• No results found

2NA EOY 2014 Answer Key.docx

N/A
N/A
Protected

Academic year: 2020

Share "2NA EOY 2014 Answer Key.docx"

Copied!
6
0
0

Loading.... (view fulltext now)

Full text

(1)

Jurongville Secondary School Science Department 2014 Marking Scheme & Marker’s Report

Subject/Assessment : 2014 End-of-Year Examination

Level: 2NA

Qn Marking Scheme Remarks Marks

1 C CAO [1]

2 A [1]

3 D [1]

4 B [1]

5 A [1]

6 B [1]

7 D [1]

8 D [1]

9 A [1]

10 B [1]

11 C [1]

12 B [1]

13 A [1]

14 A [1]

15 B [1]

16 B [1]

17 B [1]

18 B [1]

19 D [1]

20 B [1]

21 C [1]

22 D [1]

23 A [1]

24 B [1]

25 D [1]

26a (i) Melting (ii) Boiling

(iii) Freezing/ Solidification (iv) Condensation

B½ each

Reject spelling error Accept evaporation for change of state from liquid to gas.

(2)

26b [4]

Total: 6

27a C2H6O [1]

27b (i) 12 (ii) 12 (iii) 12 (iv) 2,8,2

B1 each [4]

27c [1]

Total: 6 28a (i) Cytoplasm

(ii) Large central vacuole (iii) Chloroplasts

(iv) Nucleus

[4]

28b Water has entered both cells [1/2] through osmosis [1/2].

Cell B burst because it does not have a cell wall [1/2] to prevent the cell membrane from bursting. Cell A did not burst but increase in size as it has a cell wall [1/2] to prevent the cell membrane from bursting.

B1

[2]

Total: 6 [1/2]

(3)

29a Award B1 for each of the component

A :Correct parallel arrangement of light rays

D: Correct direction of light rays towards the eye

Reject dotted lines.

[2]

29b Any three of the following: 1. The image is upright.

2. The image is laterally inverted 3. The image is virtual.

4. The image is same size as object.

5. The object distance from the mirror is equal to the image distance from the mirror.

B1 for each correct characteristic.

Award BOD½ for each spelling error

[3]

Total: 5

30a Normal B1 each.

Award BOD½ for each spelling error

1

30b Incident ray B1 each.

Award BOD½ for each spelling error (Eg: incidence ray)

1

30c B1 for each correct ray

with direction.

Award BOD½ for missing direction of ray

Angle of refraction at air-water boundary is more than that at water-glass boundary

2

30d Water is optically denser than air [1/2] so light bends towards normal [1/2].

Glass is optically denser than water [1/2]so light bends more towards normal[1/2].

OWTTE

Award BOD½ if student’s answer indicated the idea of refraction or bending

[1]

(4)

of light or change in speed when light travels through different medium.

Total: 6 31a A: Xylem

B : Phloem

B1 each.

Reject spelling mistake.

[2]

31bi Osmosis is the net movement of water molecules moving from a region of higher concentration to a region of lower concentration through a partially permeable membrane.

B1 [1]

31bii Any one of the following differences:

1. Diffusion does not require a partially permeable membrane but osmosis requires a partially permeable membrane.

2. Osmosis can only take place for water molecules but diffusion can take place for any type of molecules.

OWTTE

B1 for the correct comparison.

[1]

31c The permeable bag will reduce in size.

The water molecules move out of the bag to the sugar solution in the beaker via osmosis.

OWTTE B1 B1

[2]

Total: 6 Section C (total: 40 marks)

32a B½ for correct circuit

symbol.

Accept if battery does not have the positive or negative terminals labelled (but direction of terminals must be correct)

[2]

32b Total resistance = 15 + 25 = 40Ω B1

Deduct ½ m for missing or wrong unit.

[1]

32c V = IR = 2 (40) = 80 V

M1 A1

Allow ECF from 31b.

(5)

Deduct ½ m for missing or wrong unit.

32d Voltmeter B1

Reject spelling error

[1] 32e (i) Neutral

(ii) Live (iii) Earth (iv) Fuse

B½ each.

Reject spelling error

[2]

32f The fuse will melt and break the circuit [1/2] if the current flowing through it is excessive [1/2] or exceeds its rating.

OWTTE

Award B½ for ‘stop current flow’

[1]

32g The earth wire is not connected to the earth terminal or the earth wire is connected wrongly to the live terminal.

OWTTE

Award BOD½ for ‘earth wire is connected wrongly’ ‘earth wire is connected to the fuse/ live wire’

[1]

Total: 10

33a B½ for each correct

food chain

Total : 6 food chains

[3]

33b Gazelle Rabbit

B½ each [1]

33c Sun B1 [1]

33d The population of snake will decrease as rabbit is its main source of food.

B1 B1

[2]

33e 1. Energy is lost as heat during respiration

2. Energy is lost in faeces and excretory products OWTTEB½ for each point [2] 33f (i) Parasitism

(ii) The tick benefits/ is the parasite while the gazelle is harmed/ is the host.

B1

B½ for each point Deduct ½ for

(6)

spelling error

Total: 10

34a (i) Oesophagus

(ii) Stomach

(iii) Large intestine/ rectum (iv) Small intestine

B1

Deduct ½m for each spelling mistakes

[4]

34b Any one of the following:

 The teeth cuts the food into smaller pieces  Stomach muscles contracts and relax to

digest food.

OWTTE B1

[1]

34c B½ for each correct

answer.

Reject spelling mistakes.

[3]

34d (i) Fatty/ oily food

(ii) Her body is not able to break down fats into smaller droplets of fats.

B1 B1 OWTTE

[2]

Total: 10

35a (i) Sperm duct

(ii) scrotum

(iii) Testis (singular) (iv) Urethra

B1 each

Reject spelling error

[4]

35bi Fertilisation is the process where the nucleus of the sperm fuses with the nucleus of the egg.

B1 OWTTE

[1]

35bii 1. The fertilised egg divides repeatedly to form the foetus .

2. The embryo moves into the uterus and is implanted on the uterine lining. The woman is now pregnant.

B1 for each point OWTTE

[2]

35ci Tubal ligation B1

Reject spelling error

[1]

35cii Tubal ligation involves tying and cutting both oviducts during surgery.

This disrupts the function of the oviduct and prevents sperms from meeting the egg. Thus, fertilisation will not occur.

B1

B1 OWTTE

[2]

References

Related documents

-Substances pass through a membrane without the aid of transport proteins -There is a net movement of molecules from high to low concentration -Molecules move down the

Concentrated solution Low water concentration Dilute solution High water concentration Selectively permeable membrane Solute

• it is impossible to control the movement of nonpolar molecules through a membrane • Polar substances cross a membrane by moving. through integral membrane transporting proteins

movement of water through a semi-permeable membrane from a region of low solute concentration to an area of high solute concentration in order to equalize the level of water in

Like simple diffusion, the process of facilitated diffusion is passive and allows movement of particles across the membrane only from high concentration to low concentration..

the movement of small molecules across a semi permeable membrane c.. The products of

Please take a selectively permeable to help to let different organelles in the cell and regulates the cell membrane fluidity too much like your answer and cell membrane

This free movement of water, (or diffusion of a solvent), across a semi-permeable membrane is known as osmosis. There are three situations which can result from water movement. I)