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(1)

The  Quark  Model  

(2)

electron   neutrino   electron  

down   up  

muon   neutrino   muon  

strange   charm  

tau   neutrino  

tau  

bo8om   top  

Increasing  mass  

+2/3  

-­‐1/3  

-­‐1  

0   All    

normal   ma8er  is   made  of   these   parCcles  

The Building Blocks of Matter

(3)

Ground     state  

 

symmetric  

=

0

2

1

2

1

2

3

2

1

2

1

2

1

=

SU(3)

flavour    

irreps  

SU(3)colour    irreps!   anCsymmetric!  

must  be  symmetric  

Baryons  

Must  be  anC-­‐ symmetric   (Pauli  

Principle)  

ϕA = 1

6

(

rbgbrg + bgr

gbr + grbrgb

)

(4)

uuu

ddd

sss

uss+sus+ssu

3

dss+sds+ssd

3

dds+dsd+sdd 3

uus+usu+suu

3

uud+udu+duu

3

udd+dud+ddu 3

uds+usd+dsu+dus+sdu+sud 6

strangeness  

0  

-2  

-3  

i=3/2  

i=1  

i=1/2  

i=0  

-­‐  

1232  MeV  

1384  MeV  

1533  MeV  

1672  MeV  

J

=

3

2

i

3 Δ++ Δ+ Δ0 Δ− Σ+ Σ0 Σ−

Ξ* Ξ*0

Ω−

(2(ud−du)s+(us−su)d−(ds−sd)u) / 12 ((us−su)d+(ds−sd)u) / 2

(ud−du)d 2

(uddu)u

2

(dssd)d

2

(ussu)d

2

(dssd)s

2

(us−su)s 2

(2s(uddu)+d(ussu)−u(dssd)) / 12

(d(ussu)+u(dssd)) / 2

d(uddu) 2

u(uddu) 2

d(dssd) 2

u(ussu) 2

s(dssd) 2

s(ussu) 2

strangeness  

0  

-2  

939  MeV  

1193  MeV  

1318  MeV   1116  MeV  

J

=

1

2

i

3 p n Σ+ Σ0 Σ−

Ξ Ξ0

(5)

Decuplet

E x a m p l e s

This is the only symmetric combination of spin with

χ

10

uuu

ddd

sss

uss+sus+ssu

3

dss+sds+ssd

3

dds+dsd+sdd 3

uus+usu+suu

3

uud+udu+duu

3

udd+dud+ddu 3

(6)

uuu

ddd

sss

uss+sus+ssu

3

dss+sds+ssd

3

dds+dsd+sdd 3

uus+usu+suu

3

uud+udu+duu

3

udd+dud+ddu 3

uds+usd+dsu+dus+sdu+sud 6

strangeness  

0  

-2  

-3  

i=3/2  

i=1  

i=1/2  

i=0  

-­‐  

1232  MeV  

1384  MeV  

1533  MeV  

1672  MeV  

J

=

3

2

i

3 Δ++ Δ+ Δ0 Δ− Σ+ Σ0 Σ−

Ξ* Ξ*0

Ω−

We write down quark wavefunctions for the

J

=

3 / 2 states by taking products of

(7)

Octet

This is the only symmetric combination of spin with

χ

10 (2(ud−du)s+(us−su)d−(ds−sd)u) / 12

((us−su)d+(ds−sd)u) / 2 (ud−du)d

2

(uddu)u

2

(dssd)d

2

(ussu)d

2

(dssd)s

2

(us−su)s 2

(2s(uddu)+d(ussu)−u(dssd)) / 12

(d(ussu)+u(dssd)) / 2

d(uddu) 2

u(uddu) 2

d(dssd) 2

u(ussu) 2

s(dssd) 2

s(ussu) 2

Can also write this as: 2

ψ

121/2

χ

128

+

2

ψ

231/2

χ

238

+

ψ

1/223

χ

128

+

ψ

121/2

χ

238

There are NO other symmetric combinations of spin with

χ

10

(8)

InterpretaCon?  

Probability  of  finding  a  spin-­‐down  d-­‐quark   inside  the  proton  is:   p;1

2, 1

2 =N 2 1

2

(

↑↓ − ↓↑

)

↑ ⎡

⎣⎢

⎤ ⎦⎥

1

2

(

uddu

)

u ⎡ ⎣⎢ ⎤ ⎦⎥ ⎧ ⎨

⎩ +2

1

2 ↑ ↑↓ − ↓↑

(

)

⎣⎢

⎤ ⎦⎥

1

2 u

(

uddu

)

⎣⎢

⎤ ⎦⎥

1

2 ↑ ↑↓ − ↓↑

(

)

⎣⎢

⎤ ⎦⎥

1

2

(

uddu

)

u

⎣⎢

⎤ ⎦⎥+

1

2

(

↑↓ − ↓↑

)

↑ ⎡

⎣⎢

⎤ ⎦⎥

1

2 u

(

uddu

)

⎡ ⎣⎢ ⎤ ⎦⎥ ⎫ ⎬ ⎭

Normalize this state

p

;

1

2

,

1

2

p

;

1

2

,

1

2

=

1

N

=

1

18

Expand it out:

p

;

1

2

,

1

2

=

1

18

(

2

u

d

u

↑ −

u

d

u

↑ −

d

u

u

+

2

d

u

u

+

2

u

u

d

↓ −

u

u

d

u

d

u

↓ −

d

u

u

↓ −

u

u

d

)

(9)

(2(ud−du)s+(us−su)d−(ds−sd)u) / 12 ((us−su)d+(ds−sd)u) / 2

(ud−du)d 2

(uddu)u

2

(dssd)d

2

(ussu)d

2

(dssd)s

2

(us−su)s 2

(2s(uddu)+d(ussu)−u(dssd)) / 12

(d(ussu)+u(dssd)) / 2

d(uddu) 2

u(uddu) 2

d(dssd) 2

u(ussu) 2

s(dssd) 2

s(ussu) 2

strangeness  

0  

-2  

939  MeV  

1193  MeV  

1318  MeV   1116  MeV  

J

=

1

2

i

3 p n Σ+ Σ0 Σ−

Ξ Ξ0

Λ

We write down quark wavefunctions for the

J

=

1 / 2 states by taking symmetric

(10)

Mesons  

Bound state of a quark with an antiquark

•  Pauli principle no longer an issue because particles are never

identical

Ground  state    

symmetric  

=

0

0

1

2

1

2

1

=

SU(3)flavour    

irreps   must  be  colour  neutral;  guaranteed  since  we     have  an  anCparCcle  

s u s d u d

(

uudd

)

2 1 u s d ud s

(uu dd 2ss)

6 1

+ (uu+dd +ss)

3 1

8

χ

χ

1

s u s d u d

(

uudd

)

2 1 u s d ud s

(uu dd 2ss)

6 1

+ (uu+dd +ss)

3 1

8

(11)

+

K 0

K

K K0

+

π

π

0

π

8

η

0

η

Spin-0 Mesons

Theoretical

η

mesons are a bit different:

Experimental

(the octet and singlet get mixed together

because the strange quarks strongly interact and the quantum numbers are the same

(12)

+

*

K

0 *

K

0 *

K

*

K

+

ρ

ρ

0

ρ

8

φ

0

φ

Spin-1 Mesons

Theoretical

φ

mesons are a bit different:

Experimental

(13)

Can we do better?

M

meson

=

sum of quark masses

+

colour dipole interaction energy

Quark  Mass  RelaCons  

m

s

150 MeV?

dipole-­‐dipole   interacCon  

Yes! Quarks have

dipole moments

(14)

Electromagnetic Hyperfine splitting

Colour Hyperfine splitting

(15)
(16)

Colour factor  

(17)
(18)
(19)
(20)

MagneCc  Moments  

Compute  for  each  baryon  wavefuncCon  

(21)

For the proton:

Each  state  is  orthogonal  to  the  others,  so  do  this  term-­‐by-­‐term  

First  term  contributes  

All  others  are  similar  to  one  of  these  two,  so  get:  

 

2nd  term    

contributes  

(22)

Fit okay – but not fantastic

References

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