R E S E A R C H
Open Access
Solutions for a fractional difference boundary
value problem
Wei Dong
1*, Jiafa Xu
2and Donal O’Regan
3*Correspondence:
1Department of Mathematics,
Hebei University of Engineering, Handan, Hebei 056038, China Full list of author information is available at the end of the article
Abstract
Using a variational approach and critical point theory, we investigate the existence of solutions for a fractional difference boundary value problem.
MSC: 26A33; 35A15; 39A12; 44A55
Keywords: fractional difference boundary value problem; variational approach; critical point theory; solution
1 Introduction
In this work, using variational methods and critical point theory, we study the fractional difference boundary value problem
⎧ ⎨ ⎩
Tνt–(tνν–x(t)) =f(x(t+ν– )), t∈[,T]N,
x(ν– ) = [tνν–x(t)]t=T= ,
(.)
whereν∈(, ),tνν–andTνt are, respectively, the left fractional difference and the right
fractional difference operators,t∈[,T]N:={, , , . . . ,T}, andf :R→Ris continuous.
Fractional calculus has a long history, and there is renewed interest in the study of both fractional calculus and fractional difference equations. In [, ], the authors discussed properties of the generalized falling function, a corresponding power rule for fractional delta-operators and the commutativity of fractional sums. A number of papers have ap-peared which build the theoretical foundations of discrete fractional calculus (for more details, we refer the reader to [–] and the references therein).
Atici and Eloe [] considered the existence of positive solutions for the following two-point boundary value problem for a nonlinear finite fractional difference equation:
⎧ ⎨ ⎩
–νy(t) =f(t+ν– ,y(t+ν– )), t= , , . . . ,b+ ,
y(ν– ) = , y(ν+b+ ) = . (.)
In [], the authors used the mountain pass theorem, a linking theorem, and Clark’s the-orem to establish the existence of multiple solutions for a fractional difference boundary value problem with a parameter. Under some suitable assumptions, they obtained some results which ensure the existence of a precise interval of parameters for which the prob-lem admits multiple solutions. We note that there are many papers in the literature [–] which discuss discrete problems via variational and critical point theory.
In [], Tian and Henderson studied the nth order nonlinear difference equation
nr(t–n)nx(t–n)+ft,x(t)= , t∈Z, (.)
and established some existence results for anti-periodic solutions under various assump-tions on the nonlinearity. In [], Ye and Tang considered the second-order discrete Hamil-tonian system
u(t– ) +d(t)u(t)μ–u(t) +∇Ht,u(t)= , ∀t∈Z,
and obtained an existence theorem for a nonzeroT-periodic solution.
In the literature on discrete problem via critical point theory, the authors are interested in the existence of at least one solution or infinitely many solutions. The existence of a unique solution is not usually studied. In this paper, using Browder’s theorem, first we present a uniqueness result in Section . Then a linking theorem is used to establish exis-tence. Finally, assuming an Ambrosetti-Rabinowitz type condition, we show that problem (.) has many solutions if the nonlinearity is odd.
2 Preliminaries
For convenience, throughout this paper, we arrangemi=jx(i) = form<j. We present some definitions and lemmas for discrete fractional operators.
For any integerβ, letNβ:={β,β+ ,β+ , . . .}andt(ν):=(t+ )/(t+ –ν), wheret andνare determined by (.). We also appeal to the convention that ift+ –νis a pole of the gamma function andt+ is not a pole, thent(ν)= .
Definition .(see [, ]) Theνth fractional sum off forν> is defined by
–ν
a f(t) =
(ν)
t–ν
s=a
(t–s– )(ν–)f(s) fort∈Na–ν. (.)
We also define theνth fractional difference forν> byνf(t) :=Nν–Nf(t), wheret∈
Na+N–νandN∈Nis chosen so that ≤N– <ν≤N.
Definition .(see [, ]) Letf be any real-valued function andν∈(, ). The left discrete
fractional difference and the right discrete fractional difference operators are, respectively, defined as
tνaf(t) =t–(–ν)a f(t)
=
( –ν)
t+ν–
s=a
(t–s– )(–ν)f(s), t≡a–ν+ (mod),
bνtf(t) = –b–(–ν)t f(t)
=
( –ν)(–)
b
s=t+–ν
(s–t– )(–ν)f(s), t≡b+ν– (mod).
Definition . Suppose thatXis a Banach space andI:X→Ris a functional defined onX. For givenx,y∈X, assume that
lim ε→
I(x+εy) –I(x)
ε (.)
exists. ThenIis Gateaux differentiable atx, the limit in (.) is called the Gateaux differ-ential ofIatxin directiony, and is denoted by (I(x),y),i.e.,
I(x),y=lim ε→
I(x+εy) –I(x)
ε . (.)
Definition .(see [, p.]) LetXbe a reflexive real Banach space andX∗its dual. The operatorL:X→X∗is said to be demicontinuous ifLmaps strongly convergent sequences inXto weakly convergent sequences inX∗.
Lemma .(Browder theorem, see [, Theorem ..]) Let X be a reflexive real Banach space.Moreover,let L:X→X∗be an operator satisfying the conditions
(i) Lis bounded and demicontinuous, (ii) Lis coercive,i.e.,limx→∞(Lx(x),x)= +∞,
(iii) Lis monotone on the spaceX,i.e.,for allx,y∈X,we have
L(x) –L(y),x–y≥. (.)
Then the equation L(x) =f∗has at least one solution x∈X for every f∗∈X∗.If,moreover,
the inequality(.)is strict for all x,y∈X,x= y,then the equation L(x) =f∗has precisely one solution x∈X for all f∗∈X∗.
Definition .(see [–]) LetXbe a real Banach space,I∈C(X,R) andc∈R. We say thatIsatisfies the (PS)ccondition if any sequence{xn} ⊂Xsuch thatI(xn)→cand I(xn)→ asn→ ∞has a convergent subsequence.
Lemma .(Linking theorem, Rabinowitz, see [–]) Let X=Y⊕Z be a Banach space with Z closed in X anddimY<∞.Letρ>r> ,and let z∈Z be such thatz=r.Define
M:=u=y+λz:u ≤ρ,λ≥,y∈Y, N:=u∈Z:u=r, M:=u=y+λz:y∈Y,u=ρandλ≥, oru ≤ρandλ= .
Let I∈C(X,R)be such that
b:= inf
u∈NI(u) >a:=u∈Mmax I(u).
If I satisfies the(PS)ccondition with
c:=inf γ∈maxu∈MI
γ(u), where:=γ ∈C(M,X) :γ|M=id,
Definition .(see [–]) LetXbe a real Banach space andI∈C(X,R). We say thatI satisfies the Cerami condition ((C) condition for short) if any sequence{xn} ⊂Xsuch that I(xn) is bounded and ( +xn)I(xn) → asn→ ∞, there exists a subsequence of{xn}
which is convergent inX.
Lemma .(Mountain pass theorem, see [–]) Let X be a real Banach space,and let I∈C(X,R)satisfy the(C)condition.If I(θ) = and the following conditions hold:
(i) there are two positive constantsρ,ηand a closed linear subspaceXofXsuch that codimX=landI|X∩∂Bρ≥η,whereBρis an open ball of radiusρwith centerθ;
(ii) there is a subspaceXwithdimX=m,m>l,such that
I(x)→–∞ asx → ∞,x∈X.
Then I possesses at least m–l distinct pairs of nontrivial critical points.
In what follows, we establish the variational framework for (.). Let
X:=x=x(ν– ),x(ν), . . . ,x(ν+T– )+:x(ν+i– )∈R,i= , , . . . ,T. (.) ThenXis theT+ -dimensional Hilbert space with the usual inner product and the usual norm
(x,z) =
T+ν–
t=ν–
x(t)z(t), x= T+ν–
t=ν– x(t)
, x,z∈X. (.)
Forα> , we define theα-norm onX:xα= (Tt=ν–+ν–|x(t)|α)α. SincedimX<∞, we see that there existcα> ,cα> such that
cαx ≤ xα≤cαx (.)
for allxbelonging toX(or its subspace).
In view of [, (.)], we can define an energy functional onXby
I(x) =
T
t=–
tνν–x(t)
–
T
t=–
Fx(t+ν– ), x∈X, (.)
where
Fx(t+ν– )=
x(t+ν–)
f(s) ds,
x(ν– ) = , tνν–x(t)
t=T=
–ν ( –ν)
T+ν
s=ν–
(T+s– )(–ν–)x(s) = .
Clearly,I(θ) = . Let
E:=χ=x(ν– ),x(ν– ), . . . ,x(ν+T)+
∈RT+:x(ν– ) = ,
tνν–x(t)
t=T=
Then, from the boundary conditions of (.), it is easy to see thatEis isomorphic toX. In the following, when we sayx∈X, we always imply thatxcan be extended toχ∈Eif it is necessary. Now we claim that ifx= (x(ν– ),x(ν), . . . ,x(ν+T– ))+∈Xis a critical point of
I, thenχ= (x(ν– ),x(ν– ), . . . ,x(ν+T))+∈Eis precisely a solution of (.). Indeed, sinceI can be viewed as a continuously differentiable functional defined on the finite dimensional Hilbert spaceX, the Fréchet derivativeI(x) is zero if and only if∂I(x)/∂x(i) = for all
i=ν– ,ν, . . . ,ν+T– . From the relation between the Fréchet derivative and the Gateaux derivative, we obtain
I(x),y= lim ε→
I(x+εy) –I(x)
ε =
ε
T
t=–
tνν–
x(t) +εy(t)–tνν–x(t)
–
T
t=–
F(x+εy)(t+ν– )–Fx(t+ν– )
=
T
t=–
tνν–x(t)tνν–y(t) –
T
t=–
fx(t+ν– )y(t+ν– ). (.)
Therefore, in order to obtain the existence of solutions for (.), we only need to study the existence of critical points of the energy functionalIonX.
Next, noting Definition ., fort∈[–,T]N–, we let
tνν–x(t) =
( –ν)
t–(–ν)
s=ν–
(t–s– )(–ν)x(s) :=z(t+ν– ). (.)
Then we have
z(ν– ) = ,
z(ν– ) =
( –ν) –(–ν)
s=ν–
(–s– )(–ν)x(s) =x(ν– ),
z(ν) =
( –ν) –(–ν)
s=ν–
( –s– )(–ν)x(s) = ( –ν)x(ν– ) +x(ν),
z(ν+ ) =
( –ν) –(–ν)
s=ν–
( –s– )(–ν)x(s)
=( –ν)( –ν)
! x(ν– ) + ( –ν)x(ν) +x(ν+ ), ..
.
z(ν+T– ) =
( –ν)
T–(–ν)
s=ν–
(T–s– )(–ν)x(s)
=(T–ν)(T– –ν)· · ·( –ν)
T! x(ν– )
+(T– –ν)(T– –ν)· · ·( –ν)
(T– )! x(ν) +· · ·
i.e.,z=Bx, wherez= (z(ν– ),z(ν), . . . ,z(ν+T– ))+,x= (x(ν– ),x(ν), . . . ,x(ν+T– ))+, tive. Letλminandλmaxdenote respectively the minimum and the maximum eigenvalues
of (B–)+B–. Sincex=B–z, we have
Theorem . Let(H)hold.Then(.)has precisely one solution for c∈(, λ
λmax).
Proof We shall apply Lemma . to prove the result. From (.), we define the operator
L(x),y=
T
t=–
tνν–x(t)tνν–y(t) –
T
t=–
fx(t+ν– )y(t+ν– ), ∀x,y∈X. (.)
Clearly, if for ally∈X, there existsx∈Xsuch that (L(x),y) = , thenxis a solution of (.). Let
L(x),y
=
T
t=–
tνν–x(t)tνν–y(t),
L(x),y=
T
t=–
fx(t+ν– )y(t+ν– ), ∀x,y∈X.
We sketch the properties ofLandL. It is clear thatLis a linear operator, and further-more,Lis bounded. Indeed, the Cauchy-Schwarz inequality enables us to obtain, notice (.) and (.),
L(x),y≤ T
t=– tν
ν–x(t)tνν–y(t)
≤
T
t=– tν
ν–x(t)
T
t=– tν
ν–y(t)
≤λT+
λmin
xy<∞, x,y∈X. (.)
Consequently,Lis continuous onX. Next, we show thatLis bounded and continuous. Lety=θ in (H) and|f(θ)|=c> . Then we have from (H)
f(x)≤c|x|+c, ∀x∈X. (.)
From (.), the definition ofL, and the Cauchy-Schwarz inequality, we obtain
L(x),y≤ T
t=
fx(t+ν– )y(t+ν– )
≤
T
t=
cx(t+ν– )+cy(t+ν– )
≤cxy+c √
T+ y<∞, ∀x,y∈X, (.)
L(x) –L(x),y≤ T
t=
fx(t+ν– )–fx(t+ν– )y(t+ν– )
≤
T
t=
cx(t+ν– ) –x(t+ν– )y(t+ν– )
Therefore,Lis bounded and continuous, as required. Hence,Lis bounded and
continu-Finally, we prove thatLis strictly monotone. Indeed, from (H), we have
All the conditions of Lemma . are satisfied, as claimed. Hence, (.) has precisely one
solution. This completes the proof.
Theorem . Let(H)-(H)hold.Then(.)has at least one solution.
Proof From (H), there existsδ> with
By virtue of the inequality <μ< , there existsr> such that
b:= inf
x=r,x∈ZI(x) > . (.)
From (H), forx∈Y, we see
I(x) =
T
t=–
tνν–x(t)
–
T
t=–
Fx(t+ν– )
=
T–
t=–
z(t+ν– )–
T
t=
Fx(t+ν– )
≤ λl
λmin
x–
T
t=
Fx(t+ν– )
=
T
t=
λl
λmin
x(t+ν– ) –Fx(t+ν– )≤. (.)
From (H), we see that there existc,c> such that x
f(s) ds≥c|x|α–c, ∀x∈R. (.)
Hence, forx∈X, we find
I(x) =
T
t=–
tνν–x(t)
–
T
t=–
Fx(t+ν– )
=
T–
t=–
z(t+ν– )–
T
t=
Fx(t+ν– )
≤ λT+ λmin
x–c
T
t=
x(t+ν– )α+c(T+ ). (.)
Setz:=r ηl+
ηl+withr> is given in (.). ForY⊕Rz⊂X, (.) holds true. This, together with (.), implies
I(x)≤ λT+ λmin
x–ccααxα+c(T+ ).
Sinceα> , we obtain
lim
x→∞,x∈Y⊕Rz
I(x) = –∞. (.)
Define
M:=x=y+λz:x ≤ρ,λ≥,y∈Y,
Sincez∈Zand thenI(z)≥b> , (.) and (.) guarantee that there isρ>rsuch that
a:= max
x∈MI(x)≤.
It remains to prove thatIsatisfies the (PS)ccondition. This will be the case if we show
that any sequence{xn}∞n=⊂Xsuch that
d:=sup
n
I(xn) <∞, I(xn)→,
contains a convergent subsequence. Note thatdimX<∞, so we only need to show the boundedness of{xn}∞n=. Takeβ> such thatβ–∈(,α) fornlarge enough, and (H),
Thus the functionalIsatisfies all the conditions of Lemma ., and thenIhas a critical point, and (.) has at least one solution. This completes the proof.
Theorem . Let(H), (H)-(H)hold.Then(.)has at least m–l solutions.
Thus (i) of Lemma . holds true.
ChooseX:=span{η, . . . ,ηm}, wherem>l, anddimX=m. From (H), we see that there existc,c> such that
Therefore, from (.) and (.), we arrive at
–I(x)≥– λm λmin
x+c
T
t=
x(t+ν– )α–c(T+ )
≥– λm λmin
x+ccαα xα–c(T+ ).
Sinceα> ,I(x)→–∞asx → ∞,x∈X. Thus (ii) of Lemma . holds true.
Finally, we prove thatIsatisfies the (C) condition. Let{xn} ⊂Xbe such that for some M> ,
I(xn)≤M,
+xnI(xn)→ asn→ ∞.
We claim thatxnis bounded. Otherwise, suppose thatxn → ∞asn→ ∞. It is easy
to see that for anyn∈N, there existsMsuch that I(xn) –
I(xn),xn
≤M.
On the other hand, from (H), there existc,c> such that
f(x)x– F(x)≥c|x|γ –c, ∀x∈R. Consequently, from (.),
I(xn) –
I(xn),xn
=
T
t=
fxn(t+ν– )
xn(t+ν– ) – F
xn(t+ν– )
≥
T
t=
cxn(t+ν– )
γ –c
≥ccγγxnγ–c(T+ ).
Letn→ ∞, and we get a contradiction.
It is easy to see thatI is even andI(θ) = . Thus all the conditions of Lemma . are satisfied, and (.) has at leastm–lsolutions. The proof is complete.
Examples
. Letf(x) =ηx+η, whereη∈(,λλmax )andη= . Clearly, (H) holds.
. Letf(x) = λl λmin(x+x
)ex+ x. ThenF(x) = λl λminx
ex+x. Thus, (H) and (H) hold
automatically. ForR≥,α= , we see
< λl
λmin
xex+ x≤xf(x) = λl
λmin
x+xex+ x for all|x|> .
Therefore, (H) holds.
. Letf(x) = x+ x. ThenF(x) =x+xand (H), (H) hold. Chooseα= ,γ= , and we see
lim inf
|x|→∞ x+x
|x| = > , lim inf|x|→∞
f(x)x– F(x)
|x| =lim inf|x|→∞ x
|x|= > .
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
WD and JX carried out the main results of this article and drafted the manuscript. DO directed the study and helped with the inspection. All the authors read and approved the final manuscript.
Author details
1Department of Mathematics, Hebei University of Engineering, Handan, Hebei 056038, China.2School of Mathematics,
Shandong University, Jinan, Shandong 250100, China.3School of Mathematics, Statistics and Applied Mathematics,
National University of Ireland, Galway, Ireland.
Acknowledgements
The authors sincerely thank the reviewers for their valuable suggestions and useful comments that have led to the present improved version of the original manuscript. Research is supported by the NNSF-China (10971046 and 11371117), Shandong and Hebei Provincial Natural Science Foundation (ZR2012AQ007 and A2012402036), GIIFSDU (yzc12063) and IIFSDU (2012TS020).
Received: 30 July 2013 Accepted: 16 October 2013 Published:11 Nov 2013
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