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Table of Contents

Copyright © Cengage Learning. All rights reserved 2 5.1 Pressure

5.2 The Gas Laws of Boyle, Charles, and Avogadro 5.3 The Ideal Gas Law

5.4 Gas Stoichiometry

5.5 Dalton’s Law of Partial Pressures

5.6 The Kinetic Molecular Theory of Gases 5.7 Effusion and Diffusion

5.8 Real Gases

(3)

Why study gases?

(4)

Pressure

Return to TOC Copyright © Cengage Learning. All rights reserved 4

• Uniformly fills any container.

Mixes completely with any other gas.

Exerts pressure on its surroundings.

(5)

Pressure

SI units = 1 Pascal (Pa) = Newton/meter2

1 standard atmosphere (1 atm)

101,325 Pa

760 mm Hg

Pressure

force Pr essure =

(6)

Pressure

Return to TOC Copyright © Cengage Learning. All rights reserved 6

The pressure of a gas is measured as 2.5 atm. Represent this pressure in both torr and pascals.

Pressure Conversions: An Example

2.5 atm

760 torr = 1.9 10 torr3 1 atm

 

 

2.5 atm

101,325 Pa = 2.5 10 Pa5 1 atm

 

(7)

Pressure

Barometer

Device used to measure

atmospheric pressure.

Mercury flows out of the

tube until the pressure of the column of

(8)

The Gas Laws of Boyle, Charles, and Avogadro

Return to TOC Copyright © Cengage Learning. All rights reserved 8

Robert Boyle studies the relationship between the pressure on a gas and volume of a gas

Boyle’s Law

Using a J-shaped tube closed at one end, which he reportedly set up in the multistory entryway of his house, Boyle studied the relationship between the pressure of the trapped gas and its volume.

• Adding mercury to the open end of the tube

• Increases pressure on the trapped gas

• Decreases the volume of the trapped gas

(9)

The Gas Laws of Boyle, Charles, and Avogadro

Boyle’s Law

This is some of Boyles data

When we plot P vs V

We see that as

• Pressure goes down

(10)

The Gas Laws of Boyle, Charles, and Avogadro

Return to TOC Copyright © Cengage Learning. All rights reserved 10

Boyle’s Law

If we plot the data as V vs 1/P

we get a straight line which intersects the Y axis at 0.

This is very helpful because can use the equation for a straight line to look at the relationship between V and P.

so if y = m x + b then V = k 1

(11)

The Gas Laws of Boyle, Charles, and Avogadro

Boyle’s Law

so since V = 1

P k + 0

then V = k P

or VP = k

(12)

The Gas Laws of Boyle, Charles, and Avogadro

Return to TOC Copyright © Cengage Learning. All rights reserved 12

• PV = k

Specific temperature and number of

moles (n)

This means that the product of pressure

and volume is always the same value for a given sample of gas at a given

temperature

Boyle’s Law

1 1 = 2 2

(13)

The Gas Laws of Boyle, Charles, and Avogadro

Calculations Using Boyle’s Law

Freon-12, CCl2F2, is used in refrigeration systems. What is the new volume (L) of a 8.0-L sample of Freon gas initially at 550 mmHg after its pressure is changed to 2200 mmHg at constant T and n?

P1 = 550 mmHg P2 = 2200 mmHg V1 = 8.0 L V2 = ?

(14)

The Gas Laws of Boyle, Charles, and Avogadro

Return to TOC Copyright © Cengage Learning. All rights reserved 14

Learning Check

A sample of helium gas occupies 12.4 L at

23°C and 0.956 atm. What volume will it

(15)

The Gas Laws of Boyle, Charles, and Avogadro

Ideal Gases vs Real Gases

Gases that obey Boyles Law are called “ideal gases” (Section 5.3)

• PV = k

• Plot of PV vs P linear

• Ne and O2 show only small deviations

from ideal behavior at low pressures

• CO2 shows larger deviation from

ideal behavior

(16)

The Gas Laws of Boyle, Charles, and Avogadro

Return to TOC Copyright © Cengage Learning. All rights reserved 16

(17)

The Gas Laws of Boyle, Charles, and Avogadro

• What happened to the gas in the

balloon?

A decrease in temperature was followed

by a decrease in the volume of the balloon.

There is a direct relationship between

volume and temperature

This is an observation

(18)

The Gas Laws of Boyle, Charles, and Avogadro

Return to TOC Copyright © Cengage Learning. All rights reserved 18

• Observation: The volume of a gas

depends on the temperature of the gas

At constant pressure (P)

At constant number of moles (n)

What law summarizes observations

like these?

(19)

The Gas Laws of Boyle, Charles, and Avogadro

• Volume and Temperature (in Kelvin) are

directly related

(constant P and n).

V=bT (b is a proportionality constant)

Charles’s Law

1 2

1 2

=

V V

T T

V

(20)

The Gas Laws of Boyle, Charles, and Avogadro

Return to TOC Copyright © Cengage Learning. All rights reserved 20

Learning Check

Suppose a balloon containing 1.30 L of air at 24.7°C is placed into a beaker containing liquid nitrogen at –78.5°C. What will the

(21)

The Gas Laws of Boyle, Charles, and Avogadro

The volumes different gases with different numbers of moles all

extrapolate to the same value

- 273°C or 0K

0 K is called absolute zero.

At this point atoms or molecules have no volume and no molecular

motion (where entropy reaches its minimum value)

(22)

The Gas Laws of Boyle, Charles, and Avogadro

Return to TOC Copyright © Cengage Learning. All rights reserved 22

• In some problems 2 variables change and

you want to determine the value of the third variable

ie pressure and volume change and you

want to determine the new temperature

To solve these problems we can combine

Boyles and Charles Law

The Combined Gas Law

P

1

V

1
(23)

The Ideal Gas Law

Exercise

At what temperature (in °C) does 121 mL of CO2 at 27°C and 1.05 atm occupy a volume of 293 mL at a pressure of 1.40 atm? P1 = 1.05 atm P2 = 1.40 atm

V1 = 121 mL V2 = 293 mL T1 = 27°C T2 = ?

P1V1

T1 = P2 V2 T2

T2= P2V2T1

P1V1 so T2 = 1.40 atm

  293 m L  27+273  1.05 atm

(24)

The Ideal Gas Law

Return to TOC

Learning Check

A sample of helium gas has a volume of 0.180 L, a pressure of 0.800 atm, and a temperature of 29 °C. At what temperature (°C) will the helium have a volume of 90.0 mL and a pressure of 3.20 atm (n is constant)?

(25)

The Gas Laws of Boyle, Charles, and Avogadro

• Chapter 2 Avogadro postulated that equal

volumes of gases at the same temperature and pressure contain the same number of “particles.

Avogadro’s law,

Volume and number of moles are directly related

(constant T and P).

V = an (a is a proportionality constant)

Avogadro’s Law

n n

(26)

The Gas Laws of Boyle, Charles, and Avogadro

Return to TOC Copyright © Cengage Learning. All rights reserved 26

Learning Check

If 2.45 mol of argon gas occupies a volume

of 89.0 L, what volume will 2.10 mol of

(27)

The Ideal Gas Law

• We can bring all of these laws together into one

comprehensive law:

Basically adding Avogadro’s Law to the

combined gas law

PV = nRT

V = k

(28)

The Ideal Gas Law

Return to TOC Copyright © Cengage Learning. All rights reserved 28

PV = nRT

When using the ideal gas law Volume has to be in L

Temperature has to be in K Pressure has to be in atm

This is because of the units of R

(29)

The Ideal Gas Law

Learning Check

An automobile tire at 23°C with an internal volume of 25.0 L is filled with air to a total pressure of 3.18 atm. Determine the

(30)

The Ideal Gas Law

Return to TOC Copyright © Cengage Learning. All rights reserved 30

Learning Check

What is the pressure in a 304 L tank that

contains 5.670 kg of helium at 25°C?

(31)

The Ideal Gas Law

• Which equation do I use?

Write down initial and final conditions and look for

what is missing?

Units and Gas Law Problems

Don’t have to change units of pressure or volume

Units just have to be the same

(32)

Gas Stoichiometry

Return to TOC Copyright © Cengage Learning. All rights reserved 32

• For 1 mole of an ideal gas at 0°C and 1

atm, the volume of the gas is 22.42 L.

STP = standard temperature and pressure

 0°C and 1 atm

Therefore, the molar volume is 22.42 L

at STP.

Molar Volume of an Ideal Gas

1.000 mol 0.08206 L atm/K mol 273.2 K

 

 

V = = = 22.42 L

1.000 atm

 

(33)

Gas Stoichiometry

(34)

Gas Stoichiometry

Return to TOC Copyright © Cengage Learning. All rights reserved 34

Concept Check

A sample of oxygen gas has a volume of

2.50 L at STP. How many grams of O2 are

present?

(35)

Gas Stoichiometry

•We can determine the molar mass of a gas from a measurement of the density

Molar Mass of a Gas

PV = nRT where n = g

molar mass

so PV= gRT

molar mass and P=

g RT molar mass

  V 

and since g

V  density

(36)

Gas Stoichiometry

Return to TOC Copyright © Cengage Learning. All rights reserved 36

d = density of gas

T = temperature in Kelvin

P = pressure of gas

R = universal gas constant

Molar Mass of a Gas

 

g L atm

K

g L mol K

= =

atm mol

Molar mass =

(37)

Gas Stoichiometry

Concept Check

The density of a gas was measured at 1.50 atm and 27°C and found to be 1.95 g/L.

(38)

Gas Stoichiometry

Return to TOC Copyright © Cengage Learning. All rights reserved 38

Concept Check

(39)

Dalton’s Law of Partial Pressures

• For a mixture of gases in a container,

P

Total

= P

1

+ P

2

+ P

3

+ . . .

The total pressure exerted is the sum of

(40)

Dalton’s Law of Partial Pressures

Return to TOC Copyright © Cengage Learning. All rights reserved 40

Concept Check

Consider the following apparatus containing helium in both sides at 45°C. Initially the valve is closed.

After the valve is opened, what is the pressure of

the helium gas?

There is more than one way to solve this.

3.00 atm

3.00 L 2.00 atm

(41)

Dalton’s Law of Partial Pressures

Concept Check

27.4 L of oxygen gas at 25.0°C and 1.30 atm, and 8.50 L of helium gas at 25.0°C

and 2.00 atm were pumped into a tank with a volume of 5.81 L at 25°C.

Calculate the new partial pressure of oxygen. Calculate the new partial pressure of helium.

(42)

The Kinetic Molecular Theory of Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 42

• So far we have considered “what

happens,” but not “why.”

Observations – direct relationship

between volume and temperature

Laws – Charles Law

This is the What

Now we need a Theory

This is the Why

In science, “what” always comes before

(43)

The Kinetic Molecular Theory of Gases

1) The particles are so small compared with the distances between them that the volume of the individual particles can be assumed to be negligible (zero).

2) The particles are in constant motion. The collisions of the particles with the walls of the container are the cause of the pressure exerted by the gas.

3) The particles are assumed to exert no forces on each other; they are assumed neither to attract nor to repel each other.

4) The average kinetic energy of a collection of gas particles is assumed to be directly proportional to the Kelvin

(44)

The Kinetic Molecular Theory of Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 44

Concept Check

You are holding two balloons of the same volume. One contains

helium, and one contains

hydrogen. Complete each of the following statements

with “different” or “the same”

and be prepared to justify your answer.

He

(45)

The Kinetic Molecular Theory of Gases

Concept Check

•Complete the following

statement with “different” or “the same” and be prepared to justify your answer.

The pressures of the gas in the two balloons are

__________.

He

(46)

The Kinetic Molecular Theory of Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 46

Concept Check

•Complete the following

statement with “different” or “the same” and be prepared to justify your answer.

The temperatures of the gas in the two balloons are __________.

He

(47)

The Kinetic Molecular Theory of Gases

Concept Check

•Complete the following

statement with “different” or

“the same” and be prepared to justify your answer.

The numbers of moles of the gas in the two balloons are

__________.

He

(48)

The Kinetic Molecular Theory of Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 48

Concept Check

•Complete the following

statement with “different” or “the same” and be prepared to justify your answer.

The densities of the gas in the two balloons are

__________.

He

(49)

The Kinetic Molecular Theory of Gases

Pressure and Volume - Molecular View of Boyle’s Law

P = (nRT) 1

V

Constant

For a given sample of gas at a given temperature (n and T are constant) that if the volume of a gas is decreased, the pressure increases.

(50)

The Kinetic Molecular Theory of Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 50

Pressure and Temperature – Molecular View

P = ( nR

V

) T

Constant

From the ideal gas law P directly proportional to T.

The KMT accounts for this behavior because when the temperature of a gas increases, the speeds of its particles

increase, the particles hitting the wall with greater force and greater frequency. Since the volume remains the same, this would result in increased gas pressure,

(51)

The Kinetic Molecular Theory of Gases

Volume and Temperature - Molecular View of Charles’s Law

V

= ( nR

P

) T

Constant

The ideal gas law states that for a sample of gas at a constant P, the volume of the gas is directly proportional to the Kelvin temperature

(52)

The Kinetic Molecular Theory of Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 52

Volume and Number of Moles = Molecular View of Avagadro’s Law

V

= ( RT

P

) n

Constant

The ideal gas law predicts that the volume of a gas at a constant T and P depends directly on the n. This makes sense in terms of the KMT because an increase in the n at the same temperature would cause the pressure to increase if the volume were held constant. The only way to return the pressure to its original value is to increase the volume.

(53)

The Kinetic Molecular Theory of Gases

Volume and Number of Moles = Molecular View of Avogadro’s Law

V

= ( RT

P

) n

Constant

Remember that the volume of a gas (at constant P and T) depends only on the number of gas particles present. The individual volumes of the particles are not a factor because the particle volumes are so small compared with the distances between the particles (for a gas behaving ideally).

(54)

The Kinetic Molecular Theory of Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 54

Mixture of Gases – Molecular View of Daltons Law

The observation that the total pressure exerted by a mixture of gases is the sum of the pressures of the individual gases is expected because the KMT assumes that all gas particles are

(55)

The Kinetic Molecular Theory of Gases

Deriving The Ideal Gas Law

Can the ideal gas law be derived from the assumptions the KMT Yes!

And if you can do it

You will get extra credit on the next exam!

Your derivation must include

(56)

The Kinetic Molecular Theory of Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 56

Deriving The Ideal Gas Law

P = 2 3

nNA 1 2mu2 V          

P = pressure, n = moles, NA = Avogadro’s number, m is mass, u2 is the average of the square of the velocities of the particles, V = volume

KE

 avg = NA 1 2mu 2      

mu2 = the average kinetic energy of a gas particle. mu2 x NA, = average kinetic energy for a mole of gas particles

P = 2 3

n KE avg V       

 becomes PVn = 23 KE avg

The fourth postulate of the KMT is that the average kinetic energy of the particles in the gas sample is directly proportional to the Kelvin

temperature.

PV

n = 23 KE avg so PVn  T

(57)

The Kinetic Molecular Theory of Gases

Deriving The Ideal Gas Law

PV

n  T From KMT

PV

n  RT

From Experiment

(58)

The Kinetic Molecular Theory of Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 58

Concept Check

You have a sample of nitrogen

gas (N2) in a container fitted with

a moveable piston that maintains a pressure of 6.00 atm. Initially, the gas is at 45°C in a volume of 6.00 L.

You then cool the gas

(59)

The Kinetic Molecular Theory of Gases

Concept Check

Which best explains the final result that

occurs once the gas sample has cooled?

(60)

The Kinetic Molecular Theory of Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 60

Concept Check

The gas sample is then cooled to a

temperature of 15°C. Solve for the new

condition. (Hint: A moveable piston keeps the

(61)

The Kinetic Molecular Theory of Gases

•KMT tells us that the Kelvin temperature indicates the average kinetic energy of the gas particles.

•The exact relationship between temperature and average kinetic energy can be obtained by combining equations (1) and (2).

•Equation (3) summarizes the meaning of the Kelvin temperature of a gas.

The Meaning of Temperature

PV

n  RT (1)

PV

n = 23 KE avg (2) KEavg 

3

(62)

The Kinetic Molecular Theory of Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 62

R = 8.3145 J/K·mol

(J = joule = kg·m2/s2)

T = temperature of gas (in K)

M = mass of a mole of gas in kg

Final units are in m/s.

Root Mean Square Velocity

urms = 3RT

(63)

The Kinetic Molecular Theory of Gases

Concept Check

Calculate the root mean square velocity for the atoms in a sample of helium gas at

(64)

Effusion and Diffusion

Return to TOC Copyright © Cengage Learning. All rights reserved 64

• Diffusion – the mixing of

gases.

Effusion – describes the

passage of a gas through a tiny orifice into an evacuated chamber.

Rate of effusion measures the

speed at which the gas is

transferred into the chamber.

(65)

Effusion and Diffusion

• Rate of effusion is inversely proportional

to the square root of the molar mass

• M1 and M2 represent the molar masses of

the gases.

Grahams Law of effusion

Graham’s Law of Effusion

(66)

Real Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 66

• An ideal gas is theoretical

No gas displays perfectly ideal behavior

We must correct for non-ideal gas

behavior when:

Pressure of the gas is high.

Temperature is low.

Under these conditions:

Concentration of gas particles is high.

(67)

Real Gases

Fig 5.25 Plots of PV/nRT Versus

P for Several Gases (200 K)

Fig 5.26 Plots of PV/nRT Versus P for Nitrogen Gas at Three Temperatures

(68)

Real Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 68

For real gases:

Concentration of gas particles is high.Attractive forces become important.

We have to make two corrections to the ideal gas

law

The volume of the container is actually

smaller because some of the the volume is taken up by the gas particles themselves

The pressure is lower because the gas

(69)

Real Gases

Real Gases (van der Waals Equation)

[

P

obs

+

a

( / )

n V

2

]

V nb

 

nRT

corrected pressure

P

ideal

corrected volume

V

ideal

(70)

Characteristics of Several Real Gases

Return to TOC Copyright © Cengage Learning. All rights reserved 70

Values of the van der Waals Constants for Some Gases

The value of a reflects how

much of a correction must be made to adjust the observed pressure up to the expected ideal pressure.

A low value for a reflects

weak intermolecular forces among the gas molecules.

The value of b reflects the

(71)

Chemistry in the Atmosphere

• Two main sources:

 Transportation

 Production of electricity

Combustion of petroleum produces CO,

CO2, NO, and NO2, along with unburned

molecules from petroleum.

(72)

Chemistry in the Atmosphere

Return to TOC Copyright © Cengage Learning. All rights reserved 72

• At high temperatures, N2 and O2 react to

form NO, which oxidizes to NO2.

• The NO2 breaks up into nitric oxide and

free oxygen atoms.

• Oxygen atoms combine with O2 to form

ozone (O3).

Nitrogen Oxides (Due to Cars and Trucks)

NO2(g)

Radiant energy

NO(g)+O(g)

(73)

Chemistry in the Atmosphere

Concentration for Some Smog

(74)

Chemistry in the Atmosphere

Return to TOC Copyright © Cengage Learning. All rights reserved 74

• Sulfur produces SO2 when burned.

• SO2 oxidizes into SO3, which combines

with water droplets in the air to form sulfuric acid.

Sulfur Oxides (Due to Burning Coal for Electricity)

(75)

Chemistry in the Atmosphere

• Sulfuric acid is very corrosive and

produces acid rain.

• Use of a scrubber removes SO2 from the

exhaust gas when burning coal.

(76)

Chemistry in the Atmosphere

Return to TOC Copyright © Cengage Learning. All rights reserved 76

Figure

Fig 5.25 Plots of PV/nRT Versus

References

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