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© 2017, IRJET | Impact Factor value: 5.181 | ISO 9001:2008 Certified Journal

| Page 2365

A NEW SUB CLASS OF UNIVALENT ANALYTIC FUNCTIONS ASSOCIATED

WITH A MULTIPLIER LINEAR OPERATOR

DR. JITENDRA AWASTHI

DEPARTMENT OF MATHEMATICS

,

S.J.N.P.G.COLLEGE, LUCKNOW-226001

---***---ABSTRACT: This paper deals with a new class

km,

(

,

A

,

B

)

which is a subclass of uniformly starlikefunctions involving a multiplier linear operator m

k,

. Coefficients inequality, Distortion theorem, Extreme points, Radius of starlikeness and radius of convexity for functions belonging to this class are obtained.

Key words and phrases: Univalent, starlike, subordination, convex, analytic, linear operator. 2010 Mathematics Subject Classification: 30C45. 1. INTRODUCTION

Let S denote the class of functions of the form

2

,

)

(

)

1

.

1

(

n n n

z

a

z

z

f

which are analytic and univalent in the unit open disk ∆={z: |z|<1}.

Silverman[9] had introduced and studied a subclass T of S consisting of functions of the form

2

)

2

,

0

(

,

)

(

)

2

.

1

(

n

n n

n

z

a

n

a

z

z

f

Let f and g be analytic in ∆.Then g is said to be subordinate to f, written as

f(z)

g(z)

or

f

g

, if there exists a Schwartz function ω, which is analytic in ∆ with ω(0)=0 and

(

z

)

1

(

z

)

such that

g

(

z

)

f

(

(

z

))

(z

).

In particular, if the function f is univalent in ∆, we have the following equivalence([3],[7])

).

f(

)

g(

and

f(0)

g(0)

)

(z

)

(

)

(

z

f

z

g

Sharma and Raina ([4],[5],[6]) have introduced a multiplier linear operator m k,

for

by

0

,

1

,

Z

k

m

(1.3)

 

  

    

..]

,...

2

,

1

{

,

)

(

1

)

(

,...}

2

,

1

{

Z

m

,

)

(

1

)

(

0,

m

),

(

)

(

1 , 1 1 1

2 ,

-0

1 , 2 1 1 1 ,

,

Z

m

z

f

z

dt

d

z

k

z

f

dt

t

f

t

z

k

z

f

z

f

z

f

m k k k

m k

z

m k k k m

k m k

 

 

 

 

The series representation of

mk,

f

(

z

)

for f(z) of the form (1.1) is given by





2

k,

,

1

)

1

(

1

)

(

(1.4)

n

n n m m

z

a

n

k

z

z

f

Also

[1]

0

,

)

(

i

mk,0

D

km

m

[8]

0

,

)

(2)

© 2017, IRJET | Impact Factor value: 5.181 | ISO 9001:2008 Certified Journal

| Page 2366

[10]

0

,

)

(

iii

1m,1

D

m

m

[2]

0

,

)

(

iv

1m,

I

m

m

Involving the operator m k,

, we define a class

T

km,

,

A

,

B

as follows:

Definition 1.1: For fixed A, B,

1

B

A

1

,

0

A

1

,

0

1

,

z

,

a function

f

T

is said to be in class

)

,

,

(

,

A

B

T

km

if

.

,

1

)]

(

)

1

{(

[

1

)

(

)

(

)

6

.

1

(

,

,

z

Bz

z

B

A

B

z

f

z

f

z

m k m

k

 

From the definition, it follows that

f

T

km,

(

,

A

,

B

)

if there exists a function w(z) analytic in ∆ and satisfies w(0)=0 and

1

)

(

z

w

for

z

,

such that

.

,

)

(

1

)

(

)]

(

)

1

{(

[

1

)

(

)

(

,

,

z

z

Bw

z

w

B

A

B

z

f

z

f

z

m k m

k

 

or equivalently

1

,

.

)

(

)

(

)

(

)

1

{(

1

)

(

)

(

)

7

.

1

(

, , ,

,

z

z

f

z

f

z

B

B

A

B

z

f

z

f

z

m k m k m

k m k

  

The main object of this paper is to obtain necessary and sufficient conditions for the functions

f

(

z

)

T

km,

(

,

A

,

B

)

. Furthermore we obtain extreme points, distortion bounds, Closure properties, radius of starlikeness and convexity for

f

(

z

)

T

km,

(

,

A

,

B

).

2. COEFFICIENTS INEQUALITY

Theorem2.1: A necessary and sufficient condition for f(z) of the form (1.1) to be in the class

km,

(

,

A

,

B

)

is that

2

,

(

)

(

1

)

(

)

.

]

)

(

)

1

(

)

1

)(

1

[(

)

1

.

2

(

n

n m

k

n

a

A

B

B

A

B

n

).

1

0

,

1

0

,

1

1

(

1

)

1

(

1

)

(

,





n

k

n

for

B

A

A

where

m m

k

Proof: Assume that the inequality (2.1) holds true and |z|=1.Then we have

,

f

(

z

)

,

f

(

z

)

,

f

(

z

)

B

(

1

)

(

A

B

)

Bz

,

f

(

z

)

z

mk mk mk

mk

 

 

2 , 2

,

2 , 2

,

)

(

)

(

)

1

(

)

(

)

(

)

(

n

n n m k n

n n m k

n

n n m k n

n n m k

z

a

n

n

z

B

B

A

B

z

a

n

z

z

a

n

z

z

a

n

n

z

 

 

(3)

© 2017, IRJET | Impact Factor value: 5.181 | ISO 9001:2008 Certified Journal

| Page 2367

     

2 , 2 , 2 ,

)

(

)

(

)

(

)

1

(

)

(

)

1

(

)

(

)

1

(

n n n m k n n n m k n n n m k

z

a

n

n

B

z

a

n

B

A

B

z

B

A

z

a

n

n

  

   

2 , 2

,

(

)

(

1

)

(

)

[

(

1

)

(

1

)

(

)

]

(

)

)

1

(

n n m k n n m

k

n

a

A

B

B

n

A

B

n

a

n

(

1

)

(

)

]

(

)

(

1

)

(

)

0

.

)

1

)(

1

[(

2 ,

 

B

A

a

n

B

A

B

n

n n m

k

: Conversely, suppose that the function

f(z) defined by(1.1) be in the class

T

km,

(

,

A

,

B

).

Then from (2.1), we have

)

(

)

(

)

(

)

1

{(

1

)

(

)

(

, , , ,

z

f

z

f

z

B

B

A

B

z

f

z

f

z

m k m k m k m k    

)

(

)

(

)}]

(

)

1

{(

[

)

(

)

(

, , , ,

z

f

Bz

z

f

B

A

B

z

f

z

f

z

m k m k m k m k    

.

1

)

(

)

(

)}]

(

)

1

{(

[

)

(

)

1

(

2 , 2 , 2 ,

      n n n m k n n n m k n n n m k

z

a

n

n

z

B

z

a

n

z

B

A

B

z

a

n

n

  

Since

Re(

z

)

z

for all, we have

1

)

(

)}]

(

)

1

{(

)

1

(

[

)}

(

)

1

{(

)

(

)

1

(

Re

)

2

.

2

(

2 , 2 ,





    n n n m k n n n m k

z

a

n

B

A

n

B

z

B

A

z

a

n

n

 

We choose the value of z on the real axis so that

)

(

)

(

, ,

z

f

z

f

z

m k m k  

is real. Upon clearingthe denominator of (2. 2) and letting

z

1

, we can write (2.2) as

 

2

,

(

)

(

1

)

(

)

..

]

)

(

)

1

(

)

1

)(

1

[(

n n m

k

n

a

A

B

B

A

B

n

Thus (2.1) proves the theorem.

The result is sharp. The extremal function being

(

1

)

(

)

]

(

)

,

2

.

)

1

)(

1

[(

)

(

)

1

(

)

(

)

3

.

2

(

,

z

n

n

B

A

B

n

B

A

z

z

f

m n

(4)

© 2017, IRJET | Impact Factor value: 5.181 | ISO 9001:2008 Certified Journal

| Page 2368

Corollary 2.2: Let the function f(z) defined by(1.1) be in the class

T

km,

(

,

A

,

B

)

.Then (2.4)

(

1

)

(

)

]

(

)

,

2

.

)

1

)(

1

[(

)}

(

)

1

{(

,

n

n

B

A

B

n

B

A

a

m

k n

3. DISTORTION THEOREMS

Theorem3.1: If f (z)

T

km,

(

,

A

,

B

)

, then for

N

n

z

k

B

A

B

B

A

z

f

m





,

1

1

]

)

(

)

1

(

)

1

[(

)}

(

)

1

{(

(z)

)

1

.

3

(

2

and

(

1

)

(

)

]

,

.

)

1

[(

)}

(

)

1

{(

)

(

)

2

.

3

(

mk,

z

2

n

N

B

A

B

B

A

z

z

f

Proof: In view of inequality (2.1), it follows that

2

,

(

)

(

1

)

(

)

.

]

)

(

)

1

(

)

1

)(

1

[(

n

n m

k

n

a

A

B

B

A

B

n

.

2

,

1

1

]

)

(

)

1

(

)

1

)(

1

[(

)}

(

)

1

{(

or

(3.3)

2





n

k

B

A

B

n

B

A

a

m

n n

Therefore

)

(

2 2

2

 

n n n

n

n

z

z

z

a

a

z

z

f

or

2

1

1

]

)

(

)

1

(

)

1

[(

)}

(

)

1

{(

z

f(z)

(3.4)

z

k

B

A

B

B

A

m





and

or

)

(

2 2

2

 

n n n

n

n

z

z

z

a

a

z

z

f

2

1

1

]

)

(

)

1

(

)

1

[(

)}

(

)

1

{(

z

f(z)

(3.5)

z

k

B

A

B

B

A

m





From (3.4) and (3.5) inequality (3.1) follows.

Further for f (z)

T

km,

(

,

A

,

B

)

, the inequality (2.1) gives

2

,

(

)

(

1

)

(

)

.

]

)

(

)

1

(

)

1

[(

n

n m

k

n

a

A

B

B

A

(5)

© 2017, IRJET | Impact Factor value: 5.181 | ISO 9001:2008 Certified Journal

| Page 2369

,

2

.

]

)

(

)

1

(

)

1

[(

)}

(

)

1

{(

)

(

or

(3.6)

2

,

n

B

A

B

B

A

a

n

n

n m

k

Thus,

 

2 , 2

2 ,

,

(

)

(

)

(

)

n

n m k n

n n m k m

k

f

z

z

n

a

z

z

z

n

a

or (3.7)

2

,

]

)

(

)

1

(

)

1

[(

)}

(

)

1

{(

z

)

(

z

B

A

B

B

A

z

f

m

k

And

 

2 , 2

2 ,

,

(

)

(

)

(

)

n

n m k n

n n m k m

k

f

z

z

n

a

z

z

z

n

a

or

(3.8) ,

2

]

)

(

)

1

(

)

1

[(

)}

(

)

1

{(

z

)

(

z

B

A

B

B

A

z

f

m

k

On using (3.7) and (3.8) inequality (3.2) follows. 4. EXTREME POINTS

Theorem 4.1: Let

(4.1)

f

1

(

z

)

z

and

n m k

n

z

n

B

A

B

n

B

A

z

z

f

)

(

]

)

(

)

1

(

)

1

)(

1

[(

)}

(

)

1

{(

)

(

,

for n

2,then f (z)

T

km,

(

,

A

,

B

)

, if and only if it can be expressed in the form

(4.2)

1

)

(

)

(

n n n

f

z

d

z

f

, where

d

n

0

and

1

.

1

n n

d

In particular the extreme points of

T

km,

(

,

A

,

B

)

are the functions given by (4.1). Proof: Let f(z) be expressed in the form (4.1),then

1 2

[(

1

)(

1

)

(

1

)

(

)

]

,

(

)

)}

(

)

1

{(

)

(

)

(

n n

n m k n

n

z

n

B

A

B

n

B

A

z

z

f

d

z

f

2

n

n n n

b

z

d

z

Where

(

1

)

(

)

]

(

)

)

1

)(

1

[(

)}

(

)

1

{(

,

n

B

A

B

n

B

A

b

m

k n

Now, since

2 2

,

(

)

{(

1

)

(

)}

]

)

(

)

1

(

)

1

)(

1

[(

n

n n

n n m

k

n

d

b

A

B

d

B

A

B

n

{(

1

)

(

A

B

)}(

1

d

1

)

{(

1

)

(

A

B

)}.

Therefore, f (z)

T

km,

(

,

A

,

B

)

.

Conversely, let f (z)

T

km,

(

,

A

,

B

)

, then (2.1) yields

m n

k

n

z

n

B

A

B

n

B

A

a

)

(

]

)

(

)

1

(

)

1

)(

1

[(

)}

(

)

1

{(

,

(6)

© 2017, IRJET | Impact Factor value: 5.181 | ISO 9001:2008 Certified Journal

| Page 2370

Setting

n

m k

n

a

B

A

n

B

A

B

n

d

)}

(

)

1

{(

)

(

]

)

(

)

1

(

)

1

)(

1

[(

,

for

n

2

And

2 1

1

n n

d

d

.

Then

2

[(

1

)(

1

)

(

1

)

(

)

]

,

(

)

)}

(

)

1

{(

)

(

n

n n m k

z

d

n

B

A

B

n

B

A

z

z

f

2

)}

(

{

n

n n

z

f

z

d

z

2 2 1

).

(

)

(

)

1

(

n n n

n n n

n

n

d

f

z

d

f

z

d

z

This completes the proof. 5. RADIUS OF STARLIKENESS

THEOREM 5.1: Let f (z) , then f(z) is starlike in

z

r

(

,

A

,

B

),

where

(5.1)

,

2

.

)}

(

)

1

{(

)

(

]

)

(

)

1

(

)

1

)(

1

[(

inf

1 1

,

n

B

A

n

n

B

A

B

n

r

n m k

Proof: It suffices to show that

1

1

)

(

)

(

z

f

z

f

z

i.e.

1

1

)

1

(

1

)

(

)

(

2

1 1

2

  

n

n n

n

n

n

z

a

z

a

n

z

f

z

f

z

(5.2) or

2

1

.

1

n

n n

z

na

It is easily to see that (5.1) holds if

.

)}

(

)

1

{(

)

(

]

)

(

)

1

(

)

1

)(

1

[(

,

1

B

A

n

n

B

A

B

n

z

m k n

This completes the proof. 6. RADIUS OF CONVEXITY

THEOREM 6.1: Let f (z) , then f(z) is convex in

z

r

(

,

A

,

B

),

where

(6.1)

,

2

.

)}

(

)

1

{(

)

(

]

)

(

)

1

(

)

1

)(

1

[(

inf

1 1

2

,

n

B

A

n

n

B

A

B

n

r

n m k

(7)

© 2017, IRJET | Impact Factor value: 5.181 | ISO 9001:2008 Certified Journal

| Page 2371

REFERANCES

[1]. Al-Oboudi, F.M., “On univalent functions defined by a generalized Salageon operator”. Indian J. Math, Math. Sci. 25-28(2004), 1429-1436.

[2]. Cho, N.E. and Kim, T.H., “Multiplier transformations and strongly close-to-convex functions”, Bull. Korean Math. Soc. 40(2003), 399-410.

[3].Owa,S. and Srivastava,H.M., “Univalent and starlike generalized hypergeometric functions”. Canad.J.Math.,39(5)(1987),1057-1077.

[4].Raina, R.K. and Sharma, P., “Subordination properties of univalent functions involving a new class of operators”,Electr. J. Math. Anal. App. 2(1), (2014),37-52.

[5].Raina, R.K. and Sharma, P., “Subordination preserving properties associated with a class of operators”, Le Mathematiche 68(1),(2013),217-228.

[6].Raina, R.K., Sharma, P. and Sokol,J. “Certain subordination results involving a class of operators”. Analele Univ. Oradea Fasc. Matematica 21(2),(2014),89-99.

[7]. RUSCHEWEYH S., “Neighborhoods of Univalent Functions”, Proc. Amer. Math., Soc., 81(1981), 521-527.

[8]. Salageon, G.S., “Subclasses of univalent function in complex analysis” v Romanian-Finnish seminar, Part- I (Bucharest, 1981), Lecture notes in Mathematics 1013, Springer Verlag, Berlin and New York (1983).

[9] Silverman, H., “Univalent functions with negative coefficients, Proc. Amer. Math. Soc., 51, (1975), 109-116.

References

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