Volume 2008, Article ID 471532,7pages doi:10.1155/2008/471532
Research Article
Approximation Methods for Common Fixed Points
of Mean Nonexpansive Mapping in Banach Spaces
Zhaohui Gu1 and Yongjin Li2
1Department of Foundation, Guangdong Finance and Economics College, Guangzhou 510420, China 2Institute of Logic and Cognition, Department of Mathematics, Sun Yat-Sen University,
Guangzhou 510275, China
Correspondence should be addressed to Yongjin Li,[email protected]
Received 17 October 2007; Accepted 2 January 2008
Recommended by Tomonari Suzuki
LetXbe a uniformly convex Banach space, and letS, Tbe a pair of mean nonexpansive mappings. In this paper, it is proved that the sequence of Ishikawa iterations associated withSandTconverges to the common fixed point ofSandT.
Copyrightq2008 Z. Gu and Y. Li. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
1. Introduction and preliminaries
LetXbe a Banach space and letS,Tbe mappings fromXtoX. The pair of mean nonexpansive mappings was introduced by Bose in1:
Sx−Ty ≤ax−ybx−Sxy−Tycx−Tyy−Sx, 1.1
for allx, y ∈X,a, b, c∈0,1,a2b2c≤1.
The Ishikawa iteration sequence{xn}ofSandT was defined by
yn1−βnxnβnSxn,
xn11−αnxnαnTyn, 1.2
wherex0 ∈X,αn, βn ∈0,1. The recursion formulas1.2were first introduced in 1994
by Rashwan and Saddeek2in the framework of Hilbert spaces.
to a unique common fixed point in Hilbert spacessee2. Recently, ´Ciri´c has proved that if the sequence of Ishikawa iterations sequence{xn}associated withSandT converges top, thenp
is the common fixed point ofSandT see7. In4,6, the authors studied the same problem. In1, Bose defined the pair of mean nonexpansive mappings, and proved the existence of the fixed point in Banach spaces. In particular, he proved the following theorem.
Theorem 1.1see1. LetXbe a uniformly convex Banach space andKa nonempty closed convex subset ofX,S:K→KandT :K→Kare a pair of mean nonexpansive mappings, andc /0. Then,
iSandThave a common fixed pointu;
iifurther, ifb /0, then
auis the unique common fixed point and unique as a fixed point of eachSandT,
bthe sequence{xn}defined byx1Sx0, x2Tx1, x3Sx2. . ., for anyx0 ∈K, converges
strongly tou.
It is our purpose in this paper to consider an iterative scheme, which converges to a common fixed point of the pair of mean nonexpansive mappings. Theorem 2.1 extends and improves the corresponding results in1.
2. Main results
Now we prove the following theorem which is the main result of this paper.
Theorem 2.1. LetXbe a uniformly convex Banach space,S :X→XandT :X→Xare a pair of mean nonexpansive with a nonempty common fixed points set; ifb >0, 0 < α≤αn ≤1/2, 0≤βn ≤β <1,
then the Ishikawa sequence{xn}converges to the common fixed point ofSandT.
Proof. First, we show that the sequence{xn}is bounded. For a common fixed pointpofSand
T, we have
Tx−pTx−Sp
≤ax−pbx−Txp−Spcx−Spp−Tx ≤ax−pbx−pp−Txcx−Spp−Tx.
2.1
LetL abc/1−b−c, bya2b2c≤1, it is easy to see thatabc≤1−b−c, thus 0≤L≤1 andTx−p ≤Lx−p ≤ x−p.
Similarly, we haveSx−p ≤Lx−p ≤ x−p,
xn1−p1−αn
xnαnTyn−p
1−αnxn−pαnTyn−p
≤1−αnxn−pαnTyn−p
≤1−αnxn−pαnLyn−p
≤1−αnxn−pαn1−βn
xnβnSxn−p
1−αnxn−pαn1−βnxn−pβnSxn−p
≤1−αnxn−pαn1−βnxn−pαnβnSxn−p
≤1−αnxn−pαn1−βnxn−pαnβnxn−p 1−αnαn1−βnαnβnxn−pxn−p.
So
xn1−p≤xn−p≤xn−1−p≤ · · · ≤x0−p. 2.3
Hence,{xn}is bounded.
Second, we show that
lim
n→∞xn−Tyn0. 2.4
We recall that Banach spaceXis called uniformly convex ifδε>0 for everyε >0, where the modulusδεof convexity ofXis defined by
δε inf
1−xy 2
:x ≤1, y ≤1, x−y ≥ε
, 2.5
for everyεwith 0≤ε≤2. It is easy to see that Banach spaceXis uniformly convex if and only if for anyxn, yn∈BX {x| x ≤1}, xnyn →2 impliesxn−yn →0.
Assume that limn→∞xn−Tyn/0, then there exist a subsequence {xnk}of {xn}and a
real numberε0>0, such that
xnk−Tynk≥ε0, k 1,2,3, . . . . 2.6
On the other hand, for a common fixed pointpofTandS, we have
xnk−Tynk≤xnk−pTynk−p
≤xnk−pLynk−p
xnk−pL1−βnkxnkβnkSxnk−p
xnk−pL1−βnkxnk−pβnkSxnk−p
≤xnk−p1−βnk
Lxnk−pβnkLSxnk−p
≤11−βnkLβnkL2xnk−p
≤1Lxnk−p≤2xnk−p.
2.7
Thus,
xnk−p≥ 1
2xnk−Tynk≥ ε0
2 ε1>0. 2.8
Because
Tyn−p≤yn−p≤1−βn
xnβnSxn−p
1−βnxn−pβnSxn−p≤1−βnxn−pβnSxn−p
≤1−βnxn−pβnxn−p≤xn−p,
2.9
we know{xn}is bounded, then there existsM >0, such thatxn−p ≤M. Thus,Tyn−p ≤
Furthermore, we have
xnk−p
xnk−p −Tynk−p
xnk−p
xnk−Tynk xnk−p ≥ ε1
M >0. 2.10 From
xnk−p
xnk−p1,
Tynk−p
xnk−p≤L≤1, 2.11
and the fact thatXis uniformly convex Banach space, there existsδ >0, such that
xnk−p
xnk−p Tynk−p
xnk−p
≤2−δ. 2.12
Thus,
xnk1−p1−αnk
xnkαnkTynk−p
≤1−2αnkxnk−pαnkxnk−pαnkTynk−p
≤1−2αnkxnk−pαnkxnk−p·
xnk−p
xnk−p Tynk−p
xnk−p
≤1−2αnkxnk−p 2−δαnkxnk−p≤1−δαnkxnk−p xnk−p−δαnkxnk−p≤xnk−p−δαε1.
2.13
Using2.3, we obtain that
xnk1−p≤xnk−p−δαε1≤xnk−1−p−δαε1
≤xnk−2−p−δαε1≤ · · · ≤xnk−11−p−δαε1
≤xnk−1−p−2δαε1.
2.14
So
xnk−p≤xnk−1 −p−δαε1≤xnk−2−p−2δαε1≤ · · · ≤xn1 −p−k−1δαε1. 2.15
Letk→∞, then we havexnk−p<0. It is a contradiction. Hence, limn→∞xn−Tyn0.
Third, we show that
lim
n→∞xn−Sxn0. 2.16
Since
xn−Sxn≤xn−TynTyn−Sxn
≤xn−Tynaxn−ynbxn−Sxnyn−Tyn cxn−Tynyn−Sxn
1cxn−Tynaxn−ynbxn−Sxn byn−Tyncyn−Sxn
1cxn−Tyna1−βnxnβnSxn−xn bxn−Sxnb1−βn
xnβnSxn−Tyn c1−βnxnβnSxn−Sxn
≤1cxn−Tynaβnxn−Sxn
bxn−Sxnbβnxn−Sxnbxn−Tync1−βnxn−Sxn
1bcxn−Tynaβnbbβnc1−βnxn−Sxn,
we have
1−aβn−b−bβn−c1−βnxn−Sxn≤1bcxn−Tyn. 2.18
LetM11−aβn−b−bβn−c1−βn, then
M11−aβn−b−bβn−ccβn1−b−c−ab−cβn
≥abc−ab−cβn ab1−βnc1βn
≥ab1−β c >0.
2.19
So
xn−Sxn≤ 1bc M1
xn−Tyn. 2.20
Using2.4, we get that
lim
n→∞xn−Sxn0. 2.21
Forth, we show that if the Ishikawa sequence{xn}converges to some pointp ∈X, then
pis the common fixed point ofSandT. By
yn1−βnxnβnSxn,
xn11−αnxnαnTyn, 2.22
we havexn−Tyn 1/αnxn1−xn. Since{xn}is a convergent sequence, we get limn→∞xn−
Tyn 0. It is easy to see thatxn−yn βnxn−SxnandSxn−yn 1−βnxn−Sxn.
On the other hand,
yn−Tyn1−βn
xnβnSxn−Tyn≤1−βnxn−TynβnSxn−Tyn. 2.23
By1.1, we obtain
Tyn−Sxn≤axn−ynbxn−Sxnyn−Tyncxn−Tynyn−Sxn
≤aβnxn−Sxnbxn−Sxnb1−βnxn−Tyn bβnSxn−Tyncxn−Tync1−βnxn−Sxn aβnbc1−βnxn−Sxn
b1−βncxn−TynbβnSxn−Tyn.
2.24
Since
xn−Sxn≤Sxn−Tynxn−Tyn, 2.25
we get
Tyn−Sxn≤
b1−βncaβnbc1−βnxn−Tyn
So
1−b−c−ab−cβnTyn−Sxn≤b1−βn
caβnbc1−βnxn−Tyn. 2.27
LetM21−b−c−ab−cβn, Since 0≤βn≤β <1, we have
M2≥abc−ab−cβn≥ab
1−βnc1βn≥ab1−β c >0. 2.28
It is easy to see that
b1−βncaβnbc1−βn>0. 2.29
Note that limn→∞xn−Tyn0, then we get
lim
n→∞Sxn−Tyn0, nlim→∞yn−Tyn0. 2.30 So limn→∞xn−ynlimn→∞βnSxn−xn0.
Letp limn→∞xn, then limn→∞yn p, limn→∞Sxn p, limn→∞Tyn p. By1.1, we
have
Sxn−Tp≤axn−pbxn−Sxnp−Tp
cxn−Tpp−Sxn. 2.31
Letn→∞, then we get
p−Tp ≤bcp−Tp. 2.32
Sincebc <1, it follows that
p−Tp0, that isTpp. 2.33
Similarly, we can prove thatSpp. Sopis the common fixed point ofSandT. Finally, we show that{Sxn}is a Cauchy sequence. For anym, n∈N,
Sxn−Sxnm≤Sxn−TynmSxnm−Tynm
≤axn−ynmbxn−Sxnynm−Tynm cxn−Tynmynm−SxnSxnm−Tynm
≤axn−SxnSxn−SxnmSxnm−ynm bxn−Sxnynm−Tynm
cxn−SxnSxn−Sxnm
Sxnm−Tynmynm−Sxnm Sxnm−SxnSxnm−Tynm.
2.34
Sinceb >0, thus we get 1−a−2c >0.Simplify, then we have
Sxn−Sxnm≤Axn−SxnBynm−Tynm
Cynm−SxnmDSxnm−Tynm, 2.35
whereA abc/1−a−2c≥0, Bb/1−a−2c≥0, C ac/1−a−2c≥0, and D 1c/1−a−2c≥0.By2.16and2.30, we know that
So it is easy to see thatynm−Sxnm→0. Thus,Sxn−Sxnm→0, that is{Sxn}is a Cauchy
sequence. Hence, there existsp, such thatp limn→∞Sxn. We know thatp limn→∞xnandp
is the common fixed point ofSandT. This completes the proof of the theorem.
Acknowledgment
The work was partially supported by the Emphases Natural Science Foundation of Guangdong Institution of Higher Learning, College and Universityno. 05Z026.
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