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(1)

Multiple scale technique

Second order systems

Lesson 11

(2)

Weakly nonlinear oscillator

d2u

dt2 + ω02u = εF (u, du dt ).

it is a general form of Duffing’s equation

d2u

dt2 + u ∓ εu3 = 0 with F = ±u3 or van der Pol’s oscillator

d2u

dt2 + u − ε(1 − u2)du

dt = 0 with F = (1 − u2)du

dt .

For the first equation the method of renormalization

(3)

Type of solutions of the second order ODE.

The multiple scale technique permits successfully treat all types of weakly nonlinear oscillators. But

before introducing the method we review the types of the the second order ODE.

We start from the unperturbed equation

d2u

dt2 + ω02u = 0.

Its solution is

1 du

(4)

The phase plane

Let us introduce the coordinate system with x = u and

y = dudt . Then

x = u = A cos ω0t + B sin ω0t

and

y = du

dt = −ω0A sin ω0t + ω0B cos ω0t.

Eliminating t yields the solution curve on (x, y) plane

x2 + y2

ω02 = A2 + B2.

(5)

The phase plane

The curves x2 + y2 = A2 + B2 are ellipses with

(6)

The phase plane

The differential equation ddt2u2 + dudt + 2u = 0 has the general solution

u = e2t 

A cos

7

2 t + B sin

7 2 t

where

A = u(0) and A

2 +

7B

2 = du dt (0)

(7)

The phase plane

as we see the solutions are the spiral into the origin

(8)

Linear autonomous equations

There are three types of behavior of solutions of autonomous linear differential equations:

1. periodic orbits,

2. decay towards the origin, 3. diverge to the infinity.

(9)

Nonlinear autonomous equations

The nonlinear autonomous differential equations has one more special type of solutions limit cycle.

Occurrence of this type depends both on the form of the equation and on the initial conditions. As an

example consider the equation

d2u

dt2 = −u + 

1 − u2 du dt

2du dt .

(10)

Nonlinear autonomous equations

Let us write the equation ddt2u2 = −u + 1 − u2 dudt 2dudt using the phase plane variables

x = u, y = dx

dt = du dt .

Then the equation is equivalent to the system

dx

dt = y | · x

dy

dt = −x + (1 − x2 − y2)y | · y

(11)

Nonlinear autonomous equations

d

dt(x2 + y2) = 2(1 − x2 − y2)y2.

Using the polar coordinates

x = r cos θ r = sin θ

we get the

d

dt(r2) = 2(1 − r2)r2 sin2 θ.

(12)

Nonlinear autonomous equations

There is three possibility for the equation

d

dt(r2) = 2(1 − r2)r2 sin2 θ

1. If r = 1 then dtd (r2) = 0 and r = const give the periodic solution.

2. If r > 1 then dtd (r2) < 0 and the solution decrease to the periodic solution.

3. If r < 1 then dtd (r2) > 0 and the solution increase to the periodic solution.

This situation called the stable limit cycle.

(13)

Limit cycle

(14)

Types of solutions for nonlinear ODE

The solutions of nonlinear autonomous second order differential equations belong to the following four

classes

1. periodic solutions, 2. limit cycles,

3. solutions tends towards a fixed value 4. solutions tends to infinity.

The renormalization is success only for the first type of solutions.

(15)

Limitation of renormalization

Let us compare two problems

d2u

dt2 + u = εu, u(0) = 1, du

dt (0) = 0 d2v

dt2 + v = −εdv

dt , v(0) = 1, dv

dt (0) = 0

We look for the two term expansions

u(t, ε) = u0(t) + εu1(t)

and

(16)

Limitation of renormalization

The second coefficients are following

d2u1

dt2 + u1 = cos t, u1(0) = du1

dt (0) = 0 ⇒ u1 = t

2 sin t, d2v1

dt2 + v1 = − sin t, v1(0) = dv1

dt (0) = 0 ⇒ v1 = 1

2(−t cos t + sin t).

(17)

Limitation of renormalization

Introducing the strained coordinates t = s + εf1, we get for the first equation

cos t + 1

2εt sin t = cos(s + εf1) + 1

2εs sin s

= cos s − εf1 sin s + 1

2εs sin s

Choosing f1 = 2s we have u = cos s + O(ε) where

t = s + εs

2 + O(ε2)

(18)

Limitation of renormalization

Expressing s

s = t

1 + ε

2 + O(ε2)−1

= t

1 − ε

2 + O(ε2) .

Thus

u = cos t

1 − ε

2 + . . .  .

The exact solution is

u = cos t

1 − ε = cos t

1 − ε

2 + . . .  .

The renormalization provides a means of evaluating

(19)

Limitation of renormalization

Introducing the strained coordinates t = s + εf1 for the second equation

cos t − 1

2ε(t cos t − sin t) = cos(s + εf1) − 1

2ε(s cos s − sin s)

= cos s − εf1 sin s − 1

2εs cos s + 1

2ε sin s

f1 = −s2 cot s is not acceptable since it ia singular for

s = π, 2π, 3π, . . .. Trying to make the expansion of solution uniform the strained expansion becomes nonuniform. Let us compare with the exact solution.

(20)

Time changing amplitude

u = eεt2 

cos r

1 − ε2

4 t + ε 2

q

1 − ε42

sin r

1 − ε2 4 t

 .

It is not a periodic solution since the frequency of oscillation and the amplitude are changed.

The frequency of oscillation changed from 1 to q1 − ε42

The amplitude eεt2 decays.

Let us see why the renormalization failed in general case.

(21)

Limitation of renormalization

d2u

dt2 + u = εF (u, du

dt ), u(0) = a, du

dt (0) = 0

Starting from two term expansion u0 + εu1 we get

u0 = a cos t and

d2u1

dt2 + u1 = εF (a cos t, −a sin t).

Since F is a periodic function, it can be decomposed into the Fourier series

(22)

Limitation of renormalization

The homogeneous solution is A cos t + B sin t, so the term a1 cos t + b1 sin t will generate a particular solution

t

2(a1 sin t − b1 cos t).

The two term expansion is

a cos t + ε t

2(a1 sin t − b1 cos t) + nonsecular terms Using the renormalization t = s + εf1 we get

s nonsecular terms

(23)

Limitation of renormalization

We require f1 = a21as − b1s cot 2sa. We see that iff b1 = 0 we avoid the problems with cot 2sa. In this case the expansion is

u = a cos s + O(ε), t = s + εa1s

2a + O(ε2) ⇒ u = a cos t

1 − εa1

2a + . . .  .

The expansion can generate only periodic solutions.

(24)

Limitation of renormalization

For Duffing’s equation we had F = −u3, so

F(a cos t, −a sin t) = −a3 cos3 t = a3

4 (3 cos t + cos 3t)

and renormalization gave the positive result.

For van der Pol’s oscillator F = (1 − u2)dudt

F = (1 − a2 cos2 t)(−a sin t) = (−a + a3

4 ) sin t + a3

4 sin 3t.

If a 6= 2 the renormalization fails. The case a = 2

corresponds to the limit cycle and the normalization is

(25)

The end

References

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