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Volume 2010, Article ID 486127,11pages doi:10.1155/2010/486127

Research Article

A Hilbert Integral-Type Inequality with Parameters

Shang Xiaozhou and Gao Mingzhe

Department of Mathematics and Computer Science, Normal College of Jishou University, Hunan Jishou 416000, China

Correspondence should be addressed to Gao Mingzhe,[email protected]

Received 15 March 2010; Revised 9 April 2010; Accepted 14 April 2010

Academic Editor: Feng Qi

Copyrightq2010 S. Xiaozhou and G. Mingzhe. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

A Hilbert-type integral inequality with parameters α and α, λ > 0 can be established by introducing a nonhomogeneous kernel function. And the constant factor is proved to be the best possible. And then some important and especial results are enumerated. As applications, some equivalent forms are studied.

1. Introduction

Letfx, gxL20,. Then

0

fxgy

xy dx dyπ

0

f2xdx

1/2∞

0

g2xdx

1/2

, 1.1

where the constant factorπ is the best possible, and the equality in1.1holds if and only iffx 0, orgx 0.This is the famous Hilbert integral inequalitysee1,2. Owing to the importance of the Hilbert inequality in analysis and applications, some mathematicians have been studying them. Recently, various improvements and extensions of 1.1 appear in a great deal of paperssee3–11, etc.. Specially, Gao and Hsu enumerated the research articles to more than 40 in the paper 6. It is obvious that the integral kernel function of the left hand side of1.1is a homogeneous form of degree−1. In general, the Hilbert type integral inequality with a homogeneous kernel of degree−1 has been studied in the paper

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For convenience, we need to introduce the Catalan constant and define a real function. The Catalan constant is defined by

G 1

2 1

0

Kdk

n0

−1n

2n12, 1.2

whereKis the complete elliptic integral, namely,

KKk

π/2

0

1−k2sin2θ. 1.3

And the approximation ofGis that

G0,915965594· · · . 1.4

These results can be found in the paper12, page 503. Letλ >0. Define a real function by

n0

−1n 1

2n1λ1. 1.5

In particular,S1 G, whereGis the Catalan constant.

In order to prove our main results, we need the following lemmas.

Lemma 1.1. Letabe a positive number andb >−1. Then

0

xbeaxdx Γb1

ab1 . 1.6

Proof. According to the definition of the gamma function, we obtain immediately1.6. This result can be also found in the paper12, page 226, formula1053.

Lemma 1.2. Letα, λ >0. Define a function by

Cα, λ 2

2

α

λ1

Γλ1Sλ, 1.7

whereΓzis the gamma function, andSλis a function defined by1.5. Then

0

k1, uuα/2−1duCα, λ, 1.8

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Proof. It is easy to deduce that

0

k1, uuα/2−1du

1

0

ln1/uλ

1 u

α/2−1du

1

ln

1uαu α/2−1du

1

0

ln1/uλ

1 u

α/2−1du 1

0

ln1/vλ

1 u

α/2−1du

2 1

0

ln1/uλ

1 u

α/2−1du2

0

eα/2t 1eαt dt.

1.9

Expanding 1/1eαtinto power series ofeαtand then using Lemma1.1, we have

0

eα/2t 1eαt dt

0

tλeα/2t1−eαte−2αte−3αte−4αt· · ·dt

0

tλeα/2ttλe−3/2αttλe−5/2αttλe−7/2αt· · ·dt

2

α

λ1

Γλ1

n0

−1n 1

2n1λ1

2

α

λ1

Γλ1Sλ.

1.10

It follows from1.9,1.10, and1.7that the equality1.8holds.

2. Main Results

In the section we will formulate our main results.

Theorem 2.1. Letfandgbe two real functions, and letαandλbe arbitrary two positive numbers. If

0 x1−αf2xdx <and

0 x1−αg2xdx <, then

0

lnxyλ

fxgy

1xyα dx dyCα, λ

0

x1−αf2xdx

1/2∞

0

x1−αg2xdx 1/2

, 2.1

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Proof. We may apply Hardy’s technique and Cauchy-Schwarz’s inequality to estimate the left-hand side of2.1as follows:

0

lnxyλ

fxgy

1 xyα dx dy

0

lnxyλ/2

fx

1xyα1/2

x y

2−α/4 lnxyλ/2fx

1 xyα1/2

y

x

2−α/4

gydx dy

0

lnxyλ 1 xyα

x y

2−α/2

f2xdx dy

1/2

0

lnxyλ 1xyα

y

x

2−α/2

g2ydx dy

1/2

0

ωα, λ, xf2xdx

1/2∞

0

ωα, λ, xg2xdx

1/2

,

2.2

whereωα, λ, x 0∞|lnxy|λ/1 xyαx/y2−α/2dy. By substitutinguforxy, it is easy to deduce that

ωα, λ, x

0

lnxyλ

1xyα

x y

2−α/2

dy

x1−α

0 |lnu|λ

1

1

u

2−α/2

du

x1−α

0

|ln1/u|λ

1 u

α/2−1du.

2.3

Based on1.8, we obtain

ωα, λ, x x1−αCα, λ. 2.4

It is known from2.2and2.4that the inequality2.1is valid.

Iffx 0, orgx 0, then the equality in2.1obviously holds. Iffx/0 and

gx/0, then

0<

0

x1−αf2xdx <, 0<

0

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If2.2takes the form of the equality, then there exists a pair of non-zero constantsc1 andc2such that

c1

lnxyλ

1xyαf

2x

x y

1−α/2

c2

lnxyλ

1xyαg

2yy

x

1−α/2

a.e.on0,∞×0,.

2.6

Then we have

c1x2−αf2x c2y2−αg2

yC0.constant a.e.on0,∞×0,. 2.7

Without losing the generality, we suppose thatc1/0; then

0

x1−αf2xdx C0 c1

0

x−1dx. 2.8

This contradicts that 0<0x1−αf2xdx <∞. Hence it is impossible to take the equality in

2.2. It shows that it is also impossible to take the equality in2.1.

It remains to need only to show thatCα, λin2.1is the best possible. Below we will apply Yang’s techniquesee13to verify our assertion.

For allnN, define two functions by

fnx ⎧ ⎨ ⎩

xα/2−11/2n x0,1,

0 x∈1,,

gnx ⎧ ⎨ ⎩

0 x∈0,1, xα/2−1−1/2n x1,.

2.9

Then we have

1

0

x1−αfn2xdx

1/2

1

x1−αg2nxdx

1/2

n. 2.10

Let 0≤kCα, λsuch that the inequality2.1is still valid when Cα, λis replaced byk. Specially, we have

1

n

0

lnxyλ

fnxgn

y

1xyα dx dyk

1

n

0

x1−αfn2xdx

1/2∞

0

x1−αgn2xdx

1/2

k.

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Letk1, xy |lnxy|λ/1 xyα. By Fubini’s theorem, we have

k≥ 1 n

0

k1, xyfnxgn

ydx dy

1

n

1

yα/2−1−1/2n

1

0

k1, xyxα/2−11/2ndx

dy

1

n

1

y−1−1/n y

0

k1, uuα/2−11/2ndu dy

1

n

1

y−1−1/n

1

0

k1, uuα/2−11/2ndu

dy

1

y−1−1/n

y

1

k1, uuα/2−11/2ndu dy

1

n

1

n

1

0

k1, uuα/2−11/2ndu

1

k1, uuα/2−11/2n

u

y−1−1/ndy du

1

0

k1, uuα/2−11/2ndu

1

k1, uuα/2−1−1/2ndu.

2.12

By Fatou’s lemma and1.8, we have

k≥ lim n→ ∞

1

0

k1, uuα/2−11/2ndu lim n→ ∞

1

k1, uuα/2−1−1/2ndu

1

0 lim

n→ ∞k1, uu

α/2−11/2ndu

1 lim

n→ ∞k1, uu

α/2−1−1/2ndu

1

0

k1, uuα/2−1du

1

k1, uuα/2−1du

0

k1, uuα/2−1duCα, λ.

2.13

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Based on Theorem2.1, we may build some important and interesting inequalities.

Theorem 2.2. Let n be a nonnegative integer and α > 0. If 0x1−αf2xdx < and

0 x1−αg2xdx <, then

0

lnxy2nfxgy

1xyα dx dyCα,2n

0

x1−αf2xdx

1/2∞

0

x1−αg2xdx

1/2

,

2.14

whereCα,2n π/α2n1En,theEnsare the Euler numbers, namely,E01, E11, E25, E3

61, E4 1385,and so forth, and the constant factorCα,2nin2.14is the best possible. And the equality in2.14holds if and only iffx 0, orgx 0.

Proof. We need only to verify the constant factorCα,2nin2.14. Whenλ2n, it is known from1.10that

Cα,2n 2

2

α

2n1

Γ2n1

k0

−1k 1

2k12n1. 2.15

It is known from the paper14that

k0

−1k 1

2k12n1

π2n1

22n22n!En, 2.16

where theEnsare the Euler numbers, namely,E0 1, E1 1, E2 5, E3 61, E4 1385,and so forth.

It follows that the constant factorCα,2nin2.14is correct.

In particular, based on Theorem2.2, the following results are gotten.

Corollary 2.3. If0f2xdx <and

0 g2xdx <, then

0

fxgy

1xy dx dyπ

0

f2xdx

1/2∞

0

g2xdx 1/2

, 2.17

where the constant factorπin2.17is the best possible. And the equality in2.17holds if and only iffx 0, orgx 0.

Corollary 2.4. If0f2xdx <and

0 g2xdx <, then

0

lnxy2fxgy

1xy dx dyπ

3

0

f2xdx

1/2∞

0

g2xdx

1/2

, 2.18

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Theorem 2.5. Letfandgbe two real functions, andαa positive number. If0x1−αf2xdx < and0x1−αg2xdx <, then

0

lnxyfxg

y

1xyα dx dy

8G α2

0

x1−αf2xdx

1/2∞

0

x1−αg2xdx

1/2

, 2.19

whereGis the Catalan constant, that is,G 0,915965594· · ·. And the constant factor 8G/α2in

2.19is the best possible. And the equality in2.19holds if and only iffx 0, orgx 0.

Proof. We need only to verify the constant factor in2.19. For caseλ1, based on1.7,1.5

and1.2, it is easy to deduce that the constant factor is thatCα,1 8G/α2.

In particular, whenαλ1, the following result is obtained

Corollary 2.6. Letfandgbe two real functions. If0f2xdx <and

0 g2xdx <, then

0

lnxyfxg

y

1xy dx dy≤8G

0

f2xdx

1/2∞

0

g2xdx

1/2

, 2.20

whereGis the Catalan constant, that is,G0,915965594· · ·. And the constant factor 8Gin2.20 is the best possible. And the equality in2.20holds if and only iffx 0, orgx 0.

A great deal of the Hilbert type inequalities can be established provided that the parameters are properly selected

3. Some Equivalent Forms

As applications, we will build some new inequalities.

Theorem 3.1. Let f be a real function, and let α and λ be arbitrary two positive numbers. If

0 x1−αf2xdx <, then

0

−1

0

lnxyλ

1xyαfxdx

2

dyCα, λ2

0

x1−αf2xdx, 3.1

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Proof. First, we assume that the inequality2.1is valid. Define a functiongyby

gyyα−1

0

lnxyλ

1xyαfxdx, y∈0,. 3.2

By using2.1, we have

0

−1

0

lnxyλ

1xyαfxdx

2

dy

0

lnxyλ 1xyαfxg

ydx dy

Cα, λ

0

x1−αf2xdx

1/2∞

0

y1−αg2ydy 1/2

Cα, λ

0

x1−αf2xdx

1/2⎧⎨ ⎩

0

−1

0

lnxyλ

1xyαfxdx

2

dy

⎫ ⎬ ⎭

1/2

.

3.3

It follows from3.3that the inequality3.1is valid after some simplifications.

On the other hand, assume that the inequality3.1keeps valid; by applying in turn Cauchy’s inequality and3.1, we have

0

lnxyλ 1xyαfxg

ydx dy

0

−1/2

0

lnxyλ

1xyαfxdx

−1/2gydy

≤ ⎧ ⎨ ⎩ 0

−1

0

lnxyλ

1xyαfxdx

2

dy

⎫ ⎬ ⎭

1/2

0

y1−αg2ydy

1/2

Cα, λ2

0

x1−αf2xdx

1/2∞

0

y1−αg2ydy

1/2

Cα, λ

0

x1−αf2xdx

1/2∞

0

y1−αg2ydy

1/2

.

3.4

Therefore, the inequality3.1is equivalent to2.1.

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Theorem 3.2. Letnbe a nonnegative integer andα >0. If0x1−αf2xdx <, then

0

−1

0

lnxy2n

1xyαfxdx

2

dyCα,2n2

0

x1−αf2xdx, 3.5

whereCα,2n π/α2n1En, theEnsare the Euler numbers,namely,E01, E11, E25, E3

61, E41385, and so forth, and the constant factorCα,2nis the best possible. And the equality in

3.5holds if and only iffx 0. And the inequality3.5is equivalent to2.14.

Theorem 3.3. Letfandgbe two real functions, and letαbe a positive numbers. If0x1−αf2xdx <

and0x1−αg2xdx <, then

0

−1

0

lnxy

1xyαfxdx

2

dy≤ 8G α2

0

x1−αf2xdx

1/2∞

0

x1−αg2xdx

1/2

,

3.6

whereG is the Catalan constant, that is,G 0,915965594· · ·. And the constant factor 8G/α2 in

3.6is the best possible. And the equality in3.6holds if and only iffx 0. And the inequality

3.6is equivalent to2.19.

The proofs of Theorems3.2and3.3are similar to one of Theorem3.1; they are omitted here.

Similarly, we can establish also some new inequalities which they are, respectively, equivalent to the inequalities2.17,2.18and2.20. These are omitted here.

Acknowledgments

Authors would like to express their thanks to the referees for their valuable comments and suggestions. The research is supported by Scientific Research Fund of Hunan Provincial Education Department09C789.

References

1 G. H. Hardy, J. E. Littlewood, and G. Polya, Inequalities, Cambridge University Press, Cambridge, UK, 1952.

2 K. Jichang, Applied Inequalities, Shandong Science and Technology Press, Jinan, China, 3rd edition, 2004.

3 L. He, W. Jia, and M. Gao, “A Hardy-Hilbert’s type inequality with gamma function and its applications,” Integral Transforms and Special Functions, vol. 17, no. 5, pp. 355–363, 2006.

4 M. Gao, “On Hilbert’s inequality and its applications,” Journal of Mathematical Analysis and

Applications, vol. 212, no. 1, pp. 316–323, 1997.

5 M. Gao, T. Li, and L. Debnath, “Some improvements on Hilbert’s integral inequality,” Journal of

Mathematical Analysis and Applications, vol. 229, no. 2, pp. 682–689, 1999.

6 M. Gao and L. C. Hsu, “A survey of various refinements and generalizations of Hilbert’s inequalities,”

Journal of Mathematical Research and Exposition, vol. 25, no. 2, pp. 227–243, 2005.

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8 Y. Hong, “All-sided generalization about Hardy-Hilbert integral inequalities,” Acta Mathematica

Sinica. Chinese Series, vol. 44, no. 4, pp. 619–626, 2001.

9 H. Ke, “On Hilbert’s inequality,” Chinese Annals of Mathematics Series B, vol. 13, no. 1, pp. 35–39, 1992. 10 L. He, M. Gao, and Y. Zhou, “On new extensions of Hilbert’s integral inequality,” International Journal

of Mathematics and Mathematical Sciences, vol. 2008, Article ID 297508, 8 pages, 2008.

11 B. C. Yang, “A new Hilbert-type integral inequality and its generalization,” Journal of Jilin University.

Science Edition, vol. 43, no. 5, pp. 580–584, 2005.

12 J. Yuming, Table of Applied Integrals, University of Science and Technology of China Press, Hefei, China, 2006.

References

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