Domination in Semitotal-Point Graph
B. BASAVANAGOUD*, S.M.HOSAMANI and S.H.MALGHAN Department of Mathematics,
Karnatak University,Dharwad-580 003, Karnataka, India e-mail*: [email protected]
*Corresponding author.
ABSTRACTS
A set D of vertices in a graph G is a dominating set of G if every vertex not in D is adjacent to atleast one vertex in D. The domination number
(G)
of G is the cardinality of a minimum dominating set of G. The semitotal-point graph T2 (G) of G is the graph whose vertex set is) ( )
( G E G
V
, where two vertices are adjacent if and only if (i) they are adjacent vertices of G or (ii) one is a vertex of G and the other is an edge of G, incident with it. In this paper, some results on domination number of semitotal-point graph are obtained.2000 Mathematics Subject Classification: 05C69.
Keywords: semitotal-point graph, domination number, connected domination number, total domination number.
INTRODUCTION
The graphs considered here are finite, undirected without loops or multiple edges. Any undefined term in this paper may be found in Harary3. Let
G = ( V , E )
be a graph withV = p
andE = q
. In a graph G if deg(v) = 1, then v is called an end vertex or a pendant vertex of G. Eachvertex
v V
dominates every vertex in itss closed neighbourhoodN [v ]
. A setS V
is a dominating set if each vertex in V is dominated by atleast one vertex of S. The dominating number (G )is the smallest cardinality of a dominating set.
A dominating set D of a graph G is a split dominating set if the induced subgraph
V D
is disconnected. Thesplit domination number
s(G )
of G is the minimum cardinality of a split dominating set.A dominating set D of a graph G is a connected dominating set if the induced sub graph
D
is co nne cte d. The connected domination number
c(G )
of G is th e minimu m ca rdin ality of a connected dominating set.A dominating set D is a total dominating set if the induced subgraph
D
has no isolated vertex. The total domination number
t(G )
of a graph G is the minimum cardinality of a total dominating set.A set D of vertices of a graph G is a maximal dominating set of G if D is a dominating set and
V D
is not a dominating set. The maximal domination number
m(G )
of G is the minimum cardinality of a maximal dominating set.A dominating set D of G is a cototal dominating set if the induced subgraph
D
V
has no isolated vertices. The cototal domination number
cot(G )
of G is the minimum cardinility of a cototal dominating set.A dominating set D of vertices in a graph G is a dominating clique if the induced subgraph
D
is a complete graph. The clique domination number)
cl
(G
of G is the minimum cardinality of a dominating clique.A dominating set D of a connected graph G is a path nonsplit dominating set if the induced subgraph
V D
is a pathin G. The path nonsplit domination number
)
pns
(G
is the minimum cardinality of a path nonsplit dominating set.The maximum number of classes of a domatic partition of G is called the domatic number of G and is denoted by d(G). The vertex independence number
)
0
( G
is the maximum cardinality among the independent set of vertices of G.E.Sampatku mar and S. B.
Chikkodimath6 introduced the new graph valued function, namely the semitotal-point graph of a graph.
The semitotal-point graph T2(G) of a graph G is the graph whose vertex set is
V ( G ) E ( G )
, where two vertices are adjacent if and only if (i) they are adjacent vertices of G or (ii) one is a vertex of G and the other is an edge of G, incident with it.In Figure 1, a graph and its semitotal- point graph are shown.
1
2 3 4
1
2 3 4
G : T2(G) :
a
b
c d
a
b
c d
Figure 1
PRELIMINARY RESULTS
We need the following Theorems for our further results.
Theorem A[4]. For any graph G with a pendant vertex
( G ) =
s( G ) .
Theorem B[1]. If G is a connected graph with
p 3
vertices, then.
3 ) 2
( p
t
G
Theorem C[7]. If T is a tree with
p 3
vertices, then
c( T ) = p e .
where e denotes the number of pendant vertices in T.
The orem D[3 ]. For a ny n ontrivial con nected
( p , q )
graph G.
=
=
1 10
0
p
Theorem E[8]. For any connected
( p , q )
graph G
( ) .
)
( d G
G p
p
Theorem F[2]. If G is a graph without iso late d vertice s of orde r p, th en
) 2
( p
G
.Next we give the domination number of semitotal-point graphs of some standard class of graphs.
Proposition 1. For any path PP with
p 2
vertices,
.
= 2 )) (
(
2
P p T
p
Proposition 2. For any cycle CP with
p 3
vertices,
.
= 2 )) (
(
2
C p T
p
Proposition 3. For any wheel WP with
4
p
vertices,1 .
= 2 )) (
(
2
W p T
p
Proposition 4. For any star
K
1, p 1 with 2
p
vertices, ( T
2( K
1,p1)) = 1 .
Proposition 5. For any KP with
p 2
vertices, ( T
2( K
p)) = p 1 .
Proposition 6. If
G = K
p, thenG T
2( G )
.MAIN RESULTS
Theorem 3.1. For any
( p , q )
graph G,))
( ( )
( G T
2G
. The equality holds forG = K
2 orK
p.Proof. We consider the following cases.
Case 1. Let G be a graph without isolated vertices.Then by Theorem F,
) 2
( p
G
. The refo re by def inition o fT
2( G )
,)) 2 (
(
2p q
G
T
. Hence)) ( ( )
( G T
2G
.Case 2. Let G be a graph with isolated vertices of the type
G = H nK
1, where) , (
= p q
H
is any connected graph.Then1
2
( G ) = H nK
T
. By Case 1,) ( )
( H H
. Thereforep n
G
2 ) (
and
p q n
G
T
2
) ) ( (
2
. Hence theresult. Equality can be easily verified for
= K
2G
orK
p.Theorem 3. For any nontrivial tree T,
)
( )) (
( T
2T T
.Proof. Let T be any nontrivial tree. Let
}
, , {
=
1 21
v v v
rD
be a subset of vertex set such tha tdegv
i 2
f or1 i r
a nd} , , {
=
1 22
u u u
sD
wheredegu
i= 1
f ors
i
1
be the subsets ofV (T )
where2
=
1)
( T D D
V
. ClearlyD
1is a minimum dominating set o f T. Therefo rer D T ) =
(
1
. LetD
1 = { v
1 , v
2 , v
r }
and}
, , {
=
1 22
u u u
sD
be the corresponding vertice s of D1 and D2 inT
2( G )
respectively. Letu
1, u
2, u
n E ( T )
andu
nu
u
1 ,
2,
be the corresponding edge vertices inT
2( G )
. For each edgeu
i forn i
1
there exists a vertexv
j D
1
. Clearly ( T ) D
1 D '
1 ( T
2( T ))
. Hence the result.Corollary 1. In a tree if every nonpendant vertex is adjacent to at least one pendant vertex, then
( T
2( T )) = ( T )
Theorem 3.3 For any
( p , q )
graph G,p G T ( )) (
2
. The equality holds forK
pG =
.Proof. We consider the following cases.
Case 1. Suppose G is a connected graph.
The n
( G ) p 1
. There fore by Proposition 5, ( T
2( G )) p 1
.Case 2. Let G be a disconnected graph with n components that is
G = H1
H2
Hn.The n
T
2( G ) = H
1 H
2
H’n. W ee consider the following subcases.Subcase 2.1. Suppose each component
H
i;1 i n
is a complete graph of order2
, then by Ca se 1 ,2 ) ' (
1p
1H
,2 ) ' (
2p
2H
,,2 ) '
(
np
nH
whe re) (
= '
1V H
1p
,p '
2= V ( H
2 )
,p '
n= V ( H
n )
. Then ( T
2( G )) = p n
, where n is the number of components in G. Hence1
<
)) (
( T
2G p
.Subcase 2.2. Suppose the components
H
i;1 i n
, are either complete or other than complete graphs then by Subcase 2.1, ( T
2( G )) < p n < p 1
.The equality is easy to verify forG = K
p.Corollary 2. For a ny con nected
)
,
( p q
graph G, ( T
2( G )) p 1
.Proposition 7. For a ny g raph G ,
0 0 2
( ))
(
T G
.Proof. Follows from Theorem D and Theorem 3.3.
Theorem 3.4 For any
( p , q )
graph G,0 0 2
( )) ) (
(
1
T G
G p
.
Further the equality of lower bound is attained if
G = K
p.Proof. We first consider the lower bound.
Let D be a dominating set of G. Each vertex dominates at most itself and other vertice s o f
(G )
. Hen ce)) ( ) (
(
1 T
2G
G p
.If
G = K
p, then by The ore m 3.3,p
K T (
p)) = (
2
. Hence the lower bound is attained.Th e up per boun d fo llows from the Proposition 7.
Theorem 3.5 For any
( p , q )
graph G,p
G T G
p
0( ) (
2( )
.Further the equality of lower bound is attained if
G = P
porC
p.Proof. We first consider the lower bound.
It is obvious that fo r any graph G ,
))
( ( )
(
20
G T G
p
. For equality,we consider the following cases:Case 1. If
G = P
p forp 2
vertices then
= 2 )
0
( P
pp
. Thereforep
0( G ) =
2 .
2 =
p p
p
By Pro position 1,
= 2 )) (
(
2p
P T
p
. Hence the equality..Case 2. If
G = C
pp 3
vertices then2 .
= )
0
(
C
p p
Therefore
p
0( G ) = .
= 2
2
p p
p
By Proposition 2,
= 2 )) (
(
2p
C T
p
The upper bound follows from Theorem 3.3.
Corolla ry 3 . Fo r any grap h G ,
)).
( ( )
(
20
G T G
The orem 3 .6 For a ny g raph G ,
)
( ))
(
( T
2G diam G
.Proof. Let A = {e1, e2,et } be the set of edges which constitutes the longest path between any two vertices of G such that
) (
= diam G
A
. We consider the following cases:Case 1. If G contains only one edge then
3 2
( G ) = C
T
. Therefore ( T
2( G )) = 1 = A
. Case 2. Letu
1, u
2,
, u
m E ( G )
andu
u
1 ,
2,
, u
mbe the corresponding edge vertices ofT
2( G )
. Letv
1, v
2,
,, v
n V ( G )
andv
1 , v
2,
, v
nbe the correspondingvertices of
T
2( G )
. Since all the edge vertices are incident withV ( T
2( G )) u
m
, thereforeA D u G T V G
T ( )) ( ( ))
m =
(
2 2
.Hence
( T
2( G )) diam ( G )
. Theorem 3.7 For any tree T,) ( )) (
( T
2T
sT
.Proof. By Theorem 3.2 and Theorem A we get the required result.
Theorem 3.8 For any connected graph G of order atleast three,
( T
2( G ))
t( G )
. Proof. By Corollary 2 and Theorem we get the required result.Theorem 3.9 For any connected graph G,
)
( )) (
( T
2G
mG
where
m(G )
is the maximal domination number of G.Proof. Let G be any connected graph.
Suppose
( T
2( G )) >
m( G )
. Then eachu
i,1 i m
of a corresponding edge vertex of G inT
2( G )
will be adjacent to at least two vertices ofV ( T
2( G ) v
n )
in)
2
( G
T
, wherev
n is the corresponding vertex set of G inT
2( G )
. Therefore by taking alternate verticesv
j,1 j n
of)
2
( G
T
, the setv
j, j = 1,2,...., n
will be a dominating set ofT
2( G )
. Since eachu
i,m i
1
is an independent vertex in)
2
( G
T
, then the setu
i, i = 1,2,...., n
is a maxiaml independent set. Since everymaximal independent set is a minimal dominating set, the refo re
D G T V u
D =
m= (
2( ))
is also a dominating set o fT
2( G )
, Th us) (
<
)) (
( T
2G
mG
, a contradiction.Theorem 3.10 For any tree T of order
2
p
vertices,
c( T ) ( T
2( T ))
.Proof. Let T be a tree of order
p 2
. Let}
, , , {
= v
1v
2v
rD
be such th at2 ) ( v
i
deg
for1 i r
. Then inT
2( G )
degree of eachu
i and eachv
r will become twice. Therefore, eachv
i inT
2( G )
will be a minimal dominating set. Thereforee p T
T ( )) = (
2
where e is the number of pendant vertices in T. Hence by Theorem C,
c( T ) ( T
2( T )
.Theorem 3.11 For any
( p , q )
graph G,1
= )) ( ( T
2G
cot if and only ifG = K
1,p1. Proof. IfG = K
1,p1, thendeg v
i = 2 degv
i wherev
i is the corresponding vertex ofv
i of G inT
2( G )
. Each component of)
2
( G
T
will be a triangle and each triangle will have one common vertex which is adjacent to all other vertices ofT
2( G )
. Therefore
cot( T
2( G )) = 1
.Conversely, suppose
cot( T
2( G )) = 1
and1
K
1, pG
, then there exists a vertex of1
= )) (
(
2
T G p
. Let u be a vertex of degreep 1
, then all other vertices of)
2
( G
T
are adjacent to u. But inT
2( G )
, this is the only case when G is a star, oth erwise ( T
2( G )) < p 1
. Th us2 )) ( ( T
2G
, a contradiction.Theorem 3.12 For any
( p , q )
graph G,1
= ) )(
( T
2G
cl if and only ifG = K
1,p1. Proof. Proof is similar to the Theorem 3.11.The orem 3.1 3 Fo r any grap h G ,
)
( )) (
( T
2G
cotG
.Proof. Since
t( G )
cot( G )
, therefore by Theorem 3.8, we get the required result.Theorem 3.14 For any
( p , q )
graph G,p
G
m
( T
2( ))
.Further equality holds if and only if
K
pG =
.Proof . For any graph G, it is easy to
observe that
m( T
2( G )) p
. SupposeK
pG =
, then
m( G ) = p =
m( T
2( G ))
. Con versely, let
m( T
2( G )) = p
a ndK
pG
. If G contains an isolated vertex then
m( T
2( G )) < p
. So consider a graph G without isolated vertices. Then there exists at least one vertex with ( G ) 2
which will be present in both dominating
set and maximal dominating set of T
2( G )
.
Therefore ( T
2( G )) < p
, a contradiction.
Hence
G = K
p.Proposition 7. For any path
P
p withp 2
vertices,
pns( T
2( G )) = q
where q is the number of edges inP
p.Proof. Let G be a path with
p 2
vertices.Let
u
m;1 m q
be the corresponding edge vertices inT
2( G )
andv
n1 n p
is the corresponding vertices of G in)
2
( G T
, then
pns( T
2( G ) = V ( T
2( G ) u
m ) u
m= = q
.The orem 3.1 5 Fo r any grap h G ,
))
( ( )
( G T
2G
d
where d(G ) is the domatic number of G.Proof. For any graph G,
d ( G ) ( G ) 1
. Let u be a vertex of minimum degree in G, then degree of the corresponding vertexu
i inT
2( G )
will be twice. Also by Theorem 3.3, ( T
2( G )) p
. Therefore)) ( ( )
( G T
2G
d
. IfG = K
p, then)) ( (
=
= )
( K p T
2G
d
p
.Hence the equalityholds.
Theorem 3.16
For any graph G,
( ( ))
)
( T
2G
G p
p
.Proof. Follows from Theorem E and Theorem 3.15.
In the next Th eore m we pro ve the
Nordhaus-Gaddum type results.
Theorem 3.17 For any connected
( p , q )
graph G(i)
( T
2( G )) ( T
2( G )) 2 p 1
(ii) ( T
2( G )). ( T
2( G )) p ( p 1)
. Proof. B y u sing Propo sition 5 a nd Proposition 6 we get the required result.ACKNOWLEDGEMENT
This research was supported by the University Grants Commission, New Delhi,India-No.F.4-3/2006(BSR)/7-101/
2007(BSR) dated: September 2009.
This research was supported by the University Grants Commission, New Delhi,India-No.F.FIP/ Plan/KAKA047TF02 dated:October 8, 2009.
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