Published online February 6, 2015 (http://www.sciencepublishinggroup.com/j/acm) doi: 10.11648/j.acm.s.2015040102.15
ISSN: 2328-5605 (Print); ISSN: 2328-5613 (Online)
Linear fractional multi-objective optimization problems
subject to fuzzy relational equations with the max-average
composition
Z
.
Valizadeh-Gh
1, *,
E
.
Khorram
2 1Department of Mathematics , Roudehen Branch , Islamic Azad University , Roudehen , Iran 2
Faculty of Mathematics and Computer Science, Amirkabir University of Technology, Tehran , Iran
Email address:
[email protected] (Z . Valizadeh-Gh)
To cite this article:
Z . Valizadeh-Gh, E . Khorram. Linear Fractional Multi-Objective Optimization Problems Subject to Fuzzy Relational Equations with the Max-Average Composition. Applied and Computational Mathematics. Special Issue: New Advances in Fuzzy Mathematics: Theory, Algorithms, and Applications. Vol. 4, No. 1-2, 2015, pp. 20-30. doi: 10.11648/j.acm.s.2015040102.15
Abstract:
In this paper , linear fractional multi-objective optimization problems subject to a system of fuzzy relational equations (FRE) using the max-average composition are considered . First , some theorems and results are presented to thoroughly identify and reduce the feasible set of the fuzzy relation equations . Next , the linear fractional multi-objective optimization problem is converted to a linear one using Nykowski and Zolkiewski's approach . Then , the efficient solutions are obtained by applying the improved -constraint method . Finally , the proposed method is effectively tested by solving a consistent test problem .Keywords
:
Fuzzy Relational Equation, The Max-Average Composition,Linear Fractional Multi-Objective Optimization Problems, The Improved -Constraint Method
1. Introduction
Multi-objective programming problems play an important role in the optimization theory . Generally speaking , the objective functions of a multiple objective programming (MOP) problem may conflict with one another . Thus , the notion of Pareto optimality or efficiency associated with the feasible region has been introduced . There are several methods to find the efficient solutions of the MOP in the literature . For details see [6].
An optimization problem with multiple objective functions and fuzzy relational equation (FRE) or fuzzy relational inequality (FRI) constraints is among interesting issues in this field . Wang [23] considered a multi-objective mathematical programming problem with constraints defined by the FRE with the max-min composition . The nonlinear multi-objective optimization problems subject to FRE with the max-min and max-average compositions were studied in [16] and [13,14] , respectively . They developed specific reduction procedures to simplify a given problem , according to the special structure of the solution set , and further proposed some genetic algorithms to attain efficient
solutions . Many researchers have considered the problem and developed the theoretical topics , solution procedures and various applications [1-5,8-12,17,18,20,22,24-26].
Here , a linear fractional multi-objective optimization problem subject to the FRE with the max-average composition is considered . Since the feasible domain of this problem is generally non-convex , traditional methods may have difficulty in deriving the set of efficient solutions . Nevertheless, here, an efficient method is proposed to obtain the efficient solutions of the linear fractional multi-objective optimization problem (LFMOP) subject to the FRE, exactly and completely, using special structures of the feasible domain and the objective functions . Indeed, the linear fractional multi-objective optimization problem is converted to a linear one using Nykowski and Zolkiewski's approach [19] . Then , the efficient solutions are obtained by applying the improved -constraint method .
with fuzzy relation equation constraints. To illustrate the procedure , a numerical example will be provided in Section 5 that will be followed by our concluding remarks in Section 6.
2. Preliminaries
In this section , some definitions and theorems are presented which are basic in the literature [6]. Consider ,
min ∈ = = , … , (2.1)
where : ℛ ⟶ ℛ is a nonlinear vector function and ⊆
ℛ is the set of feasible solutions . Moreover , ∈ and =
∈ ℛ : ∃x ∈ χ, z = , … , ! are called a solution vector and the criterion space , respectively .
Notation 2.1. Let x, y ∈ ℛ# ,
≦ % ⟺ '≤ %', for ) = 1, … , +.
≤ % ⟺ ≦ % and ≠ %. < % ⟺ '< %', for ) = 1, … , +.
Letz , z/∈ Z , we sayz dominatesz/andz is non-dominated if and only if z ≤ z/and there is no z ∈ Z that dominates z , respectively . Moreover , we say1 ∈ is an efficient solution to problem (2.1) if and only if there is no
x ∈ χ such that ≤ 1 .
In the remainder of the present section , some definitions , notations and theorems from different topics are reviewed which are needed in the latter sections . Let2 =
31, … , 45 ,6 = 31, … , +5 ,7 = 31, … , 85 , 9 = :;<'=>× # and
@ = @< >× , ;<', @<∈ [0,1], for all i ∈ I and j ∈ J. A system
of fuzzy relation equations with the max-average composition can be considered as
9GHI = @, (2.2)
where the operator “GHI” is defined as follows :
;<GHI = max'∈KHLM/N M, O ∈ 2, (2.3)
and ;< is the i-th row of A.
Notation 2.2. For the i-th constraint (2.2) , we set
JQ = Rj ∈ J: a<' < 2bQU,
JQ/= Rj ∈ J: a<' = 2bQU,
JQV= Rj ∈ J: a<' > 2bQU,
X O = R) ∈ 6: 2@<− ;<' ≤ 1U, O ∈ 2
ℐ ) = 3O ∈ 2: ) ∈ X O 5, ) ∈ 6 χQ= 3 ∈ [0,1] : ;
<GHI = @<5, O ∈ 2
= 3 ∈ [0,1] : 9GHI = @5.
and <are the feasible sets of the problem and the i-th constraint , respectively . When is not empty , it is in general
a non-convex and non-singleton set and can be completely determined by a unique maximum and a finite number of minimal solutions [21].
Definition 2.3. [15] . [ ∈ χ is a maximum solution if ≤
[ , for all ∈ , and if ≤ \ implies = \ , for all ∈ ,
\ ∈ is called a minimal solution .
Definition 2.4. [16]. If a value-change in some element(s) of a given fuzzy relation matrix 9 has no effect on the solutions of a corresponding fuzzy relation equations , this value-change is called an equivalence operation.
A traditional approach for solving the MOP is the scalarization techniques that formulate the MOP as a single objective program . Sometimes , the feasible set , , is limited by some new constraints related to objective functions of the MOP and/or some new variables introduced . Here , we utilize a well-known scalarization technique called the -constraint method which was improved by Ehrgott and Ruzika [7]. In this method , the corresponding single program to the MOP (2.1) is ,
min ] − ∑<a ]_<`<N+ ∑<a ]c<`<d
`. e.
< + `<N− `<d≤ <, O ∈ 7 ∖ 3g5
`<N,`<d≥ 0, O ∈ 7 ∖ 3g5
x ∈ χ,
(2.4)
where _<,c<≥ 0 , for all O ∈ 7 ∖ 3g5.
The following results on the improved -constraint method can be found in [7]:
(i) If there is an O ≠ g such that c<− _<< 0 , then problem (2.4) will be unbounded.
(ii) If c − _ ≥ 0 , then there is always an optimal solution of (2.4) such that `<N`<d= 0 , O ≠ g.
(iii) Let _, c ≧ 0 . If [, `̂N, `̂d is an optimal solution of (2.4) , then [ will be a weakly efficient solution of the MOP.
(iv) Let _, c ≧ 0. Let [, `̂N, `̂d be an optimal solution of (2.4) . If [is unique , then [will be a strictly efficient solution of the MOP.
(v) Let _, c > 0 . Let [, `̂N, `̂d be an optimal solution of (2.4) . Then , [ is an efficient solution of the MOP.
We shall assume throughout the paper that c − _ ≥ 0 , and
m, n and p stand for the number of constraints in system (2.2) , the dimension of solution vectors and the number of objective functions of problem (2.1) , respectively .
3. Systems of Fuzzy Relation Equations
Here, the feasible set of systems of fuzzy relation equations is characterized and the corresponding reduced problem will be investigated. It means we consider the characteristics of the solution set of (2.2) , when ∈
[0,1] , that is ,
9GHI = @,
∈ [0,1] , (3.1)
and attempt to simplify the problem by reducing the solution set . System (3.1) can also be considered as ;<GHI = @< ,
is defined by (2.3) . The results which are proven in this section are our contributions .
3.1. Characterization of the Feasible Set
Proposition 3.1. A vector ∈ [0,1] fulfills the i-th constraint if and only if
∀ ) ∈ 6, ' ≤ 2@<− ;<',
∃ )l∈ 6, 'm = 2@<− ;<'m.
(3.2)
Lemma 3.2. If 6<V≠ ∅ then <= ∅ .
Proof. Let )l∈ 6<V . By contraction , if ∈ < then according to (2.3) , '≤ 2@<− ;<' , for all ) ∈ 6 . Thus ,
'm≤ 2@<− ;<'m < 0 .
Corollary 3.3. If <≠ ∅ then 6<V= ∅ .
Lemma 3.4. [12]. Let <≠ ∅ . The maximum solution in
< is <[= : [< , … , [< = where [<
'= min:2@<− ;<', 1= ,
for all ) ∈ 6 .
Proof. <[∈ was shown in [12]. By contraction , we prove that <[is the maximum solution of < . Let ∈
< and )
l∈ 6 such that '_l> [< '_l= min:2@_O −
;<'m, 1 . Thus , 'm > 2@<− ;<'m or '_l> 1 (this case is
impossible , since '_l∈ [0,1] . If 'm > 2@<− ;<'m , we have max'∈K ;<'+ ' > 2@< that is ∉ < .
Notation 3.5. Let <\ ) = : \ )< , … , \ )< = where
) ∈ X O (see Notation 2.2) and
\ ) ] = x2@<− ;<', g = ),
0, g ≠ ),y
< (3.3)
Lemma 3.6. [12]. Let <≠ ∅ .
a . For all ) ∈ X O , <\ ) is a minimal solution in <. b . <= ⋃'∈} <{ \< , [< | .
Definition 3.7.
[ = minQ∈~ <[ (3.4)
\ = maxQ∈~ <\ • O (3.5)
where • = • 1 , … , • 4 and • O ∈ X O for all O ∈ 2 . Lemma 3.8. [12].
a . [ is the maximum solution of (3.1).
b . l⊆ €• , where l denotes the minimal solutions set of , €• = 3\ • ∶ • ∈ ƒ 5 and ƒ = X 1 × … × X 4 .
c . χ = ⋃ [\ • , []„∈… , where ƒ = R• = :• 1 , … , • 4 =∶
• O ∈ X O ,O = 1, … , 4 U .
Lemma 3.9. If there is an O ∈ 2 such that 6<V≠ ∅ then
= ∅ .
Proof. According to Lemma 3.2 , the proof is obvious . Theorem 3.10. = ⋂Q∈~ < .
Proof. Let ƒ = R• = :• 1 , … , • 4 =∶ • O ∈ X O ,O =
1, … , 4U It is sufficient to prove two statements: (1) ⊆ ⋂<∈‡ <and (2)⋂<∈‡ <⊆ .
For (1):
∈ ⟺ ∈∪‰∈Š[\ • , []
⟺ ∃• ∈ ƒ,\ • ≤ ≤ [ ⟺ ∃• ∈ ƒ, ∀g ∈ 6, :\ • =]= 4;<∈‡ : \:• O =< =
] ≤ ]≤ [] = 4O+<∈‡ <[]
⟺ ∃• ∈ ƒ, ∀g ∈ 6, ∀ O ∈ 2, \< :• O =
]≤ ] ≤ [ <
]
⟺ ∃• ∈ ƒ, ∀g ∈ 6, ∀O ∈ 2,
x2@<− ;<], g = • O
0, otherwise ≤ ] ≤ min 2@<− ;<], 1 y
(3.6)
⟺ ∃• ∈ ƒ, ∀g ∈ 6, ∀O ∈ 2,
x2@<− ;<], g = • O
0, otherwise ≤ ] ≤ x2@1, otherwise<− ;<], g ∈ X O yy
⟺ ∀• ∈ 2, ∃• • ∈ X • , ∀g ∈ 6,∀O ∈ 2,
x2@<− ;<], g = • O
0, otherwisey ≤ ] ≤ x2@1, otherwise<− ;<], g ∈ X O y
⟹ ∀• ∈ 2, ∃• • ∈ X • , Let ) = • • ,∀g ∈ 6,∀O = •,
x2@<− ;<], g = )
0, otherwisey ≤ ] ≤ x2@1, 2@<− ;<] 2@<<− ;− ;<]<]≤ 1 > 1y
⟺ ∀O ∈ 2, ∃) ∈ X O , ∀g ∈ 6, \< )
]≤ ]≤ min 2@<− ;<], 1 = [ <
]
(3.7)
⟺ ∀O ∈ 2, ∃) ∈ X O , ∈ { \ )< , [< |
⟺ ∀O ∈ 2, ∈ • { \ )< , [< | '∈} <
⟺ ∀O ∈ 2, ∈ <
⟺ ∈ ‘ < <∈‡
For (2): Like to the previous part, we have:
x ∈ ‘ χQ Q∈~
⟺
⋯ ⟺ 3.7 ⟺ ∀O ∈ 2, ∃)<∈ X O , ∀g ∈ 6,
x2@<− ;<] , g = )<
0, otherwisey ≤ ]≤ x2@1, otherwise<− ;<] , g ∈ X O y
⟺ ∀O ∈ 2, ∃)<= • O ∈ X O , ∀g ∈ 6,
x2@<− ;<] , g = • O
0, otherwisey ≤ ]≤ x2@1, otherwise<− ;<] , g ∈ X O y
x2@<− ;<] , g = • O
0, otherwisey ≤ ] ≤ x2@1, otherwise<− ;<] , g ∈ X O y
⟺ 3.6 ⟺ ⋯ ⟺ ∈
Remark 3.11. If @<= 0 for some O ∈ 2 , it can be shown that
= ∅ .
According to Remark 3.11 and Lemma 3.9 , we shall assume in this section that @ > 0 and 6<V= ∅ , for all O ∈
2 , respectively .
3.2. Problem Reduction
Detection of redundant constraints : Here , we consider the conditions under which a constraint of the problem can be omitted .
Theorem 3.12. Let ≠ ∅ , O , O/∈ 2and O ≠ O/ . If the O -th and O/-th constraints satisfy
1 . X O = X O/ ,
2 . ∀g ∈ X O = X O/ , 2@ <–− ;<–] = 2@<—− ;<—], then the constraint O/ (or O ) is irredundent .
Proof. We show that⋂QaQ—χQ⊆ χQ—. Let ∈ ⋂QaQ—χQbe arbitrary .
∈ ‘ χQ QaQ—
⟺ ∀i ∈ I ∖ 3i/5, ∈ <= • { \ )< , [< | '∈} <
⟺ ∀O ∈ 2 ∖ 3i/5, ∃)<∈ X O , \ )< < ≤ ≤ [<
⟺ ∀O ∈ 2 ∖ 3O/5, ∃)<∈ X O ,∀g ∈ 6, : \ )< < =]≤ ]≤ [< ]
⟺ ∀O ∈ 2 ∖ 3O/5, ∃)<∈ X O ,∀g ∈ 6,
x2@0, otherwise<− ;<'L, g = )< y ≤ ]≤ [< ]= min 2@<− ;<], 1
⟺ ∀O ∈ 2 ∖ 3O/5, ∃)<∈ X O , ∀g ∈ 6,
˜ 0 ≤0 ≤ ]]≤ 1≤ 2@, <− ;<], g ∈ X O ∖ 3)g ∉ X O ,<5,
2@<− ;<'L ≤ ]≤ 2@<− ;<], g = )<
y
⟺ ∀O ∈ 2 ∖ 3O/5, ∃)<∈ X O ,
x ]]= 2@≤ 2@<<− ;− ;<'<], g ∈ X O ∖ 3)<5,
L, g = )<,
y
⟹ O = O , ∃)<– ∈ X O ,
™ ]≤ 2@<–− ;<–], g ∈ X O ∖ R)<–U, 'L–= 2@<–− ;<–'L–, g = )<–,
y
⟺ ∃)<– ∈ X O/ , ™ ]
≤ 2@<—− ;<—], g ∈ X O/ ∖ R)<–U, 'L–= 2@<—− ;<—'L–, g = )<–,
y
⟺ ∃)<– ∈ X O/ , ∀g ∈ 6,
˜
0 ≤ ] ≤ 1, g ∉ X O/ ,
0 ≤ ] ≤ 2@<—− ;<—], g ∈ X O/ ∖ 3)<–5, 'L–= 2@<—− ;<—'L–, g = )<–,
y
⟺ ∃)<– ∈ X O/ ,∀g ∈ 6, : \:)<— <–==]≤ ] ≤ [<— ]
⟺ ∈ • { \ )<— , [<— | '∈} <—
= <—
Example 3.13. Consider ,
š0.7954 0.4927 0.35470.7751 0.2369 0.8448
0.8165 0.5139 0.3759Ÿ GHI = š 0.6391 0.6289 0.6496Ÿ.
Here , we have X 1 = X 3 = 31,2,35 . Computing
<' = 2@<− ;<' , for all O ∈ 2 and ) ∈ 6 results that :
¡ = š0.4827 0.7854 0.92340.4827 1.0209 0.4130 0.4827 0.7854 0.9234Ÿ.
These values of the first and third rows are equal , thus , by applying Theorem 3.12 , the third (or the first) constraint is omitted . By solving the reduced system , we obtain the maximum solution ,[ = 0.4827,0.7854,0.4130 ¢and the minimal solutions as follows:
\: 1,1,1 = = 0.4827,0,0 £,
\: 1,1,2 = = 0.4827,0.7854,0 £,
\: 1,3,1 = = 0.4827,0,0.4130 £.
Detection of fixed components : By the following lemmas , the j-th element of solutions can be fixed and be eliminated from the solution space .
Lemma 3.14. [12]. If for some ) ∈ 6 , <\ ) = 0• or ) ∈ 6</ then the equation i has just one minimum as <\= 0• .
Lemma 3.15. For a constraint , say i , if 6</≠ ∅ , then '= 0 for all ∈ and all ) ∈ 6</ . It means the component(s) j ,
) ∈ 6</ , can be eliminated from the solution space .
Proof. Let ∈ = ⋂]∈‡ ] be arbitrary .
∈ ‘ ] ]∈‡
⟹ ∈ <
⟺ x∀) ∈ 6∃) ∈ 6,, '≤ 2@<− ;<',
'= 2@<− ;<',y
⟹ ∀) ∈ 6</, '≤ 2@<− ;<' = 0,
⟹ ∀) ∈ 6</, '= 0.
Example 3.16. Consider the following feasible system
¤
0.2876 0.0912 0.5763 0.6834 0.5466
0.1917 0.7093
0.4258 0.1485 0.2363
0.6445 0.4579 0.1195
0.6477 0.7245 0.6073
¥ GHI = ¤
0.4214 0.4851 0.3622 0.5664 ¥
0.4236,0,0.2666,0 ¢ , respectively .
Lemma 3.17. Let ≠ ∅ . If there are O ∈ 2 and ) ∈ 6 such that @<= ;<' = 1 , then the j-th element of solutions can be fixed as one and be eliminated from the solution space .
Proof. We have:
χQ = 3x ∈ [0,1]#: max
¦∈§ aQ¦+ x¦ = 2bQ
= Rx ∈ [0,1]#: ∀k ∈ J,aQ¦+ x¦≤ 2, ∃j©∈ J,a
Qª«+ xª«= 2U.
Since ;<], ] ∈ [0,1] , for all g ∈ 6and ;<'= 1 , the set < can be simplified as follows :
χQ= 3 x ∈ [0,1]#: let j©= j aQª+ xª= 2 5
= R x ∈ [0,1]#: x
ª= 2−aQª= 1 U
Example 3.18. Consider ,
š0.4425 1.0000 0.35930.7364 0.3948 0.6834
0.7041 0.4424 0.0197Ÿ 0HI = š 1.0000
0.8346 0.8185Ÿ
By Lemma 3.17, the second element of solutions can be fixed as one and be eliminated from the solution space , since
; /= @ = 1.0000 . The maximum and minimal solutions are [ = 0.9329,1.0000,0.9858 ¢ and
\ = 0.9329,1. 0000, 0¢ , respectively .
Lemma 3.19. Suppose X O = 3)<5 (a singleton set) , for all
O ∈ 2 . If there is a )l∈ 6 such that ℐ )l ≠ ∅ (see Notation 2.2) , then
(1) 2@<m− ;<m'm = 2@<–− ;<–'m , for all Ol, O ∈ ℐ )l . (2) for all ∈ , the )l-th element of solutions can be fixed as 2@<− ;<'m , O ∈ ℐ )l , and the component )l can be eliminated from the solution space .
Proof. (1) If ℐ )l is singleton then Ol= O and the proof is trivial . Now , assume Ol, O ∈ ℐ )l and Ol≠ O . Let =
, … , ∈ be an arbitrary feasible solution . We have :
maxª∈§ :aQª + xª= = 2bQ i = il, i
⟺ ™∃¬̅∀j ∈ J, aQª+ xª≤ 2bQ
Q ∈ J, a<®̅L+ x®̅L = 2bQ
y i = il, i
⟺ ˜∀j ∈ J\3jQ
5, xª ≤ 1 < 2bQ− aQª because j ∉ G i
j = jQ, xª≤ 2bQ− aQª≤ 1
∃¬̅Q∈ J, x®̅L = 2bQ− a<®̅L
y
i = il, i .
Therefore , it should be ¬̅<= )< , for O = Ol, O . On the other hand , by the assumption , we have )<m= )<– = )l . Thus ,
'Lm = 'L–= 'm , that is , 2@<m− ;<m'm = 2@<–− ;<–'m.
(2) By assumptions , the vector e is unique , • =
• 1 , … , • 4 = ) , … , )> . It is sufficient to prove
['= :\ • =' :
['= :\ • ='
⟺ minQ∈~ <['= maxQ∈~ <\:• O = ' = maxQ∈~ <\ )< '
⟺ minQ∈~ :min:2bQ− aQª, 1== = maxQ∈~ x2b0, otherwiseQ− aQª, j = jQ, ,y
⟺ minQ∈ℐ ª:2bQ− aQª= = maxQ∈ℐ ª:2bQ− aQª=.
According to (1) , the last statement is true .
Example 3.20. Consider ,
š0.19490.1759 0.7701 0.11710.0602 0.0195
0.0773 0.9243 0.2973Ÿ GHI = š 0.6242 0.5635 0.7013Ÿ.
By computing 2@<− ;<' , for all i, j , we have X 1 = 325 ,
X 2 = 315 , X 3 = 325 , ℐ 1 = 325 , ℐ 2 = 31,35 and
ℐ 3 = 35 . By Lemma 3.19 , the first and second elements of solutions can be fixed as 0.9510 and
0.4782 , respectively , and can be eliminated from the solution space . The maximum and minimal solutions are [ = 0.9510,0.4782,1.0000 ¢ and
\ = 0.9510,0.4782,0 ¢, respectively.
Corollary 3.21. If there is a ) ∈ 6 such that the values of
2@<− ;<' are equal for all O ∈ 2 , that is:
∃j ∈ J, ∀i , i/∈ I, 2bQ–− aQ–'= 2bQ—− aQ—',
then the j-th element of solutions can be fixed as 2@<− ;<' and be eliminated from the solution space .
According to this corollary , in Example 3.13 the first component of solutions can be fixed as 0.4827 and be eliminated from the solution space . Note that when omitting a column of the coefficient matrix causes a zero row , the corresponding constraint is redundant and should be eliminated from consideration .
Corollary 3.22. If 6</≠ ∅ , for all O ∈ 2 and ⋃ 6<∈‡ </= 6 then
[ = \ = 0 . It means = 30•5 .
Identification of equivalence operation:
Corollary 3.23. [12]. When for some O ∈ 2and ) ∈ 6 ,
) ∉ X O , then the value of ;<' has no effect on the solution space of (3.1) and can be changed to zero . In other words , changing ;<'to zero is an equivalence operation (see Definition 2.4) .
Corollary 3.24. [12]. When for some ) ∈ 6and O , O/∈ 2 ,
2@<–− ;<–'< 2@<—− ;<—' , then the value of ;<—' has no effect
on the solution space of (3.1) and can be changed to zero . In other words , changing ;<—' to zero is an equivalence operation .
Proof. It is sufficient to prove ;<—'+ ' < 2@<— , for all
∈ . Let ∈ be arbitrary . Since max]∈K:;<—]+ ]= =
2@<— , we have ;<—]+ ] ≤ 2@<— , for all g ∈ 6 , thus , ;<—'+ ' ≤ 2@<— . On the other hand , if ;<—'+ '= 2@<— , then
according to the assumption we have ;<–'+ ' = ;<–'+
2@<_/− ;<—'> 2@<– . Hence , max¦∈§:;<—]+ ]= ≥ ;<–M+ ' > 2@<– , which contradicts with ∈ <–and therefore ,
Example 3.25. Consider the following feasible system
š0.1382 0.50780.3844 0.6957 0.62790.8567
0.4504 0.4737 0.9497Ÿ GHI = š 0.7122 0.5978
0.7587Ÿ. (3.8)
Computing <' = 2@<− ;<' , for all O ∈ 2 and ) ∈ 6 results in :
¡ = š1.2862 0.91660.8113 0.4999 0.56770.5677 1.0670 1.0438 0.5677Ÿ.
According to Corollary 3.23, changing ; , ;V and ;V/ to zero is an equivalenceoperation , since 1 ∉ X 1 = 32,35 ,
1 ∉ X 3 = 335$ and 2 ∉ X 3 . Additionally , by Corollary 3.24 , the value of ; /has no effect on the solution space of (3.8) and can be changed to zero (since ¡/= 0.9166 >
¡//= 0.4999) . Thus , the system converts to
š0.0000 0.00000.3844 0.6957 0.62790.8567
0.0000 0.0000 0.9497Ÿ GHI = š 0.7122
0.5978 0.7587Ÿ.
By solving the reduced system , we obtain the maximum solution ,
[ = 0.8113,0.4999,0.5677 £,
and the minimal solutions as follows:
\: 3,1,3 = = 0.8113,0,0.5677 £,
\: 3,2,3 = = 0,0.4999,0.5677 ¢,
\: 3,3,3 = = 0,0,0.5677 ¢.
4. Linear Fractional Multi-objective
Optimization Problems Subject to
Fuzzy Relational Equations
Here , we consider
min = ´µ–¶ ·–¶ , … ,
µ¸¶ ·¸¶¹
s. t. AoHIx = b
x ∈ [0,1]#
(4.1)
where 7] = º]£ + º]l , »] = ¼]£ + ¼]l , g = 1, … , 8 ,
8 ≥ 2 , º]£ = º] , … , º] ∈ ℛ , ¼]£ = ¼] , … , ¼] ∈ ℛ ,
º]l and ¼]l are two constant numbers and GHI is the
max-average composition . Using the improved -constraint method , we try to find the efficient solutions .
First , some assumptions and results are mentioned on the characteristic of (4.1) . We denote by ½ , the set of all efficient solutions of (4.1) , that is
½= 3 ̅ ∈ [0,1] : ∄ ∈ , ≤ ̅ 5 ,
which is non-empty regarding Assumptions 4.1 .
Assumptions 4.1. Let
1 . 7] and »] be continuous real valued functions on
= 3 ∈ [0,1] : 9G¿ = @5 .
2 . »] be positive for all g ∈ 7 = 31, … , 85 and all ∈ . Clearly , the generality of the problem is not to be lost by this assumption .
3 . be a non-empty and compact set in ℛ .
4 . º]£and¼]£ be the k-th row of À = :º<'= × and Á =
:¼<'= × , respectively .
5 . Á ∈ [0,1] × and |À| = :ú<'Ã= ∈ [0,1] × .
6 . Àl= :ºl, … , ºl= ∈ [−1,1] × and Ál= :¼l, … , ¼l= ∈
[0,1] × .
Definition 4.2. Problem (4.1) is called incomplete , if there is a gl∈ 7 such that ¼]£m= 0• ∈ ℛ .
Definition 4.3. The objective functions of (4.1) are in conflict if l∩ /l∩ … ∩ l= Å , where ]l , g = 1, … , 8, denotes the set of optimal solutions for the problem
min ] =ÆÈÇÇ : ∈ ,»] > 0!,
and is a nonempty and compact set in ℛ .
Now , we deal with Theorems 4.4 – 4.5 which are similar to those of Nykowski and Zolkiewski [19].
Theorem 4.4. Suppose ̅ ∈ ½ . 1 . If ] =ÆÈÇ
Ç > 0 , for all g ∈ 7 and all ∈ then
̅ ∈ É where
É= argmin Γ = 7 , … , 7 , −» , … , −» : ∈ !
= 3 ̅ ∈ [0,1] : ∄ ∈ ,Γ ≤ Γ ̅ 5.
That is ½ ⊂ É . 2 . If ] =ÆÈÇ
Ç < 0 , for all g ∈ 7 and all ∈ then
̅ ∈ Í (that is ½ ⊂ Í) where Î= argmin
RÏ = :7 , … , 7 , » , … , » =: ∈ U = 3 ̅ ∈ [0,1] : ∄ ∈ ,Λ ≤ Λ ̅ 5.
Proof. 1. Let ̅ ∉ É , that is , there is an l∈ such that
Γ l ≤ Γ ̅ . Then , there is a non-negative vector ¼ ∈
ℛ/ such thatΓ ̅ = Γ
l + ¼ . Thus ,
] ̅ =ÆÈÇÇ ̅̅ =ÈÆÇ mÇ mdÑNÑÒÓÇÇ ≥ÈÆÇ mÇ m = ] l ,
g = 1, … , 8.
Additionally , there is an ` ∈ 7 such that ¼Ô+ ¼ NÔ>
0 , and Ô ̅ > Ô l . Therefore , ̅ ≥ l , that is , ̅ ∉ ½ .
2 . Let ̅ ∉ Í , that is , there is an l∈ such that Λ l ≤
Λ ̅ . There is a non-negative vector ¼ ∈ ℛ/ such that
Λ ̅ = Λ l + ¼ . Thus , for g ∈ 7 ,
] ̅ =»7] ̅ ] ̅ =
7] l + ¼]
»] l + ¼ N]≥
7] l
1
»] l + ¼ N]≤
1
»] l and 7] l < 0
⟹ » 7] l
] l + ¼ N]≥
7] l
»] l .
Therefore ,
] ̅ ≥» 7] l ] l + ¼ N]≥
7] l
»] l = ] l .
Similar to part (1) , it can be shown that ̅ ∉ ½which is a contradiction .
Theorem 4.5. Suppose ̅ ∈ ½ . If ] =ÆÈÇÇ > 0, for
g ∈ 31, … , ℎ5 and ] =ÆÈÇÇ < 0 , for g ∈ 3ℎ +
1, … , 85 (for all ∈ ) then ̅ ∈ × where
×= argmin3Φ : ∈ 5 = 3 ̅ ∈ [0,1] : ∄ ∈
, Φ ≤ Φ ̅ 5, where
Φ = 7 , … , 7 , −» , … , −»Ù , »ÙN , … , » .
That is ½ ⊂ × .
Proof. Let ̅ ∉ × , that is , there is an l∈ such that
Φ l ≤ Φ ̅ . Thus , there is a non-negative vector ¼ ∈
ℛ/ such that Φ ̅ = Φ
l + ¼ . Similar to Theorem
4.4 , the proof can be completed .
Remark 4.6. Theorems 4.4 and 4.5 can also be applied on an incomplete linear fractional multi-objective problem .
Remark 4.7. According to the mathematical programming theory , some constant values can be added to each objective function in (4.1), with no effect on the optimal solutions set . This means that ;ÚÛ4O+RÜ = : +
¼ , … , + ¼ : ∈ U = ½ where :¼ , … , ¼ = ∈
ℛ . Therefore , we are always able to consider the equivalent MOP problem with positive objective functions on instead of the original problem (4.1) , using the following algorithm :
Algorithm 4.8.
1 . Given MOP (4.1) and let > 0 be a small user-defined scalar , say = 10dÝ .
2 . Define a constant vector Þ = :Þ , … , Þ = ∈ ℛ as follows :
Þ]= ˜
0, If ] > 0, GÚ all ∈ ,
−7ß]
ȧ] + , otherwise,
y
where 7ß] = min ∈ 7] and »ß] = min ∈ »] , for
g ∈ 7 .
3 . The equivalent problem of (4.1) with positive objective functions on is
min ∈ Ü = : + Þ , … , + Þ =. (4.2)
Since there are finitely many objective functions 8 <
∞ , and in the course of the algorithm , two linear programming problems each with a single objective function are solved when there is an ∈ and a g ∈ 31, … , 85such
that ] < 0, Algorithm 4.8 terminates . Moreover , the following lemma shows the efficiency of Algorithm 4.8.
Lemma 4.9. The objective functions of (4.2) are positive on .
Proof. Consider an objective function ] and an l∈ with ] l ≤ 0 . We show that ] l + Þ]> 0 .
] l + Þ]= ] l +dÆßÈßÇÇ+
= ] l +d áQ#áQ#ââÈÆÇÇ +
= ] l +áã¶áQ#â:dÆâÈÇÇ =+
≥ ] l +−7»] l ] l +
= ] l − ] l +
= > 0
Remark 4.10. By Theorem 4.4 , the linear multi-objective problem related to (4.2) is
min∈ ä• = :7 + Þ » , … , 7 + Þ » ,y
y −» , … , −» = (4.3) and we have å⊆ É æ .
Assume that the FRE system (3.1) is simplified as much as possible by the results in Section 3. Let be the reduced feasible set . Using Assumption 4.1, problem (4.3) can be reformulated as
4O+ ∈ ä• = º£+ Þ ¼£ + ºl+ Þ ¼l , …, :º£+
Þ ¼£ + :ºl+ Þ ¼l=, − ¼£ − ¼l, … , −¼£ − ¼l . (4.4)
By omitting the constant values of the objective functions , we have
4O+ ∈ äç = º£+ Þ ¼£ , …, :º£+ Þ ¼£= , −
¼£ , … , −¼£ . (4.5)
Note that Éè= Éæ.
Now , we find Éèby applying the improved -constraint method (2.4) on problem (4.5) . Note that the set of efficient solutions of problem (4.1) , ½ , is a subset of Éè , i.e . ½⊆
Éè⊆ . Hence , to obtain ½ , it is sufficient to solve the
following problem on a smaller feasible set Éèinstead of :
min
∈ éè = = , … , .
Since Éèis a discrete set , a p dimension vector can be related to each individual of Éèin which the k-th element individually evaluates the k-th objective function . The efficient solutions can be obtained by comparing such vectors .
5. Numerical Testing
generated consistent constrained optimization problem .
min s. t. ê
0.4588 0.6620 0.7703 0.3503
0.6620 0.4162 0.8419 0.8329 0.2564 0.0106 0.4363 0.4273 0.8700 0.2649 0.3181 0.1193
ë GHI = ¤
0.5770 0.6786 0.4758 0.7826 ¥ ∈ [0,1]ì,
,
where : ℛì→ ℛV , is defined as
=dl.ìÝlV _ Nl.î Ýì _/Nl. VVï _VNl.îÝìV _ìdl.ðïìVl.ÝVÝ/ _ N l.ñð _/Nl.ðï ì _VN l.ñVÝî _ìNl.îñïð,
/ =l.ïîñ _ dl.ðVññ _/dl./ìï/ _Vl. ì _ Nl.lVìî _/Nl. /î _VNl.îðì/ _ìNl.ì/ñî dl.ïlð _ì dl.ñ/ñÝ ,
V =dl.ñ/Vî _ Nl.ïV// _ Nl.ìÝÝð _/Nl.ïìV/ _V l./Ýìï _/ dl.îïìð _Vdl.l/ ï _ìdl.l/ðîN l.ìðÝñ _ìNl.lïñ/ .
First , according to results in Section 3, we reduce the feasible set of the problem as much as possible . According to Theorem 3.12 and Corollary 3.21, the redundant third and fourth constraints can be ignored and the first component of solutions is fixed to 0.6952 and this component can be eliminated from the solution space as well as the first column of the coefficient matrix from consideration . Thus , the constrained linear fractional optimization problem is reduced to
min ̅
s. t. 0.6620 0.7703 0.0000
0.0000 0.0000 0.8329 GHI = 0.5770 0.6786
∈ [0,1]V,
where the reduced objective function ̅: ℛV→ ℛV, is
̅ = l.î Ýì _ Nl. VVï _/Nl.îÝìV _Vdl.ðïìV l.ñð _ Nl.ðï ì _/N l.ñVÝî _VNl.îñïð ,
̅
/ =dl.ðVññ _ dl./ìï/ _/dl.ïlð _Vl.lVìî _ Nl. /î _/Nl.îðì/ _VNl.ì/ñî dl.ñ/ñÝ ,
̅
V =l./Ýìï¶_l.ìÝÝð¶_ Nl.ïìV/¶_/ dl.îïìð¶_/dl.l/ ï¶_Vdl.l/ðîN l.ìðÝñ¶_VNl.lïñ/ .
The maximum solution and the minimal solutions of the feasible region are [ = 0.4920,0.3837,0.5243 £ , \ =
0.4920,0,0.5243 £ and \/=
0,0.3837,0.5243 ¢ , respectively . Solving the problem
following the method described in Section 4, it is concluded that
̅½= 31 = 0.4920,0.0000,0.5243 £,y
y 1/= 0.0000,0.3837,0.5243 £5,
̅ 1 = −0.3323, −1.9329,0.1715
and
̅ 1/ = −0.4835, −1.3997, −0.4199 .
Therefore , by adding the first component of solutions with the value 0.6952 , the original solutions are obtained as
½= 31 = 0.6952,0.4920,0.0000,0.5243 £,y
y1/= 0.6952,0.0000,0.3837,0.5243 £5,
1 = −0.4091, −1.0945, −0.3075
and
1/ = −0.5116, −0.6457, −0.6140 .
In Figures 1 and 2, different sections of the original feasible region and different sections of the original objective functions with the optimal solutions are shown , respectively . In addition , Figures 3 and 4 show different sections of the reduced feasible region and different sections of the reduced objective functions with the optimal solutions , respectively . The fixed variables and their values are shown in each figure .
Figure 2. The objective function and the optimal solutions of Example 5.1
Figure 4. The reduced objective function and the optimal solutions of Example 5.1
6. Conclusions
In this paper , we obtained the efficient solutions of linear fractional multi-objective optimization problems (LFMOP) subject to a system of fuzzy relational equations (FRE) using the max-average composition . First , some theorems and results were presented to thoroughly identify and reduce the feasible set of the FRE . Then , the LFMOP was converted to a linear multi-objective optimization problem using Nykowski and Zolkiewski's approach . Finally , the efficient solutions were obtained by applying the improved -constraint method . We tested the efficiency of the proposed method by solving a consistent test problem .
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