The Quark Model
electron neutrino electron
down up
muon neutrino muon
strange charm
tau neutrino
tau
bo8om top
Increasing mass
+2/3
-‐1/3
-‐1
0 All
normal ma8er is made of these parCcles
The Building Blocks of Matter
Ground state
symmetric
=
0
2
1
2
1
2
3
2
1
2
1
2
1
⊕
⊕
=
⊗
⊗
SU(3)flavour
irreps
SU(3)colour irreps! anCsymmetric!
must be symmetric
Baryons
Must be anC-‐ symmetric (Pauli
Principle)
ϕA = 1
6
(
rbg − brg + bgr− gbr + grb − rgb
)
uuu
ddd
sss
uss+sus+ssu
3
dss+sds+ssd
3
dds+dsd+sdd 3
uus+usu+suu
3
uud+udu+duu
3
udd+dud+ddu 3
uds+usd+dsu+dus+sdu+sud 6
strangeness
0
-2
-3
i=3/2
i=1
i=1/2
i=0
-‐
1232 MeV
1384 MeV
1533 MeV
1672 MeV
J
=
3
2
i
3 Δ++ Δ+ Δ0 Δ− Σ+ Σ0 Σ−Ξ* Ξ*0
Ω−
(2(ud−du)s+(us−su)d−(ds−sd)u) / 12 ((us−su)d+(ds−sd)u) / 2
(ud−du)d 2
(ud−du)u
2
(ds−sd)d
2
(us−su)d
2
(ds−sd)s
2
(us−su)s 2
(2s(ud−du)+d(us−su)−u(ds−sd)) / 12
(d(us−su)+u(ds−sd)) / 2
d(ud−du) 2
u(ud−du) 2
d(ds−sd) 2
u(us−su) 2
s(ds−sd) 2
s(us−su) 2
⊕
strangeness
0
-2
939 MeV
1193 MeV
1318 MeV 1116 MeV
J
=
1
2
i
3 p n Σ+ Σ0 Σ−Ξ Ξ0
Decuplet
E x a m p l e s
This is the only symmetric combination of spin with
χ
10uuu
ddd
sss
uss+sus+ssu
3
dss+sds+ssd
3
dds+dsd+sdd 3
uus+usu+suu
3
uud+udu+duu
3
udd+dud+ddu 3
uuu
ddd
sss
uss+sus+ssu
3
dss+sds+ssd
3
dds+dsd+sdd 3
uus+usu+suu
3
uud+udu+duu
3
udd+dud+ddu 3
uds+usd+dsu+dus+sdu+sud 6
strangeness
0
-2
-3
i=3/2
i=1
i=1/2
i=0
-‐
1232 MeV
1384 MeV
1533 MeV
1672 MeV
J
=
3
2
i
3 Δ++ Δ+ Δ0 Δ− Σ+ Σ0 Σ−Ξ* Ξ*0
Ω−
We write down quark wavefunctions for the
J
=
3 / 2 states by taking products of
Octet
This is the only symmetric combination of spin with
χ
10 (2(ud−du)s+(us−su)d−(ds−sd)u) / 12((us−su)d+(ds−sd)u) / 2 (ud−du)d
2
(ud−du)u
2
(ds−sd)d
2
(us−su)d
2
(ds−sd)s
2
(us−su)s 2
(2s(ud−du)+d(us−su)−u(ds−sd)) / 12
(d(us−su)+u(ds−sd)) / 2
d(ud−du) 2
u(ud−du) 2
d(ds−sd) 2
u(us−su) 2
s(ds−sd) 2
s(us−su) 2
⊕
Can also write this as: 2
ψ
121/2χ
128+
2
ψ
231/2χ
238+
ψ
1/223χ
128+
ψ
121/2χ
238There are NO other symmetric combinations of spin with
χ
10InterpretaCon?
Probability of finding a spin-‐down d-‐quark inside the proton is: p;1
2, 1
2 =N 2 1
2
(
↑↓ − ↓↑)
↑ ⎡⎣⎢
⎤ ⎦⎥
1
2
(
ud − du)
u ⎡ ⎣⎢ ⎤ ⎦⎥ ⎧ ⎨⎩ +2
1
2 ↑ ↑↓ − ↓↑
(
)
⎡⎣⎢
⎤ ⎦⎥
1
2 u
(
ud − du)
⎡⎣⎢
⎤ ⎦⎥
1
2 ↑ ↑↓ − ↓↑
(
)
⎡⎣⎢
⎤ ⎦⎥
1
2
(
ud − du)
u ⎡⎣⎢
⎤ ⎦⎥+
1
2
(
↑↓ − ↓↑)
↑ ⎡⎣⎢
⎤ ⎦⎥
1
2 u
(
ud − du)
⎡ ⎣⎢ ⎤ ⎦⎥ ⎫ ⎬ ⎭Normalize this state
⇒
p
;
1
2
,
1
2
p
;
1
2
,
1
2
=
1
⇒
N
=
1
18
Expand it out:
p
;
1
2
,
1
2
=
1
18
(
2
u
↑
d
↓
u
↑ −
u
↓
d
↑
u
↑ −
d
↑
u
↓
u
↑
+
2
d
↓
u
↑
u
↑
+
2
u
↑
u
↑
d
↓ −
u
↑
u
↓
d
↑
−
u
↑
d
↑
u
↓ −
d
↑
u
↑
u
↓ −
u
↓
u
↑
d
↑
)
(2(ud−du)s+(us−su)d−(ds−sd)u) / 12 ((us−su)d+(ds−sd)u) / 2
(ud−du)d 2
(ud−du)u
2
(ds−sd)d
2
(us−su)d
2
(ds−sd)s
2
(us−su)s 2
(2s(ud−du)+d(us−su)−u(ds−sd)) / 12
(d(us−su)+u(ds−sd)) / 2
d(ud−du) 2
u(ud−du) 2
d(ds−sd) 2
u(us−su) 2
s(ds−sd) 2
s(us−su) 2
⊕
strangeness
0
-2
939 MeV
1193 MeV
1318 MeV 1116 MeV
J
=
1
2
i
3 p n Σ+ Σ0 Σ−Ξ Ξ0
Λ
We write down quark wavefunctions for the
J
=
1 / 2 states by taking symmetric
Mesons
• Bound state of a quark with an antiquark• Pauli principle no longer an issue because particles are never
identical
Ground state
symmetric
=
0
0
1
2
1
2
1
⊕
=
⊗
SU(3)flavourirreps must be colour neutral; guaranteed since we have an anCparCcle
s u s d u d
(
uu−dd)
2 1 u s d u − d s −
(uu dd 2ss)
6 1
−
+ (uu+dd +ss)
3 1
8
χ
χ
1s u s d u d
(
uu−dd)
2 1 u s d u − d s −
(uu dd 2ss)
6 1
−
+ (uu+dd +ss)
3 1
8
+
K 0
K
−
K K0
+
π
−
π
0
π
8
η
0
η
Spin-0 Mesons
Theoretical
η
mesons are a bit different:
Experimental
(the octet and singlet get mixed together
because the strange quarks strongly interact and the quantum numbers are the same
+
*
K
0 *
K
0 *
K
−
*
K
+
ρ
−
ρ
0
ρ
8
φ
0
φ
Spin-1 Mesons
Theoretical
φ
mesons are a bit different:
Experimental
Can we do better?
M
meson=
sum of quark masses
+
colour dipole interaction energy
Quark Mass RelaCons
m
s
150 MeV?
dipole-‐dipole interacCon
Yes! Quarks have
dipole moments
Electromagnetic Hyperfine splitting
Colour Hyperfine splitting
Colour factor
MagneCc Moments
Compute for each baryon wavefuncCon
For the proton:
Each state is orthogonal to the others, so do this term-‐by-‐term
First term contributes
All others are similar to one of these two, so get:
2nd term
contributes
Fit okay – but not fantastic