Dr. Francis CM Lau, Associate Professor, EIE, PolyU 1
Multiple Access Techniques
Dr. Francis LAU
Content
•
Introduction
•
Frequency Division Multiple Access
•
Time Division Multiple Access
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 3
Introduction
• multiple access
– techniques allowing users to share simultaneously a finite amount of radio spectrum
• duplexing
– two-way communications to occur simultaneously
Introduction
• frequency division duplexing (FDD)
– frequency separation between each forward and reverse channel is constant throughout the system, regardless of the particular channel being used
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 5
Introduction
• time division duplexing (TDD)
Introduction
• narrowband systems
– signal bandwidth is comparable to the coherence bandwidth of the channel
– radio spectrum divided into a large number of narrowband channels
– usually operated using FDD
• frequency separation as large as possible to minimize interference
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 7
Introduction
• wideband systems
– signal bandwidth is much larger than the coherence bandwidth of the channel
• what type of fading occurs?
– TDMA allocates time slots to many users on the channel and allows only one user to access the channel at any one time
– CDMA allows all users to access the channel at the same time
– work with both FDD and TDD
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 9
Frequency Division Multiple
Access (FDMA)
FDMA
• each user is assigned a unique frequency
band or channel
• no other user can share the same channel
during the period of the call
• in FDD systems, a channel consists of a
frequency pair is assigned
– one frequency for forward channel – one frequency for reverse channel
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 11
FDMA
• each FDMA channel has a relatively narrow
bandwidth because only one user is being supported • symbol time is large compared to the average delay
spread
– what type of fading occurs?
• lower complexity and lower data rate compared with TDMA
• fewer bits needed for overhead compared with TDMA
• …
FDMA
• nonlinear effects
– many channels share the same antenna at the base station
– power amplifiers or power combiners are nonlinear when operating at or near saturation for maximum power efficiency
– nonlinearities cause intermodulation (IM) which can interfere with other channels
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 13
Example 9.1
• Find the intermodulation frequencies
generated if a base station transmits two
carrier frequencies at 1930MHz and
1932MHz that are amplified by a saturated
clipping amplifier. If the mobile radio band
is allocated from 1920MHz to 1940MHz,
designate the IM frequencies that lies inside
and outside the band.
Solution 9.1
• Intermodulation distortion products occurs at frequencies mf1+nf2for all integer values of m and n. Some of the possible IM frequencies that are produced by a nonlinear device are
– (2n+1)f1 –2nf2, (2n+2)f1 –(2n+1)f2, (2n+1)f2 –2nf1, (2n+2)f2 –(2n+1)f1
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 15
Time Division Multiple Access
(TDMA)
TDMA
• divide the radio spectrum into time slots
• only one user is allowed to either transmit
or receive in each time slot
• N time slots comprise a frame
• data transmitted in a buffer-and-burst
method
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 17
TDMA
TDMA
• mobile assisted handoff (MAHO) can be
performed by a subscriber by listening on an idle slot in the TDMA frame
• possible to allocate different number of time slots per frame to different users (e.g. GPRS)
• higher transmission rate gives rise to a signal bandwidth larger than the coherence bandwidth of the channel
– What type of fading occurs?
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 19
TDMA
• Efficiency
– frame efficiency: percentage of bits per frame that contain transmitted data
• information rate/transmission rate
Example 9.3
• Consider GSM, which is a TDMA/FDD
system that uses 25MHz for the forward
link, which is broken into radio channels of
200kHz. If 8 speech channels are supported
on a single radio channel, and if no guard
band is assumed, find the number of
simultaneously users that can be
accommodated in GSM.
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 21
Solution 9.3
• number of simultaneously users that can be
accommodated in GSM
N = (25MHz/200kHz) x 8 = 1000
Example 9.4
• If GSM uses a frame structure where each frame consists of eight time slots, and each time slot contains 156.25 bits, and data are transmitted at 270.833 kbps in the channel, find
• (a) the time duration of a bit, • (b) the time duration of a slot, • (c) the time duration of a frame,
• (d) how long must a user occupying a single time slot wait between two successive transmissions.
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 23
Solution 9.4
• If GSM uses a frame structure where each frame consists of eight time slots, and each time slot contains 156.25 bits, and data are transmitted at 270.833 kbps in the channel, find
• (a) the time duration of a bit Tb= 1/270.833 kbps = 3.692 µs • (b) the time duration of a slot Ts= 156.25 Tb= 0.577ms • (c) the time duration of a frame Tf= 8 Ts= 4.615 ms • (d) a user needs to wait one frame duration, i.e., 4.615 ms,
between two successive transmissions
Example 9.5
• If a normal GSM time slot consists of six
trailing bits, 8.25 guard bits, 26 training
bits, and two traffic bursts of 58 bits of data,
find the frame efficiency
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 25
Solution 9.5
• If a normal GSM time slot consists of six
trailing bits, 8.25 guard bits, 26 training
bits, and two traffic bursts of 58 bits of data,
find the frame efficiency
• no. of data bits per time slot = 2 x 58 = 116
• equivalent no. of bits per time slot = 2 x 58
+ 6 + 8.25 + 26 = 156.25
• frame efficiency = 116/156.25 = 74.24%
Code Division Multiple Access
(CDMA)
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 27
CDMA
• BPSK spreading accomplished by
multiplying s
d(t) by a function c(t)= ±1
representing the spreading waveform
BPSK DS-SS transmitter transmitted signal Phase modulator )] ( cos[ 2P ω0t+θd t )] ( cos[ ) ( 2Pct ω0t+θd t Binary data t Pcos 0 2 ω c(t) Phase modulator )] ( cos[ 2P ω0t+θd t )] ( cos[ ) ( 2Pct ω0t+θd t Binary data t Pcos 0 2 ω c(t)
CDMA
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 29
BPSK DS-SS
(two-sided psd of a BPSK carrier)
Power spectral density of data-modulated carrier
{
f f T f f T}
PT f Sd sinc [( ) sinc [( ) 2 1 ) ( 2 0 0 2 − + + =BPSK DS-SS
psd of data- and spreading code-modulated carrier
• st(t) is also a BPSK carrier with T replaced by Tc
• Tc= T/3 ⇒ bandwidth of the transmitted signal spread by a factor of 3 ⇒ level of the psd reduced by a factor of 3
spreading code chip
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 31
BPSK DS-SS
• despreading: re-modulation or correlation of the received signal with the delayed spreading waveform BPSK DS-SS receiver Bandpass filter Data phase demodulator Despreading mixer Estimated data φ + − θ + ω − )cos[ ( ) ( 2Pct Td 0t d t Td + interference ) ˆ (t Td c − 2Pc(t−Td)c(t−Tˆd)cos[ω0t+θd(t−Td)+φ signal component distortionless channel interference and/or Gaussian noise receiver's best estimate of the transmission delay transmission delay ] ]
Spreading Codes
• pseudorandom (PN) codes
• m-sequence
• Gold codes
• Walsh Codes
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 33
Hadamard matrix M
n• n x n matrix
– n = even integer• elements are
• one row of the matrix contains all ones
• other rows contain n/2 no. of “+1” and n/2
no. of “– 1”
• any row differs from the other row in
exactly n/2 positions
1
±
Hadamard matrix M
n − = 1 1 1 1 2 M = n n n n n M M M M M2 − − − − − − − − − − = − − − − − − = 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ; 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 4 4 M MDr. Francis CM Lau, Associate Professor, EIE, PolyU 35
Walsh-Hadamard Codes
• rows of the Hadamard matrix used as code
words
• mutually orthogonal
– e.g. row 1 and 2, 1.1+1.(–1)+1.1+1.(–1) = 0 – breaks down in the presence of multipath
− − − − − − = 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 4 M code 1 code 2 code 3 code 4
CDMA
• narrowband message signal is multiplied by a very large bandwidth signal called the spreading signal • all users use the same carrier frequency and may
transmit simultaneously, TDD or FDD may be used
• unlike FDMA or TDMA, CDMA has a soft
capacity limit
– increasing the no. of users raises the noise level, more errors occur
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 37
CDMA
• near-far problem
– mitigated using power control
• spread spectrum bandwidth much greater than the coherence bandwidth
– what type of fading?
• frequency reuse factor in CDMA cellular system is 1
– all cells use the same spectrum • soft handoff
• …
Summary
• multiple access techniques
– frequency division multiple access – time division multiple access – code division multiple access
Dr. Francis CM Lau, Associate Professor, EIE, PolyU 39
Summary
• Reading
– Rappaport T. S., Wireless Communications:
Principles and Practice, Prentice Hall PTR,
Sections 9.1-9.4.2, 2002.
• Problems
– Rappaport T. S., Wireless Communications:
Principles and Practice, Prentice Hall PTR,