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Journal of Inequalities and Applications Volume 2009, Article ID 851360,10pages doi:10.1155/2009/851360

Research Article

Some New Hilbert’s Type Inequalities

Chang-Jian Zhao

1

and Wing-Sum Cheung

2 1Department of Information and Mathematics Sciences, College of Science,

China Jiliang University, Hangzhou 310018, China

2Department of Mathematics, The University of Hong Kong, Pokfulam Road, Hong Kong

Correspondence should be addressed to Chang-Jian Zhao,[email protected]

Received 25 December 2008; Accepted 24 April 2009

Recommended by Peter Pang

Some new inequalities similar to Hilbert’s type inequality involving series of nonnegative terms are established.

Copyrightq2009 C.-J. Zhao and W.-S. Cheung. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

In recent years, several authors 1–10 have given considerable attention to Hilbert’s type inequalities and their various generalizations. In particular, in1, Pachpatte proved some new inequalities similar to Hilbert’s inequality11, page 226involving series of nonnegative terms. The main purpose of this paper is to establish their general forms.

2. Main Results

In1, Pachpatte established the following inequality involving series of nonnegative terms.

Theorem A. Letp≥1, q≥1,and let{am}and{bn}be two nonnegative sequences of real numbers defined form 1, . . . , k,andn 1, . . . , r, wherek, r are natural numbers. LetAm ms1asand

Bnnt1bt. Then

k

m1

r

n1

ApmBqn

mnC

p, q, k, r

k

m1

km1amApm−1

2 1/2 ×

r

n1

rn1bnBqn−1

2 1/2

,

(2)

where

Cp, q, k, r 1

2pqkr

1/2. 2.2

We first establish the following general form of inequality2.1.

Theorem 2.1. Letp ≥ 1, q ≥ 1, t > 0,and 11 1, α > 1. Let{am1,...,mn},and{bn1,...,nn} be positive sequences of real numbers defined for mi 1,2, . . . , ki, and ni 1,2, . . . , ri, where

ki, ri i 1, . . . , n are natural numbers. Let Am1,...,mn m1

s11· · ·

mn

sn1as1,...,sn, and Bn1,...,nn n1

t11· · ·

nn

tn1bt1,...,tn.Then

k1

m11

· · · kn

mn1

r1

n11

· · ·rn

nn1

αβt1Ap m1,...,mnB

q n1,...,nn m1· · ·mnβn1· · ·nnαt

Lk1, . . . , kn, r1, . . . , rn, p, q, α, β

×

k1

m11

· · · kn

mn1

n

j1

kjmj1am1,...,mnA

p−1

m1,...,mn

β 1

× ⎛ ⎝r1

n11

· · ·rn

nn1

n

j1

rjnj1bn1,...,nnB

q−1

n1,...,nn α

⎠ 1

,

2.3

where

Lk1, . . . , kn, r1, . . . , rn, p, q, α, βpqk1· · ·kn1/αr1· · ·rn1/β. 2.4

Proof. By using the following inequalitysee12:

n

1

m11

· · · nn

mn1 zm1,...,mn

p

pn1

m11

, . . . ,nn

mn1 zm1,...,mn

m

1

k11

· · ·mn

kn1 zk1,...,kn

p−1

, 2.5

wherep≥1 is a constant, andzm1,...,mn ≥0, mi1,2, . . . , ki,i1,2, . . . , n, we obtain

Apm1,...,mnp

m1

s11

· · ·mn

sn1

as1,...,snA

p−1

s1,...,sn. 2.6

Similarly, we have

Bnq1,...,nnq

n1

t11

· · ·nn

tn1

bt1,...,tnB

q−1

(3)

From2.6and2.7, using H ¨older’s inequality13and the elementary inequality:

a1b1 a

αt1

t1b

β , 2.8

where 111, α >1, b >0, a >0, andt >0,we have

Apmi,...,mnB

q

ni,...,nnpq m

1

s11

· · ·mn

sn1

as1,...,snA

p−1

s1,...,sn

n1

t11

· · ·nn

tn1 bt1,...,tnB

q−1

t1,...,tn

pqm1, . . . , mn1

m

1

s11

· · ·mn

sn1

as1,...,snA

p−1

s1,...,sn β 1

×n1, . . . , nn1

n

1

t11

· · ·nn

tn1

bt1,...,tnB

q−1

t1,...,tn α 1

pq

m1· · ·mn

αt1

n1· · ·nnt1

β

m1

s11

· · ·mn

sn1

as1,...,snA

p−1

s1,...,sn β 1

× n

1

t11 . . .nn

tn1

bt1,...,tnB

q−1

t1,...,tn α 1

.

2.9

Dividing both sides of2.9bym1· · ·mnβn1· · ·nnαt/αβt1/β,summing up overnifrom

1 tori i1,2, . . . , nfirst, then summing up overmifrom 1 toki i1,2, . . . , n, using again

H ¨older’s inequality, then interchanging the order of summation, we obtain

k1

m11

· · · kn

mn1

r1

n11

· · ·rn

nn1

αβt1Ap m1,...,mnB

q n1,...,nn m1· · ·mnβn1· · ·nnαt

pq

⎧ ⎨ ⎩

k1

m11

· · · kn

mn1

m

1

s11

· · ·mn

sn1

as1,...,snA

p−1

s1,...,sn β 1

⎫ ⎬ ⎭

× ⎧ ⎨ ⎩

r1

n11

· · ·rn

nn1 n

1

t11

· · ·nn

tn1

bt1,...,tnB

q−1

t1,...,tn α 1

⎫ ⎬ ⎭

pqk1· · ·kn1 k

1

m11

· · · kn

mn1 m

1

s11

· · ·mn

sn1

as1,...,snA

p−1

s1,...,sn

β 1

×r1· · ·rn1

k

1

n11

· · ·rn

nn1 n

1

t11

· · ·nn

tn1

bt1,...,tnB

q−1

t1,...,tn

(4)

Lk1, . . . , kn, r1, . . . , rn, p, q, α, β

× k

1

s11

· · ·kn

sn1

as1,...,snA

p−1

s1,...,sn

βk1

m1s1

· · · kn

mnsn 1

1

× r

1

t11

· · ·rn

tn1

bt1,...,tnB

q−1

t1,...,tn

αr1

n1t1

· · · rn

nntn 1

1

Lk1, . . . , kn, r1, . . . , rn, p, q, α, β

× ⎧ ⎨ ⎩

k1

s11

· · ·kn

sn1

n

j1

kjsj1as1,...,snA

p−1

s1,...,sn β

⎫ ⎬ ⎭

1

× ⎧ ⎨ ⎩

r1

t11

· · ·rn

tn1

n

j1

rjtj1bt1,...,tnB

q−1

t1,...,tn α⎫⎬

⎭ 1

Lk1, . . . , kn, r1, . . . , rn, p, q, α, β

× ⎧ ⎨ ⎩

k1

m11

· · · kn

mn1

n

j1

kjmj1am1,...,mnA

p−1

m1,...,mn β⎫⎬

⎭ 1

× ⎧ ⎨ ⎩

r1

n11

· · ·rn

nn1

n

j1

rjnj1bn1,...,nnB

q−1

n1,...,nn α

⎫ ⎬ ⎭

1

.

2.10

This completes the proof.

Remark 2.2. Takingαβnj2,2.3becomes

k1

m1

k2

m21

r

1

n11

r2

n21

Apm1,m2B

q n1,n2 m1m2t−1/2n1n2t1/2

≤ 1

2pq

k1k2r1r2 k

1

m1

k2

m21

k1−m11k2−m21

am1,m2A

p−1

m1,m2

2 1/2

× r

1

n1

r2

n21

r1−n11r2−n21

bn1,n2B

p−1

n1,n2

2 1/2

.

2.11

Takingt1,and changing{am1,m2},{bn1,n2},{Am1,m2},and{Bn1,n2}into{am},{bn},{Am},and

{Bn},respectively, and with suitable changes,2.11reduces to Pachpatte1, inequality1.

(5)

Theorem B. Let {am},{bn}, Am, Bn be as defined in Theorem A. Let {pm}and {qn} be positive sequences form1, . . . , k,andn1, . . . , r,wherek, r are natural numbers. DefinePm ms1ps, and Qn nt1qt. Let φ and ψ be real-valued, nonnegative, convex, submultiplicative functions defined onR 0,.Then

k

m1

r

n1

φAmψBn

mnMk, r

k

m1

km1

pmφ

a

m

pm

2 1/2

× r

n1

rn1

qnφ

b

n

qn

2 1/2

,

2.12

where

Mk, r 1 2

k

m1 φP

m

Pm

2 1/2r

n1 φQ

n

Qn

2 1/2

. 2.13

Inequality2.12can also be generalized to the following general form.

Theorem 2.3. Let{am1,...,mn},{bn1,...,nn},α, β, t, Am1,...,mn,andBn1,...,nn be as defined inTheorem 2.1. Let{pm1,...,mn}and {qn1,...,nn}be positive sequences formi 1,2, . . . , ki,and ni 1,2, . . . , ri i 1,2, . . . , n. DefinePm1,...,mn

m1

s11· · ·

mn

sn1ps1,...,sn,andQn1,...,nn n1

t11· · ·

nn

tn1qt1,...,tn.Letφ

and ψ be real-valued, nonnegative, convex, submultiplicative functions defined onR 0,.

Then

k1

m11

· · · kn

mn1

r1

n11

· · ·rn

nn1

αβt1φA

m1,...,mnψBn1,...,nn m1· · ·mnβn1· · ·nnαt

Mk1, . . . , kn, r1, . . . , rn, α, β

× ⎧ ⎨ ⎩

k1

m11

· · · kn

mn1

n

j1

kjmj1pm1,...,mnφ a

m1,...,mn pm1,...,mn

β

1

× ⎧ ⎨ ⎩

r1

n11

· · ·rn

nn1

n

j1

rjnj1qn1,...,nnψa b

n1,...,nn qn1,...,mn

α⎫⎬

⎭ 1

,

2.14

where

Mk1, . . . , kn, r1, . . . , rn, α, β

k

1

m11

· · · kn

mn1 φP

m1,...,mn Pm1,...,mn

α 1/αr1

n11

· · ·rn

nn1 ψQ

n1,...,nn Qn1,...,nn

β 1

(6)

Proof. By the hypotheses, Jensen’s inequality, and H ¨older’s inequality, we obtain

φAm1,...,mn φ

Pm1,...,mn m1

s11. . .

mn

sn1ps1,...,sn

as1,...,sn/ps1,...,sn m1

s11· · ·

mn

sn1ps1,...,sn

φPm1,...,mnφ m1

s11· · ·

mn

sn1ps1,···,sn

as1,...,sn/ps1,...,sn m1

s11· · ·

mn

sn1ps1,...,sn

φPm1,...,mn Pm1,...,mn

m1

s11

· · ·mn

sn1 ps1,...,snφ

a

s1,...,sn ps1,...,sn

φPm1,...,mn Pm1,...,mn

m1· · ·mn1

m

1

s11

· · ·mn

sn1

ps1,...,snφ a

s1,...,sn ps1,...,sn

β 1

.

2.16

Similarly,

φBn1,...,nn

φQn1,...,nn Qn1,...,nn

n1· · ·nn1 n

1

n11

· · ·nn

nn1

qt1,...,tnψ b

t1,...,tn qt1,...,tn

α 1

. 2.17

By2.16and2.17, and using the elementary inequality:

a1b1 a

αt1

t1b

β , 2.18

where 111, α >1, b >0, a >0,andt >0,we have

φAm1,...,mnφBn1,...,nn

m1· · ·mn

αt1

n1· · ·nnt1

β

× φPm1,...,mn Pm1,...,mn

m

1

s11

· · ·mn

sn1

ps1,...,snφ a

s1,...,sn ps1,...,sn

β 1

× φQn1,...,nn Qn1,...,nn

n

1

t11 . . .nn

tn1

qt1,...,tnψ b

t1,...,tn qt1,...,tn

α 1

.

(7)

Dividing both sides of2.19bym1· · ·mnβn1· · ·nnαt/αβt1/β,and summing up overni

from 1 tori i1,2, . . . , nfirst, then summing up overmifrom 1 toki i1,2, . . . , n, using again inverse H ¨older’s inequality, and then interchanging the order of summation, we obtain

k1

m11

· · · kn

mn1

r1

n11

· · ·rn

nn1

αβt1φAm

1,...,mnψBn1,...,nn m1. . . mnβn1. . . nnαt

k1

m11 . . . kn

mn1 ⎛

φPm1,...,mn Pm1,...,mn

m

1

s11

· · ·mn

sn1

ps1,...,snφ a

s1,...,sn ps1,...,sn

β 1

×r1

n11

· · ·rn

nn1 ⎛

φQn1,...,nn Qn1,...,nn

n

1

n11

· · ·nn

nn1

qt1,...,tnψ b

t1,...,tn qt1,...,tn

α 1

k

1

m11

· · · kn

mn1 φP

m1,...,mn Pm1,...,mn

α 1

×

k

1

m11

· · · kn

mn1 m

1

s11

· · ·mn

sn1

ps1,...,snφ a

s1,...,sn ps1,...,sn

β 1

× r

1

n11

· · ·rn

nn1 ψQ

n1,...,nn Qn1,...,nn

β 1

× r

1

n11

· · ·rn

nn1 n

1

t11

· · ·nn

tn1

qt1,...,tnψ b

t1,...,tn qt1,...,tn

α 1

Mk1, . . . , kn, r1, . . . , rn, α, β

× ⎧ ⎨ ⎩

k1

m11

· · · kn

mn1

n

j1

kjmj1pm1,...,mnφ a

m1,...,mn pm1,...,mn

β⎫⎬

⎭ 1

× ⎧ ⎨ ⎩

r1

n11

· · ·rn

nn1

n

j1

rjnj1qn1,...,nnψ b

n1,...,nn qn1,...,mn

α⎫⎬

⎭ 1

.

2.20

(8)

Remark 2.4. Takingαβnj2,2.14becomes

k1

m1

k2

m21

r

1

n11

r2

n21

φAm1,m2ψBn1,n2 m1m2t−1/2n1n2t1/2

Mk1, k2, r1, r2

× k

1

m1

k2

m21

k1−m11k2−m21

pm1,m2φ

a

m1,...,mn pm1,...,mn

2 1/2

× r

1

n1

r2

n21

r1−n11r2−n21

qn1,n2ψ

b

n1,...,nn qn1,...,nn

2 1/2

,

2.21

where

Mk1, k2, r1, r2

k

1

m11

k2

m21

φP

m1,m2 Pm1,m2

2 1/2r1

n11

r2

n21

ψQ

n1,n2 Qn1,n2

2 1/2

. 2.22

Takingt1,and changing{am1,m2},{bn1,n2},{Am1,m2},and{Bn1,n2}into{am},{bn},{Am},and

{Bn},respectively, and with suitable changes,2.21reduces to Pachpatte1, Inequality7.

Theorem 2.5. Let{am1,...,mn},{bn1,...,nn},{pm1,...,mn},{qn1,...,nn},Pm1,...,mn,andQn1,...,nn,α, β, t,be as

defined inTheorem 2.3. Define

Am1,...,mn 1 Pm1,...,mn

m1

s11

· · ·mn

sn1

ps1,...,snas1,...,sn,

Bn1,...,n2

1 Qn1,...,nn

n1

t11

· · ·nn

tn1

qt1,...,tnbt1,...,tn,

2.23

formi 1,2, . . . , ki,and ni 1,2, . . . , ri i 1,2, . . . , n,where ki, ri i 1, . . . , n are natural numbers. Letφandψbe real-valued, nonnegative, convex functions defined onR 0,.Then

k1

m11

· · · kn

mn1

r1

n11

· · ·rn

nn1

αβt1P

m1,...,mnQn1,...,nnφAm1,...,mnψBn1,...,nn m1· · ·mnβn1· · ·nnαt

k1· · ·kn1/αr1· · ·rn1

× ⎧ ⎨ ⎩

k1

m11

· · · kn

mn1

n

j1

kjmj1pm1,...,mnφam1,...,mn β⎫⎬

⎭ 1

× ⎧ ⎨ ⎩

r1

n11

· · ·rn

nn1

n

j1

rjnj1qn1,...,nnψbn1,...,nn α

⎫ ⎬ ⎭

1

.

(9)

Proof. By the hypotheses, Jensen’s inequality, and H ¨older’s inequality, it is easy to observe that

φAm1,...,mn φ

1 Pm1,...,mn

m1

s11

· · ·mn

sn1

ps1,...,snas1,...,sn

P 1

m1,...,mn

m1

s11

· · ·mn

sn1

ps1,...,snφas1,...,sn

P 1

m1,...,mn

m1· · ·mn1

m

1

s11

· · ·mn

sn1

ps1,...,snφas1,...,sn β 1,

2.25

ψBn1,...,nn ψ

1 Qn1,...,nn

n1

t11

· · ·nn

tn1

qt1,...,tnbt1,...,tn

Q 1

n1,...,nn

n1

t11

· · ·nn

tn1

qt1,...,tnψbt1,...,tn

Q 1

n1,...,nn

n1· · ·nn1

n

1

t11

· · ·nn

tn1

qt1,...,tnψbt1,...,tn α 1.

2.26

Proceeding now much as in the proof of Theorems2.1and2.3, and with suitable modifica-tions, it is not hard to arrive at the desired inequality. The details are omitted here.

Remark 2.6. In the special case wherej1, t1, αβ2,andn1,Theorem 2.5reduces to the following result.

Theorem C. Let {am},{bn},{pm},{qn}, Pm, Qn be as defined in Theorem B. Define Am

1/Pmms1psas,andBn 1/Qnnt1qtbt form 1, . . . , k,andn 1, . . . , r, wherek, r are natural numbers. Letφandψbe real-valued, nonnegative, convex functions defined onR 0,.

Then

k

m1

r

n1

PmQnφAmψBn

mn

1 2kr

1/2

k

m1

km1pmφam2

1/2

× r

n1

rn1qnψbn2

1/2

.

2.27

This is the new inequality of Pachpatte in [1, Theorem 4].

Remark 2.7. Takingj 1, t1, pm1, qn1, αβ2,andn1 inTheorem 2.5, and in view

(10)

Theorem D. Let{am},{bn}be as defined in Theorem A. DefineAm 1/mms1as,andBn

1/nnt1bt,form 1, . . . , k,andn 1, . . . , r, wherek, r are natural numbers. Letφ andψ be real-valued, nonnegative, convex functions defined onR 0,.Then

k

m1

r

n1

mn

mnφAmψBn≤ 1 2kr

1/2

k

m1

km1φam2

1/2

× r

n1

rn1ψbn2

1/2

.

2.28

This is the new inequality of Pachpatte in [1, Theorem 3].

Acknowledgments

Research is supported by Zhejiang Provincial Natural Science Foundation of ChinaY605065, Foundation of the Education Department of Zhejiang Province of China20050392. Research is partially supported by the Research Grants Council of the Hong Kong SAR, ChinaProject no. HKU7016/07Pand a HKU Seed Grant forBasic Research.

References

1 B. G. Pachpatte, “On some new inequalities similar to Hilbert’s inequality,”Journal of Mathematical Analysis and Applications, vol. 226, no. 1, pp. 166–179, 1998.

2 G. D. Handley, J. J. Koliha, and J. E. Peˇcari´c, “New Hilbert-Pachpatte type integral inequalities,”

Journal of Mathematical Analysis and Applications, vol. 257, no. 1, pp. 238–250, 2001.

3 M. Gao and B. Yang, “On the extended Hilbert’s inequality,”Proceedings of the American Mathematical Society, vol. 126, no. 3, pp. 751–759, 1998.

4 K. Jichang, “On new extensions of Hilbert’s integral inequality,”Journal of Mathematical Analysis and Applications, vol. 235, no. 2, pp. 608–614, 1999.

5 B. Yang, “On new generalizations of Hilbert’s inequality,” Journal of Mathematical Analysis and Applications, vol. 248, no. 1, pp. 29–40, 2000.

6 W. Zhong and B. Yang, “On a multiple Hilbert-type integral inequality with the symmetric kernel,”

Journal of Inequalities and Applications, vol. 2007, Article ID 27962, 17 pages, 2007.

7 C.-J. Zhao, “Inverses of disperse and continuous Pachpatte’s inequalities,”Acta Mathematica Sinica, vol. 46, no. 6, pp. 1111–1116, 2003.

8 C.-J. Zhao, “Generalization on two new Hilbert type inequalities,”Journal of Mathematics, vol. 20, no. 4, pp. 413–416, 2000.

9 C.-J. Zhao and L. Debnath, “Some new inverse type Hilbert integral inequalities,” Journal of

Mathematical Analysis and Applications, vol. 262, no. 1, pp. 411–418, 2001.

10 G. D. Handley, J. J. Koliha, and J. Peˇcari´c, “A Hilbert type inequality,”Tamkang Journal of Mathematics, vol. 31, no. 4, pp. 311–315, 2000.

11 G. H. Hardy, J. E. Littlewood, and G. P ´olya,Inequalities, Cambridge University Press, Cambridge, UK, 1934.

12 J. N´emeth, “Generalizations of the Hardy-Littlewood inequality,”Acta Scientiarum Mathematicarum, vol. 32, pp. 295–299, 1971.

References

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