R E S E A R C H
Open Access
Nonlocal boundary value problems for
impulsive fractional
q
k
-difference equations
Bashir Ahmad
1*, Ahmed Alsaedi
1, Sotiris K Ntouyas
1,2, Jessada Tariboon
3and Faris Alzahrani
1*Correspondence:
1Nonlinear Analysis and Applied
Mathematics (NAAM) Research Group, Department of Mathematics, Faculty of Science, King Abdulaziz University, P.O. Box 80203, Jeddah, 21589, Saudi Arabia
Full list of author information is available at the end of the article
Abstract
In this paper, we investigate the existence and uniqueness of solutions for a nonlocal boundary value problem of impulsive fractionalqk-difference equations involving a
newqk-shifting operatora
qk(m) =qkm+ (1 –qk)a. Our main results rely on Banach’s contraction mapping principle, Leray-Schauder nonlinear alternative, and Rothe fixed point theorem. Examples illustrating the obtained results are also presented.
MSC: 26A33; 39A13; 34A37
Keywords: quantum calculus; impulsive fractionalqk-difference equations;
existence; uniqueness; fixed point theorem
1 Introduction
The main purpose of this manuscript is to study the existence and uniqueness of solutions for impulsive boundary value problems of fractionalqk-difference equations of the form
⎧ ⎪ ⎨ ⎪ ⎩
tkD
αk
qkx(t) =f(t,x(t)), t∈Jk⊆[,T],t=tk,
tkI
–αk
qk x(t
+
k) –x(tk) =ϕk(x(tk)), k= , , . . . ,m,
atI
–α
q x() =bx(T) +
m l=cltlI
γl
qlx(tl+),
(.)
where =t<t<· · ·<tm<tm+=T,tkD
αk
qk denotes the Riemann-Liouvilleqk-fractional
derivative of orderαkonJk, <αk≤, <qk< ,Jk= (tk,tk+],J= [,t],k= , , . . . ,m, J= [,T],f ∈C(J×R,R),ϕk∈C(R,R),k= , , . . . ,m,tkI
αk
qk denotes the Riemann-Liouville
qk-fractional integral of orderαk> onJk,a,b,cl∈R,γl> ,l= , , , . . . ,m.
The quantum calculus is known as the calculus without limits and provides a descent approach to deal with sets of nondifferentiable functions by considering difference opera-tors. Quantum difference operators play an important role in several mathematical areas such as orthogonal polynomials, basic hyper-geometric functions, combinatorics, the cal-culus of variations, mechanics, and the theory of relativity. The book by Kac and Cheung [] covers many fundamental aspects of the quantum calculus.
In recent years, the topic ofq-calculus has attracted the attention of several researchers, and a variety of new results can be found in the papers [–] and the references therein. In [], the notions ofqk-derivative andqk-integral for a functionf :Jk:= [tk,tk+]→
R, were introduced, and several their properties were obtained. Also, the existence and uniqueness results for initial value problems of first- and second-order impulsive
qk-difference equations were studied. qk-calculus analogues of some classical inte-gral inequalities such as Hölder, Hermite-Hadamard, trapezoid, Ostrowski, Cauchy-Bunyakovsky-Schwarz, Grüss and Grüss-Čebyšev were proved in [].
In [], new concepts of fractional quantum calculus were defined by introducing a new
q-shifting operatoraq(m) =qm+ ( –q)a. After giving the basic properties of the new
q-shifting operator, theq-derivative andq-integral were defined. New definitions of the Riemann-Liouville fractionalq-integral andq-difference on an interval [a,b] were given, and their basic properties were discussed. As applications of the new concepts, exis-tence and uniqueness results for first- and second-order initial value problems for impul-sive fractionalq-difference equations were presented. Recently, the existence of solutions for impulsive fractional q-difference equations with antiperiodic boundary conditions was discussed in [], whereas the existence results for a nonlinear impulsiveqk-integral boundary value problem were obtained in [].
In this paper, we consider a boundary value problem of impulsive fractional qk -dif-ference equations (.) by introducing a newqk-shifting operatoraqk(m) =qkm+ ( –qk)a
and establish some existence results for the new problem. The rest of this paper is orga-nized as follows: In Section , we recall some known facts about fractionalqk-calculus, present an auxiliary lemma, which is used to convert problem (.) into a fixed point prob-lem, and a lemma dealing with useful bounds. Section contains the main results, whereas some illustrative examples are presented in Section .
2 Preliminaries
For any positive integerk, theqk-shifting operator:aqk(m) =qkm+ ( –qk)a[] satisfies
the relation
akqk(m) =a
k–
qk
aqk(m)
withaqk(m) =m.
We define the power ofqk-shifting operator as
a(n–m)()qk = , a(n–m)
(k)
qk =
k–
i=
n–aiqk(m)
, k∈N∪ {∞}.
Ifγ ∈R, then
a(n–m)(γqk)=n
(γ)
∞
i=
–a n
i qk(m/n)
–a n
γ+i qk (m/n)
, n= .
Theqk-derivative of a functionf on interval [a,b] is defined by
(aDqkf)(t) =
f(t) –f(aqk(t))
( –qk)(t–a)
, t=a and (aDqkf)(a) =limt→a(aDqkf)(t),
and theqk-derivative of higher order is given by
aDkqkf
(t) =aDkq–k (aDqkf)(t),
aDqkf
Theqk-integral of a functionf defined on the interval [a,b] is given by
(aIqkf)(t) =
t
a
f(s)ads= ( –qk)(t–a) ∞
i=
qikfaqik(t)
, t∈[a,b]
and
aIqkkf
(t) =aIkqk–(aIqkf)(t),
aIqkf
(t) =f(t), k∈N.
The fundamental theorem ofqk-calculus applies to the operatoraDqk andaIqk as follows:
(aDqkaIqkf)(t) =f(t).
Iff is continuous att=a, then
(aIqkaDqkf)(t) =f(t) –f(a).
The formula ofqk-integration by parts on the interval [a,b] is
b
a
f(s)aDqkg(s)adqks= (fg)(t)
b a–
b
a
gaqk(s)
aDqkf(s)adqks.
Now we recall the definitions of the Riemann-Liouville fractionalqk-integral andqk -dif-ference on interval [a,b].
Definition . Let ν ≥ , and let f be a function defined on [a,b]. The fractional
qk-integral of Riemann-Liouville type is given by (aIqkf)(t) =h(t) and
aIqνkf
(t) =
qk(ν)
t
a a
t–aqk(s)
(ν–)
qk f(s)adqks, ν> ,t∈[a,b].
Definition . The fractionalqk-derivative of Riemann-Liouville type of orderν≥ on the interval [a,b] is defined by (aDqkf)(t) =f(t) and
aDνqkf
(t) =aDlqkaI
l–ν
qk f
(t), ν> ,
wherelis the smallest integer greater than or equal toν.
Lemma . Letα,β∈R+,and let f be a continuous function on[a,b],a≥.The Riemann-Liouville fractional qk-integral has the following semigroup property:
aIqβkaI
α
qkf(t) =aI
α
qkaI
β
qkf(t) =aI
α+β
qk f(t).
Lemma . Let f be a qk-integrable function on[a,b].Then
aDαqkaI
α
Lemma . Letα> ,and let p be a positive integer.Then,for t∈[a,b],
aIqαkaD
p
qkf(t) =aD
p qkaI
α
qkf(t) –
p–
k=
(t–a)α–p+k
qk(α+k–p+ )
aDkqkf(a).
From [] we have the following formulas
aDαqk(t–a)
β= qk(β+ )
qk(β–α+ )
(t–a)β–α, (.)
aIqαk(t–a)
β
= qk(β+ )
qk(β+α+ )
(t–a)β+α. (.)
In the sequel, we definePC(J,R) ={x:J→R,x(t) is continuous everywhere except for some tk at whichx(tk+) andx(t–k) exist andx(tk–) =x(tk), k= , , , . . . ,m}. For β∈R+,
we introduce the spaceCβ,k(Jk,R) ={x:Jk→R: (t–tk)βx(t)∈C(Jk,R)}with the norm
xCβ,k =supt∈Jk|(t–tk)
βx(t)|andPC
β={x:J→R: for eacht∈Jk, (t–tk)βx(t)∈C(Jk,R),
k= , , , . . . ,m}with the norm
xPCβ =max
sup t∈Jk
(t–tk)βx(t):k= , , , . . . ,m
.
Clearly,PCβis a Banach space.
Lemma . Let y∈AC(J,R).Then x∈PC(J,R)is a solution of
⎧ ⎪ ⎨ ⎪ ⎩
tkD
αk
qkx(t) =y(t), t∈J,t=tk,
tkI
–αk
qk x(t
+
k) –x(tk) =ϕk(x(tk)), k= , , . . . ,m,
atI
–α
q x() =bx(T) +
m l=cltlI
γl
qlx(tl+),
(.)
if and only if
x(t) = (t–tk)
αk–
qk(αk)
k–
j=
(tj+–tj)αj–
qj(αj)
bm–
j=
j<i≤m
(ti+–ti)αi–
qi(αi)
×tjI
αj
qjy(tj+) +ϕj+
x(tj+)
+ btmI
αm
qmy(T)
+ m
l=
cl(tl+–tl)αl+γl– ql(αl+γl)
l–
j=
j<i≤l–
(ti+–ti)αi–
qi(αi)
×tjI
αj
qjy(tj+) +ϕj+
x(tj+)
+ m
l= cl
tlI
αl+γl
ql y(tl+)
+(t–tk)
αk–
qk(αk)
k–
j=
j<i≤k–
(ti+–ti)αi–
qi(αi)
tjI
αj
qjy(tj+) +ϕj+
x(tj+)
+tkI
αk
whereba(·) = ,ba(·) = for a>b,a<a(·) = ,and the nonzero constant is defined by
=a–b m
j=
(tj+–tj)αj–
qj(αj)
– m
l=
cl(tl+–tl)αl+γl–
ql(αl+γl)
l–
j=
(tj+–tj)αj–
qj(αj)
. (.)
Proof Applying the Riemann-Liouville fractionalq-integral of orderαto both sides of
the first equation of (.) fort∈J, we obtain
tI
α
qtD
α
qx(t) =tI
α
qtDqtI
–α
q x(t) =tI
α
qy(t). (.)
From Lemmas ., ., and . fort∈J, we have
x(t) = t
α– q(α)
tI
–α
q x() +tI
α
qy(t).
Fort∈J, applying the Riemann-Liouville fractionalq-integral of orderα again to the
first equation in (.) and using the previous process, we get
x(t) = (t–t)
α–
q(α)
tI
–α
q x
t++tI
α
qy(t). (.)
The impulsive condition implies that
x(t) = (t–t)
α–
q(α)
tα–
q(α)
tI
–α
q x() +tI
α
qy(t) +ϕ
x(t)
+tI
α
qy(t).
Similarly, fort∈J, we have
x(t) = (t–t)
α–
q(α)
(t–t)α– q(α)
tα–
q(α)
tI
–α
q x() +tI
α
qy(t) +ϕ
x(t)
+tI
α
qy(t) +ϕ
x(t)
+tI
α
qy(t).
Repeating this process fort∈Jk⊆J,k= , , , . . . ,m, we obtain
x(t) = (t–tk)
αk– qk(αk)
k–
j=
(tj+–tj)αj–
qj(αj)
tI
–α
q x()
+(t–tk)
αk–
qk(αk)
k–
j=
j<i≤k–
(ti+–ti)αi–
qi(αi)
tjI
αj
qjy(tj+) +ϕj+
x(tj+)
+tkI
αk
In particular, fort=T, we get
Taking the Riemann-Liouville fractionalql-integral of orderγlon (.) fromtltotl+and
using (.), we have
By the boundary condition of (.) we find that
tI
Substituting the value oftI
–α
q x() into (.) yields (.). The converse follows by direct
computation. This completes the proof.
Lemma . Assume that all conditions of Lemma . hold. In addition, assume that
supt∈J|y(t)|=Nand there exists a constant N such that|ϕk(x)| ≤N for k= , , . . . ,m and x∈R.Then the following inequality holds:
×
This completes the proof.
3 Main results
Now we present our first result, which deals with the existence and uniqueness of solu-tions for problem (.) and is based on the Banach contraction mapping principle.
Theorem . Assume that there exist a functionM∈C(J,R+)and a positive constant M such that
Then problem(.)has a unique solution on J if
(M+M)Tβ< , (.)
where M=supt∈J|M(t)|,the constants,are defined in Lemma.,andβ> .
Proof Consider the operatorL:PC(J,R)→PC(J,R) defined by (.) and show thatL∈
PCβ. For this, letτ,τ∈Jk. Then we have
(τ–tk)βLx(τ) – (τ–tk)βLx(τ)
≤(τ–tk)β+αk–– (τ–tk)β+αk–
qk(αk)
Kx
+(τ–tk)βtkI
αk
qkf
τ,x(τ)
– (τ–tk)βtkI
αk
qkf
τ,x(τ),
where
Kx:=
k–
j=
(tj+–tj)αj–
qj(αj)
|b| | |
m–
j=
j<i≤m
(ti+–ti)αi–
qi(αi)
×tjI
αj
qjf
tj+,x(tj+)+ϕj+
x(tj+)
+ |b|
| |tmI
αm
qmf
T,x(T)
+ m
l=
|cl|(tl+–tl)αl+γl–
| |ql(αl+γl)
l–
j=
j<i≤l–
(ti+–ti)αi–
qi(αi)
×tjI
αj
qjf
tj+,x(tj+)+ϕj+
x(tj+)
+ m
l= |cl|
| |tlI
αl+γl
ql f
tl+,x(tl+)
+
k–
j=
j<i≤k–
(ti+–ti)αi–
qi(αi)
×tjI
αj
qjf
tj+,x(tj+)+ϕj+
x(tj+)
. (.)
Asτ→τ, we get|(τ–tk)βLx(τ) – (τ–tk)βLx(τ)| → for eachk= , , . . . ,m. Thus,
Lx(t)∈PCβ.
Now we define the ballBr={x∈PCβ(J,R) :xPCβ ≤r}. We will show thatLBr⊂Br. Letsupt∈J|f(t, )|=A,max{|ϕ()|:k= , . . . ,m}=Aand choose a constantrsuch that
r≥ (A+A)T β
– (M+M)Tβ
.
Then, for anyx∈Brandt∈J, we have
(t–tk)βLx(t)≤
(t–tk)β+αk–
qk(αk)
Kx+ (t–tk)βtkI
αk
qkf
whereKxis given by (.). Using the inequalities
f(s,x)≤f(s,x) –f(s, )+f(s, )≤Mr+A, ϕ(x)≤ϕ(x) –ϕ()+ϕ()≤Mr+A
in (.) forx∈Brands∈Jand the computational details of Lemma ., together with
Kx≤
k–
j=
(tj+–tj)αj–
qj(αj)
|b| | |
m–
j=
j<i≤m
(ti+–ti)αi–
qi(αi)
×
(Mr+A)
(tj+–tj)αj
(αj+ )
+ (Mr+A)
+ (Mr+A) |b| | |
(T–tm)αm
(αm+ )
+ m
l=
|cl|(tl+–tl)αl+γl–
| |ql(αl+γl)
l–
j=
j<i≤l–
(ti+–ti)αi–
qi(αi)
×
(Mr+A)
(tj+–tj)αj
(αj+ )
+ (Mr+A)
+ m
l= |cl|
| |
(tl+–tl)αl+γl
ql(αl+γl+ )
+
k–
j=
j<i≤k–
(ti+–ti)αi–
qi(αi)
(Mr+A)
(tj+–tj)αj
(αj+ )
+ (Mr+A)
,
we obtain
(t–tk)βLx(t)≤(t–tk)β
(Mr+A) +(Mr+A)
≤r(+M)Tβ+ (A+A)Tβ ≤r.
This implies thatLxPCβ≤rand, consequently,LBr⊂Br. For allx,y∈PCβ(J,R) andt∈J, as in Lemma ., we get
Lx(t) –Ly(t)≤(M+M)x–yPCβ.
Multiplying both sides of this inequality by (t–tk)βfor eacht∈Jk, we have
(t–tk)βLx(t) –Ly(t)≤(t–tk)β(M+M)x–yPCβ
≤Tβ(M+M)x–yPCβ,
which leads toLx–LyPCβ≤T
β(M+M)x–y
PCβ. In view of condition (.), it follows by the Banach contraction mapping principle that the operatorLis a contraction. Hence,Lhas a fixed point, which is a unique solution of problem (.) onJ.
Lemma .(Nonlinear alternative for single valued maps []) Let E be a Banach space,
C a closed,convex subset of E,U an open subset of C,and∈U.Suppose that F:U→C is continuous and compact(that is,F(U)is a relatively compact subset of C)map.Then either
(i) Fhas a fixed point inU,or
(ii) there areu∈∂U(the boundary ofUinC)andθ∈(, )withu=θF(u).
Theorem . Assume that
(H) there exist continuous nondecreasing functionsQ,V: [,∞)→(,∞)and a
continu-ous functionp:J→R+such that
f(t,x)≤p(t)Q|x| and ϕk(x)≤V
|x| (.)
for all(t,x)∈(J×R)andk= , , . . . ,m;
(H) there exists a constantM∗> such that such that
M∗
(p∗Q(M∗)+V(M∗))Tβ
> , (.)
wherep∗=supt∈J|p(t)|,β> ,and the constants,are defined in Lemma..
Then problem(.)has at least one solution on J.
Proof First, we show that the operatorLdefined by(.)maps bounded sets(balls)into bounded sets in PCβ. To accomplish this, for a positive number ρ, letBρ={x∈PCβ : xPCβ ≤ρ}be a ball inPCβ. Then, forx∈Bρandt∈J, using the method of proof used in Lemma ., we obtain
Lx(t)≤(t–tk)
αk–
qk(αk)
Kx+tkI
αk
qkf
t,x(t),
whereKxis defined by (.). From (H) we have
Kx≤
k–
j=
(tj+–tj)αj–
qj(αj)
|b| | |
m–
j=
j<i≤m
(ti+–ti)αi–
qi(αi)
×
p∗Q(ρ)
(tj+–tj)αj
(αj+ )
+V(ρ)
+p∗Q(ρ)|b|
| |
(T–tm)αm
(αm+ )
+ m
l=
|cl|(tl+–tl)αl+γl–
| |ql(αl+γl)
l–
j=
j<i≤l–
(ti+–ti)αi–
qi(αi)
×
p∗Q(ρ)
(tj+–tj)αj
(αj+ )
+V(ρ)
+ m
l= |cl|
| |
(tl+–tl)αl+γl
ql(αl+γl+ )
+
k–
j=
j<i≤k–
(ti+–ti)αi–
qi(αi)
p∗Q(ρ)
(tj+–tj)αj
(αj+ )
+V(ρ)
and thus
Lx(t)≤p∗Q(ρ)+V(ρ).
Therefore, (t–tk)β|Lx(t)| ≤(t–tk)β(p∗Q(ρ)+V(ρ)), which means thatLxPCβ ≤
Tβ(p∗Q(ρ)
+V(ρ)).
Next we show thatLmaps bounded sets into equicontinuous sets of PCβ.
Lettingτ,τ∈Jkfor somek∈ {, , , . . . ,m}withτ<τandx∈Bρ, whereBρis a ball
inPCβ, we have
Lx(τ) –Lx(τ)≤
(τ–tk)αk–– (τ–tk)αk–
qk(αk)
Kx
+tkI
αk
qkf
τ,x(τ)
–tkI
αk
qkf
τ,x(τ)
≤(τ–tk)αk–– (τ–tk)αk–
qk(αk)
Kx
+p∗Q(ρ)(τ–tk)
αk– (τ
–tk)αk
qk(αk+ )
. (.)
Asτ→τ, the right-hand side of inequality (.) tends to zero independently ofx, that
is,
(τ–tk)βLx(τ) – (τ–tk)βLx(τ)→ as|τ–τ| →.
Therefore, by the Arzelà-Ascoli theorem,L:PCβ→PCβis completely continuous.
Our result will follow from the Leray-Schauder nonlinear alternative once we show the boundedness of the set of all solutions to the equationx(t) =λLx(t) for <λ< . Letxbe a solution. For anyt∈Jandx∈PCβ, following the method of proof used in the first step
together with condition (H), we get
xPCβ ≤
p∗QxPCβ
+V
xPCβ
Tβ.
In consequence, we have
xPCβ
(p∗Q(xPCβ)+V(xPCβ))T
β ≤.
By condition (H) there exists M∗ such that xPCβ = M∗. We define U={x∈PCβ :
xPCβ <M∗}. Note that the operatorL:U→PCβ is continuous and completely con-tinuous. By the choice ofUthere is nox∈∂Usuch thatx=λLxfor someλ∈(, ). Con-sequently, by the nonlinear alternative of Leray-Schauder type (Lemma .) we deduce thatLhas a fixed pointx∈U, which is a solution of problem (.) onJ. This completes
the proof.
A key to prove the final result is based on the following fixed point theorem.
(i) (Altman)Ax–x≥ Ax–xfor allx∈∂ ,
(ii) (Rothe)Ax ≤ xfor allx∈∂ ,
(iii) (Petryshyn)Ax ≤ Ax–xfor allx∈∂ .
Thendeg(I–A, ,θ) = ,and hence A has at least one fixed point in .
Theorem . Assume that
(H) the continuous functionsf :J×R→Randϕk:R→R,k= , , . . . ,m,satisfy
lim x→
f(t,x)
x = and xlim→ ϕk(x)
x = , k= , , . . . ,m. (.)
Then problem(.)has at least one solution on J.
Proof Letx∈PCβ. Takingεsufficiently small, we can choose two positive constantsδand δsuch that|f(t,x)|<ε|x|wheneverxPCβ<δandϕk(x) <ε|x|wheneverxPCβ <δfor
k= , , . . . ,m. Settingδ=min{δ,δ}, we define the open ballBδ={x∈PCβ:xPCβ <δ}. As in Theorem ., it is clear that the operatorL:PC→PCis completely continuous. For anyx∈∂Bδ, we have
Lx(t)= (t–tk)
αk–
qk(αk)
k–
j=
(tj+–tj)αj–
qj(αj)
|b| | |
m–
j=
j<i≤m
(ti+–ti)αi–
qi(αi)
×tjI
αj
qjf
tj+,x(tj+)+ϕj+
x(tj+)
+ |b|
| |tmI
αm
qmf
T,x(T)
+ m
l=
|cl|(tl+–tl)αl+γl–
| |ql(αl+γl)
l–
j=
j<i≤l–
(ti+–ti)αi–
qi(αi)
×tjI
αj
qjf
tj+,x(tj+)+ϕj+
x(tj+)
+ m
l= |cl|
| |tlI
αl+γl
ql f
tl+,x(tl+)
+(t–tk)
αk–
qk(αk)
k–
j=
j<i≤k–
(ti+–ti)αi–
qi(αi)
×tjI
αj
qjf
tj+,x(tj+)+ϕj+
x(tj+)
+tkI
αk
qkf
t,x(t)
≤(+)ε|x|.
Settingε≤(+)–, we deduce that
|Lx| ≤ |x|.
Multiplying both sides of this inequality by (t–tk)β, we haveLxPCβ≤ xPCβ. It follows from Lemma .(ii) that problem (.) has at least one solution onJ.
4 Examples
Example . Consider the following nonlocal boundary value problem for impulsive frac-tionalq-difference equations:
⎧
hold. Therefore, by the conclusion of Theorem ., problem (.) has a unique solution on [, /].
SettingQ(x) = (x/) + ,V(x) = (x/) + (/),p∗= /, andβ= , there exists a constant
M∗> . satisfying (.). Thus, the hypothesis of Theorem . is satisfied. In consequence, the conclusion of Theorem . applies, and problem (.) has at least one solution on [, ].
Example . Consider the problem of impulsive fractionalq-difference equations given
by
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
tkD
(k+k+
k+k+)
(k+k+
k+k+)
x(t) =t+t (sinx(t) –x(t))ex(t)cosx(t), t∈[, /]\tk,
tkI
( k+k+
k+k+)
(k+k+
k+k+)
x(t+k) –x(tk) =kx
(t
k)+kx(tk) log(|x(t
k)|+) , tk=k,k= , , , ,
I
x
() = x(
) +
l=(l
+l+
l+l+)tlI
(l+) (l+l+
l+l+)
x(tl+).
(.)
Hereαk= (k+k+ )/(k+ k+ ),qk= (k+ k+ )/(k+ k+ ),γk= (k+ )/,
ck = (k + k+ )/(k+ k+ ), k = , , , , ,a= /, b= /,T = /, tk =k/,
k= , , , . With this data, we find that| |= .= . The functionsf(t,x) = ((t)/(t+ ))(sinx–x)excosxandϕ
k(x) = (kx+ kx)/(log(|x|+ )),k= , , , , satisfy
lim x→
f(t,x)
x =xlim→
t
t+
sin x x –
excosx=
and
lim x→
ϕk(x)
x =xlim→
kx+ kx
log(|x|+ )= , k= , , , .
Thus, condition (H) of Theorem . holds. Therefore, by applying Theorem . we
con-clude that problem (.) has at least one solution on [, /].
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
Each of the authors, BA, AA, SKN, JT, and FA contributed to each part of this work equally and read and approved the final version of the manuscript.
Author details
1Nonlinear Analysis and Applied Mathematics (NAAM) Research Group, Department of Mathematics, Faculty of Science,
King Abdulaziz University, P.O. Box 80203, Jeddah, 21589, Saudi Arabia. 2Department of Mathematics, University of
Ioannina, Ioannina, 451 10, Greece.3Nonlinear Dynamic Analysis Research Center, Department of Mathematics, Faculty of
Applied Science, King Mongkut’s University of Technology North Bangkok, Bangkok, 10800, Thailand.
Acknowledgements
This paper was funded by the Deanship of Scientific Research (DSR) at King Abdulaziz University. The authors, therefore, acknowledge with thanks DSR for technical and financial support. The authors thank the reviewers for their useful comments.
Received: 4 March 2016 Accepted: 27 April 2016
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