Oscillation Theorems for a Second Order Delay
Difference Equations
Dr.P.Mohankumar
1, A.Ramesh
2 1(Professor of Mathematics, Aaarupadaiveedu Institute of Techonology, Vinayaka Missions University, Paiyanoor, Chengalpattu,Kancheepuram Dist- 603104 , Tamilnadu, India)
2
( Ph.D Scholar Vinayaka Missions University , Salem-636 308, Tamilnadu India)
Abstract: The Oscillation Theorems for a Second Order Delay Difference Equations of the form 2
( ( ))
0 ,
( ) ...(1)
n n n n
u
p u
n
a
The method uses techniques based on signum functions. Example is inserted to illustrate the result.
Keywords: Delay Difference equation, signum functions, Boundedness
2010MSC: 39A10
1. INTRODUCTION
The purpose of this paper is to present conditions for
all solutions of the linear delay difference equations of the form
2
( ( ))
0 ,
( ) ...(1)
n n n n
u
p u
n
a
Where
is the forward difference operator i.e.
2
1
[
]
n n n n n
u
u
u
u
u
to be oscillatory, and topresent an oscillation theorem for the more general equation
( )
(
r u
n n)
p f
n(u , u
n g n)
0...(2)
assume the condition without further mentions
{ },{
r
np
n}
positive real sequence on interval
n
( )
a
{ }
r
n
0,{
p
n}
0
and
0
( )
n
m
.
The assumptionson
f and g
are stated proceeding Lemma 2 in section.Results on the growth and boundenss of non-oscillatory
solutions are presented in section 3. By a solution of (1) and (2)
we mean real sequence
{ }
u
n satisfying equation (1) for( )
n
a
. We consider only such solutions which arenon-trivial for all large
n
. A solution{ }
u
n of (1) and (2) is callednon-oscillatory if it is eventually positive or negative.
Otherwise it is called Oscillatory.
The problem of determining oscillation theorem for
second order nonlinear difference equation has been the subject
of investigation in [1-3]. Among the papers dealing with this
subject we refer to [4] in which oscillatory theorem of linear
difference equations of second order have been established.
The purpose of this note is to give some new criteria
results we obtain the discrete analogues of some theorem for a
non-linear differential equation of second order with delay due
to katasatos [5] and staikes &petsoulat[6].
2. MAIN RESULTS
The following Lemma allows the use of technique
introduced by Coles [1] to give a short proof of a classical
oscillation Theorem for equation (3).
Lemma 1
0, (
0), 0
( )
n n
If p
p
n
m for all n
a
and{ }
u
n is a solutions of equation (1) that is positive, then0
nu
for alln
sufficiently large and there is a constant0
such that(n ( ))n
n
u
u
Proof.If
{ }
u
n is positive, then so isu
(n( ))n and there for2
0
nu
. This means the{ }
u
n is bounded non-oscillatory sothat if
u
n0
,{ }
u
n become zero again. Therefore which iscontrary to the hypothesis. Hence
u
n0
for alln
sufficiently large. Now suppose that
n
0is larger than the lastzero of
u
n m . Thenn
n u
0,
n m
u
(n( ))n and(n ( ))n n m
n n
u
u
u
u
Let
g
be a function whose graph is the line tangent to the graphof
{ }
u
n at(
n m u
,
n m)
for somen
n
0; that is(
)
s n m n m
g
u
s t
m
u
Since
{ }
u
n is bounded,n m n m n m
n n n
u
u
g
u
g
g
Let n m n mu
x
u
n
m
Then
g
x
0
and because of similar triangles we have(
)
...(4)
(
)
[
]
n m n m n m
n n n m n m
u
g
x
n
m
u
u
g
x
n
u
m u
But
u
n m is decreasing so that the last member of (4) increases to a positive limit
as n
.Hence(n ( ))n n m
n n
u
u
u
u
for all
n
sufficiently large.Theorem 1
{
n}
0, 0
( )
s,
(1)
.
s a
If
p
n
m for all n
a and
p
then all solutions of
are os
proof:
If
{ }
u
n be a non oscillatory solution of the equation (1)and there
2u
n
0,
u
n0
for sufficiently large
n
Let n n nu
u
. Then (1) becomes( ( )) 2
0
n n nAnd since the divergence of the summation s s a
p
implies that0
sp
it follows from Lemma 1 that2
0
n np
n
Thus for
n
0sufficiently large andn
n
00
0 0
2
0...(5)
n n
n n n s
s n s n
p
Let 0 2 n n s s nh
. Then it follows from (5) that
h
nh
n2from which it follows that
0 0
1
1
1
o
n n n
n n
h
h
h
For large
n
. Which contradiction to fact that0
0
n
for n
n
.If
r
n
1,{
p
n}
0,
g
n
as n
the all solutionsequation (2) is oscillatory.
The following lemma is helpful is proving an oscillation
theorem for (2) with non-constant
r
If
f y w
( , )
has thesign of y and w
when they have the same sign, andf y w
( , )
is non-decreasing iny and w
. For the oscillation Theorem presented here we make the followingassumptions on
f and g
:
(i)
g
n
as n
(ii) If
y and w
are one sign, thef y w
( , )
has that sign(iii)
f y w
( , )
is bounded and zero.Note that condition (ii) and (iii) is satisfied and
f
is non decreasing iny and w
.Lemma 2
1
{
n}
0, (
n0),
n0,
s a s
If p
p
r
r
Conditions(i)-(iii) hold and
{ }
u
n is a solutions of equation (1) that ispositive, then
u
n0
for alln
sufficiently largeProof
If
{ }
u
n
0
for
largen
and lemma is false. Then there is apoint
n
olarger than the last zerou
n and larger than the last zerog( )n
u
such that0
0.
0n
u
for n
n
( )
(
r u
n n)
p f u u
n(
n,
g n)
0
and therefore0 0
0
n n n n
r u
r
u
it follows dividing byr
n and summingfrom
n to n
0 andn
then{ }
u
n is negative. This iscontrary to the hypothesis. A similar argument treats the case of
eventually positive or eventually negative If
{ }
u
n
0
for
large
n
Theorem 2
1
0,
0,
,
n n s
s a s s a
If p
r
p
r
Conditions (i)-(iii)hold and
{ }
u
n is a solutions of equation (2) is oscillatory ifinterval
( , )
a
Suppose there is a solutions
{ }
u
n on the interval( , )
a
andthat If
{ }
u
n
0
for
largen
.By lemma 2
u
n0
for alln
sufficiently large so that{ }
u
nis non-decreasing; it then follows from conditions (i)-(iii) that
there is positive constant
such that
f g n u
( ( ),
g n( ))
forall
n
sufficiently large. Thus
(
r
n(
u
n)
p
n
0
and foro
n
sufficiently andn
n
oand Taking summation0 0
0
0...(6)
nn n n n s
s n
r u
r
u
p
But 0 n s s np
as n
this contrary that to lemma. Asimilar argument left to reader if
u
n
0
for
largen
3. Boundedness and Non-Oscillation
The proof of Lemma 2 suggests the following theorem
Therom 3
If (i)-(iii) hold
p
n
0
and u
{ }
n is a non-oscillatorysolution of (2) on an interval
( , )
a
, then there arenon-negative constants
1,
2 such that0 1 2
1
.
n ns n s
u
r
Inparticular, if
0 n s s n
p
then all solutions existing on( , )
a
are oscillatory or bounded.
Proof:
If
{ }
u
n is non-oscillatory solution of (2) that ispositive then
(
r u
n n)
0,
for alln
sufficentely large.Summing the
n to n
00 0 0
0
1
0
n
n n n n
s n s
u
u
r
u
r
We take
0 0 0
1
u
n,
2
r
n
u
n
if{ }
u
n isnegative for all large
n
, the process used above leads to theinequality
0 0 0
0
1
nn n n n
s n s
u
u
r
u
r
In this case
0 0 0
0
1
0
n
n n n n n
s n s
u
u
u
r
u
r
This complete the proof
Theorem 4
Let
p
n
0,
suppose that{
p
n}
is real sequence with0
( )
n
m
suppose that
1,
is ratio of odd integers the signum fuctions :n n n
sgn
u
1 if { }
u
n
0, sgn
u
1 if { } 0,sgn 0
u
0
Then the condition
...(7)
s s asp
Is necessary condition that all solutions of the equation
2 1
( ( ))
(
)
sgn
0...(8)
n n n n n
u
p
u
u
Are oscillatory. For
1,
(7) is a sufficient condition that allbounded solutions of (8) are oscillatory.
Proof:
For
1,
, if{ }
u
n is a bounded solution, and{ }
u
n
0
for alln
sufficiently large, Then there ia pointc
such that2
0,
0,
0,
n n n
u
u
u
for n
c
. then( ( ))
,
n m n nn
c u
u
so the multiplying(n ( ))n
n
u
by (8)and summing
c to n
2
...(9)
n n
s
s s c s m s c
s
u
sp
u
summing the fact that
u
s m
u
s it is clear that (9) can be written as2
...(10)
[
]
n
n n n
s s s m
s m s
s c s c s c
s m c s m
su
s u
u
u
sp
u
u
Since
{ }
u
n is bounded, the left side of (10) is bounded belowwhile the right tends
This contradiction completes the proof.
Example:1
Consider the difference equation
2
1
2
0...(11)
1
n n
n
u
u
n
All condition to Theorem 1 to Theorem 4 satisfied and all
solution of equation (11) is oscillatory.
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