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ISSN: 1821-1291, URL: http://www.bmathaa.org Volume 2 Issue 2(2010), Pages 42-49.

SUBORDINATION AND SUPERORDINATION FOR CERTAIN ANALYTIC FUNCTIONS

SAIBAH SIREGAR, MASLINA DARUS AND BASEM A. FRASIN

Abstract. In this article, we investigate results on subordination and super-ordination given by some authors. Motivated by earlier work and by using a method based upon the Briot-Bouquet differential subordination, we prove several subordination results related to the classB(α). For this purpose, a class denoted byB∗

b is defined and some properties are obtained in the open unit disk.

1. Introduction and Definition

LetFandGbe analytic functions in the open unit diskD={z:z∈C,|z|<1}. Iff, F ∈H(D) andF is univalent inDwe say that the functionf issubordinateto F, orFissuperordinatetof, writtenf(z)≺F(z), iff(0) =F(0) andf(D)⊆F(D). In general, given two functions F andG, which are analytic in D, the function F

is said to be subordinate toGin Dif there exists a functionh, analytic in Dwith

h(0) = 0 and |h(z)|<1 f or all z∈D

such that

F(z) =G(h(z)) f or all z∈D.

Let ϕ : C2

C and let h be univalent in D. If p is analytic and satisfies the

differential subordination ϕ(p(z), zp0(z)) ≺h(z) thenp is called a solution of the differential subordination.

The univalent function q is called a dominant of the solutions of the differential subordination, if p≺q. Ifpandϕ(p(z), zp0(z)) are univalent inDand satisfy the

differential superordinationh(z)≺ϕ(p(z), zp0(z)) thenpis called a solution of the differential superordination. An analytic function q is called subordinant of the solution of the differential superordination ifq≺p.

2000Mathematics Subject Classification. 35A07, 35Q53.

Key words and phrases. Analytic function; Differential Subordination; Subordination and

Superordination. c

2010 Universiteti i Prishtin¨es, Prishtin¨e, Kosov¨e. Submitted March, 2010. Published April, 2010.

S. S. was supported by UKM-OUP-FST-2008 (postdoctoral research fellowship from Universiti Kebangsaan Malaysia).

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LetH be the class of functions analytic inDandH[a, n] be the subclass ofH. For

a∈Candn∈N∗ we denote

H[a, n] ={f ∈H(D) :f(z) =a+anzn+· · · }.

LetAdenote the class of functions of the form

f(z) =z+ ∞ X

n=2

anzn, (1.1)

and normalized byf(0) =f0(0)−1 = 0, which are analytic inD. Also, denote

S∗(α) = (

f :f ∈ A,Re zf 0(z) f(z)

!

> α, z∈D; 0≤α <1

)

, (1.2)

and

Sst∗(α) = (

f :f ∈ A,

arg zf 0(z) f(z)

!

< π

2α z∈D; 0< α≤1 )

(1.3)

be the the familiar classes starlike function of order αin D and strongly starlike functions of orderαin D, respectively.

We note that

Sst∗(α)⊂S∗, (0< α≤1), and Sst∗(1) =S∗.

A functionf ∈ Ais said to be a member of the classB(α) if only if

z2f0(z) f2(z) −1

<1−α (z∈D). (1.4)

Note that the condition (1.4) is equivalent to

Re (

z2f0(z) f2(z)

)

> α (1.5)

for someα(0≤α <1) and for allz∈D.

Frasin and Darus [1] have defined the class B(α) and investigate some interesting properties for this class. In this paper we shall give new additional results for functions of the classB(α).

We denote byB∗ the class ofAdefine by

Bb∗= (

Re (

z2f0(z) bf2(z)+

1 b

1 + zf 00(z) f0(z)

−2zf

0(z) f(z) −1

)

>0; z∈D

) (1.6)

andB∗b(α) the class ofAdefine by

B∗

b(α) =

( Re

( z2f0(z)

bf2(z) + 1 b

1 + zf 00(z) f0(z)

−2zf

0(z) f(z) −1

)

> α; z∈D

)

(1.7) whereb∈C=C\ {0}.

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The main objective of the present paper to the aforementioned works is to apply a method based upon the Briot-Bouquet differential subordination and superordina-tion in order to derive several subordinasuperordina-tion and superordinasuperordina-tion results involving analytic functions.

2. Preliminaries

In order to prove our main subordination results, we shall make use of the following known results.

Lemma 2.1. (see[4]) Let the (nonconstant) functionwbe analytic in Dand such that w(0) = 0. If|w(z)|attains its maximum value on circle |z|=r <1 at a point zo∈D, we have

zow0(z) =kw(zo),

wherek≥1 is a real number.

Lemma 2.2. (Miller and Mocanu [6].) Let the functions F and Gbe analytic in the unit disk Dand let

F(0) =G(0). If the functionH(z) :=zG0(z)is starlike inDand

zF0(z)≺zG0(z), then

F(z)≺G(z) =G(0) + Z z

0 H(t)

t dt, (2.1)

The functionGis convex and is the best dominant in (2.1).

Lemma 2.3. (Eenigenburg et. al[5]). Letβ andγ be complex constants. Also let the function hbe convex (univalent) inDwith

h(0) = 1 and Re(βh(z) +γ)>0, (z∈D).

Suppose that the function

p(z) = 1 +p1z+p2z2+. . . .

is analytic inDand satisfies the following differential subordination:

p(z) + zp 0(z)

βp(z) +γ ≺h(z) (2.2)

If the differential equation:

q(z) + zq 0(z)

βq(z) +γ =h(z) (q(0) := 1), (2.3)

has a univalent solutionq, then

p(z)≺q(z)≺h(z)

and q is the best dominant in (2.2) (that is, p(z) ≺ q(z)) for all p(z) satisfying (2.2) and ifp(z)≺ˆq(z)for all p(z) satisfying (2.2), thenq(z)≺ˆq(z)).

Lemma 2.4. (Miller and Mocanu [7]) Let q(z) be convex univalent in the unit disk D and γ ∈ C. Further, assume that Re{γ} > 0. If p(z) ∈ H[q(0),1]∩Q,

with p(z) +γzp0(z)is univalent in

D thenq(z) +γzq0(z)≺p(z) +γzp0(z)implies

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Remark 2.5. The conclusion of Lemma 2.3 can be written in the following form:

p(z) + zp 0(z)

βp(z) +γ ≺q(z) +

zq0(z)

βq(z) +γ ⇒p(z)≺q(z)

Remark 2.6. The differential equation (2.3) has its formal solution given by

q(z) = zF 0(z) F(z) =

β+γ β

H(z) F(z)

β

−γ β,

where

F(z) =

β+γ

Z z

0

{H(t)}βtγ−1dt β1

,

and

H(z) =z.exp Z z

0

h(t)−1 t dt

.

3. Main Result

We begin with the following theorem.

Theorem 3.1. Let the function h be univalent in D, let h and Re(bh(z)) > 0,

z∈D,b∈C=C\ {0}, also let f ∈ A.

a)If

z2f0(z) bf2 +

1 b

1 + zf

00(z) f0(z)

−2zf

0(z) f(z) −1

!

≺h(z), (3.1)

then

z2f0(z)

bf2 ≺h(z). (3.2)

b)If the following differential equation:

q(z) + zq 0(z)

βq(z) +γ =h(z) (q(0) := 1),

has a univalent solutionq(z), then

z2f0(z) bf2 +

1 b

1 + zf

00(z) f0(z)

−2zf

0(z) f(z) −1

!

≺h(z)⇒ z

2f0(z)

bf2 ≺q(z)≺h(z), (3.3) andq is the best dominant in (3.3).

Proof. a) We begin by setting

z2f0(z)

bf2(z) =:p(z), (3.4)

so thatphas the following expansion:

p(z) = 1 +p1z+p2z2+. . . .

By differentiating logarithmically (3.4), we obtain

p(z) +zp 0(z) bp(z) =

z2f0(z) bf2 +

1 b

1 +zf

00(z) f0(z)

−2zf

0(z) f(z) −1

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and the subordination (3.1) can be written as follows:

p(z) +zp 0(z)

bp(z) ≺h(z).

The conclusion of the theorem would follow from Lemma 2.3 by taking

β =b γ= 0.

This evidently completes the proof of Theorem 3.1.

Theorem 3.2. Let f be analytic in D such that f(0) = 0, h be convex univalent

inDand h∈H[0,1]∩Q. Assume that

z2f0(z) bf2 +

1 b

1 + zf

00(z) f0(z)

−2zf

0(z) f(z) −1

!

is univalent function in D, where Re{γ} >0 and b∈C=C\ {0}. If h∈ A and

the subordination

h(z) =q(z) + zq 0(z) βq(z) +γ ≺

z2f0(z) bf2 +

γ b

1 +zf 00(z) f0(z)

−2zf

0(z) f(z) −1

,

holds, then

h(z)≺ z

2f0(z)

bf2(z) implies h(z)≺q(z)≺p(z),

wherep(z) = z 2f0(z)

bf2(z) andhis the best subordinant.

Proof. Our aim is to apply Lemma 2.4. Settingp(z) :=zbf2f20((zz)).

Now we must show that

q(z) +zq0(z)≺p(z) +zp0(z).

By the assumption of the theorem we have

h(z) =q(z) +γzq0(z)≺ z2bff02(z)+

γ b

1 + zff000((zz))

−2zff(0z()z)−1=p(z) +γzp0(z).

Thus in view of Lemma 2.3 and Lemma 2.4, h(z)≺q(z)≺p(z) and his the best

subordinate.

If we combine Theorem 3.2 together with Theorem 3.1, then we obtain the differ-entialsandwich-type theorem.

Next, applying Lemma 2.1, we prove the following:

Theorem 3.3. Let f ∈ A. If

z2f0(z) bf2 −1 +

1 b

1 + zf 00(z) f0(z)

−2zf

0(z) f(z) −1

< 1−α

2α , (z∈D), (3.5)

where 12 ≤α <1 andb∈C=C\ {0},then f ∈ B∗

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Proof. We definew(z) by

z2f0(z) bf2(z) =

1 + (1−2α)w(z)

1−w(z) (w(z)6= 1), (3.6)

we see thatwis regular inDandw(0) = 0. By the logarithmic differentiations, we get from (3.6) that

1 b

1 + zf

00(z) f0(z)

−2zf

0(z) f(z) −1

!

= (1−2α)zw 0(z) 1 + (1−2α)w(z)+

zw0(z)

1−w(z). (3.7)

It follows from (3.6) and (3.7) that

z2f0(z) bf2 +

1 b

1 + zf

00(z) f0(z)

−2zf

0(z) f(z) −1

!

= 1 + (1−2α)w(z) 1−w(z) +

(1−2α)zw0(z) 1 + (1−2α)w(z)+

zw0(z) 1−w(z)

or equivalently,

z2f0(z) bf2 −1 +

1 b

1 +zf

00(z) f0(z)

−2zf

0(z) f(z) −1

!

=2(1−α)w(z) 1−w(z) 1 +

zw0(z)

[1 + (1−2α)w(z)]w(z) !

. (3.8)

Suppose there existzo∈Dsuch that

max |z|<|zo|

|w(z)|=|w(zo)|= 1, (w(zo)6=−1),

and then from Lemma 2.1, we have

zow0(z) =kw(zo),

wherek≥1 is a real number. From (3.8), we have

z2of0(zo)

bf2(z

o)

−1 + 1 b

1 +zof 00(z

o)

f0(z

o)

−2zof

0(z

o)

f(zo)

−1 =

2(1−α)w(zo)

1−w(zo)

1 + zow 0(z

o)

[1 + (1−2α)w(zo)]w(zo)

! ≥

2(1−α)w(zo)

1−w(zo)

zow0(zo)

[1 + (1−2α)w(zo)]w(zo)

≥ (1−α)k

≥ 1−α

which contradicts our assumption (3.5). Therefore|w(z)|<1 holds for allz∈D.

We finally havef ∈ B∗

b(α).

Puttingα=1

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Corollary 3.4. Let f ∈ A. If

z2f0(z) bf2 −1 +

1 b

1 + zf 00(z) f0(z)

−2zf

0(z) f(z) −1

< 1

2, (z∈D). (3.9)

Thenf ∈ B∗

b(

1 2).

Remark 3.5. Settingb= 1in Theorem 3.3, we arrive to Theorem 2.5 obtained by Frasin el. al.,[2].

Theorem 3.6. If f ∈ B∗

b(α),(0≤α <1) andRe(bz+b)>0;z∈D, then

z2f0(z) bf2(z) ≺q(z)

whereq is the best dominant given by

q(z) =1 b

ebz

(−bz)−bΓ(b) + Γ(b,bz)

−1 

,

and

Γ(b,−bz) = Γ(b) +zb·1F1(b,1 +b, bz).

Proof. First of all, we observe that (1.4) is equivalent to the inequality:

z2f0(z) bf2 +

1 b

1 +zf

00(z) f0(z)

−2zf

0(z) f(z) −1

!

−1

<1, (z∈D),

which implies that

z2f0(z) bf2 +

1 b

1 + zf

00(z) f0(z)

−2zf

0(z) f(z) −1

!

≺1 +z.

Thus, in Theorem 3.1, we choose

h(z) = 1 +z,

and note that

Re(bh(z))>0,

when z ∈D , and hsatisfies the hypotheses of Lemma 2.3. Consequently, in the

view of Lemma 2.3 and Remark 2.6, we have

H(z) =z·exp Z z

0

h(t)−1 t dt

,

which, forh(z) = 1 +t, yields

H(z) =zez, (3.10)

and

F(z) =

b Z z

0

{H(t)}b

t

dt 1/b

=

b Z z

0 ebt

t1−b

dt

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By using the software MAPLE,F can be simplified to the following form:

F(z) =−zb−1(−bz)−b−zbΓ(b) +zbΓ(b,−bz) 1/b

. (3.11)

From (3.10) and (3.11), we obtain

q(z) =1 b "

ebz

(−bz)−b(Γ(b) + Γ(b,bz))−1

# .

The proof of Theorem 3.6 is complete.

Acknowledgement: The authors would like to thank the anonymous referee for the informative and creative comments given to the article.

References

[1] B. A. Frasin and M. Darus, On certain analytic univalent function,Int.Jour. Math.and Math. Sci.2001, 25(5): 305-310.

[2] B.A. Frasin, M. Darus and S. Siregar. Some sufficient conditions for univalence and subordi-nation results of certain analytic and univalent functions.Mathematica Cluj-Tome50 (73), (2008) no.1: 39-49.

[3] H. M. Srivastava and A. Y. Lashin, Some applications of the Briot-Bouquet differential sub-ordination,Jour. Ineq. Pure and Appl. Math.2005, 6(2): 1-7.

[4] I.S. Jack, Functions starlike and convex of orderα,J. London Mth. Soc.(2)3, (1971), 469-474. [5] P. Eenigenburg, S.S. Miller, P.T. Mocanu,and M. O. Read, On a Briot-Bouquet differential subordination,General Inequalities 3, pp. 339-348, International Series of Numerical Math-ematics, Vol.64, Birkh¨auser Verlag, Basel, 1983; see alsoRev. Roumaine Math. Pures Appl.

, 1984, 29: 567-573.

[6] S.S. Miller and P.T. Mocanu, Differential Subordinations: Theory and Applications Series on Monographs and Textbooks in Pure and Applied Mathematics (No 225), Marcel Dekker, New York and Basel, 2000.

[7] S.S. Miller and P.T. Mocanu,Subordinations of differential superordinations, Complex Vari-ables, 48(10)(2003), 815-826.

Saibah Siregar and Maslina Darus School of Mathematical Sciences Faculty of Science and Technology Universiti Kebangsaan Malaysia Bangi 43600 Selangor D.E., Malaysia

E-mail address:[email protected]

E-mail address:[email protected] (corresponding author)

Basem A. Frasin

Department of Mathematical Sciences Al al-Bayt University

P.O. Box 130095, Mafraq, Jordan

References

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