ON GENERALIZED
QUATERNION
ALGEBRAS
GEORGE
SZETO
Department of MathematicsBradley University Peoria, lllinois 61625
U.S.A.
(Received February i, 1979 and in revised form July 13, 1979)
ABSTRACT. Let B be a connutative ring with i, and G
(={o})
an automorphlsm group of B of order 2. The generalized quaternion ring extension B[j overB is defined by S. Parimala and R. Sridharan such that (1) B[j] is a free 2
B-odule with a basis {l,j}, and (2) j -l and jb o(b)j for each b in
B. The purpose of this paper is to study the separability of B[j]. The
separable extension of B[j] over B is characterized in terms of the trace
(=
i+o) of B over the subrlng of fixed elements under o. Also, thecharacterization of a Galols extension of a connutative ring given by Parlmala
and Sridharan is improved.
KEF
WORDS
AND PHRASES.
Quaternion Rings,
Separable
Algebras,
and alois
I.
INTRODU CTION.
In
6,
we studied the separable extension of group rings RG and quaternion ringsRi,j,k
over a ringR
withI.
We have shown thatRi,j,k
is a separable extension ofR
if and only if 2 is a unit inR.
Recently,S.
Parimala andR.
Sridharan(5)
investigated anotherclass of quaternion ring extensions
Bj
over a commutative ringB
with and with an automorphism group G(=
)
of order 2, whereBj
is a free B-module with a basis1,j),
j2
-I,
and jb6(b)j
for each b inB.
Their work is based on the following characterization of a Galois extension of a commutative ring(5,
Proposition1.1):
Let A
be theset of elements in
B
fixed under.
Assume 2 is a unit inA.
Then,B
is Galois over
A
if and only ifBABJ
M2(B),
a matrix algebra overB of order 2, where the Galois extension is in the sense of Chase-Har-rison-Rosenberg
(2).
Thepurpose
of this paper isto
study thesepar-ability of
Bj.
Without the assumption that 2 is a unit inA,
we shall characterize the separability ofBj
interms
of thetrace (=
I+)
ofB
overA.
This shows the existence of a separable generalizedquater-nion ring extension
B
with 2not
a unit in A. WhenChar(A)
2, we shall show thatBj
is a separable extension overB
if and only ifB
is Galois over
A.
Thus wecan
improve the above theorem of Parimalaand Sridharan.
Then,
thecase
in which 2 is a unit will bediscussed,
and several examples are constructed
to
illustrate our mainresults.
2.PRELIMINARIES.
Let
us recall some basic definitions as given inI,2,3,4
and6.
Let B
be a commutative ring containing a subringA
with the same identityI.
ThenB
is called a Galois extensionover
A
(2,
orelements
ai,b
i in
B
/
i1,2,...,n
for some integernsuch
thataib
i andai6(b
i)
0 whenever6
inG,
and(2)
A
b
inB
/
(b)
b for all6
inG.
The map6
is called thetrace
ofB
overA
denoted byTr.
Let
S be a ring(not
necessarilycommutative)
contain-ing a subring
R
with the same identityI.
Then S is called a separablee_xtension of
R
if there existelements,
(ci,d
i in S/
i1,2,...,n
forsome
integern}
such that(I)
a(ci(R)d
i)
(cidi)a
for all a in Swhere @ is over
R,
and(2)
cid
i
I.
Such an elementcid
i is called a separable idempotent for S. WhenR
is contained in thecenter
of
S,
S is called a separable R-algebra. The separable R-algebra S iscalled an Azumaya
R-alge.bra
ifR
is thecenter
ofS.
3.
SEPARABLE
QUATERNI ONALGEBRAS.
Throughout,
we assume thatB
is a commutative ring withI,
and G(=
{6)
an automorphismgroup
of order 2 ofB,
and that Bj3 is the generalized quaternion algebra overA,
whereA
is the subring of elements fixed under4.
Our main goal in the section isto
study a separableex-tension
Bj3
overB
without the assumption that 2 is a unit inA.
Webegin with a description of the
set
of separable idempotents forB[j3
(if there areany)
overB.
Clearly,11,1j,j1,jj}
is a basis forLEMMA 3.1.
The elementx
a11(1(R)1)+a12(1j)+a21(J(R)1)+a22(J(R)
j) isa separable idempotent for B[j] over
B
if and only if(I)
a22
-6(a11)
such thatTr(a11)
I,
and(2)
a21
6(a12)
such thata12((b-6(b))
0for all b in
B
andTr(a12)
O.
PROOF.
Let
x be a separable idempotent forBj
overB.
Thenxu
ux for each u inBj].
Hence xj jx; thatis,
a11(1(R)j)_a12(11)+a21(jj)-a22(J1).
Equating correspondingcoef-ficients,
we have(a11)
-a22,
a12
(a21);
thatis,
a22
-(a11)
and
a21
(a12)
for62
I.
Also,
bx xb for all b inB,
sob12(b-(b))
0. Thus xa11(11)+a12(1j)+(a12)(J(R)1)-(a11)(j(R)j)
with
a12(b-(b))
0.Moreover,
by the second condition of a separable idempotent,a11+(a12+(a12))j+(a11)
I,
soTr(a11)
andTr(a12)
O.
Conversely, it is straightforwardto
verify that any x satisfying all equations as given is a separable idempotent.THEOREM
3.2.
Bj is a separable extension over B if and only ifthere is an element c in
B
such thatTr(c)
I.
PROOF.
The necessity is a consequence of Lemma3.1.
For thesuf-ficiency, if
Tr(c)
I,
we takea11
c,
a12
a21
0. Thena11(11)-(a11)(jj)
is a separable idempotent for Bj by Lemma3.1.
Thus Bjis a separable extension over
B.
Using Theorem
3.2,
we can obtain a characterization of a separableextension
Bj
over B whenChar(A)
2.THEOREM
3.3.
AssumeChar(A)
2.Then, Bj
is a separableexten-sion over
B
if and only if B is a Galois extension overA.
PROOF.
Let
B
be a Galois extension overA.
Corollary1.3
onP.
85
in
3
implies thatTr(c)
for some c inB.
Thus Bj is a separableextension over B by Theorem
3.2.
Conversely, by Theorem3.2
again, there exists an c inB
such thatTr(c)
I,
so(c+(c))
I.
Byhypo-thesis,
Char(A)
2,
(c)
(-c) =-(c),
soc-(c)
I.
Hence theideal generated by
(b-(b))
/
b inB)=
B.
This implies thatB
isGalois over A by the
statement
5
in Proposition 1.2 onP.
81
in3.
Let
us recall that the theorem of Parimala and Sridharanif and only if
BAB[J
M2(B),
a matrix algebra over B of order 2. We are goingto
improve it without the assumption that 2 is a unit inA.
THEOREM
3.4.
If B is Galois overA,
thenBABJ
M2(B
).
PROOF.
IfB
is Galois overA,
there exists an c inB
such thatTr(c)
(3,
Corollary1.3,
P.
85).
HenceBKjl
is a separable ex-tension overA
by Theorem3.2.
ButB
is also a separable extensionover A by Proposition 1.2 in
3],
so the transitiveproperty
ofsepar-able extensions
([4],
Proposition2.5)
implies thatBj
is a separable A-algebra.Moreover,
we claim that(I)
B[j]
is an Azumaya algebraover
A,
and(2)
B
is a maximal commutative subalgebra ofBj.
The proof of these facts was given in[7].
For completeness, we give an outline here. Forpart
(I),
it sufficesto
show that A is thecenter
of Bj]. Clearly, A is contained in the
center.
Now,
let b+b’j be inthe
center.
Then j(b+b’j) (b+b,j)j and c(b+b’j) (b+b’j)c for each c inB.
Equating coefficients of the basis1,j}
in the above equations,we have that b is in A and b’ 0 by
Statement
5
in Proposition 1.2 onP.
81
in3].
Forpart
(2),
to
show that B is a maximal commutative subalgebra ofB[j]
isto
show that thecommutant
of B inB[j]
isB.
The computation is similar
to
part(I).
Moreover,
noting thatB
is separable overA,
we then concludethat
BA(BjS)
HomB(BjS,Bj]
by Theorem5.5
onP.
65
in3,
and this implies thatBABJ]
_
M2(B),
where(BjS)
is the opposite ring.In
7],
the sufficiency of the Parimala and Sridharan theorem was shown by a different method from[5.
Now we slightly improve thestatement
without the assumption that 2 is a unit inA.
PROOF.
Since BCj3 is a separable extension overB,
there existsan element c in
B
such thatTr(c)
by Theorem3.2.
Hence these-quence B-*A-0 is
exact
under thetrace map.
But A
is projective overA,
so the sequence splits, and thenA
is an A-direct summand ofB.
Byhypothesis,
BAB[J
M2(B
which is an Azumaya B-algebra, so BCj isan Azumaya A-algebra
(3],
Corollary1.10, P. 45).
ThereforeB
is Galois overA
by using the sameargument
as given in7.
In
Theorem3.5,
the hypothesis thatBAB[J
]
=
M2(B)
can be replacedby that
AB[J
is an Azumaya B-algebra with the se proof.4.
.PEGIL
PBLE
UAT.RNION
ALGEBS.
Theorem
3.5
tells us thatB
is an Azumaya A-algebra such thatM2(B)
whenB
is Galois overA.
In
this section, we arego-ing
to
discuss generalized quaternion algebrasBj
in which 2 is aunit in
A
whenB
is projective and separableover A.
With a similarargument as given in Lemma
3. I,
we haveM
4.1.
The elementa11(11)+a12(1j)+a21(J1)+a22(jj)
inA]AAJ]
is a separable idempotent for Aj3 if and only if(I)
a22
-a11
such that 2a11
I,
and(2)
a21
a12
such that 2a120.
THE0M
4.2.
The A-algebra A[j] is separable if and only if 2 is a unit in A.PROOF.
The necessity is clear byLemma 4.1;
the sufficiency is immediate because(I/2)
(11-jj) is a separable idempotent.Now we give a characterization of
B[j
in which 2 is a unit whenB is projective and separable over
A.
PROOF.
Let
2 be a unit inA
and let c be(I/2).
ThenTr(c)
I/2+I/2
I,
and henceB[j
is separable overB
by Theorem3.2.
By hypothesis,B
is projective overA,
so
B[j] is left projective overA (for BCj
is left projective overB).
HenceB[j
is left projectiveover
A[j]
([3],
Proposition2.3, P.
48).
Wenext
claim thatB[j
is also right projective overA
[j.In fact,
BAAJl--
B[j
defined by(b1+b’j)
bb’j for all b and b’ inB
is an isomorphism asright
Aj3-modules.
But B
is projective overA,
soBAA[J]
is right projective over A[j. This proves that B[j] is right projective over A[j]. ThusB[J]A(B[j)
is projective as AjJ-A[-module. SinceB[j]
is a direct summand ofBCJA(B[j)
as aB[JA(Bj)-module
(for B[j
is separable overA),
B[j is projective as a A[j-Aj-mo. dule.Conversely,
to
show that 2 is a unit inA,
it sufficesto
show thatA[j
is a separable A-algebra by Theorem4.2.
Since B[j is aseparable extension over
B, Tr(c)
for some c inB
by Theorem3.2.
Hence
Tr:
B-,A-0 isexact.
We
claim thatTr
induces anexact
se-quence:
Bj-A[j-@0
asA[j1-Aj-modules.
We
define:
B[j]-A[j3-0
by(b+b’j)
Tr(b)+Tr(b’)j.
Clearly, is an additivegroup
homomorphism.Moreover,
fora,a’
inA,
(b+b’ j)
(a+a’
j)(ba-b’a’)+(ba’+b’a)j,
so((b+b’j)(a+a’j))
Tr(ba-b’a’)+Tr(ba’+b’a)j
(aTr(b)-a’Tr(b’))+(a’Tr(b)+aTr(b’))
j.Also,
(b+b’j)(a+a’j)
(Tr(b)+Tr(b’)j)(a+a’j)((b+b’j)(a+a’j)).
Thusis a right
A[j-homomorphism.
Similarly, by noting thatTr
I+6
and that
(Tr)6
Tr
6(Tr),
it is straightforwardto
verify that issequence
:
Bj--A[jI-O splits as Aj-Aj-modules. Thus Aj isan A[j]-direct summand of B[j. Now by hypothesis,
Bj
is Ajl-pro-jective, soBCJA(Bj)
isACJAACj-projective
where (Bj3) isthe opposite algebra of
B[j.
By hypothesis again,B[j3
is separableover
A,
soBj
is projective overACJAAJ3.
Therefore,
theAj]-direct summand A[j of B[j] is also projective over
AJ(R)AA].
Thisproves that
Aj]
is separable overA,
and so 2 is a unit inA
by Theo-rem4.2.
5
EXAMPLES.
This section includes several examples
to
illustrate our results.(I)
Let Z
be the ring of integers, andZxZ (_-
B)
the ring of direct product ofZ
under the componentwise operations. Define:
ZxZ-ZxZ
by
(a,a’)
(a’,a)
fora,a’
inZ.
Then is an automorphism group of order 2 and{(a,a)
/
a inZ
(=
A)
is the subring ofZxZ
of the fixedelements under
.
ImbedZ
inZxZ
bya-(a,a).
Then we have(a)
ZxZ
is a free A-module with a basis{(I,0),(0,I).
(b)
ZxZ
is separable overZ.
(c)
(ZxZ)
j3
is a separable extension overZxZ
becauseTr((1,0))
(I,0)+(0,I)
(1,1)
by Theorem3.2.
(d)
Z[j is not separable overZ
because 2 is not a unit inZ
by Theorem4.2.
(e)
(ZxZ) gj
isnot
projective over Zj] because 2 isnot
a unitin
Z
by Theorem4.3.
(2)
Let
Z(3
be the local ring ofZ
at the prime ideal(3).
Re-place
Z
byZ(3
in Example(I).
Then we have(a)
2 is a unit inZ(3
).
(c)
(Z(3)xZ(3))j]
is projective overZ(3)[jl
by Theorem4.3.
(3)
ZxZ
andZ(3)xZ(3
in Example(I)
and Example(2)
are Galoisover
Z
andZ(3
respectively by using Proposition 1.2 onP.
64
in[3,
SinceTr((3,-2))
(3,-2)+(-2,3)
(1,1)
which isnot
in any maximal ideal ofZxZ
orZ(3)xZ(3
).
Thus(ZxZ)(R)z(ZXZ)[j
M2(ZxZ)
and(Z(3)xZ(3))(R)Z(
(Z(
xZ(3
)[j3)
3)
M2(Z(3)xZ(3))
by Theorem
3.4.
(4)
Let
i be the usual imaginary unit. ThenZ[iN
isnot
separable overZ.
Z[i has an automorphismgroup
{:
(a+bi)
a-bi fora,b
inZ
such that2
andZ
is the fixed ring of6.
Also,
(a)
(Zi)[j
is
not
separable overZ6il,
and(b)
Z[i isnot
Galois overZ.
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Auslander,
M.
andO.
Goldman. The Brauer Group of a CommutativeRing,
Trans.
Amer. Math.
Soc.97 (1960)
367-409.
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Chase,
S., D.
Harrison andA.
Rosenberg. Galois Theory and Galois Cohomology of Commutative Rings,Me.m...Amer.
Math. Soc.52
1965).
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DeMeyer,
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F.
andE.
Ingraham.Separable
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Yok,
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Hirata, K.
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Parimala, S.
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G.
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