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Master’s Thesis

Semiclassical analysis

the double well potential in the semiclassical limit

Author:

T.J. Manschot

Supervisor:

Prof. dr. N.P. Landsman

Second reader:

Dr. M.H.A.H. M¨

uger

July 28, 2020

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Abstract

Semiclassical analysis deals with the relationship between classical dynamics and the behaviour of solutions to pseudodifferential operators depending on a small parameter h > 0. Let a : R2n→ C

be a function, then we can associate it with an operator aW(x, hD). In the context of quantum mechanics, taking the limit h → 0 is a way to study the classical limit of quantum mechanics. In the first part of this thesis, we will follow [8] and prove the Agmon-Lithner estimate and the Carleman inequality.

The second part of this thesis deals with double well potentials. We will study the behaviour of eigenfunctions of the Schr¨odinger operator P (h) = −h2∂2x+ V (x) where the double well potential V

is symmetric. Following Jona-Lasinio et al. [9], Helffer and Sj¨ostrand [3] and [4], and Simon [7], we will study the consequences of a small perturbation ∆V that breaks the symmetry of V .

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Contents

1 Introduction 2

1.1 acknowledgment . . . 2

2 Introduction to the Schr¨odinger equation 3 2.1 Wave functions . . . 3

2.2 Position and momentum operators . . . 3

2.3 Sobolev spaces . . . 4

2.4 Weak solutions . . . 5

3 Semiclassical Fourier analysis 6 3.1 Schwartz spaceS (Rn) . . . 6

3.2 Tempered distributionsS0(Rn) . . . 8

3.3 Uncertainty principle. . . 9

4 Semiclassical quantisation 12 4.1 Semiclassical quantisation for a ∈S (R2n) . . . . 12

4.2 Composition of the Weyl quantisation . . . 15

4.3 Symbol classes . . . 20

4.4 Computing the quantisation of various symbols . . . 29

5 Tunneling 32 5.1 G˚arding inequality . . . 32

5.2 Agmon-Lithner inequality . . . 34

5.3 Carleman inequality . . . 40

6 Multiple potential wells 44 6.1 Multiple single-well potentials . . . 44

6.2 The matrix representation of the Schr¨odinger operator . . . 48

6.3 The one-dimensional symmetric double-well potential. . . 50

7 Breaking the symmetry 52 7.1 Perturbation of the single-well potential . . . 52

7.2 Perturbation of the double-well potential. . . 53

7.3 Perturbed eigenvalues and eigenfunctions . . . 55

7.3.1 (a) 2δA> δ0. . . 55 7.3.2 (b) 2δA< δ0 . . . 56 8 Outlook 57 A Notation 58 B Basic inequalities 58 C Functional analysis 59

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1

Introduction

Two topics will be discussed in this thesis. In the first part, we will discuss semiclassical analysis as presented by Zworski [8]. We will consider certain classes of functions a : R2n→ C, (x, ξ) 7→ a(x, ξ), and

associate such functions with semiclassical pseudodifferential operators, i.e. pseudodifferential operators that are scaled with a small parameter h > 0. We will study the behaviour of such operators in the semiclassical limit h → 0.

In the context of quantum mechanics, we interpret R2n as the phase space. Then x is the position

variable and ξ is the momentum variable, and a function a : R2n → C is called a symbol. Then the

corresponding operator aW(x, hD) is a quantum observable, and the semiclassical limit h → 0 is actually the classical limit of quantum mechanics.

An important example is the total energy function p(x, ξ) := |ξ|2+ V (x), where |ξ|2 is the kinetic energy and V is the potential. This symbol gives rise to the Schr¨odinger operator P (h) := −h2∆+V . We

will prove the Agmon-Lithner estimate and the Carleman inequality for eigenfunctions of this operator in the limit h → 0.

We will need some preliminary definitions, which we will give in section 2. In section 3, we will give an overview of semiclassical Fourier analysis, which is just a rescaling of standard Fourier analysis by a parameter h > 0. The Fourier transformation will first be defined on the Schwartz space S (Rn). We

will then generalise the Fourier transformation to the dual spaceS0(Rn).

Section 4 deals with semiclassical quantisation. We will again start with symbols in S (R2n), which

give rise to bounded operators L2(Rn) → L2(Rn). We will then discuss larger classes of symbols

Sδ(m) where 0 ≤ δ ≤ 1/2 and m is a so-called order function. Such symbols give rise to

opera-tors S0(Rn) → S0(Rn). We will prove that symbols in S = S0(1) give rise to bounded operators

L2(Rn) → L2(Rn).

In section 5, we will prove several important inequalities. We will first prove the G˚arding inequality for symbols a ∈ S. Then we will prove the Agmon-Lither estimate and the Carleman estimate for eigen-functions of P (h).

In the second part, we will apply these results to a potential V that has multiple wells, following several papers from the 1980s. The main goal of this part is to provide a focused and detailed approach to the ideas presented by B. Helffer and J. Sj¨ostrand in [3] and [4] and by B. Simon in [7]. Two other important papers are Jona-Lasinio et al. [9] and Graffi et al. [10].

In section 6, we will consider the symmetric double-well potential, following Helffer [2]. The splitting of the lowest two eigenvalues of P (h) is of order ˜O(e−δ0/h), and the eigenfunctions corresponding to these

eigenvalues are symmetric. In section 7, we will consider a slightly perturbed potential ˜V = V + t∆V where t ∈ [−1, 1]. Surprisingly, even a very small perturbation has drastic consequences for the eigen-functions. If ∆V is supported close to one of the wells, the eigenfunctions will be localised in just one of the wells, even if t = e−γ/h for some sufficiently small constant γ > 0. As a result, the perturbed eigenfunctions are not even approximately symmetric.

1.1

acknowledgment

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2

Introduction to the Schr¨

odinger equation

In this section, we will introduce the position and momentum operators, as well as the Schr¨odinger operator P (h) and its eigenfunctions.

2.1

Wave functions

In classical physics, a particle’s state is just its position x and its momentum p := m ˙x. These develop over time according to the differential equation F = m∂2

tx, where ∂t := dtd. In quantum mechanics, a

particle’s position and momentum are not localised as points in phase-space. Instead, a particle’s state is given by its so-called wave function u : R × Rn→ C, (t, x) 7→ u(t, x).

This wave function u is a probability amplitude in the sense that |u(x)|2= u(x)u(x) is a probability density function, i.e. the probability of finding the particle in U ⊆ Rn is given by kuk

L2(U ). For this

reason, we have u ∈ L2(Rn) and kuk

L2(Rn)= 1. Moreover, wave functions solve the Schr¨odinger equation

i~∂tu(t, x) = −~ 2

2m∆u(t, x) + V (x)u(t, x) (2.1) where ~ is the Planck constant, m the particle’s mass, and the map V : Rn → R is the potential.

We will simplify this equation by setting m = 1/2 and replacing ~ with a dimensionless constant h > 0. Moreover, we will consider stationairy states, i.e. functions u such that ih∂tu ≡ 0.

Definition 2.1. (Schr¨odinger operator) Let h > 0 and let V : Rn → R be a smooth function not depending on h, then the Schr¨odinger operator P (h) is defined by

P (h)u = −h2∆u + V u, (2.2) In subsections 2.3 and 2.4, we will define the appropriate domain of P (h) as well as what it means for a function u to solve the time-independent Schr¨odinger equation P (h)u = E(h)u.

2.2

Position and momentum operators

We will now consider the position operator Xj and the momentum operator Pj, where 1 ≤ j ≤ n. For

any wave function u ∈ L2(Rn), kuk = 1, the expectation values are hu, X

jui and hu, Pjui. We will use

the convention that

Dxj := 1 i ∂ ∂xj . Then hu, Xjui = Eu(Xj) = Z Rn dxxj|u(x)|2 = hu, xjuiL2, hu, Pjui = Eu(Pj) = 1 2∂tEu(Xj) = Z Rn dx 1 2xj∂t(u(x)u(x))  = Z Rn dx 1 2xj 

(∂tu(x))u(x) + u(x)(∂tu(x))

 = Z Rn dx 1 2xj  1 −ih(−h

2∆u(x) + V (x)u(x))u(x) + u(x)1

ih(−h 2∆u(x) + V (x)u(x))  = Z Rn dx h 2ixj  ∆u(x)u(x) − u(x)∆u(x)  = Z Rn dx h 2xjiD ·  u(x)Du(x) − u(x)Du(x)  = − Z Rn dx h 2ej·  u(x)Du(x) − u(x)Du(x)  = Z Rn dxhu(x)hDxju(x) i = hu, hDxjuiL2.

Hence Xju = xju and Pju = hDu. In order to avoid confusion, we will always denote the momentum

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2.3

Sobolev spaces

We have seen that wave functions u are quadratically integrable, i.e. u ∈ L2(Rn), and that they need to

satisfy the Schr¨odinger equation (equation2.1). However, most functions in L2(Rn) are not differentiable.

To overcome this problem, we will recall the notion of weak derivative and the Sobolev function space Hk(Rn).

Definition 2.2. (Test functions) Let U ⊆ Rn be open, then a function ϕ : U → C is called a test function

if it is smooth and compactly supported. The space of such functions is denoted by Cc∞(U ).

Note that test functions vanish at the boundary ∂U . This follows from the fact that they are sup-ported on a compact subset of U and the fact that U is open.

Now let ϕ ∈ C∞

c (U ) and let α := (α1, . . . , αn) be a multi-index (i.e. α ∈ Nn) such that |α| :=

α1+ . . . + αn≤ k. If we assume that u ∈ Ck(U ), then the partial derivative

Dαu := 1 i|α| ∂α1 ∂xα1 1 . . . ∂ αn ∂xαn n u (2.3)

exists, and we can obtain the equality Z U dx[u(x)Dαϕ(x)] = (−1)|α| Z U dx[Dαu(x)ϕ(x)]

by integrating by parts |α| times. In case u /∈ Ck(U ), we will use this equation to define generalise Dαu.

Let v be some function. We want Z U dx[u(x)Dαϕ(x)] = (−1)|α| Z U dx[v(x)ϕ(x)],

because then we can set Dαu := v. Clearly, these integrals can only exist if the functions u and v are integrable on Supp(ϕ) for all ϕ ∈ Cc∞(U ). This motives the following two definitions.

Definition 2.3. (Locally integrable functions) Let U ⊆ Rn be open and let u : U → C be a function.

Then u is called locally integrable if

u|V ∈ L1(V )

for all open V ⊂⊂ U , i.e. for all open V ⊆ U such that V is compact and V ⊂ U . The set of locally integrable functions is denoted L1

loc(U ).

Definition 2.4. (Weak derivatives) Let u, v ∈ L1

loc(U ) and let α be a multi-index, then Dαu := v is

called the weak αth partial derivative of u if

Z U dx[u(x)Dαϕ(x)] = (−1)|α| Z U dx[v(x)ϕ(x)] for all ϕ ∈ Cc∞(U ).

Lemma 2.5. (Uniqueness of weak derivatives) Weak derivatives are unique up to sets of Lebesgue-measure zero.

Proof. Let u, v, v0∈ L1

loc(U ) and let α := (α1, . . . , αn) be a multi-index. Assume that v and v0 are weak

αth partial derivatives of u. Then we have for all test functions ϕ ∈ Cc∞(U ) that

(−1)|α| Z U dx[v(x)ϕ(x)] = Z U dx[u(x)Dαϕ(x)] = (−1)|α| Z U dx[v0(x)ϕ(x)].

But then we have

Z

U

dx[(v(x) − v0(x))ϕ(x)] = 0 for all ϕ ∈ Cc∞(U ), hence v = v0 almost everywhere.

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Of course, weak derivatives need not exist in general. We will consider spaces of square integrable functions that have weak derivatives up to some degree k ∈ N.

Definition 2.6. (Sobolev spaces) Let U ∈ Rn be open and let k ∈ N, then the Sobolev space Hk(U )

consists of all functions u ∈ L2(U ) have weak derivatives Dαu ∈ L2(U ) for all multi-indices α such that

|α| ≤ k.

We can define an inner product on Hk(U ) by

hu, viHk(U ):=

X

|α|≤k

hDαu, Dαvi

L2(U ), (2.4)

making Hk(U ) into a Hilbert space.

2.4

Weak solutions

The definition of weak solutions u of P (h)u = E(h)u is analogous to the definition of the weak derivative. Let u such that P (h)u = E(h)u and let v be some function. Then

0 = hv, (P (h) − E(h))ui =

Z

Rn

dxhv(x) −h2∆u(x) + V (x)u(x) − E(h)u(x)i

= −h2 n X j=1 Z Rn dxhv(x)∂j2u(x)i+ Z Rn dxhv(x)(V (x) − E(h))u(x)i = h2 n X j=1 Z Rn dxh∂jv(x)∂ju(x) i + Z Rn dxhv(x)(V (x) − E(h))u(x)i = hv, (V − E(h))ui + n X j=1 hhDjv, hDjui.

Definition 2.7. (Weak solutions of the Schr¨odinger equation) A function u ∈ H1(Rn) possibly depending

on h is called a weak solution of P (h)u = E(h)u if

hv, (V − E)ui +

n

X

j=1

hhDjv, hDjui = 0 (2.5)

for all v ∈ Cc(Rn). A function u ∈ H1(Rn) is called a solution to the Schr¨odinger equation if it is a

weak solution of P (h)u = E(h)u and kukL2(Rn)= 1.

Since we mostly deal with the momentum operator hD instead of the differential operator D, it makes sense to scale the Sobolev norm accordingly.

Definition 2.8. (Semiclassical Sobolev norm) Let U ⊆ Rn be open. The semiclassical Sobolev norm on the space Hk(U ) is given by

kukHk h(U ):=   X |α|≤k khDαuk2L2(U )   1/2 . (2.6)

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3

Semiclassical Fourier analysis

In this section, we will discuss semiclassical Fourier theory. The semiclassical Fourier transformFh is a

rescaling of the standard Fourier transform using the parameter h > 0. ThenFh maps ϕ(x) into ˆϕh(ξ)

such that (hD)αϕ 7→ ξαϕˆ

h and (−x)αϕ 7→ (hD)αϕˆh.

3.1

Schwartz space

S (R

n

)

Our goal is to define the semiclassical Fourier transform on a large class of functions, but we will start with just the so-called Schwartz functions. Schwartz functions behave very nicely in the sense that all their derivatives decrease rapidly as |x| → ∞, as does the function itself. An example of such a function is the Gaussian function ϕ(x) := e−π|x|2

.

Definition 3.1. (Schwartz space) The Schwartz spaceS (Rn) consists of all functions ϕ ∈ C(Rn) such

that

sup

x∈Rn

|xαβϕ(x)| < ∞

for all multi-indices α, β.

Note that kϕkα,β := supx∈Rn|xα∂βϕ(x)| is a seminorm onS (Rn) for each pair of multi-indices α, β.

This collection of seminorms defines a topology onS as follows. Consider V (α, β, k) := {ϕ ∈S (Rn) | kϕkα,β <

1 k}.

The collection of finite intersections of such sets is a convex, balanced local base of a topology inS (Rn) turning it into a locally convex space such that all seminorms are continuous.

A subset U ⊂S (Rn) is bounded if and only if {kϕk

α,β | ϕ ∈ U } is bounded for all multi-indices α, β.

It should be noted that all k · kα,β are actually norms, and that the spacesS (Rn) with this norm is a

Fr´echet space.

It is easy to see that Cc(Rn) ⊂S (Rn) ⊂ L2(Rn). Recall that C

c (Rn) is dense in L2(Rn), then it

follows trivially thatS (Rn) is dense in L2(Rn) in the L2-norm.

Definition 3.2. (Semiclassical Fourier transform) Let ϕ ∈S , then its semiclassical Fourier transform ˆ ϕh is defined by ˆ ϕh(ξ) :=Fh(ϕ)(ξ) := Z Rn dxhϕ(x)e−hihx,ξi i (3.1) where ξ ∈ Rn.

Remark 3.3. In case h = 1, we also write F := F1 and ˆϕ := ˆϕ1, which is the standard Fourier

transform. Note that some authors define the Fourier transform with a normalisation factor 1/(2πh)n/2.

Proposition 3.4. (Properties of the semiclassical Fourier transform) The semiclassical Fourier trans-formFh:S → S is an isomorphism, whose inverse is given by

ϕ(x) = 1 (2πh)n Z Rn dξhϕˆh(ξ)e i hhx,ξi i

for all x ∈ Rn. Furthermore, we have the following equalities:

(i) Fh((hDx)αϕ) = ξαFh(ϕ),

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Proof. We will only show that equalities (i) and (ii) hold. The other statements are well-known facts from standard Fourier theory. Let ξ ∈ Rn, then we have

Fh((hDx)αϕ)(ξ) = Z Rn dxh(hDx)αϕ(x)e− i hhx,ξi i = (−1)|α| Z Rn dxhϕ(x)(hDx)αe− i hhx,ξi i = (−1)|α| Z Rn dx  ϕ(x) h i α −i hξ α e−hihx,ξi  = ξα Z Rn dxhϕ(x)e−hihx,ξi i = ξαFh(ϕ)(ξ), (hDξ)α(Fh(ϕ))(ξ) = (hDξ)α Z Rn dxhϕ(x)e−hihx,ξi i = Z Rn dxhϕ(x)(hDξ)αe− i hhx,ξi i = Z Rn dxhϕ(x)(−x)αe−hihx,ξi i =Fh((−x)αϕ)(ξ).

Lemma 3.5. (More properties) Let ϕ, ψ ∈S , then we have Z Rn dx [Fh(ϕ)(x)ψ(x)] = Z Rn dx [ϕ(x)Fh(ψ)(x)] (3.2) and Z Rn dxhϕ(x)ψ(x)i= 1 (2πh)n Z Rn dxhFh(ϕ)(x)Fh(ψ)(x) i . (3.3) Proof. Z Rn dx [Fh(ϕ)(x)ψ(x)] = Z Rn dx Z Rn dyhϕ(y)e−hihy,xi i ψ(x)  = Z Rn dy Z Rn dxhψ(x)e−hihx,yi i ϕ(y)  = Z Rn dx [ϕ(x)Fh(ψ)(x)]

This proves equation (3.2). Now we can substitute ϕ withFh(ϕ) to obtain

Z Rn dxhFh(ϕ)(x)Fh(ψ)(x) i = Z Rn dxhFh(Fh(ϕ))(x)ψ(x) i . Note thatFh(ϕ)(ξ) = R Rndy h ϕ(x)ehihy,ξi i = (2πh)nF−1 h (ϕ)(ξ), so Fh(Fh(ϕ))(x) = (2πh)nϕ(x).

Hence k ˆϕhk = (2πh)n/2kϕk. We will now prove a few norm estimates that will prove useful later.

The notation hxi := (1 + |x|2)1/2 will be convenient. Note that RRndx[hxi−(n+1)] < ∞ and there is a

constant C > 0 such that hxik≤ C max

|α|≤k|xα| for all x ∈ Rn, k ∈ N.

Lemma 3.6. (norm estimates) Let u ∈S and h > 0, then there is some constant C > 0 such that kˆuhkL∞ ≤ kukL1 (3.4) kukL∞ ≤ 1 (2πh)nkˆuhkL1 (3.5) kˆuhkL1 ≤ C max |α|≤n+1k∂ αuk L1 (3.6)

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Proof. kˆuhkL∞ = sup ξ∈Rn |ˆuh(ξ)| = sup ξ∈Rn Z Rn dxhu(x)ehihx,ξi i ≤ sup ξ∈Rn Z Rn dx u(x)e i hhx,ξi = sup ξ∈Rn Z Rn dx|u(x)| = kukL1 kukL∞ = sup x∈Rn |u(x)| = sup x∈Rn 1 (2πh)n Z Rn dξhuˆh(ξ)e i hhx,ξi i ≤ 1 (2πh)n Z Rn dξ uˆh(ξ)e i hhx,ξi = 1 (2πh)n Z Rn dξ|ˆuh(ξ)| = 1 (2πh)nkˆuhkL1 kˆuhkL1 = Z Rn dξ|ˆuh(ξ)| = Z Rn dξh|ˆuh(ξ)|hξin+1hξi−(n+1) i ≤ C Z Rn dξ  hξi−(n+1) max |α|≤n+1|ˆuh(ξ)ξ α|  ≤ C max |α|≤n+1kˆuhξ αk L∞ Z Rn dξhhξi−(n+1)i ≤ C max |α|≤n+1kˆuhξ αk L∞ ≤ C max |α|≤n+1k∂ αuk L1

3.2

Tempered distributions

S

0

(R

n

)

The Schwartz space is very small class of functions, so our goal is to extend the Fourier transform to a wider class of functions. Let u : Rn → C be a quadratically integrable function. Then we can define a

continuous linear map u : S → C by u(ϕ) := RRndx [u(x)ϕ(x)]. This will serve as motivation for the

following definition.

Definition 3.7. (Tempered distributions) The set

S0(Rn) := {u :S → C | u is linear and continuous } (3.7)

is the dual space ofS (Rn) and maps u ∈S0 are called tempered distributions.

A sequence {uj}j∈N⊂S0 is said to converge inS0 if there is a map u ∈S0 such that {uj(ϕ)}j∈N⊂ C

converges to u(ϕ) for all ϕ ∈S . For u ∈S0, we will sometimes write

Z

Rn

dx [u(x)ϕ(x)] := u(ϕ)

even though such a locally integrable function u : Rn→ C does not exist in general.

Definition 3.8. (More on tempered distributions) Let u ∈S0 and ϕ ∈S . Let α be a multi-index and let x ∈ Rn, then we define:

(i) Dαu(ϕ) := (−1)|α|u(Dαϕ), in the same spirit as the weak derivative. Note that Dαϕ and hence Dαu is guaranteed to exist.

(ii) (xαu)(ϕ) := u(xαϕ)

(iii) We take equation (3.2) as a definition for the semiclassical Fourier transform on tempered distri-butions, i.e. (Fhu)(ϕ) := u(Fhϕ).

Example 3.9. (Dirac delta function) Let x0∈ Rn, then we define the Dirac delta function δx0 at x0 by

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at x0 and zero everywhere else, such that its integral is

R

Rndx[δx0(x)] = 1. Then we have for any ϕ ∈S

that RRndx[δx0(x)ϕ(x)] = ϕ(x0).

We can calculate its Fourier transform by

(Fhδx0)(ϕ) := δx0(Fhϕ) =Fhϕ(x0) = Z Rn dx[ϕ(x)e−hihx,x0i]. In other words,Fhδx0(x) := e −i hhx,x0i. In particular,F h(δ0) ≡ 1.

Many of the properties ofFh:S (Rn) →S (Rn) hold more generally.

Remark 3.10. (Semiclassical Fourier transform on L2) Let u ∈ L2(Rn), then we can interpret u as a

tempered distribution defined by

ϕ 7→ Z

Rn

dx [u(x)ϕ(x)]

where ϕ ∈S . Then we have for the semiclassical Fourier transform ˆuh of u ∈ L2 that

Z Rn dξ [ˆuh(ξ)ϕ(ξ)] := Z Rn dx [u(x) ˆϕh(x)] = Z Rn dx Z Rn dξhu(x)ϕ(ξ)e−hihx,ξi i = Z Rn dξ Z Rn dxu(x)e−hihx,ξi  ϕ(ξ) 

for all ϕ ∈ S . So equation (3.1) is still valid for L2-functions. The same is true for the inverse

semiclassical Fourier transform. As a result, lemma3.5holds for L2-functions as well.

Proposition 3.11. (Properties of the semiclassical Fourier transform on tempered distributions) Let u ∈S0, x, ξ ∈ Rn, and let α be a multi-index. Then we have

(i) Fh((hDx)αu) = ξαFh(u), and

(ii) Fh((−x)αu) = (hDξ)αFh(u).

Proof. For all ϕ ∈S , we have

Fh((hD)αu) = (hD)αu(Fh(ϕ)) = (−1)|α|u((hD)αFh(ϕ)) = (−1)|α|u(Fh((−x)αϕ))) =Fh(u)(ξαϕ) = ξαFh(u)(ϕ) Fh((−x)αu)(ϕ) = (−ξ)αu(Fh(ϕ)) = u((−ξ)αFh(ϕ)) = (−1)αu(Fh((hD)αϕ)) = (−1)αFh(u)((hD)αϕ) = (hD)αFh(u)(ϕ)

3.3

Uncertainty principle

In this subsection, we will prove Heisenberg’s uncertainty principle. Let u ∈S (Rn) such that kuk = 1 and let 1 ≤ j ≤ N . Consider the standard deviation of position σxj and the standard deviation of

momentum σhDj. Note that

σ2xj = hu, x2jui − hu, xjui2,

σ2hDj = hu, (hDj)

2ui − hu, hD jui2.

Then Heisenberg’s uncertainty principle states that σxjσhDj ≥ h/2. We interpret that the position and

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The relation between a wave function u(x) and its semiclassical Fourier transform ˆuh(ξ) is

charac-terised by equation (3.3), i.e. for u ∈S (Rn), the expectation values for the position and momentum operators in direction 1 ≤ j ≤ n are given by

hu, xjui = Z Rn dxhu(x)xju(x) i = 1 (2πh)n Z Rn dξhFh(u)(ξ)Fh(xju)(ξ) i = 1 (2πh)n Z Rn dξhuˆh(ξ)(−hDj)ˆuh(ξ) i = 1 (2πh)nhˆuh, −hDjuˆhi, hu, hDjui = Z Rn dxhu(x)hDju(x) i = 1 (2πh)n Z Rn dξhFh(u)(ξ)Fh(hDju)(ξ) i = 1 (2πh)n Z Rn dξhuˆh(ξ)ξjuˆh(ξ) i = 1 (2πh)nhˆuh, ξjuˆhi.

For this reason, u(x) is said to be the wave function in position coordinates, and ˆuh(ξ) the wave function

in momentum coordinates.

Lemma 3.12. (Shifting the position coordinates) Let u ∈S (Rn) such that kuk

L2(Rn)= 1 and let a ∈ Rn,

then we can shift the coordinates by setting x y := x − a and v(y) := u(y + a). The shifted wave function v satisfies hv, yvi = hu, xui − a and hv, hDvi = hu, hDui.

Proof. This is a fairly straightforward computation. Let 1 ≤ j ≤ n, then hv, yjvi = Z Rn dyhv(y)yjv(y) i = Z Rn

dyhu(y + a)yju(y + a)

i = Z Rn dxhu(x)(xj− aj)u(x) i = hu, xjui − aj, ˆ vh(ξ) = Z Rn dyhv(y)e−hihy,ξi i = Z Rn

dyhu(y + a)e−hihy,ξi

i = Z Rn dxhu(x)e−hihx−a,ξi i = ehiha,ξiuˆh(ξ), hˆvh, ξjˆvhi = Z Rn dξhvˆh(ξ)ξjˆvh(ξ) i = Z Rn dξhehiha,ξiuˆh(ξ)ξje i hha,ξiuˆh(ξ) i = Z Rn dξhuˆh(ξ)ξjuˆh(ξ) i = hˆuh, ξjuˆhi.

Lemma 3.13. (Shifting the momentum coordinates) Let u ∈S (Rn) such that kuk

L2(Rn)and let b ∈ Rn,

then we can shift the coordinates by setting ξ η := ξ − b and ˆvh(η) := ˆuh(η + b). The shifted wave

function v satisfies hv, xvi = hu, xui and hv, hDvi = hu, hDui − b. Proof. This is analogous to the previous lemma.

Corollary 3.14. By setting a := hu, xui and b := hu, hDui, we obtain a shifted wave function v such that hv, xvi = hv, hDvi = 0. So for any u ∈S (Rn) such that kukL2(Rn), we can assume without loss of

generality that σ2xj = hu, x2jui = kxjuk2, σ2hD j = hu, (hDj) 2ui = khD juk2.

From now on, we will write kxjuk and khDjuk = (2πh)−n/2kξjuˆhk instead of σxj and σhDj. Only

one more lemma is needed before the uncertainty principle can be proved.

Lemma 3.15. (Commutation relation of position and momentum) The commutation relation of the position and momentum operators xj and hDj as operatorsS (Rn) →S (Rn) is given by

[xj, hDj] := xjhDj− hDjxj = ih.

Proof. Let u ∈S (Rn). Then we can simply compute that

[xj, hDj]u = xjhDju − hDj(xju) =

h

i(xj∂xju − ∂xj(xju)) = −

h

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Proposition 3.16. (Heisenberg uncertainty principle) Let u ∈S (Rn), then kxjukkξjuˆhk ≥

h

2kukkˆuhk. (3.8) In particular, if kukL2(Rn)= 1, then

kxjukkhDjuk ≥

h

2. (3.9)

Proof. Let u ∈S (Rn). Using the Cauchy-Schwarz inequality and the previous lemma we obtain

kxjukkhDjuk ≥ |hhDju, xjui| ≥ |=hhDju, xjui|

= 1 2|hhDju, xjui − hxju, hDjui| = 1 2|h(xjhDj− hDjx)u, ui| = 1 2|h[xj, hDj]u, ui| = h 2kuk 2, hence kxhukkξjuˆhk = kxjuk(2πh)n/2khDjuk ≥ h 2(2πh) n/2kuk2=h 2kukkˆuhk.

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4

Semiclassical quantisation

In classical mechanics, the state of a system is completely determined by the position and momentum variables, and all dynamical quantities are a function of said variables. In the context of semiclassical quantisation, such a function is called a symbol. Examples are: the kinetic energy T := ξ2or the angular

momentum L := x × ξ (where × is the outer product on R3).

In quantum mechanics, the operators associated with the position and momentum are x and hD, respectively. This raises the question what operators are associated with the other symbols. In this section, we will discuss this for various classes of symbols.

Definition 4.1. (Symbols) A function a : R2n→ R, (x, ξ) 7→ a(x, ξ) is called a symbol.

Since x and hD do not commute, we can immediately see that there is no canonical way to quantise symbols that are linear in both arguments, such as a(x, ξ) := hx, ξi. We could pick any linear combination

a(x, ξ) = thx, ξi + (1 − t)hξ, xi. This motivates the following definition.

Definition 4.2. (Semiclassical quantisation) Let t ∈ [0, 1] and let a(x, ξ) be a symbol, then the semi-classical pseudodifferential operator Opt(a) is defined by

Opt(a)u(x) := 1 (2πh)n Z Rn dξ Z Rn

dyha(tx + (1 − t)y, ξ)u(y)ehihx−y,ξi

i

. (4.1)

In particular, we will be interested in the standard quantisation a(x, hD) := Op1(a) and the Weyl

quan-tisation aW(x, hD) := Op 1 2(a).

Remark 4.3. In subsections 4.1, we will show that Opt(a) : L2(Rn) → L2(Rn) is indeed well-defined for

symbols a ∈S (R2n). In subsection 4.3, we will show that Op

t(a) :S0(Rn) →S0(Rn) is well-defind for

symbols a ∈ Sδ(m).

The Weyl quantisation is the most important quantisation formula because it gives rise to a self-adjoint operator if the symbol a is real-valued. The standard quantisation is important because

a(x, hD)u(x) = 1 (2πh)n Z Rn dξ Z Rn

dyha(x, ξ)u(y)ehihx−y,ξi

i = 1 (2πh)n Z Rn dξha(x, ξ)Fhu(ξ)e i hhx,ξi i =Fh−1(a(x, ·)Fhu(·))(x),

for a ∈S (R2n) and u ∈S (Rn). This makes that standard quantisation easier to compute. The other Opt are useful because they allow us to transfer computations from the standard quantisation to the

Weyl quantisation, as we will see in the proof of lemma4.38.

4.1

Semiclassical quantisation for a ∈

S (R

2n

)

The following defintion gives a very convenient way to abbreviate the formula for Opt(a).

Definition 4.4. (Kernel of Opt) Let t ∈ [0, 1], then we define the kernel Kt of Opt by

Kt(x, y) :=

1 (2πh)n

Z

Rn

dξha(tx + (1 − t)y, ξ)ehihx−y,ξi

i =Fh−1(a(tx + (1 − t)y, ·))(x − y).

Note that Opt(a)u(x) =RRndy [Kt(x, y)u(y)].

Now assume that a ∈ S (R2n). SinceFh−1 :S (Rn) → S (Rn), we also have Kt(x, ·) ∈S (Rn). So

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Lemma 4.5. Let a ∈S (R2n) be a symbol, t ∈ [0, 1], then Opt(a) :S0→S is continuous.

Proof. Consider a sequence uj → u converging inS0(Rn) and let α, β be multi-indices. Then

xα∂β(u(Kt(x, ·)) − uj(Kt(x, ·))) = u(xα∂βKt(x, ·)) − uj(xα∂βKt(x, ·)) → 0,

hence Opt(a)uj → Opt(a)u inS (Rn) and Opt(a) is indeed continuous.

Proposition 4.6. Let a ∈S (R2n) and let h > 0, then the operator

aW(x, hD) : L2(Rn) → L2(Rn)

is bounded uniformly in h, i.e. there is some constant C > 0 not depending on h such that we have kaW(x, hD)uk ≤ Ckuk for all u ∈ L2(Rn).

Proof. We have a ∈S (R2n), and so K

1/2∈S (R2n). Define the two constants

C1:= sup x∈Rn Z Rn dy|K1/2(x, y)| < ∞, C2:= sup y∈Rn Z Rn dx|K1/2(x, y)| < ∞,

then the L2-norm of aW(x, hD)u is

kaW(x, hD)uk2= haW(x, hD)u, aW(x, hD)ui

≤ Z Rn dx Z Rn dy Z Rn dz|K1/2(x, y)||u(y)||K1/2(x, z)||u(z)|  ≤ Z Rn dx Z Rn dy Z Rn dz  |K1/2(x, y)||K1/2(x, z)| 1 2 |u(y)| 2+ |u(z)|2  = Z Rn dx Z Rn dy Z Rn dz|K1/2(x, y)||K1/2(x, z)||u(y)|2  ≤ C1C2 Z Rn dy|u(y)|2 = C1C2kuk2

Theorem 4.7. Let a ∈S (R2n), then the operator aW(x, hD) : L2→ L2 is compact.

Proof. Recall the definition of a compact operator (see C.1). The operator aW(x, hD) is compact if

for any bounded sequence {uk}k∈N ⊂ L2(Rn), the sequence {aW(x, hD)uk}k∈N ⊂ L2(R2n) has some

converging subsequence.

Let {uk}k∈N⊂ L2(Rn) be a bounded sequence and let k, l ∈ N. We want to find a subsequence {u0k}

of {uk} such that the sequence {aW(x, hD)u0k} converges. Let N ∈ N be some fixed constant (we will

later choose N > n/2), then we have for some sufficiently large constant C > 0 that kaW(x, hD)u k− aW(x, hD)ulkL2 = Z Rn dx|aW(x, hD)u k(x) − aW(x, hD)ul|2  = Z Rn

dxhxi−2N|hxiN(aW(x, hD)u

k(x) − aW(x, hD)ul(x))|2

 ≤ CkhxiN(aW(x, hD)u

k− aW(x, hD)ul)kL∞.

So it suffices to show that the sequence {hxiNaW(x, hD)u0

k} converges in the sup-norm. We will first

construct a candidate subsequence {u0k} and then prove that hxiNaW(x, hD)u0

k indeed converges

uni-formly.

For any x ∈ Rn, the sequence {hxiNaW(x, hD)uk(x)}k∈N ⊂ C is bounded and therefore admits a

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s.t. Qn = S

p∈N{qp}. We inductively define subsequences {u (j)

k }k∈N, j ∈ N, such that {u (j)

k }k∈N

{u(j−1)k }k∈N such that {hqjiNaW(x, hD)u (j)

k (qj)}k∈N converges. Define {u0k}k∈N by u0k := u (k) k , then

{hqiNaW(x, hD)u0

k(q)}k∈Nconverges for all q ∈ Qn.

Let  > 0. Our goal is to show that there is some K ∈ N such that for all k, l ≥ K and all x ∈ Rn, |hxiNaW(x, hD)u0

k(x) − hxi

NaW(x, hD)u0

l(x)| < . Choose N > n/2, and let α, β be multi-indices. Due

to a ∈S (R2n) there exists some C > 0 s.t. sup x∈Rn |xαβ(aW(x, hD)u)| ≤ sup (x,y)∈R2n |xαβ xhyi NK(x, y)| Z Rn dyhyi−N|u(y)| ≤ CkukL2,

where we used the Cauchy-Schwartz inequality. The sequence {u0k}k∈N is bounded in the L2-norm, so

there is some M > 0 such that for all k ∈ N, x ∈ Rn, |∂hxiNaW(x, hD)u0

k(x)| < M/3, hxiN +1|aW(x, hD)u0k(x)| < M/2.

We will consider two cases: where x is inside some open neighbourhood of 0, and where x is far away from 0. Let R > 0 be large enough such that M/R ≤ . Then

sup |x|≥R |hxiNaW(x, hD)u0 k(x) − hxi NaW(x, hD)u0 l(x)| ≤ R−1 sup |x|≥R |hxiN +1aW(x, hD)u0 k(x)| + R −1 sup |x|≥R |hxiN +1aW(x, hD)u0 l(x)| < M/R < .

Finally, {B(q, /M )}q∈Qnis an open cover of B(0, R), and so there is a finite subcover {B(qp, /M )}1≤p≤P.

For all 1 ≤ p ≤ P , {hqpiNaW(x, hD)u0k(qp)}k∈N converges. So there is some K ∈ N such that for all

k, l ≥ K, 1 ≤ p ≤ P ,

|hqpiNaW(x, hD)u0k(qp) − hqpiNaW(x, hD)u0l(qp)| < /3.

For any x ∈ B(0, R), choose 1 ≤ p ≤ P such that x − qp< /M , then for all k, l ≥ K;

|hxiNaW(x, hD)u0 k(x) − hxi NaW(x, hD)u0 l(x)| ≤ |hxiNaW(x, hD)u0 k(x) − hqpiNaW(x, hD)u0k(qp)| + |hqpiNaW(x, hD)u0k(qp) − hqpiNaW(x, hD)u0l(qp)

+ |hxiNaW(x, hD)u0l(x) − hqpiNaW(x, hD)u0l(qp)|

< /3 + |x − qp|(sup x |∂hxiNaW(x, hD)u0 k(x)| + sup x |∂hxiNaW(x, hD)u0 l(x)|) < .

Proposition 4.8. (Formal adjoint) Let t ∈ [0, 1] and let a ∈S (R2n). Then the formal adjoint of Opt(a)

is Op1−t(a), i.e. for all u, v ∈ L2(Rn),

hu, Opt(a)vi = Z Rn dxhu(x)Opt(a)v(x) i = Z Rn dxhOp1−t(a)u(x)v(x) i = hOp1−t(a)u, vi.

Proof. Let Kt be the kernel of Opt(a), then its complex conjugate is

Kt(x, y) =

1 (2πh)n

Z

Rn

dξha(tx + (1 − t)y, ξ)e−hihx−y,ξi

i

= 1 (2πh)n

Z

Rn

dξha((1 − t)y + (1 − (1 − t))x, ξ)ehihy−x,ξi

i ,

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which is precisely the kernel of Op1−t(a). Hence hu, Opt(a)vi = Z Rn dxhu(x)Opt(a)v(x) i = Z Rn dx Z Rn dyhu(x)Kt(x, y)v(y) i = Z Rn dx Z Rn dyhKt(x, y)u(x)v(y) i = Z Rn dyhOp1−t(a)u(y)v(y) i = hOp1−t(a)u, vi.

Lemma 4.9. Let a ∈S0(Rn× Rn), then Op

t(a) :S → S0.

Proof. If a ∈S0(Rn×Rn), then K

t∈S0(Rn×Rn). Now let u, v ∈S (Rn) and define v ⊗u ∈S (Rn×Rn)

by v ⊗ u(x, y) := v(x)u(y). Then we can define Opt(a)u ∈S0(Rn) by Opt(a)u(v) := Kt(v ⊗ u).

4.2

Composition of the Weyl quantisation

Let a, b be symbols, then we can ask what should be the symbol c such that cW(x, hD) = aW(x, hD)bW(x, hD).

We will denote this symbol by a#b := c. In this subsection, we will prove that a#b(z) = e2hiσ(hDz,hDw)(a(z)b(w))|

z=w.

In order to prove this, we will decompose symbols into Fourier components. The following lemmas will be useful.

Definition 4.10. (Linear symbols) A symbol l of the form l(z) := hz∗, zi = hx, xi + hξ, ξi for some

z∗= (x∗, ξ∗) ∈ R2n is called a linear symbol. We will identify linear symbols l with their point z∈ R2n.

Now let a ∈S (R2n), then its semiclassical Fourier transform and its inverse are

ˆ ah(l) = Z R2n dzha(z)e−hil(z) i , a(z) = 1 (2πh)2n Z R2n dlhˆah(l)e i hl(z) i ,

and so the quantisation is

Opt(a) = 1 (2πh)2n Z R2n dlhˆah(l)Opt  ehil(·) i .

for all t ∈ [0, 1]. The following lemmas deal with the quantisation and composition of such exponentials. Lemma 4.11. (Quantisation of linear symbols) Consider the linear symbol l(x, ξ) := hx∗, xi + hξ∗, ξi, then we have for all t ∈ [0, 1] that

Opt(l)u(x) = (hx∗, xi + hξ∗, hDi)u(x) (4.2)

Proof. This is just a simple calculation. Opt(l)u(x) = 1 (2πh)n Z Rn dξ Z Rn

dyhehihx−y,ξil(tx + (1 − t)y, ξ)u(y)

i = thx∗, xiu(x) + (1 − t)Fh−1◦Fh(hx∗, ·iu(·))(x) +Fh−1(hξ

, ·iˆu h(·))(x)

= hx∗, xiu(x) + hξ∗, hDxiu(x).

Lemma 4.12. (Quantisation of exponentials of linear symbols) Let l be a linear symbol, and define the symbol a(z) := ehil(z). Then we have

Opt(a)u(x) := e i hhx ∗,xi+i h(1−t)hx ∗i u(x + ξ∗). (4.3) for all t ∈ [0, 1].

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Proof. Again, we can simply calculate Opt(a)u(x) = 1 (2πh)n Z Rn dξ Z Rn

dyhehihx−y,ξiehil(tx+(1−t)y,ξ)u(y)

i = 1 (2πh)n Z Rn dξ Z Rn dyhehihx−y,ξie i hhx ∗,tx+(1−t)yi+i hhξ ∗,ξi u(y)i = ehithx ∗,xi 1 (2πh)n Z Rn dξ Z Rn dyhehihx+ξ ∗−y,ξi ehi(1−t)hx ∗,yi u(y)i = ehithx ∗,xi ehi(1−t)hx ∗,x+ξi u(x + ξ∗) = ehihx ∗,xi+i h(1−t)hx ∗i u(x + ξ∗). Remark 4.13. We can write

ehil(x,hD)u(x) = e i h(hx ∗,xi+1 2hx ∗i) u(x + ξ∗), so that  ehil(·) W (x, hD) = ehil(x,hD) (4.4)

Proof. Let u ∈ S (Rn) and t ∈ R. The partial differential equation h

i∂tv(x, t) = l(x, hD)v(x, t) with

boundary condition v(x, 0) = u(x) has a unique solution, but it is solved by v(x, t) = eithl(x,hD)u(x) as well as by v(x, t) = ehi(thx ∗,xi+t2 2hx ∗i) u(x + tξ∗), hence these expressions must coincide.

We will now find a#b for exponentials of linear symbols. Then we can generalise this to arbitrary a, b ∈S (R2n) by using the Fourier decomposition of a and b.

Lemma 4.14. (Composition of exponentials of linear symbols) Let l, m ∈ S (R2n) be linear, i.e. l = (x∗1, ξ1∗) and m = (x∗2, ξ∗2) for some (x∗1, ξ∗1), (x∗2, ξ2∗) ∈ R2n, then

ehil(x,hD)e i hm(x,hD)= e i 2hσ(l,m)e i h(l+m)(x,hD), (4.5) where σ(l, m) := hx∗2, ξ1∗i − hx∗

1, ξ2∗i is the standard symplectic product on R2n.

Proof. ehil(x,hD)e i hm(x,hD)u(x) = e i hl(x,hD)e i hhx ∗ 2,x+12ξ ∗ 2iu(x + ξ∗ 2) = ehihx ∗ 1,x+12ξ ∗ 1iehihx ∗ 2,x+ξ ∗ 1+12ξ ∗ 2iu(x + ξ∗ 2+ ξ1∗) = e2hi(hx ∗ 2,ξ ∗ 1i−hx ∗ 1,ξ ∗ 2i)ehihx ∗ 1+x ∗ 2,x+12ξ ∗ 1+12ξ ∗ 2iu(x + ξ∗ 1+ ξ ∗ 2)b = e2hiσ(l,m)ehi(l+m)(x,hD).

Theorem 4.15. (Fourier decomposition of aW) Let a ∈S (R2n) and l ∈ R2n, then aW(x, hD) = 1 (2πh)2n Z R2n dlhˆah(l)e i hl(x,hD) i . (4.6)

Moreover, if a ∈S0(R2n) and u, v ∈S (Rn), then we can view ei

hl(x,hD)u as a tempered distribution by setting ehil(x,hD)u(v) := Z Rn dxhehil(x,hD)u(x)v(x) i , which is itself in S (R2n) as a function of l, so

aW(x, hD)(u)(v) = 1 (2πh)2nˆah  l 7→ ehil(x,hD)u(v  . (4.7)

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Theorem 4.16. (Composition) Let a, b ∈S (R2n), then the symbol a#b defined by a#b(z) := e2hiσ(hDz,hDw)(a(z)b(w))|

z=w (4.8)

satisfies

(a#b)W(x, hD) = aW(x, hD)bW(x, hD). (4.9) Proof. Recall that σ(hDz, hDw) = hhDξ, hDyi − hhDη, hDxi, so

e2hiσ(hDz,hDw)ehi(l(z)+m(w)) = ∞ X k=0 " 1 k!  i 2h k σ(hDz, hDw)ke i h(l(z)+m(w)) # = ∞ X k=0 " 1 k!  i 2h k (hhDξ, hDyi − hhDη, hDxi)ke i h(l(z)+m(w)) # = ∞ X k=0 " 1 k!  i 2h k ehi(l(z)+m(w))(hξ∗ 1, x∗2i − hξ∗2, x∗1i) k # = ∞ X k=0 " 1 k!  i 2h k σ(l, m)kehi(l(z)+m(w)) # = e2hiσ(l,m)ehi(l(z)+m(w)).

Using the Fourier decomposition of a and b, a#b can be written as a#b(z) = 1 (2πh)4n Z R2n dl Z R2n dmhe2hiσ(hDz,hDw)ehi(l(z)+m(w))|z=wˆah(l)ˆbh(m) i = 1 (2πh)4n Z R2n dl Z R2n dmhe2hiσ(l,m)e i h(l+m)(z)aˆh(l)ˆbh(m) i , so its Weyl quantisation becomes

(a#b)W(x, hD) = 1 (2πh)4n Z R2n dl Z R2n dmhe2hiσ(l,m)e i h(l+m)(x,hD)ˆah(l)ˆbh(m) i = 1 (2πh)4n Z R2n dl Z R2n dmhehil(x,hD)e i hm(x,hD)ˆah(l)ˆbh(m) i = aW(x, hD)bW(x, hD).

Symbols of the form a(x, ξ) = a(ξ) =P

αcαξα for certain constants cα have the property that

Opt(a)u(x) = 1 (2πh)n Z Rn dξ Z Rn dy " X α cαξαu(y)e i hhx−y,ξi # = 1 (2πh)n Z Rn dξ " X α cαξαuˆh(ξ)e i hhx,ξi # =X α cα(hD)αu(x).

This allows us to write equation (4.8) in integral form.

Lemma 4.17. (Integral form of a#b) Let a, b ∈S (R2n) and z ∈ R2n, then

a#b(z) = 1 (πh)2n Z R2n dw1 Z R2n dw2 h e−2ihσ(w1,w2)a(z + w 1)b(z + w2) i (4.10)

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Proof. Let (w1, w2) = (y1, η1, y2, η2) ∈ R4n take the role of y, and let (z, w) = (x, ξ, y, η) ∈ R4n the role

of x, and (z0, w0) ∈ R4n take the role of ξ. Then a#b(z) = e2hiσ(hDz,hDw)(a(z)b(w))| z=w = 1 (2πh)4n Z R4n d(w1, w2) Z R4n d(z0, w0)he2hiσ(z 0,w0) ehih(z,w)−(w1,w2),(z0,w0)ia(w 1)b(w2) i z=w = Z R4n d(w1, w2)hFh−1  (z0, w0) 7→ e2hiσ(z 0,w0) (z − w1, z − w2)a(w1)b(w2) i = Z R4n d(w1, w2)hFh−1  (z0, w0) 7→ e2hiσ(z 0,w0) (−w1, −w2)a(z + w1)b(z + w2) i , where the inverse Fourier transform is given by

F−1 h  (z, w) 7→ e2hi σ(z,w)  (w1, w2) = 1 (2πh)4n Z R4n d(z, w)he2hi σ(z,w)e i hh(w1,w2),(z,w)i i = 1 (2πh)2n Z R2n d(x, η)he−2hihx,ηie i hhx,y1iehihη,η2i i · 1 (2πh)2n Z R2n

d(y, ξ)he2hihy,ξiehihy,y2iehihξ,η1ii

= 1 (2πh)2n Z Rn dη  ehihη,η2i Z Rn dxhehih x 2,2y1ie−hih x 2,ηi i · 1 (2πh)2n Z Rn dy  ehihy,y2i Z Rn dξhehih ξ 2,2η1ie i hhy, ξ 2i i = 1 (2πh)2n Z Rn dηh2nFh  x 7→ ehihx,2y1i(η)ehihη,η2ii · 1 (2πh)n Z Rn dyh2nFh−1ξ 7→ ehihξ,2η1i(y)e−hihy,−y2ii = 1 (πh)ne 2i hhy2,η1i· 1 (πh)ne −2i hhy2,η1i= 1 (πh)2ne 2i hσ(w1,w2).

Corollary 4.18. (# is associative) Let a, b, c ∈S (R2n), then (a#b)#c = a#(b#c).

Proof. Using the integral form, we obtain: (a#b)#c(z) = 1 (2πh)4n Z R8n d ˜w1d ˜w2dw1dw2 h e−2ih(σ( ˜w1, ˜w2)+σ(w1,w2))a(z + ˜w 1+ w1)b(z + ˜w1+ w2)c(z + ˜w2) i a#(b#c)(z) = 1 (2πh)4n Z R8n d ˜v1d ˜v2dv1dv2 h e−2ih(σ( ˜v1, ˜v2)+σ(v1,v2))a(z + ˜v1)b(z + ˜v2+ v1)c(z + ˜v2+ v2) i

It is easy to see that these integrals are equal by using the substitution v1 = ˜w1, v2 = ˜w2− w2, ˜v1 =

˜

w1+ w1, ˜v2= w2.

Definition 4.19. Let ϕ ∈S (Rn), N ∈ N, then we say ϕ = OS(hN) if for all multi-indices α, β, there is a constant Cα,β > 0 such that

sup

x∈Rn

|xα∂βϕ(x)| ≤ Cα,βhN

as h → 0.

Theorem 4.20. Let a, b ∈S (R2n), and N ∈ N, then

a#b(z) = N −1 X k=0 " 1 k!  ih 2 k σ(Dz, Dw)k(a(z)b(w)) # z=w + OS(hN) (4.11) as h → 0.

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Proof. First note that F−1(z, w) 7→ e−2i hσ(z,w)  (w1, w2) =  h 4π 2n eih2σ(w1,w2),

the proof of which is similar to the calculation in the previous lemma. Now we have for all z ∈ R2n, a#b(z) = 1 (πh)2n Z R2n dw1 Z R2n dw2 h e−2ihσ(w1,w2)a(z + w 1)b(z + w2) i = 1 (πh)2n Z R2n dw1 Z R2n dw2hF−1  (z, w) 7→ e−2ihσ(z,w)  (w1, w2)eihz,w1+w2iˆa(w1)ˆb(w2) i = 1 (2π)4n Z R2n dw1 Z R2n dw2 h eih2σ(w1,w2)eihz,w1+w2iˆa(w 1)ˆb(w2) i = 1 (2π)4n Z R2n dw1 Z R2n dw2 h ei(h2σ(w1,w2)+hz,w1+w2i)F (a ⊗ b)(w 1, w2) i . We will introduce the convenient notation Jz(h, a ⊗ b) := a#b(z) as well as P := 2iσ(Dw0

1, Dw02). Then ∂hJz(h, a ⊗ b) = 1 (2π)4n Z R4n d(w1, w2)  ei(h2σ(w1,w2)+hz,w1+w2i)i 2σ(w1, w2)F (a ⊗ b)(w1, w2)  = 1 (2π)4n Z R4n d(w1, w2) h ei(h2σ(w1,w2)+hz,w1+w2i)F (P a ⊗ b)(w 1, w2) i = Jz(h, P a ⊗ b)

Consequently, ∂hkJz(h, a ⊗ b) = Jz(h, Pka ⊗ b) for all k ∈ N. Taylor’s theorem around h = 0 now gives

for any N ∈ N that

a#b(z) = N −1 X k=0  hk k!Jz(0, P ka ⊗ b)  +h N N !Rz,N(h, a ⊗ b) where Rz,N(h, a ⊗ b) := N R1 0 dt[(1 − t) N −1J

z(th, PNa ⊗ b)]. It is now left to show that Jz(0, Pka ⊗ b) is

indeed the required expression and that the rest term is indeed OS(hN), i.e. |R

z,N(h, a ⊗ b)| is bounded independent of h. • Jz(0, Pka ⊗ b) = 1 (2π)4n Z R4n d(w1, w2) " F (w01, w02) 7→ i 2 k σ(Dw0 1, Dw20) ka(w0 1)b(w 0 2) ! (w1, w2)eihz,w1+w2i # = i 2 k σ(Dz, Dw)ka(z)b(w) z=w • |Rz,N(h, a ⊗ b)| = N Z 1 0 dt(1 − t)N1J z(th, pNa ⊗ b)  ≤ CNkF (PNa ⊗ b)kL1 ≤ CN max |α|≤n+1k∂ αPNa ⊗ bk L1 ≤ CN max |α|≤N +n+1k∂ αa ⊗ bk L1, by lemma3.6.

Corollary 4.21. Let a, b ∈S (R2n), then

a#b = ab + h 2i{a, b} + OS(h 2) (4.12) and [aW(x, hD), bW(x, hD)] = h i{a, b} W(x, hD) + O S(h3) (4.13)

where [A, B] := AB − BA is the commutator and {f, g} :=Pn

j=1(fξjgxj− fxjgξj) is the Poisson bracket

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Proof. a#b(z) = a(z)b(z) + ih 2σ(Dz, Dw)a(z)b(w) z=w + OS(h2) = a(z)b(z) + h 2i(∂y∂ξ− ∂x∂η)a(x, ξ)b(y, η) (x,ξ)=(y,η) + OS(h2) = a(z)b(z) + h 2i{a, b}(z) + OS(h 2) [aW(x, hD), bW(x, hD)] = (a#b)W(x, hD) − (b#a)W(x, hD) = h i{a, b} W(x, hD) − h2 8 σ(Dz, Dw) 2(a(z)b(w) − b(z)a(w)) z=w + OS(h3) = h i{a, b} W(x, hD) + O S(h3)

4.3

Symbol classes

In this subsection we will prove that aW(x, hD) : L2 → L2 is well-defined as a bounded operator for

certain symbol classes that are larger thanS (R2n).

Definition 4.22. (Order functions) A measurable function m : R2n−→ (0, ∞) is called an order function

if ∃C, N ∈ R such that ∀w, z ∈ R2n,

m(w) ≤ Chz − wiNm(z), where hzi :=p1 + |z|2.

Proposition 4.23. Let m, m1, and m2 be order functions and let a ∈ [0, ∞), then ma, 1/m, m1+ m2,

and m1m2 are order functions as well. Moreover, mk,l defined by

mk,l(z) := hxik+ hξil (4.14)

is an order function for all k, l ∈ R.

Proof. Since m is an order function, there are constants C, N ∈ R such that m(w) ≤ Chz − wiNm(z) for

all w, z ∈ R2n. Then ma(w) ≤ Cahz − wiN ama(z), and 1 m(z) ≤ Chz − wi N 1 m(w).

Now let Cj, Nj ∈ R such that mj(w) ≤ Cjhz − wiNjmj(z) for j = 1, 2 and all w, z ∈ R2n, and assume

without loss of generality that N1≤ N2. Then

(m1+ m2)(w) = m1(w) + m2(w) ≤ C1hz − wiN1m1(z) + C2hz − wiN2m2(z) = hz − wiN2C 1hz − wi−(N2−N1)m1(z) + C2m2(z)  ≤ hz − wiN2(C 1m1(z) + C2m2(z)) ≤ max(C1, C2)hz − wiN2(m1+ m2)(z), (m1m2)(w) = m1(w)m2(w) ≤ C1C2hz − wiN1+N2(m1m2)(z).

Now it is only left to show that m(w) := hxi is an order function. Note that m(w) = hyi =p1 + |y|2p1 + (|y − x| + |x|)2

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We will consider two cases: (a) |x||y − x| ≤ 1, and (b) |x||y − x| ≥ 1. Then m(w)

(a)

≤ p1 + |x − y|2+ |x|2+ 2 ≤2p

1 + |x − y|2+ 1 + |x|2

≤√2 (hy − xi + hxi) ≤ 2√2 max(hy − xi, hxi) ≤ 2√2hy − xihxi = 2√2hy − xim(z),

m(w)

(b)

≤p1 + |y − x|2+ |x|2+ 2|y − x|2|x|22p(1 + |y − x|2)(1 + |x|2)

=√2hy − xihxi =√2hy − xim(z).

Definition 4.24. (Symbol classes) Let m : R2n→ (0, ∞) be an order function and let δ ≥ 0, then

Sδ(m) := {a ∈ C∞| ∀α, ∃Cα> 0; |∂αa| ≤ Cαh−δ|α|m}. (4.15)

We shall write S(m) := S0(m), Sδ := Sδ(1), and S := S0(1). Note that

sup

z,h

m < ∞ =⇒ Sδ(m) ⊆ Sδ,

inf

z,hm > 0 =⇒ Sδ ⊆ Sδ(m).

The constant δ ≥ 0 is relevant in case we want to study aW(x, hD) in the limit h → 0. Of course, the

quantisation formula (4.1) itself already depends on h. By rescaling ˜x := h−12x, ˜ξ := h− 1

2ξ, ˜y := h− 1 2y,

˜

u(˜x) := u(x) = u(h12x), ˜˜ a(˜x, ˜ξ) := a(x, ξ) = a(h12x, h˜ 12ξ), we obtain˜

aW(x, hD)u(x) = 1 (2πh)n Z Rn dξ Z Rn dy  ehihx−y,ξia x + y 2 , ξ  u(y)  = 1 (2πh)nh nZ Rn d ˜ξ Z Rn d˜y  eih˜x−˜y, ˜ξia  h12x + ˜˜ y 2 , h 1 2ξ  u(h12y)˜  = 1 (2π)n Z Rn d ˜ξ Z Rn d˜y  eih˜x−˜y, ˜ξia˜ ˜x + ˜y 2 , ˜ξ  ˜ u(˜y)  = ˜aW(˜x, D)˜u(˜x).

Let δ ≥ 0, let m be an order function, and let a ∈ Sδ(m). Then for all multi-indices α, the rescaled

function ˜a satisfies |∂αa| = h˜ 12|α||∂αa| ≤ Cαh|α|( 1

2−δ)m. This is unbounded as h → 0 for δ > 1

2, so from

now on we will always assume that 0 ≤ δ ≤ 12.

Proposition 4.25. Let δ ≥ 0 and t ∈ [0, 1]. Let m be an order function, and let a ∈ Sδ(m). Then

Opt(a) :S (Rn) →S (Rn)

is a continuous linear operator.

Proof. Let u ∈ S (Rn). We want to prove that x 7→ Opt(a)u(x) is again a Schwartz function. We

will first prove that supx∈Rn|Opt(a)u(x)| < ∞. Then, for 1 ≤ j ≤ n, we will apply this to the cases

xjOpt(a)u(x) and ∂jOpt(a)u(x) by writing these as the finite sum of functions of the form Opt(b)v(x)

for certain b ∈ Sδ(m), v ∈S (Rn).

Let C, N > 0 such that m(w) ≤ Chz − wiNm(z) for all w, z ∈ R2n. Then for all 1 ≤ j ≤ n,

hDyje i hhx−y,ξi= −ξje i hhx−y,ξi, and hDξje i hhx−y,ξi= (xj− yj)ehihx−y,ξi.

So for the operators L1and L2defined by

L1:= 1 − hξ, hDyi 1 + |ξ|2 = 1 − hξ, hDyi hξi2 , L2:= 1 + hx − y, hDξi 1 + |x − y|2 = 1 + hx − y, hDξi hx − yi2 ,

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the identities L1e i hhx−y,ξi= L2e i hhx−y,ξi= e i

hhx−y,ξihold. Then we obtain

Opt(a)u(x) =

1 (2πh)n

Z

R2n

d(ξ, y)hehihx−y,ξia (tx + (1 − t)y, ξ) u(y)

i = 1 (2πh)n Z R2n d(ξ, y)hLN +n+11 ehihx−y,ξi  a (tx + (1 − t)y, ξ) u(y)i = 1 (2πh)n Z R2n d(ξ, y) " ehihx−y,ξi N +n+1 X k=0 hξ, hDyik

hξi2(N +n+1)(a (tx + (1 − t)y, ξ) u(y))

#

by integration by parts, where the boundary term vanishes because u(y) is a Schwartz function,

= 1 (2πh)n Z R2n d(ξ, y) " LN +n+12 ehihx−y,ξi N +n+1X k=0 hξ, hDyik

hξi2(N +n+1)(a (tx + (1 − t)y, ξ) u(y))

# = 1 (2πh)n Z R2n d(ξ, y) " ehihx−y,ξi · N +n+1 X l=0 (−1)lhx − y, hD ξil hx − yi2(N +n+1) "N +n+1 X k=0 hξ, hDyik

hξi2(N +n+1)(a (tx + (1 − t)y, ξ) u(y))

# #

by integration by parts where the boundary term vanishes because a and all its derivatives grow by at most ∼ hξiN.

All derivatives of a(tx + (1 − t)y, ξ)u(y) grow by at most ∼ hx − yiNhξiN, hence for some C > 0,

sup x∈Rn |Opt(a)u(x)| ≤ C Z Rn dξ Z Rn dy  1 hx − yin+1 1 hξin+1  < ∞. Now let 1 ≤ j ≤ n, then

(2πh)nxjOpt(a)u(x) = Z R2n d(ξ, y) " xje i hhx−y,ξi N +n+1 X k=0 hξ, hDyik

hξi2(N +n+1)(a (tx + (1 − t)y, ξ) u(y))

# = Z R2n d(ξ, y) " (yj+ hDξj)  ehihx−y,ξi N +n+1X k=0 hξ, hDyik

hξi2(N +n+1)(a (tx + (1 − t)y, ξ) u(y))

# = Z R2n d(ξ, y) " ehihx−y,ξi(yj− hDξ j) N +n+1 X k=0 hξ, hDyik

hξi2(N +n+1)(a (tx + (1 − t)y, ξ) u(y))

# , (2πh)nhDxja W(x, hD)u(x) = Z R2n d(ξ, y)hhDxj  ehihx−y,ξia (tx + (1 − t)y, ξ)  u(y)i = Z R2n d(ξ, y)hξje i

hhx−y,ξia (tx + (1 − t)y, ξ) + ehihx−y,ξihDx ja  x + y 2 , ξ   u(y) # = Z R2n d(ξ, y) " ehihx−y,ξi " 1 + hξ, hDyi

hξi2 (ξja (tx + (1 − t)y, ξ) u(y)) + hDxja

 x + y 2 , ξ  u(y) ## .

Now let {uj}j∈NS (Rn) be a Cauchy sequence converging to 0, then it is clear from the above

expressions that the sequence Opt(a)uj also converges to 0 inS (Rn), hence Opt(a) is continuous.

Proposition 4.26. Let δ ≥ 0, t ∈ [0, 1]. Let m be an order function, and let a ∈ Sδ(m). Then

Opt(a) :S0(Rn) →S0(Rn)

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Proof. Let u, v ∈S (Rn) and define ˜ξ := −ξ, ˜a(x, ˜ξ) := a(x, ξ) = a(x, − ˜ξ), then Z Rn dx [v(x)Opt(a)u(x)] = 1 (2πh)n Z Rn dx Z Rn dξ Z Rn

dyhehihx−y,ξia (tx + (1 − t)y, ξ) u(y)v(x)

i = Z Rn dy  u(y) 1 (2πh)n Z R2n d(ξ, x)hehihy−x,−ξia (tx + (1 − t)y, −(−ξ)) v(x) i = Z Rn dy  u(y) 1 (2πh)n Z R2n d( ˜ξ, x)hehihy−x, ˜ξia  tx + (1 − t)y, − ˜ξv(x)i  = Z Rn dy  u(y) 1 (2πh)n Z R2n d( ˜ξ, x)hehihy−x, ˜ξi˜a  tx + (1 − t)y, ˜ξv(x)i  = Z Rn dy [u(y)Opt(˜a)v(y)] ,

so we can define for u ∈S0(Rn) and v ∈S (Rn) that

(Opt(a)u)(v) := u(Opt(˜a)v).

So far, we have considered quantisation for symbols in S (Rn) or in S

δ(m). We will now try to

construct such a symbol for a given operator A :S0 →S0. It turns out that for all t ∈ [0, 1] and all

a ∈ Sδ(m), the identity a(x, ξ) = ehi(t−1)hhDx,hDξi  e−hihx,ξiOpt(a)  x 7→ ehihx,ξi  (x) (4.16) holds. We will first prove this for standard quantisation, i.e. t = 1.

Lemma 4.27. Let 0 ≤ δ ≤ 12 and let m be an order function. Let a ∈ Sδ(m), then

a(x, ξ) = e−hihx,ξia(x, hD)



x 7→ ehihx,ξi



(x). (4.17) Proof. Using example3.9, we obtain

e−hihx,ξia(x, hD)  x 7→ ehihx,ξi  (x) = e−hihx,ξi 1 (2πh)n Z Rn dη Z Rn

dyhehihx−y,ηia(x, η)e i hhy,ξi i = Z Rn dη 

a(x, η)ehihx,η−ξi 1

(2πh)n Z Rn dyhehihy,η−ξi i = Z Rn

dηha(x, η)ehihx,η−ξiδ0(η − ξ)

i = a(x, ξ).

Proposition 4.28. Let 0 ≤ δ ≤ 12 and let m be an order function. Let b ∈ Sδ(m) and define for t ∈ [0, 1];

a(x, ξ) := e−hi(1−t)hhDx,hDξib(x, ξ).

Then a ∈ Sδ(m) and Opt(a) = Op1(b) = b(x, hD). Moreover, if b ∈S (R2n), then also a ∈S (R2n).

Proof. The operator e−hi(1−t)hhDx,hDξiarises by quantisation from the symbol A(z, z0) = e−hi(1−t)hx 00i

, where z = (x, ξ) takes the role of x, z0 = (x0, ξ0) takes the role of ξ, and w = (y, η) takes the role of y,

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i.e. e−hi(1−t)hhDx,hDξib(x, ξ) = 1 (2πh)2n Z R2n dz0 Z R2n dwhehihz−w,z 0 ie−i h(1−t)hx 00 ib(w)i = 1 (2πh)2n Z R2n d(ξ0, η) Z R2n d(x0, y)hehihx−y,x 0i ehihξ−η,ξ 0i e−hi(1−t)hx 00i b(y, η)i = 1 (2πh)n Z R2n d(ξ0, η)  1 (2πh)n Z R2n d(x0, y)hehihx−(1−t)ξ 0−y,x0i ehihξ−η,ξ 0i b(y, η)i  = 1 (2πh)n Z R2n d(ξ0, η)hehihξ−η,ξ 0i b(x − (1 − t)ξ0, η)i. Now we can define

L1:= 1 − hξ0, hDηi 1 + |ξ0|2 = 1 − hξ0, hDηi hξ0i2 , L2:= 1 + hξ − η, hDξ0i 1 + |ξ − η|2 = 1 + hξ − η, hDξ0i hξ − ηi2 , so that L1e i hhξ−η,ξ 0i = L2e i hhξ−η,ξ 0i = ehihξ−η,ξ 0i

. Now we can use arguments similar to those in the proof of proposition4.25to show that b ∈S (R2n) =⇒ a ∈S (R2n) and b ∈ S

δ(m) =⇒ a ∈ Sδ(m).

Now let b ∈S (R2n) and u ∈S (Rn), then

Opt(a)u(x) = 1 (2πh)n Z R2n dlhˆah(l) Opt  ehil(·)  u(x)i = 1 (2πh)n Z R2n dlhFh  e−hi(1 − t)hhDx, hDξib(x, ξ)  (l) Opt  ehil(·)  u(x)i = 1 (2πh)n Z R2n dlhe−hi(1−t)hx ∗∗ iˆb h(l)e i hhx ∗,xi+i h(1−t)hx ∗∗ iu(x + ξ)i = 1 (2πh)n Z R2n dlhˆbh(l)e i hhx ∗,xi u(x + ξ∗)i = 1 (2πh)n Z R2n dlhˆbh(l)Op1  ehil(·)  u(x)i = Op1(b)u(x).

Using the fact thatS (R2n) ⊂ S

δ(m) is dense, we obtain Opt(a) = Op1(b) for all b ∈ Sδ(m).

Definition 4.29. (Order of vanishing) Let 0 ≤ δ ≤ 12 and let m be an order function. Then a function a ∈ Sδ(m) is said to vanish with order N as h → 0 if for each multi-index α there is a constant C > 0

such that |∂αa| ≤ ChN −δ|α|m. If this is the case, we write a = O Sδ(m)(h

N).

Proposition 4.30. (Composition) Let 0 ≤ δ < 1

2 and let m1 and m2 be order functions. Let a ∈

Sδ(m1), b ∈ Sδ(m2), then a#b ∈ Sδ(m1m2) and aW(x, hD)bW(x, hD) = (a#b)W(x, hD). Moreover, for

all n ∈ N we have a#b(z) = N −1 X k=0 " 1 k!  ih 2 k σ(Dz, Dw)k(a(z)b(w)) # z=w + OSδ(m1m2)(h k(1−2δ)). (4.18)

Proof. Clearly, (z, w) 7→ a(z)b(w) ∈ Sδ((z, w) 7→ m1(z)m2(w). Now we need to prove that e i

2hσ(hDz,hDw):

Sδ((z, w) 7→ a(z)b(w)) → Sδ((z, w) 7→ a(z)b(w)). The proof of this is very similar to the previous proof,

so it will be omitted. Then a#b := e2hi σ(hDz,hDw)(a(z)b(w))

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Let α be a multi-index, then ∂zα 1 k!  ih 2 k σ(Dz, Dw)k(a(z)b(w)) z=w ! ≤ hkCh−(2k+|α|)δm 1m2= Chk(1−2δ)−δ|α|m1m2, hence 1 k!  ih 2 k σ(Dz, Dw)k(a(z)b(w)) z=w = OSδ(m1m2)(h k(1−2δ)).

Corollary 4.31. If a ∈ Sδ(m1) and b ∈ Sδ(m2), then

a#b = ab + h 2i{a, b} + OSδ(m1m2)(h 2(1−2δ)) (4.19) and [aW(x, hD), bW(x, hD)] = h i{a, b} W(x, hD) + O S0(Rn)→S0(Rn)(h3(1−2δ)). (4.20)

Remark 4.32. Let a, b be symbols, then a#b = b#a and a#a is real-valued. Proof. We have for all z ∈ R2n that

a#b(z) = e2hi σ(hDz,hDw)(a(z)b(w)) z=w= e − i 2hσ(hDz,hDw)(a(z)b(w)) z=w = e2hi σ(hDw,hDz)(b(w)a(z)) z=w= b#a(z). Now let a = b + ic where b, c : R2n → R. Then

a(z)a(w) = b(z)b(w) + c(z)c(w) + i(b(z)c(w) − b(w)c(z)) =: A(z, w) + iB(z, w) where A(z, w) = A(w, z) and B(z, w) = −B(w, z) for all z, w ∈ R2n. Then for all k ∈ N,

σ(Dz, Dw)2k+1A(z, w) z=w= −σ(Dw, Dz)2k+1A(w, z) z=w σ(Dz, Dw)2kB(z, w) z=w= −σ(Dw, Dz)2kB(w, z) z=w.

Hence σ(Dz, Dw)2k+1A(z, w)|z=w = σ(Dz, Dw)2kB(z, w)|z=w = 0. From formula (4.18) it is clear that

a#a is indeed real-valued.

Next, we want to prove that aW(x, hD) : L2(Rn) → L2(Rn) for symbols a ∈ S

δ(m). This is true for

all order functions m such that sup m < ∞. We will prove this using the Cotlar-Stein theorem.

Theorem 4.33. (Cotlar-Stein theorem) Let H1, H2 be Hilbert spaces and let Aj : H1 → H2 be linear

operators for all j ∈ N. If there is a constant C > 0 such that

sup j∈N ∞ X k=1 kA∗jAkk 1 2 ≤ C, sup j∈N ∞ X k=1 kAjA∗kk 1 2 ≤ C, (4.21) thenP∞

j=1Aj converges in the strong topology, i.e. P∞j=1Aju ∈ H2for all u ∈ H1, and kP∞j=1Ajk ≤ C.

So our goal is to construct a sequence {Aj : L2(Rn) → L2(Rn)}j∈N that satisfies the conditions of

the Cotlar-Stein theorem and converges to aW(x, hD). We will use the following contruction to cut the symbol a ∈ Sδ(m) into compactly supported symbols aα for α ∈ Z2n.

Let χ ∈ C∞

c (R2n) such that 0 ≤ χ ≤ 1 and

P

α∈Z2nχ(z − α) = 1 for all z ∈ R2n. Such a function can

be constructed as follows: define for 0 ≤ j ≤ 2n, χj(z) := 12cos(πzj) +12 if zj ∈ [−1, 1], and χj(z) := 0

otherwise. Then the function χ := Π2n

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Now define the function aα∈S (R2n) for all α ∈ Z2nby aα(z) := χ(z −α)a(z). ThenPα∈Z2naα≡ 1.

Now let Aα:= aWα (x, hD). Our goal is to show that there is a constant C > 0 such that

C ≥ sup α∈Z2n X β∈Z2n kA∗jAkk 1 2 = sup α∈Z2n X β∈Z2n kaWα(x, hD)∗a W β (x, hD)k 1 2 = sup α∈Z2n X β∈Z2n kaW α (x, hD)a W β (x, hD)k 1 2 = sup α∈Z2n X β∈Z2n k(aα#aβ)W(x, hD)k 1 2, C ≥ sup α∈Z2n X β∈Z2n kAjA∗kk 1 2 = sup α∈Z2n X β∈Z2n kaW α (x, hD)a W β (x, hD) ∗k1 2 = sup α∈Z2n X β∈Z2n kaWα (x, hD)a W β (x, hD)k 1 2 = sup α∈Z2n X β∈Z2n k(aα#aβ)W(x, hD)k 1 2.

The following lemma shows that aα#aβand its derivatives vanish rapidly if α and β or if z and (α + β)/2

are far apart.

Lemma 4.34. (Mixed term decay) Let 0 ≤ δ ≤ 1/2 and let m be a bounded order function. Let a ∈ Sδ(m) and define aα as above. For all α, β ∈ Z2n, N ∈ N, and multi-indices γ ∈ N2n there is a

constant Cγ,N > 0, such that for all z ∈ R2n;

|∂γa

α#aβ(z)| ≤ Cγ,Nhα − βi−Nhz −

α + β 2 i

−N. (4.22)

Moreover, there is a constant Cγ,N > 0 not depending on a or h, and a K ∈ N depending linearly on n,

such that for all z ∈ R2n;

|∂γa α#aβ(z)| ≤ Cγ,N   X |κ|≤K h|κ|/2| sup ∂κa|   2 hα − βi−Nhz − α + β 2 i −N. (4.23)

and there is a constant Cγ,N> 0 possibly depending on h, such that for all z ∈ R2n;

|∂γa

α#aβ(z)| ≤ Cγ,Nm(α)m(β)hα − βi−Nhz −

α + β 2 i

−N. (4.24)

Proof. Recall that aα#aβ(z) = 1 (πh)2n Z R2n dw1 Z R2n dw2 h e−2ihσ(w1,w2)a α(z + w1)aβ(z + w2) i = 1 π2n Z R2n d ˜w1 Z R2n d ˜w2 h e−2iσ( ˜w1, ˜w2)a α(h1/2(˜z + ˜w1))aβ(h1/2(˜z + ˜w2)) i = 1 π2n Z R2n d ˜w1 Z R2n d ˜w2 h e−2iσ( ˜w1, ˜w2)˜a α(˜z + ˜w1)˜aβ(˜z + ˜w2) i ,

where we put ˜w1 := h−1/2w1, ˜w2 := h−1/2w2, ˜z := h−1/2z, and ˜aα(˜z) := aα(z) = aα(h1/2z). For the˜

sake of readability, all tildes will be omitted for now. For any multi-index γ we have ∂γaα#aβ(z) = 1 π2n Z R2n dw1 Z R2n dw2 h e−2iσ(w1,w2)γ z  aα(z + w1)aβ(z + w2) i .

Note that the support of our choice of χ lies in B(0, n), so the integrand is just zero unless z + w1−

α, z + w2− β ∈ B(0, n). We obtain |α − β| = |(z − β + w2) − (z − α + w1) − w2+ w1| ≤ 2n + |w1| + |w2|, z −a + b 2 = 1 2|(z − α + w1) − w1+ (z − β + w2) − w2| ≤ 2n + |w1| + |w2|,

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hence for some constant C > 0 such that hα−βi ≤ Chwi and hz −(α+β)/2i ≤ Chwi where w := (w1, w2).

So for any N ∈ N, hwi−2N ≤ Chα − βi−Nhz − (α + β)/2i−N for some constant C > 0.

We will obtain a factor hwi−2N by integrating by parts. As will be clear shortly, integration by parts is only possible if w := (w1, w2) lies outside an open neighbourhood of 0. We will cut the integral in two

parts: one in a bounded neighbourhood of 0, and one outside of it. Let ζ : R4n → [0, 1] be a smooth

function such that ζ ≡ 1 on B(0, 1) and Supp(ζ) ⊂ B(0, 2). Define for each multi-index γ: Aγ(z) := 1 π2n Z R2n dw1 Z R2n dw2 h e−2iσ(w1,w2)ζ(w 1, w2)∂γz(aα(z + w1)aβ(z + w2)) i , Bγ(z) := 1 π2n Z R2n dw1 Z R2n dw2 h e−2iσ(w1,w2)(1 − ζ(w 1, w2))∂zγ(aα(z + w1)aβ(z + w2)) i , so that ∂γa α#aβ(z) = Aγ(z) + Bγ(z) for all z ∈ R2n.

(Proof of (4.22).) We will first estimate |∂γ

z(aα(z + w1)aβ(z + w2))|, and then |Aγ(z)| and |Bγ(z)|.

• Since sup m < ∞, we have ∂ γ z(aα(z + w1)aβ(z + w2)) ≤ C X |κ|≤|γ| ∂ κ z(aα(z + w1)) ∂γ−κz (aβ(z + w2)) ≤ Cγ X |κ|≤|γ| (sup m)2≤ Cγ.

• Since the support of ζ is bounded, clearly there is some constant Cγ,0> 0 such that |Aγ(z)| ≤ Cγ,0

for all z ∈ R2n. Furthermore, due to |w| ≤ 2 we have hwi−2N ≥ h2i−2N. So we can define for any

N ∈ N, Cγ,N := h2i2NCγ,0, then

|Aγ(z)| ≤ Cγ,0= Cγ,Nh2i−2N ≤ Cγ,Nhwi−2N ≤ Cγ,Nhα − βi−Nhz −

α + β 2 i

−N.

• Now for Bγ(z): it is convenient to write ϕ(w) := −2σ(w1, w2) = −2(x2ξ1− x1ξ2). It’s derivatives

are ∂x1ϕ(w) = 2ξ2, ∂ξ1ϕ(w) = −2x2, ∂x2ϕ(w) = −2ξ1, and ∂ξ2ϕ(w) = 2x1, so |∂ϕ(w)| = 2|w|.

Then we can define the operator

L := h∂ϕ, Dwi |∂ϕ|2 =

h∂ϕ, Dwi

|w|2

and this operator satisfies Le−2iσ(w1,w2) = e−2iσ(w1,w2). Now we can integrate B

γ(z) by parts.

Note that the integrand vanishes in B(0, 1), so there are no problems with w = 0.

Bγ(z) = 1 π2n Z R2n dw1 Z R2n dw2 h L2N +4n+1e−2iσ(w1,w2)  (1 − ζ(w1, w2))∂zγ(aα(z + w1)aβ(z + w2)) i = 1 π2n Z R4n dw e −2iσ(w1,w2) |w|4N +8n+2(−h∂ϕ, Dwi) 2N +4n+1(1 − ζ(w 1, w2))∂zγ(aα(z + w1)aβ(z + w2))  , |Bγ(z)| ≤ Cγ,N Z R4n dwhhwi−(2N +4n+1)i≤ Cγ,Nhα − βi−Nhz − α + β 2 i −N. (Proof of (4.23).)

• Recall that for any two positive real numbers a and b, ab ≤ 1 2(a 2+ b2) and a2+ b2≤ (a + b)2. So we obtain ∂ γ z(aα(z + w1)aβ(z + w2)) ≤ C X |κ|≤|γ| ∂ κ z(aα(z + w1)) ∂γ−κz (aβ(z + w2)) ≤ Cγ   X |κ|≤|γ| | sup ∂κa|   2 .

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• The rest of the proof is analogous to the previous proof. Putting the tildes back in, we obtain ∂zκ˜˜a(˜z) = ∂zκ˜a(h1/2z) = h˜ |κ|/2∂zκa(z), hence | sup ∂κ˜a| = h|κ|/2| sup ∂κa|.

(Proof of (4.24).)

• Note that m is an order function, so for some M ∈ N, we have m(w) ≤ Chz − wiMm(z) for all

w, z ∈ R2n. Then we obtain |∂γ zaα(w1+ z)| = |∂zγ(χ(w1+ z − α)a(w1+ z))| ≤ C sup |κ|≤|γ| |∂κ zχ(w1+ z − α)|m(w1+ z) ≤ C sup |κ|≤|γ| |∂κ zχ(w1+ z − α)|hw1+ z − αiMm(α) ≤ Cγm(α),

where we used that |w1+ z − α| ≤ n. Hence |∂zγ(aα(z + w1)aβ(z + w2))| ≤ Cm(α)m(β).

• The rest of the proof is again analogous to the first proof.

Lemma 4.35. (More on mixed term decay) For sufficiently large N ∈ N, there is a constant CN > 0

such that

k(aα#aβ)W(x, hD)k ≤ CNhα − βi−N. (4.25)

Moreover, there is a constant CN > 0 not depending on a or h, and a K ∈ N depending linearly on n,

such that k(aα#aβ)W(x, hD)k ≤ CN   X |κ|≤K h|κ|/2| sup ∂κa|   2 hα − βi−N, (4.26)

and there is a constant CN > 0 possibly depending on h, such that

k(aα#aβ)W(x, hD)k ≤ CNm(α)m(β)hα − βi−N. (4.27)

Proof. Recall that for any a ∈S (R2n), we have

aW(x, hD) = 1 (2πh)2n Z R2n dlhˆah(l)e i hl(x,hD) i .

Using lemma3.6, we obtain

k(aα#aβ)W(x, hD)kL2(Rn)→L2(Rn)≤ C Z R2n dl [|Fh(aα#aβ)|] = CkFh(aα#aβ)kL1(R2n) ≤ C max |γ|≤2n+1k∂ γa α#aβkL1(R2n) = C max |γ|≤2n+1 Z R2n dzh∂γaα#aβ(z)hzi2n+1hzi−(2n+1) i ≤ C sup z∈R2n max |γ|≤2n+1hzi 2n+1γa α#aβ(z) ≤ CN sup z∈R2n hzi2n+1hz − α + β 2 i −Nhα − βi−N

for all N ∈ N according to (4.22) in the previous lemma. If N is sufficiently large, this supremum is finite and we obtain

k(aα#aβ)W(x, hD)kL2(Rn)→L2(Rn)≤ CNhα − βi−N,

References

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