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THE BLOCK APPROXIMATION THEOREM

Dan Haran, Moshe Jarden and Florian Pop

Abstract. The block approximation theorem is an extensive general- ization of both the well known weak approximation theorem from valu- ation theory and the density property of global fields in their henseliza- tions. It guarantees the existence of rational points of smooth affine varieties that solve approximation problems of local-global type (see e.g. [HJP07]). The theorem holds for pseudo real closed fields, by [FHV94]. In this paper we prove the block approximation for pseudo-F- closed fields K, where F is an ´etale compact family of valuations of K with bounded residue fields (Theorem 4.1). This includes in particular the case of pseudo p-adically closed fields and generalizations of these like the ones considered in [HJP05].

Introduction

The block approximation property of a field K is a local-global principle for absolutely irreducible varieties defined over K on the one hand and a weak approximation theorem for valuations and orderings on the other hand.

It was proved in [FHV94] for orderings. Moreover, [HJP07] constructs fields with the block approximation property for valuations. In this work we prove the block approximation property for a much larger class of valuations.

More technically, the block approximation property of a proper field- valuation structure K = (K, X, K

x

, v

x

)

x∈X

is a quantitative local-global principle for absolutely irreducible varieties over K. Here K is a field and X is a profinite space on which the absolute Galois group Gal(K) of K continu- ously acts. Each K

x

is a separable algebraic extension of K equipped with a valuation v

x

. Given an absolutely irreducible variety V over K, open-closed subsets X

1

, . . . , X

n

of X (called blocks), and points a

1

, . . . , a

n

∈ V

simp

(K

s

) satisfying certain compatibility conditions, the block approximation prop- erty gives an a ∈ V (K) which is v

x

-close to a

i

for i = 1, . . . , n and every x ∈ X

i

.

The block approximation property of K has several far reaching conse- quences: For each x ∈ X, Aut(K

x

/K) = 1 and the valued field (K

x

, v

x

) is the Henselian closure of (K, v

x

|

K

). If x

1

, . . . , x

n

are non-conjugate ele- ments of X, then v

x1

|

K

, . . . , v

xn

|

K

satisfy the weak approximation theorem.

Finally, K is PX C, where X = {K

x

| x ∈ X}. This means that every abso- lutely irreducible variety V with a simple K

x

-rational point for each x ∈ X has a K-rational point [HJP07, Prop. 12.3].

53

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The main result of [HJP07] characterizes proper projective group struc- tures as absolute Galois group structures of proper field-valuation structures having the block approximation property. In particular, the local fields of the field-valuation structures turn out to be Henselian closures of K.

In [HJP05] we replace the general Henselian fields of [HJP07] by P-adically closed fields. Here we call a field F P-adically closed if it is elementarily equivalent to a finite extension of Q

p

for some p. The main result of [HJP05]

considers a finite set F of P-adically closed fields closed under Galois isomorphism (i.e. if F, F

are P-adically closed fields such that Gal(F) ∼ = Gal(F

) and F ∈ F, then F

∈ F.) It says that G is isomorphic to the absolute Galois group of a PFC field K if and only if G is F-projective and Subgr(G, F) is strictly closed in Subgr(G) for each F ∈ F.

The condition “G is F-projective” is very mild. It says, every finite embedding problem for G which is F-locally solvable is globally solvable.

Nevertheless, adding the second condition that Subgr(G, F) is strictly closed in Subgr(G) for each F ∈ F, the group G can be extended to a proper projective group structure G [HJP05, Thm. 10.4]. Then the main theorem of [HJP07] is applied to realize G as the absolute Galois structure of a field-valuation structure K = (K, X, K

x

, v

x

) having the block approximation property [HJP05, Thm. 11.3]. In particular, K is then PFC, that is K is PX C, where X = AlgExt(K, F)

min

. The latter symbol stands for the set of minimal fields in the set AlgExt(K, F) = S

F∈F

AlgExt(K, F), where AlgExt(K, F) is the set of all algebraic extensions of K that are elementarily equivalent to F.

Conversely, let K be a PFC field. Then AlgExt(K, F) is strictly closed in AlgExt(K) [HJP05, Lemma 10.1] and Gal(K) is F-projective [HJP05, Prop. 4.1]. It follows from the preceding paragraph that Gal(K) ∼ = Gal(K

) for some field extension K

of K that admits a field-valuation structure having the block approximation property.

The goal of the present work is to prove that if K is PFC, then one may choose K

= K in the preceding theorem. In other words, the natural field-valuation structure K

F

attached to K and F has the block approxima- tion property. For the convenience of the reader we reformulate this result without referring to field-valuation structures.

The P-adic Block Approximation Theorem. Let F be a finite set of P-adic fields closed under Galois isomorphism and K a PFC field. Set X = AlgExt(K, F)

min

. For each F ∈ X let v

F

be the unique P-adic valuation of F . Let I

0

be a finite set. For each i ∈ I

0

let X

i

be an ´etale open-closed subset of X , L

i

a finite separable extension of K contained in K

s

, and c

i

∈ K

×

. Suppose X = S

i∈I0

S

σ∈Gal(K)

X

iσ

. Suppose further, for all i ∈ I

0

and all σ ∈ Gal(K) we have X

iσ

= X

j

if and only if i = j and σ ∈ Gal(L

i

);

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otherwise X

iσ

∩ X

i

= ∅. Assume L

i

⊆ K

v

for each K

v

∈ X

i

. Let V be an affine absolutely irreducible variety defined over K. For each i ∈ I

0

let a

i

∈ V

simp

(L

i

). Then there exists a ∈ V (K) such that v

F

(a − a

i

) > v

F

(c

i

) for each i ∈ I

0

and for every F ∈ X

i

.

A block approximation theorem for real closed fields is proved in [FHV94, Prop. 1.2]: Let K be a PRC field, X a strictly closed system of represen- tatives for the Gal(K)-orbits of the real closures of K, and X = S

·

i∈I

X

i

a partition of X with X

i

open-closed. Let V be an absolutely irreducible va- riety defined over K. For each i ∈ I let a

i

be a simple point of V contained in V (F ) for each F ∈ X

i

. Then there exists a ∈ V (K) which is F -close to a

i

for each i ∈ I and each F ∈ X

i

.

The easy proof of the real block approximation theorem takes advantage of the function X

2

whose values are totally positive and of the assumption on X being a strictly closed system of representatives of the real closures of K.

The assumption on the existence of a strictly closed system of representatives holds for every field K [HaJ85, Cor. 9.2].

In the P-adic case we can prove a similar result about systems of represen- tatives only in some cases, e.g. if F = {Q

p

} or if K is countable. But we do not know whether in the general case the Gal(K)-orbits of AlgExt(K, F)

min

have a closed (in the ´etale topology) system of representatives. Fortunately, the conditions on the blocks in the P-adic block approximation theorem can be always realized and they turn out to be sufficient for the proof of the block approximation theorem.

The P-adic block approximation theorem is based on a block approxi- mation theorem for field-valuation structures K = (K, X, K

x

, v

x

)

x∈X

with bounded residue fields (Theorem 4.1). Instead of the function X

2

used in the proof of the block approximation theorem for real closed fields our proof uses a function ℘(X) with good P-adic properties. In particular, its values are totally P-adically integral (Section 3). We also use that if K is PX C, with X = {K

x

| x ∈ X}, then K is v

x

-dense in K

x

for each x ∈ X.

The next step is to extend the PFC field K of the P-adic block approx- imation theorem to a field-valuation structure K = (K, X, K

x

, v

x

)

x∈X

such that X = AlgExt(K, F)

min

. There are two essential points in the proof.

First we prove that Aut(K

x

/K) = 1 for each x ∈ X (essentially Proposition 2.3(b)). Then we prove that for each finite extension L of K the map of X

L

= {K

x

∈ X | L ⊆ K

x

} into Val(L) given by v

x

7→ v

x

|

L

is ´etale continuous [Lemma 5.12].

1. On the Algebraic Topological Closure of a Valued Field

The completion ˆ K

v

of a rank one valued field (K, v) is the ring of all

Cauchy sequences modulo 0-sequences. A similar construction works for an

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arbitrary valued field (K, v). If rank(v) = 1, then the Henselization K

v

of (K, v) coincides with the closure K

v,alg

of K in K

s

with respect to the v-adic topology. In the general case, K

v,alg

is only contained in K

s

. Nevertheless, as we shall see below, K

v,alg

shares several properties with K

v

.

Definition 1.1 (Cauchy sequences). Let v be a valuation of a field K. We denote the valuation ring of v by O

v

and its residue field by ¯ K

v

. Unless we say otherwise, we assume that v is nontrivial; that is O

v

is a proper subring of K. Occasionally we also speak about the trivial valuation v

0

of K with O

v0

= K.

Let λ be a limit ordinal. A sequence (of length λ of elements of K) is a function x from the set of all ordinals smaller than λ (usually one identifies this set with λ itself) to K. We denote the value of x at κ < λ by x

κ

and the whole sequence by (x

κ

)

κ<λ

. The sequence (x

κ

)

κ<λ

converges to an element a of K if for each c ∈ K

×

there is a κ

0

< λ with v(x

κ

− a) > v(c) for all κ ≥ κ

0

. We say (x

κ

)

κ<λ

is a Cauchy sequence if for each c ∈ K

×

there is a κ

0

with v(x

κ

− x

κ

) > v(c) for all κ, κ

≥ κ

0

. Finally, (K, v) is complete if every Cauchy sequence in K converges.

Proposition 1.2 ([Ax71, p. 173, Prop. 8]). Every valued field (K, v) has an extension ( ˆ K

v

, ˆ v) which is complete such that (K, v) is dense in ( ˆ K

v

, ˆ v).

This extension is unique up to a (K, v)-isomorphism.

Remark 1.3 (The valuation ring of ˆ K

v

). Denote the valuation ring of ˆ K

v

by ˆ O

v

. It is the closure of O

v

in ˆ K

v

under the ˆ v-topology. In analogy to the presentation of Z

p

as an inverse limit lim

←− Z/p

n

Z, we present ˆ O

v

as an inverse limit of quotient rings of O

v

.

To this end let Γ

v

be the value group of (K, v). For each nonnegative α ∈ Γ

v

consider the ideal m

α

= {a ∈ K | v(a) > α} of O

v

. We prove that there is a natural isomorphism lim

←− O

v

/m

α

∼ = ˆ O

v

.

Choose a well ordered cofinal subset ∆ of Γ

v

. For each x = (x

α

+ m

α

)

α∈Γv

in lim

←− O

v

/m

α

the sequence (x

α

)

α∈∆

is Cauchy. Hence, it converges to an element ˆ x of ˆ O

v

which is independent of the representatives x

α

of x

α

+ m

α

. Conversely, let ˆ x ∈ ˆ O

v

. For each α ∈ Γ choose x

α

∈ O

v

with ˆ v(x

α

−ˆ x) > α.

If β > α, then v(x

β

− x

α

) > α. So, x

β

≡ x

α

mod m

α

. This gives a well defined element x = (x

α

+ m

α

)

α∈Γv

of lim

←− O

v

/m

α

which is mapped to ˆ x under the map of the preceding paragraph.

The map x 7→ ˆ x is the promised isomorphism.

Notation 1.4. We denote the set of all valuations of K and the trivial valu-

ation by Val(K).

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Let v, v

∈ Val(K). We say v is finer than v

(and v

is coarser than v) and write v  v

if O

v

⊆ O

v

. In particular, the trivial valuation is coarser than every v ∈ Val(K). If, in addition, O

v

⊂ O

v

(i.e. O

v

is a proper subset of O

v

), we say that v

is strictly coarser than v and write v ≺ v

.

Remark 1.5 (Dependent valuations). Valuations v and v

of K are depen- dent if K has a valuation v

′′

which is coarser than both v and v

; equiv- alently, if the ring O

v

O

v

= { P

n

i=1

a

i

a

i

| a

i

∈ O

v

, a

i

∈ O

v

} is a proper subring of K. This is the case if and only if the v-topology of K coincides with the v

-topology [Jar91b, Lemma 3.2(a) and Lemma 4.1]

1

. Denote the common topology by T .

The definitions of a Cauchy sequence and the convergence of transfinite sequences, as well of the concept of density can be rephrased in terms of the T -topology. For example, a sequence (x

κ

)

κ<λ

is Cauchy if and only if the following holds: For every T -open neighborhood U of 0 in K there is a κ

0

with x

κ

− x

κ

∈ U for all κ, κ

≥ κ

0

. Hence, ( ˆ K

v

, ˆ v) depends only on the topology T . Thus, ˆ K

v

can be identified with ˆ K

v

. If O

v

⊆ O

v

, than O ˆ

v

⊆ ˆ O

v

, because ˆ O

v

is the T -closure of O

v

and ˆ O

v

is the T -closure of O

v

in ˆ K

v

.

Remark 1.6 (The separable algebraic part of the completion). Let ( ˆ K

v

, ˆ v) be the completion of a valued field (K, v). In general, ˆ K

v

is not a separable extension of K. Nevertheless, we denote the maximal valued subfield of ( ˆ K

v

, ˆ v) which is separable algebraic over K by (K

v,alg

, v

alg

). Since ( ˆ K

v

, ˆ v) is unique up to a (K, v)-isomorphism, so is (K

v,alg

, v

alg

).

We extend ˆ v to a valuation ˆ v

s

of the separable closure ( ˆ K

v

)

s

of ˆ K

v

and embed K

s

in ( ˆ K

v

)

s

. Let v

s

be the restriction of ˆ v

s

to K

s

. Then K

v,alg

is the closure of K in K

s

under the v

s

-topology. Thus, a choice of ˆ v

s

and an embedding of K

s

in ( ˆ K

v

)

s

determines K

v,alg

uniquely within K

s

. We say that K

v,alg

is the v-closure of K.

Suppose w is a valuation coarser than v. Then ˆ K

w

= ˆ K

v

(Remark 1.5).

By the first paragraph of this remark, K

w,alg

= K

v,alg

. Thus, the v-closure and the w-closure of K coincide.

Let D

vs

= {σ ∈ Gal(K) | σO

vs

= O

vs

} be the decomposition group of v

s

over K. Let K

v

be the fixed field of D

vs

in K

s

and v

h

be the restriction of v

s

to K

v

. Then (K

v

, v

h

) is the Henselian closure of (K, v). It is determined by v up to a K-isomorphism.

Each σ ∈ D

vs

preserves the v

s

-topology of K

s

, hence fixes each element of the v

s

-closure of K in K

s

, so σ ∈ Gal(K

v,alg

). Therefore, K

alg,v

⊆ K

v

.

1

We use [Jar91b] as our main source for basic facts about valuation theory. Other

possible sources are [Rbn64], [Ax71], [End72], [Efr01], etc.

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Suppose rank(v) = 1; that is, no nontrivial valuation of K is strictly coarser than v. Alternatively, the value group of v is isomorphic to a sub- group of R [Jar91b, Lemma 3.4]. Then ˆ K

v

is Henselian (Hensel’s lemma).

Hence, K

v,alg

= K

s

∩ ˆ K

v

is also Henselian. It follows that K

v,alg

= K

v

. Remark 1.7 (Definition of T

wv

K

w

). We consider v ∈ Val(K). If v is nontrivial, we extend v to a valuation v

s

of K

s

, otherwise we let v

s

be the trivial valuation of K

s

. Then we extend each w ∈ Val(K) which is coarser than v to a valuation w

s

which is coarser than v

s

[Jar91b, Lemma 9.4]. The map w 7→ w

s

is a bijection of the set of all valuations of K coarser than v onto the set of all valuations of K coarser than v

s

. Its inverse is the map w

s

7→ w

s

|

K

. Moreover, if w  w

, then w

s

 w

s

. Indeed, since both w

s

and w

s

are coarser than v

s

, they are comparable [Jar91b, Lemma 3.2]. Hence, w

s

 w

s

or w

s

 w

s

. In the latter case, w = w

, so w

s

= w

s

.

Let D(w

s

) be the decomposition group of w

s

over K. We denote the fixed field of D(w

s

) in K

s

by K

w

and put w

h

= w

s

|

Kw

. Then (K

w

, w

h

) is a Henselian closure of (K, w). If w  w

, then D

ws

⊆ D

ws

and K

w

⊆ K

w

[Jar91b, Prop. 9.5].

It follows that T

w≻v

K

w

is an extension of K which is well defined up to a K-isomorphism. Since K

v,alg

= K

w,alg

for each w ≻ v [Remark 1.6], K

v,alg

⊆ T

w≻v

K

w

⊆ K

v

.

Lemma 1.8 ([Eng78, Thm. 2.11]). Let (K, v) be a valued field. For each valuation w of K which is coarser than v we choose a Henselian closure (K

w

, w

h

) with K

w

⊆ K

v

and v

h

|

Kw

= w

h

. Then K

v,alg

= T

wv

K

w

. Proof. By Remark 1.7, L = T

wv

K

w

is well defined. Moreover, the set of all valuations w of K which are coarser than v is linearly ordered. That is, if v  w, w

, than either O

w

⊆ O

w

or O

w

⊆ O

w

[Jar91b, Lemma 3.2].

Hence, O = S

wv

O

w

is either a valuation ring of K or K itself.

Case A: O is the valuation ring of a valuation w

0

. (We say that v is bounded). In this case w

0

is finer than no other valuation of K. Hence, rank(w

0

) = 1. Therefore, L = K

w0

= K

w0,alg

= K

v,alg

(Remark 1.6).

Case B: O = K (We say that v is unbounded). It suffices to prove K is v-dense in L. Consider w, w

 v. Denote the restriction of w

h

(resp. (w

)

h

, v) to L by w

L

(resp. w

L

, v

L

). By our choice w  w

if and only if w

L

 w

L

. Hence, v

L

is unbounded. Therefore, S

wv

O

wL

= L and T

wv

m

w

L

= 0.

Let now x, c ∈ L

×

. Then, there is w  v with c, c

−1

, x, x

−1

∈ m /

wL

. Thus, w

L

(c) = w

L

(x) = 0. Since K ⊆ L ⊆ K

w

, the residue field of L at w

L

is ¯ K

w

. Hence, there is a ∈ K with w

L

(a − x) > 0 = w

L

(c). Since m

wL

⊆ m

vL

, this

gives v

L

(a − x) > v

L

(c), as desired. 

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Lemma 1.9. Let f ∈ K

v,alg

[X]. Suppose f has a zero in K

w

for each w  v. Then f has a zero in K

v,alg

.

Proof. Let x

1

, . . . , x

n

be the zeros of f in ˜ K. Assume x

1

, . . . , x

n

∈ K /

v,alg

. Then, for each i there is w

i

 v with x

i

∈ K /

wi

(Lemma 1.8). Let w be the coarsest valuation among w

1

, . . . , w

n

. Thus, K

w

⊆ K

wi

, i = 1, . . . , n, so x

1

, . . . , x

n

∈ K /

w

. In other words, f has no zero in K

w

, a contradiction.  The following result generalizes a lemma of Kaplansky-Krasner [FrJ86, Lemma 10.13]. Its proof is included in the proof of [Pop90, Lemma 2.7].

Lemma 1.10. Let f ∈ K

v,alg

[X]. Suppose f has no root in K

v,alg

. Then f is bounded away from 0. That is, 0 has a v-open neighborhood U in K

v,alg

such that f (K

v,alg

) ∩ U = ∅.

Proof. Lemma 1.9 gives w  v with no roots in K

w

of f . Kaplansky-Krasner for Henselian fields [FrJ, Lemma 10.13] gives a w-open neighborhood U

w

of 0 in K

w

with f (K

w

) ∩ U

w

= ∅. Then U = K

v,alg

∩ U

w

is a w-open, hence also v-open, neighborhood of 0 in K

v,alg

which satisfies f (K

v,alg

) ∩ U = ∅.



Proposition 1.11. Consider valuations v and w of K. Suppose K

v

= K

v,alg

, K

w

= K

w,alg

, and K

v

6= K

w

. Then K

v

K

w

= K

s

.

Proof. Put M = K

v

K

w

. Assume M 6= K

s

. With the notation of Remark 1.6, let v

s

(resp. v

M

) be the restriction of ˆ v

s

to K

s

(resp. M ). Define w

M

and w

s

analogously. Then M is Henselian with respect to both v

M

and w

M

. Hence, v

M

and w

M

are dependent [Jar91b, Lemma 13.2]. Therefore, they define the same topology T on M .

By Remark 1.6, K

v

is the closure of K in K

s

in the v

s

-topology, so K

v

is the T -closure of K in M . Similarly K

w

is the T -closure of K in M . It follows, K

v

= K

w

, in contradiction to our assumption.  Definition 1.12 (The core of a valuation). Let (K, v) be a valued field.

Suppose ¯ K

v

is separably closed. Denote the set of all w ∈ Val(K) with v  w and ¯ K

w

separably closed by V (v). If w ∈ V (v), w

0

∈ Val(K) and v  w

0

 w, then ¯ K

w0

is a residue field of ¯ K

w

. Hence, ¯ K

w0

is separably closed and w

0

∈ V (v).

Let O = S

w∈V(v)

O

w

. The right hand side is an ascending union of

overrings of O

v

(i.e. subrings of K containing O

v

). Hence, O is an overring

of O

v

. As such, either O is a valuation ring of K or K itself. Let v

core

be

the corresponding valuation in the former case and the trivial valuation in

the latter case. Call v

core

the core of v.

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To make the definition complete, we define V (v) = {v} and v

core

= v if K ¯

v

is not separably closed. This definition follows the convention of [Pop88]

but is slightly different from that of [Pop94].

Let K be a non-separably-closed field and v

1

, v

2

Henselian valuations of K.

If ¯ K

v1

or ¯ K

v2

are not separably closed, then by F.K.Schmidt-Engler [Jar91b, Prop 13.4], v

1

and v

2

are comparable. The following result completes this statement in the case where both ¯ K

v1

and ¯ K

v2

are separably closed. It appears without proof as [Pop88, Satz 1.9].

Lemma 1.13 ([Pop94, Prop. 1.3]). Let v

1

and v

2

be Henselian valuations of a field K. Suppose K is not separably closed. Then v

1,core

and v

2,core

are comparable.

Proof. We consider two cases.

Case A: v

1

and v

2

are comparable. Without loss we may assume that v

1

 v

2

. Then ¯ K

v1

is a residue field of ¯ K

v2

. We first suppose ¯ K

v1

is not separably closed. Then ¯ K

v2

is not separably closed. So, v

1,core

= v

1

and v

2,core

= v

2

. Therefore, v

1,core

 v

2,core

.

Next we suppose ¯ K

v1

is separably closed but ¯ K

v2

is not. Let w ∈ V (v

1

).

Then v

1

 w and ¯ K

w

is separably closed. Hence, w is not coarser than v

2

, so w must be finer than v

2

. It follows, v

1,core

 v

2

= v

2,core

.

Finally we suppose both ¯ K

v1

and ¯ K

v2

are separably closed. Then v

2

∈ V (v

1

) and v

1,core

= v

2,core

.

Case B: v

1

and v

2

are incomparable. By assumption, K is not separably closed. Hence, both ¯ K

v1

and ¯ K

v2

are separably closed. Moreover, K has a valuation w with v

1

, v

2

 w and ¯ K

w

separably closed [Jar91b, Proposition 13.4]. Hence, by the third paragraph of Case A, v

1,core

= w

core

= v

2,core

.  We use the notion of the core of a valuation to supplement a result of F.K.Schmidt-Engler saying that if ¯ K

v

is not separably closed, then Aut(K

v

/K) = 1 [Jar91b, Prop. 14.5].

Proposition 1.14. Let (K, v) be a valued field. Suppose K

v

= K

v,alg

but K

v

6= K

s

. Then Aut(K

v

/K) is trivial.

Proof. Consider σ ∈ Aut(K

v

/K). Let K

be the fixed field of σ in K

v

and v

the restriction of v

h

to K

. Then K

v

= K

v

. Also, K

v

is the v

s

-closure of K

in K

s

(Remark 1.6). Hence, K

v

= K

v,alg

. Replace therefore (K, v) by (K

, v

), if necessary, to assume K

v

/K is Galois.

The field K

v

is Henselian with respect to both v

h

and v

h

◦ σ. By Lemma

1.13, (v

h

)

core

and (v

h

◦ σ)

core

are comparable. Since (v

h

◦ σ)

core

= (v

h

)

core

σ, the valuations (v

h

)

core

and (v

h

)

core

◦ σ are comparable. In addition,

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(v

h

)

core

|

K

= (v

h

)

core

◦ σ|

K

. Hence, by [Jar91b, Cor. 6.6], (v

h

)

core

= (v

h

)

core

◦ σ. Thus, σ belongs to the decomposition group D of (v

h

)

core

in Gal(K

v

/K).

Denote the restriction of (v

h

)

core

to K by w. Then v  w. Hence, K

v

= K

v,alg

⊆ K

w

⊆ K

v

. So, K

w

= K

v

. This implies D is trivial. It follows

from the preceding paragraph that σ = 1. 

2. Henselian Closures of PX C Fields

A valued field (K, v) is v-dense in K

v,alg

but not necessarily in its Henselization. However, under favorable conditions, this is the case.

We consider a field K, a fixed separable closure K

s

of K, and denote the family of all extensions of K in K

s

by SepAlgExt(K). A basis for the ´ etale topology of SepAlgExt(K) is the collection of all sets SepAlgExt(L), where L is a finite separable extension of K [HJP07, Section 1].

Let X be an ´etale compact subset of SepAlgExt(K), K

a minimal field in X , and v a valuation of K

. Suppose K is PX C and (K

, v) is Henselian.

We prove that K is v-dense in K

and (K

, v) is a Henselian closure of (K, v|

K

) (Proposition 2.3). An analogous result holds when v is replaced by an ordering.

We recall here that K is said to be PX C, if each absolutely irreducible variety over K with a simple K

-rational point for each K

∈ X has a K- rational point.

Lemma 2.1. Let F be a separable algebraic extension of K and M an arbitrary extension of K. Suppose every irreducible polynomial f ∈ K[X]

with a root in F has a root in M . Then there is a K-embedding of F in M . Proof. For each finite extension L of K in F let Embd

K

(L, M ) be the set of all K-embedding of L in M . It is a nonempty finite set. Indeed, let x be a primitive element for L/K and f = irr(x, K). By assumption, f has a root x

in M . The map x 7→ x

extends to a K-embedding of L into M .

Suppose L

is a finite extension of L in F . Then the restriction from L

to L maps Embd

K

(L

, M ) into Embd

K

(L, M ). The inverse limit of all Embd

K

(L, M ) is nonempty. Each element in the inverse limit defines a

K-embedding of F into M . 

The following result is an elaboration of [Pop90, Lemma 2.7].

Lemma 2.2. Let X be an ´etale compact subset of SepAlgExt(K) and v a valuation of K. Suppose K is PX C. Then the following holds.

(a) Let f ∈ K[X] be a separable polynomial. Suppose f has a zero in each K

∈ X . Then f has a zero in K

v,alg

.

(b) There is a K

∈ X that can be K-embedded in K

v,alg

.

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Proof of (a). Assume f has no root in K

v,alg

. Choose b ∈ K with f

(b) 6= 0 and let c = f (b). Then c 6= 0. Lemma 1.10 gives a v-open neighborhood U of 0 in K

v,alg

with

(2) f (K

v,alg

) ∩ U = ∅

Choose d ∈ K

×

with

(3) {y ∈ K

v,alg

| v(y) > v(d)} ⊆ U.

Finally choose e ∈ K

×

with v(e) > 2v(d) − v(c).

Now consider x ∈ K. By (2), f (x) / ∈ U , so by (3), v(f (x)) ≤ v(d).

Similarly, by (3), v(c) = v(f (b)) ≤ v(d). Hence, v

f(x)c



≥ v(c) − v(d).

Therefore, v 

e 1 − c f (x)

 

≥ v(e) + min(v(1), v(c) − v(d))

> 2v(d) − v(c) + v(c) − v(d) = v(d).

Thus,

(4) e 

1 − c f (K)

 ⊆ U.

Set h(X, Y ) = f (Y ) 1 −

f(X)e

 − c. Since f (Y ) has no multiple roots and c 6= 0, Eisenstein’s criterion [FrJ05, Lemma 2.3.10(b’)] implies that h(X, Y ) is absolutely irreducible. By assumption, for each K

∈ X there exists a ∈ K

with f (a) = 0. Hence, h(a, b) = 0 and

∂Y∂h

(a, b) = f

(b) 6= 0. Since K is PX C, there are x, y ∈ K with h(x, y) = 0. Thus, f (x) = e 1 −

f(y)c

. By (4), the right hand side is in U . Hence, f (x) ∈ f (K) ∩ U . This contradiction to (2) completes the proof of (a).

Proof of (b). Assume no K

∈ X is K-embeddable in K

v,alg

. Consider K

∈ X . By Lemma 2.1, there is an a

K

∈ K

such that irr(a

K

, K) has no roots in K

v,alg

. By definition, SepAlgExt(K(a

K

)) is an ´etale open neighborhood of K

in SepAlgExt(K). The union of all these neighbor- hoods covers X . Since X is ´etale compact, there are K

1

, . . . , K

n

∈ X with X ⊆ S

n

i=1

SepAlgExt(K(a

K

i

)). Put f (X) = lcm(irr(a

K

i

, K) | i = 1, . . . , n).

It is a separable polynomial without roots in K

v,alg

.

On the other hand, for each K

∈ X there is an i with K

∈ SepAlgExt(K(a

K

i

)). Thus, a

Ki

is a root of f (X) in K

. We con- clude from (a) that f (X) has a root in K

v,alg

. This contradiction to the preceding paragraph proves there is a K

∈ X which is K-embeddable in

K

v,alg

. 

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Call a pair (F, T ) a locality if F is a field, and either T is the topology defined on F by a Henselian valuation or F is real closed and T is the topology defined by the unique ordering of F .

Proposition 2.3 (Density, [Pop90, Thm. 2.6]). Let K be a field, X a Gal(K)-invariant family of separable algebraic extensions of K, and (K

, T

) a locality. Suppose X is ´etale compact, K is PX C, and K

is a minimal el- ement of X . Then:

(a) K is T

-dense in K

. Moreover, if T

is defined by a Henselian valuation v

of K

and v = v

|

K

, then (K

, v

) is a Henselian closure of (K, v) and K

= K

v,alg

.

(b) Suppose K

6= K

s

. Then, Aut(K

/K) = 1.

(c) Let (K

′′

, T

′′

) be a locality such that K

′′

is a minimal element of X and K

′′

6= K

. Then K

K

′′

= K

s

.

Proof of (a). First we suppose T

is defined by a Henselian valuation v

of K

. Since (K

, v

) is Henselian, it contains a Henselian closure (K

v

, v

h

) of (K, v).

Lemma 2.2(b) gives E ∈ X in K

v,alg

. Thus, K ⊆ E ⊆ K

v,alg

⊆ K

v

⊆ K

. Since K

is minimal, E = K

. Hence, K

v,alg

= K

v

= K

. In particular, (K

, v

) is a Henselian closure of (K, v) and K is v

-dense in K

(Remark 1.6).

Now we suppose K

is real closed and T

is the topology defined by the unique ordering < of K

. If < is archimedean, then K

is contained in R and Q ⊆ K. Since Q is dense in R, so is K.

Suppose < is nonarchimedean. Then the set of all x ∈ K

with −n ≤ x ≤ n for some n ∈ N is a valuation ring of a Henselian valuation v of K

[Jar91b, Lemma 16.2]. In particular, {x ∈ K

| −1 ≤ x ≤ 1} ⊆ O

v

. This means, in the terminology of [Jar91b, §16], v is coarser than <. It follows from [Jar91b, Remark 16.3] that the T

-topology on K

coincides with the

<-topology. We conclude from the first case that K is <-dense in K

. Proof of (b). Statement (b) is well known if K

is real closed [Lan, p. 455, Thm. 2.9]. When T

is defined by a Henselian valuation v of K

, use (a) and Proposition 1.14.

Proof of (c). If K

or K

′′

is real closed, then its codegree in ˜ K is 2. Hence, K

6= K

′′

implies K

K

′′

= ˜ K. If both T

and T

′′

are induced by nontrivial

valuations, use (a) and Proposition 1.11. 

The minimality condition in Proposition 2.3 is automatic if (K

, v

) is a

Henselian closure of (K, v) with a finite residue field.

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Lemma 2.4. Let E be a Henselian field with respect to valuations v and w.

Suppose both ¯ E

v

and ¯ E

w

are algebraic extensions of finite fields but at least one of them is not algebraically closed. Then v and w are equivalent.

Proof. Since one of the fields ¯ E

v

and ¯ E

w

is not separably closed, v and w are comparable [Jar91b, Prop. 13.4]. This means ¯ E

v

is a residue field of ¯ E

w

or E ¯

w

is a residue field of ¯ E

v

. Since both ¯ E

v

and ¯ E

w

are algebraic extensions of finite fields, none of them has a nontrivial valuation. Hence, ¯ E

v

= ¯ E

w

.

Consequently, v and w are equivalent. 

Proposition 2.5. Let K be a field and X a set. For each x ∈ X let (K

x

, v

x

) be a valued field with residue field ¯ K

x

= (K

x

)

vx

. Suppose ¯ K

x

is finite and (K

x

, v

x

) is the Henselian closure of (K, v

x

|

K

) for all x ∈ X, and X = {K

xσ

| x ∈ X, σ ∈ Gal(K)} is ´etale compact, and K is PX C. Then K is v

x

-dense in K

x

.

Proof. By Proposition 2.3, it suffices to prove that each K

x

with x ∈ X is minimal in X .

Let y ∈ X, σ ∈ Gal(K), and K

yσ

⊆ K

x

. We may assume that σ = 1.

Extend v

y

to a valuation v

y

of K

x

. Then K

x

is Henselian with respect to both v

x

and v

y

. By assumption, ¯ K

x

is finite and (K

x

)

vy

is an algebraic extension of the finite field ¯ K

y

. By Lemma 2.4, v

x

= v

y

, so v

x

|

K

= v

y

|

K

. Thus, both K

x

and K

y

are Henselian closures of K with respect to the same valuation, hence K

x

∼ =

K

K

y

. Since K ⊆ K

y

⊆ K

x

, this implies K

x

= K

y

[FrJ05, Lemma 20.6.2]. 

3. The bounded Operator

Let (K, v) be a Henselian field having an element π with a minimal posi- tive value and a finite residue field of q elements. The Kochen operator

γ(X) = 1 π

X

q

− X (X

q

− X)

2

− 1

is then a rational function on K satisfying γ(K) = O

v

[JaR80, p. 426 or PrR84, p. 122]. It plays a central role in the theory of P-adically closed fields.

Here we consider an arbitrary valued field (K, v) with a finite residue field. Let m be a positive integer. Denote the residue of an element a ∈ O

v

(resp. polynomial g ∈ O

v

[X]) in ¯ K

v

(resp. ¯ K

v

[X]) by ¯ a (resp. ¯ g). We say

(K, v) has an m-bounded residue field if ¯ K

v

is finite and m is a multiple

of | ¯ K

v×

|. Then ¯a

m

= 1 for each a ∈ O

v

with v(a) = 0.

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We replace the Kochen operator by the m-bounded operator

(1) ℘(X) = ℘

m

(X) = X

2m

X

2m

− X

m

+ 1 ∈ K(X).

It has several improved properties which turn out to be useful in the proof of the block approximation theorem:

Lemma 3.1. Let (K, v) be a valued field with an m-bounded residue field.

Then the following holds for each a ∈ K:

(a) v(℘(a)) ≥ 0.

(b) v(℘(a)) ≥ v(a).

(c) Either v(℘(a)) > 0 or v(℘(a) − 1) > 0.

(d) v(a) > 0 if and only if v(℘(a)) > 0.

(e) v(a) ≤ 0 if and only if v(℘(a) − 1) > 0.

Proof. The assertions follow by analyzing the three possible cases.

First we suppose, v(a) > 0. Then v(a

2m

− a

m

+ 1) = v(1) = 0, so v(℘(a)) = 2mv(a) > v(a) > 0.

Now suppose v(a) < 0. Then v(a

2m

− a

m

+ 1) = v(a

2m

) = 2mv(a) and v(a

m

− 1) = mv(a). Thus v(℘(a) − 1) = v(a

m

− 1) − v(a

2m

− a

m

+ 1) =

−mv(a) > 0 and v(℘(a)) = 0.

Finally suppose v(a) = 0. Then v(a

2m

− a

m

+ 1) ≥ 0. Hence, ¯ a

2m

¯

a

m

+ 1 = 1

2

− 1 + 1 6= 0. Therefore, v(a

2m

− a

m

+ 1) = 0. Consequently, v(℘(a) − 1) = v(a

m

− 1) > 0 and v(℘(a)) = 0. 

Lemma 3.1(a),(b) implies:

Corollary 3.2. Let (K, v) be a valued field with an m-bounded residue field and let c

1

, . . . , c

r

∈ K

×

. Then, c = Q

r

i=1

℘(c

i

) satisfies v(c) ≥ v(c

1

), . . . , v(c

r

).

Notation 3.3 (A special rational function). Consider a polynomial g(Y ) = b

n

Y

n

+ b

n−1

Y

n−1

+ · · · + b

1

Y + b

0

∈ O

v

[Y ] satisfying the following conditions:

(3a) b

0

, b

n

∈ O

v×

,

(3b) ¯ g(Y ) has no roots in ¯ K

v

= F

q

,

(3c) if char(K) = p > 0, then g has a root of multiplicity < p in ˜ K, and (3d) n ≥ 4.

(For instance, g(Y ) =

YY −1m−1

= Y

m−1

+ · · · + Y + 1, where m ≥ 5 is relatively prime to q(q − 1). In this case each zero of g in ˜ K is simple.) Set

f (Y ) = b

1

Y

3

− 2b

1

Y

2

+ (b

1

− b

0

)Y + b

0

(14)

and

Φ(Y ) = 1 − f (Y )

g(Y ) = g(Y ) − f (Y ) g(Y )

= b

n

Y

n

+ · · · + b

4

Y

4

+ (b

3

− b

1

)Y

3

+ (b

2

+ 2b

1

)Y

2

+ b

0

Y b

n

Y

n

+ b

n−1

Y

n−1

+ · · · + b

1

Y + b

0

. Lemma 3.4. Let (K, v) be a valued field with an m-bounded residue field.

(a) Every a ∈ K satisfies v(Φ(a)) ≥ 0. Moreover, if v(a) > 0 then v(Φ(a)) ≥ v(a).

(b) Φ(0) = 0 and Φ(1) = 1.

(c) Suppose (K, v) is Henselian. Let c ∈ K be such that either v(c) > 0 or v(c − 1) > 0. Then there is a y ∈ K such that Φ(y) = c and Φ

(y) 6= 0.

(d) The numerator of the rational function Φ(Y

1

) + Φ(Y

2

) + Φ(Y

3

) − a is absolutely irreducible for each a ∈ K.

Proof of (a). If v(a) > 0, then v(g(a)) = v(b

0

) = 0. Also, v(g(a) − f (a)) ≥ v(a), because Y divides g(Y ) − f (Y ) in O

v

[Y ]. Hence v(Φ(a)) ≥ v(a) > 0.

If v(a) = 0, then v(g(a) − f (a)) ≥ 0 and v(g(a)) ≥ 0. But v(g(a)) ≤ 0, by (3b). Hence, v(g(a)) = 0. Therefore, v(Φ(a)) ≥ 0.

Finally, if v(a) < 0, then v(g(a) − f (a)) = nv(a) and v(g(a)) = nv(a).

Hence v(Φ(a)) = 0.

Proof of (c). It suffices to show that the polynomial h(Y ) = f (Y ) + (c − 1)g(Y ) ∈ K[Y ]

has a root y in K such that h

(y) 6= 0 and g(y) 6= 0. Indeed, then Φ(y) = c and Φ

(y) = −

hg(y)(y)

. By (3b) it suffices to find a root y ∈ O

v

of h such that h

(y) 6= 0.

If v(c) > 0, then

(4a) h(0) ≡ f (0) − g(0) ≡ b

0

− b

0

≡ 0 mod m

v

and

(4b) h

(0) ≡ f

(0) − g

(0) ≡ (b

1

− b

0

) − b

1

≡ −b

0

6≡ 0 mod m

v

. If v(c − 1) > 0, then

(5a) h(1) ≡ f (1) ≡ b

1

− 2b

1

+ (b

1

− b

0

) + b

0

≡ 0 mod m

v

and (5b) h

(1) ≡ f

(1) ≡ 3b

1

− 4b

1

+ (b

1

− b

0

) ≡ −b

0

6≡ 0 mod m

v

. Thus, the assertion follows from Hensel’s Lemma.

Proof of (d). By [Gey94, Theorem A], it suffices to prove the following statement: Suppose char(K) = p > 0. Then there exist no rational function Ψ(Y ) ∈ ˜ K(Y ) and a

0

, a

1

, . . . , a

k

∈ ˜ K with k > 0, a

k

6= 0, and Φ(Y ) = P

k

j=0

a

j

Ψ

pj

(Y ).

Assume the contrary. Then every pole of Φ(Y ) is a pole of Ψ(Y ). Con-

versely, every pole of Ψ(Y ), say, of order d, is a pole of Φ(Y ) of order p

k

d.

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Thus, every pole of Φ(Y ) is of order divisible by p. Hence, every zero of g(Y ) is of order ≥ p. This contradicts (3c).  Lemma 3.5. Let V ⊆ A

n

be an absolutely irreducible affine variety, de- fined over a field K by polynomials f

1

, . . . , f

m

∈ K[X] = K[X

1

, . . . , X

n

].

Set K[x] = K[X]/(f

1

, . . . , f

m

). Let r ≥ 0 and for each 1 ≤ i ≤ r let h

i

∈ K[X, Y

i

] = K[X

1

, . . . , X

n

, Y

i1

, . . . , Y

ini

] be a polynomial such that h

i

(x, Y

i

) ∈ K[x, Y

i

] is absolutely irreducible. Suppose the tuples X, Y

1

, . . . , Y

r

are disjoint. Then the affine variety W defined in A

m+n1+···+nr

by the equations

f

i

(X) = 0, i = 1, . . . , m; h

j

(X, Y

j

) = 0, j = 1, . . . , r,

is an absolutely irreducible variety defined over K of dimension dim(V ) + (n

1

− 1) + · · · + (n

r

− 1).

Proof. For each 1 ≤ i ≤ r put

R

i

= ˜ K[X, Y

1

, . . . , Y

i

]/(f

1

(X), . . . , f

m

(X), h

1

(X, Y

1

), . . . , h

i

(X, Y

i

));

if R

i

is a domain, let Q

i

be its quotient field. Put d

i

= dim(V ) + (n

1

− 1) +

· · · + (n

i

− 1).

We have to show that ˜ K[W ] = R

r

is an integral domain and that trans.deg

K˜

Q

r

= d

r

.

Observe that R

0

= ˜ K[V ] and trans.deg

Q

0

= d

0

. Suppose, by induction on i, that R

i−1

is a domain and trans.deg

K˜

Q

i−1

= d

i−1

. Since h

i

(x, Y

i

) is irreducible over Q

i−1

, the ring Q

i−1

[Y

i

]/(h

i

(x, Y

i

)) is a domain. Hence so is its subring R

i

= R

i−1

[Y

i

]/(h

i

(x, Y

i

)) and Q

i

is the quotient field of Q

i−1

[Y

i

]/(h

i

(x, Y

i

). We conclude that trans.deg

K˜

Q

i

= d

i−1

+ (n

i

− 1) = d

i

.



Definition 3.6. Let K be a field. The patch topology of Val(K) has a basis consisting of all sets

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{v ∈ Val(K) | v(b

1

) > 0, . . . , v(b

k0

) > 0, v(b

k0+1

) ≥ 0, . . . , v(b

k

) ≥ 0}, with v

1

, . . . , b

k

∈ K. Each of these sets is also closed [HJP07, Section 8]. In particular, each of the sets

{v ∈ Val(K) | v(c

1

) = 0, . . . , v(c

m

) = 0}

with c

1

, . . . , c

m

∈ K

×

is open-closed in Val(K). By [HJP07, Prop. 8.2],

Val(K) is profinite under the patch topology. Let B be a closed subset

of Val(K), and m a positive integer. We say B has m-bounded residue

fields if for every v ∈ B the valued field (K, v) has an m-bounded residue

field.

(16)

Lemma 3.7. Let K be a field and B a closed subset of Val(K) with m- bounded residue fields. Let B

0

be an open-closed subset of B. Then there exists b ∈ K such that

(7) B

0

= {v ∈ B | v(b) > 0} and B r B

0

= {v ∈ B | v(1 − b) > 0}.

Proof. First we assume that B

0

is the intersection of B with a basic set of the form (6). By Lemma 3.1(e), for each k

0

+ 1 ≤ j ≤ k the condition v(b

j

) ≥ 0 is equivalent to v(1 − ℘(b

−1j

)) > 0. Thus, we may assume that

B

0

= {v ∈ B | v(b

1

) > 0, . . . , v(b

k

) > 0}.

If k = 0, then B

0

= B and we may take b = 0. Thus, we assume that k ≥ 1.

By Lemma 3.1(d), we may replace b

j

by ℘(b

j

). Hence, by Lemma 3.1(c), we may assume that, for each v ∈ B, either v(b

j

) > 0 or v(1 − b

j

) > 0.

For k = 1, this gives B

0

= {v ∈ B | v(b

1

) > 0} and B r B

0

= {v ∈ B | v(1 − b

1

) > 0}.

Suppose k = 2. Then B

0

= {v ∈ B | v(b

1

) > 0, v(b

2

) > 0} and each v ∈ B r B

0

satisfies either b

1

≡ 1 mod m

v

and b

2

≡ 0 mod m

v

, or b

1

≡ 1 mod m

v

and b

2

≡ 1 mod m

v

, or b

1

≡ 0 mod m

v

and b

2

≡ 1 mod m

v

. Set b = b

21

− b

1

b

2

+ b

22

. Then v(b) > 0 for each v ∈ B

0

and v(1 − b) > 0 for each v ∈ B r B

0

. The quickest way to check the latter relation is to prove that b ≡ 1 mod m

v

by computing b modulo m

v

in each of the above mentioned three alternatives.

If k ≥ 3, we inductively find b

1

∈ K such that

{v ∈ B | v(b

1

) > 0, . . . , v(b

k−1

) > 0} = {v ∈ B | v(b

1

) > 0}.

Then B

0

= {v ∈ B | v(b

1

) > 0, v(b

k

) > 0} and we apply the case k = 2.

In the general case B

0

is compact, and hence it is a finite union of basic subsets of B. The preceding paragraphs prove that the collection of subsets B

0

as in (7) with b ∈ K contains the basic subsets and is closed under finite intersections. Clearly it is also closed under taking complements in B: if B

0

is defined by b then B r B

0

is defined by 1 − b. Therefore this collection is

closed also under finite unions. 

Lemma 3.8. Let K be an infinite field and B a closed subset of Val(K) with m-bounded residue fields. Then there is a b ∈ K

×

such that v(b) > 0 for all v ∈ B.

Proof. First we note that the residue field of the trivial valuation v

0

of K is K itself, hence v

0

is not m-bounded, so v

0

∈ B. Therefore, for each v ∈ B / there is a b

v

∈ K

×

such that v(b

v

) > 0. If v

∈ B is sufficiently close to v, then also v

(b

v

) > 0. Since B is compact, there are b

1

, . . . , b

r

∈ K

×

such that for each v ∈ B there is an i = i(v) with v(b

i

) > 0. By Corollary 3.2, b = Q

i

℘(b

i

) satisfies v(b) ≥ v(b

i(v))

) > 0 for each v ∈ B. 

(17)

4. Block Approximation Theorem

The block approximation theorem is a far reaching generalization of the weak approximation theorem. The latter deals with independent valuations v

1

, . . . , v

n

of a field K and elements a

1

, . . . , a

n

∈ K and c

1

, . . . , c

n

∈ K

×

. It assures the existence of an a ∈ K with v

i

(a − a

i

) > v(c

i

), i = 1, . . . , n. The block approximation theorem considers a family (K

x

, v

x

) of valued fields with K

x

separable algebraic over K indexed by a profinite space X and an affine variety V . The space X is partitioned into finitely many “blocks” X

i

. For each i a point a

i

∈ T

x∈Xi

V

simp

(K

x

) and an element c

i

∈ K

×

are given.

Under certain conditions on this data, the block approximation theorem gives an a ∈ V (K) such that v

x

(a − a

i

) > v

x

(c

i

) for all i and each x ∈ X

i

.

The version of the block approximation theorem we prove assumes that the residue fields of (K

x

, v

x

) are finite with bounded cardinality. The for- mulation of all other conditions uses terminology of [HJP07] which we now recall.

Let G be a profinite group. Denote the set of all closed subgroups of G by Subgr(G). This set is equipped with two topologies, the strict topology and the ´ etale topology. A basic strict open neighborhood of an element H

0

of Subgr(G) is the set {H ∈ Subgr(G) | HN = H

0

N }, where N is an open normal subgroup of G. A basic ´ etale open neighborhood of Subgr(G) is the set Subgr(G

0

), where G

0

is an open subgroup of G. See also [HJP07, §1] and [HJP05, Section 2] for more details.

Now let K be a field. Galois correspondence carries over the strict and the

´etale topologies of Gal(K) to strict and ´etale topologies of SepAlgExt(K).

Thus, a basic strict open neighborhood of an element F

0

of SepAlgExt(K) is the set {F ∈ SepAlgExt(K) | F ∩ L = F

0

∩ L}, where L is a finite Galois extension of K. A basic ´ etale open neighborhood of SepAlgExt(K) is the set SepAlgExt(L), where L is a finite separable extension of K.

A group-structure is a system G = (G, X, G

x

)

x∈X

consisting of a profi- nite group acting continuously (from the right) on a profinite space X and a closed subgroup G

x

of G for each x ∈ X satisfying these conditions:

(1a) The map δ : X → Subgr(G) defined by δ(x) = G

x

is ´etale continuous.

(1b) G

xσ

= G

σx

for all x ∈ X and σ ∈ G (1c) {σ ∈ G | x

σ

= x} ≤ G

x

[HJP07, §2].

A special partition of a group-structure G as above is a data (G

i

, X

i

)

i∈I0

satisfying the following conditions [HJP07, Def. 3.5]:

(2a) I

0

is a finite set disjoint from X.

(2b) X

i

is a nonempty open-closed subset of X, i ∈ I

0

.

(2c) For all i ∈ I

0

and all x ∈ X

i

, G

i

is an open subgroup of G that contains

G

x

.

(18)

(2d) G

i

= {σ ∈ G | X

iσ

= X

i

}, i ∈ I

0

.

(2e) For each i ∈ I

0

let R

i

be a subset of G satisfying G = S

·

ρ∈Ri

G

i

ρ. Then X = S

·

i∈I0

S

·

ρ∈Ri

X

iρ

.

A proper field-valuation-structure is a system K = (K, X, K

x

, v

x

)

x∈X

, where K is a field, X is a profinite space, and for each x ∈ X, K

x

is a sep- arable algebraic extension of K and v

x

is a valuation of K

x

satisfying these conditions:

(3a) Let X = {K

x

∈ SepAlgExt(K) | x ∈ X} and δ : X → X the maps de- fined by δ(x) = K

x

. Then δ is an ´etale homeomorphism. In particular, X is profinite under the ´etale topology.

(3b) K

xσ

= K

xσ

and v

xσ

= v

xσ

for all x ∈ X and σ ∈ Gal(K).

(3c) x

σ

= x implies σ ∈ Gal(K

x

) for all x ∈ X and σ ∈ Gal(K).

(3d) For each finite separable extension L of K let X

L

= {x ∈ X | L ⊆ K

x

}.

Then the map ν

L

: X

L

→ Val(L) defined by ν

L

(x) = v

x

|

L

is continuous.

In particular, Gal(K) = (Gal(K), X, Gal(K

x

))

x∈X

is a group structure.

A block approximation problem for a proper field-valuation-structure K is a data (V, X

i

, L

i

, a

i

, c

i

)

i∈I0

satisfying the following conditions:

(4a) (Gal(L

i

), X

i

)

i∈I0

is a special partition of Gal(K).

(4b) V is an affine absolutely irreducible variety over K.

(4c) a

i

∈ V

simp

(L

i

).

(4d) c

i

∈ K

×

.

A solution of the problem is a point a ∈ V (K) satisfying v

x

(a − a

i

) >

v

x

(c

i

) for all i ∈ I

0

and x ∈ X

i

. We say K satisfies the block approxima- tion condition if each block approximation problem has a solution.

Theorem 4.1 (Residue Bounded Block Approximation Theorem). Let K = (K, X, K

x

, v

x

)

x∈X

be a proper field-valuation-structure. Put X = {K

x

| x ∈ X} and B = {v

x

|

K

| x ∈ X}. Suppose K is PX C, B is m-bounded for some positive integer m, and for all x ∈ X the valued field (K

x

, v

x

) is the Henselian closure of (K, v

x

|

K

). Then K has the block approximation property.

Proof. We let (4) be a block approximation problem for K and divide the rest of the proof into several parts.

Part A: Proof in case V = A

1

. We write a, a

i

rather than a, a

i

, respec- tively.

Part A1: Reduction to the case where a

i

∈ K, for all i ∈ I

0

. Fix i ∈ I

0

.

Let x ∈ X

i

. By Proposition 2.5, K is v

x

-dense in K

x

. Hence, there is

a

ix

∈ K with v

x

(a

ix

− a

i

) > v

x

(c

i

). We consider the open-closed subset

T

ix

= {w ∈ Val(L

i

) | w(a

ix

− a

i

) > w(c

i

)} of Val(L

i

). By (2c), L

i

⊆ K

x

for each x ∈ X

i

. By (3d), the map X

i

→ Val(L

i

) defined by y 7→ v

y

|

Li

(19)

is continuous. Hence, X

ix

= {y ∈ X

i

| v

y

(a

ix

− a

i

) > v

y

(c

i

)}, which is the inverse image of T

ix

in X

i

, is an open-closed neighborhood of x in X

i

. Moreover, X

ix

is Gal(L

i

)-invariant.

Since X

i

is compact, finitely many of these neighborhoods cover X

i

. Hence, there is a partition X

i

= X

i1

∪ · · ·

·

∪ X

· it

of X

i

with X

ij

closed and Gal(L

i

)-invariant and for each 1 ≤ j ≤ t there is some a

ij

∈ K with v

x

(a

ij

− a

i

) > v

x

(c

i

) for all x ∈ X

ij

.

If we find a ∈ K with v

x

(a − a

ij

) > v

x

(c

i

) for all x ∈ X

ij

, with i ∈ I

0

, then v

x

(a − a

i

) > v

x

(c

i

) for all x ∈ X

ij

with i ∈ I

0

. Thus, replacing the family {X

i

| i ∈ I

0

} by its refinement {X

ij

| i, j}, and the elements a

i

by a

ij

, if necessary, we may assume a

i

∈ K.

Part A2: Reduction to the case where L

i

= K. Let B

i

= {v

x

|

K

| x ∈ X

i

}. Since the map X → Val(K) is continuous (by (3d)) and both X and Val(K) are profinite spaces (Definition 3.6), B and each of the sets B

i

is closed in Val(K). If x ∈ X

i

and ρ ∈ Gal(K), then v

xρ

|

K

= v

xρ

|

K

= v

x

, hence B = S

i∈I0

B

i

(by (2e)). Moreover, B = S

·

i∈I0

B

i

. Indeed, assume there are distinct i, j ∈ I

0

and x ∈ X

i

, x

∈ X

j

with v

x

|

K

= v

x

|

K

. Then there exists σ ∈ Gal(K) with (K

xσ

, v

σx

) = (K

x

, v

x

) (because both (K

x

, v

x

) and (K

x

, v

x

) are Henselian closures of (K, v

x

|

K

)). By (3b), K

xσ

= K

x

. Hence, by (3a), x

σ

= x

. Let ρ ∈ R

i

and τ ∈ Gal(L

i

) with σ = τ ρ. Then x

= x

τ ρ

∈ X

iτ ρ

= X

iρ

. This is a contradiction to X = S

·

i∈I0

S

·

ρ∈Ri

X

iρ

(Assumption (2e)). It follows that each of the sets B

i

is open-closed in B.

Thus, we have to find an a ∈ K with v(a − a

i

) > v(c

i

) for all i ∈ I

0

and v ∈ B

i

.

Part A3: Simplifying B

i

. If there is an i with B

i

= B (and hence B

j

= ∅ for j 6= i), take a = a

i

. Thus, we may assume B

i

6= B for each i.

Since B is closed in Val(K) and each B

i

is open-closed in B (Part A2), Lemma 3.7 gives for each i an element d

i

∈ K with B

i

= {v ∈ B | v(d

i

) > 0}

and B r B

i

= {v ∈ B | v(1 − d

i

) > 0}. Since B

i

6= B, we have d

i

6= 0.

Part A4: System of equations. Let ℘ = ℘

m

be the m-bounded operator defined by (1) of Section 3. We write I

0

as {1, 2, . . . , r} and consider the system

(5) ℘( Z − a

i

c

i

) = d

i

Φ(Y

i1

) + Φ(Y

i2

) + Φ(Y

i3

), i = 1, . . . , r

of r equations in 3r + 1 variables Z, Y

ij

, where Φ is the special rational

function defined in Notation 3.3. By Lemma 3.4(d), each of these equations

is absolutely irreducible over the field of rational functions K(Z). Therefore,

by Lemma 3.5, with V = A

1

, (5) defines an absolutely irreducible variety

A ⊆ A

3r+1

over K of dimension 2r + 1.

References

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