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University of Mazandaran, Iran

http://cjms.journals.umz.ac.ir

ISSN: 1735-0611 CJMS.8(2)(2019), 91-102

Eigenfunction expansion in the singular case forq−Sturm-Liouville operators

Bilender P. Allahverdiev1 and H¨useyin TUNA 2

1 Department of Mathematics, S¨uleyman Demirel University, 32260

Isparta, Turkey

2 Department of Mathematics, Mehmet Akif Ersoy University, 15030

Burdur, Turkey

Abstract. In this work, we prove the existence of a spec-tral function for singularq−Sturm-Liouville operator.

Fur-ther, we establish a Parseval equality and expansion for-mula in eigenfunctions by terms of the spectral function.

Keywords: q−Sturm-Liouville operator, singular point, Parseval equal-ity, spectral function.

2000 Mathematics subject classification: 33D15, 34L10,39A13, 34L40.

1. Introduction

q−calculus, roughly speaking, is calculus without ordinary limits. It allows to deal with sets of not differentiable functions if the classical derivative is replaced with the q−derivative operator. It has a lot of applications in different mathematical areas, such as number theory, orthogonal polynomials, fractal geometry, combinatorics, the calculus of variations, mechanics, orthogonal polynomials, statistic physics, theory of relativity and quantum theory. For a general introduction to the

1Corresponding author:H¨useyin TUNA [email protected]

Received: 11 April 2018 Revised: 04 June 2018 Accepted: 20 June 2018

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q−calculus we refer the reader to the references [1-2, 5,7-9,12-13,17-18, 21-22, 25, 27].

In mathematics, eigenfunction expansions theorems are important for solving varies problems. Specially, whenever we seek a solution of a par-tial differenpar-tial equation by the Fourier method, we lead to the problem of expanding an arbitrary function as a series of eigenfunctions. There are a lot of studies about eigenfunction expanding problems (see [2-9, 14-15, 19-20, 23, 28]).

It is clear thatq−difference equations ariseq−analogues of differential equations. In this paper, we considerq−analogue of the Sturm-Liouville equations. Recently, in [11], the Titchmarsh-Weyl theory of Sturm-Liouville equations was extended to the case ofq−Sturm-Liouville

equa-tion

1

qDq−1Dqy(x) +u(x)y(x) =λy(x),

on an interval [0, a), where 0 x a ≤ ∞. In [11], Annaby et al. defineq−limit point andq−limit circle singularities. Using Titchmarsh’s

technique, they give sufficient conditions that the singular points are in a limit point case and derive the eigenfunction expansions.

In this paper, we prove the existence of a spectral function for singular

q−Sturm-Liouville operators on semi-unbounded interval. A Parseval equality and an expansion formula in eigenfunctions are established.

2. Preliminaries

Now, we recall some necessary fundamental concepts of quantum anal-ysis. Following the standard notations in [22],[10], let q be a positive number with 0< q < 1, A⊂Rand a∈A. A q−difference equation is an equation that containsq−derivatives of a function defined onA.Let

ybe a complex-valued function onA.Theq−difference operator Dq,the

Jackson q−derivative is defined by

Dqy(x) =

y(qx)−y(x)

qx−x for allx∈A\ {0}.

Note that there is a connection between q−deformed Heisenberg un-certainty relation and the Jackson derivative on q−basic numbers (see [26]). In the q−derivative, as q 1,the q−derivative is reduced to the classical derivative. The q−derivative at zero is defined by

Dqy(0) = lim n→∞

y(qnx)−y(0)

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if the limit exists and does not depend onx.A right-inverse toDq, the

Jackson q−integration is given by

Z x

0

f(t)dqt=x(1−q)

X

n=0

qnf(qnx) (x∈A),

provided that the series converges, and

Z b

a

f(t)dqt=

Z b

0

f(t)dqt−

Z a

0

f(t)dqt (a, b∈A).

The q−integration for a function over [0,∞) defined in [16] by the for-mula

Z

0

f(t)dqt=

X

n=−∞

qnf(qn).

A functionf which is defined on A, 0∈A, is said to be q−regular at zero if

lim n→∞f(xq

n) =f(0),

for everyx∈A.Through the remainder of the paper, we deal only with functionsq−regular at zero.

Iff and g areq−regular at zero, then we have Z a

0

g(t)Dqf(t)dqt+

Z a

0

f(qt)Dqg(t)dqt=f(a)g(a)−f(0)g(0).

LetL2q(0,∞) be the space of all complex-valued functions defined on (0,∞) such that

∥f∥:=

Z

0

|f(x)|2dqx

1/2 <∞.

The spaceL2q (0,∞) is a separable Hilbert space with the inner product

(f, g) :=

Z

0

f(x)g(x)dqx, f, g∈L2q(0,∞)

(see [11]).

Theq−Wronskian ofy(x), z(x) is defined to be

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3. Main Results

Let us consider theq−Sturm-Liouville equations

1

qDq−1Dqy(x) +u(x)y(x) =λy(x), (3.1)

with the boundary condition

y(0, λ) cosβ+Dq1y(0, λ) sinβ = 0, β∈R, (3.2)

whereλis a complex eigenvalue parameter,u is a real-valued functions defined on [0,∞) and continuous at zero andu∈L1

q,loc(0,∞).

Denote by ϕ(x, λ), the solution of the system (3.1) subject to the initial conditions

ϕ(0, λ) = sinβ, Dq−1ϕ(0, λ) =cosβ. (3.3)

Further, we adjoin to problem (3.1)-(3.2) the boundary condition

Dq−1y q−n, λ

sinα+y q−n, λcosα= 0, α∈R, n∈N. (3.4) It is clear that the problem (3.1), (3.2), (3.4) is a regular problem for a

q−Sturm-Liouville equation.

In [10], the authors prove that the boundary value problem (3.1) with the boundary conditions (3.2), (3.4) has a compact resolvent, thus it has a purely discrete spectrum.

Letλm,q−n denote the eigenvalues of this problem and byym,q−n(x) = ym,q−n x, λm,q−n

the corresponding eigenfunctions which satisfy the conditions (3.3). Iff(.) is areal valued function,f(.)∈L2q(0, q−n) and

α2m,q−n = Z q−n

0

y2m,q−n(x)dqx,

then we have

Z q−n

0

f2(x)dqx=

X

m=−∞

1

α2m,q−n

(Z q−n

0

f(x)ym,q−n(x)dqx )2

. (3.5)

which is called the Parseval equality (see [10]).

Now, let us define the nondecreasing step functionϱq−n on [0,∞) by

ϱq−n(λ) =   

Pλ<λm,q−n<0 1

α2 m,q−n

, forλ≤0

P

0≤λm,q−n<λ 1

α2 m,q−n

forλ≥0.

Then equality (3.5) can be written as

Z q−n

0

f2(x)dqx=

Z

−∞F

2(λ)

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where

F(λ) =

Z q−n

0

f(x)y(x, λ)dqx.

We will show that the Parseval equality for the problem (3.1), (3.2) can be obtained from (3.6) by letting n → ∞. For this purpose, we shall prove a lemma.

Lemma 3.1. For any positiveκ,there is a positive constant Υ = Υ (κ)

not depending onq−n such that

κ

−κ

ϱq−n(λ) =

X

−κ≤λm,q−n<κ

1

α2

m,q−n

=ϱq−n(κ)−ϱq−n(−κ)<Υ. (3.7)

Proof. Let sinβ ̸= 0.Since ϕ(x, λ) is continuous at zero, by condition

ϕ(0, λ) = sinβ,there is a positive numberkand near by 0 such that

1

k

Z k

0

ϕ(x, λ)dqx

2 > 1

2sin

2β. (3.8)

Let us definefk(x) by

fk(x) =

1

k, 0≤x < k 0, x > k. .

From (3.6) and (3.8), we get

Z k

0

fk2(x)dqx = 1

k =

Z

−∞

1

k Z k

0

ϕ(x, λ)dqx

2

q−n(λ)

Z κ

−κ

1

k Z k

0

ϕ(x, λ)dqx

2

dϱq−n(λ)

> 1

2sin

2βϱ

q−n(κ)−ϱq−n(−κ) ,

which proves the inequality (3.7).

If sinβ = 0,then we define the function fk(x) by the formula

fk(x) =

1

k2, 0≤x < k

0, x > k. .

So, we obtain the inequality (3.7) by applying the Parseval equality. Now, we recall that the following well-known theorems of Helly’s.

Theorem 3.2 ([24]). Let (wn)n∈N be a uniformly bounded sequence of

real nondecreasing functions on a finite interval a≤λ≤b. Then there exists a subsequence(wnk)k∈N and a nondecreasing function wsuch that

lim

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Theorem 3.3 ([24]). Assume (wn)nN is a real, uniformly bounded, sequence of nondecreasing functions on a finite interval a≤λ≤b, and suppose

lim

n→∞wn(λ) =w(λ), a≤λ≤b.

If f is any continuous function on a≤λ≤b,then

lim n→∞

Z b

a

f(λ)dwn(λ) =

Z b

a

f(λ)dw(λ).

Let ϱ be any nondecreasing function on −∞ < λ < ∞. Denote by

L2ϱ(−∞,∞) the Hilbert space of all functionsf : (−∞,∞) R which are measurable with respect to the Lebesque-Stieltjes measure defined by ϱand such that Z

−∞f

2(λ)(λ)<,

with the inner product

(f, g)ϱ:=

Z

−∞f(λ)g(λ)(λ).

The main result of this paper is the following theorem.

Theorem 3.4. For the q−Sturm-Liouville problem (3.1)-(3.2), there exists a nondecreasing functionϱ(λ)on−∞< λ <∞with the following properties:

(i) If f(.) is a real valued function and f(.)∈L2q(0, q−n),then there exists a function F ∈L2

ϱ(0,∞) such that

lim n→∞

Z

−∞ (

F(λ)

Z q−n

0

f(x)y(x, λ)dqx

)

(λ) = 0, (3.9)

and the Parseval equality

Z

0

f2(x)dqx=

Z

−∞F

2(λ)(λ) (3.10)

holds.

(ii) The integral Z

−∞F(λ)y(x, λ)(λ),

converges to f in L2q(0,∞). That is,

lim n→∞

Z q−n

0

f(x)

Z n

−n

F(λ)y(x, λ)(λ)

2

dqx= 0.

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Proof. Assume that the function(x) satisfies the following conditions. 1)(x) vanishes outside the interval

0, q−ξ, q−ξ< q−n.

2) The functions(x) and Dqfξ(x) are q− regular at zero 3)(x) satisfies the boundary condition (3.3).

If we apply to(x) the Parseval equality (3.6), we obtain

Z q−ξ

0

fξ2(x)dqx=

Z

−∞F

2(λ)(λ) (3.11)

where

F(λ) =

Z q−ξ

0

(x)y(x, λ)dqx. (3.12)

Since y(x, λ) satisfies the system (3.1), we see that

y(x, λ) = 1

λ

1

qDq−1Dqy(x, λ) +u(x)y(x, λ)

.

By (3.12), we get

Fn(λ) = 1

λ Z q−n

0

(x)

1

qDq−1Dqy(x, λ) +u(x)y(x, λ)

dqx.

Since(x) vanishes in a neighborhood of the pointq−n and (x) and

y(x, λ) satisfy the boundary condition (3.3), we obtain

Fn(λ) = 1

λ Z q−n

0

y(x, λ)

1

qDq−1Dqfξ(x) +u(x)(x)

dqx,

by q−integration by parts.

For any finiteκ >0,using (3.6), we have

Z

|λ|>κ

Fn2(λ)q−n(λ)

1

κ2 Z

|λ|>κ

(Z q−n

0

y(x, λ)

1

qDq−1Dqfξ(x) +u(x)(x)

dqx

)2

q−n(λ)

1

κ2

Z

−∞

(Z q−n

0

y(x, λ)

1

qDq−1Dqfξ(x) +u(x)(x)

dqx

)2

q−n(λ)

= 1

κ2 Z q−ξ

0

1

qDq−1Dqfξ(x) +u(x)(x) 2

dqx.

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Z q−ξ

0

fξ2(x)dqx−

Z κ

−κ

Fn2(λ)q−n(λ)

< 1 κ2

Z q−ξ

0

1

qDq−1Dqfξ(x) +u(x)(x) 2

dqx. (3.13)

By Lemma 3.1, the setϱq−n(λ) is bounded. Using Theorems 3.2 and

3.3, we can find a sequence {q−nk} such that the function ϱ

q−nk(λ) converges to a monotone functionϱ(λ).Passing to the limit with respect to{q−nk} in (3.13), we get

Z q−ξ

0

fξ2(x)dqx−

Z κ

−κ

Fn2(λ)(λ)

< 1 κ2

Z q−ξ

0

1

qDq−1(x) +y(x)(x) 2

dqx.

Hence, lettingκ→ ∞,we obtain

Z q−ξ

0

fξ2(x)dqx=

Z

−∞F 2

n(λ)(λ).

Now, let f be an arbitrary real valued function on L2q(0,∞). It is known that there exists a sequence of function {fξ(x)} satisfying the condition 1-3 and such that

lim ξ→∞

Z

0

(f(x)−fξ(x))2dqx= 0.

Let

(λ) =

Z

0

(x)y(x, λ)dqx.

Then, we have

Z

0

fξ2(x)dqx=

Z

−∞F 2

ξ (λ)(λ).

Since Z

0

(1(x)−fξ2(x)) 2d

qx→0 as ξ1, ξ2 → ∞,

we haveZ

−∞(1(λ)−Fξ2(λ)) 2

(λ) =

Z

0

(1(x)−fξ2(x)) 2

dqx→0

asξ1, ξ2→ ∞.Consequently, there is a limit function F which satisfies

Z

0

f2(x)dqx=

Z

−∞F

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by the completeness of the space L2ϱ(−∞,∞).

Our next goal is to show that the function

(λ) =

Z q−ξ

0

f(x)y(x, λ)dqx

converges as ξ→ ∞ toF in the metric of space L2

ϱ(−∞,∞). Letg be another function inL2q(0,∞).By a similar arguments, G(λ) be defined by g.It is clear that

Z

0

(f(x)−g(x))2dqx=

Z

−∞{F(λ)−G(λ)} 2

(λ).

Set

g(x) =

f(x), x∈0, q−ξ

0, x∈ q−ξ,∞ .

Then we have

Z

−∞{F(λ)−Kξ(λ)} 2

(λ) =

Z

q−ξ

f2(x)dqx→0 (ξ→ ∞),

which proves that converges to F in L2ϱ(−∞,∞) as ξ → ∞. This proves (i).

Now, we will prove (ii). Suppose that the functions f(.), g(.)

L2

q(0, q−n), and F(λ) and G(λ) are their Fourier transforms. Then

F∓Gare transforms of f∓g. Consequently, by (3.10), we have

Z

0

[f(x) +g(x)]2dqx =

Z

−∞(F(λ) +G(λ))

2(λ), Z

0

[f(x)−g(x)]2dqx =

Z

−∞(F(λ)−G(λ))

2(λ).

Subtracting the second relation from the first, we get

Z

0

f(x)g(x)dqx=

Z

−∞F(λ)G(λ)(λ) (3.14)

which is called the generalized Parseval equality. Set

(x) =

Z τ

−τ

(10)

where F is the function defined in (3.9). Let g(.) be a vector-function which equals zero outside the finite interval [0, q−µ].Thus, we obtain

Z q−µ

0

(x)g(x)dqx =

Z q−µ

0

Z τ

−τ

F(λ)y(x, λ)(λ)

g(x)dqx

=

Z τ

−τ

F(λ)

(Z q−µ

0

y(x, λ)g(x)dqx

) (λ)

=

Z τ

−τ

F(λ)G(λ)(λ). (3.15)

From (3.14), we get

Z

0

f(x)g(x)dqx=

Z

−∞F(λ)G(λ)(λ). (3.16)

Subtracting (3.15) and (3.16), we have

Z

0

(f(x)−fτ(x))g(x)dqx=

Z

|λ|>τ

F(λ)G(λ)(λ).

Using Cauchy-Schwarz inequality, we obtain

Z

0

(f(x)−fτ(x))g(x)dqx

2

Z

|λ|>τ

F2(λ)(λ)

Z

|λ|>τ

G2(λ)(λ)

Z

|λ|>τ

F2(λ)(λ)

Z

−∞G

2(λ)(λ).

Apply this inequality to the function

g(x) =

(x)−f(x), x∈[0, q−µ] 0, x∈(q−µ,∞) , we get

Z q−µ

0

(f(x)−fτ(x))2dqx≤

Z

|λ|>τ

F2(λ)(λ).

Letting τ → ∞ yields the desired result since the right side does not

depend onµ.

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References

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