R E S E A R C H
Open Access
A posteriori error estimates for fourth order
hyperbolic control problems by mixed finite
element methods
Chunjuan Hou
1, Zhanwei Guo
1and Lianhong Guo
1**Correspondence: [email protected]
1Huashang College Guangdong University of Finance and Economics, Guangzhou, P.R. China
Abstract
In this paper, we consider the a posteriori error estimates of the mixed finite element method for the optimal control problems governed by fourth order hyperbolic equations. The state is discretized by the orderkRaviart–Thomas mixed elements and control is discretized by piecewise polynomials of degreek. We adopt the mixed elliptic reconstruction to derive the a posteriori error estimates for both the state and the control approximations.
MSC: 49J20; 65N30
Keywords: A posteriori error estimates; Optimal control problems; Fourth order hyperbolic equations; Mixed finite element methods
1 Introduction
The finite element approximation for optimal control problems has an enormously im-portant function in the numerical approach for these problems. Scientists have studied extensively this area; see, for example, [4,12,13,21,25]. They discussed the a priori er-ror estimates using finite element approximations, such as [1,16,23], in which elliptic or parabolic problems are considered by optimal control theory. They studied adaptivity for many optimal control problems; for example, see [4,11,17,20–22].
In some optimal control problems, for the objective function containing a gradient of the state variable, we use mixed finite element methods to discretize the state equation, so that the scalar variable and its flux variable can be approximated in the same accuracy; for example, see [3]. Many scientists have addressed the mixed finite element methods for elliptic problems [6–8,14], for the first bi-harmonic equation [5], for parabolic problems [26] and for hyperbolic problems [9,15].
The purpose of this work is to discuss the a posteriori error estimates of the semidiscrete mixed finite element approximation for fourth order hyperbolic optimal control problems. Considering the fourth order hyperbolic equations by the idea of a mixed elliptic recon-struction [24], we obtain the error estimates for the state and the control approximations. The following is the model we considered:
min
u∈K∈U
1 2
T
0
y2+y–yd2+u2
dt
, (1.1)
ytt(x,t) +2y(x,t) =f(x,t) +u(x,t), x∈Ω,t∈J, (1.2)
y(x,t) = ∂y
∂n= 0, x∈∂Ω,t∈J, (1.3)
y(x, 0) =y0(x), x∈Ω, (1.4)
yt(x, 0) =y1(x), x∈Ω, (1.5)
whereΩ⊂R2is an open set of polygon with∂Ω.Kis inU=L2(J;L2(Ω)), a closed convex set,J= [0,T],f,yd∈L2(J;L2(Ω)) andy0,y1∈H4(Ω).Kis defined as follows:
K=
u∈U:
T
0
Ω
u dx dt≥0
. (1.6)
Lety˜= –y,p˜= –∇yandp= –∇˜y, then (1.1)–(1.5) can be written as
min
u∈K∈U
1 2
T
0
˜y2+y–yd2+u2
dt
, (1.7)
ytt(x,t) +divp(x,t) =f(x,t) +u(x,t), x∈Ω,t∈J, (1.8)
p(x,t) = –∇˜y(x,t), x∈Ω,t∈J, (1.9)
divp˜(x,t) =y(x,˜ t), x∈Ω,t∈J, (1.10)
˜
p(x,t) = –∇y(x,t), x∈Ω,t∈J, (1.11)
y(x,t) = –p˜·n= 0, x∈∂Ω,t∈J, (1.12)
y(x, 0) =y0(x), x∈Ω, (1.13)
yt(x, 0) =y1(x), x∈Ω. (1.14)
In the paper, we adopt the standard notationWm,p(Ω) for Sobolev space onΩ with a
normvm,pgiven byvpm,p:=
|α|≤mDαv p
Lp(Ω), and a seminorm|v|m,pgiven by|v|pm,p:=
|α|=mDαv p
Lp(Ω). We setW0m,p(Ω) ={v∈Wm,p(Ω) :γ(Dαv)|∂Ω= 0,|α|=m}, whereγ is
the trace operator. We denoteWm,2(Ω)(W0m,2(Ω)) byHm(Ω)(H0m(Ω)).
We denote byLs(0,T;Wm,p(Ω)) the Banach space of allLsintegrable functions fromJ
intoWm,p(Ω) with normvLs(J;Wm,p(Ω))= (T
0 v
s
Wm,p(Ω)dt)
1
s fors∈[1,∞), and the
stan-dard modification fors=∞. For simplicity of presentation, we denotevLs(J;Wm,p(Ω))by vLs(Wm,p). Similarly, one can define the spacesH1(J;Wm,p(Ω)) andCk(J;Wm,p(Ω)). We
can find details in [19].Cis a general positive constant independent ofh.
The rest of this paper is as follows: In Sect.2, we introduce the optimal control problems and its mixed finite element scheme. Section2ends with the definition of the mixed elliptic reconstructions, which is useful in deriving the a posteriori estimates for the fourth order hyperbolic optimal control problems in Sect.3. Finally, we make some concluding remarks in Sect.4.
2 Optimal control problems for mixed methods
A semidiscrete approximation of a mixed finite element for the optimal control problems (1.7)–(1.14) will be constructed. We set the state spacesL=L2(J;V), L
Q=L2(J;W),W=L2(Ω), whereV, andV
0are defined as follows:
V=H(div;Ω) = v∈L2(Ω)2,divv∈L2(Ω),
V0=H0(div;Ω) = v∈H(div,Ω),v·n|∂Ω= 0
.
The spaceVis a Hilbert space, its norm is defined as follows:
vH(div;Ω)=
v20,Ω+divv20,Ω1/2.
Now we introduce operators:div,∇,curlandCurl. For anyv= (v1,v2)∈(H1(Ω))2 or w∈H1(Ω),
divv=∂1v1+∂2v2, ∇w= (∂1w,∂2w), (2.1)
curlv=∂1v2–∂2v1, Curlw= (–∂2w,∂1w). (2.2)
Next, (1.7)–(1.14) can be rewritten into weak form as follows: find (p˜,y,p,y,u)∈(L0× Q×L×Q×K), such that
min
u∈K⊂U
1 2
T
0
˜y2+y–yd2+u2
dt
, (2.3)
(ytt,w) + (divp,w) = (f+u,w), ∀w∈W,t∈J, (2.4)
(p,v) – (y,˜ divv) = 0, ∀v∈V0,t∈J, (2.5)
(divp˜,w) = (y,˜ w), ∀w∈W,t∈J, (2.6)
(p˜,v) – (y,divv) = 0, ∀v∈V,t∈J, (2.7)
y(x, 0) =y0(x), ∀x∈Ω, (2.8)
yt(x, 0) =y1(x), ∀x∈Ω. (2.9)
From [18], we know that the above optimal control problem has a unique solution
(p˜,y,p,y,˜ u), and that (p˜,y,p,y,˜ u) is the solution of (2.3)–(2.9) if and only if there is a co-state (q˜,z,q,˜z)∈(L0×Q×L×Q) such that (p˜,y,p,y,˜ q˜,z,q,z,˜ u) satisfies the following optimality conditions:
(ytt,w) + (divp,w) = (f+u,w), ∀w∈W,t∈J, (2.10)
(p,v) – (y,˜ divv) = 0, ∀v∈V,t∈J, (2.11)
(divp˜,w) = (y,˜ w), ∀w∈W,t∈J, (2.12)
(p˜,v) – (y,divv) = 0, ∀v∈V,t∈J, (2.13)
y(x, 0) =y0(x), ∀x∈Ω, (2.14)
yt(x, 0) =y1(x), ∀x∈Ω, (2.15)
(ztt,w) + (divq,w) = (y–yd,w), ∀w∈W,t∈J, (2.16)
(divq˜,w) = (y˜+z,˜ w), ∀w∈W,t∈J, (2.18)
(q˜,v) – (z,divv) = 0, ∀v∈V,t∈J, (2.19)
z(x,T) = 0, ∀x∈Ω, (2.20)
zt(x,T) = 0, ∀x∈Ω, (2.21)
T
0
(u+z,u˜–u)dt≥0, ∀˜u∈K, (2.22)
where (·,·) is the inner product ofL2(Ω).
Kis a control constraint, so we can get a relationship betweenuandz. This relationship is important for our result.
Lemma 2.1 Let(z,u)be the solution of(2.10)–(2.22).Then we have u=max{0,zˇ}–z,where
ˇ
z= T
0
Ωz dx dt
T
0
Ω1dx dt
denotes the integral average onΩ×J of the function z.
Let Th be regular triangulations of Ω, hτ is the diameter of τ andh=maxhτ.
Fur-thermore, letEh be the set of element sides of the triangulationTh withΓh=
E
h. Let
Vh×Wh⊂V×W denote the Raviart–Thomas space [3] associated with the
triangula-tionsThofΩ.Pkdenotes the space of polynomials of total degree no greater thank(k≥0).
LetV(τ) ={v∈Pk2(τ) +x·Pk(τ)},W(τ) =Pk(τ). We set
Vh:= vh∈V:∀τ ∈Th,vh|τ∈V(τ)
,
Wh:= wh∈W:∀τ∈Th,wh|τ∈W(τ)
,
Kh:=L2(J;Wh)∩K.
We now discretize (2.3)–(2.9). We calculate (p˜h,yh,ph,y˜h,uh) such that
min
uh∈Kh
1 2
T
0
˜yh2+yh–yd2+uh2
dt
, (2.23)
(yhtt,wh) + (divph,wh) = (f+uh,wh), ∀wh∈Wh,t∈J, (2.24)
(ph,vh) – (y˜h,divvh) = 0, ∀vh∈Vh,t∈J, (2.25)
(divp˜h,wh) = (˜yh,wh), ∀wh∈Wh,t∈J, (2.26)
(p˜h,vh) – (yh,divvh) = 0, ∀vh∈Vh,t∈J, (2.27)
yh(x, 0) =yh0(x), ∀x∈Ω, (2.28)
yht(x, 0) =yh1(x), ∀x∈Ω, (2.29)
where yh
and (p˜h,yh,ph,y˜h,uh) is the solution of (2.23)–(2.29) if and only if there is a co-state
(q˜h,zh,qh,˜zh) such that the following optimality conditions hold:
(yhtt,wh) + (divph,wh) = (f+uh,wh), ∀wh∈Wh,t∈J, (2.30)
(ph,vh) – (y˜h,divvh) = 0, ∀vh∈Vh,t∈J, (2.31)
(divp˜h,wh) = (˜yh,wh), ∀wh∈Wh,t∈J, (2.32)
(p˜h,vh) – (yh,divvh) = 0, ∀vh∈Vh,t∈J, (2.33)
yh(x, 0) =yh0(x), ∀x∈Ω, (2.34)
yht(x, 0) =yh1(x), ∀x∈Ω, (2.35)
(zhtt,wh) + (divqh,wh) = (yh–yd,wh), ∀wh∈Wh,t∈J, (2.36)
(qh,vh) – (z˜h,divvh) = 0, ∀vh∈Vh,t∈J, (2.37)
(divq˜h,wh) = (˜yh+˜zh,wh), ∀wh∈Wh,t∈J, (2.38)
(q˜h,vh) – (zh,divvh) = 0, ∀vh∈Vh,t∈J, (2.39)
zh(x,T) = 0, ∀x∈Ω, (2.40)
zht(x,T) = 0, ∀x∈Ω, (2.41)
T
0
(uh+zh,u˜h–uh)dt≥0, ∀˜uh∈Kh. (2.42)
For Lemma2.1, the relationship betweenuhandzhis given as follows:
uh=max{0,zˇh}–zh, (2.43)
wherezˇh=
T
0
Ωzhdx dt
T
0
Ω1dx dt
is the integral average onΩ×Jof the functionzh.
Now, we give the local definition of divh, curlh : H1(Th)2 →L2(Ω) and ∇h, Curlh :
H1(T
h)→L2(Ω)2, such that for anyT∈Th
divhv|T:=div(v|T), curlhv|T:=curl(v|T), (2.44)
∇hv|T:=∇(v|T), Curlhv|T:=Curl(v|T). (2.45)
SetPh:W→Whto be the orthogonalL2(Ω)-projection intoWh[2], which satisfies
(Phw–w,χ) = 0, w∈W,χ∈Wh, (2.46)
Phw–w0,q≤Chtwt,q, 0≤t≤k+ 1, ifw∈W∩Wt,q(Ω), (2.47)
Phw–w–r≤Chr+twt, 0≤r,t≤k+ 1, ifw∈Ht(Ω). (2.48)
Next, introduce the Fortin projection (see [3] and [10])Πh:V→Vh, which satisfies: for
anyq∈V
div(Πhq–q),wh
= 0, ∀q∈V,wh∈Wh, (2.49)
q–Πhq0,q≤Chrqr,q, 1/q<r≤k+ 1,∀q∈V∩
Wr,q(Ω)2, (2.50)
The commuting diagram property reads
div◦Πh=Ph◦div:V→Wh and div(I–Πh)V⊥Wh, (2.52)
whereIdenotes the identity operator.
Next, the intermediate variableu˜∈Kis introduced as follows:
ytt(u),˜ w
+divp(u),˜ w= (f+u,˜ w), ∀w∈W,t∈J, (2.53)
p(u),˜ v–y(˜u),˜ divv= 0, ∀v∈V,t∈J, (2.54)
divp˜(u),˜ w=y(˜ u),˜ w, ∀w∈W,t∈J, (2.55)
˜
p(u),˜ v–y(u),˜ divv= 0, ∀v∈V,t∈J, (2.56)
y(u)(x, 0) =˜ y0(x), ∀x∈Ω, (2.57)
yt(u)(x, 0) =˜ y1(x), ∀x∈Ω, (2.58)
ztt(u),˜ w
+divq(u),˜ w=y(u) –˜ yd,w
, ∀w∈W,t∈J, (2.59)
q(u),˜ v–z(˜u),˜ divv= 0, ∀v∈V,t∈J, (2.60)
divq˜(u),˜ w=y(˜ u) +˜ z(˜u),˜ w, ∀w∈W,t∈J, (2.61)
˜
q(u),˜ v–z(u),˜ divv= 0, ∀v∈V,t∈J, (2.62)
z(u)(x,˜ T) = 0, ∀x∈Ω, (2.63)
zt(u)(x,˜ T) = 0, ∀x∈Ω. (2.64)
Next, we present mixed elliptic constructions (p˜¯,y,¯ p¯,y,˜¯ q˜¯,z,¯ q¯,z)˜¯ ∈(V×W)4:
(p˜¯,v) – (y,¯ divv) = 0, ∀v∈V, (2.65)
(divp˜¯,w) = (y˜h,w), ∀w∈W, (2.66)
(p¯,v) – (y,˜¯ divv) = 0, ∀v∈V, (2.67)
(divp¯,w) = (f +uh–yhtt,w), ∀w∈W, (2.68)
(q˜¯,v) – (¯z,divv) = 0, ∀v∈V, (2.69)
(divq˜¯,w) = (z˜h+y˜h,w), ∀w∈W, (2.70)
(q¯,v) – (˜¯z,divv) = 0, ∀v∈V, (2.71)
(divq¯,w) = (yh–yd–zhtt,w), ∀w∈W. (2.72)
For simplicity of presentation, we resolve the errors in following forms:
˜
p–p˜h=p˜–p˜(uh) +p˜(uh) –p˜¯+p˜¯–p˜h=r1+e1+η1, (2.73)
y–yh=y–y(uh) +y(uh) –y¯+¯y–yh=r2+e2+η2, (2.74)
p–ph=p–p(uh) +p(uh) –p¯+p¯–ph=r3+e3+η3, (2.75)
˜
˜
q–q˜h=q˜–q˜(uh) +q˜(uh) –q˜¯+q˜¯–q˜h=r5+e5+η5, (2.77)
z–zh=z–z(uh) +z(uh) –z¯+¯z–zh=r6+e6+η6, (2.78)
q–qh=q–q(uh) +q(uh) –q¯+q¯–qh=r7+e7+η7, (2.79)
˜
z–z˜h=z˜–z(u˜ h) +z(u˜ h) –z˜¯+˜¯z–˜zh=r8+e8+η8. (2.80)
From mixed elliptic reconstructions [24], we derive the error estimates as below.
Lemma 2.2 ([8, 14]) For Raviart–Thomas elements, there exists a positive constant C which depends the domainΩ,the shape regularity of the elements and polynomial degree k such that
η2 ≤C
h1+min{1,k}(divp˜h–y˜h)+ min wh∈Wh
h(p˜h–∇hwh), (2.81)
η2t ≤C
h1+min{1,k}(divp˜ht–y˜ht)+ min wh∈Wh
h(p˜ht–∇hwh), (2.82)
η2tt ≤C
h1+min{1,k}(divp˜htt–y˜htt)+ min wh∈Wh
h(p˜htt–∇hwh), (2.83)
η2ttt ≤C
h1+min{1,k}(divp˜
httt–y˜httt)+ min wh∈Wh
h(p˜httt–∇hwh), (2.84)
η4 ≤C
h1+min{1,k}(yhtt+divph–f –uh)+ min wh∈Wh
h(ph–∇hwh), (2.85)
η4t ≤C
h1+min{1,k}(yhtt+divph–f–uh)t+ min wh∈Wh
h(pht–∇hwh), (2.86)
η4tt ≤C
h1+min{1,k}(yhtt+divph–f –uh)tt+ min wh∈Wh
h(phtt–∇hwh), (2.87)
η6 ≤C
h1+min{1,k}(divq˜h–y˜h–z˜h)+ min wh∈Wh
h(q˜h–∇hwh), (2.88)
η6t ≤C
h1+min{1,k}(divq˜ht–y˜ht–z˜ht)+ min wh∈Wh
h(q˜ht–∇hwh), (2.89)
η6tt ≤C
h1+min{1,k}(divq˜htt–y˜htt–z˜htt)+ min wh∈Wh
h(q˜htt–∇hwh), (2.90)
η8 ≤C
h1+min{1,k}(zhtt+divqh–yh+yd)+ min wh∈Wh
h(qh–∇hwh), (2.91)
η8t ≤C
h1+min{1,k}(zhtt+divqh–yh+yd)t+ min wh∈Wh
h(qht–∇hwh), (2.92)
η1 ≤Ch 1 2J(p˜
h·t)0,Γh+hcurlhp˜h+h(divp˜h–y˜h), (2.93)
η3 ≤Ch 1 2J(p
h·t)0,Γh+hcurlhph+h(yhtt+divph–f –uh), (2.94)
η5 ≤Ch 1 2J(q˜
h·t)0,Γh+hcurlhq˜h+h(divq˜h–y˜h–y˜h), (2.95)
η7 ≤Ch 1 2J(q
h·t)0,Γh+hcurlhqh+
h(zhtt+divqh–yh+yd), (2.96)
divη1 ≤Cdivp˜h–y˜h,divη3 ≤Cyhtt+divph–f –uh, (2.97)
divη5 ≤Cdivq˜h–y˜h–z˜h,divη7 ≤Czhtt+divqh–yh+yd, (2.98)
where∇handcurlhhave been defined in(2.44)–(2.45),J(v·t)denotes the jump ofv·tacross
3 Error estimation of optimal control
In this part, a posteriori error estimation of optimal control problems shall be given. From (2.53)–(2.56) and (2.65)–(2.68), we obtain the error equations
(e1,v) – (e2,divv) = 0, ∀v∈V, (3.1)
(dive1,w) = (e4+η4,w), ∀w∈W, (3.2)
(e3,v) – (e4,divv) = 0, ∀v∈V, (3.3)
(e2tt,w) + (dive3,w) = –(η2tt,w), ∀w∈W. (3.4)
Lemma 3.1 Let e1–e4satisfy(3.1)–(3.4).Then we have
e2L∞(J;L2(Ω))+e1L∞(J;H(div;Ω))+e4L∞(J;L2(Ω))+e3L∞(J;H(div;Ω))
≤Cη4tL2(J;L2(Ω))+y1–yh1+η2t(0)+y0+y˜h(0)+η4L∞(J;L2(Ω))
+η2ttL∞(J;L2(Ω))+η2tttL2(J;L2(Ω))+η4ttL2(J;L2(Ω))+y0–yh0
+divη3(0)+2y0–divph(0)
+y1+y˜ht(0)+η4t(0)) +η2(0)). (3.5)
Proof Differentiating (3.1)–(3.2) with respect tot, we get
(e1t,v) – (e2t,divv) = 0, ∀v∈V, (3.6)
(dive1t,w) = (e4t+η4t,w), ∀w∈W. (3.7)
We choosev=e3in (3.6),w= –e4in (3.7),v= –e1tin (3.3) andw=e2tin (3.4), separately,
then add up the four equations and obtain
(e2t,e2tt) + (e4t,e4) = –(η4t,e4) – (η2tt,e2t). (3.8)
We integrate (3.8) from 0 tot, use Gronwall’s inequality and the Cauchy inequality, then we obtain
e4L∞(J;L2(Ω))+e2tL∞(J;L2(Ω))
≤Cη4tL2(J;L2(Ω))+η2ttL2(J;L2(Ω))+e2t(0)+e4(0), (3.9)
where
e2t(0)≤y1–yh1+η2t(0), (3.10)
e4(0)≤y0+y˜h(0)+η4(0). (3.11)
Note that t
0
then we have
e2 ≤Ce2tL∞(J;L2(Ω))+e2(0)
≤Ce2tL∞(J;L2(Ω))+y0–yh0+η2(0). (3.12)
Lettingv=e1in (3.1),w=e2in (3.2),v=e3in (3.3) andw=e4in (3.4), respectively. We get
e1L∞(J;L2(Ω))≤ η4L∞(J;L2(Ω))+e4L∞(J;L2(Ω))+e2L∞(J;L2(Ω)), (3.13)
e3L∞(J;L2(Ω))≤ e2ttL∞(J;L2(Ω))+η2ttL∞(J;L2(Ω))+e4L∞(J;L2(Ω)). (3.14)
Differentiating (3.3)–(3.4) and (3.6)–(3.7) with respect tot, we get
(e3t,v) – (e4t,divv) = 0, ∀v∈V, (3.15)
(e2ttt,w) + (dive3t,w) = –(η2ttt,w), ∀w∈W, (3.16)
(e1tt,v) – (e2tt,divv) = 0, ∀v∈V, (3.17)
(dive1tt,w) = (e4tt+η4tt,w), ∀w∈W. (3.18)
We choosev= –e1tt in (3.15),w=e2ttin (3.16),v=e3tin (3.17),w= –e4t in (3.18),
sepa-rately. We derive the following after addition for four equations:
(e2ttt,e2tt) + (e4tt,e4t) = –(η4tt,e4t) – (η2ttt,e2tt). (3.19)
Similar to (3.9), we derive
e2ttL∞(J;L2(Ω))+e4tL∞(J;L2(Ω))
≤Cη2tttL2(J;L2(Ω))+η4ttL2(J;L2(Ω))+e2tt(0)+e4t(0). (3.20)
Takingt= 0 andw=e2tt(0) in (3.4) leads to
e2tt(0)≤dive3(0)+η2tt(0)
≤divη3(0)+η2tt(0)+2y0–divph(0). (3.21)
Note that
e4t(0)≤y˜t(uh)(0) –y˜ht(0)+η4t(0)
≤y1+y˜ht(0)+η4t(0). (3.22)
At last, settingw=dive1andw=dive3in (3.2) and (3.4), we get
dive1L∞(J;L2(Ω))≤ η4L∞(J;L2(Ω))+e4L∞(J;L2(Ω)), (3.23)
dive3L∞(J;L∞(Ω))≤ e2ttL∞(J;L2(Ω))+η2ttL∞(J;L2(Ω)). (3.24)
By (2.59)–(2.62) and (2.69)–(2.72), we obtain the error equations
(e5,v) – (e6,divv) = 0, ∀v∈V, (3.25)
(dive5,w) = (e4+e8+η4+η8,w), ∀w∈W, (3.26)
(e7,v) – (e8,divv) = 0, ∀v∈V, (3.27)
(e6tt,w) + (dive7,w) = (η6tt+η2+e2,w), ∀w∈W. (3.28)
Lemma 3.2 Let e5–e8satisfy(3.25)–(3.28).Then we get
e6L∞(J;L2(Ω))+e5L∞(J;H(div;Ω))+e8L∞(J;L2(Ω))+e7L2(J;H(div;Ω))
≤Cη4L∞(J;L2(Ω))+η4tL2(J;L2(Ω))+η4ttL2(J;L2(Ω))+η2L2(J;L2(Ω))
+η6ttL2(J;L2(Ω))+η8L∞(J;L2(Ω))+η8tL2(J;L2(Ω))+η2tttL2(J;L2(Ω))
+e4L∞(J;L2(Ω))+e2L2(J;L2(Ω))+y1+y˜ht(0)+η4t(0)
+divη3(0)+η2tt(0)+2y0–divph(0). (3.29)
Proof At first, settingt=T in (2.69)–(2.70) and (3.25)–(3.26), we derive
e6(T) =e6t(T) = 0 (3.30)
and
e8(T)≤Ce4(T)+η4(T)+η8(T). (3.31)
Differentiating (3.25)–(3.26) with respect tot, we obtain
(e5t,v) – (e6t,divv) = 0, ∀v∈V, (3.32)
(dive5t,w) = (e4t+e8t+η4t+η8t,w), ∀w∈W. (3.33)
Letv= –e7in (3.32),w=e8in (3.33),v=e5t in (3.27) andw= –e6tin (3.28), separately.
After adding up the new equations, we have
–(e6tt,e6t) – (e8t,e8) = (e4t+η4t+η8t,e8) – (η6tt+η2+e2,e6t). (3.34)
Integrating (3.34) fromttoT, from (3.30), Gronwall’s inequality and the Cauchy inequal-ity, it is easy to see that
e6tL∞(J;L2(Ω))+e8L∞(J;L2(Ω))
≤Cη4tL2(J;L2(Ω))+e4tL2(J;L2(Ω))+η8tL2(J;L2(Ω))
+e2L2(J;L2(Ω))+η2L2(J;L2(Ω))+η6ttL2(J;L2(Ω))+e8(T). (3.35)
Lettingv=e7in (3.27), we get
Next, for (3.25), we differentiate two times with respect tot, and setv=e7. for (3.26), we also differentiate two times with respect tot, and setw=e8. For (3.27), we setv=e5tt.
For (3.28), we setw=dive7. Combining the new four equalities, we derive
dive7L2(J;L2(Ω))≤C
e2L2(J;L2(Ω))+η6ttL2(J;L2(Ω))+η2L2(J;L2(Ω))+η4tL∞(J;L2(Ω))
+η8tL∞(J;L2(Ω))
+e4L2(J;L2(Ω))) +e8tL2(J;L2(Ω))). (3.37)
At last, similar to (3.13)–(3.14), (3.23)–(3.24) and (3.36), we have
e5L∞(J;H(div;Ω))≤C
e4L∞(J;L2(Ω))+e8L∞(J;L2(Ω))
+η4L∞(J;L2(Ω))+η8L∞(J;L2(Ω))
+e6L∞(J;L2(Ω))), (3.38)
e7L2(J;H(div;Ω))
≤Ce2L2(J;L2(Ω))+η6ttL2(J;L2(Ω))+η2L2(J;L2(Ω))+η4tL∞(J;L2(Ω))
+η8tL∞(J;L2(Ω))+e4L2(J;L2(Ω))
+e8tL2(J;L2(Ω))+e8L2(J;L2(Ω))). (3.39)
Thus, combining Lemma3.1, (3.31), (3.35)–(3.40) and (3.5), we complete the proof.
Choosingu˜=uandu˜=uhin (2.53)–(2.64), respectively, we have the error equations
(r1,v) – (r2,divv) = 0, ∀v∈V, (3.40)
(divr1,w) = (r4,w), ∀w∈W, (3.41)
(r3,v) – (r4,divv) = 0, ∀v∈V, (3.42)
(r2tt,w) + (divr3,w) = (u–uh,w), ∀w∈W, (3.43)
(r5,v) – (r6,divv) = 0, ∀v∈V, (3.44)
(divr5,w) = (r4+r8,w), ∀w∈W, (3.45)
(r7,v) – (r8,divv) = 0, ∀v∈V, (3.46)
(r6tt,w) + (divr7,w) = (r2,w), ∀w∈W. (3.47)
Similar to Lemmas3.1and3.2, Lemma3.3is given below.
Lemma 3.3 Let r1–r8satisfy(3.40)–(3.47).Then we have
r2tL∞(J;L2(Ω))+r4L∞(J;L2(Ω))+r1L∞(J;H(div;Ω))+r3L2(J;H(div;Ω))
≤Cu–uhL2(J;L2(Ω)), (3.48)
r4tL∞(J;L2Ω))+r6tL∞(J;L2Ω))+r8L∞(J;L2(Ω))
≤u(0) –uh(0)
+Cu–uhL2(J;L2(Ω))+(u–uh)t
r5L∞(J;H(div;Ω))+r7L2(J;H(div;Ω))
≤u(0) –uh(0)
+Cu–uhL2(J;L2(Ω))+(u–uh)tL2(J;L2(Ω)), (3.50)
whereis an arbitrary small positive constant.
Lemma 3.4 [15]Let(p˜,y,p,y,˜ q˜,z,q,z,˜ u)and(p˜h,yh,ph,y˜h,q˜h,zh,qh,uh)be the solutions
of(2.10)–(2.22)and(2.30)–(2.42),respectively.Suppose that(uh+zh)|τ ∈H1(τ)and that
there exists w∈Khsuch that
u–uhL2(J;L2(Ω))≤C(θ+zh–z(uh)
L2(J;L2(Ω)), (3.51)
where
θ=
T
0
τ
h2τ|uh+zh|2H1(τ)dt 1
2 .
Now, by Lemmas3.1–3.3, the important result of this paper is given as follows.
Theorem 3.1 Let(y,p˜,˜y,p,z,q˜,z,˜ q,u)and(yh,p˜h,˜yh,ph,zh,q˜h,z˜h,qh,uh)be the solutions
of(2.9)–(2.19)and(2.26)–(2.36),respectively.Then we have
u–uhL∞(J;L2(Ω))+y–yhL∞(J;L2(Ω))+˜y–y˜hL∞(J;L2(Ω))
+˜p–p˜hL∞(J;H(div;Ω))+p–phL∞(J;H(div;Ω))+z–zhL∞(J;L2(Ω))
+˜z–z˜hL∞(J;L2(Ω))+˜q–q˜hL∞(J;H(div;Ω))+q–qhL2(J;H(div;Ω))
≤Cη1L∞(J;H(div;Ω))+η3L∞(J;H(div;Ω))+η5L∞(J;H(div;Ω))+η7L2(J;H(div;Ω))
+η4L∞(J;L2(Ω))+η4tL2(J;L2(Ω))+η4ttL2(J;L2(Ω))+η2L2(J;L2(Ω))
+η2ttL∞(J;L2(Ω))+η2tttL2(J;L2(Ω))+η6L∞(J;L2(Ω))+η6tL2(J;L2(Ω))
+η6ttL2(J;L2(Ω))+η8L∞(J;L2(Ω))+η8tL2(J;L2(Ω))+y0–yh0
+y0+y˜h(0)+y1–yh1+divη3(0)+2y0–divph(0)
+y1+y˜ht(0)+η2(0)+η2t(0)+η4t(0). (3.52)
Proof From Lemma2.1and (2.43), we have
u(0) –uh(0)≤ u–uhL∞(J;L2(Ω))≤Cz–zhL∞(J;L2(Ω)), (3.53) (u–uh)tL2(J;L2(Ω))=(z–zh)tL2(J;L2(Ω))
≤ e6tL2(J;L2(Ω))+η6tL2(J;L2(Ω))+r6tL2(J;L2(Ω)). (3.54)
For sufficiently small, using Lemmas3.1–3.3and (3.35), (3.53)–(3.54), we complete the
4 Conclusion and future work
In the article, using semidiscrete Raviart–Thomas mixed finite element methods, we stud-ied fourth order hyperbolic equations of quadratic problems for optimal control, and then got the posteriori error estimates. In subsequent work, an a posteriori estimation will be considered by a fully discrete approximation of the mixed finite element. Of course, the error estimates of the same problems certainly also can be discussed with nonlinear fourth order hyperbolic equations.
Acknowledgements
The authors express their thanks to the referees for their helpful suggestions, which led to improvements of the presentation.
Funding
This work is supported by Youth Innovative Talents Project (Natural Science) of research on humanities and social sciences in Guangdong normal university (2017KQNCX265), The issue for the 13th Five-Year plan for the development of philosophy and social sciences in Guangzhou of 2018 (2018GZGJ168), School projects of Huashang College Guangdong University of Finance and Economics.
Availability of data and materials
Data sharing not applicable to this article as no datasets were generated or analyzed during the current study.
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
CH, ZG and LG participated in the sequence alignment and drafted the manuscript. All authors read and approved the final manuscript.
Publisher’s Note
Springer Nature remains neutral with regard to jurisdictional claims in published maps and institutional affiliations.
Received: 20 July 2017 Accepted: 7 May 2019
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