R E S E A R C H
Open Access
Fixed point results for cyclic
(ψ
,
φ,
A
,
B
)
-contraction in partial metric
spaces
Wasfi Shatanawi
1and Saurabh Manro
2**Correspondence: [email protected] 2School of Mathematics and Computer Applications, Thapar University, Patiala, Punjab, India Full list of author information is available at the end of the article
Abstract
Very recently, Agarwalet al.(Fixed Point Theory Appl. 2012:40, 2012) initiated the study of fixed point theorems for mappings satisfying cyclical generalized contractive conditions in complete partial metric spaces. In the present paper, we study some fixed point theorems for a mapping satisfying a cyclical generalized contractive condition based on a pair of altering distance functions in complete partial metric spaces. Also, we introduce an example and an application to support the usability of our paper.
MSC: Primary 54H25; secondary 47H10
Keywords: partial metric spaces; fixed point; altering distance function; cyclic map
1 Introduction
The existence and uniqueness of fixed and common fixed point theorems of operators has been a subject of great interest since Banach [] proved the Banach contraction principle in . Many authors generalized the Banach contraction principle in various spaces such as quasi-metric spaces, generalized metric spaces, cone metric spaces and fuzzy metric spaces. Matthews [] introduced the notion of partial metric spaces in such a way that each object does not necessarily have to have a zero distance from itself and proved a modified version of the Banach contraction principle. Afterwards, many authors proved many existing fixed point theorems in partial metric spaces (see [–] for examples).
We recall below the definition of partial metric space and some of its properties.
Definition [] A partial metric on a nonempty setXis a functionp:X×X→R+such that for allx,y,z∈X:
(p) x=y⇐⇒p(x,x) =p(x,y) =p(y,y), (p) p(x,x)≤p(x,y),
(p) p(x,y) =p(y,x),
(p) p(x,y)≤p(x,z) +p(z,y) –p(z,z).
A partial metric space is a pair (X,p) such thatXis a nonempty set andpis a partial metric onX. It is clear that, ifp(x,y) = , then from (p) and (p),x=y. But ifx=y,p(x,y)
may not be . The functionp(x,y) =max{x,y} for allx,y∈R+ defines a partial metric
onR+.
Each partial metric ponXgenerates a Ttopologyτp onX which has as a base the family of openp-balls{Bp(x,ε) :x∈X,ε> }, whereBp(x,ε) ={y∈X:p(x,y) <p(x,x) +ε} for allx∈Xandε> .
Ifpis a partial metric onX, then the functiondp:X×X→R+given by
dp(x,y) = p(x,y) –p(x,x) –p(y,y)
is a metric onX.
Definition Let (X,p) be a partial metric space. Then
() A sequence{xn}in a partial metric space(X,p)converges to a pointx∈Xif and
only ifp(x,x) =limn→∞p(x,xn).
() A sequence{xn}in a partial metric space(X,p)is called a Cauchy sequence iff
limn,m→∞p(xn,xm)exists (and is finite).
() A partial metric space(X,p)is said to be complete if every Cauchy sequence{xn}in Xconverges, with respect toτp, to a pointx∈Xsuch that
p(x,x) =limn,m→∞p(xn,xm).
() A subsetAof a partial metric space(X,p)is closed if whenever{xn}is a sequence in Asuch that{xn}converges to somex∈X, thenx∈A.
Remark The limit in a partial metric space is not unique.
Lemma ([, ]) Let(X,p)be a partial metric space.
(a) {xn}is a Cauchy sequence in(X,p)if and only if it is a Cauchy sequence in the metric space(X,dp).
(b) A partial metric space(X,p)is complete if and only if the metric space(X,dp)is complete.Furthermore,limn→∞dp(xn,x) = if and only if
p(x,x) = lim
n→∞p(xn,x) =n,mlim→∞p(xn,xm).
Now, we define the cyclic map.
Definition LetAandBbe nonempty subsets of a metric space (X,d) andT:A∪B→ A∪B. ThenTis called a cyclic map ifT(A)⊆BandT(B)⊆A.
In , Kirket al.[] gave the following fixed point theorem for a cyclic map.
Theorem [] Let A and B be nonempty closed subsets of a complete metric space(X,d). Suppose that T:A∪B→A∪B is a cyclic map such that
d(Tx,Ty)≤kd(x,y) ∀x∈A,∀y∈B.
If k∈[, ),then T has a unique fixed point in A∩B.
Definition [] Let A andB be nonempty closed subsets of a metric space (X,d). A cyclic mapT:A∪B→A∪Bis said to be a Kannan type cyclic contraction if there existsk∈(,) such that
d(Tx,Ty)≤kd(Tx,x) +d(Ty,y) ∀x∈A,∀y∈B.
Definition [] Let A and B be nonempty closed subsets of a metric space (X,d). A cyclic mapT:A∪B→A∪Bis said to be a Reich type cyclic contraction if there exists k∈(,) such that
d(Tx,Ty)≤kd(x,y) +d(Tx,x) +d(Ty,y) ∀x∈A,∀y∈B.
Definition [] Let A andB be nonempty closed subsets of a metric space (X,d). A cyclic mapT:A∪B→A∪Bis said to be a Ćirić type cyclic contraction if there exists k∈(,) such that
d(Tx,Ty)≤kmaxd(x,y),d(Tx,x),d(Ty,y) ∀x∈A,∀y∈B.
Moreover, Karapınar and Erhan [] obtained the following results:
Theorem [] Let A and B be nonempty closed subsets of a complete metric space(X,d), and let T:A∪B→A∪B be a Kannan type cyclic contraction.Then T has a unique fixed point in A∩B.
Theorem [] Let A and B be nonempty closed subsets of a complete metric space(X,d), and let T :A∪B→A∪B be a Reich type cyclic contraction.Then T has a unique fixed point in A∩B.
Theorem [] Let A and B be nonempty closed subsets of a complete metric space(X,d), and let T:A∪B→A∪B be a Ćirić type cyclic contraction.Then T has a unique fixed point in A∩B.
For more results on cyclic contraction mappings, see [, ].
Very recently, Agarwalet al.[] initiated the study of fixed point theorems for mappings satisfying cyclical generalized contractive conditions in complete partial metric spaces.
Khanet al.[] introduced the notion of altering distance function as follows.
Definition (Altering distance function []) The function φ: [, +∞)→[, +∞) is called an altering distance function if the following properties are satisfied:
() φis continuous and nondecreasing. () φ(t) = if and only ift= .
For some work on altering distance function, we refer the reader to [–].
2 Main result
We start with the following definition.
Definition Let (X,p) be a partial metric space andA,Bbe nonempty closed subsets ofX. A mappingT:X→Xis called a cyclic (ψ,φ,A,B)-contraction if
() ψandφare altering distance functions;
() A∪Bhas a cyclic representation w.r.t.T; that is,T(A)⊆BandT(B)⊆A; and ()
ψp(Tx,Ty)≤ψ
max
p(x,y),p(x,Tx),p(y,Ty),
p(x,Ty) +p(Tx,y)
–φmaxp(x,y),p(y,Ty) (.)
for allx∈Aandy∈B.
From now on, byψandφwe mean altering distance functions unless otherwise stated.
In the rest of this paper,Nstands for the set of nonnegative integer numbers.
Theorem Let A and B be nonempty closed subsets of a complete partial metric space (X,p).If T:X→X is a cyclic (ψ,φ,A,B)-contraction,then T has a unique fixed point u∈A∩B.
Proof Letx∈A. SinceTA⊆B, we choosex∈Bsuch thatTx=x. Also, sinceTB⊆A,
we choosex∈Asuch thatTx=x. Continuing this process, we can construct sequences {xn}inXsuch thatxn∈A,xn+∈B,xn+=Txnandxn+=Txn+. Ifxn+=xn+for
somen∈N, thenxn+=Txn+. Thus,xn+is a fixed point ofTinA∩B. Thus, we may
assume thatxn+=xn+for alln∈N.
Givenn∈N. Ifnis even, thenn= tfor somet∈N. By (.), we have
ψp(xn+,xn+)
=ψp(xt+,xt+)
=ψp(Txt,Txt+)
≤ψ
max
p(xt,xt+),p(Txt,xt),p(Txt+,xt+),
p(xt,Txt+) +p(Txt,xt+)
–φmaxp(xt,xt+),p(Txt+,xt+)
=ψ
max
p(xt,xt+),p(xt+,xt+),
p(xt,xt+) +p(xt+,xt+)
–φmaxp(xt,xt+),p(xt+,xt+)
By (p), we have
ψp(xn+,xn+)
=ψp(xt+,xt+)
≤ψ
max
p(xt,xt+),p(xt+,xt+),
p(xt,xt+) +p(xt+,xt+)
–φmaxp(xt,xt+),p(xt+,xt+)
≤ψmaxp(xt,xt+),p(xt+,xt+)
–φmaxp(xt,xt+),p(xt+,xt+)
≤ψmaxp(xt,xt+),p(xt+,xt+)
.
If
maxp(xt,xt+),p(xt+,xt+)
=p(xt+,xt+),
then
ψp(xt+,xt+)
≤ψp(xt+,xt+)
–φp(xt+,xt+)
.
Therefore, φ(p(xt+,xt+)) = , and hencep(xt+,xt+) = . By (p) and (p), we have
xt+=xt+, which is a contradiction. Therefore,
maxp(xt,xt+),p(xt+,xt+)
=p(xt,xt+).
Hence,
p(xn+,xn+) =p(xt+,xt+)≤p(xt,xt+) =p(xn,xn+) (.)
and
ψp(xn+,xn+)
≤ψp(xn,xn+)
–φp(xn,xn+)
. (.)
Ifnis odd, thenn= t+ for somet∈N. By (.), we have
ψp(xn+,xn+)
=ψp(xt+,xt+)
=ψp(xt+,xt+)
=ψp(Txt+,Txt+)
≤ψ
max
p(xt+,xt+),p(Txt+,xt+),p(Txt+,xt+),
p(xt+,Txt+) +p(Txt+,xt+)
=ψ
max
p(xt+,xt+),p(xt+,xt+),
p(xt+,xt+) +p(xt+,xt+)
–φmaxp(xt+,xt+),p(xt+,xt+)
.
By (p), we have
ψp(xn+,xn+)
=ψp(xt+,xt+)
≤ψ
max
p(xt+,xt+),p(xt+,xt+),
p(xt+,xt+) +p(xt+,xt+)
–φmaxp(xt+,xt+),p(Txt+,xt+)
≤ψmaxp(xt+,xt+),p(xt+,xt+)
–φmaxp(xt+,xt+),p(Txt+,xt+)
≤ψmaxp(xt+,xt+),p(xt+,xt+)
.
If
maxp(xt+,xt+),p(xt+,xt+)
=p(xt+,xt+),
then
φp(xt+,xt+)
≤ψp(xt+,xt+)
–φp(xt+,xt+)
.
Therefore, φ(p(xt+,xt+)) = , and hencep(xt+,xt+) = . By (p) and (p), we have
xt+=xt+, which is a contradiction. Therefore,
maxp(xt+,xt+),p(xt+,xt+)
=p(xt+,xt+).
Hence,
p(xn+,xn+) =p(xt+,xt+)≤p(xt+,xt+) =p(xn+,xn), (.)
ψp(xn+,xn+)
≤ψp(xn,xn+)
–φp(xn,xn+)
. (.)
From (.) and (.), we have{p(xn+,xn) :n∈N}is a nonincreasing sequence and hence there existsr≥ such that
lim
n→+∞p(xn,xn+) =r.
Also, from (.) and (.), we have
ψp(xn+,xn+)
≤ψp(xn,xn+)
–φp(xn,xn+)
∀n∈N. (.)
Lettingn→+∞in (.) and using the fact thatψandφare continuous, we get that
Therefore,φ(r) = and hencer= . Thus
lim
n→+∞p(xn,xn+) = . (.)
By (p), we get that
lim
n→+∞p(xn,xn) = . (.)
Sincedp(x,y)≤p(x,y) for allx,y∈X, we get that
lim
n→+∞dp(xn,xn+) = . (.)
Next, we show that{xn}is a Cauchy sequence in the metric space (A∪B,dp). It is suf-ficient to show that{xn}is a Cauchy sequence in (A∪B,dp). Suppose the contrary; that is,{xn}is not a Cauchy sequence in (A∪B,dp). Then there exists> for which we can find two subsequences{xm(i)}and{xn(i)}of{xn}such thatn(i) is the smallest index for which
n(i) >m(i) >i, dp(xm(i),xn(i))≥. (.)
This means that
dp(xm(i),xn(i)–) <. (.)
From (.), (.) and the triangular inequality, we get that
≤dp(xm(i),xn(i))
≤dp(xm(i),xn(i)–) +dp(xn(i)–,xn(i)–)
+dp(xn(i)–,xn(i))
<+dp(xn(i)–,xn(i)–) +dp(xn(i)–,xn(i)).
On lettingi→+∞in the above inequalities and using (.), we have
lim
i→+∞dp(xm(i),xn(i)) =. (.)
Again, from (.) and the triangular inequality, we get that
≤dp(xm(i),xn(i))
≤dp(xn(i),xn(i)–) +dp(xn(i)–,xm(i))
Lettingi→+∞in the above inequalities and using (.) and (.), we get that
lim
i→+∞dp(xm(i),xn(i)) =i→lim+∞dp(xm(i)+,xn(i)–)
= lim
i→+∞dp(xm(i)+,xn(i))
= lim
i→+∞dp(xm(i),xn(i)–)
=.
Since
dp(x,y) = p(x,y) –p(x,x) –p(y,y)
for allx,y∈X, then
lim
i→+∞p(xm(i),xn(i)) =i→lim+∞p(xm(i)+,xn(i)–)
= lim
i→+∞p(xm(i)+,xn(i))
= lim
i→+∞p(xm(i),xn(i)–)
= .
By (.), we have
ψp(xm(i)+,xn(i))
=ψp(Txm(i),Txn(i)–)
≤ψ
max
p(xm(i),xn(i)–),p(xm(i),Txm(i)),p(xn(i)–,Txn(i)–),
p(xm(i),Txn(i)–) +p(xn(i)–,Txm(i))
–φmaxp(xm(i),xn(i)–),p(xn(i)–,Txn(i)–)
=ψ
max
p(xm(i),xn(i)–),p(xm(i),xm(i)+),p(xn(i)–,xn(i)),
p(xm(i),xn(i)) +p(xn(i)–,xm(i)+)
–φmaxp(xm(i),xn(i)–),p(xn(i)–,xn(i))
.
Lettingi→+∞and using the continuity ofφandψ, we get that
ψ
≤ψ
–φ
.
Therefore, we get thatφ(
) = . Hence,= is a contradiction. Thus{xn}is a Cauchy
sequence in (A∪B,dp). Since (X,p) is complete andA∪Bis a closed subspace of (X,p), then we have (A∪B,p) is complete. From Lemma , the sequence{xn}converges in the metric space (A∪B,dp), saylimn→∞dp(xn,u) = . Again from Lemma , we have
p(u,u) = lim
Moreover, since{xn}is a Cauchy sequence in the metric space (A∪B,dp), we have
lim
n,m→∞dp(xn,xm) = . (.)
From the definition ofdpwe have
dp(xn,xm) = p(xn,xm) –p(xn,xn) –p(xm,xm).
Lettingn,m→+∞in the above equality and using (.) and (.), we get
lim
n,m→∞p(xn,xm) = .
Thus by (.), we have
lim
n→+∞p(xn,u) =p(u,u) = . (.)
Sincep(xn,u)→ =p(u,u),{xn}is a sequence inA, andAis closed in (X,p), we have u∈A. Similarly, we haveu∈B, that isu∈A∩B. Again, from the definition ofp, we have
p(xn,Tu)≤p(xn,u) +p(u,Tu) –p(u,u)
≤p(xn,u) +p(u,xn) +p(xn,Tu) –p(xn,xn) –p(u,u).
Lettingn→+∞in the above inequalities and using (.) and (.), we get that
lim
n→+∞p(xn,Tu) =p(u,Tu).
Now, we claim thatTu=u.
Sincexn∈Aandu∈B, by (.) we have
ψp(xn+,Tu)
=ψp(Txn,Tu)
≤ψ
max
p(xn,u),p(Txn,xn),p(Tu,u),
p(xn,Tu) +p(u,Txn)
–φmaxp(xn,u),p(Tu,u)
=ψ
max
p(xn,u),p(xn,xn+),p(Tu,u),
p(xn,Tu) +p(u,xn+)
–φmaxp(xn,u),p(u,Tu)
.
Lettingn→+∞, we get that
ψp(u,Tu)≤ψp(u,Tu)–φp(u,Tu).
Therefore,uis a fixed point ofT. To prove the uniqueness of the fixed point, we letvbe any other fixed point ofTinA∩B. It is an easy matter to prove thatp(v,v) = . Now, we prove thatu=v. Sinceu∈A∩B⊆Aandv∈A∩B⊆B, we have
ψp(u,v)=ψp(Tu,Tv)
≤ψmaxp(u,v),p(u,u),p(v,v)–φmaxp(u,v),p(v,v)
=ψp(u,v)–φp(u,v).
Thusφ(p(u,v)) = and hencep(u,v) = . Therefore,u=v.
Takingψ=I[,+∞)(the identity function) in Theorem , we have the following result.
Corollary Let A and B be nonempty closed subsets of a complete partial metric space (X,p).Let T:X→X be a mapping such that A∪B has a cyclic representation w.r.t.T. Suppose there exists an altering distance functionφsuch that
p(Tx,Ty)≤max
p(x,y),p(x,Tx),p(y,Ty),
p(x,Ty) +p(Tx,y)
–φmaxp(x,y),p(y,Ty)
for all x∈A and y∈B.Then T has a unique fixed point u∈A∩B.
Corollary Let A and B be nonempty closed subsets of a complete partial metric space (X,p).Let T:X→X be a mapping such that A∪B has a cyclic representation w.r.t.T. Suppose there exists an altering distance functionφsuch that
p(Tx,Ty)≤maxp(x,y),p(x,Tx),p(y,Ty)–φmaxp(x,y),p(x,Tx),p(y,Ty)
for all x∈A and y∈B.Then T has a unique fixed point u∈A∩B.
Now, we introduce an example to support the usability of our results.
Example LetX= [, ]. Define the partial metricponXby
p(x,y) =
⎧ ⎨ ⎩
, ifx=y;
max{x,y}, ifx=y.
Also, define the mapping T:X→X byT(x) = +xx and the functionsψ,φ: [, +∞)→ [, +∞) byψ(t) = tandφ(t) = t
+t. TakeA= [,
] andB= [, ]. Then () (X,p)is a complete partial metric space.
() A∪Bhas a cyclic representation w.r.t.T. () For allx∈Aandy∈B, we have
ψp(Tx,Ty)≤ψ
max
p(x,y),p(x,Tx),p(y,Ty),
p(x,Ty) +p(Tx,y)
Proof Note thatTA= [,]⊆BandTB= [,]⊆A. ThusA∪Bhas a cyclic representa-tion ofT. To prove (), givenx∈Aandy∈B, without loss of generality, we may assume thatx≤y. So,
ψp(Tx,Ty)=ψ
p
x
+x, y
+y
=ψ
y
+y = y
+y,
ψ
max
p(x,y),p(x,Tx),p(y,Ty),
P(x,Ty) +p(Tx,y)
=ψ
max
y,p
x, x
+x ,p
y, y
+y ,
p
x, y
+y +p
x +x,y
≤ψ(y) = y,
and
φmaxp(x,y),p(y,Ty)=φ
max
y,p
y, y
+y
=φ(y) = y + y.
Since
y
+y≤y– y + y,
we have
ψp(Tx,Ty)≤ψ
max
p(x,y),p(x,Tx),p(y,Ty),
p(x,Ty) +p(Tx,y)
–φmaxp(x,y),p(y,Ty).
Note that Example satisfies all the hypotheses of Theorem .
3 Application
Denote bythe set of functionsμ: [, +∞)→[, +∞) satisfying the following hypothe-ses:
(h) μis a Lebesgue-integrable mapping on each compact of[, +∞). (h) For every> , we have
μ(t)dt> .
Theorem Let A and B be nonempty closed subsets of a complete partial metric space (X,p).Let T:X→X be a mapping such that A∪B has a cyclic representation w.r.t.T. Suppose that for x∈A and y∈B,we have
p(Tx,Ty)
μ(t)dt≤
max{p(x,y),p(x,Tx),p(y,Ty),(p(x,Ty)+p(Tx,y))}
μ(t)dt
–
max{p(x,y),p(y,Ty)}
μ(t)dt,
Proof Follows from Theorem by definingψ,φ: [, +∞)→[, +∞)viaψ(t) =tμ(s)ds
andφ(t) =tμ(s)dsand noting thatψ,φare altering distance functions.
Remark Theorem . of [] is a special case of Corollary .
Remark Theorem . of [] is a special case of Corollary .
Remark Theorem . of [] is a special case of Corollary .
Remark Theorem . of [] is a special case of Corollary .
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
All authors read and approved the manuscript.
Author details
1Department of Mathematics, Hashemite University, P.O. Box 150459, Zarqa, 13115, Jordan.2School of Mathematics and Computer Applications, Thapar University, Patiala, Punjab, India.
Acknowledgements
The authors thank the Editor and the referees for their useful comments and suggestions.
Received: 2 July 2012 Accepted: 31 August 2012 Published: 28 September 2012 References
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