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Physics 106 Lecture 12. Oscillations II. Recap: SHM using phasors (uniform circular motion) music structural and mechanical engineering waves

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Physics 106 Lecture 12

Oscillations – II

SJ 7thEd.: Chap 15.4, Read only 15.6 & 15.7

• Recap: SHM using phasors (uniform circular motion)

Ph i l d l l

• Physical pendulum example • Damped harmonic oscillations • Forced oscillations and resonance. • Resonance examples and discussion

– music

– structural and mechanical engineering – waves

• Sample problems • Sample problems

• Oscillations summary chart

Damped Oscillations

Non-conservative forces may be presentFriction is a common nonconservative force No longer an ideal system (such as those dealt with

so far)

The mechanical energy of the system diminishes in

neglect gravity

The mechanical energy of the system diminishes in time, motion is said to be damped

The motion of the system can be decaying oscillations if the damping is “weak”.

If damping is “strong”, motion may die away without oscillating.Still no driving force, once system has been started

(2)

Add Damping: E

mech

not constant, oscillations not simple

neglect gravity

bv

F

Spring oscillator as before, but with dissipative force Fdamp

Fdampviscous drag force, proportional to velocity

such as the system in the figure, with vane moving in fluid.

bv

F

damp

=

Previous force equation gets a new, damping force term

)

t

(

dx

( )

)

t

(

x

d

2

dt

)

t

(

dx

b

x(t)

k

dt

)

t

(

x

d

m

F

net

=

2

=

x(t)

m

k

dt

)

t

(

dx

m

b

dt

)

t

(

x

d

=

+

2 2 new term

Solution for Damped oscillator equation

x(t)

m

k

dt

)

t

(

dx

m

b

dt

)

t

(

x

d

=

+

2

2

new term Solution: modified oscillations 4 2 2 m b m k

'

ω

)

t

'

cos(

e

x

)

t

(

x

m bt m

ω

+

φ

=

2 exponentially

decaying envelope frequencyaltered ωor imaginary’ can be real

0

k

ω

0

=

: natural frequency

m

ω

: natural frequency

2 2 0

'

( / 2 )

b

m

ω

ω

(3)

Damped physical systems can be of three types

Solution: damped oscillations 2 4 2 m b m k

'

ω

)

t

'

cos(

e

x

)

t

(

x

m bt m

ω

+

φ

=

2

U d

d

d

ll

b

2

k

Underdamped: small

2

2 , for which is positive.

4 b k m <m

ω

Critically damped:

0 4 2 0 2 2 ≈ ω ω ≡ ≈ ' m k m b which for

2

b

<

km

2

b

=

km

4m m

Overdamped:

for which ' isimaginary

m k m b > ω2 ω 0 2 2 4

cos( )

cosh( )

(

) / 2

sin( )

sinh( )

(

) / 2

x x x x

ix

x

e

e

ix

x

e

e

− −

=

=

+

=

=

Math Review:

cos(

ix

+

y

)

=

cos( ) cos( ) sin( ) sin( )

ix

y

ix

y

Types of Damping, cont (

Link to Active Fig.)

a) an underdamped oscillator

b) a critically damped oscillator

c) an overdamped oscillator

For critically damped and overdamped oscillators there is no

periodic motion and the angular frequency

ω

has a different

meaning

(4)

Weakly damped oscillator :

m k m 4 b 2 0 2 2 ω ≡ <<

( )

2 bt

-X

2 0 2 4

'

k b m m

ω

ω

2 0

( )

cos(

)

bt m m

x t

=

x e

ω

t

+

ϕ

slow decay

of amplitude envelope

e

x

(t)

x

2m m m

m

X =

small fractional change in amplitude during one complete cycle ) t os( c ω0 +φ ≈

Weakly damped oscillator :

small fractional m k m 4 b 2 0 2 2 ω ≡ <<

e

x

(t)

x

2m bt -m m

A X : Amplitude m = 2 0 2 4

'

k b m m

ω

ω

2 0

( )

cos(

)

bt m m

x t

=

x e

ω

t

+

ϕ

small fractional change in amplitude during one complete

cycle slow decay of amplitude envelope ) t os( c ω0 +φ ≈

Velocity with weak damping: find derivative ) t ' sin( e v ) t ( x dt d ) t ( v m bt m ω +φ ≈ = −2

exponentially frequency ~ altered ω

m 0 m velocity maximum

x

v

=

ω

(5)

(t)

kx

(t)

mv

U(t)

K(t)

E

2 2 1 2 2 1 mech

=

+

=

+

Mechanical energy decays exponentially in an

“weakly damped” oscillator (small b)

2 0

( )

cos(

)

bt m m

x t

=

x e

ω

t

+

ϕ

Velocity with weak damping: find derivative ) t ' sin( e v ) t ( x dt d ) t ( v m bt m ω +φ ≈ = −2 altered m 0 m velocity maximum

x

v

=

ω

exponentially decaying envelope altered frequency ~ ω0 2 0

cos(

)

2

bt m m

b

x

e

t

m

ω

ϕ

+

term is negligible, because

b

is small..

Substitute previous solutions:

(t)

kx

(t)

mv

U(t)

K(t)

E

2 2 1 2 2 1 mech

=

+

=

+

Mechanical energy decays exponentially in an

“weakly damped” oscillator (small b)

bt ) t ' sin( e x ) t ( v m bt m ω +φ ω − ≈ −2 0 ) t ' cos( e x ) t ( x m bt m ω +φ = −2

)

t

'

(

os

c

e

kx

)

t

'

(

sin

e

x

m

E

2 m / bt 2 m 2 1 2 m / bt 2 m 2 1 mech

φ

+

ω

+

φ

+

ω

ω

=

− − 2 0

As always: cos2(x) + sin2(x) = 1

exponential decay at twice the rate of amplitude decay

m k ≡ ω2 0 Also:

e

kx

)

t

(

E

2m bt/m 2 1 mech

=

(6)

Damped physical systems can be of three types

Solution: damped oscillations 2 4 2 m b m k

'

ω

)

t

'

cos(

e

x

)

t

(

x

m bt m

ω

+

φ

=

2 exponentially

decaying envelope frequencyaltered ωor imaginary’ can be real

Underdamped:

0 2 0 2 2 4 << m≡ω ω'≈ω k m b which for

ƒThe restoring force is large compared to the damping force. ƒThe system oscillates with decaying amplitude

Critically damped:

0 4 2 0 2 2 ≈ ω ω ≡ ≈ ' m k m b which for

ƒThe restoring force and damping force are comparable in effect.

ƒThe system can not oscillate; the amplitude dies away exponentially

Overdamped:

imaginary is which for ' m k m b > ω2 ω 0 2 2 4

ƒThe damping force is much stronger than the restoring force.

ƒThe amplitude dies away as a modified exponential

ƒNote: Cos( ix ) = Cosh( x )

Forced (Driven) Oscillations and Resonance

ƒ An external driving force starts oscillations in a stationary system

ƒ The amplitude remains constant (or grows) if the energy input per cycle exactly equals (or exceeds) the energy loss from damping

ƒ Eventually, Edriving = Elostand a steady-state condition is reached

ƒ Oscillations then continue with constant amplitude

ƒ Oscillations are at the driving frequency ωD

F

D

(t)

)

'

t

cos(

F

)

t

(

F

D

=

0

ω

D

+

φ

Oscillating driving force applied to

d

d

ill t

(7)

Equation for Forced (Driven) Oscillations

ω

0

= natural frequency

ω

D

= driving frequency of external force

External driving force function:

0

k

m

ω

=

F

D

(t)

)

'

t

cos(

F

)

t

(

F

D

=

0

ω

D

+

φ

2 2

( )

( )

( ) -b

- x(t)

m

net D

dx t

d x t

F

F t

k

dt

dt

=

=

Solution for Forced (Driven) Oscillations

)

'

t

cos(

F

)

t

(

F

D

=

0

ω

D

+

φ

2 2

( )

( )

( ) -b

- x(t)

m

net D

dx t

d x t

F

F t

k

dt

dt

=

=

Solution (steady state solution):

F

D

(t)

Th t

l

ill t

t

th

)

t

cos(

A

)

t

(

x

=

ω

D

+

φ

Solution (steady state solution):

2 2 2 0 2 0 ) m b ( ) ( m / F A D D ω + ω − ω =

where

The system always oscillates at the

driving frequency ω

D

in steady-state

The amplitude A depends on how

close ω

D

is to natural frequency ω

0 0

k

m

ω

=

(8)

Amplitude of the driven oscillations:

resonance

ƒ

The largest amplitude

oscillations occur at or

2 2 2 0 2 0 ) m b ( ) ( m / F A D D ω + ω − ω =

near RESONANCE (

ω

D

~

ω

0

)

As damping becomes

weaker

Æ

resonance sharpens

resonance sharpens

&

amplitude at

resonance increases.

Resonance

ƒAt resonance, the applied force is in phase with the velocity and the power Fov transferred to the oscillator is a

maximum.

Th lit d f t

ƒThe amplitude of resonant oscillations can become enormous when the damping is weak, storing enormous amounts of energy

Applications:

buildings driven by earthquakes

buildings driven by earthquakes

bridges under wind load

all kinds of radio devices, microwave

(9)

Forced resonant torsional oscillations due to

wind -

Tacoma Narrows Bridge

(10)

Breaking glass with voice

References

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