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COMPOUNDS

 MOST OF THE MATTER AROUND YOU IS IN THE FORM OF COMPOUNDS.

 WATER, CARBON DIOXIDE, SALT IN YOUR FOOD ARE ALL COMPOUNDS.  COMPOUNDS HAVE PROPERTIES

DIFFERENT FROM THE ELEMENTS WHICH MAKE THEM UP. A GOOD EXAMPLE IS

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COMPOUNDS

 ELEMENTAL SYMBOLS WHEN

WRITTEN TOGETHER MAKE UP A FORMULA OR A CHEMICAL

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COMPOUNDS

 COMMON NAME: SUGAR

 CHEMICAL NAME: SUCROSE

 FORMULA: C12H22O11

 SAND: SILICON DIOXIDE: SiO2

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COMPOUNDS

 THE CHEMICAL FORMULA FOR A

COMPOUND TELLS WHAT

ELEMENTS IT CONTAINS AND THE RATIO OF THE ATOMS OF THOSE ELEMENTS.

 WHAT CAUSES ELEMENTS TO FORM

COMPOUNDS?

 THE ELECTRON ARRANGMENT OF

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COMPOUNDS

 CHEMICALLY STABLE MEANS THAT

THE OUTERMOST ENERGY LEVEL OF AN ATOM IS COMPLETELY FILLED WITH ELECTRONS.

 THE NOBLE GASES ARE THIS WAY.

THEY DON’T FORM CHEMICAL

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COMPOUNDS

 THE OUTERMOST ELECTRONS OR

HIGH ENERGY ELECTRONS ARE CALLED VALENCE ELECTRONS.

 EACH ATOM OF ALL ELEMENTS

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COMPOUNDS

 ATOMS TEND TO GAIN, LOSE, OR

SHARE ELECTRONS WITH ATOMS OF OTHER ELEMENTS IN AN

ATTEMPT TO FILL THEIR

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COMPOUNDS

 SODIUM Na IS A GROUP ONE

PERIOD THREE ALKALI METAL.

 Na HAS AN ATOMIC NUMBER OF 11.

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COMPOUNDS

 Na IS PERIOD THREE, SO IT HAS

THREE ENERGY LEVELS. THE 1ST

LEVEL CONTAINS 2 ELECTRONS. THE 2ND LEVEL CONTAINS 8

ELECTRONS. THE 3RD CONTAINS 1

ELECTRON.

 IT COULD HOLD A TOTAL OF 8

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COMPOUNDS

 CHLORINE IS A GROUP 17 PERIOD

3 HALOGEN. Cl HAS AN ATOMIC NUMBER OF 17. IT HAS 17

PROTONS AND 17 ELECTRONS.

 Cl HAS 2 ELECTRONS IN ITS 1ST

ENERGY LEVEL. Cl HAS 8

ELECTRONS IN ITS 2ND ENERGY

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COMPOUNDS

 Na HAS ONE VALENCE ELECTRON

AND NEEDS 7 TO FILL ITS

OUTERMOST LEVEL. Cl HAS 7

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COMPOUNDS

 MAGNESIUM IS A GROUP TWO

PERIOD THREE ALKALINE METAL. IT HAS AN ATOMIC NUMBER OF 12. IT HAS 12 PROTONS AND 12

ELECTRONS. IT IS ELECTRICALLY NEUTRAL.

 IT HAS 2 e IN 1ST LEVEL. 8 e IN 2ND

LEVEL. IT HAS 2 e IN ITS

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COMPOUNDS

 OXYGEN (O) IS A GROUP 16

PERIOD 2 NONMETAL. IT HAS AN ATOMIC NUMBER OF 8. IT HAS 8 PROTONS AND 8 ELECTRONS AND IS AN ELECTRICALLY NEUTRAL

ATOM.

 IT HAS 2 e IN ITS 1ST LEVEL. IT HAS

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COMPOUNDS

 Mg HAS 2 VALENCE ELECTRONS. IT

COULD HOLD 8. (O) HAS 6

VALENCE ELECTRONS. IT COULD HOLD 8. IN OTHER WORDS, IF IT TOOK THE TWO ELECTRONS FROM MAGNESIUM, IT WOULD HAVE 8

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COMPOUNDS

 Mg + O YIELDS MgO

 Mg 12 + AND 12 -. LOSES 2

VALENCE ELECTRONS TO OXYGEN. NOW IT HAS 12 + AND 10 -. IT IS NO LONGER ELECTRICALLY

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COMPOUNDS

 OXYGEN HAS 8 + AND 8 -. IT

GAINS TWO ELECTRONS FROM Mg. NOW IT HAS 8 + AND 10 -. IT IS NO LONGER ELECTRICALLY

NEUTRAL. IT HAS A -2 CHARGE.

 AN ATOM WITH A CHARGE IS

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COMPOUNDS

 THE CHARGE IS SHOWN AS A

SUPERSCRIPT.

 Mg 2+ AND O

2- THE COMPOUND FORMED,

MAGNESIUM OXIDE IS

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COMPOUNDS

IONIC BONDING: WHEN ONE

ATOM GAINS e AND ONE ATOM LOSES e.

COVALENT BONDING: WHEN

TWO ATOMS SHARE ELECTRONS TO COMPLETE THEIR OUTERMOST

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COMPOUNDS

 POLAR MOLECULES: UNEQUAL

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COMPOUNDS

 WATER H2O IS ALSO A POLAR

MOLECULE. OXYGEN ATTRACTS MORE ELECTRONS. IT IS ALSO

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COMPOUNDS

OXIDATION NUMBER: INDICATES

THE NUMBER OF ELECTRONS LOST, GAINED, OR SHARED WHEN

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COMPOUNDS

 GENERAL OXIDATION NUMBERS:

 ALKALI METALS: +1

 ALKALINE METALS: +2

 BORON GROUP: +3

 CARBON GROUP: +4

 NITROGEN GROUP: -3

 OXYGEN GROUP: -2

 HALOGENS: -1

 NOBLES: 0

 THE TRANSITION METALS HAVE VARIABLE

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COMPOUNDS

 COPPER AND IRON ARE TWO

TRANSITIONAL ELEMENTS THAT HAVE VARIABLE OXIDATION

NUMBERS.

 COPPER Cu CAN HAVE A +1 AND A

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COMPOUNDS

 IRON Fe COMMONLY HAS A +2 OR

A +3 OXIDATION NUMBER. WRITTEN Fe +2 OR Fe +3

 WHEN IN A COMPOUND, FOR

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COMPOUNDS

 THE ROMAN NUMERALS INDICATE

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COMPOUNDS

 THERE ARE TWO TYPES OF BINARY

COMPOUNDS:

 BINARY SALTS: A METAL AND A

NONMETAL.

 BINARY MOLECULES: TWO

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COMPOUNDS

 WHEN WRITING FORMULAS:

 1) WRITE THE SYMBOL OF THE

ELEMENT WITH THE POSITIVE OXIDATION NUMBER FIRST. HYDROGEN AND ALL OF THE METALS.

 2) WRITE THE SYMBOL OF THE

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COMPOUNDS

 3) ADD THE SUBSCRIPTS SO THAT

THE SUM OF THE OXIDATION

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COMPOUNDS

 A COMPOUND THAT CONTAINS THE

ELEMENTS ALUMINUM AND SULFUR.

 1) WHAT ARE THE OXIDATION

NUMBERS?

 Al IS A GROUP 13 UNDER THE

BORON GROUP. USUALLY A +3

 S IS A GROUP 16 UNDER THE

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COMPOUNDS

 2) HOW MANY ATOMS OF EACH

ELEMENT DO YOU NEED SO THAT THE SUM OF THE OXIDATION

NUMBERS EQUALS ZERO?

 WHAT IS THE LEAST COMMON

MULTIPLE OF 3 AND 2? THE +3 Al AND THE -2 S.

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COMPOUNDS

 (+3)2 PLUS 3(-2) EQUALS A PLUS 6

AND A MINUS 6 WHICH EQUALS ZERO.

 WRITE ALUMINUM FIRST (IT IS A

METAL AND HAS A POSITIVE OX #)

 Al

2S3

 WE CALL THIS COMPOUND

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COMPOUNDS

 CHROMIUM Cr IS ANOTHER

TRANSITIONAL METAL WITH

VARIABLE OXIDATION NUMBERS.

 Cr 2+ AND Cr 3+

 WHEN NAMING COMPOUNDS WITH

ELEMENTS WITH VARIABLE OX #’S, USE THE OX # OF THE NEGATIVE

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COMPOUNDS

 NAME THE FOLLOWING: CrO

 CHROMIUM (II) OXIDE

 REMEMBER THAT THE ROMAN

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COMPOUNDS

 NOT ALL COMPOUNDS ARE BINARY.

SOME COMPOUNDS CONTAIN MORE THAN TWO ELEMENTS.

 A POLYATOMIC ION IS A GROUP

OF ATOMS THAT BEHAVE AS A SINGLE ION. USE PARENTHESES

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COMPOUNDS

 NaHCO

3 IS SODIUM HYDROGEN

CARBONATE OR BAKING SODA. IT IS NOT BINARY. IT HAS FOUR

ELEMENTS. SODIUM, HYDROGEN, CARBON, AND OXYGEN.

 IT ALSO CONTAINS A POLYATOMIC:

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COMPOUNDS

 IN THE CASE OF BAKING SODA,

NaHCO3, THE POLYATOMIC IS (CO3)2-

CARBONATE.

 OTHER COMMON POLYATOMIC IONS

ARE:

 SULFATE: SO

4

2- NITRATE NO

3

- PHOSPHATE PO

4

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COMPOUNDS

 NAME THE FOLLOWING:

 K

2SO4

 POTASSIUM SULFATE

 WRITE THE FORMULA FOR CALCIUM

NITRATE:

 1) WHAT ARE THE SYMBOLS?

 Ca AND NO

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COMPOUNDS

 2) WHAT ARE THE OXIDATION

NUMBERS?

 Ca IS A GROUP TWO ALKALINE

METAL…

 +2

 THE POLYATOMIC NO3

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COMPOUNDS

 CALICUM NITRATE

 Ca(NO

3)2

 WHY ARE THERE 2 NO

3?

 THE PLUS 2 OXIDATION NUMBER OF

Ca AND TWO OF THE -1 OXIDATION

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PERIODIC TABLE

 METALS: MOST ARE HARD AND

SHINY. MOST ARE MALLEABLE,

WHICH MEANS THAT THEY CAN BE HAMMERED OR ROLLED INTO

SHEETS. MOST ARE DUCTILE, WHICH MEANS THEY CAN BE

DRAWN INTO WIRES. MOST ARE GOOD CONDUCTORS OF

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PERIODIC TABLE

 METALLIC BONDING: (REMEMBER

IONIC AND COVALENT).

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PERIODIC TABLE

 GROUP I ALKALI METALS:

 +1 OX #, HIGHLY REACTIVE (NOT

FOUND FREE IN NATURE), LITHIUM USED FOR MANIC DEPRESSION,

SODIUM AND POTASSIUM IN OUR BODIES, FRANCIUM, THE LAST

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PERIODIC TABLE

 GROUP 2 ALKALINE METALS:

 +2 OX #, HIGHLY REACTIVE (NOT FOUND FREE IN NATURE), RADIUM IS

RADIOACTIVE, MAGNESIUM AND

CALCIUM IMPORTANT FOR LIFE, Mg USED IN INDUSTRY. Mg FOUND IN

CHLOROPHYLL, STRONTIUM IN FIREWORKS, BERYLLIUM IN

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PERIODIC TABLE

 GROUP 3-12 TRANSITION

ELEMENTS:

 MAINLY METALS, VARIABLE OX #’S,

USUALLY +1 OR +2, ALUMINUM IS MOST ABUNDANT METAL IN

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PERIODIC TABLE

 ORES: METALS IN THE EARTHS

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PERIODIC TABLE

 TRANSURANIUM ELEMENTS: ALL OF THE ELEMENTS FOLLOWING URANIUM,

ATOMIC NUMBER 92. THESE ARE THE

SYNTHETIC ELEMENTS MADE BY MAN IN A LAB.

 MADE BY SMASHING ATOMS WITH

OTHER PARTICLES. BOMBARD URANIUM WITH NEUTRONS TO PRODUCE

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PERIODIC TABLE

 NONMETALS: MOST NONMETALS

ARE GASES AT ROOM TEMP. SOLID NONMETALS ARE DULL, BRITTLE, POWDERY, POOR CONDUCTORS OF HEAT AND ELECTRICITY.

NONMETALS GAIN ELECTRONS FROM METALS BECOMING

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PERIODIC TABLE

 GROUP 18 NOBLE GASES ARE THE

ONLY GROUP OF ELEMENTS THAT ARE ALL NONMETALS.

 GROUP 1 HYDROGEN. MOST

HYDROGEN ON EARTH IS FOUND IN THE COMPOUND WATER.

 IT IS ONE OF MANY DIATOMIC

MOLECULES, MEANING IT

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PERIODIC TABLE

 GROUP 17 HALOGENS HAVE 7

VALENCE ELECTRONS. ONLY ONE ELECTRON IS NEEDED TO

COMPLETE ITS OUTER ENERGY

LEVEL. IF IT GAINS AN ELECTRON FROM A METAL, IT FORMS AN

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PERIODIC TABLE

 GROUP 18 NOBLE GASES. VERY

STABLE BECAUSE THEIR

OUTERMOSY ENERGY LEVEL IS FULL. THEY DON’T NATURALLY

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PERIODIC TABLE

 GROUPS 13-16 ARE MIXED

GROUPS. THEY CONTAIN METALS, NONMETALS, AND METALLOIDS.

 GROUP 14 HAS FOUR VALENCE

ELECTRONS. CARBON IS A NONMETAL, SILICON AND

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PERIODIC TABLE

 ALLOTROPE: DIFFERENT FORMS OF

THE SAME ELEMENT HAVING DIFFERENT MOLECULAR

STRUCTURES. THE ELEMENT

CARBON HAS THE ABILITY TO BIND WITH ITSELF. ALLOWS FOR

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PERIODIC TABLE

 SILICON IS THE SECOND MOST

ABUNDANT ELEMENT IN THE

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PERIODIC TABLE

 GROUP 15 HAS 5 VALENCE

ELECTRONS. THIS GROUP TENDS TO SHARE ELECTRONS FORMING COVALENT BONDS.

 NITROGEN IS A DIATOMIC

MOLECULE N2. EARTHS

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PERIODIC TABLE

 GROUP 16 CONTAINS THE ELEMENT

OXYGEN. THE MOST ABUNDANT ELEMENT IN THE EARTHS CRUST. IT IS A DIATOMIC MOLECULE. IT MAKES UP 21% OF THE EARTHS ATMOSPHERE. O3 IS OZONE THAT PROTECTS US FROM UV

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CHEMICAL REACTIONS

 CHEMICAL REACTION: ONE OR

MORE SUBSTANCES ARE CHANGED TO NEW SUBSTANCES. THE

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REACTIONS

 LAW OF CONSERVATION OF MASS:

IN A CHEMICAL REACTION, MATTER IS NOT CREATED OR DESTROYED, IT JUST CHANGES FORM. ATOMS ARE REARRANGED, BUT NEVER LOST OR DESTROYED.

 YOU HAVE TO SHOW THIS WHEN

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REACTIONS

 SOLID LEAD (II) NITRATE,

DISSOLVED IN WATER, PLUS SOLID POTASSIUM IODIDE, DISSOLVED

IN WATER, PRODUCES SOLID LEAD (II) IODIDE PLUS POTASSIUM

NITRATE DISSOLVED IN WATER.

 THIS IS THE LONG WAY TO

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REACTIONS

 INSTEAD, WE USE A CHEMICAL

SHORTHAND.

 Pb(NO3)2 (aq) + 2Kl (aq) YIELDS

PbI2 (cr) + 2KNO3 (aq)

 (aq) MEANS AQUEOUS OR

DISSOLVED IN WATER.

 (cr) MEANS CRYSTALLINE OR

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REACTIONS

 THE LARGE NUMBERS SUCH AS

2KNO3 ARE CALLED COEFFICIENTS.

 THEY TELL US HOW MANY UNITS

TAKE PART IN THE REACTION. IN OTHER WORDS, THEY HELP US

BALANCE AN EQUATION.

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REACTIONS

 A BALANCED CHEMICAL EQUATION

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BALANCING MOLECULAR

EQUATIONS

 TIPS:

 1) MENTALLY COUNT OR ACTUALLY

TALLY HOW MANY OF EACH TYPE OF ATOM IS PRESENT ON EACH SIDE OF THE EQUATION.

 2) BEGIN BY BALANCING ELEMENTS

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BALANCING MOLECULAR

EQUATIONS

 3) BALANCE OXYGEN AND

HYDROGEN LAST.

 4) IF THERE IS AN ODD NUMBER OF

AN ELEMENT ON ONE SIDE AND AN EVEN NUMBER ON THE OTHER SIDE, THE ODD NUMBER WILL NEED TO BE EVENED OUT. USE A COEFFICIENT

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BALANCING MOLECULAR

EQUATIONS

 5) IF THERE ARE POLYATOMIC IONS

THAT REMAIN TOGETHER AS A UNIT DURING THE REACTION, COUNT

THE POLYATOMIC ION AS A UNIT.

 6) WHEN TALLYING, BE SURE TO

ADJUST THE COUNT FOR EACH AND EVERY ELEMENT THAT AN ADDED

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Balancing equations

 NaOH + H2SO4 YIELDS Na2SO4 + H2O

 ELEMENT BEFORE AFTER

 Na 1 2

 O 5 5

 H 3 2

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BALANCING EQUATIONS

 2NaOH + H2SO4 YIELDS Na2SO4 +

H20

 ELEMENT BEFORE AFTER

 N 2 2

 O 6 5

 H 4 2

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BALANCING EQUATIONS

 2NaOH + H2SO4 YIELDS Na2SO4 +

2H20

 ELEMENT BEFORE AFTER

 Na 2 2

 O 6 6

 H 4 4

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BALANCING EQUATIONS

 BALANCE THE FOLLOWING:

 NaCl + BeF2 -- NaF + BeCl2

 AgNO3 + LiOH  AgOH +LiNO3

 CH4 + O2  CO2 + H20

 Mg + Mn2O3  MgO + Mn

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BALANCING MOLECULAR

EQUATIONS

 AMMONIUM NITRATE REACTS WITH CALCIUM PHOSPHATE TO FORM

AMMONIUM PHOSPHATE AND CALCIUM NITRATE.

 NH4NO3 + Ca3(PO4)2 YIELDS (NH4)3PO4 + Ca(NO3)2

 FIRST, NOTICE THAT EACH OF THE

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BALANCING MOLECULAR

EQUATIONS

 NH4NO3 + Ca3(PO4)2 YIELDS (NH4)3PO4 + Ca(NO3)2

 NH4 1 NH4 3

 NO3 1 NO3 2

 Ca 3 Ca 1

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BALANCING MOLECULAR

EQUATIONS

 1) BEGIN WITH CALCIUM, ADD A

COEFFICIENT OF 3 ON THE RIGHT

TO BALANCE THE CALCIUM.

 2) DOING THIS CHANGES THE

NITRATE COUNT TO 6 ON THE

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BALANCING MOLECULAR

EQUATIONS

6NH4NO3 + Ca3(PO4)2 YIELDS (NH4)3PO4 +

3Ca(NO3)2

 NH4 6 NH4 3

 NO3 6 NO3 6

 Ca 3 Ca 3

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BALANCING MOLECULAR

EQUATIONS

 FINALLY ADD A COEFFICIENT OF 2 IN FRONT OF

AMMONIUM PHOSPHATE TO COMPLETE THE BALANCING.

 6NH

4NO3 + Ca3(PO4)2 YIELDS 2(NH4)3PO4

+ 3Ca(NO3)2

 NH

4 6 NH4 6

 NO

3 6 NO3 6

 Ca 3 Ca 3  PO

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REACTIONS

 CLASSIFYING CHEMICAL

REACTIONS:

 1) SYNTHESIS: TWO OR MORE

SUBSTANCES COMBINE TO FORM ANOTHER SUBSTANCE.

 A + B YIELDS AB

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REACTIONS

 2) DECOMPOSITION: ONE

SUBSTANCE BREAKS DOWN INTO TWO OR MORE SIMPLER

SUBSTANCES.

 AB YIELDS A + B

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REACTIONS

 3) SINGLE REPLACEMENT: ONE

ELEMENT REPLACES ANOTHER ELEMENT IN A COMPOUND.

 A + BC YIELDS AC + B

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REACTIONS

 4) DOUBLE REPLACEMENT: THE

POSITIVE ION OF ONE COMPOUND REPLACES THE POSITIVE ION OF ANOTHER COMPOUND TO FORM TWO NEW COMPOUNDS.

 AB + CD YIELDS AD + CB

 AgNO3 + NaCl YIELDS AgCl +

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REACTIONS

 IN CHEMICAL REACTIONS, ENERGY

IS EITHER RELEASED OR ABSORBED.

 ENERGY CAN TAKE MANY FORMS,

USUALLY HEAT OR LIGHT, IT CAN BE IN THE FORM OF SOUND OR

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REACTIONS

 WHEN A CHEMICAL REACTION TAKES

PLACE, CHEMICAL BONDS IN THE REACTANTS MUST BE BROKEN.

 TO BREAK CHEMICAL BONDS, ENERGY

MUST BE PROVIDED.

 IN ORDER FOR PRODUCTS TO BE

PRODUCED, NEW BONDS MUST BE FORMED.

 BOND FORMATION RELEASES

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REACTIONS

 IN SOME REACTIONS, LESS ENERGY

IS REQUIRED TO BREAK ORIGINAL BONDS THAN IS RELEASED WHEN NEW BONDS FORM. THIS IS

REFERRED TO AS AN EXOTHERMIC

REACTION.

 IN EXOTHERMIC REACTIONS,

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REACTIONS

 IN SOME REACTIONS, MORE ENERGY

IS REQUIRED TO BREAK BONDS THAN TO FORM NEW BONDS IN A CHEMICAL REACTION. THESE ARE CALLED

ENDOTHERMIC REACTIONS.

 ENERGY MUST BE PROVIDED FOR

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REACTIONS

 BURNING WOOD AND EXPLODING

DYNAMITE ARE EXOTHERMIC REACTIONS. THEY GIVE OFF ENERGY AS THE REACTION PROCEEDS.

 REFINING ORES IN METAL MAKING

AND BAKING BREAD ARE

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REACTIONS

 CATALYST: A SUBSTANCE THAT

SPEEDS UP A CHEMICAL REACTION WITHOUT BEING USED UP OR

CHANGED DURING THE REACTION.

 CATALYSTS IN THE BODY ARE

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