Approximation of Common Fixed Points for Nonself-Asymptotically Nonexpansive Mappings
Esra YOLACAN Hukmi KIZILTUNC
AtaturkUniversity Faculty of Science
Department of Mathematics 25240 Erzurum, Turkey
Abstract.
Suppose that K is a nonempty closed convex subset of a real uniformly convex and smooth Banach space E with P as a sunny nonexpansive retraction. Let Ti:K E (i=1,2,3,4,5,6) be six of weakly inward and asymptotically nonexpansive mappings with respect to P with common sequence
k
n 1,
satisfying
n=1k
n1 <
and
i i
T F F
61
=
= , respectively. For any given
x
1 K ,
suppose that
xn is a sequence generated iteratively by
,
=
,
=
,
=
6 3 5
3 3
4 2 3
2 2
2 1 1
1 1
1
n n n
n n n
n n n
n n n
n n n
n n n
n n n
n n n n n n
x PT c x PT b x a z
z PT c z PT b x a y
y PT c y PT b x a x
where
a
ni, b
ni and c
ni i = 1,2,3
are sequences in ,1
for some 0,1
which satisfy condition1
ni
=
ni
ni
b c
a i = 1,2,3 .
Under some suitable conditions, strong convergence theorems of
xn to a common fixed point of T
i 6i=1 are obtained.Keywords and phrases: Nonself-Asymptotically Nonexpansive Mappings, common fixed point, strongconvergence.
2000 Mathematics Subject Classification: 47H09, 47H10, 46B20.
1. Introduction
Let K be a nonempty closed convex subset of a real uniformly convex Banach space E. A mapping
T : K K
is callednonexpansi ve
ifTx Ty x y
for all x, yK . A mappingT : K K
is calledally
asymptotic
nonexpansi ve
if there exists a sequence k
n 1,
withk
n 1
such that yx k y T x
Tn n n (1.1)
for all x, yK and
n 1
.A mapping
T : K K
is called uniformly LLipschitzian if there exists constantL 0
such that yx L y T x
Tn n (1.2)
for all x, yK and
n 1
.A subset K of E is said to be a retract of E if there exists a continuous map
P : E K
such thatPx = x
, for allx K
. Every closed convex subset of a uniformly convex Banach space is a retract. A mappingK E
P :
is said to be a retraction ifP =
2P
. It follows that if a map P is a retraction, then Py = y for all )(P R
y , the range of P.
It is well-known that every closed convex subset of a uniformly convex Banach space is a retract. The concept of asymptotically nonexpansive nonself-mappings was firstly introduced by Chidume et al. [2] as the generalization of asymptotically nonexpansive self-mappings. The asymptotically nonexpansive nonself-mapping is defined as follows:
Let K be a nonempty subset of real normed linear space
E .
LetP : E K
be the nonexpansive retraction of E ontoK .
A nonself mappingT : K E
is called asymptoticallynonexpansi ve
if there exists sequence k
n 1,
,k
n 1
(n) such that1.
, , all for )
( )
(PT 1xT PT 1y k xy x yK n
T n n n (1.3)
Let K be a nonempty subset of real normed linear space
E .
LetP : E K
be the nonexpansive retraction of E ontoK .
A nonself mappingT : K E
is called uniformly LLipschitzian if there exists constant 0
L
such that1.
, , all for )
( )
(PT 1xT PT 1y L xy x yK n
T n n (1.4)
As a matter of fact, if T is self-mapping, then P becomes the identity mapping, so that (1.3) and (1.4) reduces to (1.1) and (1.2), respectively. In addition, if
T : K E
is asymptotically nonexpansive andP : E K
is a nonexpansive retraction, thenPT : K K
is asymptotically nonexpansive. Indeed, for all x,yK and
n
, it follows thaty PT PT x PT PT y PT x
PT)n ( )n = ( )n 1 ( )n 1
(
y PT T x PT
T( )n1 ( )n1
. y x k
n
The converse, however, may not be true. Therefore, Zhou et al. [4] introduced the following generalized definition recently.
Definition 1.[4] Let K be a nonempty subset of real normed linear space
E .
LetP : E K
be the nonexpansive retraction of E intoK .
(i)A nonself mapping
T : K E
is called asymptotically nonexpansive with respect to P if there exists sequences
kn
1,
withk
n 1
asn
such that. , , , )
( )
(PT nx PT ny kn xy x yK n
(ii)A nonself mapping
T : K E
is said to be uniformly L-Lipschitzian with respect to P if there exists a constantL 0
such that. , , , )
( )
(PT nx PT ny L xy x yK n
Zhou et al. [4] obtained some strong and weak convergence theorems for common fixed points of nonself asymptotically nonexpansive mappings with respect to P in uniformly convex Banach spaces. As a consequence, the main results of Chidume et al. [2] were deduced.
Inspired and motivated by this facts, we study three step iteration scheme for approximating common fixed points of six nonself-asymptotically nonexpansive mappings with respect to P and to prove some strong convergence theorems for such mappings in uniformly convex Banach spaces. The scheme (1.5) is defined as follows.
Let K be a nonempty closed convex subset of a real normed linear space E with retraction P. Let Ti:K E 6)
1,2,3,4,5,
=
(i be six nonself-asymptotically nonexpansive mappings with respect to
P .
For any givenK
x
1
andn 1
, suppose that
xn is a sequence generated iteratively by
,
=
,
=
,
=
6 3 5
3 3
4 2 3
2 2
2 1 1
1 1
1
n n n
n n n
n n n
n n n
n n n
n n n
n n n
n n n n n n
x PT c x PT b x a z
z PT c z PT b x a y
y PT c y PT b x a x
(1.5)
where
a
ni, b
ni and c
ni i = 1,2,3
are sequences in ,1
for some 0,1
which satisfy condition1
ni
=
ni
ni
b c
a i = 1,2,3 .
If bn3 =bn2 =cn3 =cn2 0 for all n1, then (1.5) reduces to the iteration defined by Zhou et al. [4]
, , ) ( )
(
=
, 1 1 1 1 1 2
1K x a x b PT x c PT x n
x n n n n n n n n n (1.6)
where
a
n1, b
n1 and c
n1 are three sequences in ,1
for some 0,1 ,
satisfying an1bn1cn1 =1.2.Preliminaries
For the sake of convenience, we restate the following concepts and results.
Let E be a Banach space with its dimension greater than or equal to
2.
The modulus of E is the function 0 , 1 (0,2]
: )
(
E defined by.
= 1,
= 1,
= : ) 2 (
1 1 inf
= )
(
x y x y x y
E
A Banach space E is uniformly convex if and only if
E( ) > 0
for all
(0,2].Let E be a Banach space and
S ( E ) = x E : x = 1 .
The space E is said to be smooth ift
x ty x
t
lim
0
exists for all x,yS(E).
Let
C
and K be subsets of a Banach space E . A mapping P fromC
into K is called sunny if PxPx x t Px
P( ( ))= for
x C
with Pxt(xPx)C andt 0.
For any xK, the inward set
I
K(x )
is defined as follows: : = ( ), , 0 .
= )
( x y E y x z x z K I
KA mapping
T : K E
is said to satisfy the inward condition ifTx I
K(x )
for allx K .
T is said to be weakly inward ifTx clI
K(x )
for each xK,whereclI
K(x )
is the closure ofI
K(x )
.A mapping
T : K K
is said to be completely continuous if for every bounded sequence x
n,
there exists a subsequence say
xnj of
xn such that
Txnj converges to some element of the rangeT .
A mapping
T : K K
is said to be demicompact if any sequence
xn in K satisfyingx
n Tx
n 0
as
n
has a convergent subsequence.We need the following lemmas for our main results.
Lemma 1.[5] If
r
n ,
tn are two sequences of nonnegative real numbers such that
1
, 11
t r n
rn n n
and
<1
= n n
t , then
lim
nr
n exists.Lemma 2.[3] Let E be real smooth Banach space, let K be nonempty closed convex subset of E with P as a sunny nonexpansive retraction, and let
T : K E
be a mapping satisfying weakly inward condition. Then).
(
= ) (PT F T F
Lemma 3.[1] Let E be a real uniformly convex Banach space and
B
R= x E : x R
. Then there exists a continuous, strictly increasing, and convex functiong : 0, 0,
, g(0)=0 such that
,2 2
2
2 x y z g x y
z y
x
for all x, y,
z B
R, and all , , 0,1
with
=1. 3.Main ResultsIn this section, we present some several strong convergence theorems of the three step iteration scheme (1.5) to a common fixed point for six nonself-asymptotically nonexpansive mappings with respect to P in a real uniformly convex Banach spaces. We shall make use of the following lemmas.
Lemma 4.Let E be a real normed space and K a nonempty closed convex subset of E which is also a nonexpansive retract of E . Let Ti:K E (i=1,2,3,4,5,6) be six nonself-asymptotically nonexpansive mappings with respect to P with common sequence
k
n 1,
satisfying
n=1 k
n 1 <
. Suppose that
xn is defined by (1.5).
If
i i
T F F
61
=
= , then
lim
nx
n p
exists for all pF.Proof. Let pF. From (1.5), we have
PT x c PT x p b
x a p
z
n =
n3 n
n3 5 n n
n3 6 n n
(3.1)p x k c p x k b p x
a
n n
n n n
n n n
3 3 3. p x k
n n
By (1.5) and (3.1), we obtain
PT z c PT z p
b x a p
y
n =
n2 n
n2 3 n n
n2 4 n n
(3.2)p z k c p z k b p x
a
n n
n n n
n n n
2 2 2p x k c p x k b p x
a
n n
n n n
n n n
2 2 2 2 22
.
p x k
n n
Therefore, it follows from (1.5) and (3.2) that
x p b PT y p c PT y p
a p
x
n1 =
n1 n
n1 1 n n
n1 2 n n
(3.3)p y k c p y k b p x
a
n n
n n n
n n n
1 1 1p x k c p x k b p x
a
n n
n n n
n n n
1 1 3 1 3p x k
n n
3 1 .
=
nx
n p
Note that
n=1 k
n 1 <
is equivalent to
n=1 k
n3 1 < .
Thus, by (3.3) and Lemma 1,lim
nx
n p
exists for allpF. This completes the proof.Lemma 5.Let E be a real uniformly convex Banach space and K a nonempty closed convex subset of E which is also a nonexpansive retract of E . Let Ti:K E (i=1,2,3,4,5,6) be six nonself-asymptotically nonexpansive mappings with respect to P with common sequence
k
n 1,
satisfying
n=1 k
n 1 <
.Suppose that
xn is defined by (1.5), where a
ni, b
ni and c
ni i = 1,2,3
are sequences in ,1
for some 0,1 .
If
i i
T F F
61
=
= , then
lim
nx
n PT
ix
n= 0
for each i=1,2,3,4,5,6.Proof. From (1.5), by the property of P, and Lemma 3 , we have
5 3
6 23 3
2
= a x b PT x c PT x p
p
z
n
n n
n n n
n n n
(3.4)
5 2 3
6 23 2
3
x p b PT x p c PT x p
a
n n
n n n
n n n
n
n n
n
n
b g x PT x
a
3 3 1
5
2 2 3 2 2
3 2
3 x p b k x p c k x p
an n n n n n n n
n
n
n
PT x
x
g
1 52
n
n n
n
n
x p g x PT x
k
2
2
2 1
5
which implies that
g
1 x
n PT
5 nx
n 0
asn
. Sinceg
1: 0, 0,
withg
1 0 = 0
is a continuous strictly increasing convex function, it follows that = 0.
lim
5 nn n n
x PT x
(3.5)
Similarly, we obtain
= 0.
lim
6 nn n n
x PT x
(3.6)
It follows from (1.5), (3.4) and Lemma 3 that
3 2
4 22 2
2
= a x b PT z c PT z p
p
y
n
n n
n n n
n n n
(3.7)
3 2 2
4 22 2
2
x p b PT z p c PT z p
a
n n
n n n
n n n
n
n n
n
n
b g x PT z
a
2 2 2
3
2 2 2 2 2
2 2
2 x p b k z p c k z p
an n n n n n n n
n
n n
n
n
b g x PT z
a
2 2 2
3
4 2 2 4 2
2 2
2 x p b k x p c k x p
an n n n n n n n
n
n n
n n n n n
n
n
c g x PT x a b g x PT z
b
2
2 2 1
5
2 2 2
3
3 ,
2 2 2
4
n n n
n
n
x p g x PT z
k
which implies that
g
2 x
n PT
3 nz
n 0
asn
. Sinceg
2: 0, 0,
withg
2 0 = 0
is a continuous strictly increasing convex function, it follows that = 0.
lim
n 3 n nn
z PT x
(3.8)
Similarly, we have
= 0.
lim
n 4 n nn
z PT x
(3.9)
Similarly, it follows from (1.5), (3.7) and Lemma 3 that
1 1
2 21 1 2
1
p = a x b PT y c PT y p
x
n
n n
n n n
n n n
1 2 1
2 21 2
1
x p b PT y p c PT y p
a
n n
n n n
n n n
n
n n
n
n
b g x PT y
a
1 1 3
1
2 2 1 2 2
1 2
1 x p b k y p c k y p
an n n n n n n n
n
n
n
PT y
x
g
3 12
6 2 1 6 2
1 2
1 x p b k x p c k x p
an n n n n n n n
n
n n
n n n
n
n
c g x PT z g x PT y
b
1
1 2 2
3
2 3
1
1 ,
3 2 2 6
n n n
n
n
x p g x PT y
k
which implies that
g
3 x
n PT
1 ny
n 0
asn
. Since g3:
0,
0,
with g3
0 =0 is a continuous strictly increasing convex function, it follows that = 0.
lim
n 1 n nn
y PT x
(3.10)
Similarly, we have
= 0.
lim
2 nn n n
y PT x
(3.11)
It follows from (1.5), (3.5) and (3.6) that
n n n nn n n
n n n
n
x a x b PT x c PT x x
z =
3
3 5
3 6
(3.12)
nn n
n n n n
n
x PT x c x PT x
b
3
5
3
6
0,asn
It follows from (3.8) and (3.12) that
PT
3 nz
n z
n x
n PT
3 nz
n z
n x
n (3.13)
0,asn Similarly we have
= 0.
lim
4 n nn n
z z
PT
(3.14)
Noting that
n n
n n
n n n n
n n n n
n
z a x z b PT z z c PT z z
y =
2
2 3
2 4
, we have
n nn n
n n n n
n n n n
n
z a x z b PT z z c PT z z
y
2
2 3
2 4
This with (3.12), (3.13) and (3.14) implies that
0 lim
n n=
n
z y
(3.15)
From (3.12) and (3.15)
0 lim
n n=
n
y x
(3.16)
It follows from (3.10) and (3.16) that
n n nn n
n n
n
y y x PT y x y
PT
1
1
(3.17)
0,asn Similarly we have
= 0.
lim
2 n n nn
y y
PT
(3.18)
From (3.10) and (3.11), we have
n n n nn n n n n n
n
x a x b PT y c PT y x
x
1 =
1
1 1
1 2
(3.19)
nn n
n n n n
n
x PT y c x PT y
b
1
1
1
2
0,asn Noting that
nn n
n n
n n n
n n n
n
PT x x z PT z z PT z PT x
x
3
3
3
3
n nn n
n
n
x z PT z z
k
1
3This with (3.12) and (3.13) implies that
= 0
lim
3 nn n n
x PT x
(3.20)
Similarly we have
= 0
lim
n 4 n nn
x PT x
(3.21)
Noting that
nn n
n n
n n n
n n n
n
PT x x y PT y y PT y PT x
x
1
1
1
1
n nn n
n
n
x y PT y y
k
1
1This with (3.16) and (3.17) implies that
= 0
lim
1 nn n n
x PT x
(3.22)
Similarly we have
= 0.
lim
2 nn n n
x PT x
(3.23)
Since an asymptotically nonexpansive mapping with respect to P must be uniformly L-Lipschitzian with respect to P,where
L = sup
n1 k
n 1
, then we have
1
11 1
1 1
1
1
i n
n
i n n
i n n
i nn
PT x x PT x PT x PT x
x
1 1
1 11
x
nPT
i nx
nL x
nPT
i nx
n
nn i n n
n n
n i
n
PT x L x x L x PT x
x
1 1 1 1
1 L PT
i nx
nPT
i nx
n
nn i n n
n i
n
PT x L x PT x
x
1 1 1 L 1 x
n 1x
n.
L
Consequently, by (3.5), (3.6), (3.20), (3.21), (3.22), (3.23) and (3.19), it can be obtained that
= 0( = 1,2,3,4,5, 6) lim x
nPT
ix
ni
n
(3.24)
This completes the proof.
Theorem 1.Let E be a real uniformly convex Banach space and K a nonempty closed convex subset of E which is also a nonexpansive retract of E. Let Ti:K E (i=1,2,3,4,5,6) be six nonself-asymptotically nonexpansive mappings with respect to P with common sequence
k
n 1,
satisfying
n=1 k
n 1 <
. Suppose that
xn is defined by (1.5), where a
ni, b
ni and c
ni i = 1,2,3
are sequences in ,1
for some 0,1
and
i i
T F F
61
=
= . Then
xn converges strongly to a common fixed point of T
i 6i=1 if andonly if
lim inf
nd x
n, F = 0
, whered x
n, F = inf x
n p : p F .
Proof. The necessity is obvious. Thus, we need only prove the sufficiency. Suppose that
lim inf
nd x
n, F = 0
. From (3.3), we obtain
x 1,F
1
k3 1
d
x ,F .d n n n (3.25)
As
n=1 k
n3 1 <
, thereforelim
nd x
n, F
exists by Lemma 1. But by hypothesis , = 0,
lim inf
nd x
nF
hence we must havelim
nd x
n, F = 0.
Next we shall prove that
xn is a Cauchy sequence. It follows from (3.3) that for any n,mn0 x p
p
x
nm 1
nm1 nm1
n m x
n m p
exp
1 1. exp
1
=
p x
nk m n
n k
Let
M = exp
k=1
k ,
thenM > 0
and. ,
, n m n
0p
x M p
x
nm
n
(3.26)For an arbitrary
>0, sincelim
nd x
n, F = 0
, there exists a positive integerN
1 such that
F M x d n
< 4
,
for all
n N
1.
So, we have
.< 4
1,F M
x
d N
This means that there exists a x F such that 4 .
1 x M
xN
It follows from (3.26) that for all
n N
1 and m1,
x x x x x xn m n n m n