Journal of Inequalities and Applications Volume 2009, Article ID 851360,10pages doi:10.1155/2009/851360
Research Article
Some New Hilbert’s Type Inequalities
Chang-Jian Zhao
1and Wing-Sum Cheung
2 1Department of Information and Mathematics Sciences, College of Science,China Jiliang University, Hangzhou 310018, China
2Department of Mathematics, The University of Hong Kong, Pokfulam Road, Hong Kong
Correspondence should be addressed to Chang-Jian Zhao,[email protected]
Received 25 December 2008; Accepted 24 April 2009
Recommended by Peter Pang
Some new inequalities similar to Hilbert’s type inequality involving series of nonnegative terms are established.
Copyrightq2009 C.-J. Zhao and W.-S. Cheung. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
1. Introduction
In recent years, several authors 1–10 have given considerable attention to Hilbert’s type inequalities and their various generalizations. In particular, in1, Pachpatte proved some new inequalities similar to Hilbert’s inequality11, page 226involving series of nonnegative terms. The main purpose of this paper is to establish their general forms.
2. Main Results
In1, Pachpatte established the following inequality involving series of nonnegative terms.
Theorem A. Letp≥1, q≥1,and let{am}and{bn}be two nonnegative sequences of real numbers defined form 1, . . . , k,andn 1, . . . , r, wherek, r are natural numbers. LetAm ms1asand
Bnnt1bt. Then
k
m1
r
n1
ApmBqn
mn ≤C
p, q, k, r
k
m1
k−m1amApm−1
2 1/2 ×
r
n1
r−n1bnBqn−1
2 1/2
,
where
Cp, q, k, r 1
2pqkr
1/2. 2.2
We first establish the following general form of inequality2.1.
Theorem 2.1. Letp ≥ 1, q ≥ 1, t > 0,and 1/α1/β 1, α > 1. Let{am1,...,mn},and{bn1,...,nn} be positive sequences of real numbers defined for mi 1,2, . . . , ki, and ni 1,2, . . . , ri, where
ki, ri i 1, . . . , n are natural numbers. Let Am1,...,mn m1
s11· · ·
mn
sn1as1,...,sn, and Bn1,...,nn n1
t11· · ·
nn
tn1bt1,...,tn.Then
k1
m11
· · · kn
mn1
r1
n11
· · ·rn
nn1
αβt1/βAp m1,...,mnB
q n1,...,nn m1· · ·mnβn1· · ·nnαt
≤Lk1, . . . , kn, r1, . . . , rn, p, q, α, β
×
k1
m11
· · · kn
mn1
n
j1
kj−mj1am1,...,mnA
p−1
m1,...,mn
β 1/β
× ⎛ ⎝r1
n11
· · ·rn
nn1
n
j1
rj−nj1bn1,...,nnB
q−1
n1,...,nn α⎞
⎠ 1/α
,
2.3
where
Lk1, . . . , kn, r1, . . . , rn, p, q, α, βpqk1· · ·kn1/αr1· · ·rn1/β. 2.4
Proof. By using the following inequalitysee12:
n
1
m11
· · · nn
mn1 zm1,...,mn
p
≤pn1
m11
, . . . ,nn
mn1 zm1,...,mn
m
1
k11
· · ·mn
kn1 zk1,...,kn
p−1
, 2.5
wherep≥1 is a constant, andzm1,...,mn ≥0, mi1,2, . . . , ki,i1,2, . . . , n, we obtain
Apm1,...,mn ≤p
m1
s11
· · ·mn
sn1
as1,...,snA
p−1
s1,...,sn. 2.6
Similarly, we have
Bnq1,...,nn ≤q
n1
t11
· · ·nn
tn1
bt1,...,tnB
q−1
From2.6and2.7, using H ¨older’s inequality13and the elementary inequality:
a1/αb1/β≤ a
αt1/β
t1/αb
β , 2.8
where 1/α1/β1, α >1, b >0, a >0, andt >0,we have
Apmi,...,mnB
q
ni,...,nn ≤pq m
1
s11
· · ·mn
sn1
as1,...,snA
p−1
s1,...,sn
n1
t11
· · ·nn
tn1 bt1,...,tnB
q−1
t1,...,tn
≤pqm1, . . . , mn1/α
m
1
s11
· · ·mn
sn1
as1,...,snA
p−1
s1,...,sn β 1/β
×n1, . . . , nn1/β
n
1
t11
· · ·nn
tn1
bt1,...,tnB
q−1
t1,...,tn α 1/α
≤pq
m1· · ·mn
αt1/β
n1· · ·nnt1/α
β
m1
s11
· · ·mn
sn1
as1,...,snA
p−1
s1,...,sn β 1/β
× n
1
t11 . . .nn
tn1
bt1,...,tnB
q−1
t1,...,tn α 1/α
.
2.9
Dividing both sides of2.9bym1· · ·mnβn1· · ·nnαt/αβt1/β,summing up overnifrom
1 tori i1,2, . . . , nfirst, then summing up overmifrom 1 toki i1,2, . . . , n, using again
H ¨older’s inequality, then interchanging the order of summation, we obtain
k1
m11
· · · kn
mn1
r1
n11
· · ·rn
nn1
αβt1/βAp m1,...,mnB
q n1,...,nn m1· · ·mnβn1· · ·nnαt
≤pq
⎧ ⎨ ⎩
k1
m11
· · · kn
mn1
m
1
s11
· · ·mn
sn1
as1,...,snA
p−1
s1,...,sn β 1/β
⎫ ⎬ ⎭
× ⎧ ⎨ ⎩
r1
n11
· · ·rn
nn1 n
1
t11
· · ·nn
tn1
bt1,...,tnB
q−1
t1,...,tn α 1/α
⎫ ⎬ ⎭
≤pqk1· · ·kn1/α k
1
m11
· · · kn
mn1 m
1
s11
· · ·mn
sn1
as1,...,snA
p−1
s1,...,sn
β 1/β
×r1· · ·rn1/β
k
1
n11
· · ·rn
nn1 n
1
t11
· · ·nn
tn1
bt1,...,tnB
q−1
t1,...,tn
Lk1, . . . , kn, r1, . . . , rn, p, q, α, β
× k
1
s11
· · ·kn
sn1
as1,...,snA
p−1
s1,...,sn
βk1
m1s1
· · · kn
mnsn 1
1/β
× r
1
t11
· · ·rn
tn1
bt1,...,tnB
q−1
t1,...,tn
αr1
n1t1
· · · rn
nntn 1
1/α
Lk1, . . . , kn, r1, . . . , rn, p, q, α, β
× ⎧ ⎨ ⎩
k1
s11
· · ·kn
sn1
n
j1
kj−sj1as1,...,snA
p−1
s1,...,sn β
⎫ ⎬ ⎭
1/β
× ⎧ ⎨ ⎩
r1
t11
· · ·rn
tn1
n
j1
rj−tj1bt1,...,tnB
q−1
t1,...,tn α⎫⎬
⎭ 1/α
Lk1, . . . , kn, r1, . . . , rn, p, q, α, β
× ⎧ ⎨ ⎩
k1
m11
· · · kn
mn1
n
j1
kj−mj1am1,...,mnA
p−1
m1,...,mn β⎫⎬
⎭ 1/β
× ⎧ ⎨ ⎩
r1
n11
· · ·rn
nn1
n
j1
rj−nj1bn1,...,nnB
q−1
n1,...,nn α
⎫ ⎬ ⎭
1/α
.
2.10
This completes the proof.
Remark 2.2. Takingαβnj2,2.3becomes
k1
m1
k2
m21
r
1
n11
r2
n21
Apm1,m2B
q n1,n2 m1m2t−1/2n1n2t1/2
≤ 1
2pq
k1k2r1r2 k
1
m1
k2
m21
k1−m11k2−m21
am1,m2A
p−1
m1,m2
2 1/2
× r
1
n1
r2
n21
r1−n11r2−n21
bn1,n2B
p−1
n1,n2
2 1/2
.
2.11
Takingt1,and changing{am1,m2},{bn1,n2},{Am1,m2},and{Bn1,n2}into{am},{bn},{Am},and
{Bn},respectively, and with suitable changes,2.11reduces to Pachpatte1, inequality1.
Theorem B. Let {am},{bn}, Am, Bn be as defined in Theorem A. Let {pm}and {qn} be positive sequences form1, . . . , k,andn1, . . . , r,wherek, r are natural numbers. DefinePm ms1ps, and Qn nt1qt. Let φ and ψ be real-valued, nonnegative, convex, submultiplicative functions defined onR 0,∞.Then
k
m1
r
n1
φAmψBn
mn ≤Mk, r
k
m1
k−m1
pmφ
a
m
pm
2 1/2
× r
n1
r−n1
qnφ
b
n
qn
2 1/2
,
2.12
where
Mk, r 1 2
k
m1 φP
m
Pm
2 1/2r
n1 φQ
n
Qn
2 1/2
. 2.13
Inequality2.12can also be generalized to the following general form.
Theorem 2.3. Let{am1,...,mn},{bn1,...,nn},α, β, t, Am1,...,mn,andBn1,...,nn be as defined inTheorem 2.1. Let{pm1,...,mn}and {qn1,...,nn}be positive sequences formi 1,2, . . . , ki,and ni 1,2, . . . , ri i 1,2, . . . , n. DefinePm1,...,mn
m1
s11· · ·
mn
sn1ps1,...,sn,andQn1,...,nn n1
t11· · ·
nn
tn1qt1,...,tn.Letφ
and ψ be real-valued, nonnegative, convex, submultiplicative functions defined onR 0,∞.
Then
k1
m11
· · · kn
mn1
r1
n11
· · ·rn
nn1
αβt1/βφA
m1,...,mnψBn1,...,nn m1· · ·mnβn1· · ·nnαt
≤Mk1, . . . , kn, r1, . . . , rn, α, β
× ⎧ ⎨ ⎩
k1
m11
· · · kn
mn1
n
j1
kj−mj1pm1,...,mnφ a
m1,...,mn pm1,...,mn
β⎫⎬ ⎭
1/β
× ⎧ ⎨ ⎩
r1
n11
· · ·rn
nn1
n
j1
rj−nj1qn1,...,nnψa b
n1,...,nn qn1,...,mn
α⎫⎬
⎭ 1/α
,
2.14
where
Mk1, . . . , kn, r1, . . . , rn, α, β
k
1
m11
· · · kn
mn1 φP
m1,...,mn Pm1,...,mn
α 1/αr1
n11
· · ·rn
nn1 ψQ
n1,...,nn Qn1,...,nn
β 1/β
Proof. By the hypotheses, Jensen’s inequality, and H ¨older’s inequality, we obtain
φAm1,...,mn φ
Pm1,...,mn m1
s11. . .
mn
sn1ps1,...,sn
as1,...,sn/ps1,...,sn m1
s11· · ·
mn
sn1ps1,...,sn
≤φPm1,...,mnφ m1
s11· · ·
mn
sn1ps1,···,sn
as1,...,sn/ps1,...,sn m1
s11· · ·
mn
sn1ps1,...,sn
≤ φPm1,...,mn Pm1,...,mn
m1
s11
· · ·mn
sn1 ps1,...,snφ
a
s1,...,sn ps1,...,sn
≤ φPm1,...,mn Pm1,...,mn
m1· · ·mn1/α
m
1
s11
· · ·mn
sn1
ps1,...,snφ a
s1,...,sn ps1,...,sn
β 1/β
.
2.16
Similarly,
φBn1,...,nn≤
φQn1,...,nn Qn1,...,nn
n1· · ·nn1/β n
1
n11
· · ·nn
nn1
qt1,...,tnψ b
t1,...,tn qt1,...,tn
α 1/α
. 2.17
By2.16and2.17, and using the elementary inequality:
a1/αb1/β≤ a
αt1/β
t1/αb
β , 2.18
where 1/α1/β1, α >1, b >0, a >0,andt >0,we have
φAm1,...,mnφBn1,...,nn≤
m1· · ·mn
αt1/β
n1· · ·nnt1/α
β
× φPm1,...,mn Pm1,...,mn
m
1
s11
· · ·mn
sn1
ps1,...,snφ a
s1,...,sn ps1,...,sn
β 1/β
× φQn1,...,nn Qn1,...,nn
n
1
t11 . . .nn
tn1
qt1,...,tnψ b
t1,...,tn qt1,...,tn
α 1/α
.
Dividing both sides of2.19bym1· · ·mnβn1· · ·nnαt/αβt1/β,and summing up overni
from 1 tori i1,2, . . . , nfirst, then summing up overmifrom 1 toki i1,2, . . . , n, using again inverse H ¨older’s inequality, and then interchanging the order of summation, we obtain
k1
m11
· · · kn
mn1
r1
n11
· · ·rn
nn1
αβt1/βφAm
1,...,mnψBn1,...,nn m1. . . mnβn1. . . nnαt
≤ k1
m11 . . . kn
mn1 ⎛
⎝φPm1,...,mn Pm1,...,mn
m
1
s11
· · ·mn
sn1
ps1,...,snφ a
s1,...,sn ps1,...,sn
β 1/β⎞
⎠
×r1
n11
· · ·rn
nn1 ⎛
⎝φQn1,...,nn Qn1,...,nn
n
1
n11
· · ·nn
nn1
qt1,...,tnψ b
t1,...,tn qt1,...,tn
α 1/α⎞
⎠
≤
k
1
m11
· · · kn
mn1 φP
m1,...,mn Pm1,...,mn
α 1/α
×
k
1
m11
· · · kn
mn1 m
1
s11
· · ·mn
sn1
ps1,...,snφ a
s1,...,sn ps1,...,sn
β 1/β
× r
1
n11
· · ·rn
nn1 ψQ
n1,...,nn Qn1,...,nn
β 1/β
× r
1
n11
· · ·rn
nn1 n
1
t11
· · ·nn
tn1
qt1,...,tnψ b
t1,...,tn qt1,...,tn
α 1/α
Mk1, . . . , kn, r1, . . . , rn, α, β
× ⎧ ⎨ ⎩
k1
m11
· · · kn
mn1
n
j1
kj−mj1pm1,...,mnφ a
m1,...,mn pm1,...,mn
β⎫⎬
⎭ 1/β
× ⎧ ⎨ ⎩
r1
n11
· · ·rn
nn1
n
j1
rj−nj1qn1,...,nnψ b
n1,...,nn qn1,...,mn
α⎫⎬
⎭ 1/α
.
2.20
Remark 2.4. Takingαβnj2,2.14becomes
k1
m1
k2
m21
r
1
n11
r2
n21
φAm1,m2ψBn1,n2 m1m2t−1/2n1n2t1/2
≤Mk1, k2, r1, r2
× k
1
m1
k2
m21
k1−m11k2−m21
pm1,m2φ
a
m1,...,mn pm1,...,mn
2 1/2
× r
1
n1
r2
n21
r1−n11r2−n21
qn1,n2ψ
b
n1,...,nn qn1,...,nn
2 1/2
,
2.21
where
Mk1, k2, r1, r2
k
1
m11
k2
m21
φP
m1,m2 Pm1,m2
2 1/2r1
n11
r2
n21
ψQ
n1,n2 Qn1,n2
2 1/2
. 2.22
Takingt1,and changing{am1,m2},{bn1,n2},{Am1,m2},and{Bn1,n2}into{am},{bn},{Am},and
{Bn},respectively, and with suitable changes,2.21reduces to Pachpatte1, Inequality7.
Theorem 2.5. Let{am1,...,mn},{bn1,...,nn},{pm1,...,mn},{qn1,...,nn},Pm1,...,mn,andQn1,...,nn,α, β, t,be as
defined inTheorem 2.3. Define
Am1,...,mn 1 Pm1,...,mn
m1
s11
· · ·mn
sn1
ps1,...,snas1,...,sn,
Bn1,...,n2
1 Qn1,...,nn
n1
t11
· · ·nn
tn1
qt1,...,tnbt1,...,tn,
2.23
formi 1,2, . . . , ki,and ni 1,2, . . . , ri i 1,2, . . . , n,where ki, ri i 1, . . . , n are natural numbers. Letφandψbe real-valued, nonnegative, convex functions defined onR 0,∞.Then
k1
m11
· · · kn
mn1
r1
n11
· · ·rn
nn1
αβt1/βP
m1,...,mnQn1,...,nnφAm1,...,mnψBn1,...,nn m1· · ·mnβn1· · ·nnαt
k1· · ·kn1/αr1· · ·rn1/β
× ⎧ ⎨ ⎩
k1
m11
· · · kn
mn1
n
j1
kj−mj1pm1,...,mnφam1,...,mn β⎫⎬
⎭ 1/β
× ⎧ ⎨ ⎩
r1
n11
· · ·rn
nn1
n
j1
rj−nj1qn1,...,nnψbn1,...,nn α
⎫ ⎬ ⎭
1/α
.
Proof. By the hypotheses, Jensen’s inequality, and H ¨older’s inequality, it is easy to observe that
φAm1,...,mn φ
1 Pm1,...,mn
m1
s11
· · ·mn
sn1
ps1,...,snas1,...,sn
≤ P 1
m1,...,mn
m1
s11
· · ·mn
sn1
ps1,...,snφas1,...,sn
≤ P 1
m1,...,mn
m1· · ·mn1/α
m
1
s11
· · ·mn
sn1
ps1,...,snφas1,...,sn β 1/β,
2.25
ψBn1,...,nn ψ
1 Qn1,...,nn
n1
t11
· · ·nn
tn1
qt1,...,tnbt1,...,tn
≤ Q 1
n1,...,nn
n1
t11
· · ·nn
tn1
qt1,...,tnψbt1,...,tn
≤ Q 1
n1,...,nn
n1· · ·nn1/β
n
1
t11
· · ·nn
tn1
qt1,...,tnψbt1,...,tn α 1/α.
2.26
Proceeding now much as in the proof of Theorems2.1and2.3, and with suitable modifica-tions, it is not hard to arrive at the desired inequality. The details are omitted here.
Remark 2.6. In the special case wherej1, t1, αβ2,andn1,Theorem 2.5reduces to the following result.
Theorem C. Let {am},{bn},{pm},{qn}, Pm, Qn be as defined in Theorem B. Define Am
1/Pmms1psas,andBn 1/Qnnt1qtbt form 1, . . . , k,andn 1, . . . , r, wherek, r are natural numbers. Letφandψbe real-valued, nonnegative, convex functions defined onR 0,∞.
Then
k
m1
r
n1
PmQnφAmψBn
mn ≤
1 2kr
1/2
k
m1
k−m1pmφam2
1/2
× r
n1
r−n1qnψbn2
1/2
.
2.27
This is the new inequality of Pachpatte in [1, Theorem 4].
Remark 2.7. Takingj 1, t1, pm1, qn1, αβ2,andn1 inTheorem 2.5, and in view
Theorem D. Let{am},{bn}be as defined in Theorem A. DefineAm 1/mms1as,andBn
1/nnt1bt,form 1, . . . , k,andn 1, . . . , r, wherek, r are natural numbers. Letφ andψ be real-valued, nonnegative, convex functions defined onR 0,∞.Then
k
m1
r
n1
mn
mnφAmψBn≤ 1 2kr
1/2
k
m1
k−m1φam2
1/2
× r
n1
r−n1ψbn2
1/2
.
2.28
This is the new inequality of Pachpatte in [1, Theorem 3].
Acknowledgments
Research is supported by Zhejiang Provincial Natural Science Foundation of ChinaY605065, Foundation of the Education Department of Zhejiang Province of China20050392. Research is partially supported by the Research Grants Council of the Hong Kong SAR, ChinaProject no. HKU7016/07Pand a HKU Seed Grant forBasic Research.
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