In this section we discuss intersections of lines in R3 and show how to calculate those intersections.
Theoretical Remarks
2.7.Given two lines in R3, say 1 and 2, we have the following possibilities regarding their intersection:
a) 1 and 2 may intersect in a unique common point.
b) 1 and 2 may intersect at every point on 1 and 2, so that the two lines coincide.
c) 1 and 2 may not intersect at any point.
Remark: Given any number of lines inR3, the possibilities of their common intersections are the same as those listed above for two lines.
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Problem
2.7.1.Consider the following two lines inR3:
1:
b) Do the lines intersect for b = 1? If so, find the intersection(s) in this case.
Solution
2.7.1.a) At any point where 1and 2intersect, there must exist parametric values for t and s for the coordinates of the intersection points. To establish those points, we consider
x = 2t + 3 =−s and in matix form we have
The corresponding augmented matrix is
We now apply two elementary row operations to the above augmented matrix, namely
1: multiply the first row by 2 and add the resulting row to the second row;
2: multiply the first row by−1 and add the resulting row to the third row.
This leads to the following echelon form:
From the above echelon form we conclude that the system has a solution for t and s if and only if
b= 2.
Therefore the two lines 1 and 2 intersect if and only if b∈ R\{2}.
For those values of b, we have t = 2− 3b
2(b− 2), s = 4 b− 2.
Inserting the above values for t and s into 1 or 2, we obtain the x-, y- and z-coordinates of the point of intersection for any b∈ R\{2}, namely
x = −4
Inserting those values for t and s into 1 or 2 we obtain the coordinates of the point of intersection, namely
(4,−1, 3).
Problem
2.7.2.Consider the following three lines inR3:
1:
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a) Find the intersection(s) of the lines 1 and 2, if those lines do intersect.
b) Find the intersection(s) of the lines 1, 2 and 3, if those lines do intersect.
Solution
2.7.2.a) To find the intersection(s) of 1 and 2 we consider x =−t + 3 = 3s + 3
y = 2t + 1 =−6s + 1 z =−t + 2 = 3s + 2, so that
−t − 3s = 0 2t + 6s = 0
−t − 3s = 0.
In matrix form we have
−1 −3
2 6
−1 −3
t s
=
0 0 0
.
For the corresponding augmented matrix we have
−1 −3 0
2 6 0
−1 −3 0
∼
1 3 0 0 0 0 0 0 0
,
which means that
t =−3s for all s ∈ R.
Thus for every value of s∈ R for 2 there is a value of t for 1, namely t =−3s, that gives the same coordinates and hence a point of intersection between 1 and 2. The two lines, 1 and 2, therefore intersect at every point on 1 (or 2), so that the two lines in fact coincide.
b) Since 1 and 2 coincide (as established above), we can now search for the intersec-tion(s) between 1 and 3. We consider
x =−t + 3 = −4p + 8 y = 2t + 1 = p + 2 z =−t + 2 = 2p − 1,
so that the matrix equation takes the form
−1 4
2 −1
−1 −2
t p
=
5 1
−3
.
For the corresponding augmented matrix we have
−1 4 5
2 −1 1
−1 −2 −3
∼
1 −4 −5
0 7 11
0 −6 −8
∼
1 −4 −5
0 1 11/7
0 0 1
,
which means that the system is inconsistent. Hence there exist no values for t and p which would give the same point, so that there is no intersection between 1 and
3. The three lines, 1, 2 and 3, do therefore not intersect in a common point or points.
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2.8 Exercises
1. Consider the matrix equation AX−1+ 3B = A2, where
A =
1 −1
0 3
, B =
2 1 1 1
and X is an invertible 2× 2 matrix. Find X, such that the given matrix equation is satisfied.
[Answer: X =
−2/17 −5/17
−1/17 6/17
. ]
2. Consider the matrix equation 2X + AX = 3B,
where A =
1 3
−1 −2
and X is an unspecified matrix.
a) For the given matrix equation, assume that B =
3 1
−3 2
and find the matrix X.
[Answer: X =
9 −6
−6 7
. ]
b) For the given matrix equation, assume that B =
1 −1 −2
−1 1 3
and find the matrix X.
[Answer: X =
3 −3 −9
−2 2 7
. ]
3. Consider the matrix equation C−1(XB− A)B−1 = X,
where B, C and In− C are all n × n invertible matrices. Find the matrix X that satisfies the above equation in terms of the other given matrices and in terms of the identity matrix In.
[Answer: X = (In− C)−1AB−1. ]
4. Consider the matrix equation AX−1+ (X + B)−1 = X−1,
where A, B, X, X + B, A−1− In and A− In are all n× n invertible matrices.
a) Solve the given matrix equation for X.
[Answer: X = B(A−1− In). ]
b) Solve the given matrix equation for X, where A and B take the following explicit forms:
A =
1 −1
1 0
, B =
2 1 1 1
.
[Answer: X =
−3 2
−2 1
. ]
5. Consider the following matrix:
A =
a 2 3
1 0 −1
−1 3 a + 6
,
where a is an unspecified real parameter.
a) Find all values of a, such that the matrix A is invertible.
[Answer: a∈ R\{1}. ]
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b) Calculate the inverse of A with a = 0.
6. Find all solutions of the system Ax = b for the given matrix A and vector b as given below. Give also the geometrical interpretation of the solutions where possible.
a) A =
[Answer: The unique solution is given by a point in R3, the coordinates of which are x =
[Answer: The solutions are given by a line in R3 passing through the point (3/2, 0, 1/2) and parallel to the vector (1, 1,−1), i.e. the infinitely many solutions are
[Answer: The solutions are given by a plane in R3 with equation x1− x2+ 2x3 = 1, i.e. the infinitely many solutions are
[Answer: The system is inconsistent. That is, the system has no solution. ]
7. Find the intersection of the following two planes inR3: Π1: x− y + 3z = 1
Π2: x + y + 2z = 10.
Use Maple to sketch the planes inR3(see Appendix A for information about Maple).
[Answer: The two planes intersect along the following line:
:
x =−5t + 28 y = t
z = 2t− 9 for all t∈ R. ]
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8. Find the intersection of the following three planes in R3: Π1 : x + 3y− 5z = 0
Π2 : x + 4y− 8z = 0 Π3 :−2x − 7y + 13z = 0.
Use Maple to sketch the planes inR3 (See Appendix A for information about Maple).
[Answer: The three planes intersect along the following line:
:
x =−4t y = 3t
z = t for all t∈ R. ]
9. Consider the following three planes in R3: Π1 : x1− 4x2+ 7x3 = 1
Π2 : 3x2− 5x3 = 0
Π3 : −2x1+ 5x2− 9x3 = k, where k is an unspecified real parameter.
a) Find all values of k such that the given three planes intersect along a common line and give this line of intersection in parametric form.
[Answer: The three planes intersect along a common line if and only if k =−2, where is given by
:
x1=−t/5 + 1 x2= t
x3= 3t/5 for all t∈ R. ]
b) For which value(s) of k do the three planes intersect in a unique point.
[Answer: There exists no value of k for which the three planes intersect in a unique point. ]
10. Find all solutions of the following system:
11. Consider the following system:
x1+ x3+ 2x4= 1 2x1+ kx2+ x3+ x4 = 2 3x2+ x3+ 2x4= 3 x1+ x2+ x4 = 4,
where k is an unspecified real parameter.
a) Find all values of k, such that the given system has a unique solution.
[Answer: k ∈ R\{−7}. ]
b) Find all values of k, such that the given system has infinitely many solutions.
[Answer: There exist no values of k for which the system admits infinitely many solutions. ]
c) Find all values of k, such that the given system is inconsistent.
[Answer: k =−7. ]
d) Find all values of k for which the coefficient matrix of the given system is singular.
[Answer: k =−7. ]
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12. Consider the following system:
x1+ x2+ x3 = a 3x1+ kx3 = b x1+ kx2+ x3 = c,
where a, b, c and k are unspecified real parameters.
a) Find all values of k, such that the given system has a unique solution for all real values of a, b and c.
[Answer: k∈ R\{1, 3}. ]
b) Find all values of k and the corresponding conditions on a, b and c, such that the given system is consistent.
[Answer: From part a) above, we know that the system has a unique solution (and is consistent) for all k ∈ R\{1, 3} and all real values of a, b and c. For k = 1 the system has infinitely many solutions (and is consistent) if and only if c = a for all c∈ R. For k = 3 the system has infinitely many solutions (and is consistent) if and only if c = 3a− 2b/3 for all a ∈ R and all b ∈ R. ]
13. Consider the following matrix equation:
X
1 1
−1 1
−
0 1
α −α
X =
1 2
−1 3
,
where X is an unspecified 2× 2 matrix. Determine all real values of α, such that the given matrix equation has a unique solution for X.
[Answer: α∈ R\{−2}. ] 14. a) Consider the function
f (x) = ax3+ bx2+ cx + d,
where a, b, c and d are unspecified real parameters. Find the values of these parameters such that the graph y = f (x) is passing through the following points in the xy-plane: {(1, 1), (−1, 1), (2, 2), (−2, 12)}. Use Maple to sketch your obtained function f (x) in the xy-plane (see Appendix A for information about Maple).
[Answer: a =−5/6, b = 2, c = 5/6, d = −1. ]
b) Consider the function
f (x) = a cos(2x) + b(π− x) cos(2x) + cx sin(π − x),
where a, b and c are unspecified real parameters. Find the values of these parameters such that the graph y = f (x) is passing through the following points in the xy-plane: {(−π/2, −3π), (π/2, 0), (3π/2, 5π)}. Use Maple to sketch your obtained function f (x) in the xy-plane (see Appendix A for information about Maple).
[Answer: a =−2π, b = 3, c = −1. ]
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15. Consider the system Ax = b with
where h and k are unspecified real parameters.
a) Find the relation between the parameters h and k, such that the given system Ax = b is consistent.
[Answer: k = 2h for all h∈ R. ]
b) Find all solutions for the given system Ax = b.
[Answer: The system has the unique solution x =
h− 3 6− h
for all h∈ R, where k = 2h. ]
16. Consider the following line in R3:
:
Find all real values of the parameters a, b and c, such that the line is lying on the plane
17. Consider the following two lines inR3:
1 :
a) Find all values of b, such that the lines 1 and 2 intersect.
[Answer: b∈ R\{2}. ]
b) Do the lines intersect for b = 1? If so, find the point of intersection for this case.
[Answer: Yes, the point of intersection has the coordinates (4,−1, 3). ]
18. Consider the following six planes that describe a parallelepiped at their intersections:
Π1: x + 2y− z = 1 Π2: 2x + 4y− 2z = 0 Π3: −3x − y + 2z = 1 Π4: −9x − 3y + 6z = 1 Π5: y + z =−1
Π6: −2y − 2z = 3.
Find the vertices, the volume and the midpoint of this parallelepiped, as well as the hight of the parallelepiped with base face described by Π2.
[Answer: The coordinates of the vertices of the parallelepiped are as follows:
P1: (−17 12, 11
36, −65 36) P2: (−7
6, 7 18, −25
18) P3: (−3
2, 1 2, −3
2) P4: (−7
4, 5 12, −23
12) P5: (−11
12, −7 36, −47
36) P6: (−2
3, −1 9, −8
9) P7: (−1, 0, −1) P8: (−5
4, −1 12, −17
12)
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The volume of the parallelepiped is 1/18 cubic units. The coordinates of the the midpoint Q of the parallelepiped is
Q : (−29 24, 11
72, −101 72 ).
The hight of the parallelepiped with base described by Π2 is 1/√
6 units. ]
19. Consider the following two planes:
Π1 : x + 2y− 4z = 2 Π2 : x− z = 5.
Find the equation of the planes Π∗1, such that Π∗1 is the reflection of the plane Π1
about the plane Π2.
[Answer: Π∗1 : 4x− 2y − z = 23. ] 20. Consider the linear system Ax = b with
1 3 k k 1 4 1 k k
, b =
2
3
−3
,
where k is an unspecified real parameter.
a) Find all values of k, such that the given system admits a unique solution.
[Answer: The system admits a unique solution for all k ∈ R\{−2, 2, 3}. ]
b) Find all values of k, such that the given system admits infinitely many solutions, as well as all values of k for which the system is inconsistent.
[Answer: For k =−2 the system has infinitely many solutions, namely x = t
2 0 1
+
−1 1 0
for all t ∈ R. For k = 2 as well as for k = 3 the system is inconsistent. ]
c) Find all values of k, such that the coefficient matrix A is singular.
[Answer: The matrix A is singular if and only if det A = 0, that is, A is singular for k∈ {−2, 2, 3}. ]
21. The following three lines, 1, 2and 3, describe a triangle inR3at their intersections:
1 :
x = 4α− 1 y =−2α + 3
z = 8α− 3 for all α ∈ R
2 :
x =−3β + 7 y =−β + 4
z =−β + 3 for all β ∈ R
3 :
x =−δ + 6 y =−2δ + 7
z = 3δ− 4 for all δ ∈ R.
Find the area of this triangle.
[Answer: The area of the triangle is 5√
6 square units. ]
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22. Consider the homogeneous system Ax = 0, where
A =
1 5 1 k 2 1 k 1 1 4 1 1 4 1 3 1
and k is an unspecified real parameter.
a) Find all values of k, such that the system admits only the trivial solution and all values of k for which A is invertible.
[Answer: For all k ∈ R\{4 3, 7
5} the system admits only the trivial solution x = (0, 0, 0, 0). The matrix A is also invertible for those values of k. ]
b) Find all values of k, such that the system admits infinitely many solutions.
[Answer: For all k = 4
3 or k = 7
5 the system admits infinitely many solutions.]
Chapter 3
Spanning sets and linearly independent sets
The aim of this chapter:
In this chapter we introduce the following definitions and concepts for a finite set of vectors in Rn: linear combinations of vectors, spanning sets and linearly independent sets of vectors. We apply these concepts to describe, for example, a plane or a line in R3 and to gain a better understanding of linear systems.
3.1 Linear combinations of vectors
In this section we introduce the concept of a linear combination for a finite set of vectors inRn.
Theoretical Remarks
3.1.Consider the set S of p vectors S ={u1, u2, . . . , up}, where uj∈ Rn for j = 1, 2, . . . , p.
1. A linear combination of the vectors from the set S is another vector inRn, namely the vector
c1u1+ c2u2+· · · + cpup∈ Rn
for any fixed choice of the p constants c1, c2, . . ., cp, called the scaling factors of the linear combination. That is, v∈ Rn is a linear combination of the vectors from the set S if there exist scaling factors c1, c2, . . . , cp, such that
v = c1u1+ c2u2+· · · + cpup. 133
2. Consider v ∈ Rn and let A be an m× n matrix. Assume now that v is a linear
Then the matrix-vector product Ax is defined as the linear combination of the set of vectors{a1, a2, . . . , an} with scaling factors x1, x2, . . . , xn, i.e.
Ax = x1a1+ x2a2+· · · + xnan.
Remark: See also Theoretical Remark 2.1 (3) where the matrix-vector product Ax is discussed.
Problem
3.1.1.Consider the following set of five vectors inR3: S ={u1, u2, u3, u4, u5},
Consider also the vector
v =
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a) Show that v is a linear combination of the vectors in the set S and give the linear combination explicitly.
b) Is v a linear combination of the set of vectors{u1, u2}? Justify your answer.
c) Let A be an unspecified 3× 3 matrix, such that
Au1=
1
2
−1
, Au2 =
2 1 0
, Au3=
3 1 3
Au4=
−8 11
−18
, Au5 =
22
−13 32
.
Find Av explicitly.
Solution
3.1.1.a) We have to show that there exist real constants (scaling factors), c1, c2, c3, c4 and c5, such that
v = c1u1+ c2u2+ c3u3+ c4u4+ c5u5.
We write this vector equation in the form of a matrix equation, namely [u1 u2 u3 u4 u5] c = v,
With the given vectors uj, we have
and the following corresponding augmented matrix is
Applying several elementary row operations on this augmented matrix, we obtain its unique reduced echelon form, namely
We conclude that the constants c4 and c5 can be chosen arbitrarily, so we let c4 = t, c5 = s,
where t and s are arbitrary real parameters. From the above reduced echelon form we then have
where t and s are arbitrary real parameters. From the above reduced echelon form we then have