R E S E A R C H
Open Access
Existence of positive solutions of the Cauchy
problem for a second-order differential
equation
Toshiharu Kawasaki
1*and Masashi Toyoda
2*Correspondence:
1College of Engineering, Nihon
University, Fukushima, 963-8642, Japan
Full list of author information is available at the end of the article
Abstract
In this paper we consider the equationu(t) =f(t,u(t),u(t)) and prove the unique solvability of the Cauchy problemu(0) = 0,u(0) =
λ
withλ
> 0.1 Introduction
In [], Knežević-Miljanović considered the Cauchy problem
u(t) =P(t)tau(t)σ, t∈(, ],
u() = , u() =λ, ()
wherePis continuous,a,σ,λ∈Rwithσ< andλ> , and|P(t)|ta+σdt<∞. Moreover,
in [], Kawasaki and Toyoda considered the Cauchy problem
u(t) =f(t,u(t)), for almost everyt∈[, ],
u() = , u() =λ, ()
wheref is a mapping from [, ]×(,∞) intoRandλ∈Rwithλ> . They proved the unique solvability of Cauchy problem () using the Banach fixed point theorem. The the-orem in [] is as follows.
Theorem Suppose that a mapping f from[, ]×[,∞)intoRsatisfies the following.
(a) The mappingt−→f(t,u)is measurable for anyu∈(,∞),and the mapping
u−→f(t,u)is continuous for almost everyt∈[, ].
(b) |f(t,u)| ≥ |f(t,u)|for almost everyt∈[, ]and for anyu,u∈[,∞)with u≤u.
(c) There existsα∈Rwith <α<λsuch that
f(t,αt)dt<∞.
(d) There existsβ∈Rwithβ> such that
∂u∂f(t,u)≤β|f(t,u)|
u
for almost everyt∈[, ]and for anyu∈(,∞).
Then there exists h∈Rwith <h≤such that Cauchy problem()has a unique solution in X,where X is a subset
X=
u
u∈C[,h],u() = ,u() =λ andαt≤u(t)for any t∈[,h]
of C[,h],which is the class of continuous mappings from[,h]intoR.
The case thatf(t,u(t)) =P(t)tau(t)σ in the above theorem is the theorem of
Knežević-Miljanović [].
In this paper, we consider the Cauchy problem
u(t) =f(t,u(t),u(t)), for almost everyt∈[, ],
u() = , u() =λ,
wheref is a mapping from [, ]×(,∞)×RintoRandλ∈Rwithλ> . We prove the unique solvability of this Cauchy problem using the Banach fixed point theorem.
In Section , we consider the following four cases foruandv.
(I) Decreasing foruinf(t,u,v)(b) and decreasing forvinf(t,u,v)(b). (II) Decreasing foruinf(t,u,v)(b) and increasing forvinf(t,u,v)(b). (III) Increasing foruinf(t,u,v)(b) and decreasing forvinf(t,u,v)(b). (IV) Increasing foruinf(t,u,v)(b) and increasing forvinf(t,u,v)(b).
Theorems ., ., . and . are the cases of (I), (II), (III) and (IV), respectively.
2 Main results
In this section, we consider the Cauchy problem
u(t) =f(t,u(t),u(t)), for almost everyt∈[, ],
u() = , u() =λ, ()
wheref is a mapping from [, ]×(,∞)×RintoRandλ∈Rwithλ> . First, we consider the case of (I).
Theorem . Letλbe a real number withλ> .Suppose that a mapping f from[, ]× (,∞)×RintoRsatisfies the following:
(a) The mappingt−→f(t,u,v)is measurable for any(u,v)∈(,∞)×R,and the mapping(u,v)−→f(t,u,v)is continuous for almost everyt∈[, ];
(b) |f(t,u,v)| ≥ |f(t,u,v)|for almost everyt∈[, ],for anyu,u∈(,∞)with u≤uand for anyv∈R;
(b) |f(t,u,v)| ≥ |f(t,u,v)|for almost everyt∈[, ],for anyu∈(,∞)and for any v,v∈Rwithv≤v;
(c) There existα∈Rwith <α<λandα∈Rwithα<λsuch that
(d) There existsβ∈Rwithβ> such that
∂f
∂u(t,u,v)
≤β|f(t,u,v)| u
for almost everyt∈[, ],for anyu∈(,∞)and for anyv∈R; (d) There existsβ∈Rwithβ> such that
∂f∂v(t,u,v)≤βf(t,u,v)
for almost everyt∈[, ],for anyu∈(,∞)and for anyv∈R; (e) There exists the limit
lim
t→+
t
t
sfs,u(s),u(s)ds
for any continuously differentiable mappingufrom[, ]into[,∞); (f) Forαandα,
lim
t→+
t
t
sf(s,αs,α)ds= .
Then there exists h∈Rwith <h≤such that Cauchy problem()has a unique solution in X,where X is a subset
X=
⎧ ⎪ ⎨ ⎪ ⎩u
u∈C[,h],u() = ,u() =λ,
αt≤u(t)andα≤u(t)for any t∈[,h] and there exists the limitlimt→+tu
(t)–u(t)
t
⎫ ⎪ ⎬ ⎪ ⎭
of C[,h],which is the class of continuously differentiable mappings from[,h]intoR.
Proof It is noted thatC[,h] is a Banach space by the maximum norm
u =maxmaxu(t)|t∈[,h],maxu(t)|t∈[,h]. Instead of Cauchy problem (), we consider the integral equation
u(t) =λt+
t
(t–s)fs,u(s),u(s)ds.
By condition (c), there existsh∈Rwith <h≤ such that
h
f(t,αt,α)dt<min
λ–α,λ–α,
β α
+ β
–
.
By condition (f), there existsh∈Rwith <h≤hsuch that
sup
t∈(,h]
t
t
sf(s,αs,α)ds≤
h
LetAbe an operator fromXintoC[,h] defined by
Au(t) =λt+
t
(t–s)fs,u(s),u(s)ds.
Since a mappingt−→λtbelongs toX,X= ∅. Moreover, we haveA(X)⊂X. Indeed, by condition (a),Au∈C[,h],Au() = and
(Au)() =
λ+
t
fs,u(s),u(s)ds
t=
=λ.
By conditions (b) and (b), we obtain that
Au(t) =λt+
t
(t–s)fs,u(s),u(s)ds
≥λt–t
h
fs,u(s),u(s)ds
≥λt–t
h
f(s,αs,α)ds
≥αt
and
(Au)(t) =λ+
t
fs,u(s),u(s)ds
≥λ–
h
fs,u(s),u(s)ds
≥λ–
h
f(s,αs,α)ds
≥α
for anyt∈[,h]. Moreover, by condition (e), there exists the limit
lim
t→+
t(Au)(t) –Au(t)
t =tlim→+
t
t
sfs,u(s),u(s)ds.
We will find a fixed point ofA. Letϕbe an operator fromXintoC[,h] defined by
ϕ[u](t) =
u(t)
t ift∈(,h],
λ ift= .
Letϕ[X] be a subset defined by
ϕ[X] =ϕ[u]|u∈X. Then we have
ϕ[X] =
v
v∈C[,h],v() =λ,
α≤v(t) andα≤v(t) +tv(t) for anyt∈[,h]
andϕ[X] is a closed subset ofC[,h]. Hence it is a complete metric space. Letbe an
operator fromϕ[X] intoϕ[X] defined by
ϕ[u] =ϕ[Au].
By the mean value theorem, for anyu,u∈X, there exist mappingsξ,ηsuch that
ft,u(t),u(t)
–ft,u(t),u(t)
=∂f
∂u
t,ξ(t),u(t)u(t) –u(t)
+∂f
∂v
t,u(t),η(t)
u(t) –u(t) =
t∂f ∂u
t,ξ(t),u(t)+∂f
∂v
t,u(t),η(t)
ϕ[u](t) –ϕ[u](t)
+t∂f ∂v
t,u(t),η(t)
ϕ[u](t) –ϕ[u](t)
,
minu(t),u(t)
≤ξ(t)≤maxu(t),u(t)
and
minu(t),u(t)≤η(t)≤maxu(t),u(t)
for almost everyt∈[,h]. Therefore, by conditions (b), (b), (d) and (d), we obtain that
ft,u(t),u(t)
–ft,u(t),u(t)
=
t∂f ∂u
t,ξ(t),u(t)+∂f
∂v
t,u(t),η(t)
ϕ[u](t) –ϕ[u](t)
+t∂f ∂v
t,u(t),η(t)
ϕ[u](t) –ϕ[u](t)
≤
t∂f ∂u
t,ξ(t),u(t)+∂f
∂v
t,u(t),η(t)
ϕ[u](t) –ϕ[u](t)
+t∂f ∂v
t,u(t),η(t)ϕ[u](t) –ϕ[u](t)
≤
β α
+β
f(t,αt,α)ϕ[u](t) –ϕ[u](t)
+βtf(t,αt,α)ϕ[u](t) –ϕ[u](t)
for almost everyt∈[,h]. Therefore we have
ϕ[u](t) –ϕ[u](t)
=
t
t
(t–s)fs,u(s),u(s)
–fs,u(s),u(s)
ds
≤
t
fs,u(s),u(s)
–fs,u(s),u(s)ds
≤ t β α
+β
+βsf(s,αs,α)ϕ[u](s) –ϕ[u](s)
ds
≤
β α
+ β
h
f(s,αs,α)dsϕ[u] –ϕ[u]
for anyt∈[,h]. Moreover, we have
ϕ[u]
(t) –ϕ[u]
(t) =
t
t
sfs,u(s),u(s)
–fs,u(s),u(s)
ds
≤
t
t
sfs,u(s),u(s)
–fs,u(s),u(s)ds
≤
t
t
s
β α
+β
f(s,αs,α)ϕ[u](s) –ϕ[u](s)
+βsf(s,αs,α)ϕ[u](s) –ϕ[u](s)
ds
≤
β α
+β
h
f(s,αs,α)ds
+β
h
f(s,αs,α)ds
ϕ[u] –ϕ[u]
for anyt∈[,h]. Hence we obtain that
ϕ[u] –ϕ[u]
≤
β α
+ β
h
f(s,αs,α)dsϕ[u] –ϕ[u].
By the Banach fixed point theorem, there exists a unique mappingϕ[u]∈ϕ[X] such that
ϕ[u] =ϕ[u]. ThenAu=u.uis a solution of ().
Next, we consider the case of (II).
Theorem . Letλbe a real number withλ> .Suppose that a mapping f from[, ]× (,∞)×RintoRsatisfies the following:
(a) The mappingt−→f(t,u,v)is measurable for any(u,v)∈(,∞)×R,and the mapping(u,v)−→f(t,u,v)is continuous for almost everyt∈[, ];
(b) |f(t,u,v)| ≥ |f(t,u,v)|for almost everyt∈[, ],for anyu,u∈(,∞)with u≤uand for anyv∈R;
(b) |f(t,u,v)| ≤ |f(t,u,v)|for almost everyt∈[, ],for anyu∈(,∞)and for any v,v∈Rwithv≤v;
(c) There existα∈Rwith <α<λandα∈Rwithα>λsuch that
(d) There existsβ∈Rwithβ> such that
∂f∂u(t,u,v)≤ β|f(t,u,v)|
u
for almost everyt∈[, ],for anyu∈(,∞)and for anyv∈R; (d) There existsβ∈Rwithβ> such that
∂f∂v(t,u,v)≤βf(t,u,v)
for almost everyt∈[, ],for anyu∈(,∞)and for anyv∈R; (e) There exists the limit
lim
t→+
t
t
sfs,u(s),u(s)ds
for any continuously differentiable mappingufrom[, ]into[,∞); (f) Forαandα,
lim
t→+
t
t
sf(s,αs,α)ds= .
Then there exists h∈Rwith <h≤such that Cauchy problem()has a unique solution in X,where X is a subset
X=
⎧ ⎪ ⎨ ⎪ ⎩u
u∈C[,h],u() = ,u() =λ,
αt≤u(t)and u(t)≤αfor any t∈[,h] and there exists the limitlimt→+tu
(t)–u(t)
t
⎫ ⎪ ⎬ ⎪ ⎭
of C[,h].
Proof By condition (c), there existsh∈Rwith <h≤ such that
h
f(t,αt,α)dt<min
λ–α,α–λ,
β α
+ β
–
.
By condition (f), there existsh∈Rwith <h≤hsuch that
sup
t∈(,h]
t
t
sf(s,αs,α)ds≤
h
f(t,αt,α)dt.
LetAbe an operator fromXintoC[,h] defined by
Au(t) =λt+
t
(t–s)fs,u(s),u(s)ds.
Since a mappingt−→λtbelongs toX,X= ∅. Moreover, we haveA(X)⊂X. Indeed, by condition (a),Au∈C[,h],Au() = and
(Au)() =
λ+
t
fs,u(s),u(s)ds
t=
By conditions (b) and (b), we obtain that
Au(t) =λt+
t
(t–s)fs,u(s),u(s)ds
≥λt–t
h
f
s,u(s),u(s)ds
≥λt–t
h
f(s,αs,α)ds
≥αt
and
(Au)(t) =λ+
t
fs,u(s),u(s)ds
≤λ+
h
fs,u(s),u(s)ds
≤λ+
h
f(s,αs,α)ds
≤α
for anyt∈[,h]. Moreover, by condition (e), there exists the limit
lim
t→+
t(Au)(t) –Au(t)
t =tlim→+
t
t
sfs,u(s),u(s)ds.
We will find a fixed point ofA. Letϕbe an operator fromXintoC[,h] defined by
ϕ[u](t) =
u(t)
t ift∈(,h],
λ ift= ,
and
ϕ[X] =ϕ[u]|u∈X
=
v
v∈C[,h],v() =λ,
α≤v(t) andv(t) +tv(t)≤αfor anyt∈[,h]
.
Thenϕ[X] is a closed subset ofC[,h] and hence it is a complete metric space. Letbe
an operator fromϕ[X] intoϕ[X] defined by
ϕ[u] =ϕ[Au].
Then we can show, just like Theorem ., that by the Banach fixed point theorem there exists a unique mappingϕ[u]∈ϕ[X] such thatϕ[u] =ϕ[u] and henceAu=u.
Theorem . Letλbe a real number withλ> .Suppose that a mapping f from[, ]× (,∞)×RintoRsatisfies the following:
(a) The mappingt−→f(t,u,v)is measurable for any(u,v)∈(,∞)×R,and the mapping(u,v)−→f(t,u,v)is continuous for almost everyt∈[, ];
(b) |f(t,u,v)| ≤ |f(t,u,v)|for almost everyt∈[, ],for anyu,u∈(,∞)with u≤uand for anyv∈R;
(b) |f(t,u,v)| ≥ |f(t,u,v)|for almost everyt∈[, ],for anyu∈(,∞)and for any v,v∈Rwithv≤v;
(c) There existα∈Rwith <α<λandα∈Rwithα<λsuch that
ft, (λ–α)t,αdt<∞;
(d) There existsβ∈Rwithβ> such that
∂u∂f(t,u,v)≤β|f(t,u,v)|
u
for almost everyt∈[, ],for anyu∈(,∞)and for anyv∈R; (d) There existsβ∈Rwithβ> such that
∂f∂v(t,u,v)≤βf(t,u,v)
for almost everyt∈[, ],for anyu∈(,∞)and for anyv∈R; (e) There exists the limit
lim
t→+
t
t
sfs,u(s),u(s)ds
for any continuously differentiable mappingufrom[, ]into[,∞); (f) Forαandα,
lim
t→+
t
t
sfs, (λ–α)s,αds= .
Then there exists h∈Rwith <h≤such that Cauchy problem()has a unique solution in X,where X is a subset
X=
⎧ ⎪ ⎨ ⎪ ⎩u
u∈C[,h],u() = ,u() =λ,
αt≤u(t)≤(λ–α)t andα≤u(t)for any t∈[,h] and there exists the limitlimt→+tu
(t)–u(t)
t
⎫ ⎪ ⎬ ⎪ ⎭
of C[,h].
Proof By condition (c), there existsh∈Rwith <h≤ such that
h
ft, (λ–α)t,αdt<min
λ–α,λ–α,
β α
+ β
–
By condition (f), there existsh∈Rwith <h≤hsuch that
sup
t∈(,h]
t
t
sfs, (λ–α)s,αds≤
h
ft, (λ–α)t,αdt.
LetAbe an operator fromXintoC[,h] defined by
Au(t) =λt+
t
(t–s)fs,u(s),u(s)ds.
Since a mappingt−→λtbelongs toX,X=∅. Moreover,A(X)⊂X. Indeed, by condition (a),Au∈C[,h],Au() = ,
(Au)() =
λ+
t
fs,u(s),u(s)ds
t=
=λ,
by conditions (b) and (b),
Au(t) =λt+
t
(t–s)fs,u(s),u(s)ds
≥λt–t
h
fs,u(s),u(s)ds
≥λt–t
h
fs, (λ–α)s,αds
≥αt,
Au(t) =λt+
t
(t–s)fs,u(s),u(s)ds
≤λt+t
h
f
s,u(s),u(s)ds
≤λt+t
h
fs, (λ–α)s,αds
≤(λ–α)t,
(Au)(t) =λ+
t
fs,u(s),u(s)ds
≥λ–
h
f
s,u(s),u(s)ds
≥λ–
h
fs, (λ–α)s,αds
≥α
for anyt∈[,h], and by condition (e), there exists the limit
lim
t→+
t(Au)(t) –Au(t)
t =tlim→+
t
t
We will find a fixed point ofA. Letϕbe an operator fromXintoC[,h] defined by
ϕ[u](t) =
u(t)
t ift∈(,h],
λ ift= ,
and
ϕ[X] =ϕ[u]|u∈X
=
v
v∈C[,h],v() =λ,
α≤v(t)≤λ–αandα≤v(t) +tv(t) for anyt∈[,h]
.
Thenϕ[X] is a closed subset ofC[,h], and hence it is a complete metric space. Letbe
an operator fromϕ[X] intoϕ[X] defined by
ϕ[u] =ϕ[Au].
Then we can show, just like Theorem ., that by the Banach fixed point theorem there exists a unique mappingϕ[u]∈ϕ[X] such thatϕ[u] =ϕ[u] and henceAu=u.
Finally, we consider the case of (IV).
Theorem . Letλbe a real number withλ> .Suppose that a mapping f from[, ]× (,∞)×RintoRsatisfies the following:
(a) The mappingt−→f(t,u,v)is measurable for any(u,v)∈(,∞)×R,and the mapping(u,v)−→f(t,u,v)is continuous for almost everyt∈[, ];
(b) |f(t,u,v)| ≤ |f(t,u,v)|for almost everyt∈[, ],for anyu,u∈(,∞)with u≤uand for anyv∈R;
(b) |f(t,u,v)| ≤ |f(t,u,v)|for almost everyt∈[, ],for anyu∈(,∞)and for any v,v∈Rwithv≤v;
(c) There existα∈Rwith <α<λandα∈Rwithα>λsuch that
ft, (λ–α)t,αdt<∞;
(d) There existsβ∈Rwithβ> such that
∂u∂f(t,u,v)≤β|f(t,u,v)|
u
for almost everyt∈[, ],for anyu∈(,∞)and for anyv∈R; (d) There existsβ∈Rwithβ> such that
∂f∂v(t,u,v)≤βf(t,u,v)
(e) There exists the limit
lim
t→+
t
t
sfs,u(s),u(s)ds
for any continuously differentiable mappingufrom[, ]into[,∞); (f) Forαandα,
lim
t→+
t
t
sfs, (λ–α)s,αds= .
Then there exists h∈Rwith <h≤such that Cauchy problem()has a unique solution in X,where X is a subset
X=
⎧ ⎪ ⎨ ⎪ ⎩u
u∈C[,h],u() = ,u() =λ,
αt≤u(t)≤(λ–α)t and u(t)≤αfor any t∈[,h] and there exists the limitlimt→+tu
(t)–u(t)
t
⎫ ⎪ ⎬ ⎪ ⎭
of C[,h].
Proof By condition (c), there existsh∈Rwith <h≤ such that
h
ft, (λ–α)t,αdt<min
λ–α,α–λ,
β α
+ β
–
.
By condition (f), there existsh∈Rwith <h≤hsuch that
sup
t∈(,h]
t
t
sfs, (λ–α)s,αds≤
h
ft, (λ–α)t,αdt.
LetAbe an operator fromXintoC[,h] defined by
Au(t) =λt+
t
(t–s)fs,u(s),u(s)ds.
Since a mappingt−→λtbelongs toX,X= ∅. Moreover,A(X)⊂X. Indeed, by condition (a),Au∈C[,h],Au() = ,
(Au)() =
λ+
t
fs,u(s),u(s)ds
t=
=λ,
by conditions (b) and (b),
Au(t) =λt+
t
(t–s)fs,u(s),u(s)ds
≥λt–t
h
fs,u(s),u(s)ds
≥λt–t
h
fs, (λ–α)s,αds
Au(t) =λt+
t
(t–s)fs,u(s),u(s)ds
≤λt+t
h
fs,u(s),u(s)ds
≤λt+t
h
fs, (λ–α)s,αds
≤(λ–α)t,
(Au)(t) =λ+
t
fs,u(s),u(s)ds
≤λ+
h
fs,u(s),u(s)ds
≤λ+
h
f(s,αs,α)ds
≤α
for anyt∈[,h], and by condition (e), there exists the limit
lim
t→+
t(Au)(t) –Au(t)
t =tlim→+
t
t
sfs,u(s),u(s)ds.
We will find a fixed point ofA. Letϕbe an operator fromXintoC[,h] defined by
ϕ[u](t) =
u(t)
t ift∈(,h],
λ ift= ,
and
ϕ[X] =ϕ[u]|u∈X
=
v
v∈C[,h],v() =λ,
α≤v(t)≤λ–αandv(t) +tv(t)≤αfor anyt∈[,h]
.
Thenϕ[X] is a closed subset ofC[,h] and hence it is a complete metric space. Letbe
an operator fromϕ[X] intoϕ[X] defined by
ϕ[u] =ϕ[Au].
Then we can show, just like Theorem ., that by the Banach fixed point theorem there exists a unique mappingϕ[u]∈ϕ[X] such thatϕ[u] =ϕ[u] and henceAu=u.
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
Author details
1College of Engineering, Nihon University, Fukushima, 963-8642, Japan.2Marine Faculty of Engineering, Tamagawa
University, Tokyo, 194-8610, Japan.
Received: 1 June 2013 Accepted: 20 September 2013 Published:07 Nov 2013 References
1. Kneževi´c-Miljanovi´c, J: On the Cauchy problem for an Emden-Fowler equation. Differ. Equ.45(2), 267-270 (2009) 2. Kawasaki, T, Toyoda, M: Existence of positive solution for the Cauchy problem for an ordinary differential equation. In:
Li, S, Wang, X, Okazaki, Y, Kawabe, J, Murofushi, T, Guan, L (eds.) Nonlinear Mathematics for Uncertainly and Its Applications. Advances in Intelligent and Soft Computing, vol. 100, pp. 435-441. Springer, Berlin (2011)
10.1186/1029-242X-2013-465