R E S E A R C H
Open Access
Existence of two positive solutions for a
class of second order impulsive singular
integro-differential equations on the half line
Dajun Guo
**Correspondence: [email protected] Department of Mathematics, Shandong University, Jinan, Shandong 250100, People’s Republic of China
Abstract
In this paper, the author discusses the existence of two positive solutions for an infinite boundary value problem of second order impulsive singular
integro-differential equations on the half line by means of the fixed point theorem of cone expansion and compression with norm type.
MSC: 45J05; 47H10
Keywords: impulsive singular integro-differential equation; infinite boundary value problem; fixed point theorem of cone expansion and compression with norm type
1 Introduction
The theory of impulsive differential equations has been emerging as an important area of investigation in recent years (see [–]). Many problems have been investigated for im-pulsive differential equations, imim-pulsive functional differential equations and imim-pulsive differential inclusions. These problems include existence of solutions, stability theory, ge-ometric properties, applications,etc.There is a vast literature on existence of solutions: by using upper and lower solutions together with the monotone iterative technique to obtain the extremal solutions [–]; by using fixed point theorems to obtain the existence of so-lution and multiple soso-lutions [–]; by using the Leray-Schauder degree theory or fixed point index theory to obtain multiple solutions [–]; by using the variational method to obtain the existence of solution and existence of infinite many solutions [–]. In re-cent article [], the author discussed the existence of two positive solutions for an infinite boundary value problem of first order impulsive singular integro-differential equations on the half line by means of the fixed point theorem of cone expansion and compression with norm type, which was established by the author in [] (see also [–]). Now, in this article, we shall discuss such problem for a class of second order equations. The discus-sion for second order equations is more complicated than the first order case. We must introduce a new Banach space and a new cone in it to control both the unknown function and its derivative so that we can still use the fixed point theorem of cone expansion and compression with norm type.
Consider the infinite boundary value problem (IBVP) for second order impulsive singu-lar integro-differential equation of mixed type on the half line:
⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩
u(t) =f(t,u(t),u(t), (Tu)(t), (Su)(t)), ∀t∈R++, u|t=tk=Ik(u(t–k)) (k= , , , . . .),
u|t=tk=Ik(u¯ (t–
k)) (k= , , , . . .), u() = , u(∞) =βu(),
()
whereRdenotes the set of all real numbers,R+={x∈R:x≥},R++={x∈R:x> }, <
t<· · ·<tk<· · ·,tk→ ∞,R++=R++\{t, . . . ,tk, . . .},f∈C[R++×R++×R++×R+×R+,R+],
Ik,¯Ik∈C[R++,R+] (k= , , , . . .),β> ,u(∞) =limt→∞u(t) and
(Tu)(t) =
t
K(t,s)u(s)ds, (Su)(t) =
∞
H(t,s)u(s)ds, ()
K∈C[D,R+],D={(t,s)∈R+×R+:t≥s},H∈C[R+×R+,R+].u|t=tkandu|t=tkdenote the jumps ofu(t) andu(t) att=tk, respectively,i.e.
u|t=tk=u
tk+–ut–k, u|t=tk=u
t+k–utk–, whereu(t+
k) andu(t–k) represent the right and left limits ofu(t) att=tk, respectively, and u(t+
k) andu(tk–) represent the right and left limits ofu(t) att=tk, respectively. In what follows, we always assume that
lim
t→+f(t,u,v,w,z) =∞, ∀u,v∈R++,w,z∈R+, ()
lim
u→+f(t,u,v,w,z) =∞, ∀t,v∈R++,w,z∈R+ ()
and
lim
v→+f(t,u,v,w,z) =∞, ∀t,u∈R++,w,z∈R+, ()
i.e. f(t,u,v,w,z) is singular att= ,u= andv= . We also assume that
lim
v→+Ik(v) =∞ (k= , , , . . .) ()
and
lim
v→+¯Ik(v) =∞ (k= , , , . . .), ()
i.e. Ik(v) and¯Ik(v) (k= , , , . . .) are singular atv= . LetPC[R+,R] ={u:uis a real function
onR+such thatu(t) is continuous att=tk, left continuous att=tk, andu(tk+) exists,k= , , , . . .}andPC[R+,R] ={u∈PC[R+,R] :u(t) is continuous att=tk, andu(tk+) and u(t–
k) exist fork= , , , . . .}. Letu∈PC[R+,R]. For <h<tk–tk–, by the mean value
theorem, there existstk–h<ξk<tksuch that
hence the left derivative ofu(t) att=tk, which is denoted byu–(tk), exists, and
u–(tk) = lim h→+
u(tk) –u(tk–h) h =u
t–
k
.
In what follows, it is understood thatu(tk) =u–(tk). So, foru∈PC[R
+,R], we haveu∈
PC[R+,R].
A functionu∈PC[R+,R]∩C[R++,R] is called a positive solution of IBVP () ifu(t) >
fort∈R++andu(t) satisfies (). Now, we need to introduce a new spaceDPC[R+,R] and
a new coneQin it. Let
DPC[R+,R] = u∈PC[R+,R] : sup
t∈R++
|u(t)|
t <∞,t∈Rsup+
u(t)<∞
.
It is easy to see thatDPC[R+,R] is a Banach space with the norm
uD=max
uS,uB,
where
uS= sup
t∈R++
|u(t)|
t , u
B=sup t∈R+
u(t).
LetW={u∈DPC[R
+,R] :u(t)≥,u(t)≥,∀t∈R+}and
Q= u∈DPC[R+,R] : inf
t∈R++
u(t) t ≥β
–uS,inf
t∈R+
u(t)≥β–uB
.
Obviously,W andQare two cones in the spaceDPC[R
+,R] andQ⊂W (for details on
cone theory, see []). LetQ+={u∈Q:uD> }andQpq={u∈Q:p≤ uD≤q}for q>p> .
2 Several lemmas
Remark (a) Foru∈DPC[R+,R], we haveu() = . This is clear sinceu()= implies
sup t∈R++
|u(t)| t =∞.
(b) Foru∈Q+, we haveu(t) > fort∈R++andu(t) > fort∈R+.
Lemma For u∈Q,we have
uS≥β–uB, uB≥β–uS, ()
β–uD≤ uS≤ uD, β–uD≤uB≤ uD () and
β–uD≤ u(t)
t ≤ uD, ∀t∈R++; β
–u
Proof Since () implies () and () and () imply (), we need only to show ().
For fixed <t<t, observingu() = and by the mean value theorem, there exists
<ξ<tsuch that
u(t) t =
u(t) –u() t =u
(ξ).
So,
uS= sup
s∈R++
u(s) s ≥
u(t) t =u
(ξ)≥ inf s∈R+
u(s)≥β–uB.
On the other hand, for any <t<t, we have
u(t) t ≥β
–u
S,
so,
u() = lim t→+
u(t) –u() t =t→lim+
u(t) t ≥β
–uS,
hence,
uB=sup s∈R+
u(s)≥u()≥β–uS.
Let us list some conditions. (H)supt∈J
t
K(t,s)s ds<∞,supt∈J
∞
H(t,s)s ds<∞and
lim t→t
∞
Ht,s–H(t,s)s ds= , ∀t∈R+.
In this case, let
k∗=sup t∈R+
t
K(t,s)s ds, h∗=sup t∈R+
∞
H(t,s)s ds.
(H) There exista,b∈C[R++,R+],g∈C[R++,R+] andG∈C[R++×R+×R+,R+] such that
f(t,u,v,w,z)≤a(t)g(u) +b(t)G(v,w,z), ∀t,u,v∈R++,w,z∈R+
and
a∗r=
∞
a(t)gr(t)dt<∞
for anyr> , where
and
b∗=
∞
b(t)dt<∞.
(H)Ik(v)≤tk¯Ik(v),∀v∈R++(k= , , , . . .), and there existγk∈R+(k= , , , . . .) and
F∈C[R++,R+] such that
¯
Ik(v)≤γkF(v), ∀v∈R++(k= , , , . . .)
and
¯
γ = ∞
k=
tkγk<∞,
and, consequently,
γ∗= ∞
k=
γk≤t– γ¯<∞.
It is clear: if condition (H) is satisfied, then () implies ().
(H) There existsc∈C[R++,R++] such that
f(t,u,v,w,z)
c(t)v → ∞ asv→ ∞
uniformly fort,u∈R++,w,z∈R+, and
c∗=
∞
c(t)dt<∞.
(H) There existsd∈C[R++,R++] such that
d(t)–f(t,u,v,w,z)→ ∞ asv→+
uniformly fort,u∈R++,w,z∈R+, and
d∗=
∞
d(t)dt<∞.
Remark It is clear: if condition (H) is satisfied, then the operatorsT andSdefined
by () are bounded linear operators fromDPC[R+,R] intoBC[R+,R] (the Banach space
of all bounded continuous functionsu(t) onR+with the normuB=supt∈R+|u(t)|) and
T ≤k∗,S ≤h∗; moreover, we haveT(DPC[R
+,R+])⊂BC[R+,R+] (BC[R+,R+] ={u∈
BC[R+,R] :u(t)≥,∀t∈R+}) andS(DPC[R+,R+])⊂BC[R+,R+].
Remark Condition (H) means that the functionf(t,u,v,w,z) is superlinear with
Remark Condition (H) means that the functionf(t,u,v,w,z) is singular atv= and it
is stronger than ().
Remark In what follows, we need the following two formulas (see [], Lemma ):
(a) Ifu∈PC[R+,R]∩C[R++,R], then
u(t) =u() +
t
u(s)ds+
<tk<t
utk+–ut–k, ∀t∈R+. ()
(b) Ifu∈PC[R
+,R]∩C[R++,R], then
u(t) =u() +tu() +
t
(t–s)u(s)ds
+
<tk<t
utk+–ut–k+ (t–tk)ut+k–utk–, ∀t∈R+. ()
We shall reduce IBVP () to an impulsive integral equation. To this end, we first consider operatorAdefined by
(Au)(t) = t β–
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds+ ∞
k=
¯
Ik
ut–k
+
t
(t–s)fs,u(s),u(s), (Tu)(s), (Su)(s)ds
+
<tk<t
Ik
utk–+ (t–tk)¯Ik
ut–k, ∀t∈R+. ()
In what follows, we writeJ= [,t],Jk= (tk–,tk] (k= , , , . . .).
Lemma If conditions(H)-(H)are satisfied,then operator A defined by()is a
contin-uous operator from Q+into Q;moreover,for any q>p> ,A(Qpq)is relatively compact.
Proof Letu∈Q+anduB=r. Thenr> and, by () and Remark (a),
β–rt≤u(t)≤rt, β–r≤u(t)≤r, ∀t∈R+. ()
By conditions (H), (H) and (), we have (fork∗,h∗,a(t),g(u),b(t),G(v,w,z),gr(t) and
a∗r,b∗, see conditions (H) and (H))
ft,u(t),u(t), (Tu)(t), (Su)(t)≤a(t)gr(t) +Grb(t), ∀t∈R++, ()
where
Gr=maxg(v,w,z) :β–r≤v≤r, ≤w≤k∗r, ≤z≤h∗r, which implies the convergence of the infinite integral
∞
and
∞
ft,u(t),u(t), (Tu)(t), (Su)(t)dt≤a∗r+Grb∗. ()
On the other hand, by condition (H) and (), we have
¯
Ikutk–≤Nrγk (k= , , , . . .), ()
where
Nr=maxF(v) :β–r≤v≤r,
which implies the convergence of the infinite series
∞
k=
¯
Ikutk– ()
and
∞
k=
¯
Ik
utk–≤Nrγ∗. ()
In addition, from () we get
(Au)(t) t ≥
β–
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds
+ ∞
k=
¯
Ikut–k
, ∀t∈R++. ()
Moreover, by condition (H), we have
Ik(v)≤tkI¯k(v), ∀v∈R++(k= , , , . . .),
so, () gives
(Au)(t) t ≤
β–
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds+ ∞
k=
¯
Ikut–k
+
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds+ ∞
k=
¯
Ikut–k
= β
β–
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds
+ ∞
k=
¯
Ikut–k
On the other hand, by (), we have
(Au)(t) = β–
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds+ ∞
k=
¯
Ik
utk–
+
t
fs,u(s),u(s), (Tu)(s), (Su)(s)ds+
<tk<t
¯
Ik
ut–k, ∀t∈R+, ()
so,
(Au)(t)≥ β–
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds
+ ∞
k=
¯
Ikut–k
, ∀t∈R+ ()
and
(Au)(t)≤ β β–
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds
+ ∞
k=
¯
Ikut–k
, ∀t∈R+. ()
It follows from (), ()-() thatAu∈Q,i.e. Au∈DPC[R
+,R] and
inf t∈R++
(Au)(t) t ≥β
–AuS,
inf t∈R+
(Au)(t)≥β–(Au)B,
and, by (), (), () and (),
AuS≤
β β–
a∗r+Grb∗+Nrγ∗, ()
(Au)B≤ β β–
a∗r+Grb∗+Nrγ∗
. ()
Thus, we have proved thatAmapsQ+intoQ.
Now, we are going to show thatAis continuous. Letun,u¯∈Q+,un–u¯D→ (n→ ∞). Write¯uD= r¯(r¯> ) and we may assume that
¯
r≤ unD≤r¯ (n= , , , . . .).
So, () and () imply
β–¯r≤un(t)
t ≤¯r, β
–¯r≤u(t)¯
t ≤r,¯ ∀t∈R++(n= , , , . . .) ()
and
By (), we have
|(Aun)(t) – (Au)(t)¯ | t
≤
β–
∞
fs,un(s),u(s), (Tun)(s), (Sun)(s)
–fs,u(s),¯ u¯(s), (Tu)(s), (S¯ u)(s)¯ ds+ ∞
k=
Ik¯untk––¯Iku¯tk–
+
t
fs,un(s),un(s), (Tun)(s), (Sun)(s)–fs,u(s),¯ u¯(s), (Tu)(s), (T¯ u)(s)¯ ds
+ t
<tk<t
Ikunt–k–Iku¯t–k+
<tk<t
¯Ikunt–k–¯Iku¯tk–,
∀t∈R++(n= , , , . . .). ()
When <t≤t, we have
<tk<t
Ikuntk––Iku¯tk–= ,
so,
sup t∈R++
t
<tk<t
Ik
untk––Ik
¯
utk–
= sup t<t<∞
t
<tk<t
Ikunt–k–Iku¯t–k
≤
t
∞
k=
Ik
unt–k–Iku¯t–k. ()
It follows from () and () that
Aun–Au¯S = sup
t∈R++
|(Aun)(t) – (Au)(t)¯ | t
≤
t
∞
k=
Ikuntk––Iku¯tk–
+ β β–
∞
fs,un(s),un(s), (Tun)(s), (Sun)(s)
–fs,u(s),¯ u¯(s), (Tu)(s), (S¯ u)(s)¯ ds +
∞
k=
¯Ikunt–k–¯Iku¯t–k
(n= , , , . . .). ()
It is clear that
ft,un(t),un(t), (Tun)(t), (Sun)(t)
and, similar to () and observing (), we have
f
t,un(t),un(t), (Tun)(t), (Sun)(t)–ft,u(t),¯ u¯(t), (Tu)(t), (S¯ u)(t)¯
≤a(t)g(t) +¯ Gb(t)¯ =σ(t), ∀t∈R++(n= , , , . . .), ()
where
¯
g(t) =maxg(u) :β–¯rt≤u≤rt¯,
¯
G(t) =maxg(v,w,z) :β–¯r≤v≤r, ¯ ≤w≤k∗r, ¯ ≤z≤h∗¯r. It is easy to see that condition (H) implies
a∗pq=
∞
a(t)gpq(t)dt<∞ ()
for anyq>p> , where
gpq(t) =max
g(u) :β–pt≤u≤qt. () So,
∞
a(t)g(t)dt¯ <∞,
and therefore,
∞
σ(t)dt<∞. ()
It follows from (), (), () and the dominated convergence theorem that
lim n→∞
∞
ft,un(t),un(t), (Tun)(t), (Sun)(t)–ft,u(t),¯ u¯(t), (Tu)(t), (S¯ u)(t)¯ dt
= . ()
On the other hand, similar to () and observing (), we have
¯
Ikuntk–≤ ¯Nrγk, Ik¯u¯tk–≤ ¯Nrγk (k,n= , , , . . .), () where
¯
Nr=maxF(v) :β–r¯≤v≤r¯.
For any given> , by () and condition (H), we can choose a positive integerksuch
that
∞
k=k+
and
∞
k=k+
tkI¯k
¯
utk–<,
so,
∞
k=k+
Ikuntk–< (n= , , , . . .), () ∞
k=k+
Iku¯tk–<, ()
∞
k=k+
¯
Ikuntk–≤ t
∞
k=k+
tkIk¯untk–<t– ()
and
∞
k=k+
¯
Ik
¯
utk–≤ t
∞
k=k+
tkI¯k
¯
utk–<t– . ()
It is clear that
Ikuntk–→Iku¯t–k asn→ ∞(k= , , , . . .) and
¯
Ikuntk–→ ¯Iku¯t–k asn→ ∞(k= , , , . . .), so, we can choose a positive integernsuch that
k
k=
Ikunt–k–Iku¯t–k<, ∀n>n ()
and
k
k=
¯Ikunt–k–¯Iku¯t–k<, ∀n>n. ()
From ()-(), we get
∞
k=
Ikunt–k–Iku¯t–k< , ∀n>n
and
∞
k=
hence
lim n→∞
∞
k=
Ikuntk––Iku¯tk–= ()
and
lim n→∞
∞
k=
I¯k
untk––¯Ik
¯
utk–= . ()
It follows from (), (), () and () that
lim
n→∞Aun–Au¯S= . ()
On the other hand, from () it is easy to get
(Aun)– (Au)¯ B≤ β β–
∞
fs,un(s),un(s), (Tun)(s), (Sun)(s)
–fs,u(s),¯ u¯(s), (Tu)(s), (S¯ u)(s)¯ ds +
∞
k=
¯Ikunt–k–¯Iku¯t–k
. ()
So, (), () and () imply
lim n→∞(Aun)
– (Au)¯
B= . ()
It follows from () and () thatAun–Au¯D→ asn→ ∞, and the continuity ofAis proved.
Finally, we prove thatA(Qpq) is relatively compact, whereq>p> are arbitrarily given. Letu¯n∈Qpq(n= , , , . . .). Then, by (),
β–pt≤ ¯un(t)≤qt, β–p≤ ¯un(t)≤q, ∀t∈R+(n= , , , . . .). ()
Similar to (), (), () and observing (), we have
ft,un(t),¯ u¯n(t), (Tun)(t), (S¯ un)(t)¯
≤a(t)gpq(t) +Gpqb(t), ∀t∈R++(n= , , , . . .), ()
¯
Iku¯ntk–≤Npqγk (k,n= , , , . . .) () and
Au¯nS≤ β β–
a∗pq+Gpqb∗+Npqγ∗
(n= , , , . . .), ()
wheregpq(t) anda∗pqare defined by () and (), respectively, and
From () we see that functions{(Aun)(t)¯ }(n= , , , . . .) are uniformly bounded on [,r] for anyr> . On the other hand, by () and ()-(), we have
≤(Aun)¯ t– (Aun)(t)¯ = t
–t
β–
∞
fs,un(s),¯ u¯n(s), (Tun)(s), (S¯ un)(s)¯ ds+ ∞
k=
¯
Iku¯ntk–
+t–t t
fs,un(s),¯ u¯n(s), (Tun)(s), (S¯ un)(s)¯ ds
+
t t
t–sfs,u¯n(s),u¯n(s), (Tu¯n)(s), (Su¯n)(s)
ds
+t–t
<tk<t
¯
Ik
¯
unt–k
≤ t–t
β–
a∗pq+Gpqb∗+Npqγ∗
+t–ta∗pq+Gpqb∗
+ (tk–tk–)
t t
a(s)gpq(s) +Gpqb(s)
ds+t–tNpqγ∗,
∀t,t∈Jk,t>t(k,n= , , , . . .),
which implies that functions{wn(t)}(n= , , , . . .) defined by (for any fixedk)
wn(t) =
(Aun)(t),¯ ∀t∈Jk= (tk–,tk],
(Aun)(t¯ +
k–), ∀t=tk–
(n= , , , . . .)
((Aun¯ )(t+
k–) denotes the right limit of (Aun¯ )(t) at t=tk–) are equicontinuous on ¯Jk=
[tk–,tk]. Consequently, by the Ascoli-Arzela theorem,{wn(t)}has a subsequence which is convergent uniformly onJ¯k. So, functions{Au¯n(t)}(n= , , , . . .) have a subsequence which is convergent uniformly on Jk. Now, by the diagonal method, we can choose a subsequence{(Au¯ni)(t)} (i= , , , . . .) of{(Au¯n)(t)} (n= , , , . . .) such that {(Au¯ni)(t)} (i= , , , . . .) is convergent uniformly on eachJk(k= , , , . . .). Let
lim
i→∞(Au¯ni)(t) =w(t),¯ ∀t∈R+. ()
Similarly, we can discuss{(Aun)¯ (t)}(n= , , , . . .). Similar to () and by (), we have
(Au¯n)B≤ β β–
a∗pq+Gpqb∗+Npqγ∗
(n= , , , . . .) ()
and
≤(Aun)¯ t– (Aun)¯ (t) =
t t
fs,un(s),¯ u¯n(s), (Tun)(s), (S¯ un)(s)¯ ds
≤ t
t
a(s)gpq(s) +Gpqb(s)ds, ∀t,t∈Jk,t>t(n= , , , . . .),
no-tation, we may assume that{(Auni¯ )(t)}(i= , , , . . .) itself converges uniformly on eachJk (k= , , , . . .). Let
lim i→∞(Au¯ni)
(t) =y(t). ()
By (), () and the uniformity of convergence, we have
¯
w(t) =y(t), ∀t∈R+, ()
and so,w¯ ∈PC[R+,R]. From () and (), we get
¯wS≤ β β–
a∗pq+Gpqb∗+Npqγ∗
and
w¯B≤ β β–
a∗pq+Gpqb∗+Npqγ∗.
Consequently,w¯ ∈DPC[R
+,R] and
¯wD≤ β β–
a∗pq+Gpqb∗+Npqγ∗.
Let> be arbitrarily given. Choose a sufficiently large positive numberηsuch that
∞
η
a(t)gpq(t)dt+Gpq
∞
η
b(t)dt+Npq tk≥η
γk<. ()
For anyη<t<∞, we have, by (), () and (),
≤(Auni¯ )(t) – (Auni¯ )(η)
=
t
η
fs,uni¯ (s),u¯ni(s), (Tuni¯ )(s), (Suni¯ )(s)ds+
η≤tk<t
¯
Iku¯nit–k
≤
t
η
a(s)gpq(s)ds+Gpq
t
η
b(s)ds+Npq
η≤tk<t
γk (i= , , , . . .),
which implies by virtue of () that
≤(Auni¯ )(t) – (Auni¯ )(η) <, ∀t>η(i= , , , . . .). ()
Lettingi→ ∞in () and observing () and (), we get
≤ ¯w(t) –w¯(η)≤, ∀t>η. ()
On the other hand, since{(Au¯ni)(t)}converges uniformly tow¯(t) on [,η] asi→ ∞, there exists a positive integerisuch that
It follows from ()-() that
(Auni¯ )(t) –w¯(t)≤(Auni¯ )(t) – (Auni¯ )(η)+(Auni¯ )(η) –w¯(η)
+w¯(η) –w¯(t)< , ∀t>η,i>i. ()
By () and (), we have
(Au¯ni)–w¯B≤, ∀i>i,
hence
lim i→∞(Auni¯ )
–w¯
B= . ()
It is clear that () implies
(Auni¯ )tk+– (Auni¯ )tk–=Iku¯nitk– (k,i= , , , . . .). ()
By virtue of the uniformity of convergence of{(Auni¯ )(t)}, we see that
lim i→∞(Au¯ni)
t–k=w¯t–k, lim i→∞(Au¯ni)
tk+=w¯tk+ (k= , , , . . .),
so, () implies that
lim i→∞Ik
¯
unitk– (k= , , , . . .)
exist and
¯
wt+k–w¯tk–=lim i→∞Ik
¯
un i
tk– (k= , , , . . .).
Let
lim i→∞Ik
¯
unitk–=αk (k= , , , . . .).
Thenαk≥ (k= , , , . . .) and
¯
wt+k–w¯tk–=αk (k= , , , . . .). ()
By () and condition (H), we have
Ik
¯
unit–k≤Npqtkγk (k,i= , , , . . .), ()
so,
For any given> , choose a sufficiently large positive integerksuch that
Npq ∞
k=k+
tkγk<, ()
and then, choose another sufficiently large integerisuch that
Iku¯nitk––αk< k
, ∀i>i(k= , , . . . ,k). ()
It follows from ()-() that
∞
k=
Iku¯nitk––αk≤ k
k=
Iku¯nit–k–αk
+ ∞
k=k+
Iku¯nit–k+ ∞
k=k+
αk< , ∀i>i,
hence
lim i→∞
∞
k=
Ik
¯
unit–k–αk= . ()
By formula () and (), (), we have
(Auni¯ )(t) =
t
(Auni¯ )(s)ds+
<tk<t
Iku¯nitk–, ∀t∈R+(i= , , , . . .)
and
¯
w(t) =
t
¯
w(s)ds+
<tk<t
αk, ∀t∈R+,
which imply
(Auni¯ )(t) –w(t)¯ ≤t(Auni¯ )–w¯B
+
<tk<t
Iku¯nitk––αk, ∀t∈R+(i= , , , . . .). ()
Since
<tk<t
Iku¯nitk––αk= , ∀ <t≤t,
() implies
Auni¯ –w¯S≤(Auni¯ )–w¯B+t–
∞
k=
By (), () and (), we have
lim
i→∞Auni¯ –w¯S= . ()
It follows from () and () thatAu¯ni–w¯D→ asi→ ∞, and the relative compactness
ofA(Qpq) is proved.
Lemma Let conditions (H)-(H)be satisfied.Then u∈Q+∩C[R++,R]is a positive
solution of IBVP()if and only if u∈Q+is a solution of the following impulsive integral
equation:
u(t) = t β–
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds+ ∞
k=
¯
Ikut–k
+
t
(t–s)fs,u(s),u(s), (Tu)(s), (Su)(s)ds
+
<tk<t
Ikut–k+ (t–tk)¯Ikut–k, ∀t∈R+, ()
i.e. u is a fixed point of operator A defined by().
Proof Ifu∈Q+∩C[R++,R] is a positive solution of IBVP (), then, by () and formula
(), we have
u(t) =tu() +
t
(t–s)fs,u(s),u(s), (Tu)(s), (Su)(s)ds
+
<tk<t
Ikut–k+ (t–tk)¯Ikut–k, ∀t∈R+. ()
Differentiation of () gives
u(t) =u() +
t
fs,u(s),u(s), (Tu)(s), (Su)(s)ds+
<tk<t
¯
Ik
ut–
k
, ∀t∈R+. ()
Under conditions (H)-(H), we have shown in the proof of Lemma that the infinite
integral () and the infinite series () are convergent. So, by taking limits ast→ ∞in both sides of () and using the relationu(∞) =βu(), we get
u() = β–
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds+ ∞
k=
¯
Ikut–k
. ()
Now, substituting () into (), we see thatu(t) satisfies equation ().
Conversely, ifu∈Q+ is a solution of equation (), then direct differentiation of ()
twice gives
u(t) = β–
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds+ ∞
k=
¯
Ikutk–
+
t
fs,u(s),u(s), (Tu)(s), (Su)(s)ds+
<tk<t
¯
and
u(t) =ft,u(t),u(t), (Tu)(t), (Su)(t), ∀t∈R++.
So,u∈C[R
++,R] and
u|t=tk=Ik
utk–, u|t=tk=¯Ik
utk– (k= , , , . . .).
Moreover, taking limits ast→ ∞in (), we see thatu(∞) exists and
u(∞) = β β–
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds+ ∞
k=
¯
Ikut–k
=βu().
Hence,u(t) is a positive solution of IBVP ().
Lemma (Fixed point theorem of cone expansion and compression with norm type, see Corollary in [] or Theorem in [] or Theorem .. in [], see also [, ]) Let P be a cone in a real Banach space E and,be two bounded open sets in E such that
θ ∈,¯⊂,whereθ denotes the zero element of E and¯idenotes the closure ofi (i= , ).Let the operator A:P∩(¯\)→P be completely continuous(i.e. continuous
and compact).Suppose that one of the following two conditions is satisfied:
(a) Ax ≤ x,∀x∈P∩∂;Ax ≥ x,∀x∈P∩∂,where∂idenotes the
boundary ofi(i= , ).
(b) Ax ≥ x,∀x∈P∩∂;Ax ≤ x,∀x∈P∩∂.
Then A has at least one fixed point in P∩(¯\).
3 Main theorem
Theorem Let conditions(H)-(H)be satisfied.Assume that there exists r> such that
β β–
a∗r+Grb∗+Nrγ∗<r, ()
where a∗r,b∗andγ∗are defined in conditions(H)and(H),and,Grand Nrare defined
by two equalities below()and(),respectively.Then IBVP()has at least two positive solutions u∗,u∗∗∈Q+∩C[R++,R]such that
< inf t∈R++
u∗(t) t ≤t∈Rsup++
u∗(t) t <r,
< inf t∈R+
u∗(t)≤sup t∈R+
u∗(t) <r,
β–r< inf t∈R++
u∗∗(t) t ≤t∈Rsup++
u∗∗(t) t <∞
and
β–r< inf t∈R+
u∗∗(t)≤sup t∈R+
Proof By Lemma and Lemma , operatorAdefined by () is continuous fromQ+into
Q, and we need to prove thatAhas two fixed pointsu∗andu∗∗inQ+such that <u∗D< r<u∗∗D.
By condition (H), there existsr> such that
f(t,u,v,w,z)≥β
(β– )
c∗ c(t)v, ∀t,u∈R++,v≥r,w,z∈R+. ()
Choose
r>max
βr,r
. ()
Foru∈Q,uD=r, we have, by () and (),
u(t)≥β–r>r, ∀t∈R+,
so, () and () imply
(Au)(t)≥ β–
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds
≥β
c∗
∞
c(s)u(s)ds≥r c∗
∞
c(s)ds=r, ∀t∈R+,
and consequently,
(Au)B≥r,
hence
AuD≥ uD, ∀u∈Q,uD=r. ()
By condition (H), there existsr> such that
f(t,u,v,w,z)≥(β– )r
d∗ d(t), ∀t,u∈R++, <v<r,w,z∈R+. ()
Choose
<r<min{r,r}. ()
Foru∈Q,uD=r, we have, by () and (),
r>r≥u(t)≥β–r> ,
so, we get, by () and (),
(Au)(t)≥ β–
∞
fs,u(s),u(s), (Tu)(s), (Su)(s)ds
≥ r
d∗
∞
hence
(Au)B>r,
and consequently,
AuD>uD, ∀u∈Q,uD=r. ()
On the other hand, foru∈Q,uD=r, () and () imply
AuD≤
β β–
a∗r+Grb∗+Nrγ∗. ()
Thus, from () and (), we get
AuD<uD, ∀u∈Q,uD=r. ()
By () and () we know <r<r<r, and, by Lemma , operatorAis completely
con-tinuous fromQrrintoQ. Hence, (), (), () and Lemma imply thatAhas two fixed
pointsu∗,u∗∗∈Qrr such thatr<u∗D<r<u∗∗D≤r. The proof is complete.
Example Consider the infinite boundary value problem for second order impulsive sin-gular integro-differential equation of mixed type on the half line:
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩
u(t) = e–t
t
( [u(t)]
+
u(t)+ [u(t)] ) + e–t
t{
(te–(t+)su(s)ds)
+ (∞(+u(st)+dss))}, ∀ <t<∞,t=k(k= , , , . . .),
u|t=k= –k–
u(k–)+√u(k–) (k= , , , . . .),
u|t=k=k––k–√
u(k–) (k= , , , . . .),
u() = , u(∞) = u().
()
Conclusion IBVP () has at least two positive solutionsu∗,u∗∗∈PC[R+,R]∩C[R++,R]
such that
< inf
<t<∞ u∗(t)
t ≤<supt<∞ u∗(t)
t < ,
< inf
≤t<∞
u∗(t)≤ sup
≤t<∞
u∗(t) < ,
<<inft<∞ u∗∗(t)
t ≤<supt<∞ u∗∗(t)
t <∞
and
<≤tinf<∞
u∗∗(t)≤ sup
≤t<∞
u∗∗(t) <∞.
Proof System () is an IBVP of form (). In this situation,tk=k(k= , , , . . .),K(t,s) = e–(t+)s,H(t,s) = ( +t+s)–,β= , and
f(t,u,v,w,z) = e
–t
t
u
+ v+v
+ e
–t
t
Ik(v) = –k–
v+√v, ∀v∈R++(k= , , , . . .),
¯
Ik(v) =k––k–√
v, ∀v∈R++(k= , , , . . .).
It is clear that ()-() are satisfied, so, () is a singular problem. It is easy to see that condition (H) is satisfied andk∗≤,h∗≤. We have
f(t,u,v,w,z)≤ e
–t
t
u
+e
–t
t
v+v
+
w+z,
so, condition (H) is satisfied for
a(t) = e
–t
t
, g(u) = u
, b(t) =e
–t
t
and
g(v,w,z) =
v+v
+
w+z
with
gr(t) =max u– :rt
≤u≤rt
= r
t–,
a∗r=
∞
a(t)gr(t)dt= r ∞
e–t
t
dt<∞
()
and
b∗=
∞
e–t
t
dt<∞. ()
It is obvious that condition (H) is satisfied forγk=k––k– (γ∗= ) andF(v) =v–
.
From
f(t,u,v,w,z)≥ e
–t
t
v, ∀t,u,v∈R++,w,z∈R+
and
f(t,u,v,w,z)≥ e
–t
t
v, ∀t,u,v∈R++,w,z∈R+,
we see that conditions (H) and (H) are satisfied for
c(t) = e
–t
t
c∗=b∗, see ()
and
d(t) =e
–t
t
respectively. Finally, we check that inequality () is satisfied forr= ,i.e.
a∗+Gb∗+Nγ∗
< . ()
By () and (), we have
a∗ =
∞
e–t
t
dt<
dt
t
+
∞
e–tdt
= + e – < + = , and
b∗<
dt
t
+
∞
e–tdt= +
e
–<
.
Moreover, it is easy to get
G<
, N= .
Hence
a∗+Gb∗+Nγ∗
< ,+ ,+ = , ,< .
Consequently, () holds, and our conclusion follows from the theorem.
Competing interests
The author declares that they have no competing interests.
Acknowledgements
The author thanks the reviewers for valuable suggestions.
Received: 8 December 2014 Accepted: 21 April 2015 References
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