R E S E A R C H
Open Access
An explicit algorithm for solving the optimize
hierarchical problems
Poom Kumam
1,2, Thanyarat Jitpeera
3*and Wararat Yarangkham
4*Correspondence:
3Department of Mathematics,
Faculty of Science and Agriculture, Rajamangala University of Technology Lanna, Phan, Chiangrai, 57120, Thailand
Full list of author information is available at the end of the article
Abstract
In this paper, we consider the variational inequality problem over the generalized mixed equilibrium problem which has a hierarchical structure. Strong convergence of the algorithm to the unique solution is guaranteed under some assumptions.
MSC: 47H09; 47H10; 47J20; 49J40; 65J15
Keywords: nonexpansive; strong convergence; variational inequality; fixed point; hierarchical problem
1 Introduction
LetCbe a closed convex subset of a real Hilbert spaceHwith the inner product·,·and the norm · . We denote weak convergence and strong convergence by the notations
and→, respectively. LetA:C→Hbe a nonlinear mapping and letFbe a bifunction of C×CintoR, whereRis the set of real numbers.
Consider thegeneralized mixed equilibrium problemwhich is to findx∈Csuch that
F(x,y) +Ax,y–x+ϕ(y) –ϕ(x)≥, ∀y∈C. (.)
The solution set of (.) is denoted byGMEP(F,ϕ,A). See [–].
Ifϕ≡, the problem (.) is reduced to thegeneralized equilibrium problemwhich is to findx∈Csuch that
F(x,y) +Ax,y–x ≥, ∀y∈C. (.)
The set of solutions of (.) is denoted byGEP(F,A).
IfA≡ andϕ≡, the problem (.) is reduced to theequilibrium problem[] which is to findx∈Csuch that
F(x,y)≥, ∀y∈C. (.)
The solution set of (.) is denoted byEP(F).
IfF≡ andϕ≡, the problem (.) is reduced to theHartmann-Stampacchia varia-tional inequality[] which is to findx∈Csuch that
Ax,y–x ≥, ∀y∈C. (.)
The solution set of (.) is denoted byVI(C,A).
A mappingT:C→Cis callednonexpansiveifTx–Ty ≤ x–yfor allx,y∈C. IfC is bounded closed convex andT is a nonexpansive mapping ofCinto itself, thenF(T) is nonempty []. A pointx∈His afixed pointofT providedTx=x. Denote byF(T) the set of fixed points ofT; that is,F(T) ={x∈H:Tx=x}.
We discuss the following variational inequality problem over the generalized mixed equilibrium problem, which is called thehierarchical problem over the generalized mixed equilibrium problem, which is to find a pointx∈GMEP(F,ϕ,B) such that
Ax,y–x ≥, ∀y∈GMEP(F,ϕ,B),
whereA,Bare two monotone operators. See [, ].
A mappingA:C→Cis calledα-strongly monotoneif there exists a positive real number
αsuch thatAx–Ay,x–y ≥αx–yfor allx,y∈C. A mappingA:C→Cis called L-Lipschitz continuousif there exists a positive real numberLsuch thatAx–Ay ≤Lx–y for allx,y∈C. A linear bounded operatorAis calledstrongly positiveonHif there exists a constantγ¯> with the propertyAx,x ≥ ¯γxfor allx∈H. A mappingf :C→His
called aρ-contractionif there exists a constantρ∈[, ) such thatf(x) –f(y) ≤ρx–y for allx,y∈C.
In , Yaoet al.[] considered the hierarchical problem over the generalized equi-librium problem,xs,tbeing defined by implicit algorithms:
xs,t=s
tf(xs,t) + ( –t)(xs,t–λAxs,t)
+ ( –s)Tr(xs,t–rBxs,t), s,t∈(, ), (.)
for each (s,t)∈(, ). The netxs
,thierarchically converges to the unique solutionx∗of the problem of the variational inequality which is to find a pointx∗∈GEP(F,B) such that
Ax∗,x–x∗≥, ∀x∈GEP(F,B), (.)
whereA,Bare two monotone operators. The solution set of (.) is denoted by. Fur-thermore,x∗also solves the following variational inequality:
x∗∈, (I–f)x∗,x–x∗≥, ∀x∈.
In , Yaoet al.[] studied the hierarchical problem over the fixed point set. Let the sequence{xn}be generated by two algorithms as follows.
Implicit Algorithm:xt=TPC[I–t(A–γf)]xt,∀t∈(, )and
Explicit Algorithm:xn+=βnxn+ ( –βn)TPC[I–αn(A–γf)]xn,∀n≥.
They showed that these two algorithms converge strongly to the unique solution of the problem of the variational inequality which is to findx∗∈F(T) such that
(A–γf)x∗,x–x∗≥, ∀x∈F(T),
where A:C→H is a strongly positive linear bounded operator, f :C →H is a ρ -contraction, andT:C→Cis a nonexpansive mapping.
forx∈C,
xn+=αn
βnxn+ ( –βn)PCI–λn(A–γf)xn+ ( –αn)Trn(I–rnB)xn, (.)
where {αn},{βn},{λn} ⊂[, ], andrn∈(, β) satisfy some conditions. Then {xn} con-verges strongly tox∗∈GMEP(F,ϕ,B), which is the unique solution of the variational in-equality:
(A–γf)x∗,x–x∗≥, ∀x∈GMEP(F,ϕ,B). (.)
Our results improve the results of Yaoet al.[], Yaoet al.[] and some other authors.
2 Preliminaries
LetCbe a nonempty closed convex subset ofH. We have the following inequality in an inner product space:x+y≤ x+ y,x+y,∀x,y∈H. For every pointx∈H, there
exists a uniquenearest pointinC, denoted byPCx, such that
x–PCx ≤ x–y, for ally∈C.
PCis called themetric projectionofHontoC. It is well known thatPCis a nonexpansive mapping ofHontoCand satisfies
x–y,PCx–PCy ≥ PCx–PCy,
for everyx,y∈H. Moreover,PCxis characterized by the following properties:PCx∈C and
x–PCx,y–PCx ≤, (.)
x–y≥ x–PCx+y–PCx,
for allx∈H,y∈C. LetBbe a monotone mapping ofCintoH. In the context of the vari-ational inequality problem the characterization of projection (.) implies the following:
u∈VI(C,B) ⇔ u=PC(u–λBu), λ> .
It is also well known thatHsatisfies the Opial condition [],i.e., for any sequence{xn} ⊂H withxnx, the inequalitylim infn→∞xn–x<lim infn→∞xn–y, holds for everyy∈H
withx=y.
For solving the generalized mixed equilibrium problem and the mixed equilibrium prob-lem, let us give the following assumptions for the bifunctionF,ϕ, and the setC:
(A) F(x,x) = for allx∈C;
(A) Fis monotone,i.e.,F(x,y) +F(y,x)≤for allx,y∈C; (A) for eachy∈C,x→F(x,y)is weakly upper semicontinuous; (A) for eachx∈C,y→F(x,y)is convex;
(B) for eachx∈Handr> , there exist a bounded subsetDx⊆Candyx∈Csuch that for anyz∈C\Dx,
F(z,yx) +ϕ(yx) –ϕ(z) +
ryx–z,z–x< ; (.)
(B) Cis a bounded set.
Lemma .[] Let C be a nonempty closed convex subset of a real Hilbert space H.Let F be a bifunction from C×C toRsatisfying(A)-(A)and letϕ:C→Rbe a proper lower semicontinuous and convex function.For r> and x∈H,define a mapping Tr:H→C as follows.
Tr(x) =
z∈C:F(z,y) +ϕ(y) –ϕ(z) +
ry–z,z–x ≥,∀y∈C (.)
for all x∈H.Assume that either(B)or(B)holds.Then the following results hold: () for eachx∈H,Tr(x)=∅;
() Tris single-valued;
() Tris firmly nonexpansive,i.e.,for anyx,y∈H,Trx–Try≤ Trx–Try,x–y; () F(Tr) =MEP(F,ϕ);
() MEP(F,ϕ)is closed and convex.
Lemma .[] Let C be a closed convex subset of a real Hilbert space H and let T:C→C be a nonexpansive mapping.Then I–T is demiclosed at zero,that is,xnx,xn–Txn→ implies x=Tx.
Lemma .[] Assume A is a self adjoint and strongly positive linear bounded operator on a Hilbert space H with coefficientγ¯> and <ρ≤ A–,thenI–ρA ≤ –ργ¯.
Lemma .[] Assume{an}is a sequence of nonnegative real numbers such that
an+≤( –γn)an+δn, ∀n≥,
where{γn} ⊂(, )and{δn}are sequences inRsuch that (i) ∞n=γn=∞,
(ii) lim supn→∞δn γn ≤or
∞
n=|δn|<∞. Thenlimn→∞an= .
3 Strong convergence theorems
In this section, we introduce an explicit algorithm for solving some hierarchical problem over the set of fixed points of a nonexpansive and the generalized mixed equilibrium prob-lem.
Theorem . Let C be a nonempty closed convex subset of a real Hilbert space H,A:
and lower semicontinuous with either(B)or(B).Let{xn}be a sequence generated by the following algorithm for arbitrary x∈C:
xn+=αn
βnxn+ ( –βn)PCI–λn(A–γf)xn+ ( –αn)Trn(I–rnB)xn, (.)
where{αn},{βn},{λn} ⊂[, ],αn≤λn,and rn∈(, β)satisfy the following conditions: (C) ∞n=|αn–αn–|<∞;
(C) ∞n=|βn–βn–|<∞;
(C) ∞n=|λn–λn–|<∞,∞n=λn=∞,limn→∞λn= ; (C) ∞n=|rn–rn–|<∞,lim infn→∞rn> .
Then {xn}converges strongly to x∗∈GMEP(F,ϕ,B), which is the unique solution of the variational inequality:
(A–γf)x∗,x–x∗≥, ∀x∈GMEP(F,ϕ,B). (.)
Proof We will divide the proof into five steps.
Step . We will show{xn}is bounded. For anyq∈GMEP(F,ϕ,B) and takingyn=PC[I–
λn(A–γf)]xn, we note that
yn–q =PCI–λn(A–γf)xn–PCq
≤I–λn(A–γf)xn–q
≤λnγf(xn) –γf(q)+λnγf(q) –Aq+|I–λnA|xn–q
≤λnγρxn–q+λnγf(q) –Aq+ ( –λnγ¯)xn–q = – (γ¯–γρ)λn
xn–q+λnγf(q) –Aq. (.)
From (.), we have
xn+–q=αn
βnxn+ ( –βn)yn+ ( –αn)Trn(I–rnB)xn–q
≤αnβnxn+ ( –βn)yn–q+ ( –αn)Trn(I–rnB)xn–q
≤αnβnxn–q+αn( –βn)yn–q
+ ( –αn)Trn(I–rnB)xn–Trn(I–rnB)q
≤αnβnxn–q+αn( –βn)
– (γ¯–γρ)λn
xn–q+λnγf(q) –Aq + ( –αn)xn–q
=αnβnxn–q+αn( –βn)
– (γ¯–γρ)λn
xn–q
+αn( –βn)λnγf(q) –Aq+ ( –αn)xn–q = –αn( –βn)xn–q+αn( –βn) – (γ¯–γρ)λn
xn–q
+αn( –βn)λnγf(q) –Aq = –αn( –βn)
– – (γ¯–γρ)λn
xn–q
= –αn( –βn)λn(γ¯–γρ)xn–q+αn( –βn)λnγf(q) –Aq = –αn( –βn)λn(γ¯–γρ)xn–q
+αn( –βn)λn(γ¯–γρ)γf(q) –Aq
¯
γ –γρ .
It follows by induction that
xn–q ≤max
x–q,
γf(q) –Aq
¯
γ –γρ , ∀n≥.
Therefore{xn}is bounded and so are{yn},{Axn}, and{f(xn)}.
Step . We show thatlimn→∞xn+–xn= . Settingvn= [I–λn(A–γf)]xnand we
observe that
yn+–yn=PCvn+–PCvn ≤I–λn+(A–γf)
xn+–
I–λn(A–γf)xn =λn+γ
f(xn+) –f(xn)
+ (λn+–λn)γf(xn) + (I–λn+A)(xn+–xn)
+(λn+–λn)Axn
≤λn+γf(xn+) –f(xn)+ ( –λn+γ¯)xn+–xn
+|λn+–λn|γf(xn)+Axn
≤λn+γρxn+–xn+ ( –λn+γ¯)xn+–xn
+|λn+–λn|γf(xn)+Axn
= – (γ¯–γρ)λn+
xn+–xn+|λn+–λn|M, (.)
whereM=sup{γf(xn)+Axn:n∈N}. Settingzn=βnxn+ ( –βn)ynfor alln≥. We
observes that
zn+–zn=βn+xn++ ( –βn+)yn+–
βnxn+ ( –βn)yn
≤βn+xn+–xn+|βn+–βn|xn–yn+| –βn+|yn+–yn. (.)
Substituting (.) into (.) it follows that
zn+–zn ≤βn+xn+–xn+|βn+–βn|xn–yn
+| –βn+|
– (γ¯–γρ)λn+
xn+–xn+|λn+–λn|M
≤βn+xn+–xn+|βn+–βn|xn–yn
+ –βn+– ( –βn+)(γ¯–γρ)λn+
xn+–xn+|λn+–λn|M
= – ( –βn+)(γ¯–γρ)λn+
xn+–xn+|βn+–βn|M
whereM=sup{xn–yn:n∈N}. On the other hand, fromun–=Trn–(xn––rn–Bxn–)
andun=Trn(xn–rnBxn) it follows that
F(un–,y) +Bxn–,y–un–+ϕ(y) –ϕ(un–) +
rn–
y–un–,un––xn– ≥,
∀y∈C, (.)
and
F(un,y) +Bxn,y–un+ϕ(y) –ϕ(un) + rn
y–un,un–xn ≥, ∀y∈C. (.)
Substitutingy=uninto (.) andy=un–into (.), we have
F(un–,un) +Bxn–,un–un–+ϕ(un) –ϕ(un–) +
rn–
un–un–,un––xn– ≥
and
F(un,un–) +Bxn,un––un+ϕ(un–) –ϕ(un) +
rnun––un,un–xn ≥.
From (A), we have
un–un–,Bxn––Bxn+
un––xn–
rn–
–un–xn rn
≥,
and then
un–un–,rn–(Bxn––Bxn) +un––xn––
rn–
rn (un–xn)
≥,
so
un–un–,rn–Bxn––rn–Bxn+un––un+un–xn––
rn–
rn (un–xn)
≥.
It follows that
un–un–, (I–rn–B)xn– (I–rn–B)xn–+un––un+un–xn– rn–
rn (un–xn)
≥,
un–un–,un––un+
un–un–,xn–xn–+
–rn– rn
(un–xn)
≥.
Without loss of generality, let us assume that there exists a real numbercsuch thatrn–>
c> , for alln∈N. Then we have
un–un–≤
un–un–,xn–xn–+
–rn– rn
(un–xn)
≤ un–un–
xn–xn–+
–rn–
rn
and hence
un–un– ≤ xn–xn–+
rn|rn–rn–|un–xn
≤ xn–xn–+
M
c |rn–rn–|, (.)
whereM=sup{un–xn:n∈N}. From (.), we have
xn+–xn=αnzn+ ( –αn)un–αn–zn–– ( –αn–)un–
≤αnzn–zn–+|αn–αn–|zn––un–+| –αn|un–un–
=αnzn–zn–+|αn–αn–|M+| –αn|un–un–, (.)
whereM=sup{zn–un:n∈N}. Substituting (.) and (.) into (.)
xn+–xn ≤αn
– ( –βn)(γ¯–γρ)λn
xn–xn–
+|βn–βn–|M+|λn–λn–|M
+|αn–αn–|M+| –αn|
xn–xn–+
M
c |rn–rn–|
≤ – ( –βn)(γ¯–γρ)αnλn
xn–xn–+αn|βn–βn–|M
+αn|λn–λn–|M+|αn–αn–|M+
M
c |rn–rn–|, (.)
from (C)-(C) and the boundedness of {xn}, {yn}, {zn}, {f(xn)}, and {Axn}. Applying Lemma ., we obtain
lim
n→∞xn+–xn= . (.)
Step . We show thatlimn→∞xn–un= . For eachq∈GMEP(F,ϕ,B), note thatTrn is firmly nonexpansive, then we have
un–q =Trn(xn–rnBxn) –Trn(q–rnBq)
≤Trn(xn–rnBxn) –Trn(q–rnBq),un–q =(xn–rnBxn) – (q–rnBq),un–q
=
(xn–rnBxn) – (q–rnBq)
+un–q
–(xn–rnBxn) – (q–rnBq) – (un–q)
≤
xn–q+un–q–xn–un–rn(Bxn–Bq)
≤
xn–q+un–q–xn–un
+ rnxn–un,Bxn–Bq–rnBxn–Bq
, (.)
which implies that
From (.), we get
yn–xn=PCI–λn(A–γf)xn–PCxn
≤I–λn(A–γf)
xn–xn
≤λn(A–γf)xn.
By (C), we have
lim
n→∞yn–xn= . (.)
Settingwn= [I–λn(A–γf)]xn. It follows that
wn–xn=I–λn(A–γf)xn–xn
≤I–λn(A–γf)xn–xn
≤λn(A–γf)xn.
By using (C) again, we get
lim
n→∞wn–xn= . (.)
Fromyn=PC[I–λn(A–γf)]xn, we compute
yn–q =PCI–λn(A–γf)xn–PCq
≤I–λn(A–γf)xn–q
=wn–q. (.)
It follows from (.) that
xn–q ≤ wn–q. (.)
Then we get
wn–q≤
I–λn(A–γf)
xn–q,wn–q
=λnγfxn–Aq,wn–q+
(I–λnA)(xn–q),wn–q
≤λnγfxn–Aq,wn–q+ ( –λnγ¯)xn–qwn–q
≤( –λnγ¯)wn–q+λnγfxn–Aq,wn–q.
It follows that
wn–q≤
¯
γγfxn–Aq,wn–q
=
¯ γ
γfxn–fq,wn–q+γfq–Aq,wn–q
≤ ¯ γ
that is,
wn–q≤
¯ γ –γρ
(A–γf)q,q–wn. (.)
On the other hand, we note that
un–q =Trn(xn–rnBxn) –Trn(q–rnBq)
≤(xn–rnBxn) – (q–rnBq)
=(xn–q) –rn(Bxn–Bq)
≤ xn–q– rnxn–q,Bxn–Bq+rnBxn–Bq
≤ xn–q– rnβBxn–Bq+rnBxn–Bq. (.)
Using (.), (.), (.), and (.), we note that
xn+–q≤αnβnxn–q+αn( –βn)yn–q+ ( –αn)un–q
≤αnβnwn–q+αn( –βn)wn–q+ ( –αn)un–q
=αnwn–q+ ( –αn)un–q
≤ αn
¯ γ–γρ
(A–γf)q,q–wn
+ ( –αn)xn–q– rnβBxn–Bq+rnBxn–Bq
= αn
¯ γ–γρ
(A–γf)q,q–wn
+ ( –αn)xn–q+rn(rn– β)Bxn–Bq
≤ αn
¯ γ–γρ
(A–γf)q,q–wn+xn–q
+ ( –αn)rn(rn– β)Bxn–Bq. (.)
Then we have
( –αn)c(β–d)Bxn–Bq
≤ αn
¯ γ–γρ
(A–γf)q,q–wn+xn–q–xn+–q ≤ αn
¯ γ–γρ
(A–γf)q,q–wn+xn–xn+
xn–q+xn+–q
.
From (C),{rn} ⊂[c,d]⊂(, β), and (.), we obtain
lim
n→∞Bxn–Bq= . (.)
Substituting (.) into (.), we have
xn+–q≤αnwn–q+ ( –αn)un–q
≤αnwn–q+ ( –αn)
+ rnxn–unBxn–Bq
≤αnwn–q+xn–q– ( –αn)xn–un
+ rn( –αn)xn–unBxn–Bq,
and it follows that
( –αn)xn–un≤αnwn–q+xn–q–xn+–q
+ rn( –αn)xn–unBxn–Bq
≤αnwn–q+xn–xn+
xn–q+xn+–q
+ rn( –αn)xn–unBxn–Bq.
Since we have (C), (.), and (.),
lim
n→∞xn–un= . (.)
By (C), we obtain
lim
n→∞
xn–un
rn
= lim
n→∞
rnxn–un= . (.)
Step . Next, we will show that
lim sup
n→∞
(γf –A)x∗,xn–x∗
≤.
Indeed, we choose a subsequence{xni}of{xn}such that
lim sup
n→∞
(γf –A)x∗,xn–x∗=lim
i→∞
(γf–A)x∗,xni–x∗.
Since{xni}is bounded, there exists a subsequence{xnij}of{xni}which converges weakly to z∈C. We notice thatwn–xn ≤λn(A–γf)xn →. Hence, we getlim supn→∞(γf –
A)x∗,xn–x∗ ≤. Next, we will show thatz∈GMEP(F,ϕ,B). Sinceun=Trn(xn–rnBxn), we have
F(un,y) +Bxn,y–un+ϕ(y) –ϕ(un) +
rny–un,un–xn ≥, ∀y∈C.
From (A), we also have
Bxn,y–un+ϕ(y) –ϕ(un) +
rny–un,un–xn ≥F(y,un), ∀y∈C,
and hence
Bxni,y–uni+ϕ(y) –ϕ(uni) +
y–uni,uni–xni rni
Fortwith <t≤ andy∈C, letyt=ty+ ( –t)z. Sincey∈Candz∈C, we haveyt∈C. So, from (.), we have
yt–uni,Byt ≥ yt–uni,Byt–ϕ(yt) +ϕ(uni) –yt–uni,Bxni
–
yt–uni,uni–xni rni
+F(yt,uni)
=yt–uni,Byt–Buni+yt–uni,Buni–Bxni–ϕ(yt) +ϕ(uni)
–
yt–uni,uni–xni rni
+F(yt,uni).
Sinceuni–xni →, we haveBuni–Bxni →. Further, from the inverse strongly mono-tonicity ofB, we haveyt–uni,Byt–Buni ≥. So, from (A), (A), and the weak lower semicontinuity ofϕ,unir–xni
ni → anduniw, we have in the limit
yt–w,Byt ≥–ϕ(yt) +ϕ(w) +F(yt,w) (.)
asi→ ∞. From (A), (A) and (.), we also get
= F(yt,yt) +ϕ(yt) –ϕ(yt)
≤tF(yt,y) + ( –t)F(yt,z) +tϕ(y) – ( –t)ϕ(z) –ϕ(yt)
=tF(yt,y) +ϕ(y) –ϕ(yt)+ ( –t)F(yt,z) +ϕ(z) –ϕ(yt)
≤tF(yt,y) +ϕ(y) –ϕ(yt)+ ( –t)yt–z,Byt =tF(yt,y) +ϕ(y) –ϕ(yt)+ ( –t)ty–z,Byt, ≤F(yt,y) +ϕ(y) –ϕ(yt) + ( –t)y–z,Byt.
Lettingt→, we have, for eachy∈C,
F(z,y) +ϕ(y) –ϕ(z) +y–z,Bz ≥.
This implies thatz∈GMEP(F,ϕ,B). It is easy to see thatPGMEP(F,ϕ,B)(I–A+γf)(x∗) is a
contraction ofHinto itself. HenceHis complete, there exists a unique fixed pointx∗∈H, such thatx∗=PGMEP(F,ϕ,B)(I–A+γf)(x∗).
Step . Next, we will provexn→x∗∈GMEP(F,ϕ,B), which solves the variational in-equality (.). It follows from (.) that
xn+–x∗
=αnβn
xn–x∗,xn+–x∗
+αn( –βn)PCI–λn(A–γf)xn–PCI–λn(A–γf)x∗,xn+–x∗
+αn( –βn)PCI–λn(A–γf)x∗–x∗,xn+–x∗
+ ( –αn)Trn(I–rnB)xn–Trn(I–rnB)x∗,xn+–x∗
≤αnβnxn–x∗xn+–x∗
+αn( –βn)I–λn(A–γf)xn–I–λn(A–γf)x∗,xn+–x∗
+αn( –βn)I–λn(A–γf)x∗–x∗,xn+–x∗
+ ( –αn)Trn(I–rnB)xn–Trn(I–rnB)x∗xn+–x∗ ≤αnβnxn–x∗xn+–x∗
+αn( –βn)
– (γ¯–γρ)λnxn–x∗ +λnγf
x∗–Ax∗xn+–x∗
–αn( –βn)λn
(A–γf)x∗,xn+–x∗
+ ( –αn)xn–x∗xn+–x∗
=αnβnxn–x∗xn+–x∗+ ( –αn)xn–x∗xn+–x∗
+αn( –βn) – (γ¯–γρ)λnxn–x∗xn+–x∗
+αn( –βn)λnγf
x∗–Ax∗xn+–x∗
–αn( –βn)λn
(A–γf)x∗,xn+–x∗
= –αn( –βn)xn–x∗xn+–x∗
+αn( –βn)
– (γ¯–γρ)λnxn–x∗xn+–x∗
+αn( –βn)λnγf
x∗–Ax∗xn+–x∗
–αn( –βn)λn
(A–γf)x∗,xn+–x∗
= –αn( –βn) – + (γ¯–γρ)λnxn–x∗xn+–x∗
+αn( –βn)λnγf
x∗–Ax∗xn+–x∗
–αn( –βn)λn
(A–γf)x∗,xn+–x∗
= –αn( –βn)(γ¯–γρ)λnxn–x∗xn+–x∗
+αn( –βn)λnγf
x∗–Ax∗xn+–x∗
–αn( –βn)λn
(A–γf)x∗,xn+–x∗
≤ –αn( –βn)(γ¯–γρ)λn
xn–x
∗
+xn+–x∗
+αn( –βn)λnγf
x∗–Ax∗xn+–x∗
–αn( –βn)λn
(A–γf)x∗,xn+–x∗
≤ – ( –βn)(γ¯–γρ)αnλn
xn–x
∗
+
xn+–x
∗
+ ( –βn)αnλnγf
x∗–Ax∗xn+–x∗
– ( –βn)αnλn
(A–γf)x∗,xn+–x∗
,
which implies that
xn+–x∗≤ – ( –βn)(γ¯–γρ)αnλnxn–x∗
+ ( –βn)αnλnγf
x∗–Ax∗xn+–x∗
– ( –βn)αnλn
(A–γf)x∗,xn+–x∗
Since{xn},{f(xn)}, and{Axn}are all bounded, we can choose a constantM> such that
sup
¯ γ –γρ
γfx∗–Ax∗xn+–x∗+
(A–γf)x∗,xn+–x∗
≤M.
It follows that
xn+–x∗
≤ – ( –βn)(γ¯–γρ)αnλnxn–x∗
+ ( –βn)αnλnM.
By (C), we conclude thatxn→x∗, asn→ ∞. This completes the proof.
4 An example
Next, the following example shows that all conditions of Theorem . are satisfied.
Example . For instance, letαn= nn++,βn=n+ ,λn=(n+), andrn=nn+. Then clearly the sequences{αn},{λn}satisfy the following condition:
n+ n+ ≤
(n+ ).
We will show that the condition (C) is fulfilled. Indeed, we have
∞
n=
|αn–αn–|= ∞
n=
nn+ + –
n (n– )+
= ∞ n=
(n+ )(n(n+ )(n– n+ ) –– n+ )n(n+ )
= ∞ n=
n– n ++ nn–n– n +
.
The sequence{αn}satisfies the condition (C) by ap-series.
Next, we will show that the condition (C) is fulfilled. We compute
∞
n=
|βn–βn–|= ∞
n=
n+ – n = – + – + – +· · · = .
The sequence{βn}satisfies the condition (C).
Next, we will show that the condition (C) is fulfilled. We compute
∞
n=
|λn–λn–|= ∞
n=
lim
n→∞λn=nlim→∞ (n+ )= ,
and
∞
n= λn=
∞
n=
(n+ )=∞.
The sequence{λn}satisfies the condition (C).
Finally, we will show that the condition (C) is fulfilled. We compute
∞
n=
|rn–rn–|= ∞
n=
nn+ – n– (n– ) +
=
∞
n=
n(n) – (n(n+ )n– )(n+ )
=
∞
n=
n(n–+ )nn+
=
∞
n=
n(n+ )
and
lim inf
n→∞ rn=lim infn→∞
n n+ = .
The sequence{rn}satisfies the condition (C).
Corollary . Let C be a nonempty closed convex subset of a real Hilbert space H.Let
A:H→H be a strongly positive linear bounded operator,f :C→H beρ-contraction,γ
be a positive real number such thatγ¯ρ–<γ <γρ¯ and T:C→C be a nonexpansive mapping with F(T)=∅.Let{xn} be a sequence generated by the following algorithm for arbitrary x∈C:
xn+=βnxn+ ( –βn)TPC
I–λn(A–γf)xn, (.)
where{βn},{λn} ⊂[, ]satisfy the following conditions:
(C) ∞n=|βn+–βn|<∞, <lim infn→∞βn<lim supn→∞βn< ; (C) ∞n=|λn+–λn|<∞,
∞
n=λn=∞,limn→∞λn= .
Then{xn}converges strongly to x∗∈F(T),which is the unique solution of the variational inequality:
(A–γf)x∗,x–x∗≥, ∀x∈F(T). (.)
Proof Setting{αn} ≡ andT to be a nonexpansive mapping in Theorem ., we obtain
the desired conclusion immediately.
Corollary . Let C be a nonempty closed convex subset of a real Hilbert space H.Let A: H→H be a strongly positive linear bounded operator,B:C→H be aβ-inverse-strongly monotone and F be a bifunction from C×C→Rsatisfying(A)-(A)and letϕ:C→R be convex and lower semicontinuous with either(B)or(B).Suppose GMEP(F,ϕ,B)=∅. Let{xn}be a sequence by the following algorithm for arbitrary x∈C:
xn+=αn
βnxn+ ( –βn)[I–λnA]xn+ ( –αn)Trn(I–rnB)xn, (.)
where{αn},{βn},{λn} ⊂[, ],αn≤λn,and rn∈(, β)satisfy the following conditions: (C) ∞n=|αn–αn–|<∞;
(C) ∞n=|βn–βn–|<∞;
(C) ∞n=|λn–λn–|<∞,∞n=λn=∞,limn→∞λn= ; (C) ∞n=|rn–rn–|<∞,lim infn→∞rn> .
Then {xn}converges strongly to x∗∈GMEP(F,ϕ,B), which is the unique solution of the variational inequality:
Ax∗,x–x∗≥, ∀x∈GMEP(F,ϕ,B). (.) Proof SettingT,PCto be the identity andf ≡ in Theorem ., we obtain the desired
conclusion immediately.
Corollary . Let C be a nonempty closed convex subset of a real Hilbert space H.Let
A:H→H be a strongly positive linear bounded operator,f :C→H beρ-contraction,B: C→H beβ-inverse-strongly monotone and F be a bifunction from C×C→Rsatisfying (A)-(A)and letϕ:C→Rbe convex and lower semicontinuous with either(B)or(B). Let{xn}be a sequence generated by the following algorithm for arbitrary x∈C:
xn+=αn
λn( –βn)f(xn) +I–λn( –βn)Axn+ ( –αn)Trn(I–rnB)xn, (.) where{αn},{βn},{λn} ⊂[, ],λn≤βn,and rn∈(, β)satisfy the following conditions:
(C) ∞n=|αn+–αn|<∞; (C) ∞n=|βn+–βn|<∞;
(C) ∞n=|λn+–λn|<∞,∞n=λn=∞,limn→∞λn= ; (C) ∞n=|rn+–rn|<∞,lim infn→∞rn> .
Then {xn}converges strongly to x∗∈GMEP(F,ϕ,B), which is the unique solution of the variational inequality
(A–f)x∗,x–x∗≥, ∀x∈GMEP(F,ϕ,B). (.) Proof SettingT,PCto be the identity andγ ≡ in Theorem ., we obtain the desired
conclusion immediately.
Competing interests
The authors declare that they have no competing interests. Authors’ contributions
Author details
1Department of Mathematics, Faculty of Science, King Mongkut’s University of Technology Thonburi, 126 Pracha u-thit
Rd., Bang Mod, Thrung Khru, Bangmod, Bangkok, 10140, Thailand.2Centre of Excellence in Mathematics, CHE, Si
Ayutthaya Road, Bangkok, 10400, Thailand.3Department of Mathematics, Faculty of Science and Agriculture,
Rajamangala University of Technology Lanna, Phan, Chiangrai, 57120, Thailand.4Department of Logistic Engineering,
Faculty of Engineering, Rajamangala University of Technology Lanna, Phan, Chiangrai, 57120, Thailand. Acknowledgements
This project was partially supported by Centre of Excellence in Mathematics, the Commission on Higher Education, Ministry of Education, Thailand. The second author and third author were supported by Innovation park, RMUTL Hands-on Researcher Project, Rajamangala University of Technology Lanna Chiangrai under Grant no. 57HRG-10 during the preparation of this paper.
Received: 28 April 2014 Accepted: 5 September 2014 Published:16 Oct 2014
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