International Journal of Mathematical Archive- 6(10), Oct. – 2015 254
SUFFICIENT CONDITIONS FOR THE EXISTENCE OF FIXED POINTS
OF WEAK GENERALIZED GERAGHTY CONTRACTIONS IN COMPLETE METRIC SPACES
K. P. R. SASTRY*
1, K. K. M. SARMA
2, CH.SRINIVASA RAO
3, VEDULA PERRAJU*
1D.No.45-42-25/A, Opp. Indian Overseas Bank,
Akkayyapalem, Visakhapatnam, Pin: 530016, Andhra Pradesh, India.
India (Received On: 09-10-15; Revised & Accepted On: 30-10-15)
ABSTRACT
W
e introduce the notion of(
α
,
ϕ
,
β
)
-weak generalized Geraghty contractions via triangularα
-admissible mappings to prove some sufficient conditions for the existence of fixed points of such maps in complete metric space, whereϕ
is an altering distance function andβ
∈
S
whereS
=
{
β
:
(0,
∞
)
→
[0,1)
satisfyingβ
(
t
n)
→
1
⇒
t
n→
0}
. Examples are provided to illustrate our results.Key words: Fixed points, Weak contraction, Altering distance function, Geraghty type contraction. triangular
α
- admissible, complete metric space,(
α
,
ϕ
,
β
)
- weak generalized Geraghty contraction.Mathematics Subject Classification (2010): 54H25,47H10.
1. INTRODUCTION AND PRELIMINARIES
Most of the fixed point theorems in nonlinear analysis usually start with Banach [9] contraction principle. A huge amount of literature is witnessed on applications, generalizations and extensions of this principle carried out by several authors in different directions like weakening the hypothesis and considering different mappings. Fixed point theory is an essential tool in the study of various varieties of problems in control theory, economic theory, nonlinear analysis and global analysis.
But all the generalizations may not be from this principle. In 1989, Bakktin [8] introduced the concept of a b-metric space as a generalization of a metric space. In 1993, Czerwik[11] extended many results related to the b - metric space. In 1994, Matthews [20] introduced the concept of partial metric space in which the self distance of any point of space may not be zero. In 1996, O’Neill [28] generalized the concept of partial metric space by admitting negative distances. In 2013, Shukla [34] generalized both the concepts of b-metric and partial metric space by introducing the notation of partial b-metric spaces. Many authors recently studied the existence of fixed points of self maps in different types of metric spaces [16,35,23,32,37]. Some authors [4,20,24,30,31] obtained some fixed point theorems in b-metric spaces. Some authors proved
α
−
ψ
versions of certain fixed point theorems in different types of metric spaces [3,16]. Recently Samet et.al [29] and Jalal Hassanzadeasl [14] obtained fixed point theorems forα
−
ψ
contractive mappings. Mustafa [24] gave a generalization of Banach contraction principle in complete ordered partial b-metric space by introducing the notion of a generalizedα
−
ψ
weakly contractive mapping. G.V.R. Babu et.al [5] proved coupled fixed point theorems by using(
α
,
ϕ
,
β
)
-weak generalized Geraghty contraction. In 2012, Mohammad Mursaleen et.al [22] proved coupled fixed point theorems forα
-ψ
contractive type mappings in partially ordered metric spaces.In this paper we modify the concepts of G. V. R. Babu et.al [6] to study sufficient conditions for the existence of fixed points of weak generalized Geraghty contractions in a complete metric space. In fact, we obtain sufficient conditions for the existence of fixed points of weak generalized Geraghty contractions in a complete metric space. A supporting example is also given. Further an open problem is also given at the end of this paper.
Corresponding Author: Vedula Perraju*
1D.No.45-42-25/A, Opp. Indian Overseas Bank,
Notation: G. V. R. Babu. et.al [6] used the following notation in their paper.
(
X
,
d
)
denotes a metric space. LetX
X
T
:
→
be a self map ofX
and Fix(
T
)
denotes the set of all fixed points ofT
. We denote= { : (0, )
[0,1) /
( )
n1
n0},
S
β
∞ →
β
t
→ ⇒ →
t
andΦ
=
{
ϕ
:
[0,
∞
)
→
[0,
∞
)/
ϕ
is non-decreasing, continuous andϕ
(
t
)
=
0
⇔
t
=
0}
. We call the elements ofΦ
as altering distance functions. Further, we use the following notation: for sub sequences{
}
n h
x
and{
}
n k
x
in X withn k n
h
x
x
≠
, we write( (
), (
))
= (
,
), =
hn knn hn kn n
n
d T x
T x
d
d x
x
d
∆
and( ( (
), (
))
=
,
(
)
hn kn
n
n
d T x
T x
n
d
φ
φ
φ
∆
∀
.We denote the set of all real numbers by
R
, the set of all non-negative reals byR
+and the set of all natural numbers byN
.Definition 1.1: (B.Samet.et.al.[29]) Let
T
:
X
→
X
be a self map andα
:
X
×
X
→
R
be a function. Then T is said to beα
- admissible ifα
(
x
,
y
)
≥
1
⇒
α
(
Tx
,
Ty
)
≥
1
.Definition 1.2: (E. Karapinar. et.al. [18]) An
α
-admissible mapT
is said to be triangularα
- admissible if1
)
,
(
x
z
≥
α
andα
(
z
,
y
)
≥
1
⇒
α
(
x
,
y
)
≥
1
.For more details and examples on
α
-admissible and triangularα
-admissible maps, one can refer [17], [18] and [29].Lemma 1.3: (E. Karapinar. et.al. [18])
Let
T
:
X
→
X
be triangularα
-admissible map. Assume that there existsx
1∈
X
such thatα
(
x
1,
Tx
1)
≥
1
. Define the sequencex
n+1 byx
n+1=
Tx
n,n
=
1,2,...
. Then we haveα
(
x
n,
x
m)
≥
1
for allm
,
n
∈
N
withn
<
m
.Definition 1.4: (S. H. Cho. et.al.[13]) Let
(
X
,
d
)
be a metric space, and letα
:
X
×
X
→
R
be a function. A mapX
X
T
:
→
is called anα
- Geraghty type contraction if there existsβ
∈
S
such that( , ) (
x y d Tx Ty
,
) ( ( , )) ( , )
d x y
d x y
α
≤
β
for allx
,
y
∈
X
. (1.4.1)Definition 1.5: (G. V. R. Babu. et.al.[6]) Let
(
X
,
d
)
be a metric space andT
:
X
→
X
be a self map. If there existΦ
∈
→
×
,
:
ϕ
α
X
X
R
andL
≥
0
such that( , ) (( (
x y
d Tx Ty
,
))) < ((
M x y
( , ))) . ( , )
L N x y
α
φ
φ
+
(1.5.1) for allx
,
y
∈
X
,
x
≠
y
where
1
( , ) = { ( , ), ( ,
), ( ,
), [ ( ,
)
( ,
)]},
2
M x y
max d x y d x Tx d y Ty
d x Ty
+
d y Tx
( , ) = { ( ,
), ( ,
), ( ,
)}
N x y
min d x Tx d x Ty d y Tx
thenT
is said to be an almost generalizedα
- contractive map w.r.to the altering distance functionϕ
.Definition 1.6: (G. V. R. Babu. et.al.[6]) Let
(
X
,
d
)
be a metric space letT
:
X
→
X
be a self map. If there exist:
X
X
R
,
S
,
α
×
→
β
∈
φ
∈Φ
andL
≥
0
such that( , ) (( (
x y
d Tx Ty
,
)))
( (
M x y
( , ))) (
M x y
( , ))
L N x y
. ( , )
α
φ
≤
β φ
φ
+
(1.6.1) for allx
,
y
∈
X
,where
1
( , ) =
{ ( , ), ( ,
), ( ,
), [ ( ,
)
( ,
)]},
2
M x y
max d x y d x Tx d y Ty
d x Ty
+
d y Tx
( , ) =
{ ( ,
), ( ,
), ( ,
)}
© 2015, IJMA. All Rights Reserved 256
Theorem 1.7: (G. V. R. Babu. et.al.[6]) Let
T
be a self map on a complete metric spaceX
. Letα
:
X
×
X
→
R
be a function. Assume that there existϕ
∈
Φ
, andL
≥
0
such that)
,
(
.
))
,
(
(
<
))
,
(
(
)
,
(
x
y
ϕ
d
Tx
Ty
ϕ
M
x
y
+
L
N
x
y
α
(1.7.1) for all
x
,
y
∈
X
,
x
≠
y
where
1
( , ) =
{ ( , ), ( ,
), ( ,
), [ ( ,
)
( ,
)]},
2
M x y
max d x y d x Tx d y Ty
d x Ty
+
d y Tx
( , ) =
{ ( ,
), ( ,
), ( ,
)}.
N x y
min d x Tx d x Ty d y Tx
Further, assume that
(i)
T
isα
- admissible, and(ii) there exists
x
0∈
X
such thatα
(
x
0,
Tx
0)
≥
1
and setx
n=
Tx
n−1 forn
=
1,2,3,...
. Then the sequence}
{
x
n converges toz
andz
is a unique fixed point ofT
inX
if and only if for any two sub-sequences}
{
n h
x
and{
}
n k
x
of{
x
n}
withn k n
h
x
x
≠
, we have that∆
ϕn→
1
⇒
d
n→
0
, provided thatT
iscontinuous at
z
.Theorem 1.8: (G. V. R. Babu. et.al.[6]) Let
(
X
,
d
)
be a complete metric space,α
:
X
×
X
→
R
be a function and letT
:
X
→
X
be a self map. Suppose the following conditions hold:(i)
T
is(
α
,
ϕ
,
β
)
- weak generalized Geraghty contraction;(ii)
T
is triangularα
- admissible,(iii)there exists
x
0∈
X
such thatα
( ,
x Tx
0 0) 1
≥
and setx
n=
Tx
n−1 forn
=
1,2,3,...
(iv)either (a)
T
is continuous (or) (b) if{
x
n}
is a sequence inX
such thatα
(
x
n,
x
n+1)
≥
1
for all n andx
x
n→
asn
→
∞
, then there exists a sub-sequence{
}
k n
x
of{
x
n}
such that(
x
,
x
)
≥
1
k n
α
for allk
. ThenT
has a fixed pointx
inX
, provided thatβ
is continuous on(0,
∞
)
2. MAIN RESULT
In this section we obtain sufficient conditions for the existence of fixed points of weak generalized Geraghty contractions in a complete space. We begin this section with the following lemma, which can be easily established.
Lemma 2.1: Let
(
X
,
d
)
be a metric space. Let{
x
n}
be a sequence in X such thatd
(
x
n+1,
x
n)
→
0
asn
→
∞
. If}
{
x
n is not a Cauchy sequence then there exist anε
>
0
and sequences of positive integers{
m
k}
and{
n
k}
withk
n
m
k>
k>
and(i)
lim
(
−1,
+1)
=
ε
∞
→ mk nk
k
x
x
d
(ii)
lim
(
,
)
=
ε
k n k m k
x
x
d
∞ →
(iii)
lim
(
1,
)
=
ε
k n k m k
x
x
d
−∞ →
(iv)
lim
(
,
)
=
ε
1+ ∞
→ mk nk
k
x
x
d
Notation: We adopt the following notation throughout this paper.
(
X
,
d
)
denotes a metric space. LetT
:
X
→
X
be a self map ofX
and Fix(
T
)
denotes the set of all fixed points ofT
.
We denote= { : (0, )
[0,1) /
( )
n1
n0},
S
β
∞ →
β
t
→ ⇒ →
t
andΦ
=
{
ϕ
:
[0,
∞
)
→
[0,
∞
)/
ϕ
is non-decreasing, continuous andϕ
(
t
)
=
0
⇔
t
=
0}
. We call the elements ofΦ
as altering distance functions. Further, we use the following notation: for any sequences{
a
n}
and{
b
n}
in X witha
n≠
b
n,
we writen n n n
n n n
d
b
T
a
T
d
b
a
d
d
=
(
,
),
∆
=
(
(
),
(
))
and=
( ( (
), ( ))
,
(
)
n n
n
n
d T a
T b
n
d
φ
φ
φ
∆
∀
We denote the set of all realTheorem 2.2: Let
T
be a self map on a complete metric spaceX
. Letα
:
X
×
X
→
R
be a continuous function andα
(
x
,
x
)
>
1
∀
x
∈
X
. Assume that there existϕ
∈
Φ
, andL
≥
0
such that)
,
(
.
))
,
(
(
<
))
,
(
(
)
,
(
x
y
ϕ
d
Tx
Ty
ϕ
M
x
y
+
L
N
x
y
α
(2.2.1) for all
x
,
y
∈
X
,
x
≠
y
where)]},
,
(
)
,
(
[
2
1
),
,
(
),
,
(
),
,
(
{
=
)
,
(
x
y
max
d
x
y
d
x
Tx
d
y
Ty
d
x
Ty
d
y
Tx
M
+
and
)}
,
(
),
,
(
),
,
(
{
=
)
,
(
x
y
min
d
x
Tx
d
x
Ty
d
y
Tx
N
(2.2.2)Further, assume that
(i)
T
isα
- admissible, and(ii) there exists
x
0∈
X
such thatα
(
x
0,
Tx
0)
≥
1
. Setx
n=
Tx
n−1 forn
=
1,2,3,...
. (iii)forany two sequences{
a
n}
and{
b
n}
ofX
witha
n≠
b
n, we have that∆
ϕn→
1
0
→
⇒
d
n (2.2.3)Then the sequence
{
x
n}
converges to a pointz
∈
X
andz
is a fixed point ofT
inX
. Further ify
,
z
are fixed point ofT
inX
, thenα
(
y
,
z
)
<
1
ory
=
z
Proof: Let
x
0∈
X
be such thatα
(
x
0,
Tx
0)
≥
1
. We define{
x
n}
inX
byx
n+1=
Tx
n for eachn
=
0,1,2,3,..
.
Ifx
n=
x
n+1 for somen
∈
N
, thenx
n=
Tx
n and hencex
n is a fixed point ofT
. Hence, without loss of generality, we assume thatx
n≠
x
n+1 for alln
∈
N
. By using theα
- admissibility ofT
, we have1
)
,
(
=
)
,
(
x
0x
1α
x
0Tx
0≥
α
⇒
α
(
x
1,
x
2)
=
α
(
Tx
0,
Tx
1)
=
≥
1
. Now, by mathematical induction, it is easy to see thatα
(
x
n,
x
n+1)
≥
1
for alln
∈
N
. By takingx
=
x
n−1 andy
=
x
n in the inequality (2.2.1), we get)
,
(
))
,
(
(
))
,
(
(
)
,
(
))
,
(
(
=
))
,
(
(
d
x
nx
n+1ϕ
d
Tx
n−1Tx
n≤
α
x
n−1x
nϕ
d
Tx
n−1Tx
n≤
ϕ
M
x
n−1x
n+
LN
x
n−1x
nϕ
(2.2.4)where
)]}
,
(
)
(
[
2
1
),
,
(
),
,
(
),
,
(
{
=
)
,
(
−1 −1 −1 −1 −1,+
n n−1n Tx n n
n n
n n n n
n
x
max
d
x
x
d
x
Tx
d
x
Tx
d
x
d
x
Tx
x
M
)]}
,
(
)
,
(
[
2
1
),
,
(
),
,
(
),
,
(
{
=
max
d
x
n−1x
nd
x
n−1x
nd
x
nx
n+1d
x
n−1x
n+1+
d
x
nx
n
=
max
{
d
(
x
n−1,
x
n),
d
(
x
n,
x
n+1)}
(2.2.5)
)}
,
(
),
,
(
),
,
(
{
=
)
,
(
x
n 1x
nmin
d
x
n 1x
nd
x
n 1Tx
nd
Tx
n 1x
nN
− − − −
=
min
{
d
(
x
n−1,
x
n),
d
(
x
n−1,
Tx
n),
d
(
x
n,
x
n)}
=
0
(2.2.6)If
max
{
d
(
x
n−1,
x
n),
d
(
x
n,
x
n+1)}
=
d
(
x
n,
x
n+1)
for somen
∈
N
then from (2.2.4),(2.2.5) and (2.2.6), we have))
,
(
(
=
))
,
(
(
<
))
,
(
(
d
x
nx
n+1ϕ
M
x
n−1x
nϕ
d
x
nx
n+1ϕ
, a contradiction.Thus, we have
max
{
d
(
x
n−1,
x
n),
d
(
x
n,
x
n+1)}
=
d
(
x
n−1,
x
n)
for alln
∈
N
and hence)
,
(
<
)
,
(
x
nx
n 1d
x
n 1x
nd
+ − for alln
∈
N
. (2.2.7)Thus it follows that
{
d
(
x
n,
x
n+1)}
is a non-negative, decreasing sequence of real numbers. Suppose thatlim
(
,
+1)
=
,
≥
0
∞
→
d
x
nx
nr
r
n
Now we prove that
r
=
0.
© 2015, IJMA. All Rights Reserved 258
By choosing
a
n=
x
n,
b
n=
x
n+1,n
d
x
T
x
T
d
n n n n)
(
))
(
),
(
(
(
=
1∀
∆
+ϕ
ϕ
ϕ,
On taking limit as
n
→
∞
,then we have
lim
∞ → n 1 2 1 2 1 1(
lim
(
,
))
( (
,
))
( )
=
lim
=
=
= 1
( (
,
))
(
lim
(
,
))
( )
n n
n n n
n n
n n n n
n
d x
x
d x
x
r
d x x
d x x
r
φ
φ
φ
φ
φ
φ
φ
+ +
+ + →∞
→∞ + +
→∞
∆
.Hence by our assumption
ϕ
(
d
n)
→
0
asn
→
∞
i.e.,lim
∞ → n0
=
))
,
(
(
d
x
nx
n+1ϕ
0
=
)
(
r
ϕ
⇒
0
=
r
⇒
, contradicts our assumption thatr
>
0
0
=
)
,
(
lim
=
+1∞ →
∴
n nn
x
x
d
r
Now, we show that
{
x
n}
is a Cauchy sequence inX
.Suppose that
{
x
n}
is not a Cauchy sequence.Then there exist
ε
>
0
, and sub-sequences{
}
k m
x
and{
}
k n
x
of{
x
n}
withm
k>
n
k>
k
such thatε
≥
)
,
(
k n k mx
x
d
and(
1,
)
<
ε
k n k
m
x
x
d
− and we have the following identities.(1)
lim
(
+1,
+1)
=
ε
∞
→ mk nk
k
x
x
d
(2)
lim
(
,
)
=
ε
k n k m k
x
x
d
∞ → Hence))
,
(
(
))
,
(
(
lim
k n k m k n k mk
d
x
x
Tx
Tx
d
ϕ
ϕ
∞ → = 1 1( (
,
))
lim
( (
,
))
mk nk
k
mk nk
d x
x
d x
x
φ
φ
+ +
→∞ =
(
)
=
1.
)
(
ε
ϕ
ε
ϕ
Now, by our assumption
ϕ
(
d
n)
→
0
asn
→
∞
i.e.,
lim
n→∞0
=
))
,
(
(
k n k mx
x
d
ϕ
⇒
lim
∞ → n0
=
)
,
(
k n k mx
x
d
, a contradiction to (2).Therefore
{
x
n}
is a Cauchy sequence inX
.Since
X
is complete, there existsz
∈
X
such thatx
nz
n
=
lim
∞
→ .
Now, we show that z is a fixed point of T .
Then the following are the cases.
Case- (1): Suppose there is a sequence
n
x
z
k n
k
}
=
{
∋
, we supposex
z
k n −1
≠
z
x
k
n −1
→
,α
(
z
,
z
)
>
1
andα
is continuous,1
>
)
,
(
1z
x
k n −Now,
))
,
(
(
d
z
Tz
ϕ
=
(
d
(
x
,
Tz
))
k n
ϕ
=
ϕ
(
d
(
Tx
nk−1,
Tz
))
≤
α
(
x
nk−1,
z
)
ϕ
(
d
(
Tx
nk−1,
Tz
))
<
ϕ
(
M
(
x
nk−1,
z
))
+
L
.
N
(
x
n,
z
)
(2.2.8)But
1 1 1
(
n, ) =
{ (
n, ), (
n,
n),
k k k k
M x
z
ma
d x
x
z d x
x
− − − 1
1
( ,
), [ (
,
)
(
, )]}
2
nk nkd z Tz
d x
Tz
d x
z
−
+
1
=
{ (
n,
n),
k k
max d x
x
−
d x
(
nk,
x
nk+1)}
=
d
(
x
nk−1,
x
nk)
0
=
))
,
(
(
<
))
,
(
(
1 nk
k
n
x
x
d
Tz
z
d
−
∴
ϕ
ϕ
0
=
))
,
(
(
d
z
Tz
ϕ
∴
( ,
) = 0
d z Tz
⇒
Tz
z
=
∴
Case-(2): Suppose
x
n≠
z
andz
≠
Tz
))
,
(
(
=
))
,
(
(
d
x
n 1Tz
ϕ
d
Tx
nTz
ϕ
+∴
≤
α
(
x
n,
z
)
ϕ
(
d
(
Tx
n,
Tz
))
(sinceα
is continuous andα
(
z
,
z
)
>
1
)
<
ϕ
(
M
(
x
n,
z
))
+
L
.
N
(
x
n,
z
)
(2.2.9)But
)
,
(
=
)]}
,
(
)
,
(
[
2
1
),
,
(
),
,
(
),
,
(
{
=
)
,
(
1d
x
1z
d
x
Tz
d
z
Tz
s
Tz
z
d
x
x
d
z
x
d
max
z
x
M
n n n n+ n++
n for largen
1
( , ) =
n{ ( , ), ( ,
n n n), ( ,
)} = 0
N x z
min d x z d x x
+d z Tz
for largen
∴
ϕ
(
d
(
x
n+1,
Tz
))
≤
α
(
x
n,
z
)
ϕ
(
d
(
Tx
n,
Tz
))
<
ϕ
(
d
(
z
,
Tz
))
+
L
.0
On letting
n
→
∞
, we get))
,
(
(
))
,
(
(
)
,
(
))
,
(
(
d
z
Tz
α
z
z
ϕ
d
z
Tz
ϕ
d
z
Tz
ϕ
≤
≤
1
=
)
,
(
z
z
α
⇒
, a contradiction.Hence
z
=
Tz
.Consequently
z
is a fixed point ofT
inX
.Suppose
y
,
z
are two fixed points ofT
inX
z
Tz
y
Ty
=
,
=
⇒
(2.2.10)If
α
(
y
,
z
)
<
1
, then there is nothing to prove.© 2015, IJMA. All Rights Reserved 260
Then
))
,
(
(
d
Ty
Tz
ϕ
≤
α
(
y
,
z
)
ϕ
(
d
(
Ty
,
Tz
))
<
ϕ
(
M
(
y
,
z
))
+
L
.
N
(
y
,
z
)
(2.2.11)But
[
(
,
)
(
,
)]}
=
(
,
)
2
1
),
,
(
),
,
(
),
,
(
{
=
)
,
(
y
z
max
d
y
z
d
y
Ty
d
z
Tz
d
y
Tz
d
Ty
z
d
y
z
M
+
0
=
)}
,
(
),
,
(
),
,
(
{
=
)
,
(
y
z
min
d
y
z
d
y
Ty
d
z
Tz
N
∴
ϕ
(
d
(
Ty
,
Tz
))
≤
α
(
y
,
z
)
ϕ
(
d
(
Ty
,
Tz
))
<
ϕ
(
d
(
y
,
z
))
⇒
ϕ
(
d
(
y
,
z
))
≤
α
(
y
,
z
)
ϕ
(
d
(
y
,
z
))
<
ϕ
(
d
(
y
,
z
))
, a contradiction.Hence
y
=
z
.The following corollary can be easily established.
Corollary 2.3: Let
T
be a self map on a complete metric spaceX
. Letα
:
X
×
X
→
R
be a continuous function. Assume that there existϕ
∈
Φ
, such that)
,
(
.
))
,
(
(
<
))
,
(
(
)
,
(
x
y
ϕ
d
Tx
Ty
ϕ
M
x
y
+
L
N
x
y
α
(2.3.1) for all
x
,
y
∈
X
,
x
≠
y
where1
( , ) =
{ ( , ), ( ,
), ( ,
), [ ( ,
)
(
, )]},
2
( , ) =
{ ( ,
), ( ,
), ( ,
)}.
M x y
max d x y d x Tx d y Ty
d x Ty
d Tx y
N x y
min d x Tx d x Ty d y Tx
+
Further, assume that
(i)
T
isα
- admissible, and(ii) there exists
x
0∈
X
such thatα
(
x
0,
Tx
0)
≥
1
and setx
n=
Tx
n−1 forn
=
1,2,3,...
. (iii) for any two sequences{
a
n}
and{
b
n}
ofX
witha
n≠
b
n,We have that
∆
ϕn→
1
⇒
d
n→
0
(2.3.2)
Then the sequence
{
x
n}
is a Cauchy sequence. Suppose{
x
n}
converges toz
andα
(
z
,
z
)
>
1
.Then
z
is a fixed point ofT
inX
.Theorem 2.4: Let
(
X
,
d
)
be a complete metric space,α
:
X
×
X
→
R
be a continuous function and letX
X
T
:
→
be a self map. Suppose the following conditions hold: (i)T
is(
α
,
ϕ
,
β
)
- weak generalized Geraghty contraction i.e.,)
,
(
.
))
,
(
(
)))
,
(
(
(
))
,
(
(
)
,
(
x
y
ϕ
d
Tx
Ty
≤
β
ϕ
M
x
y
ϕ
M
x
y
+
L
N
x
y
α
(2.4.1) where
L
≥
0
for allx
,
y
∈
X
, where)}.
,
(
),
,
(
),
,
(
{
=
)
,
(
)]},
,
(
)
,
(
[
2
1
),
,
(
),
,
(
),
,
(
{
=
)
,
(
Tx
y
d
Ty
x
d
Tx
x
d
min
y
x
N
and
y
Tx
d
Ty
x
d
Ty
y
d
Tx
x
d
y
x
d
max
y
x
M
+
(ii)
T
is triangularα
- admissible,(iii)there exists
x
0∈
X
such thatα
( ,
x Tx
0 0) 1
≥
and setx
n=
Tx
n−1forn
=
1,2,3,...
.Then{
x
n}
is a Cauchysequence.
Proof: As in the theorem 2.2, Let
x
0∈
X
be such thatα
(
x
0,
Tx
0)
≥
1
. We define{
x
n}
inX
byx
n=
Tx
n−1 for eachn
=
1,2,3,...
Ifx
n=
x
n+1 for somen
∈
N
, thenx
n=
Tx
n and hencex
n is a fixed point ofT
. Hence, without loss of generality, we assume thatx
n≠
x
n+1 for alln
∈
N
. By using theα
- admissibility ofT
, we have1
)
,
(
=
)
,
(
x
0x
1α
x
0Tx
0≥
α
1
)
,
(
=
)
,
(
1 2 0 1≥
⇒
α
x
x
α
Tx
Tx
.Now, by mathematical induction, it is easy to see that
α
(
x
n,
x
n+1)
≥
1
for alln
∈
N
.By taking
x
=
x
n−1 andy
=
x
n in the inequality (2.4.1),We get
1 1
( ( ,
d x x
n n)) = ( (
d Tx
n,
Tx
n))
φ
+φ
−
≤
α
(
x
n−1,
x
n) ( (
φ
d Tx
n−1,
Tx
n))
≤
α
(
x
n−1,
x
n) ( (
φ
d Tx
n−1,
Tx
n))
(2.4.2) where)]}
,
(
)
(
[
2
1
),
,
(
),
,
(
),
,
(
{
=
)
,
(
x
n−1x
nmax
d
x
n−1x
nd
x
n−1Tx
n−1d
x
nTx
nd
x
n−1,Txn+
d
x
nTx
n−1M
)]}
,
(
)
,
(
[
2
1
),
,
(
),
,
(
),
,
(
{
=
max
d
x
n−1x
nd
x
n−1x
nd
x
nx
n+1d
x
n−1x
n+1+
d
x
nx
n
=
max
{
d
(
x
n−1,
x
n),
d
(
x
n,
x
n+1)}
(2.4.3)
)}
,
(
),
,
(
),
,
(
{
=
)
,
(
x
n 1x
nmin
d
x
n 1x
nd
x
n 1Tx
nd
Tx
n 1x
nN
− − − −
=
min
{
d
(
x
n−1,
x
n),
d
(
x
n−1,
Tx
n),
d
(
x
n,
x
n)}
=
0
(2.4.4)If
max
{
d
(
x
n−1,
x
n),
d
(
x
n,
x
n+1)}
=
d
(
x
n,
x
n+1)
for somen
∈
N
then from (2.4.2),(2.4.3) and (2.4.4), we have))
,
(
(
=
))
,
(
(
<
))
,
(
(
d
x
nx
n+1ϕ
M
x
n−1x
nϕ
d
x
nx
n+1ϕ
, a contradiction.Thus, we have
max
{
d
(
x
n−1,
x
n),
d
(
x
n,
x
n+1)}
=
d
(
x
n−1,
x
n)
for alln
∈
N
and hence)
,
(
<
)
,
(
x
nx
n 1d
x
n 1x
nd
+ − for alln
∈
N
. (2.4.5)Thus it follows that
{
d
(
x
n,
x
n+1)}
is a non-negative, decreasing sequence of real numbers. Suppose that0
,
=
)
,
(
lim
+1≥
∞
→
d
x
nx
nr
r
n
Now we prove that
r
=
0.
Assume that
r
>
0
.∴
α
( ,
x x
n n+1) ( (
φ
d Tx Tx
n,
n+1)) ( (
≤
β φ
M x x
( ,
n n+1))) (
φ
M x x
( ,
n n+1))
+
L N x x
. ( ,
n n+1)
⇒
ϕ
(
d
(
Tx
n,
Tx
n+1))
≤
β
(
ϕ
(
M
(
x
n,
x
n+1)))
ϕ
(
d
(
x
n,
x
n+1)
+
L
.
N
(
x
n,
x
n+1)
© 2015, IJMA. All Rights Reserved 262
On letting
n
→
∞
1 2 1 1
( (
,
))
( ( ( ,
))) ( ( ,
))
lim
n nliminf
n n n nn n
d x
x
d x x
d x x
φ
+ +β φ
+φ
+→∞
≤
→∞
limsup
( ( (
n,
n 1))) ( (
n,
n 1))
n
d x x
d x x
β φ
+φ
+→∞
≤
lim
( ( ,
n n 1))
n
d x x
φ
+ →∞≤
)
(
)
(
))
,
(
(
(
limsup
)
(
)))
,
(
(
(
liminf
)
(
r
d
x
x
1r
d
x
nx
n 1r
r
n n n n
ϕ
ϕ
ϕ
β
ϕ
ϕ
β
ϕ
≤
≤
≤
∴
+ ∞ → + ∞ →0
=
)
(
r
ϕ
⇒
orlim
(
(
(
,
+1)))
=
1
∞
→ n n
n
x
x
d
ϕ
β
1
=
)))
,
(
(
(
lim
+1∞ →
∴
n nn
x
x
d
ϕ
β
0
=
)
,
(
lim
+1∞ →
⇒
n nn
x
x
d
0
=
r
⇒
, a contradiction for our assumption ofr
>
0
.0
=
r
∴
Hence
lim
(
,
+1)
=
0
∞→ n n
n
x
x
d
Let us suppose
{
x
n}
is not a Cauchy sequence.Then there exist
ε
>
0
, and sub-sequences{
}
k m
x
and{
}
k n
x
of{
x
n}
withm
k>
n
k>
k
such thatε
≥
)
,
(
k n k mx
x
d
and(
1,
)
<
ε
k n k
m
x
x
d
− and we have the following identities.(i)
lim
(
+1,
+1)
=
ε
∞
→ mk nk
k
x
x
d
(ii)lim
(
,
)
=
ε
k n k m k
x
x
d
∞ →Also since
T
is triangularα
- admissible andα
(
x
n,
x
n+1)
≥
1
∀
n
∈
N
,1
)
,
(
≥
∴
k n k mx
x
α
Hence 1 1( (
m,
n)) = ( (
m,
n))
k k k k
d x
x
d Tx
Tx
φ
+ +φ
(
m,
n) ( (
m,
n))
k k k k
x
x
d Tx
Tx
α
φ
≤
( (
(
m,
n)) (
(
m,
n))
(
m,
n)
k k k k k k
M x
x
M x
x
LN x
x
β φ
φ
≤
+
(2.4.6) where1
(
m,
n) =
{ (
m,
n), (
m,
m),
k k k k k k
M x
x
ma
d x
x
x
d x
x
+ 1 1 11
(
,
), [ (
,
)
(
,
)]}
2
nk nk mk nk mk nk
d x
x
+d x
x
++
d x
+x
=
d
(
x
mk,
x
nk)
(2.4.7)
1 1
(
m,
n) =
{ (
m,
n), (
m,
m), (
n,
n)}
k k k k k k k k
N x
x
min d x
x
d x
x
+d x
x
+
=
0
for largek
(2.4.8)Therefore from (2.4.6),(2.4.7) and (2.4.8), we have
)
,
(
))
,
(
(
))
,
(
(
(
))
,
(
(
1 1k n k m k n k m k n k m k n k
m