( )
( )
1 , 2
n
q ⋅ q ⋅ ∈ with
( ) ( )
q2 −≥ q1 +. And let p1( )
⋅ ∈B( )
n satisfy( )
10 n
p
µ
+
< ≤ and define the vari-
able exponent p2
( )
x by( )
( )
1 2
1 1
p x p x n
µ
− = . Then the operators TΩ,µ is bounded from 1( )1( )
( )
,q n
p
Kα ⋅ ⋅ to
( )2( )
( )
2
,q n
p
Kα ⋅ ⋅ .
Theorem 2. Let b Lip
( )
n , .mβ
∈ ∈ Suppose that 0< <µ n,
(
µ+mβ)
−nδ2 < <α nδ1,( ) ( )(
1)
2
n r n
L∞ L S − r p+
Ω ∈ × > , q1
( ) ( )
⋅ ,q2 ⋅ ∈( )
n with( ) ( )
2 1
q −≥ q +. If p1
( )
⋅ ∈B( )
n satisfy( )
10 m n
p
µ β
+
< + ≤ and define the variable exponent p2
( )
x by( )
( )
1 2
1 1 m
p x p x n
µ+ β
− = . Then the com- mutators bm,TΩ,µ is bounded from 1( )1( )
( )
,q n
p
Kα⋅ ⋅ to ( )2( )
( )
2,q n
p
Kα ⋅ ⋅ .
Proof of Theorem1: Let ( )1( )
( )
1
,q n p
f ∈Kα⋅ ⋅ . We write
( )
( )
j j( )
j j
f x f x χ f x
∞ ∞
=−∞ =−∞
=
∑
=∑
From definition of ( ),q( )
( )
n pKα⋅ ⋅
( )( )
( )
( )
( )( ) ( )
2
, 2
2 2
2
, ,
2
, q n inf 0 : 1
p p
q q k
k K
k
L
T f T f α
α µ µ
χ η
η ⋅
⋅ ⋅
⋅
⋅
∞ Ω
Ω
=−∞
= > ≤
∑
( )
( )( ) ( )
( )
( )( ) ( )
( )
( )( ) ( )
( )
( )( ) ( )
( )
22 2
2 2
2 2
2 2
2
2 2
,
2
, ,
11 12 13 11
1
, ,
1 2
12 13
2
2 2
2 2
p q
p p
q q
p q q
k
k
L
q q
k
k k
j k j k
j j
L L
q k
k k
j k j k
j k j k
L
T f
T f T f
T f T f
α µ
α α
µ µ
α α
µ µ
χ η
χ χ
η η η η
χ χ
η η
⋅ ⋅
⋅ ⋅
⋅ ⋅
⋅ ⋅
⋅ Ω
⋅ ⋅
∞ −
Ω Ω
=−∞ =−∞
⋅
+ ∞
Ω Ω
= − = +
≤ ≤
+ +
+ +
∑
∑
∑
∑
( )
( ) ( )
2
2 2
p q q
L ⋅ ⋅
⋅
where
( )
( )
( )
( )2 2
2
11 2 ,
q p
k k
j k j
k l L
T f
α µ
η χ
⋅ ⋅
∞ −
Ω
=−∞ =−∞
=
∑
( )
( )
( )
( )2 2
1
12 ,
1
2
q p
k k
j k j k
k l L
T f
α
µ
η χ
⋅ ⋅
∞ +
Ω
= − =−∞
=
∑
( )
( )
( )
( )2 2
13 ,
2
2
q p
k
j k j k
k
l L
T f
α
µ
η χ
⋅ ⋅
∞ ∞
Ω
= + =−∞
=
∑
And η η= 11+η12+η13, thus
( )
( )( ) ( )
2
2 2
,
2
p q
q k
j k
k
L
T f
C
α
µ χ
η ⋅
⋅
⋅
∞ Ω
=−∞
≤
∑
That is
( )
( )( )
( )
[
]
, 2 2
, q n 11 12 13 .
p K
T µ f α ⋅ Cη C η η η
⋅
Ω ≤ = + +
This implies only to prove
( )( )
( )
, 1 1
11, 12, 13 q n
p
K
C f α
η η η
⋅⋅
≤ . Denote
( )( )
( )
, 1 1
1 q n
p
K
f α
η
⋅⋅
=
Now we consider η12. Applying Lemma 3.7
( )
( )( ) ( )
( )
( )
( )
( )
( )
( )
12 2
2
2 2
1 2
2
1 1
, ,
1 1
1 1
1
,
1 1
2 2
2 p
p q
p
q q k
k k
k k
j k j k
j k j k
k k
L L
q k k
k
j k
k j k
L
T f T f
C
T f C
α α
µ µ
α µ
χ χ
η η
χ η ⋅
⋅ ⋅
⋅
⋅
+ +
Ω Ω
∞ = − ∞ = −
=−∞ =−∞
∞ + Ω
=−∞ = −
≤
≤
∑
∑
∑
∑
where
( )
( )
( )
( )
( ) ( )
( )
( )
( )
( ) ( )
2
2 2
2
2 2
1
, 1 2
1
1 2
1
, 1 2
1 2
, 1
2
, 1
p q
p q q k
k
j k j k
L q k
k
j k j k
L
T f q
q k
T f q
α
µ
α
µ
χ
η
χ
η
⋅ ⋅
⋅ ⋅
⋅ +
Ω = − −
⋅ +
Ω = − +
≤
=
>
∑
∑
By the Proposition 3.2, we get
( )
( )( ) ( )
( )
( )
21 2
1 2
2
1
, 1
1
1
1 1
2
2
p p
q
q k
k
q k k
j k k
j k j
k k j k
L
L
T f
f C
α
α µ χ
η η ⋅
⋅ ⋅
⋅ +
Ω
∞ = − ∞ +
=−∞ =−∞ = −
≤
∑
∑
∑ ∑
Since ( )1( )
( )
1,q n p
f ∈Kα⋅ ⋅ , then we have
( )
1
2
1
p
j j
L
f
α χ
η ⋅ ≤ , and
( )
( ) ( )
1
1 1
1 2
1 p q q j
j j
L
f
α χ
η ⋅
⋅
⋅ ∞
=−∞
≤
∑
By Lemma 3.7 and Remark 2.2, we get
( )
( )( ) ( )
( )
( ) ( )
( )
( )
( )
( ) ( )
2 1
2
1 1
1 1 2
2
*
1
1
1
1
, 1
1 1
1 2
2
2
p q p
q
p q q
k q k
k
q q
j k k
j k k
k k L
L L
q q
k k k
L L
T f
f C
f
C C
α
µ α
α
χ
χ
η η
χ η
+
⋅ ⋅ ⋅
⋅
⋅ ⋅
⋅ +
⋅ Ω
∞ = − ∞
=−∞ =−∞
⋅ ∞
=−∞
≤
≤ ≤
∑
∑
∑
∑
Hence
( ) ( )
( )
11 , 2 2
p + p −≤ q k, and
( )
( )
1 2 *
1 min
k
q k q
q ∈
+
=
, this implies that
( )( )
( )
, 1 1
12 1 q n
p
K
C C f α
η
η
⋅⋅
≤ ≤
Now, we estimate of η11 using size condition of fj and Minkowski inequality, when j≤ −k 1 we get,
( )
( )( )
( ) (
)
( )
( )
( )
2
2
,
, ,
d
p n j
p n
j k L B j n n k
L
x x y x x
T f f y y
x y x
µ χ ⋅ µ µ χ
⋅
Ω − −
Ω − Ω
≤ −
−
∫
Since r> p2+ we define the variable exponent
( )
( )
2 2
1 1 1
p x = +r p x , by Lemma 3.3 we get
(
)
( )
( )
( )
(
)
( )
( )
( )
( )
(
)
( )
( )
( )( )
22
2
, , , ,
, ,
p x n r n
p n
p x n k r n
k k
n n n n L
L L
B
n n L
L
x x y x x x x y x x
x y x x y x
x x y x x x y x
µ µ µ µ
µ µ
χ χ
χ ⋅
− − − −
− −
Ω − Ω Ω − Ω
− ≤ −
− −
Ω − Ω
≤ −
−
According Lemma 3.4 and the formula
( )
( )
2 2
1 1 1
p x = p x −r, then we have
( )
( )
( )( )
( )( )
2 2 1
1 1
p x n p x n p x n
k k k
r r n
B L B L Bk B L Bk
µ
χ χ − χ −−
≈ ≈
(1.2)
By Lemma 3.2, we get
(
)
( )
( )
( )
( )
( )
( )
1
2
1 2
1
0
1
, ,
d 2
2 1 d
2
k
k r n
n y
n
r r
n n k
y L
n n
j k r
r
n
k n
r
y
x x y x x
CR
x y x
CR
C
µ
µ µ
µ β
µ
ω δ δ δ
ω δ δ δ −
− +
− − −
− + −
− − +
Ω − Ω
− ≤ +
−
≤ +
≤
∫
∫
It follows that
( )
2( )( )
( )
1( )( )
, p n 2 j d k p x n
kn
j k B j B L
L
T µ f χ ⋅ C f y y χ
−
Ω ≤
∫
(1.3)By the Equation (1.3) and using Lemmas 3.1, 3.5, 3.6, 3.7, we can obtain
( )
( )( ) ( )
( )
( )
( )
( )
( )( )
( )
( )
( )( )
22 2
2
2 2
2 2
2 2
1 1 1( )
1 1
2 2
, ,
1 1
2 2
1 1
2 2
2 2 2 2
p
p q
p p p
j k
p
n n
q q k
k k
k k
j k j k
j j
k k
L L
q k q k
k k
j j
k kn k kn
k L B L B L
k j L k j L
T f T f
C
f f
C C
α α
µ µ
α α
χ χ
η η
χ χ χ
η η
⋅
⋅ ⋅
⋅ ′ ⋅ ⋅
⋅
⋅
− −
Ω Ω
∞ =−∞ ∞ =−∞
=−∞ =−∞
∞ − ∞ −
− −
=−∞ =−∞ =−∞ =−∞
≤
≤ ≤
≤
∑
∑
∑
∑
∑
∑
∑
∑
( )
( )
( ) ( )
( )
( )
( )
( )
( )
( )( )
( )
( ) ( )
( )
( )
( )
2 2
2 2
1 1
1 1 1
2 2
1 1
1
1 1
2 2
1 1
1
2
1
2 2 2
2 2
p j
p n p p n
k
p q n
q k q k
k B k
j j k n j
k L k
k j L B k j L
L
q k
q q
j k
j k j k n
k j
L
f f
C C
f C
δ
α α
α δ α
χ
η χ η
χ η
′ ⋅
⋅ ′ ⋅ ⋅
+
⋅ ⋅
∞ − ∞ −
−
=−∞ =−∞ =−∞ =−∞
⋅ ∞ −
− − =−∞ =−∞
≤
≤
∑
∑
∑
∑
∑ ∑
( )
( )
( )
( ) ( ) ( )( )
( )
( ) ( ) ( ) 2 2 2 2 2 2 2 , 2 1 2 2 2 , 2 1 2, 1
2
, 1
p q p q q k k j k j L q k k j k j L T f q q k T f q α µ α µ χ η χ η ⋅ ⋅ ⋅ ⋅ ⋅ − Ω =−∞ − ⋅ − Ω =−∞ + ≤ =
>
∑
∑
Since ( )1( )
( )
1,q n p
f ∈Kα⋅ ⋅ , then we have
( ) 1 2 1 p j j L f α χ η ⋅
≤ , and
( ) ( ) ( ) 1 1 1 1 2 1 p q q j j j L f α χ η ⋅ ⋅ ⋅ ∞ =−∞ ≤
∑
Now if
( )
q1 + <1, then we have( )
( ) ( ) ( ) ( )( ) ( ) ( ) ( )( )
( )
( ) ( ) ( ) ( )( )
( )( ) 2 2 2 1 1 1 1 1 2 2 * 1 1 1 1 2 , 2 1 1 2 1 2 2 2 2 2 p q n pq
p q n
q k q k q k q j
j k k
j k
j j k n
k k j
L L
q q
j
j k j k n
j k j
L T f f C f C C α α µ δ α α δ α χ χ η η χ η + ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ ⋅ − ⋅ Ω ∞ =−∞ ∞ − − − =−∞ =−∞ =−∞ ⋅ ∞ ∞ − − =−∞ = + ≤ ≤ ≤
∑
∑
∑ ∑
∑
∑
where
( )
( )
2 2 * 1 min k q k q q ∈ + = If
( )
q1 + ≥1, then we have( )
( ) ( ) ( ) ( )( )( ) ( ) ( ) ( )( )
( )
( ) ( )( )(( ) )( )
( ) ( ) ( ) 2 2 2 2 2 2 2 1 1 1 1 2 1 1 1 1 1 1 2 , 1 2 2 2 2 1 1 2 2 2 2 2 p qp q n
p q k k j k j k L q k q q q q j q q
k j k n k j k n
j k
k j j
L q j j k j L T f f C f C α µ α
δ α δ α
α χ η χ η χ η ⋅ ⋅ + ′ ′ + + ⋅ ⋅ ⋅ − Ω ∞ =−∞ =−∞ + ⋅ + ∞ − − − − − − =−∞ =−∞ =−∞ ⋅ ∞ =−∞ ≤ × ≤
∑
∑
∑ ∑
∑
∑
( ) ( )( )
( )( )( )
* 1 1 1 2 2 2 q n q q j k nk j
C
δ α +
where
( )
( )
2 2 *
1 min
k
q k q
q ∈
+
=
, this implies that
( )( )
( )
, 1 1
11 1 q n
p
K
C C f α
η
η
⋅⋅
≤ ≤
Finally, we estimate η13 by Lemma 3.7, we get
( )
( )( ) ( )
( )
( )
( )
(
) ( )
( )
( )
3
2 2
2
2 2
3 2
2
, ,
2 2
1 1
2 1
2 2
, 1
2 d
p
p q
j
p
q q k
k k
j k j k
j k j k
k k
L L
q k
k
j k
n
k j k C
L
T f T f
C
x x y
f y y x y
α α
µ µ
α
µ
χ χ
η η
χ η
⋅
⋅ ⋅
⋅
⋅
∞ ∞
Ω Ω
∞ = + ∞ = +
=−∞ =−∞
∞ ∞
− =−∞ = +
≤
Ω −
≤
−
∑
∑
∑
∑
∑
∑
∫
(1.4)
Note that, when x∈Ck, j≥ +k 2, then x−y ~ x. Therefore, applying the generalized Hölder’s In- equality, we have
(
) ( )
( )
(
)
( )1
1
, ,
d p
p j
j j j
n L n
C
L
x x y x x y
f y y f
x y µ x y µ
χ ⋅
′ ⋅
− −
Ω − Ω −
≤
− −
∫
Define the variable exponent
( )
( )
1 1
1 1 1
p′ ⋅ = +r p′ ⋅ by Lemma 3.3, then we have
(
) ( )
( )
(
)
( )
1
1 ,
d p , r
p j
j
j j
n L L n
C
L
x x y
f y y f x x y
x y µ x y µ
χ ⋅
′ ⋅
− −
Ω −
≤ Ω −
− −
∫
(
) ( )
( )
( ) ( )
(
(
)
( )
)
( )
( ) ( )
( ) ( )
( )
( ) ( )
1
1 1
2
1
1 1
1 1
1 2
1
2 ,
d
2 d , d
2 2
2 2
j
j
p p n
j
n r n
p p
p p
j n C
r r
j n n
j L j L s
jn
j n r
j L j L L L S
jn
j n r
j L j L
x x y
f y y x y
C f r r x y y
C f
C f
µ
µ
µ
µ
χ σ
χ
χ ′
⋅ ⋅ −
−
∞ −
′
⋅ ⋅
′
⋅ ⋅
−
− − −
− −
× − −
Ω −
−
′ ′
≤ Ω
≤ Ω
≤
∫
∫
∫
According Lemma 3.4 and the formula
( )
1( )
1
1 1 1
p r
p′ ⋅ = ′ ⋅ − , we have 1( ) 1( )
1
p p
j j
r
B B j
L L B
χ
′⋅χ
′⋅−
≈ Then we get
(
) ( )
( )( ) ( )
1 1
,
d 2 p j p
j
j n
j j B
n L L
C
x x y
f y y f
x y
µ
µ ⋅ χ ′ ⋅
− − −
Ω −
≤ −
∫
(1.5)From Equations (1.4), (1.5) and using Lemma 3.7, and
( )
( ) ( )
1
1 1
1 2
1 p q q j
j
L
f
α χ
η ⋅
⋅
⋅
≤
( )
( )( ) ( )
( )
( )
( )
( ) ( )( )
22 2
3 2
2 1
1
, 2
1
2 1
2
2 2
p q
p p
j k
p n q k
j k j k
k
L
q k j
j n k
B B
L L
k j k L
T f
f C
α
µ
µ α
χ
η
χ χ
η
⋅ ⋅
⋅ ′ ⋅
⋅
⋅ ∞
Ω ∞ = + =−∞
∞ ∞
− − =−∞ = +
≤
∑
∑
∑
∑
Note that
( ) ( )
2 2 1
p p
k k
k
B L C B L
µ
χ ⋅ ≤ − χ ⋅ see [9]. Then we have
( )
( )( ) ( )
( )
( )
( ) ( )( )
( )
( )
( )
( )
( )
( )
( )
2
2 2
3 2
1 1
1
3 2
1
1
1
, 2
1
2 1
2 1
2
2
2 2 2 2
2 2
2 2
p q
p p
j k
p n
p k p n
p j
q k
j k j k
k
L
q k
j
k j jn k
B B
L L
k j k L
q k
B j
j k
k L
k j k L
B L
k j n k
k j k
T f
f C
f C
C
α
µ
α µ µ
µ α
α
χ
η
χ χ
η
χ
η χ
⋅ ⋅
⋅ ′ ⋅
⋅
⋅
⋅
⋅
⋅ ∞
Ω ∞ = + =−∞
∞ ∞
− −
=−∞ = +
∞ ∞
− =−∞ = +
∞ ∞
− =−∞ = +
≤
≤
≤
∑
∑
∑
∑
∑
∑
∑
∑
( )
( )
( )
( )
( )( )
( )
( ) ( )
( )
( )
( )
3 2
2
1
3 2
1 1
2
1 1
1
1
2 1
2 2
p n
p q n
q k
j
L
q k
q q
j j k k j n
k j k
L
f
f C
δ µ
α δ µ α
η
χ η
⋅
+
⋅ ⋅
−
⋅ ∞ ∞
− − + =−∞ = +
≤
∑ ∑
where
( )
( )
( )
( )
( ) ( )
( )
( )
( )
( ) ( )
2
2 2
2
2 2
, 2 2
1
3 2
, 2 2
1 2
, 1
2
, 1
p q
p q q k
j k j k
L q k
j k j k
L
T f q
q k
T f q
α
µ
α
µ
χ
η
χ
η
⋅ ⋅
⋅ ⋅
⋅ ∞
Ω = + −
⋅ ∞
Ω = + +
≤
=
>
∑
∑
( )( )
( )
, 1 1
13 1 q n
p
K
C C f α
η
η
⋅⋅
≤ ≤
This completes the proof Theorem 1. Proof of Theorem 2
Let b Lip
( )
nβ
∈ , ( )1( )
( )
1,q n p
f∈Kα⋅ ⋅ . We write
( )
( )
k j( )
j j
f x f x χ f x
∞ ∞
=−∞ =−∞
=
∑
=∑
From definition of ( ),q( )
( )
n pKα⋅ ⋅
( )
( )( )
( )
( )
( )( ) ( )
2
, 2
2 2
2
, ,
2 ,
, q n inf 0 : 1
p p
q
q
k m
k m
k K
k
L
b T f
b T f α
α
µ µ
χ
χ η
η ⋅
⋅ ⋅
⋅
⋅
∞ Ω
Ω
=−∞
= > ≤
∑
Since
( )
( )( ) ( )
( )
( )
( ) ( )
( )
( )
( ) ( )
( )
( )( )
2
2 2
2 2
2 2
2 2
2
2
,
2
, ,
21 22 23 21
1
, 1
22
2 ,
2 , 2 ,
2 ,
p q
p p
q q
p q q
k m
k
L
q q
k
k m k m
k k
j j
L L
q k
k m
k j k
L
b T f
b T f b T f
b T f
α
µ
α α
µ µ
α
µ
χ η
χ χ
η η η η
χ
η
⋅ ⋅
⋅ ⋅
⋅ ⋅
⋅
⋅ Ω
⋅ ⋅
∞ −
Ω Ω
=−∞ =−∞
⋅ +
Ω = −
≤ ≤
+ +
+
∑
∑
∑
( )
( )
( )( ) ( )
2
2
2 2
, 2
23
2 ,
p q q
k m
k j k
L
b T f
α
µ χ
η
⋅
⋅ ⋅
⋅ ∞
Ω = +
+
∑
where
( )
( )
( )
( )2 2
2
21 2 , ,
q p
k
k m
k j
k l L
b T f
α
µ
η χ
⋅ ⋅
∞ −
Ω
=−∞ =−∞
=
∑
( )
( )
( )
( )2 2
1
22 ,
1
2 ,
q p
k
k m
k j k
k l L
b T f
α
µ
η χ
⋅ ⋅
∞ +
Ω
= − =−∞
=
∑
( )
( )
( )
( )2 2
23 ,
2
2 ,
q p
k m
k j k
k l L
b T f
α
µ
η χ
⋅ ⋅
∞ ∞
Ω
= + =−∞
=
∑
And η η= 21+η22+η23. The similar to prove of Theorem 1
( )
( )( )
( )
[
]
, 2 2
, 21 22 23
, q
n p m
k K
b T µ f χ α ⋅ Cη C η η η
⋅
Ω
≤ ≤ + +
Hence
( )
( )( )
( )
, 1 1
21, 22, 23 n q n
p m
Lip K
C b f α β
η η η ⋅
⋅
≤ . Denote
( )( )
( )
, 1 1
1 q n
p
K
f α
η
⋅⋅
=
First we estimate η22. Note that bm,TΩ,µ is bonuded on ( )
( )
p n