International Journal of Mathematics and Mathematical Sciences Volume 2009, Article ID 219586,18pages
doi:10.1155/2009/219586
Research Article
Existence of Solution for
Nonlinear Elliptic Equations with
Unbounded Coefficients and
L
1
Data
Hicham Redwane
Facult´e des Sciences Juridiques, ´Economiques et Sociales, Universit´e Hassan 1, B.P. 784, Settat 26 000, Morocco
Correspondence should be addressed to Hicham Redwane,redwane [email protected]
Received 20 July 2009; Accepted 17 November 2009
Recommended by M ´onica Clapp
An existence result of a renormalized solution for a class of nonlinear elliptic equations is established. The diffusion functionsax, u,∇umay not be inL1
locΩ
N
for a finite value of the unknown and the data belong toL1Ω.
Copyrightq2009 Hicham Redwane. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
1. Introduction
In this paper we investigate the problem of existence of a renormalized solutions for elliptic equations of the type
−divax, u,∇u f inΩ,
u0 on∂Ω, 1.1
where Ω is an open bounded subset of RN, N ≥ 1, with the data f in L1Ω. The
operator−divax, u,∇uis a Leray-Lions operator defined on the weighted sobolev spaces
W01,pΩ, w, but which is not restricted by any growth condition with respect to u see
assumptions2.2,2.4, and2.5ofSection 3. The functionax, s, ξis controlled by a real functionb:− ∞, m→ Rwhich blows up for a finite valuem >0see2.2,2.3.
i.e., in the distribution meaningseems to be an arduous task. To overcome this difficulty we use in this paper the framework of renormalized solutions. This notion was introduced by DiPerna and Lions1for the study of Boltzmann equationsee also Lions2for a few applications to fluid mechanics models. This notion was then adapted to elliptic vesion of 1.1 in Boccardo et al. 3, and Murat 4, 5 see also 6, 7 for nonlinear parabolic problems. At the same time the equivalent notion of entropy solutions has been developed independently by B´enilan et al.8for the study of nonlinear elliptic problems.
In the case whereax, u,∇uis replaced bydu Au∇uproblems with diffusion
matrices that have at least one diagonal coefficient that blows up for a finite value of the unknownandf ∈L2Ω, existence and uniqueness has been established in Blanchard and
Redwane9,10.
As far as we have the stationary and evolution equations case1.1, the existence and a partial uniqueness of renormalized solutions have been proved in Blanchard et al.11in the case whereax, u,∇uis replaced byAx, u∇uwhereAx, sis a Carath´eodory symmetric matrices, such thatAx, sblows up as s → m− uniformly with respect to x. It has also
been applied to the study of linear and nonlinear elliptic and parabolic equations when the diffusion coefficient has a singularity for a finite value of the unknownsee Garc´ıa V´azquez and Orteg ´on Gallego12,13and Orsina14.
The paper is organized as follows. InSection 2we will precise some basic properties of weighted Sobolev spaces.Section 3is devoted to specify the assumptions onax, s, ξ, bs,
andfneeded in the present study and gives the definition of a renormalized solution of1.1. InSection 4Theorem 4.1we establish the existence of such a solution.
2. Preliminaries
Throughout the paper, we assume that the following assumptions hold true.Ωis a bounded open subset onRN, N ≥ 1. Let us suppose that 1 < p < ∞ is a real number, andωx {ωix}{0≤i≤N}is a vector of weight functions. Furthermore we suppose that every component
ωixis a measurable function which is strictly positive and satisfies
ωi∈L1locΩ, ωi−1/p−1∈L1locΩ. 2.1
We define the weighted Lebesgue spaceLpΩ, ω
0with weight ω0, as the space of all
real-valued measurable functionsufor which
up,ω0
Ω|ux|
pω
0xdx
1/p
<∞. 2.2
In order to define the weighted Sobolev space ofW1,pΩ, ω, as the space of all real-valued
functionsu∈LpΩ, ω
0such that the derivaties in the sense of distributions satisfy∂u/∂xi∈
LpΩ, ωifor alli1, . . . , N. This set of functions forms a Banach space under the norm
u1,p,ω
Ω|ux|
pω
0xdx
N
i1
Ω
∂x∂uipωixdx 1/p
To deal with the Dirichlet problem, we use the spaceX W01,pΩ, ωdefined as the closure of C0∞Ω with respect to the norm · 1,p,ω. Note that, C∞0 Ω is dense inW01,pΩ, ωand W01,pΩ, ω, · 1,p,ωis a reflexive Banach space. Note that the expression
uX
N
i1
Ω
∂x∂uipωixdx 1/p
2.4
is a norm defined onXand is equivalent to the norm2.3. MoreoverX, · Xis a reflexive Banach space, and there exist a weight functionσonΩand a parameter 1< q <∞such that the Hardy inequality
Ω|u|
qσxdx
1/q
≤C
N
i1
Ω
∂x∂uipωixdx 1/p
2.5
holds for everyu ∈ X with a constantC > 0 independent of u. Moreover, the imbedding
X →LqΩ, σis compact.
We recall that the dual of the weighted Sobolev spacesW01,pΩ, ω is equivalent to
W−1,pΩ, ω∗, whereω∗ {ω∗ i ω
1−p
i ;i1, . . . , N}andp p/p−1is the conjugate ofp. For more details we refer the reader to15 see also16.
3. Assumptions on the Data and Definition of a Renormalized Solution
Throughout the paper, we assume that the following assumptions hold true.Ωis a bounded open set onRN, N ≥1. Let 1 < p <∞, and letωx {ωix}
{0≤i≤N}be a vector of weight functions.
Let now −divax, u,∇u be a Leray-Lions operator defined on W01,pΩ, ω into
W−1,pΩ, ω∗and where
a:Ω×R×RN−→RN is a Carath´eodory function, such that 3.1
there exists a positive functionb∈C0−∞, mwhich satisfies
lim
r→m−br ∞;
m
0
bsds <∞, br≥α >0∀r ∈−∞, m,
ax, s, ξ·ξ≥bsp−1
N
i1
ωix|ξi|p, ax, s,0 0,
3.2
for almost everyx∈Ω, for everys∈Randξ∈RN. For anyi1, . . . , N,
|aix, s, ξ| ≤ωix1/p ⎡
⎣Lx σx1/p|s|q/p bsp−1
N
j1
ω1j/pxξjp−1
⎤
for almost everyx∈Ω, for everysandξ, and whereLxis a positive function inLpΩ
ax, s, ξ−ax, s, ξξ−ξ≥0, 3.4
for anyξ, ξ ∈RN, for anys∈Rand for almost everyx∈Ω
f is an element ofL1Ω. 3.5
Remark 3.1. As already mentioned in the introduction, problem1.1does not admit a weak solution under assumptions3.1–3.5since the growth ofax, u,∇uis not controlled with respect to u, the field ax, u,∇u is not, in general, defined as a distribution because the difficulty is defining the field ax, u,∇uon the subset{x ∈ Ω;ux m}ofΩ,since on this set,bu ∞.
The following notations will be used throughout the paper. For any K ≥ 0, the truncation at heightKis defined byTKr max−K, minr, K, for any positive numbersl
andK, the functionsTK
l are defined by
TlKr ⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩
−K, ifr≤ −K,
r, if −K≤r≤l,
l, ifr≥l.
3.6
We define forn≥1 fixed
θnr T1r−Tnr
⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩
0, if |r| ≤n,
r−n sgs, if n≤ |r| ≤n1,
sgs, if |r| ≥n1,
3.7
andSnr 1− |θnr|, for allr∈R.
The definition of a renormalized solution for Problem1.1can be stated as follows.
Definition 3.2. A measurable functionudefined onΩis a renormalized solution of Problem 1.1if
TKu∈W01,pΩ, ω ∀K≥0, 3.8
ux≤m for almost everyx∈Ω, 3.9
ax, TmKu,∇TmKuχ{u<m}∈ N
i1
{−n−1≤ux≤−n}ax, u,∇u∇udx−→0 asn−→∞, 3.11
1
δ
{m−2δ≤ux≤m−δ}ax, u,∇u∇udx−→
{um}fdx asδ−→0, 3.12
and if, for every functionSinW1,∞Rsuch that suppSis compact andSm 0, usatisfies
Ωax, u,∇u∇
Suϕdx
ΩfSuϕdx, ∀ϕ∈W
1,p
0 Ω, ω∩L∞Ω. 3.13
The following remarks are concerned withDefinition 3.2.
Remark 3.3. Notice that, thanks to our regularity assumptions 3.8, 3.9, 3.10 and the choice ofS, all terms in3.13are well defined.
The following two identifications are made in3.13:
iax, u,∇u∇Suϕidentifies withax, TK
mu,∇TmKu∇Suϕfor almost every
x∈ Ω, whereK > 0 and suppS⊂ −K, K. As a consequence of3.8,3.9, and 3.10, and ofS∈W1,∞R, ϕ∈W1,p
0 Ω, ω∩L∞Ω, it follows that
ax, TmKu,∇TmKu∇Suϕ∈L1Ω, 3.14
iifSuϕ∈L1Ω, becausef∈L1ΩandSuϕ∈L∞Ω.
4. Existence Result
This section is devoted to establish the following existence theorem.
Theorem 4.1. Under assumptions3.1–3.5there exists a renormalized solutionuof Problem1.1.
Proof. The proof is divided into 7 steps. In Step 1, we introduce an approximate problem. Step 2is devoted to establish a few a priori estimates, the limituof the approximate solutions
uεis introduced and it is shown thatusatisfies3.8and3.9.Step 3is devoted to prove an energy estimateLemma 4.2which is a key point for the monotonicity arguments that are developed inStep 4.Step 5is devoted to prove thatusatisfies3.11. InStep 6we prove that
usatisfies3.12. Finally,Step 7is devoted to prove thatusatisfies3.13ofDefinition 3.2.
Step 1. Let us introduce the following regularization of the data:
bεr bT1/ε m−εr
∀r∈Rforε >0, 4.1
aεx, s, ξ ax, Tm1/ε−εs, ξ a.e.inΩ, ∀s∈R, ∀ξ∈RN, 4.2
fε∈LpΩ; fε
Let us now consider the following regularized problem:
−divaεx, uε,∇uε fε inΩ, 4.4
uε0 on∂Ω. 4.5
In view of3.3,4.1, and4.2,aεsatisfy. Fori1, . . . , N
aε
ix, s, ξ≤ωix1/p
⎡
⎣Lx σx1/pTm1/ε−εs q/p
bεsp−1
N
j1
ω1j/pxξjp−1
⎤
⎦ 4.6
a.e.x∈Ω, for alls∈R, ξ∈RN.And
α≤bεr≤ max
{−1/ε≤r≤m−ε}br Cε ∀r∈R. 4.7
As a consequence, proving existence of a weak solutionuε ∈ W1,p
0 Ω, ωof4.4and
4.5is an easy tasksee, e.g., Theorem 2.1 and Remark 2.1 in Chapter 2 of17and see also 18.
Step 2. A priori estimates and pointwise convergence ofuε. UsingTKuεas a test function in4.4leads to
Ωa
εx, uε,∇uε∇TKuεdx
Ωf
εTKuεdx≤Kf
L1Ω. 4.8
Sinceaεsatisfies3.2,4.2, and owing to4.8we have
Ωb
εuεp−1N
i1
∂TK∂xui εpωixdx≤KfL1Ω, 4.9
αp−1
Ω
N
i1
∂TK∂xuiεpωixdx≤KfL1Ω. 4.10
From4.10we deduce with a classical argumentsee, e.g.,18that, for a subsequence still indexed byε,
uε−→u a.e.inΩ, 4.11
TKuε−→TKuweakly inW01,pΩ, ωand strongly inLqΩ, σ, 4.12
Taking nowZεTmKuε
0 bεsdsas a test function in4.4gives
Ωa
εx, uε,∇uε∇Zεdx
Ωf
εZεdx. 4.13
Sinceaεsatisfies3.2andbsatisfies3.1, permit to deduce from4.13that
Ω
N
i1
∂Z∂xiεpωixdx≤CKfL1Ω, 4.14
where|Zε| ≤m
−KbsdsCKis a constant independent ofε.
Now for a fixedK >0, assumption3.3gives fori1, . . . , N,
aε
i
x, TmKuε,∇TmKuε
≤ωix1/p
⎡
⎣Lx σx1/p maxK, mq/p
N
j1
ω1j/px∂Z
ε
∂xj
p−1⎤
⎦.
4.15
In view of4.14and4.15, we deduce that
aεx, TmKuε,∇TmKuεis bounded in N
i1
LpΩ, w1i−p, 4.16
then there exists a functionXK∈
N
i1LpΩ, w 1−p
i such that
aεx, TmKuε,∇TmKuε XKweakly in N
i1
LpΩ, wi1−p asε−→0. 4.17
To prove thatuis less or equal tomis an easy task which is performed exactly as in10,11. UsingT2muε−Tmuεas a test function in4.4leads to
Ωa
εx, uε,∇uε∇T
2muε−Tmuε
dx
Ωf
εT
2muε−Tmuε
dx, 4.18
which implies easily that
Ωa
εx, uε,∇T
2muε−Tmuε
∇T2muε−Tmuεdx≤mfL1Ω. 4.19
Then3.2,4.1, and4.2yield
bm−εp−1
Ω
N
i1
∂T2muε−T
muε
∂xi
p
With the help of Poincar´e’s inequality, we have
Ω
T2muε−Tmuεpω0xdx≤
Cm
bm−εp−1fL1Ω
, 4.21
whereCdoes not depend onε. Then in view of3.1,4.11, andω0 >0, we can pass to the
limit in4.21asεtends to 0, to deduce that
T2mu−Tmu 0 a.e.inΩ,
u≤m a.e.inΩ. 4.22
Let us now takeTKvεas a test function in4.4, wherevεuε
0 bεsds. We obtain
Ωa
εx, uε,∇uε∇TKvεdx
Ωf
εTKvεdx≤Kf
L1Ω. 4.23
Then3.2yields
Ω
N
i1
∂T∂xKviεpωixdx≤KfL1Ω. 4.24
We deduce with a classical argument that, for a subsequence still indexed byε,
vε−→v a.e.inΩ, 4.25
TKvε−→TKvweakly inW01,pΩ, ω, 4.26
asεtends to 0, wherevis a measurable function defined onΩwhich is finite a.e. inΩ. Using the admissible test functionθnvεin4.4leads to
Ωa
εx, uε,∇uε∇θnvεdx
Ωf
εθnvεdx. 4.27
As a consequence of the previous convergence results, we are in a position to pass to the limit asεtends to 0 in4.27
lim ε→0
Ωa
εx, uε,∇uε∇θnvεdx
Using the pointwise convergence of θnu to 0 as n tends to ∞ and |θnu| ≤ 1 a.e. in Ω independently of n, since f ∈ L1Ω, Lebesgue’s convergence theorem shows that
Ωfθnvdx → 0,asntends to∞. Passing to the limit in4.28we obtain
lim n→∞εlim→0
{n≤|vε|≤n1}
aεx, uε,∇uε∇vεdx0. 4.29
Step 3. In this step we prove the following monotonicity estimate.
Lemma 4.2. The subsequence ofuεdefined in Step 1 satisfies for anyK≥0
lim ε→0
Ω
aεTK
muε,∇TmKuε
bεuεp−1 −
aεTK
muε,∇TmKu
bεuεp−1
∇TK
muε− ∇TmKu
dx0. 4.30
Proof. LetK≥0 be fixed. Equality4.30is split into
Ω
aεTK
muε,∇TmKuε
bεuεp−1 −
aεTK
muε,∇TmKu
bεuεp−1
∇TK
muε− ∇TmKu
dx
Aε1Aε2Aε3,
4.31
where
Aε
1
Ω aεTK
muε,∇TmKuε
bεuεp−1 ∇T K
muεdx ds dt,
Aε2−
Ω aεTK
muε,∇TmKuε
bεuεp−1 ∇T K
mudx ds dt,
Aε3−
Ω aεTK
muε,∇TmKu
bεuεp−1
∇TK
muε− ∇TmKu
dx ds dt.
4.32
In the sequel we pass to the limit in4.31whenεtends to 0.
Limit of
A
ε1Using the admissible test functionSnvεTK mu
0 1/bs
p−1dsin4.4leads to
ΩSnv
εaεx, uε,∇uε∇TmKu
bup−1dx
Ωa
εuε,∇uε∇Snvε·
TK
mu
0
1
bsp−1ds
dx
Ωf
εSnvε
TK mu
0
1
bsp−1dsdx,
4.33
wherevεuε
Since suppSn⊂−n1, n1and{x∈Ω;|vε| ≤n1} ⊂ {x∈Ω;|uε| ≤n1/α}, we have fori1, . . . , Nandε≤α/n1
aε
ix, uε,∇uεSnvεaεi
x, Tn1/α uε,∇Tn1/αuε
Snvε
≤ SnL∞Rωix1/p
⎡
⎣Lx σx1/pTn1/αuεq/p
N j1
ωj1/px∂Tn1v
ε
∂xj
p−1⎤
⎦.
4.34
In view of4.24,4.34we deduce that for fixedn≥1:
aεx, Tn1/αuε,∇Tn1/αuεSnvεis bounded in
N
i1
LpΩ, w1i−p, 4.35
independently ofε≤α/n1. Then there exists a functionYn ∈Ni1LpΩ, w 1−p
i such that for fixedn≥1:
Snvεaεx, Tn1/αuε,∇Tn1/αuε Yn weakly in N
i1
LpΩ, w1i−p asε−→0.
4.36
Now for maxK, m≤n/α, we have
Snvεaεx, T
n1/αuε,∇Tn1/αuε
χ{−K<uε<m}
Snvεaεx, TKmuε,∇TKmuεχ{−K<uε<m}
4.37
a.e. inΩ,which implies that, through the use of4.17,4.25, and4.36and passing to the limit asεtends to 0,
Ynχ{−K<u<m}SnvXKχ{−K<u<m} 4.38
a.e. inΩ− {{u−K} ∪ {um}} for maxK, m≤n/α. As a consequence of4.38we have for maxK, m≤n/α
We are now in a position to exploit4.33, which gives together with4.36and4.39
lim ε→0
ΩSnv
εaεx, uε,∇uε∇TmKu
bup−1dx
lim ε→0
ΩSnv
εaεx, T
n1/αuε,∇Tn1/αuε∇T
K mu
bup−1dx
ΩYn
∇TK
mu
bup−1 dx
ΩSnvXK
∇TK
mu
bup−1dx.
4.40
Passing to the limit asntends to∞in4.40leads to
lim n→∞εlim→0
ΩSnv
εaεx, uε,∇uε∇TmKu
bup−1dx
ΩXK
∇TK
mu
bup−1dx. 4.41
The second term of4.33
Ωa
εx, uε,∇uε∇Snvε.
TK
mu
0
1
bsp−1ds
dx
≤ maxm, K
αp−1
{n≤|vε|≤n1}
aεx, uε,∇uε∇vεdx.
4.42
Then4.29implies that
lim n→∞εlim→0
Ωa
εx, uε,∇uε∇Snvε.
TK
mu
0
1
bsp−1ds
dx0. 4.43
In view4.41and4.43, passing to the limit asεtends to 0 and asntends to∞in4.33is an easy task and leads to
ΩXK
∇TK
mu
bup−1 dx
Ωf TK
mu
0
1
bsp−1ds dx. 4.44
We are now in a position to exploit4.44. The use of the test functionTmKuε
0 1/bεs
p−1dsin4.4, yields
Ωa
εx, uε,∇uε∇TmKuε
bεuεp−1dx
Ωf
ε
TK muε
0
1
Passing to the limit asεtends to 0 in4.45, in view4.44, we have
lim ε→0A
ε
1εlim→0
Ωa
εx, uε,∇uε∇TmKuε
bεuεp−1dx
ΩXK
∇TK
mu
bup−1 dx. 4.46
Limit of
A
ε2In view of4.12,4.17and since 1/bεuεp−1converges to 1/bup−1a.e. inΩand due to the
bound 1/bεuεp−1≤1/αp−1a.e. inΩ, we have
lim ε→0A
ε
2−
ΩXK
∇TK
mu
bup−1dx. 4.47
Limit of
A
ε3Let us remark that3.1,4.1, and4.11imply that
aεx, TK
muε,∇TmKu
bεuεp−1 −→
ax, TK
mu, DTmKu
bup−1 a.e.inΩ, 4.48
asεtends to 0, and that fori1, . . . , N
aεiTmKuε,∇TmKu bεuεp−1
≤w1i/px
⎡
⎣ 1
αp−1Lx
maxK, mq/p
αp−1 σ
1/px N j1
w1j/p∂T
K mu
∂xj
p−1⎤
⎦
4.49
a.e. inΩ, uniformly with respect toε. It follows that whenεtends to 0
ax, TK
muε,∇TmKu
bεuεp−1 −→
ax, TK
mu,∇TKu
bup−1 strongly in
N
i1
LpΩ, w1i−p. 4.50
In view of4.12, we conclude that
∇TK
muε− ∇TmKu
0 weakly in N
i1
LpΩ, wi, asεgoes to 0. 4.51
As a consequence of4.50and4.51we have for allK >0
lim ε→0A
ε
Equations4.46,4.46,4.47, and4.46allow to pass to the limit asεtends to zero in4.31 and to obtain4.30ofLemma 4.2.
Step 4. In this step we identify the weak limitXKand we prove the weakL1convergence of the “truncated” energyaεx, TK
muε,∇TmKuε/bεuεp−1∇TmKuεasεtends to 0. Lemma 4.3. For fixedK≥0, one has
XKa
x, TmKu,∇TmKu a.e.in{x∈Ω;ux< m}. 4.53
And asεtends to 0
aεx, TK
muε,∇TmKuε
bεuεp−1 ∇T
K muε
ax, TK
mu,∇TmKu
bup−1 ∇T
K
muweakly inL1Ω. 4.54
Proof. LetK≥0 be fixed. From4.11and4.50together with4.30ofLemma 4.2, we obtain
lim ε→0
Ω
aεx, TK
muε,∇TmKuε
bTmKuε
p−1 ∇T
K
muεdx
Ω
XK
bTmKu
p−1 ∇TKudx. 4.55
We remark the monotone characterawith respect toξand since 1/bεuεp−1 converges to
1/bup−1a.e. inΩand due to the bound 1/bεuεp−1≤1/αp−1a.e. inΩ, we conclude that for allψ∈Ni1LpΩ, wiwe have
0≤lim ε→0
Ω
aεx, TK
muε,∇TmKuε
bεuεp−1 −
aεx, TK muε, ψ
bεuεp−1
∇TK
muε−ψ
dx
lim ε→0
Ω
aεx, TK
muε,∇TmKuε
bεuεp−1
∇TK
muε−ψ
dx
−lim
ε→0
Ω
aεx, TK muε, ψ
bεuεp−1
∇TK
muε−ψ
dx Ω XK
bup−1
∇TK
mu−ψ
dx−
Ω
ax, TK mu, ψ
bup−1
∇TK
mu−ψ
dx × Ω XK
bup−1 −
ax, TK mu, ψ
bup−1
∇TK
mu−ψ
dx.
4.56
The usual Minty’s argument applies in view of4.56. It follows that
XK
bup−1
ax, TK
mu,∇TmKu
bup−1 a.e.inΩ 4.57
In order to prove4.54, we observe that the monotone character ofawith respect to ξand4.30give
aεx, TmKuε,∇TmKuε bεuεp−1 −
aεx, TmKuε,∇TmKu bεuεp−1
∇TK
muε− ∇TmKu
−→0 4.58
strongly inL1Ωasεtends to 0. Moreover4.12,4.17,4.50, and4.53imply that
aεx, TK
muε,∇TmKuε
bεuεp−1 ∇T
K mu
ax, TK
mu,∇TmKu
bup−1 ∇T
K
mu 4.59
weakly inL1Ωasεtends to 0
aεx, TK
muε,∇TmKu
bεuεp−1 ∇T
K muε
ax, TK
mu,∇TmKu
bup−1 ∇T
K
mu 4.60
weakly inL1Ωasεtends to 0, and
aεx, TK
muε,∇TmKu
bεuεp−1 ∇T K mu
ax, TK
mu,∇TmKu
bup−1 ∇T
K
mu 4.61
strongly inL1Ωasεtends to 0.
Using the above convergence results4.59,4.60, and4.61in4.58we obtain that for anyK≥0
aεx, TK
muε,∇TmKuε
bεuεp−1 ∇T
K muε
ax, TK
mu,∇TmKu
bup−1 ∇T
K
mu 4.62
weakly inL1Ωasεtends to 0.
Step 5. In this step we prove thatusatisfies3.11. UsingTn1
m uε−Tmnuεas a test function in4.4leads to
Ωa
εx, uε,∇uε∇Tn1
m uε−Tmnuε
dx
Ωf
εTn1
m uε−Tmnuε
Since suppTn1
m ·−Tmn·⊂−n1,−n, we have
{−n−1≤uεx≤−n}
aεx, uε,∇uε∇uεdx
Ωa
εx, uε,∇uε∇Tn1
m uε−Tmnuε
dx
Ω
aεx, uε,∇uε
bεuεp−1 ∇
Tmn1uε−TmnuεbTmn−11uεp−1dx
Ω
aεx, Tn1
m uε,∇Tmn1uε
bεuεp−1 ∇T
n1
m uεb
Tmn−11uεp−1dx
−
Ω
aεx, Tn
muε,∇Tmnuε
bεuεp−1 ∇T n muεb
Tmn−11uεp−1dx.
4.64
In view of4.54ofLemma 4.3and sincebTmn−11uεp−1 converges tobTmn−11up−1a.e. inΩ and due to the boundbTn1
m−1uε
p−1 ≤ max
s∈−n−1,m−1bsp−1 a.e. inΩ, we can pass to the
limit asεtends to 0 for fixedn≥0 to obtain
lim ε→0
{−n−1≤uεx≤−n}
aεx, uε,∇uε∇uεdx
Ω
ax, Tn1
m u,∇Tmn1u
bup−1 ∇T
n1
m ub
Tn1
m−1u
p−1
dx
−
Ω ax, Tn
mu,∇Tmnu
bup−1 ∇T
n mub
Tmn−11up−1dx
{−n−1≤ux≤−n}ax, u,∇u∇udx.
4.65
Taking the limit asεtends to 0 andntends to∞in4.63and using the estimate4.64and 4.65show that
lim n→∞
{−n−1≤ux≤−n}ax, u,∇u∇udx≤nlim→∞
{u≤−n}
fdx0. 4.66
Step 6. In this step we prove thatusatisfies3.12. UsingSnvε1/δT
m−δu−Tm−2δuas a test function in4.4leads to
1
δ
ΩSnv
εaεx, uε,∇uε∇T
m−δu−Tm−2δu
dx
ΩSnv
εfε
Tm−δu−Tm−2δu
δ dx,
wherevε uε
0 bεsds. Since suppSn ⊂ −n1, n1and{x ∈ Ω;|vε| ≤n1} ⊂ {x ∈
Ω;|uε| ≤n1/α}we have
1
δ
ΩSnv
εaεx, uε,∇uε∇T
m−δu−Tm−2δu
dx
1
δ
ΩSnv
εaεx, T
n1/αuε,∇Tn1/αuε
∇Tm−δu−Tm−2δudx.
4.68
In view of4.22,4.36,4.39, and4.53, passing to the limit asεtends to 0 andntends to ∞
lim n→∞εlim→0
1
δ
ΩSnv
εaεx, T
n1/αuε,∇Tn1/αuε∇Tm−δu−Tm−2δu
dx
lim n→∞
1
δ
ΩSnva
x, Tn1/αu,∇Tn1/αu
∇Tm−δu−Tm−2δudx
lim n→∞
1
δ
ΩSnvax, Tm−δu,∇Tm−δu∇
Tm−δu−Tm−2δudx
1
δ
Ωax, Tm−δu,∇Tm−δu∇
Tm−δu−Tm−2δudx
1
δ
{m−2δ≤u≤m−δ}ax, u,∇u∇udx.
4.69
Taking the limit asεtends to 0,ntends to∞andδtends to 0 in4.67and using the estimate 4.68and4.69show that
lim δ→0
1
δ
{m−2δ≤u≤m−δ}
ax, u,∇u∇udx lim δ→0
Ωf
Tm−δu−Tm−2δu
δ dx
{um}fxdx.
4.70
Step 7. In this step,uis shown to satisfy3.13. Letϕ ∈W01,pΩ, ω∩L∞Ωand letSbe a function inW1,∞Rsuch that Shas a compact support andSm 0. LetKbe a positive real number such that suppS ⊂ −K, Kandvε uε
0 bεsds. UsingSuSnvεϕas a test
function in4.4leads to
ΩSnv
εaεx, uε,∇uε∇Suϕdx
ΩSuϕa
εx, uε,∇uε∇Snvεdx
Ωf
εSnvεSuϕdx.
4.71
Limit of First Term in
4.71
Since suppSn⊂−n1, n1and{x∈Ω;|vε| ≤n1} ⊂ {x∈Ω;|uε| ≤n1/α}, we have
Snvεaεx, uε,∇uε Snvεaεx, Tn1/αuε,∇Tn1/αuε
a.e.inΩ. 4.72
In view of4.22,4.36,4.39, and4.53, passing to the limit asεtends to 0
lim ε→0
ΩSnv
εaεx, uε,∇uε∇Suϕdx
lim ε→0
ΩSnv
εaεx, T
n1/αuε,∇Tn1/αuε∇Suϕdx
ΩSnva
x, Tn1/αu,∇Tn1/αu∇Suϕdx
ΩSnva
x, TmKu,∇TmKu∇Suϕdx,
lim n→∞εlim→0
ΩSnv
εaεx, uε,∇uε∇Suϕdx
lim n→∞
ΩSnva
x, TmKu,∇TmKu∇Suϕdx
Ωa
x, TmKu,∇TmKu∇Suϕdx
Ωax, u,∇u∇
Suϕdx.
4.73
Limit of Second Term in
4.71
Since suppSn⊂−n1,−n∪n1, nfor anyn≥1. As a consequence
ΩSuϕa
εx, uε,∇uε∇Snvεdx≤ S
L∞ΩϕL∞Ω
{n≤|vε|≤n1}
aεx, uε,∇uε∇vεdx.
4.74
Taking the limit asεtends to 0 andntends to∞in4.74and using the estimate4.29show that
lim n→∞εlim→0
ΩSuϕaεx, uε,∇uε∇Snvεdx0. 4.75
Limit of the Right-Hand Side of
4.71
Due to4.3and4.25, we have
lim n→∞εlim→0
Ωf
εSnvεSuϕdx
As a consequence of the previous convergence results, we are in a position to pass to the limit asεtends to 0 in4.71and to conclude thatusatisfies3.13. The proof of Theorem 4.1is achieved.
Acknowledgment
The author would like to thank the anonymous referees for interesting remarks.
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