Available online throug
ISSN 2229 – 5046
International Journal of Mathematical Archive- 9(4), April-2018 66
ON TRANS-SASAKIAN MANIFOLDS SATISFYING CERTAIN CURVATURE CONDITIONS
RIDDHI JUNG SHAH*
Department of Mathematics, Janata Campus, Nepal Sanskrit University, Dang, Nepal.
(Received On: 27-02-18; Revised & Accepted On: 03-04-18)
ABSTRACT
T
he present paper deals with a study of trans-Sasakian manifolds satisfying certain curvature conditions on contact conformal curvature tensor. It is shown that the trans-Sasakian manifold satisfying the curvature conditions,
0
).
,
(
0
X
R
=
C
ξ
C
0(
ξ
,
X
).
C
0=
0
andC
~
(
ξ
,
X
).
C
0=
0
is contact conformally semi-symmetric manifold.Keywords: Trans-Sasakian manifold, contact conformal curvature tensor, semi-symmetric, concircular curvature tensor.
MSC 2010: 53C15, 53C25, 53D15.
1.INTRODUCTION
In [5], authors studied on the sixteen classes of almost Hermitian manifolds and their linear invariants. They considered unitary group
U
(
n
)
on a certain spaceW
and studied that the representation ofU
(
n
)
onW
has four irreducible components,W
=
W
1⊕
W
2⊕
W
3⊕
W
4.
Among these componentsW
3⊕
W
4 corresponds to the class of Hermitian manifolds. A new class of almost contact metric structure, called trans-Sasakian structure was studied in [9] which is an analogue of a locally conformal Kaehler structure on an almost Hermitian manifold. An almost contact metric structure(
ϕ
,
ξ
,
η
,
g
)
(where the symbols have their usual meanings) onM
is trans-Sasakian [9] if(
M
×
R
,
J
,
G
)
belongs to the classW
4,
whereJ
is the almost complex structure onM
×
R
defined by
=
−
dt
d
X
f
X
dt
d
f
X
J
,
ϕ
ξ
,
η
(
)
(1.1)for any vector field
X
onM
,
whereG
is the product metric onM
×
R
.
Trans-Sasakian manifold is the trans-Sasakian structure of type(
α
,
β
),
whereα
andβ
are smooth functions onM
.
Trans-Sasakian manifold of type)
0
,
(
),
0
,
0
(
α
and(
0
,
β
)
are cosympletic [1],α
-Sasakian andβ
-Kenmotsu manifold [2,7] respectively. Trans-Sasakian manifolds have been studied in [3], [10] and by others.In [6], contact conformal curvature tensor field was introduced and defined by Jeong et al. in a
(
2
n
+
1
)
-dimensional Sasakian manifold.2. PRELIMINARIES
Let
M
be a(
2
n
+
1
)
-dimensional differentiable manifold with an almost contact metric structure(
ϕ
,
ξ
,
η
,
g
),
whereϕ
is a (1, 1) tensor field,ξ
is a vector field,η
is a 1-form andg
is a compatible Riemannian metric such that [1],
)
(
)
(
2
η
ξ
ϕ
X
=
−
X
+
X
η
(
ξ
)
=
1
,
ϕξ
=
0
,
η
(
ϕ
X
)
=
0
,
(2.1)),
(
)
(
)
,
(
)
,
(
X
Y
g
X
Y
X
Y
g
ϕ
ϕ
=
−
η
η
(2.2)),
(
)
,
(
),
,
(
)
,
(
X
Y
g
X
Y
g
X
X
g
ϕ
=
−
ϕ
ξ
=
η
(2.3) for allX
,
Y
∈
TM
.
The fundamental 2-form Φ of the almost contact metric structure(
ϕ
,ξ
,η
,g)
is defined as), , ( ) , ( ) ,
(X Y =g X ϕY =−g ϕX Y
Φ (2.4)
Corresponding Author: Riddhi Jung Shah*
Since ϕ is a skew-symmetric with respect to .g
An almost contact metric manifold M is called trans-Sasakian manifold if [9]
( )
∇Xϕ
Y =α
{g(X,Y)ξ
−η
(Y)X}+β
{g(ϕ
X,Y)ξ
−η
(Y)ϕ
X}, (2.5) where ∇is Levi-Civita connection of Riemannian metric gand α,β are smooth functions on M.From (2.5) it follows that
}, ) ( {
η
ξ
β
αϕ
ξ
X X XX =− + −
∇ (2.6) ).
, ( ) , ( )
(∇X
η
Y =−α
gϕ
X Y +β
gϕ
Xϕ
Y (2.7)In a (2n+1)-dimensional trans-Sasakian manifold M,the following relations hold [3]:
(
)
), ( ) ( ) ( ] ) ( ) ( [ 2
) ( ) ( ) ( ] ) ( ) ( [ )
, (
2 2 2
2
X Y X Y Y X X Y
Y X Y X Y X X Y Y
X R
ϕ
β
ϕ
α
ϕ
η
ϕ
η
αβ
ϕ
β
ϕ
α
η
η
β
α
ξ
+ +
− +
− −
− −
=
(2.8)
), )( , ( ] ) ( )[ (
) )( , ( ) ( ] ) (
) , ( [ 2 ] ) ( ) , ( )[ (
) ,
( 2 2
β ϕ
ϕ ξ η β
α ϕ
ϕ α ϕ
η
ξ ϕ αβ η
ξ β
α ξ
grad Y X g X X Y
grad X Y g X Y X Y
X Y g X
Y Y
X g Y
X R
− −
+
+ +
−
+ −
− =
(2.9)
, 0 ) (
2αβ+ ξα = (2.10)
), )( 1 2 ( ) ) (( ) ( )] ( ) (
2 [ ) ,
(X
ξ
nα
2β
2ξβ
η
Xϕ
Xα
n Xβ
S = − − − − − (2.11)
), , ) , ( ( ) ) , (
(R X Y Z g R X Y ξ Z
η =− (2.12) ,
0 ) , ( ( ) ) , ( ( ) ) , (
( ξ =η ξ ξ =η ξ ξ =
η R X Y R X R X (2.13)
). , ( )) ( (
) ) , (
(R
ξ
X Yα
2β
2ξβ
gϕ
Xϕ
Yη
= − − (2.14)In a (2n+1)-dimensional trans-Sasakian manifold if we put ϕ(gradα)=(2n−1)gradβ,then some of the above relations are reduced to
, 0 )
(ξβ = (2.15)
), ( ) (
2 ) ,
(X n 2 2 X
S
ξ
=α
−β
η
(2.16)), , ( ) (
) ) , (
(R
ξ
X Yα
2β
2 gϕ
Xϕ
Yη
= − (2.17) },) ( ){ (
) ,
( X 2 2 X X
R
ξ
ξ
=α
−β
η
ξ
− (2.18). ) , ( ) ,
(X ξ ξ Rξ X ξ
R =− (2.19)
We shall calculate all the results under the condition ϕ(gradα)=(2n−1)gradβ.
In a (2n+1)-dimensional trans-Sasakian manifold the contact conformal curvature tensor field C0and the concircular
curvature tensor C~of type (1, 3) are defined by
0
1
( , ) ( , ) { ( , ) ( , ) ( , ) 2
( , ) ( , ) ( ) ( , ) ( )
( ) ( ) ( ) ( ) ( , )
( , ) ( , ) ( ) ( ,
C X Y Z R X Y Z S Y Z X S X Z Y g Y Z QX n
g X Z QY S X Z Y S Y Z X
X Z QY Y Z QX S X Z Y
S Y Z X g X Z Q Y g Y Z
η ξ η ξ
η η η η φ φ
φ φ φ φ φ
= + − +
− + −
+ − +
− + −
2
) ( )
2 ( , ) ( ) 2 ( , ) }
1 ( 2)
{2 2 }{ ( , )
2 22( 1) 2
1 (3 2)
( , ) 2 ( , ) } { 2 }
2 ( 1) 2
{
Q X
g X Y Q Z S X Y Z
n r
n n g Y Z X
n n n
n r
g X Z Y g X Y Z n
n n n
φ
φ φ φ φ
φ φ
φ φ φ φ
+ +
+
+ − − +
+
+
− − + + −
+
× 1 2 (3 2)
( , ) ( , ) } {4 5 2 }
2 ( 1) 2
{ ( ) ( ) ( ) ( ) ( , ) ( ) ( , ) ( ) } n r
g Y Z X g X Z Y n n
n n n
Y Z X X Z Y g Y Z X g X Z Y
η η η η η ξ η ξ
+
− − + + −
+
× − + −
(2.20)
© 2018, IJMA. All Rights Reserved 68
} ) , ( ) , ( { ) 1 2 ( 2 ) , ( ) , ( ~
V Z U g U Z V g n n
r Z
V U R Z V U
C −
+ −
= (2.21)
for all X,Y,Z,U,V∈χ(M)respectively [4].
From (2.20), we have
}, ) ( ) ( ){ 2 (
) , ( ) ,
( 2 2
0 X Y R X Y Y X X Y
C ξ = ξ+ α −β − η −η (2.22)
}, ) ( ) , ( ){ 2 (
) , ( ) ,
( 2 2
0 X Y R X Y g X Y Y X
C ξ = ξ + α −β − ξ −η (2.23)
)}, ( ) , ( ) ( ) , ( ){ 2 (
) ) , ( ( ) ) , (
(C0 X Y Z η R X Y Z α2 β2 g Y Z η X g X Z η Y
η = + − − − (2.24)
, 0 ) ) , (
( 0 ξ =
η C X Y (2.25) )}.
( ) ( ) , ( ){ 1 (
2 ) ) , (
( 2 2
0 X Y g X Y X Y
C ξ α β η η
η = − − − (2.26)
From (2.21), we also have
}. ) ( ) , ( { ) 1 2 ( 2 ) , ( ) , ( ~
V Z Z
V g n n
r Z
V R Z V
C ξ ξ ξ−η
+ −
= (2.27)
Definition: A (2n+1)-dimensional trans-Sasakian manifold M is said to be an Einstein manifold if its Ricci tensor S of type (0, 2) is of the form
) , ( ) ,
(X Y g X Y
S =λ (2.28) where λis a scalar function on M.
3. TRANS-SASAKIAN MANIFOLD SATISFYING
C
0(
ξ
,
X
).
S
=
0
Now, we prove the following result
Theorem 3.1: If a trans-Sasakian manifold Mof dimension (2n+1) satisfies the condition C0(ξ,X).S =0,then the
manifold is an Einstein manifold and its scalar curvature is r=2n(2n+1)(
α
2−β
2).Proof: Let Mbe a (2n+1)-dimensional trans-Sasakian manifold which satisfies the condition
. 0 ) , )( ). , (
(C0 ξ X S U V = (3.1) (3.1) implies that
. 0 ) ) , ( , ( ) , ) , (
(C0 X U V +S U C0 X V =
S ξ ξ (3.2)
Putting V =ξin (3.2) and using (2.16) and (2.23), we obtain
). , ( ) (
2 ) ,
(X U n 2 2 g X U
S =
α
−β
(3.3)Let {ei},i=1,2,...,2n+1be an orthonormal basis of the tangent space at any point of the manifold. Putting X =U =ei
in (3.3) and summing over i,1≤i≤2n+1,we get
). )(
1 2 (
2 +
α
2−β
2 = n nr (3.4)
In view of (3.3) and (3.4) it follows that the manifold Mis an Einstein manifold with scalar curvature
). )(
1 2 (
2 +
α
2−β
2 = n nr This completes the proof of the theorem.
4. TRANS-SASAKIAN MANIFOLD SATISFYING
C
~
(
ξ
,
X
).
C
0=
0
Theorem 4.1: Let M be a (2n+1)-dimensional trans-Sasakian manifold. If M satisfies the condition
, 0 ). , ( ~
0 = C X
C ξ then the manifold is contact conformally semi-symmetric. Proof: By definition we have
0
0 0 0
( , ) ( , ) ( ( , ) , ) ( , ( , ) ) ( , ) ( , ) 0 C ξ X C U V Z−C C ξ X U V Z−C U C ξ X V Z−C U V C ξ X Z=
Using (2.21) in (4.1) we get
0 0
0 0
0
0
( , ) ( , ) { ( , ( , ) ) 2 (2 1)
( ( , ) ) } ( , ) { ( , ) ( ) },
2 (2 1)
, ( , ) { ( , ) ( ) }
2 (2 1)
( , ) ( , ) { ( , ) ( ) } 0
2 (2 1) r
R X C U V Z g X C U V Z
n n
r
C U V Z X C R X U g X U U X V Z
n n
r
C U R X V g X V V X Z
n n
r
C U V R X Z g X Z Z X
n n
ξ ξ
η ξ ξ η
ξ ξ η
ξ ξ η
−
+
− − − −
+
− − −
+
− − − =
+
Or,
0 0 0
0 0
0 0 0
0 0 0
0
[ ( , ) ( , ) ( ( , ) , ) ( , ( , ) )
( , ) ( , ) ] [ ( ( , ) ) 2 (2 1)
( , ( , ) ) ( , ) ( , ) ( ) ( , )
( , ) ( , ) ( ) ( , ) ( , ) ( , )
( ) ( , ) ] 0
R X C U V Z C R X U V Z C U R X V Z
r
C U V R X Z C U V Z X
n n
g X C U V Z g X U C V Z U C X V Z
g X V C U Z V C U X Z g X Z C U V
Z C U V X
ξ ξ ξ
ξ η
ξ ξ η
ξ η ξ
η
− −
− +
+
− + −
+ − +
− =
Or,
(
( , ). 0)
( , ) [ ( 0( , ) ) 2 (2 1)r
R X C U V Z C U V Z X
n n
ξ + η
+
0 0 0
0 0 0
0
( , ( , ) ) ( , ) ( , ) ( ) ( , )
( , ) ( , ) ( ) ( , ) ( , ) ( , )
( ) ( , ) ] 0.
g X C U V Z g X U C V Z U C X V Z
g X V C U Z V C U X Z g X Z C U V
Z C U V X
ξ ξ η
ξ η ξ
η
− + −
+ − +
− =
(4.2)
Putting Z=ξin (4.2) and taking inner product on both sides by ξwe get
. 0 ] ) , ( ( ) ) , ( , ( [ ) 1 2 ( 2 ) , ) , ( ). , (
( 0 − 0 − 0 =
+
+ g X C U V C U V X
n n
r V
U C X R
g ξ ξ ξ ξ η (4.3)
Using (2.22) and (2.24) in (4.3), we get
)]. ) , ( ( ) ) , ( , ( [ ) 1 2 ( 2 ) , ) , ( ). , (
( 0 g X R U V R U V X
n n
r V
U C X R
g ξ ξ ξ − ξ −η
+
+ (4.4)
In view of (2.8), (2.12) and (4.4) we obtain
. 0 ) , ( ). ,
(ξ X C0 U V ξ =
R (4.5) Equation (4.5) implies that the manifold is contact conformally semi-symmetric. This completes the proof of the theorem.
5. TRANS-SASAKIAN MANIFOLD SATISFYING
C
0(
ξ
,
X
).
C
0=
0
Theorem 5.1: Let Mbe a (2n+1)-dimensional trans-Sasakian manifold. The manifold M satisfying the condition
0 ). , ( 0 0 X C =
C ξ is contact conformally semi-symmetric if
. 0 ) , ( ) , ) , ( ( } ) , ( ) , ( ) , ( 2 ){
(
α
2−β
2 g V Z X −g X V Z−g X Z V −g Rξ
V Z Xξ
−R X V Z =Proof: Let Mbe a trans-Sasakian manifold of dimension (2n+1)which satisfies the condition
, 0 ) , ( ). , ( 0
0 X C U V Z=
C ξ then by definition we have
0( , ) 0( , ) 0( 0( , ) , ) 0( , 0( , ) ) 0( , ) 0( , ) 0 .
C ξ X C U V Z−C C ξ X U V Z−C U C ξ X V Z−C U V C ξ X Z = (5.1)
Using (2.23) in (5.1) we get
) , ( ) , ( ) , ( ) ( ) , ( ) , (
) , ( ) ( ) , ( ) , ( ) ) , ( (
) ) , ( , ( )[ 2 (
) , ( ). , (
0 0
0
0 0
0
0 2
2 0
− +
−
+ −
−
− − +
V U C Z X g Z X U C V Z U C V X g
Z V X C U Z V C U X g X Z V U C
Z V U C X g Z
V U C X R
ξ η
ξ
η ξ
η
ξ β
α ξ
© 2018, IJMA. All Rights Reserved 70 Taking inner product on both sides of (5.2) by ξand using (2.25) we obtain
. 0 )] ) , ( ( ) ( ) ) , ( ( ) (
) ) , ( ( ) , ( ) ) , ( ( ) (
) ) , ( ( ) , ( ) ) , ( ( ) (
) ) , ( , ( )[ 2 (
) , ) , ( ). , ( (
0 0
0 0
0 0
0 2
2 0
= −
+
− +
− −
− − +
X V U C Z Z X U C V
Z U C V X g Z V X C U
Z V C U X g Z V U C X
Z V U C X g Z
V U C X R g
η η η
η
ξ η
η η
ξ η η
η
β α ξ ξ
(5.3)
Putting U =ξin (5.3) and using (2.23), (2.24) and (2.26), we get
. 0 )}] , ( ) (
) , ( ) ( 2 ) , ( ) ( ){ (
) ) , ( (
) , ) , ( ( )[ 2 (
) , ) , ( ). , ( (
2 2
2 2 0
= +
− −
+ +
− − +
Z X g V
Z V g X V
X g Z Z
V X R
X Z V R g Z
V C X R g
η
η η
β α η
ξ β
α ξ ξ ξ
(5.4)
Equation (5.4) implies that
]. ) , (
) , ) , ( ( } ) , ( ) , (
) , ( 2 ){ )[(
2 (
) , ( ). ,
( 2 2 2 2
0
Z V X R
X Z V R g V Z X g Z V X g
X Z V g Z
V C X R
−
− −
−
− −
− =
ξ ξ
β α β
α ξ
ξ
(5.5)
From (5.5) it follows that the manifold M is contact conformally semi-symmetric if the right hand side vanishes i.e., if
2 2
(α −β ){2 ( ,g V Z X) −g X V Z( , ) −g X Z V( , ) }−g R( ( , ) ,ξ V Z X)ξ−R X V Z( , ) =0 . (5.6)
This completes the proof of the theorem.
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Source of support: Nil, Conflict of interest: None Declared.