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Volume 2010, Article ID 361512,33pages doi:10.1155/2010/361512

Research Article

A System of Generalized Mixed Equilibrium

Problems and Fixed Point Problems for

Pseudocontractive Mappings in Hilbert Spaces

Poom Kumam

1

and Chaichana Jaiboon

2

1Department of Mathematics, Faculty of Science, King Mongkut’s University of Technology Thonburi,

KMUTT, Bangkok 10140, Thailand

2Department of Mathematics, Faculty of Liberal Arts, Rajamangala University of Technology Rattanakosin,

RMUTR, Bangkok 10100, Thailand

Correspondence should be addressed to Chaichana Jaiboon,[email protected]

Received 2 April 2010; Accepted 11 June 2010

Academic Editor: A. T. M. Lau

Copyrightq2010 P. Kumam and C. Jaiboon. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We introduce and analyze a new iterative algorithm for finding a common element of the set of fixed points of strict pseudocontractions, the set of common solutions of a system of generalized mixed equilibrium problems, and the set of common solutions of the variational inequalities with inverse-strongly monotone mappings in Hilbert spaces. Furthermore, we prove new strong convergence theorems for a new iterative algorithm under some mild conditions. Finally, we also apply our results for solving convex feasibility problems in Hilbert spaces. The results obtained in this paper improve and extend the corresponding results announced by Qin and Kang2010and the previously known results in this area.

1. Introduction

Let H be a real Hilbert space with inner product ·,· and norm · and let E be a nonempty closed convex subset ofH. We denote weak convergence and strong convergence by notationsand →, respectively. LetS:EEbe a mapping. In the sequel, we will use

FSto denote the set offixed pointsofS, that is,FS {xE:Sxx}.

Definition 1.1. LetS:EEbe a mapping. ThenSis called

1contractionif there exists a constantα∈0,1such that

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2nonexpansive if

SxSyxy,x, yE. 1.2

Remark 1.2. It is well known that ifEHis nonempty, bounded, closed, and convex andS

is a nonexpansive mapping onEthenFSis nonempty; see, for example,1.

3strongly pseudocontractivewith the coefficientτ ∈0,1if

SxSy, xyτxy2,x, yE, 1.3

4strictly pseudocontractivewith the coefficientk∈0,1if

SxSy2≤xy2kISxISy2,x, yE; 1.4

for such a case,Sis also said to be ak-strict pseudocontraction,and ifk0, thenSis a nonexpansive mapping,

5pseudocontractive if

SxSy2

xy2ISxISy2,x, yE. 1.5

The class of strict pseudocontractions falls into the one between classes of nonex-pansive mappings and pseudocontractions. Within the past several decades, many authors have been devoting to the studies on the existence and convergence of fixed points for strict pseudocontractions.

In 1967, Browder and Petryshyn2introduced a convex combination method to study strict pseudocontractions in Hilbert spaces. On the other hand, Marino and Xu3and Zhou 4 introduced and researched some iterative scheme for finding a fixed point of a strict pseudocontraction mapping. More precisely, takek∈0,1and define a mappingSkby

Skxkx 1−kSx,xE, 1.6

whereSis a strict pseudocontraction. Under appropriate restrictions onk, it is proved the mappingSkis nonexpansive. Therefore, the techniques of studying nonexpansive mappings can be applied to study more general strict pseudocontractions.

Thedomainof the functionϕ:E → R ∪ {∞}is the set

domϕxE:ϕx<. 1.7

Letϕ:E → R ∪ {∞}be a proper extended real-valued function and letΦbe a bifunction of

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There exists thegeneralized mixed equilibrium problemfor findingxEsuch that

Φx, yΨx, yxϕyϕx≥0,yE. 1.8

The set of solutions of1.8is denoted by GMEPΦ, ϕ,Ψ,that is,

GMEPΦ, ϕ,ΨxEx, yΨx, yxϕyϕx≥0,yE. 1.9

We see thatxis a solution of problem1.8implies thatx∈domϕ.

Special Examples

1IfΨ 0, problem1.8is reduced into themixed equilibrium problemfor findingxE

such that

Φx, yϕyϕx≥0,yE. 1.10

Problem1.10was studied by Ceng and Yao5. The set of solutions of1.10is denoted by MEPΦ, ϕ.

2Ifϕ0, problem1.8is reduced into thegeneralized equilibrium problemfor finding

xEsuch that

Φx, yΨx, yx≥0,yE. 1.11

Problem1.11was studied by Takahashi and Toyoda6. The set of solutions of 1.11is denoted by GEPΦ,Ψ.

3IfΨ 0 andϕ0, problem1.8is reduced into theequilibrium problem for finding

xEsuch that

Φx, y≥0,yE. 1.12

Problem1.12was studied by Blum and Oettli7. The set of solutions of1.12is denoted by EPΦ.

4IfΦ 0, problem1.8is reduced into themixed variational inequality of Browder type

for findingxEsuch that

Ψx, yxϕyϕx≥0,yE. 1.13

Problem1.13was studied by Browder8. The set of solutions of1.13is denoted by VIE,Ψ, ϕ.

5IfΦ 0 andϕ0, problem1.8is reduced into thevariational inequality problemfor findingxEsuch that

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Problem1.14was studied by Hartman and Stampacchia9. The set of solutions of 1.14 is denoted by VIE,Ψ. The variational inequality has been extensively studied in the literature. See, for example,7,10,11and the references therein. 6IfΦ 0 andΨ 0, problem1.8is reduced into theminimize problemfor finding

xEsuch that

ϕyϕx≥0,yE. 1.15

The set of solutions of1.15is denoted by Argminϕ.

The generalized mixed equilibrium problems include fixed point problems, variational inequality problems, optimization problems, Nash equilibrium problems, and the equilib-rium problem as special cases. Numerous problems in physics, optimization, and economics reduce to find a solution of 1.8. In 1997, Combettes and Hirstoaga 12 introduced an iterative scheme of finding the best approximation to initial data when EPΦis nonempty and proved a strong convergence theorem. Many authors have proposed some useful methods for solving the GMEPΦ, ϕ,Ψ, MEPΦ, ϕ,and EPΦ; see, for instance,5,12–23.

Definition 1.3. LetB:EHbe a nonlinear mapping. ThenBis called

1monotoneif

BxBy, xy≥0,x, yE, 1.16

2β-strongly monotone if there exists a constantβ >0 such that

BxBy, xyβxy2,x, yE, 1.17

3η-Lipschitz continuousif there exists a positive real numberηsuch that

BxByηxy,x, yE, 1.18

4β-inverse-strongly monotoneif there exists a constantβ >0 such that

BxBy, xyβBxBy2,x, yE. 1.19

Remark 1.4. It is obvious that anyβ-inverse-strongly monotone mappingsBare monotone

and 1-Lipschitz continuous.

For finding a common element of the set of fixed points of a nonexpansive mapping and the set of solution of variational inequalities for aβ-inverse-strongly monotone mapping, Takahashi and Toyoda6introduced the following iterative scheme:

x0∈Echosen arbitrary,

xn1αnxn 1−αnSPExnλnBxn,n≥0,

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wherePEis the metric projection ofHontoE,Bis aβ-inverse-strongly monotone mapping,

{αn}is a sequence in 0,1, and{λn} is a sequence in0,2β. They showed that if FS

VIE, Bis nonempty, then the sequence{xn}generated by1.20converges weakly to some qFS∩VIE, B.

On the other hand, Y. Yao and J.-C Yao24introduced the following iterative process defined recursively by

x1xEchosen arbitrary,

ynPExnλnBxn,

xn1αnxβnxnγnSPE

ynλnByn

,n≥1,

1.21

where Bis aβ-inverse-strongly monotone mapping, {αn},{βn},and {γn}are sequences in the interval0,1, and{λn}is a sequence in0,2β. They showed that ifFS∩VIE, Bis

nonempty, then the sequence{xn}generated by1.21converges strongly to someqFS

VIE, B.

LetAbe a strongly positive linear bounded operator onHif there is a constantγ >0 with property

Ax, xγx2,xH. 1.22

A typical problem is to minimize a quadratic function over the set of the fixed points a nonexpansive mapping on a real Hilbert spaceH:

min

xE

1

2Ax, xx, b, 1.23

whereAis a linear bounded operator,Eis the fixed point set of a nonexpansive mappingS

onH,andbis a given point inH.Moreover, it is shown in25that the sequence{xn}defined

by the scheme

xn1 nγfxn 1−nASxn 1.24

converges strongly to q PFSIA γfq. Recently, Plubtieng and Punpaeng 26

proposed the following iterative algorithm:

Φun, y

1

rn

yun, unxn

≥0,yH,

xn1nγfxn InASun.

1.25

They proved that if the sequences{n}and{rn}of parameters satisfy appropriate condition,

then the sequences{xn}and{un}both converge to the unique solutionqof the variational inequality:

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which is the optimality condition for the minimization problem:

min

xFS∩EPφ

1

2Ax, xhx, 1.27

wherehis a potential function forγfi.e.,hx γfxforxH.

Very recently, Ceng et al. 27 introduced iterative scheme for finding a common element of the set of solutions of equilibrium problems and the of fixed points of ak-strict pseudocontraction mapping defined in the setting of real Hilbert spaceH:x0∈Hand let

Φun, y

1

rn

yun, unxn

≥0,yE,

xn1αnun 1−αnSun,

1.28

where{αn} ⊂a, bfor somea, bk,1and{rn} ⊂0,∞satisfies lim infn→ ∞rn>0. Further,

they proved that{xn}and{un}converge weakly toqFS∩EPΦ, whereqPFS∩EPΦx0.

On the other hand, for finding a common element of the set of fixed points of ak -strict pseudocontraction mapping and the set of solutions of an equilibrium problems in a real Hilbert space, Liu28introduced the following iterative scheme:

Φun, y

1

rn

yun, unxn

≥0,yE,

ynβnun1−βnSun,

xn1nγfxn InAyn,n≥1,

1.29

where S is a k-strict pseudocontraction mapping and {n} and {βn} are sequences in

0,1.They proved that under certain appropriate conditions over{n},{βn}, and{rn}, the

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In 2008, Ceng and Yao5introduced an iterative scheme for finding a common fixed point of a finite family of nonexpansive mappings and the set of solutions of a problem1.8

in Hilbert spaces and obtained the strong convergence theorem which used the following condition.

GK:E → R is η-strongly convex with constant σ > 0 and its derivative K is sequentially continuous from the weak topology to the strong topology. We note that the conditionGfor the functionK:E → Ris a very strong condition. We also note that the conditionGdoes not cover the caseKx x2/2 andηx, y xyfor eachx, yE×E. Very recently, Wangkeeree and Wangkeeree29introduced a general iterative method for finding a common element of the set of solutions of the mixed equilibrium problems, the set of fixed point of a k-strict pseudocontraction mapping, and the set of solutions of the variational inequality for an inverse-strongly monotone mapping in Hilbert spaces. They obtained a strong convergence theorem except the conditionGfor the sequences generated by these processes.

In 2009, Qin and Kang30introduced an explicit viscosity approximation method for finding a common element of the set of fixed points of strict pseudocontraction and the set of solutions of variational inequalities with inverse-strongly monotone mappings in Hilbert spaces. Let{xn}be a sequence generated by the following iterative algorithm:

x1∈E,

znPExnμnCxn,

ynPExnλnBxn,

xn1nfxn βnxnγn αn1Skxnαn2ynαn3zn

,n≥1.

1.30

Then, they proved that under certain appropriate conditions imposed on {n}, {βn},{γn},

{αn1}, {αn2}, and {αn3}, the sequence {xn}generated by 1.30converges strongly to qFS∩VIE, B∩VIE, C, whereqPFS∩VIE,B∩VIE,Cfq.

In the present paper, motivated and inspired by Qin and Kang30, Peng and Yao21, Plubtieng and Punpaeng26, and Liu28, we introduce a new general iterative scheme for finding a common element of the set of fixed points of strict pseudocontractions, the set of common solutions of the system of generalized mixed equilibrium problems, and the set of common solutions of the variational inequalities for inverse-strongly monotone mappings in Hilbert spaces. We obtain a strong convergence theorem for the sequences generated by these processes under some parameter controlling conditions. The results in this paper extend and improve the corresponding recent results of Qin and Kang30, Peng and Yao21, Plubtieng and Punpaeng26, and Liu28and many others.

2. Preliminaries

LetHbe a real Hilbert space and letEbe a nonempty closed convex subset ofH. In a real Hilbert spaceH, it is well known that

λx 1λy2

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For anyxH, there exists aunique nearest pointinE, denoted byPEx, such that

xPExxy,yE. 2.2

The mappingPEis called themetric projectionofHontoE.

It is well known thatPEis a firmly nonexpansive mapping ofHontoE, that is,

xy, PExPEyPExPEy2,x, yH. 2.3

Moreover,PExis characterized by the following properties:PExEand

xPEx, yPEx≤0,

xy2≥ xPEx2yPEx2

2.4

for allxH, yE.

Lemma 2.1. LetEbe a nonempty closed convex subset of a real Hilbert spaceH. GivenxHand

zE,then,

zPEx⇐⇒

xz, yz≤0,yE. 2.5

Lemma 2.2. LetHbe a Hilbert space, letEbe a nonempty closed convex subset ofH,and letBbe a mapping ofEintoH.LetuE. Then forλ >0,

uVIE, B⇐⇒uPEuλBu, 2.6

wherePEis the metric projection ofHontoE.

A set-valued mappingT :H → 2His called amonotone if for allx, yH,fTxand gTyimplyxy, fg ≥ 0. A monotone mappingT :H → 2H is calledmaximalif the

graphGTofT is not properly contained in the graph of any other monotone mapping. It is known that a monotone mappingTis maximal if and only if forx, fH×H,xy, fg

0 for everyy, gGTimpliesfTx. LetBbe a monotone map ofEintoH,η-Lipschitz continuous mappings and letNEvbe thenormal conetoEwhenvE, that is,

NEv{wH:vu, w ≥0,uE}, 2.7

and define a mappingTonEby

Tv

⎧ ⎨ ⎩

BvNEv, vE,

, v /E.

2.8

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Lemma 2.3. LetH be a Hilbert space, letEbe a nonempty closed convex subset ofH,and letΨ :

EHbeρ-inverse-strongly monotone. It0 < r ≤ 2ρ, thenIρΨis a nonexpansive mapping in

H.

Proof. For allx, yEand 0< r≤2ρ, we have

IrΨxIrΨy2 xyrΨx−Ψy2

xy2−2rxy,Ψx−Ψyr2ΨxΨy2

xy2−2Ψx−Ψyrx−Ψy2

xy2rr−2ρΨx−Ψy2

xy2.

2.9

So,IρΨis a nonexpansive mapping ofEintoH.

Lemma 2.4see32. LetE,·,·be an inner product space. Then, for allx, y, zEandα, β, γ

0,1withαβγ1,one has

αxβyγz2

αx2βy2γz2−αβxy2−αγxz2−βγyz2. 2.10

Lemma 2.5see25. LetE be a nonempty closed convex subset ofH,let f be a contraction of

H into itself withα ∈ 0,1, and letAbe a strongly positive linear bounded operator on Hwith coefficientγ >0. Then, for0< γ < γ/α,

xy,AγfxAγfyγγαxy2, x, yH. 2.11

That is,Aγfis strongly monotone with coefficientγγα.

Lemma 2.6see25. Assume thatA is a strongly positive linear bounded operator onH with coefficientγ >0and0< ϑA−1. ThenIϑA1ϑγ.

Lemma 2.7see4. LetEbe a nonempty closed convex subset of a real Hilbert spaceH and let

S : EEbe a k-strict pseudocontraction mapping with a fixed point. ThenFSis closed and

convex. DefineSk:EEbySkkx 1−kSxfor eachxE. ThenSkis nonexpansive such

thatFSk FS.

Lemma 2.8see33. LetEbe a closed convex subset of a Hilbert spaceHand letS:EEbe a nonexpansive mapping. ThenISis demiclosed at zero, that is,

xn x, xnSxn−→0 implies xSx. 2.12

Lemma 2.9see34. LetEbe a nonempty closed convex subset of a strictly convex Banach space

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nonempty. Letδnbe a sequence of positive number withn1δn1. Then a mappingSonEdefined by

Sx

n1

δnTnx 2.13

forxEis well defined and nonexpansive andFSn1FTnholds.

For solving the mixed equilibrium problem, let us give the following assumptions for the bifunctionΦ, the functionϕ,and the setE:

A1 Φx, x 0 for allxE;

A2 Φis monotone, that is,Φx, y Φy, x≤0 for allx, yE; A3for eachx, y, zE, limt→0Φtz 1−tx, y≤Φx, y;

A4for eachxE, y→Φx, yis convex and lower semicontinuous; A5for eachyE, x→Φx, yis weakly upper semicontinuous;

B1for eachxHandr >0, there exists a bounded subsetDxEandyxEsuch

that for anyzE\Dx,

Φz, yx

ϕyx

ϕz 1 r

yxz, zx

<0; 2.14

B2Eis a bounded set.

By similar argument as in the proof of Lemma 2.10 in 35, we have the following lemma appearing.

Lemma 2.10. LetEbe a nonempty closed convex subset ofH. LetΦ:E×E → Rbe a bifunction

satisfies (A1)–(A5) and letϕ:E → R∪{∞}be a proper lower semicontinuous and convex function.

Assume that either (B1) or (B2) holds. Forr >0andxH, define a mappingTrΦ:HEas follows:

TrΦx

zEz, yϕyϕz 1 r

yz, zx≥0,yE

2.15

for allzH. Then, the following holds:

ifor eachxH, TrΦx/;

iiTrΦis single-valued;

iiiTrΦis firmly nonexpansive, that is, for anyx, yH,

TrΦxTrΦy2≤TrΦxTrΦy, xy; 2.16

ivFTrΦ MEPΦ, ϕ;

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Remark 2.11. We remark thatLemma 2.10is not a consequence of Lemma 3.1 in5, because the condition of the sequential continuity from the weak topology to the strong topology for the derivativeKof the functionK:E → Rdoes not cover the caseKx x2/2.

Lemma 2.12see36. Let{xn}and{ln}be bounded sequences in a Banach spaceXand let{βn}be a sequence in0,1with0<lim infn→ ∞βn≤lim supn→ ∞βn<1.Supposexn1 1−βnlnβnxn

for all integersn≥1andlim supn→ ∞ln1−lnxn1−xn≤0.Then,limn→ ∞lnxn0.

Lemma 2.13see37. Assume that{an}is a sequence of nonnegative real numbers such that

an1≤

1−n

anσn, n≥1, 2.17

where{n}is a sequence in0,1and{σn}is a sequence inRsuch that

1∞n1n,

2lim supn→ ∞σn/n≤0or

n1|σn|<.

Thenlimn→ ∞an 0.

Lemma 2.14. LetHbe a real Hilbert space. Then for allx, yH,

xy2≤ x22y, xy. 2.18

3. Main Results

In this section, we will use the new approximation iterative method to prove a strong convergence theorem for finding a common element of the set of fixed points of strict pseudocontractions, the set of common solutions of the system of generalized mixed equilibrium problems, and the set of a common solutions of the variational inequalities for inverse-strongly monotone mappings in a real Hilbert space.

Theorem 3.1. LetEbe a nonempty closed convex subset of a real Hilbert spaceH. LetΦ1andΦ2be

two bifunctions fromE×EtoRsatisfyingA1–A5and letϕ:E → R ∪ {∞}be a proper lower semicontinuous and convex function with either (B1) or (B2). LetC:EHbe aξ-inverse-strongly

monotone mapping, letΨ1:EHbe a ρ-inverse-strongly monotone mapping, letΨ2:EH

be anω-inverse-strongly monotone mapping, and letB:EHbe aβ-inverse-strongly monotone

mapping. Letf:EEbe anα-contraction with coefficientα0 ≤α < 1and letAbe a strongly positive linear bounded operator onHwith coefficientγ >0and0 < γ < γ/α. LetS:EEbe a

k-strict pseudocontraction with a fixed point. Define a mappingSk:EEbySkxkx1−kSx,

for allxE. Suppose that

Θ:FSVIE, BVIE, CGMEPΦ1, ϕ,Ψ1

GMEPΦ2, ϕ,Ψ2

/

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Let{xn}be a sequence generated by the following iterative algorithm:

x1∈E, unE, vnE,

Φ1un, u ϕxϕun Ψ1xn, uun

1

ruun, unxn ≥0,uE,

Φ2vn, v ϕxϕvn Ψ2xn, vvn1

svvn, vnxn ≥0,vE, knαn1Skxnαn2PExnλnBxn αn3PE

xnμnCxn

αn4unαn5vn,

xn1nγfxn βnxn

1−βnInAkn,n≥1,

3.2

where {n},{βn},{γn}, and{αni}are sequences in0,1, wherei 1,2,3,4,5,r ∈ 0,2ρ,s

0,2ω, and{λn} and {μn} are positive sequences. Assume that the control sequences satisfy the following restrictions:

C15i1αni1,

C2limn→ ∞n0andn1n,

C30<lim infn→ ∞βn≤lim supn→ ∞βn<1,

C4limn→ ∞|λn1−λn|limn→ ∞|μn1−μn|0,

C5 dλn≤2βandeμn≤2ξ, whered, eare two positive constants,

C6limn→ ∞αniαi∈0,1, wherei1,2,3,4,5.

Then, {xn} converges strongly to a point q ∈ Θwhich is the unique solution of the variational

inequality:

Aγfq, xq≥0,x∈Θ. 3.3

Equivalently, one hasqPΘIAγfq.

Proof. Sincen → 0, asn → ∞, we may assume, without loss of generality, thatn ≤1−

βnA−1for alln∈N. ByLemma 2.6, we know that if 0≤ϑA−1, thenIϑA ≤1−ϑγ.

We will assume thatIA ≤ 1−γ. SinceAis a strongly positive bounded linear operator onH,we have

Asup{|Ax, x|:xH,x1}. 3.4

Observe that

1−βnInAx, x1−βnnAx, x

≥1−βnnA

≥0,

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and so this shows that1−βnInAis positive. It follows that

1−βn

InAsup1−βn

InA

x, x:xH,x1

sup1−βnnAx, x:xH,x1

≤1−βnnγ.

3.6

Sincefis a contraction ofHinto itself withα∈0,1, then, we have

PΘIAγfxPΘIAγfyIAγfxIAγfy

IAxyγfxfy

≤1−γxyγαxy

1−γγαxy,x, yH.

3.7

Since 0<1−γγα<1, it follows thatPΘIAγfis a contraction ofHinto itself. Therefore

the Banach Contraction Mapping Principle implies that there exists a unique elementqH

such thatqPΘIAγfq.

Next, we will divide the proof into five steps.

Step 1. We claim that{xn}is bounded.

Indeed, letp∈Θand byLemma 2.10, we obtain

pPEpλnBpPEpμnCpTΦ1

r IrΨ1pTsΦ2IsΨ2p. 3.8

Note thatunTΦ1

r IrΨ1xn∈domϕandvnTsΦ2IsΨ2xn∈domϕ; we have

unpTΦ1

r IrΨ1xnTrΦ1IrΨ1pxnp,

vnpTsΦ2IsΨ2xnTsΦ2IsΨ2pxnp.

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PutznPExnμnCxnandynPExnλnBxn. For eachλn≤2βandμn≤2ξbyLemma 2.3, we get thatIλnBandIμnBare nonexpansive. Thus, we have

znpPE

xnμnCxnPEpμnCp

xnμnCxnpμnCp

IμnCxnIμnCp

xnp,

ynpPExnλnBxnPE

pλnBp

xnλnBxn

pλnBp

IλnBvnIλnBp

vnpxnp.

3.10

FromLemma 2.7, we have thatSkis nonexpansive withFSk FS. It follows that

knpα1

n Skxnαn2ynαn3znαn4unαn5vn

αn1Skxnpαn2ynpαn3znpαn3unpαn3vnp

αn1xnpαn2xnpαn3xnpαn3xnpαn3xnp

xnp,

3.11

which yields that

xn1−pn

γfxnAp

βn

xnp

1−βn

InA

knp

≤1−βnnγknpβnxnpnγfxnAp

≤1−βnnγxnpβnxnpnγfxnAp

≤1−nγxnpnγfxnf

pnγf

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≤1−nγxnpnγαxnpnγfpAp

1−γαγnxnαγnγf

pAp γαγ

≤max

xnp,γfpAp γαγ

≤ ...

≤max

x1−p,

γfpAp γαγ

,n∈N.

3.12

Hence,{xn}is bounded, and so are{un},{vn},{zn},{yn},{kn},{fxn},{Cxn},and{Bxn}.

Step 2. We claim that limn→ ∞xn1−xn0 and limn→ ∞knxn0.

Observing thatunTΦ1

r IrΨ1xn∈domϕandun1TrΦ1IrΨ1xn1∈domϕ, by

the nonexpansiveness ofTΦ1

r , we get

un1−unTrΦ1IrΨ1xn1−TrΦ1IrΨ1xnxn1−xn. 3.13

Similarly, letvnTsΦ2IsΨ2xn ∈domϕandvn1TsΦ2IsΨ2xn1∈domϕ; we have

vn1−vnTsΦ2IsΨ2xn1−TsΦ2IsΨ2xnxn1−xn. 3.14

FromznPExnμnCxnandynPExnλnBxn; thus, we compute

zn1−znPE

xn1−μn1Cxn1

PE

xnμnCxn

xn1−μn1Cxn1

xnμnCxn

xn1−μn1Cxn1

xnμn1Cxn

μnμn1

Cxn

xn1−μn1Cxn1

xnμn1Cxnμnμn1Cxn

Iμn1C

xn1−

Iμn1C

xnμnμn1Cxnxn1−xnμnμn1Cxn.

3.15

Similarly, we have

yn1−ynPExn1−λn1Bxn1−PExnλnBxn

xn1−xn|λnλn1|Bxn.

(16)

Also noticing that

knαn1Skxnαn2ynαn3znαn4unαn5vn

kn1αn11Skxn1αn21yn1αn31zn1αn41un1αn51vn1,

3.17

we compute

kn1−knαn11Skxn1−Skxnαn11αn1Skxnαn21yn1−yn

αn21αn2ynαn31zn1−znαn31αn3zn

αn41un1−unαn41αn4unαn51vn1−vnαn51αn5vn

αn11xn1−xnαn11αn1Skxnαn21yn1−yn

αn21αn2ynαn31zn1−znαn31αn3zn

αn41un1−unαn41αn4unαn51vn1−vnαn51αn5vn.

3.18

Substitution of3.13,3.14,3.15, and3.16into3.18yields that

kn1−knαn11xn1−xnαn11αn1Skxn

αn21{xn1−xn|λnλn1|Bxn}αn21αn2yn

αn31xn1−xnμnμn1Cxn

αn31αn3zn

αn41xn1−xnαn41αn4unαn51xn1−xnαn51αn5vn

xn1−xnM1αn11αn1αn21αn2αn31αn3αn41αn4

αn51αn5|λnλn1|μnμn1,

3.19

whereM1is an appropriate constant such that

M1≥max

sup

n≥1

{Skxn},sup

n≥1

yn,sup

n≥1

{zn}, sup

n≥1

{un},

sup

n≥1

{vn},sup

n≥1

{Bxn},sup

n≥1

{Cxn}

.

(17)

Puttingxn1 1−βnlnβnxn,for alln≥1, we have

ln

xn1−βnxn

1−βn

nγfxn 1−βnInAkn

1−βn

. 3.21

Then, we compute

ln1−ln

n1γfxn1

1−βn1

In1A

kn1

1−βn1 −

nγfxn 1−βnInAkn

1−βn

n1

1−βn1

γfxn1−

n

1−βnγfxn kn1−kn n

1−βnAknn1

1−βn1

Akn1

n1

1−βn1

γfxn1−Akn1

n

1−βn

Aknγfxnkn1−kn.

3.22

It follows from3.19and3.22that

ln1−lnxn1−xnn1

1−βn1

γfxn1Akn1

n

1−βn

Aknγfxn

kn1−knxn1−xn

n1

1−βn1

γfxn1Akn1

n 1−βn

Aknγfxn

M1αn11αn1αn21αn2αn31αn3αn41αn4

αn51αn5|λnλn1|μnμn1.

3.23

This together withC2,C3,C4, andC6implies that

lim sup

n→ ∞ ln1−lnxn1−xn≤0. 3.24

Hence, byLemma 2.12, we obtainlnxn → 0 asn → ∞. It follows that

lim

n→ ∞xn1−xnnlim→ ∞

(18)

Moreover, we also get

lim

n→ ∞un1−unnlim→ ∞vn1−vnnlim→ ∞zn1−znnlim→ ∞yn1−yn

lim

n→ ∞kn1−kn0.

3.26

Observe that

xn1−xnn

γfxnAxn1−βnnγknxn. 3.27

By conditionsC2,C3, and3.25, we have

limn→ ∞knxn0. 3.28

Step 3. We claim that the following statements hold:

s1limn→ ∞xnun0;

s2limn→ ∞xnyn0;

s3limn→ ∞xnzn0;

s4limn→ ∞xnvn0.

Forp∈Θ, we compute

znp2PE

xnμnCxn

PE

pμnCp2

xnμnCxnpμnCp2

xnp

μn

CxnCp2

xnp2−2μn

xnp, CxnCp

μ2

nCxnCp2

xnp2μnμn−2ξCxnCp2

xnp2−μn

2ξμnCxnCp2.

3.29

By the same way, we can get

ynp2

(19)

We note that

unp2

TΦ1

r IrΨ1xnTrΦ1IrΨ1p 2

IrΨ1xnIrΨ1p2

xnp

rΨ1xn−Ψ1p2

xnp2−2rxnp,Ψ1xn−Ψ1p

r2Ψ1xn−Ψ1p2

xnp2−2Ψ1xn−Ψ1pr2Ψ1xn−Ψ1p2

xnp2r

r−2ρΨ1xn−Ψ1p2

xnp2−r2ρrΨ1xn−Ψ1p2.

3.31

Similarly, we have

vnp2≤xnp2−s2ωsΨ2xn−Ψ2p2. 3.32

Observe that

knp2≤αn1Skxnp2αn2ynp2αn3znp2αn4unp2αn5vnp2

αn1xnp2αn2ynp2αn3znp2αn4unp2αn5vnp2.

3.33

Substituting3.29,3.30,3.31, and3.32into3.33, we obtain

knp2 ≤αn1xnp2αn2

xnp2−λn2βλnBxnBp2

αn3

xnp2−μn

2ξμnCxnCp2

αn4

xnp2−r

2ρrΨ1xn−Ψ1p2

αn5

xnp2−s2ωsΨ2xn−Ψ2p2

xnp2−αn2λn

2βλnBxnBp2−αn3μn

2ξμnCxnCp2

αn4r

2ρrΨ1xn−Ψ1p2−αn5s2ωsΨ2xn−Ψ2p2.

(20)

It follows from3.2and3.34that

xn1−p2

nγfxn βnxn1−βnInAknp2

nγfxnAp2βnxnp2

1−βnnγknp2

nγfxnAp2βnxnp2

1−βn

×xnp2−αn2λn

2βλnBxnBp2−αn3μn

2ξμnCxnCp2

αn4r

2ρrΨ1xn−Ψ1p2−αn5s2ωsΨ2xn−Ψ2p2

nγfxnAp2

1−nγxnp2−

1−βn

αn2λn

2βλnBxnBp2

−1−βnnγαn3μn

2ξμnCxnCp2

−1−βn

αn4r

2ρrΨ1xn−Ψ1p2

−1−βn

αn5s2ωsΨ2xn−Ψ2p2

nγfxnAp2xnp2−1−βnnγαn2λn

2βλnBxnBp2

−1−βn

αn3μn

2ξμnCxnCp2

−1−βnnγαn4r

2ρrΨ1xn−Ψ1p2

−1−βn

αn5s2ωsΨ2xn−Ψ2p2

nγfxnAp2xnp2−1−βnnγαn3μn

2ξμnCxnCp2.

3.35

It follows fromC5that

1−βnnγαn3μn

2ξμnCxnCp2

nγfxnAp2xnp2−xn1−p2

nγfxnAp2xnpxn1−pxnpxn1−p

nγfxnAp2xn1−xnxnpxn1−p.

3.36

FromC2,C6, and3.25, we have

lim

(21)

Sinces∈0,2ω, we also have

1−βnnγαn5s2ωsΨ2xn−Ψ2p2

nγfxnAp2xnp2−xn1−p2

nγfxnAp2xn1−xnxnpxn1−p.

3.38

FromC2,C6, and3.25, we obtain

lim

n→ ∞Ψ2xn−Ψ2p0. 3.39

Similarly, from3.37and3.39, we can prove that

lim

n→ ∞BxnBpnlim→ ∞Ψ1xn−Ψ1p0. 3.40

On the other hand, letp ∈Θfor eachn≥ 1; we getp TΦ1

r IrΨ1p. ByLemma 2.10iii,

that is,TΦ1

r is firmly nonexpansive, we obtain

unp2

TΦ1

r IrΨ1xnTrΦ1IrΨ1p 2

IrΨ1xnIrΨ1p, unp

1 2

IrΨ1xnIrΨ1p2unp2−IrΨ1xnIrΨ1p

unp2

≤ 1

2

xnp2unp2−xnunrΨ1xn−Ψ1p2

≤ 1

2

xnp2unp2− xnun22rxnunΨ1xn−Ψ1pr2Ψ1xn−Ψ1p2

.

3.41

So, we obtain

unp2

(22)

Observe that

ynp2

PExnλnBxnPEpλnBp2

IλnBxnIλnBp, ynp

1 2

IλnBxnIλnBp2ynp2

IλnBxnIλnBp

ynp2

≤ 1

2

xnp2ynp2−xnyn

λn

BxnBp2

≤ 1

2

xnp2ynp2−xnyn2−λ2nBxnBp2

2λn

xnyn, BxnBp

,

3.43

and hence

ynp2 ≤xnp2−xnyn22λnxnynBxnBp. 3.44

By using the same argument in3.42and3.44, we can prove that

vnp2 ≤xnp2− xnvn22sxnvnΨ2xn−Ψ2p,

znp2

xnp2− xnzn22μnxnznCxnCp.

3.45

Substituting3.42,3.44, and3.45into3.33, we obtain

knp2≤αn1xnp2αn2ynp2αn3znp2αn4unp2αn5vnp2

αn1xnp2αn2

xnp2−xnyn22λnxnynBxnBp

αn3

xnp2− xnzn22μnxnznCxnCp

αn4

xnp2− xnun22rxnunΨ1xn−Ψ1p

αn5

xnp2− xnvn22sxnvnΨ2xn−Ψ2p

xnp2−αn2xnyn22λnαn2xnynBxnBp

αn3xnzn22μnαn3xnznCxnCp

αn4xnun22rαn4xnunΨ1xn−Ψ1p

αn5xnvn22sαn5xnvnΨ2xn−Ψ2p.

(23)

FromLemma 2.4,3.2, and3.46, we obtain

xn1−p2 n

γfxnAp

βn

xnp

1−βn

InA

knp2

nγfxnAp2βnxnp21−βnnγknp2

nγfxnAp2βnxnp2

1−βnnγxnp2−αn2xnyn22λnαn2xnynBxnBp

αn3xnzn22μnαn3xnznCxnCp

αn4xnun22rαn4xnunΨ1xn−Ψ1p

αn5xnvn22sαn5xnvnΨ2xn−Ψ2p

nγfxnAp21−nγxnp2

−1−βn

αn2xnyn22

1−βn

λnαn2xnynBxnBp

−1−βnnγαn3xnzn22

1−βnnγμnαn3xnznCxnCp

−1−βn

αn4xnun22r

1−βn

αn4xnunΨ1xn−Ψ1p

−1−βn

αn5xnvn22s

1−βn

αn5xnvnΨ2xn−Ψ2p

nγfxnAp2xnp2−1−βnnγαn2xnyn2

21−βn

λnαn2xnynBxnBp

1−βn

αn3xnzn2

21−βnnγμnαn3xnznCxnCp

1−βnnγαn4xnun2

2r1−βn

αn4xnunΨ1xn−Ψ1p

1−βn

αn5xnvn2

2s1−βnnγαn5xnvnΨ2xn−Ψ2p.

3.47

It follows that

1−βn

αn4xnun2 ≤nγfxnAp2xn1−xnxnpxn1−p

21−βn

λnαn2xnynBxnBp

21−βnnγμnαn3xnznCxnCp

2r1−βn

αn4xnunΨ1xn−Ψ1p

2s1−βnnγαn5xnvnΨ2xn−Ψ2p.

(24)

FromC2,C6,3.37,3.39,3.40, andxn1−xn → 0 asn → ∞, we also have

lim

n→ ∞xnun0. 3.49

From3.47and by using the same argument above, we can prove that

lim

n→ ∞xnynnlim→ ∞xnznnlim→ ∞xnvn0. 3.50

Applying3.28,3.49, and3.50, we obtain

lim

n→ ∞knunnlim→ ∞knynnlim→ ∞knznnlim→ ∞knvn0. 3.51

Step 4. We claim that lim supn→ ∞Aγfq, qxn ≤0,whereqPΘIAγfqis the

unique solution of the variational inequalityAγfq, xq ≥0, for allx∈Θ.

To show the above inequality, we choose a subsequence{xni}of{xn}such that

lim sup

n→ ∞

Aγfq, qxn

lim

i→ ∞

Aγfq, qxni. 3.52

Since{xni}is bounded, there exists a subsequence{xnij}of{xni}which converges weakly to

zE. Without loss of generality, we can assume thatxni z.We claim thatz∈Θ. That is, we will prove that

zFS∩VIE, C∩VIE, B∩GMEPΦ1, ϕ,Ψ1

∩GMEPΦ2, ϕ,Ψ2

. 3.53

Assume also thatλnλd,2βandμnμe,2ξ. Define a mappingQ:EEby

Q1Skxα2PE1−λBxα3PE1−μCxα4TΦ1

r IrΨ1x

α5TΦ2

s IrΨ2x,xE,

3.54

where limn→ ∞αni αi ∈0,1, wherei1,2,3,4,5. Since

5

i1α

i

n 1 and byLemma 2.9,

we have thatQis nonexpansive and

FQ FSkFPE1−λBF

PE

1−μCFTΦ1

r IrΨ1

FTΦ2

s IrΨ2

FS∩VIE, C∩VIE, B∩GMEPΦ1, ϕ,Ψ1

∩GMEPΦ2, ϕ,Ψ2

.

(25)

Notice that

Qxnxn

≤ Qxnknknxn

α1Skxnα2PE1−λBxnα3PE1−μCxnα4TΦ1

r IrΨ1xn

α5TΦ2

s IrΨ2xn

αn1Skxnαn2PE1−λnBxnαn3PE

1−μnC

xn

αn4TrΦ1IrΨ1xnαn5TsΦ2IrΨ2xn knxn

α1−αn1Skxnα2PEIλBxnPEIλnBxnα2−αn2PEIλnBxn

α3PE

IμCxnPE

IμnC

xnα3−αn3PE

IμnC

xn

α4−αn4TrΦ1IrΨ1xnα5−αn5TsΦ2IrΨ2xnknxn

α1−αn1Skxnα2|λnλ|Bxnα2−αn2PEIλnBxn

α3μnμCxnα3−αn3PE

IμnC

xn

α4−αn4TrΦ1IrΨ1xnα5−αn5TsΦ2IrΨ2xnknxn

K1

5

i1

αiαni|λnλ|μnμ

knxn,

3.56

whereK1is an appropriate constant such that

K1≥max

sup

n≥1

TΦ1

r IrΨ1xn

,sup

n≥1

TΦ2

s IrΨ2xn

,sup

n≥1

{PEIλnBxn},

sup

n≥1

PE

IμnC

xn,sup n≥1

{Bxn},sup n≥1

{Cxn},sup n≥1

{Skxn}

.

3.57

FromC4,C6, and3.28, we obtain

lim

n→ ∞xn− Qxn0. 3.58

SincePΘIAγfqis a contraction with the coefficientα∈0,1, we have that there exists a

unique fixed point. We useqto denote the unique fixed point to the mappingPΘIAγfq.

(26)

which converges weakly toz. Without loss of generality, we may assume that{xni} z. It follows from3.58, that

lim

n→ ∞xni− Qxni0. 3.59

It follows fromLemma 2.8thatzFQ. By3.55, we havez∈Θ. Hence from3.52and2.4, we arrive at

lim sup

n→ ∞

Aγfq, qxnlim sup

n→ ∞

Aγfq, qxni

Aγfq, qz≤0.

3.60

On the other hand, we have

Aγfq, qxn1

Aγfq, xnxn1

Aγfq, qxn

Aγfqxnxn1

Aγfq, qxn

. 3.61

From3.25and3.60, we obtain that

lim sup

n→ ∞

Aγfq, qxn1

≤0. 3.62

Step 5. We claim that limn→ ∞xnq0.

Indeed, by3.2and using Lemmas2.6and2.14, we observe that

xn1−q2nγfxn βnxn

1−βn

InA

knq2

1−βn

InA

knq

βn

xnq

n

γfxnAq2

1−βn

1−βn

InA

1−βn

knqβnxnq

2

2nγfxnAq, xn1−q

≤1−βn

1−βn

InA

1−βn

knq

2

(27)

2nγfxnfq, xn1−q

2nγfqAq, xn1−q

≤1−βn

1−βnInA

1−βn

knq

2

βnxnq2

2nγαxnqxn1−q2n

γfqAq, xn1−q

≤ 1−βn

InA2

1−βn

knq2βnxnq2

nγα

xnq2xn1−q2

2n

γfqAq, xn1−q

≤ 1−βn

InA2

1−βn

xnq2

βnxnq2

nγα

xnq2xn1−q2

2n

γfqAq, xn1−q

1−βn

γn

2

1−βn βnnγα

xnq2

nγαxn1−q22n

γfqAq, xn1−q

1−2γαγn γ22

n

1−βn

xnq2

nγαxn1−q22n

γfqAq, xn1−q

, 3.63

which implies that

xn1q2

1− 2

γαγn

1−αγn

xnq2

n 1−αγn

γ2n

1−βn

xnq22

γfqAq, xn1−q

. 3.64 Taking σn n

1−αγn

γ2n

1−βn

xnq22

γfqAq, xn1−q

n 2

γαγn

1−αγn ,

3.65

then, we can rewrite3.64as

xn1q2

(28)

and we can see that ∞n1n ∞ and lim supn→ ∞σn/n ≤ 0. Applying Lemma 2.13 to 3.66, we conclude that{xn}converges strongly toqin norm. This completes the proof.

If the mappingSis nonexpansive, thenSkS0S. We can obtain the following result

fromTheorem 3.1immediately.

Corollary 3.2. LetEbe a nonempty closed convex subset of a real Hilbert spaceH. LetΦ1andΦ2be

two bifunctions fromE×EtoRsatisfying (A1)–(A5) and letϕ:E → R ∪ {∞}be a proper lower

semicontinuous and convex function with either (B1) or (B2). LetC:EHbe aξ-inverse-strongly

monotone mapping, letΨ1:EHbe a ρ-inverse-strongly monotone mapping, letΨ2:EH

be anω-inverse-strongly monotone mapping and letB:EHbe aβ-inverse-strongly monotone

mapping. Letf :EEbe anα-contraction with coefficientα0≤ α <1and letAbe a strongly positive linear bounded operator onHwith coefficientγ >0and0 < γ < γ/α. LetS :EEbe a nonexpansive mapping with a fixed point. Suppose that

Θ:FSVIE, BVIE, CGMEPΦ1, ϕ,Ψ1

GMEPΦ2, ϕ,Ψ2

/

. 3.67

Let{xn}be a sequence generated by the following iterative algorithm3.2, where{n},{βn},{γn},

and{αni}are sequences in0,1, wherei1,2,3,4,5,r∈0,2ρ,s∈0,2ω, and{λn}and{μn}

are positive sequences. Assume that the control sequences satisfy (C1)–(C6) in Theorem 3.1. Then,

{xn}converges strongly to a pointq∈Θwhich is the unique solution of the variational inequality:

Aγfq, xq ≥0,x∈Θ. 3.68

Equivalently, one hasqPΘIAγfq.

Ifϕ 0,Ψ1 Ψ2 0, A I, γ ≡ 1,andγn 1−nβn inTheorem 3.1, then we can

obtain the following result immediately.

Corollary 3.3. LetEbe a nonempty closed convex subset of a real Hilbert spaceH. LetΦ1andΦ2

be two bifunctions fromE×EtoRsatisfying (A1)–(A4). LetC :EH be aξ-inverse-strongly

monotone mapping and letB:EHbe aβ-inverse-strongly monotone mapping. Letf :EE

be anα-contraction with coefficientα0 ≤ α < 1and let Abe a strongly positive linear bounded operator onHwith coefficientγ >0and0< γ < γ/α. LetS:EEbe ak-strict pseudocontraction

with a fixed point. Define a mappingSk :EEbySkxkx 1−kSx,for allxE. Suppose

that

(29)

Let{xn}be a sequence generated by the following iterative algorithm:

x1∈E, unE, vnE,

Φ1un, u

1

ruun, unxn ≥0,uE,

Φ2vn, v 1

svvn, vnxn ≥0,vE, znPExnμnCxn,

ynPExnλnBxn,

knαn1Skxnαn2ynαn3znαn4unαn5vn,

xn1nfxn βnxnγnkn,n≥1,

3.70

where {n}, {βn}, {γn}, and {αni} are sequences in 0,1, where i 1,2,3,4,5, r ∈ 0,, s ∈ 0,, and{λn}and {μn}are positive sequences. Assume that the control sequences satisfy

the condition (C1)–(C6) inTheorem 3.1andnβnγn1. Then,{xn}converges strongly to a point q∈Θ, whereqPΘfq.

IfB0, C0,andΦ1un, u Φ1vn, v 0 inCorollary 3.3, thenPEIand we get unynxnandvnznxn; hence we can obtain the following result immediately.

Corollary 3.4. LetEbe a nonempty closed convex subset of a real Hilbert spaceH. LetS:EE

be ak-strict pseudocontraction with a fixed point. Define a mappingSk:EEbySkxkx 1−

kSx,for allxE. Suppose thatFS/.Let{xn}be a sequence generated by the following iterative

algorithm:

x1∈E,

kn αnSkxn 1−αnxn,

xn1nfxn βnxnγnkn,n≥1,

3.71

where{n},{βn},{γn}, and{αn}are sequences in0,1. Assume that the control sequences satisfy

the conditions (C2) and (C3),limn→ ∞αn α ∈0,1inTheorem 3.1, andnβnγn 1. Then,

{xn}converges strongly to a pointqFS, whereqPFSfq.

Finally, we consider the followingConvex Feasibility ProblemCFP:

finding an xM

i1

Ci, 3.72

where M ≥ 1 is an integer and each Ci is assumed to be the of solutions of equilibrium

References

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