Table of Contents
Copyright © Cengage Learning. All rights reserved 2 5.1 Pressure
5.2 The Gas Laws of Boyle, Charles, and Avogadro 5.3 The Ideal Gas Law
5.4 Gas Stoichiometry
5.5 Dalton’s Law of Partial Pressures
5.6 The Kinetic Molecular Theory of Gases 5.7 Effusion and Diffusion
5.8 Real Gases
Why study gases?
Pressure
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• Uniformly fills any container.
• Mixes completely with any other gas.
• Exerts pressure on its surroundings.
Pressure
• SI units = 1 Pascal (Pa) = Newton/meter2
• 1 standard atmosphere (1 atm)
– 101,325 Pa
– 760 mm Hg
Pressure
force Pr essure =
Pressure
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The pressure of a gas is measured as 2.5 atm. Represent this pressure in both torr and pascals.
Pressure Conversions: An Example
2.5 atm
760 torr = 1.9 10 torr3 1 atm
2.5 atm
101,325 Pa = 2.5 10 Pa5 1 atm
Pressure
Barometer
• Device used to measure
atmospheric pressure.
• Mercury flows out of the
tube until the pressure of the column of
The Gas Laws of Boyle, Charles, and Avogadro
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Robert Boyle studies the relationship between the pressure on a gas and volume of a gas
Boyle’s Law
Using a J-shaped tube closed at one end, which he reportedly set up in the multistory entryway of his house, Boyle studied the relationship between the pressure of the trapped gas and its volume.
• Adding mercury to the open end of the tube
• Increases pressure on the trapped gas
• Decreases the volume of the trapped gas
The Gas Laws of Boyle, Charles, and Avogadro
Boyle’s Law
This is some of Boyles data
When we plot P vs V
We see that as
• Pressure goes down
The Gas Laws of Boyle, Charles, and Avogadro
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Boyle’s Law
If we plot the data as V vs 1/P
we get a straight line which intersects the Y axis at 0.
This is very helpful because can use the equation for a straight line to look at the relationship between V and P.
so if y = m x + b then V = k 1
The Gas Laws of Boyle, Charles, and Avogadro
Boyle’s Law
so since V = 1
P k + 0
then V = k P
or VP = k
The Gas Laws of Boyle, Charles, and Avogadro
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• PV = k
– Specific temperature and number of
moles (n)
• This means that the product of pressure
and volume is always the same value for a given sample of gas at a given
temperature
Boyle’s Law
1 1 = 2 2
The Gas Laws of Boyle, Charles, and Avogadro
Calculations Using Boyle’s Law
Freon-12, CCl2F2, is used in refrigeration systems. What is the new volume (L) of a 8.0-L sample of Freon gas initially at 550 mmHg after its pressure is changed to 2200 mmHg at constant T and n?
P1 = 550 mmHg P2 = 2200 mmHg V1 = 8.0 L V2 = ?
The Gas Laws of Boyle, Charles, and Avogadro
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Learning Check
A sample of helium gas occupies 12.4 L at
23°C and 0.956 atm. What volume will it
The Gas Laws of Boyle, Charles, and Avogadro
Ideal Gases vs Real Gases
• Gases that obey Boyles Law are called “ideal gases” (Section 5.3)
• PV = k
• Plot of PV vs P linear
• Ne and O2 show only small deviations
from ideal behavior at low pressures
• CO2 shows larger deviation from
ideal behavior
The Gas Laws of Boyle, Charles, and Avogadro
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The Gas Laws of Boyle, Charles, and Avogadro
• What happened to the gas in the
balloon?
• A decrease in temperature was followed
by a decrease in the volume of the balloon.
• There is a direct relationship between
volume and temperature
• This is an observation
The Gas Laws of Boyle, Charles, and Avogadro
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• Observation: The volume of a gas
depends on the temperature of the gas
– At constant pressure (P)
– At constant number of moles (n)
• What law summarizes observations
like these?
The Gas Laws of Boyle, Charles, and Avogadro
• Volume and Temperature (in Kelvin) are
directly related
– (constant P and n).
• V=bT (b is a proportionality constant)
Charles’s Law
1 2
1 2
=
V V
T T
V
The Gas Laws of Boyle, Charles, and Avogadro
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Learning Check
Suppose a balloon containing 1.30 L of air at 24.7°C is placed into a beaker containing liquid nitrogen at –78.5°C. What will the
The Gas Laws of Boyle, Charles, and Avogadro
• The volumes different gases with different numbers of moles all
extrapolate to the same value
• - 273°C or 0K
• 0 K is called absolute zero.
• At this point atoms or molecules have no volume and no molecular
motion (where entropy reaches its minimum value)
The Gas Laws of Boyle, Charles, and Avogadro
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• In some problems 2 variables change and
you want to determine the value of the third variable
• ie pressure and volume change and you
want to determine the new temperature
• To solve these problems we can combine
Boyles and Charles Law
The Combined Gas Law
P
1V
1The Ideal Gas Law
Exercise
At what temperature (in °C) does 121 mL of CO2 at 27°C and 1.05 atm occupy a volume of 293 mL at a pressure of 1.40 atm? P1 = 1.05 atm P2 = 1.40 atm
V1 = 121 mL V2 = 293 mL T1 = 27°C T2 = ?
P1V1
T1 = P2 V2 T2
T2= P2V2T1
P1V1 so T2 = 1.40 atm
293 m L 27+273 1.05 atm
The Ideal Gas Law
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Learning Check
A sample of helium gas has a volume of 0.180 L, a pressure of 0.800 atm, and a temperature of 29 °C. At what temperature (°C) will the helium have a volume of 90.0 mL and a pressure of 3.20 atm (n is constant)?
The Gas Laws of Boyle, Charles, and Avogadro
• Chapter 2 Avogadro postulated that equal
volumes of gases at the same temperature and pressure contain the same number of “particles.
• Avogadro’s law,
• Volume and number of moles are directly related
(constant T and P).
• V = an (a is a proportionality constant)
Avogadro’s Law
n n
The Gas Laws of Boyle, Charles, and Avogadro
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Learning Check
If 2.45 mol of argon gas occupies a volume
of 89.0 L, what volume will 2.10 mol of
The Ideal Gas Law
• We can bring all of these laws together into one
comprehensive law:
• Basically adding Avogadro’s Law to the
combined gas law
PV = nRT
V = k
The Ideal Gas Law
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PV = nRT
When using the ideal gas law Volume has to be in L
Temperature has to be in K Pressure has to be in atm
This is because of the units of R
The Ideal Gas Law
Learning Check
An automobile tire at 23°C with an internal volume of 25.0 L is filled with air to a total pressure of 3.18 atm. Determine the
The Ideal Gas Law
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Learning Check
What is the pressure in a 304 L tank that
contains 5.670 kg of helium at 25°C?
The Ideal Gas Law
• Which equation do I use?
• Write down initial and final conditions and look for
what is missing?
• Units and Gas Law Problems
• Don’t have to change units of pressure or volume
– Units just have to be the same
Gas Stoichiometry
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• For 1 mole of an ideal gas at 0°C and 1
atm, the volume of the gas is 22.42 L.
• STP = standard temperature and pressure
0°C and 1 atm
Therefore, the molar volume is 22.42 L
at STP.
Molar Volume of an Ideal Gas
1.000 mol 0.08206 L atm/K mol 273.2 K
V = = = 22.42 L
1.000 atm
Gas Stoichiometry
Gas Stoichiometry
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Concept Check
A sample of oxygen gas has a volume of
2.50 L at STP. How many grams of O2 are
present?
Gas Stoichiometry
•We can determine the molar mass of a gas from a measurement of the density
Molar Mass of a Gas
PV = nRT where n = g
molar mass
so PV= gRT
molar mass and P=
g RT molar mass
V
and since g
V density
Gas Stoichiometry
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d = density of gas
T = temperature in Kelvin
P = pressure of gas
R = universal gas constant
Molar Mass of a Gas
g L atm
K
g L mol K
= =
atm mol
Molar mass =
Gas Stoichiometry
Concept Check
The density of a gas was measured at 1.50 atm and 27°C and found to be 1.95 g/L.
Gas Stoichiometry
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Concept Check
Dalton’s Law of Partial Pressures
• For a mixture of gases in a container,
P
Total= P
1+ P
2+ P
3+ . . .
• The total pressure exerted is the sum of
Dalton’s Law of Partial Pressures
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Concept Check
Consider the following apparatus containing helium in both sides at 45°C. Initially the valve is closed.
–After the valve is opened, what is the pressure of
the helium gas?
–There is more than one way to solve this.
3.00 atm
3.00 L 2.00 atm
Dalton’s Law of Partial Pressures
Concept Check
27.4 L of oxygen gas at 25.0°C and 1.30 atm, and 8.50 L of helium gas at 25.0°C
and 2.00 atm were pumped into a tank with a volume of 5.81 L at 25°C.
• Calculate the new partial pressure of oxygen. • Calculate the new partial pressure of helium.
The Kinetic Molecular Theory of Gases
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• So far we have considered “what
happens,” but not “why.”
• Observations – direct relationship
between volume and temperature
• Laws – Charles Law
– This is the What
• Now we need a Theory
– This is the Why
• In science, “what” always comes before
The Kinetic Molecular Theory of Gases
1) The particles are so small compared with the distances between them that the volume of the individual particles can be assumed to be negligible (zero).
2) The particles are in constant motion. The collisions of the particles with the walls of the container are the cause of the pressure exerted by the gas.
3) The particles are assumed to exert no forces on each other; they are assumed neither to attract nor to repel each other.
4) The average kinetic energy of a collection of gas particles is assumed to be directly proportional to the Kelvin
The Kinetic Molecular Theory of Gases
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Concept Check
You are holding two balloons of the same volume. One contains
helium, and one contains
hydrogen. Complete each of the following statements
with “different” or “the same”
and be prepared to justify your answer.
He
The Kinetic Molecular Theory of Gases
Concept Check
•Complete the following
statement with “different” or “the same” and be prepared to justify your answer.
•The pressures of the gas in the two balloons are
• __________.
He
The Kinetic Molecular Theory of Gases
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Concept Check
•Complete the following
statement with “different” or “the same” and be prepared to justify your answer.
•The temperatures of the gas in the two balloons are __________.
He
The Kinetic Molecular Theory of Gases
Concept Check
•Complete the following
statement with “different” or
“the same” and be prepared to justify your answer.
•The numbers of moles of the gas in the two balloons are
__________.
He
The Kinetic Molecular Theory of Gases
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Concept Check
•Complete the following
statement with “different” or “the same” and be prepared to justify your answer.
•The densities of the gas in the two balloons are
__________.
He
The Kinetic Molecular Theory of Gases
Pressure and Volume - Molecular View of Boyle’s Law
P = (nRT) 1
V
ConstantFor a given sample of gas at a given temperature (n and T are constant) that if the volume of a gas is decreased, the pressure increases.
The Kinetic Molecular Theory of Gases
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Pressure and Temperature – Molecular View
P = ( nR
V
) T
ConstantFrom the ideal gas law P directly proportional to T.
The KMT accounts for this behavior because when the temperature of a gas increases, the speeds of its particles
increase, the particles hitting the wall with greater force and greater frequency. Since the volume remains the same, this would result in increased gas pressure,
The Kinetic Molecular Theory of Gases
Volume and Temperature - Molecular View of Charles’s Law
V
= ( nR
P
) T
ConstantThe ideal gas law states that for a sample of gas at a constant P, the volume of the gas is directly proportional to the Kelvin temperature
The Kinetic Molecular Theory of Gases
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Volume and Number of Moles = Molecular View of Avagadro’s Law
V
= ( RT
P
) n
ConstantThe ideal gas law predicts that the volume of a gas at a constant T and P depends directly on the n. This makes sense in terms of the KMT because an increase in the n at the same temperature would cause the pressure to increase if the volume were held constant. The only way to return the pressure to its original value is to increase the volume.
The Kinetic Molecular Theory of Gases
Volume and Number of Moles = Molecular View of Avogadro’s Law
V
= ( RT
P
) n
ConstantRemember that the volume of a gas (at constant P and T) depends only on the number of gas particles present. The individual volumes of the particles are not a factor because the particle volumes are so small compared with the distances between the particles (for a gas behaving ideally).
The Kinetic Molecular Theory of Gases
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Mixture of Gases – Molecular View of Daltons Law
The observation that the total pressure exerted by a mixture of gases is the sum of the pressures of the individual gases is expected because the KMT assumes that all gas particles are
The Kinetic Molecular Theory of Gases
Deriving The Ideal Gas Law
Can the ideal gas law be derived from the assumptions the KMT Yes!
And if you can do it
You will get extra credit on the next exam!
Your derivation must include
The Kinetic Molecular Theory of Gases
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Deriving The Ideal Gas Law
P = 2 3
nNA 1 2mu2 V
P = pressure, n = moles, NA = Avogadro’s number, m is mass, u2 is the average of the square of the velocities of the particles, V = volume
KE
avg = NA 1 2mu 2
mu2 = the average kinetic energy of a gas particle. mu2 x NA, = average kinetic energy for a mole of gas particles
P = 2 3
n KE avg V
becomes PVn = 23 KE avg
The fourth postulate of the KMT is that the average kinetic energy of the particles in the gas sample is directly proportional to the Kelvin
temperature.
PV
n = 23 KE avg so PVn T
The Kinetic Molecular Theory of Gases
Deriving The Ideal Gas Law
PV
n T From KMT
PV
n RT
From Experiment
The Kinetic Molecular Theory of Gases
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Concept Check
You have a sample of nitrogen
gas (N2) in a container fitted with
a moveable piston that maintains a pressure of 6.00 atm. Initially, the gas is at 45°C in a volume of 6.00 L.
•You then cool the gas
The Kinetic Molecular Theory of Gases
Concept Check
Which best explains the final result that
occurs once the gas sample has cooled?
The Kinetic Molecular Theory of Gases
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Concept Check
The gas sample is then cooled to a
temperature of 15°C. Solve for the new
condition. (Hint: A moveable piston keeps the
The Kinetic Molecular Theory of Gases
•KMT tells us that the Kelvin temperature indicates the average kinetic energy of the gas particles.
•The exact relationship between temperature and average kinetic energy can be obtained by combining equations (1) and (2).
•Equation (3) summarizes the meaning of the Kelvin temperature of a gas.
The Meaning of Temperature
PV
n RT (1)
PV
n = 23 KE avg (2) KEavg
3
The Kinetic Molecular Theory of Gases
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R = 8.3145 J/K·mol
(J = joule = kg·m2/s2)
T = temperature of gas (in K)
M = mass of a mole of gas in kg
• Final units are in m/s.
Root Mean Square Velocity
urms = 3RT
The Kinetic Molecular Theory of Gases
Concept Check
Calculate the root mean square velocity for the atoms in a sample of helium gas at
Effusion and Diffusion
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• Diffusion – the mixing of
gases.
• Effusion – describes the
passage of a gas through a tiny orifice into an evacuated chamber.
• Rate of effusion measures the
speed at which the gas is
transferred into the chamber.
Effusion and Diffusion
• Rate of effusion is inversely proportional
to the square root of the molar mass
• M1 and M2 represent the molar masses of
the gases.
• Grahams Law of effusion
Graham’s Law of Effusion
Real Gases
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• An ideal gas is theoretical
• No gas displays perfectly ideal behavior
• We must correct for non-ideal gas
behavior when:
– Pressure of the gas is high.
– Temperature is low.
• Under these conditions:
– Concentration of gas particles is high.
Real Gases
Fig 5.25 Plots of PV/nRT Versus
P for Several Gases (200 K)
Fig 5.26 Plots of PV/nRT Versus P for Nitrogen Gas at Three Temperatures
Real Gases
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• For real gases:
– Concentration of gas particles is high. – Attractive forces become important.
• We have to make two corrections to the ideal gas
law
– The volume of the container is actually
smaller because some of the the volume is taken up by the gas particles themselves
– The pressure is lower because the gas
Real Gases
Real Gases (van der Waals Equation)
[
P
obs
+
a
( / )
n V
2
]
V nb
nRT
corrected pressure
P
ideal
corrected volume
V
ideal
Characteristics of Several Real Gases
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Values of the van der Waals Constants for Some Gases
• The value of a reflects how
much of a correction must be made to adjust the observed pressure up to the expected ideal pressure.
• A low value for a reflects
weak intermolecular forces among the gas molecules.
• The value of b reflects the
Chemistry in the Atmosphere
• Two main sources:
Transportation
Production of electricity
• Combustion of petroleum produces CO,
CO2, NO, and NO2, along with unburned
molecules from petroleum.
Chemistry in the Atmosphere
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• At high temperatures, N2 and O2 react to
form NO, which oxidizes to NO2.
• The NO2 breaks up into nitric oxide and
free oxygen atoms.
• Oxygen atoms combine with O2 to form
ozone (O3).
Nitrogen Oxides (Due to Cars and Trucks)
NO2(g)
Radiant energy
NO(g)+O(g)
Chemistry in the Atmosphere
Concentration for Some Smog
Chemistry in the Atmosphere
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• Sulfur produces SO2 when burned.
• SO2 oxidizes into SO3, which combines
with water droplets in the air to form sulfuric acid.
Sulfur Oxides (Due to Burning Coal for Electricity)
Chemistry in the Atmosphere
• Sulfuric acid is very corrosive and
produces acid rain.
• Use of a scrubber removes SO2 from the
exhaust gas when burning coal.
Chemistry in the Atmosphere
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