ISSN 0975-5748 (online); 0974-875X (print)
Published by RGN Publications http://www.rgnpublications.com
DOI: 10.26713/jims.v11i3-4.419
Research Article
The Existence and Approximation Fixed Point
Theorems for Monotone Nonspreading Mappings in Ordered Banach Spaces
Khanitin Muangchoo-in1,2 and Poom Kumam2,3,*
1Department of Exercise and Sports Science, Faculty of Sports and Health Science, 239, Moo. 4, Muang Chaiyaphum, Chaiyaphum 36000, Thailand
2KMUTTFixed Point Research Laboratory, KMUTT-Fixed Point Theory and Applications Research Group, Department of Mathematics, Faculty of Science, King Mongkut’s University of Technology Thonburi (KMUTT), 126 Pracha-Uthit Road, Bang Mod, Thrung Khru, Bangkok 10140, Thailand
3Center of Excellence in Theoretical and Computational
Science (TaCS-CoE), SCL 802 Fixed Point Laboratory, Science Laboratory Building, King Mongkut’s University of Technology Thonburi (KMUTT), 126 Pracha-Uthit Road, Bang Mod, Thrung Khru, Bangkok 10140, Thailand
*Corresponding author: [email protected]
Abstract. In this paper, we proved some existence theorems of fixed points for monotone nonspreading mappings T in a Banach space E with the partial order ≤. In order to finding a fixed point of such a mapping T , moreover we proved the convergence theorem of Mann iterative schemes under the condition P∞
n=1βn(1 −βn) = ∞, which containβn=n+11 as a special case.
Keywords. Ordered Banach space; Fixed point; Monotone nonspreading mapping; Mann iterative scheme
MSC. 47H07; 47H10
Received: June 6, 2016 Accepted: October 20, 2018
Copyright © 2019 Khanitin Muangchoo-in and Poom Kumam. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
1. Introduction
Let E be a Banach space and E∗ be the dual space of E. For all x ∈ E and f ∈ E∗, let the value of f at x be denoted by 〈x, f 〉. The normalized duality mapping J : E → 2E∗ is defined by
J(x) = {f ∈ E∗: 〈x, f 〉 = kxk2, kf k = kxk}
for all x ∈ E. A single-valued normalized duality mapping is denoted by j, which means a mapping j : E → E∗ such that, for each u ∈ E, j(u) ∈ E∗satisfying the following:
〈 j(u), u〉 = k j(u)kkuk, k j(u)k = kuk.
In 2008, Kohsaka and Takahashi [3] also introduced the class of mappings called the class of nonspreading mappings to study the resolvent of a maximal monotone operator in Banach spaces. Let E be a smooth, strictly convex and reflexive Banach space and K be a nonempty closed convex subset of E.
Definition 1.1. A mapping T : K → K is said to be nonspreading if φ(Tx, T y) + φ(T y, Tx) ≤ φ(Tx, y) + φ(T y, x)
for all x, y ∈ C, where
φ(x, y) = kxk2− 2〈x, j(y)〉 + kyk2.
The set of fixef points of a mapping T : K → K is defined by F(T) := {x ∈ C : T x = x}.
In 1954, Mann [5] introduced the following iteration to finding a fixed point, which is referred to as the Mann iteration,
xn+1= βnxn+ (1 − βn)T xn
for each n ≥ 1, where βn∈ [0, 1] is a sequence with some condition. However, there are not many convergence theorems of such a iteration in a order Banach space (E, ≤). Motivated by the above results, we consider the weak convergence of the Mann iterative scheme for a monotone nonspreading mapping T under the condition
X∞ n=1
βn(1 − βn) = ∞
which contain βn= n+11 as a special case. By motivation of Mann iteration for a monotone nonexpansive mapping of Dehaish and Khamsi [2].
2. Preliminaries
Let P be a closed convex cone of a real Banach space E. A partial order “≤” with respect to P in E is defined as follows:
x ≤ y (x ≤ y) if and on if y − x ∈ P (y − x ∈ ˚P) for all x, y ∈ E, where ˚P is the interior of P .
Throughout this paper, let E be a Banach space with the norm “k · k” and the partial order
that the order intervals are closed and convex. An order interval [x, y] for all x, y ∈ E is given by
[x, y] = {z ∈ E : x ≤ z ≤ y}. (1)
Then the convexity of the order interval [x, y] implies that
x ≤ tx + (1 − t)y ≤ y for all x, y ∈ E with x ≤ y. (2)
Definition 2.1. Let K be a nonempty closed and convex subset of a Banach space E. A mapping T : K → K is said to be:
(1) monotone if T x ≤ T y for all x, y ∈ K with x ≤ y;
(2) monotone nonspreading if T is monotone and kT x − T yk2≤ kx − yk2+ 2〈x − T x, J(y − T y)〉
for all x, y ∈ K with x ≤ y and J is normalized duality mapping.
A Banach space E is said to be:
(1) strictly convex if kx+y2 k < 1 for all x, y ∈ E with kxk = kyk = 1 and x 6= y;
(2) uniformly convex if, for allε ∈ (0,2], there exists δ > 0 such that kx+yk2 < 1−δ for all x, y ∈ E with kxk = kyk = 1 and kx − yk ≥ ε.
The following inequality was showed by Xu [9] in a uniformly convex Banach space E, which is known as Xu’s inequality.
Lemma 2.2 (Xu [9, Theorem 2]). For any real numbers q > 1 and r > 0, a Banach space E is uniformly convex if and only if there exists a continuous strictly increasing convex function g : [0, +∞) → [0,+∞) with g(0) = 0 such that
ktx + (1 − t)ykq≤ tkxkq+ (1 − t)kykq− ω(q, t)g(kx − yk) (3) for all x, y ∈ Br(0) = {x ∈ E;kxk ≤ r} and t ∈ [0,1], where ω(q, t) = tq(1 − t) + t(1 − t)q. In particular, take q = 2 and t =12,
°
°
° x + y
2
°
°
°
2
≤1
2kxk2+1
2kyk2−1
4g(kx − yk). (4)
The following conclusion is well known:
Lemma 2.3 (Takahashi [8, Theorem 1.3.11]). Let K be a nonempty closed convex subset of a reflexive Banach space E. Assume thatϕ : K → R is a proper convex lower semi-continuous and coercive function. Then the functionϕ attains its minimum on K, that is, there exists x ∈ K such that
ϕ(x) = inf
y∈Kϕ(y).
Theorem 2.4. Let {xn} be a bounded above monotone nondecreasing sequence. Then {xn} converges to the supemum of {xn: n ∈N}.
Lemma 2.5. Let K be a nonempty closed convex subset of a uniformly convex Banach space (E, ≤) and T : K → K be a monotone nonspreading mapping. If x ∈ K such that xn+1= T xn, the sequence {T xn}∞
n=1 is bounded. Then lim sup
n→∞ kxn− T xnk → 0.
Proof. From Theorem 2.4 {xn} is bounded and monotone increasing then there exists M > 0 such that kxnk ≤ M so,
lim sup
n→∞ kxn− Mk ≤ 0 by analogy we obtain
lim sup
n→∞ kxn+1− Mk ≤ 0 so,
lim sup
n→∞ kxn− xn+1k ≤ lim sup
n→∞ [kxn− Mk + kxn+1− Mk]
≤ lim sup
n→∞ kxn− Mk + lim sup
n→∞ kxn+1− Mk
= 0, therefore, we can conclude that
lim sup
n→∞ kxn− xn+1k → 0. (5)
Theorem 2.6. Let {xn} be a bounded above monotone nonincreasing sequence, then {xn} converges to the infimum of {xn: n ∈N}.
Lemma 2.7. Let K be a nonempty closed convex subset of an uniformly convex Banach space (E, ≤) and T : K → K be a monotone nonspreading mapping. If x ∈ K such that xn+1= T xn, the sequence {T xn}∞
n=1is bounded. Then lim sup
n→∞ kxn− T xnk → 0.
Proof. From Theorem 2.6 {xn} is bounded and monotone decreasing then there exists M > 0 such that kxnk ≤ M so,
lim inf
n→∞ kxn− Mk ≤ 0 by analogy we get
lim inf
n→∞ kxn+1− Mk ≤ 0 so,
lim inf
n→∞ kxn− xn+1k ≥ lim inf
n→∞ [kxn− Mk + kxn+1− Mk]
≥ lim inf
n→∞ kxn− Mk + lim inf
n→∞ kxn+1− Mk
= 0.
Therefore, we can conclude that lim inf
n→∞ kxn− xn+1k → 0
on the other hand, we can conclude that lim inf
n→∞ kxn− xn+1k = lim sup
n→∞ kxn− xn+1k → 0. (6)
Definition 2.8. Let E be a smooth Banach space and define the functionalφ : E × E → R by φ(x, y) = kxk2− 2〈x, J y〉 + |y|2
for x, y ∈ E from the definition of φ, we have (kxk − kyk)2≤ φ(x, y) ≤ (kxk + kyk)2,
kxk2− 2kxkkyk + kyk2≤ kxk2− 2〈x, J y〉 + kyk2≤ kxk2+ 2kxkkyk + kyk2 and, we can conclude that
2〈x, J y〉 ≤ 2kxkkyk. (7)
3. Main Results
3.1 Existence of Fixed Points
In this section, we prove the existence theorem of fixed points of a monotone nonspreading mapping in an uniformly convex Banach space (E, ≤).
Theorem 3.1. Let K be a nonempty and closed convex subset of an uniformly convex Banach space (E, ≤) and T : K → K be a monotone nonspreading mapping. Assume that there exists x ∈ K such that x ≤ T x, the sequence {T xn}∞
n=1is bounded and T xn≤ y for some y ∈ K and all n ≥ 1.
ThenF(T) 6= ; and x ≤ y∗ for some y∗∈ F(T).
Proof. Let x1= x, and xn+1= T xn= Tnx. So, we have x1= x ≤ T x = x2, and so, we get x2= T x1= T x ≤ T x2= T2x = x3.
By analogy, we must have
x = x1≤ x2≤ x3≤ · · · ≤ xn≤ xn+1≤ · · · .
Let Kn= {z ∈ K; xn≤ z} for all n ≥ 1. Clearly, for each n ≥ 1, Kn is closed convex (Kn∈ K ) and Kn is nonempty too ( y ∈ Kn). Let K∗= ∞T
n=1
Kn. Then K∗ is a nonempty closed convex subset of K . Since {xn} is bounded, we can define a functionϕ : K∗→ [0, +∞) as follows:
ϕ(z) = limsup
n→∞ kxn− zk2
for all z ∈ K∗. From Lemma 2.3, it follows that there exists y∗∈ K such that ϕ(y∗) = inf
z∈K∗ϕ(z). (8)
Now, we show y∗= T y∗. In fact, by the definition of K∗, we obtain x1≤ x2≤ x3≤ · · · ≤ xn≤ xn+1≤ · · · ≤ y∗.
Then, we have xn+1= T xn≤ T y∗by the monotonicity of T and hence, for each n ≥ 1, xn≤ T y∗. So we have T y∗∈ K∗. From the convexity of K∗, it follows that y∗+T y2 ∗ ∈ K∗and so, by equation (8), we have
ϕ(y∗) ≤ ϕ³y∗+ T y∗ 2
´
and ϕ(y∗) ≤ ϕ(T y∗). (9)
By the way, from equations (5) and (7), we obtain ϕ(T y∗) = limsup
n→∞ kxn+1− T y∗k2
= lim sup
n→∞ kT xn− T y∗k2
≤ lim sup
n→∞ [kxn− y∗k2+ 2〈xn− T xn, J( y∗− T y∗)〉]
≤ lim sup
n→∞ [kxn− y∗k2+ 2kxn− T xnkky∗− T y∗k]
≤ lim sup
n→∞ kxn− y∗k2+ lim sup
n→∞ 2kxn− T xnkky∗− T y∗k
≤ lim sup
n→∞ kxn− y∗k2 (10)
= ϕ(y∗).
Combining equations (9) and (10), we have
ϕ(T y∗) = ϕ(y∗). (11)
It follows from Lemma 2.7 (q = 2 and t =12) and equation (11) that ϕ³y∗+ T y∗
2
´
= lim sup
n→∞
°
°
°xn−y∗+ T y∗ 2
°
°
°
2
= lim sup
n→∞
°
°
°
xn− y∗
2 +xn− T y∗ 2
°
°
°
2
≤ lim sup
n→∞
³1
2kxn− y∗k2+1
2kxn− T y∗k2−1
4g(ky∗− T y∗k)
´
≤1
2ϕ(y∗) +1
2ϕ(T y∗) −1
4g(ky∗− T y∗k)
= ϕ(y∗) −1
4g(ky∗− T y∗k).
Noticing equation (9), we have g(ky∗− T y∗k) ≤ ϕ(y∗) − ϕ
³y∗+ T y∗ 2
´
≤ 0
and from Lemma 2.2, we have g(ky∗− T y∗k) = 0. Thus we have y∗= T y∗ by the property of g.
This yields the desired conclusion.
Theorem 3.2. Let K be a nonempty and closed convex subset of an uniformly convex Banach space (E, ≤) and T : K → K be a monotone nonspreading mapping. Assume that there exists x ∈ K such thatT x ≤ x, the sequence {T xn}∞
n=1is bounded and y ≤ T xn for some y ∈ K and all n ≥ 1.
ThenF(T) 6= ; and y∗≤ x for some y∗∈ F(T).
Proof. Let x1= x and xn+1= T xn= T xn. Then T x = x2≤ x1= x, and so, T x2= T2x = x3≤ x2= T x1= T x .
By analogy, we have
· · · ≤ xn+1≤ xn≤ · · · ≤ x3≤ x2≤ x = x1.
Let Kn= {z ∈ K; z ≤ xn}for all n ≥ 1. Clearly, for each n ≥ 1, Kn is closed convex (Kn∈ K ) and Kn is nonempty too ( y ∈ Kn). Let K∗= ∞T
n=1
Kn. Then K∗ is a nonempty closed convex subset of
K . Since {xn} is bounded, we can define a functionϕ : K∗→ [0, +∞) as follows:
ϕ(z) = limsup
n→∞ kxn− zk2
for all z ∈ K∗. From Lemma 2.2, it follows that there exists y∗∈ K such that ϕ(y∗) = inf
z∈K∗ϕ(z). (12)
Now, we show y∗= T y∗. In fact, by the definition of K∗, we obtain y∗≤ · · · ≤ xn+1≤ xn≤ · · · ≤ x3≤ x2≤ x1.
Then, we have T y∗≤ xn+1= T xn by the monotonicity of T and hence, for each n ≥ 1, T y∗≤ xn. So we have T y∗∈ K∗. From the convexity of K∗, it follows that y∗+T y2 ∗ ∈ K∗and so, by equation (12), we have
ϕ(y∗) ≤ ϕ³y∗+ T y∗ 2
´
and ϕ(y∗) ≤ ϕ(T y∗). (13)
On the other hand, by using equations (6) and (7) we get ϕ(T y∗) = limsup
n→∞ kxn+1− T y∗k2= lim sup
n→∞ kT xn− T y∗k2
≤ lim sup
n→∞ [kxn− y∗k2+ 2〈xn− T xn, J( y∗− T y∗)〉]
≤ lim sup
n→∞ [kxn− y∗k2+ 2kxn− T xnkky∗− T y∗k]
≤ lim sup
n→∞ kxn− y∗k2+ lim sup
n→∞ 2kxn− T xnkky∗− T y∗k
≤ lim sup
n→∞ kxn− y∗k2
= ϕ(y∗). (14)
Combining equations (13) and (14), we have
ϕ(T y∗) = ϕ(y∗). (15)
It follows from Lemma 2.7 (q = 2 and t =12) and (15) that ϕ³y∗+ T y∗
2
´
= lim sup
n→∞
°
°
°xn−y∗+ T y∗ 2
°
°
°
2
= lim sup
n→∞
°
°
°
xn− y∗
2 +xn− T y∗ 2
°
°
°
2
≤ lim sup
n→∞
³1
2kxn− y∗k2+1
2kxn− T y∗k2−1
4g(ky∗− T y∗k)
´
≤1
2ϕ(y∗) +1
2ϕ(T y∗) −1
4g(ky∗− T y∗k)
= ϕ(y∗) −1
4g(ky∗− T y∗k).
Noticing equation(13), we have
g(ky∗− T y∗k) ≤ ϕ(y∗) − ϕ³y∗+ T y∗ 2
´
≤ 0
and from Lemma 2.2, we have g(ky∗− T y∗k) = 0. Thus we have y∗= T y∗by the property of g.
This yields the desired conclusion. This completes the proof.
3.2 The Convergence of the Mann Iteration
In this section, for a monotone nonspreading mapping T , we consider the Mann iteration sequence defined by
xn+1= βnxn+ (1 − βn)T xn (16)
for each n ≥ 1, where {βn} in (0, 1) satisfies the following condition:
X∞ n=1
βn(1 − βn) = ∞.
Clearly, the above condition containsβn=n+11 as a special case.
Lemma 3.3 (Dehaish and Khamsi [2, Lemma 3.1]). Let K be a nonempty and closed convex subset of a Banach space (E, ≤) and T : K → K be a monotone mapping. Assume that the sequence {xn} is defined by equation(16) and x1≤ T x1 (or T x1≤ x1). If F(T) 6= ; and p ≤ x1 (or x1≤ p) for some p ∈ F(T), then
(1) {xn} is bounded and xn≤ xn+1≤ T xn(or T xn≤ xn+1≤ xn);
(2) xn≤ x (or x ≤ xn) for all n ≥ 1 provided {xn} weakly converges to a point x ∈ K .
Lemma 3.4. Let K be a nonempty and closed convex subset of a Banach space (E, ≤) and T : K → K be a monotone nonspreading mapping. Assume that the sequence {xn} is defined by equation (16) and x1≤ T x1 (or T x1≤ x1). If F(T) 6= ; and p ≤ x1 (or x1≤ p) for some p ∈ F(T), then
n→∞lim kxn− pk exists.
Proof. Assume that p ≤ xn for any n ≥ 1. Since T is monotone, then we obtain p = T p ≤ T x1. Since the order interval [p, →) is convex, assume p ≤ x2 since T is monotone, then we have T p ≤ T x2. By induction we will show that p ≤ xnfor any n ≥ 1, as claimed. Since T is monotone nonspreading, from equation (7), we have p = T p and we get
kT xn− pk2= kT xn− T pk2
≤ kxn− pk2+ 2〈xn− T xn, J(p − T p)〉
≤ kxn− pk2+ 2kxnkkp − T pk
≤ kxn− pk2 it follows that,
kT xn− pk ≤ kxn− pk.
Since equation (16), which implies
kxn+1− pk ≤ tnkT xn− pk + k(1 − tn)kxn− pk
≤ tnkxn− pk + k(1 − tn)kxn− pk
≤ kxn− pk
for any n ≥ 1. This means that kxn− pk is a monotone sequence, which implies that lim
n→∞kxn− pk exists.
Theorem 3.5. Let K be a nonempty and closed convex subset of an uniformly convex Banach space (E, ≤) and T : K → K be a monotone nonspreading mapping. Assume that the sequence {xn} is defined by equation(16) and x1≤ T x1 (or T x1≤ x1). If F(T) 6= ; and p ≤ x1 (or x1≤ p) for some p ∈ F(T), then
n→∞lim kxn− T xnk = 0.
Proof. It follows from Lemma 3.4 that p ≤ x1≤ xn(or xn≤ x1≤ p)
for all n ≥ 1. Then it follows from the nonspreadingness of T, p = T p and an application of Lemma 2.7 (q = 2 and t = βn) that
kxn+1− pk2= kβn(xn− p) + (1 − βn)(T xn− T p)k2
≤ βnkxn− pk2+ (1 − βn)kT xn− T pk2− βn(1 − βn)g(kxn− T xnk)
≤ βnkxn− pk2+ (1 − βn)kxn− pk2+ 2kxn− T xnkkp − T pk − βn(1 − βn)g(kxn− T xnk)
≤ βnkxn− pk2+ (1 − βn)kxn− pk2− βn(1 − βn)g(kxn− T xnk)
≤ kxn− pk2− βn(1 − βn)g(kxn− T xnk) and so
βn(1 − βn)g(kxn− T xnk) ≤ kxn− pk2− kxn+1− pk2. Therefore, we have
X∞ n=1
βn(1 − βn)g(kxn− T xnk) ≤ kx1− pk2< +∞. (17) Now, we claim that there exists a subsequence {xnk}such that
k→∞lim g(kxnk− T xnkk) = 0. (18)
Suppose that the conclusion is not true. Then, for all subsequence {xnk}such that lim
k→∞g(kxnk− T xnkk) > 0, we have
lim inf
n→∞ g(kxn− T xnk) > 0.
Thus there exists a positive number a and a positive integer N such that g(kxn− T xnk) > a > 0 for all n > N. Consequently, we have
βn(1 − βn)g(kxn− T xnk) ≥ aβn(1 − βn) and hence, by the condition ∞P
n=1βn(1 − βn) = +∞, we obtain X∞
n=1
βn(1 − βn)g(kxn− T xnk) = +∞.
This contradicts equation (17). So equation (18) holds and hence, by the property of g(0) = 0, we have
k→∞limkxnk− T xnkk = 0.
Otherwise, we obtain
kxn+1− T xn+1k = kβn(xn− T xn) + (T xn− T xn+1)k
≤ βnkxn− T xnk + kxn+1− xnk
= βnkxn− T xnk + (1 − βn)kxn− T xnk
= kxn− T xnk.
Therefore, the sequence {kxn− T xnk} is monotonically nonincreasing and hence it follows that
n→∞lim kxn− T xnk exists. This yields the desired conclusion.
Recall that a Banach space E is said to satisfy Opial’s condition ([7]) if a sequence {xn}with {xn}weakly converges to a point x ∈ E implies
lim sup
n→∞ kxn− xk < lim sup
n→∞ kxn− yk for all y ∈ E with y 6= x.
Next, we show the weak convergence of the sequence {xn}defined by equation (16). The proof is similar to ones of Dehaish and Khamsi [2], but, for more details, we give the proof.
Theorem 3.6. Let K be a nonempty and closed convex subset of an uniformly convex Banach space (E, ≤) and T : K → K be a monotone nonspreading mapping. Assume that E satisfies Opial’s condition and the sequence {xn} is defined by equation(16) with x1≤ T x1 (or T x1≤ x1).
If F(T) 6= ; and p ≤ x1 (or x1≤ p) for some p ∈ F(T), then {xn} weakly converges to a fixed point x∗ ofT .
Proof. It follows from Lemma 3.4 and Theorem 3.5 that {xn} is bounded and
n→∞lim kxn− T xnk = 0.
Then, there exists a subsequence {xnk} ⊂ {xn}such that {xnk}weakly converges to a point x∗∈ K.
Following Lemma 3.4, we have x1≤ xnk≤ x∗ (or x∗≤ xnk ≤ x1) for all k ≥ 1. In particular, we have
k→∞limkxnk− T xnkk = 0.
Now, we claim that x∗ = T x∗. In fact, assume that this is not true. Then, from the nonspreadingness of T and Opial’s condition, it follows that
lim sup
k→∞
kxnk− x∗k < lim sup
k→∞
kxnk− T x∗k
≤ lim sup
k→∞ (kxnk− T xnkk + kT xnk− T x∗k)
≤ lim sup
k→∞ (kT xnk− T x∗k). (19)
Consider equation (19), lim sup
k→∞ kT xnk− T x∗k2≤ lim sup
k→∞ [kxnk− x∗k2+ 2kxnk− T xnkkkx∗− T x∗k]
≤ lim sup
k→∞
kxnk− x∗k2+ lim sup
k→∞ 2kxnk− T xnkkkx∗− T x∗k
≤ lim sup
k→∞
kxnk− x∗k2. (20)
So, we get
From equations (19) and (21), we obtain lim sup
k→∞
kxnk− x∗k ≤ lim sup
k→∞
kxnk− x∗k
which is a contradiction. Thus, by Lemma 3.4, it follows that the limit lim
n→∞kxn− x∗k exists. Now, we show that {xn} weakly converges to the point x∗. Suppose that this is not true. Then There exists a subsequence {xnj} to converge weakly to a point z ∈ K and z 6= x∗. Similarly, it follows that z = T z and lim
n→∞kxn− zk exists. It follows from Opial’s condition that
n→∞lim kxn− zk < lim
n→∞kxn− x∗k = lim sup
i→∞
kxni− x∗k < lim
n→∞kxn− zk.
This is a contradiction and hence x∗= z. This completes the proof.
4. Conclusions
We prove some existence theorems of fixed point for monotone nonspreading mapping in a Banach space E with the partial order ≤.
Theorem 4.1. Let K be a nonempty and closed convex subset of an uniformly convex Banach space (E, ≤) and T : K → K be a monotone nonspreading mapping. Assume that there exists x ∈ K such that x ≤ T x, the sequence {T xn}∞n=1is bounded and T xn≤ y for some y ∈ K and all n ≥ 1.
ThenF(T) 6= ; and x ≤ y∗ for some y∗∈ F(T).
Theorem 4.2. Let K be a nonempty and closed convex subset of an uniformly convex Banach space (E, ≤) and T : K → K be a monotone nonspreading mapping. Assume that there exists x ∈ K such thatT x ≤ x, the sequence {T xn}∞
n=1is bounded and y ≤ T xn for some y ∈ K and all n ≥ 1.
ThenF(T) 6= ; and y∗≤ x for some y∗∈ F(T).
In part of convergence theorem, we prove a weak convergence theorem for monotone nonspreading in order Banach space (E, ≤).
Theorem 4.3. Let K be a nonempty and closed convex subset of an uniformly convex Banach space (E, ≤) and T : K → K be a monotone nonspreading mapping. Assume that E satisfies Opial’s condition and the sequence {xn} is defined by equation(16) with x1≤ T x1 (or T x1≤ x1).
If F(T) 6= ; and p ≤ x1 (or x1≤ p) for some p ∈ F(T), then {xn} weakly converges to a fixed point x∗ ofT .
And we can get some results if we reduce some conditions for prove some existence theorems of fixed point by using a monotone nonexpansive mapping T in a Banach space E with the partial order “≤”, in Theorem 4.1 and 4.2, we have following corollaries respectively.
Corollary 4.4. Let K be a nonempty and closed convex subset of an uniformly convex Banach space (E, ≤) and T : K → K be a monotone nonexpansive mapping. Assume that there exists x ∈ K such that x ≤ T x, the sequence {T xn}∞
n=1is bounded and T xn≤ y for some y ∈ K and all n ≥ 1.
ThenF(T) 6= ; and x ≤ y∗ for some y∗∈ F(T).
Corollary 4.5. Let K be a nonempty and closed convex subset of an uniformly convex Banach space (E, ≤) and T : K → K be a monotone nonexpansive mapping. Assume that there exists x ∈ K
such thatT x ≤ x, the sequence {T xn}∞
n=1is bounded and y ≤ T xn for some y ∈ K and all n ≥ 1.
ThenF(T) 6= ; and y∗≤ x for some y∗∈ F(T).
And if we consider the convergence of Mann iteration for a monotone nonexpansive mapping T , in Theorem 3.5 and 4.3 by using Dehaish and Khamsi [2, Lemmas 3.1 and 3.2], we have following corollary:
Corollary 4.6. Let K be a nonempty and closed convex subset of an uniformly convex Banach space (E, ≤) and T : K → K be a monotone nonexpansive mapping. Assume that the sequence {xn} is defined by equation (16) and x1≤ T x1 (or T x1≤ x1). If F(T) 6= ; and p ≤ x1 (or x1≤ p) for some p ∈ F(T), then lim
n→∞kxn− T xnk = 0.
Corollary 4.7. Let K be a nonempty and closed convex subset of an uniformly convex Banach space (E, ≤) and T : K → K be a monotone nonexpansive mapping. Assume that E satisfies Opial’s condition and the sequence {xn} is defined by equation(16) with x1≤ T x1 (or T x1≤ x1).
If F(T) 6= ; and p ≤ x1 (or x1≤ p) for some p ∈ F(T), then {xn} weakly converges to a fixed point x∗ ofT .
Acknowledgement
The author would like to thank Theoretical and Computational Science (TaCS) Center under Computational and Applied Science for Smart Innovation Research Cluster (CLASSIC), Faculty of Science, KMUTT for financial support.
Competing Interests
The authors declare that they have no competing interests.
Authors’ Contributions
All the authors contributed significantly in writing this article. The authors read and approved the final manuscript.
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