Biology
Sylvia S. Mader Michael Windelspecht
Chapter 12
Molecular Biology of the Gene
Lecture Outline
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Outline
• 12.1 The Genetic Material
• 12.2 Replication of DNA
• 12.3 The Genetic Code of Life
• 12.4 First Step: Transcription
• 12.5 Second Step: Translocation
• 12.6 Structure of the Eukaryotic Chromosome
12.1 The Genetic Material
• Frederick Griffith investigated virulence of
Streptococcus pneumoniae
Concluded that virulence could be passed
from a dead strain to a nonvirulent living strain
Transformation
• Further research by Avery et al.
Discovered that DNA is the transforming
substance
DNA from dead cells was being incorporated
into the genome of living cells
The Genetic Material
• Griffith’s Transformation Experiment
Mice were injected with two strains of
pneumococcus: an encapsulated (S) strain and a non-encapsulated (R) strain.
• The S strain is virulent (the mice died); it has a mucous capsule and forms “shiny” colonies.
• The R strain is not virulent (the mice lived); it has no capsule and forms “dull” colonies.
Griffith’s Transformation
Experiment
5
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capsule
Injected live S strain has capsule and causes mice
to die.
a. b.
Injected live R strain has no capsule and mice do not die.
c.
Injected heat- killed S strain does not cause mice to die.
d.
Injected heat-killed S strain plus live
R strain causes
The Genetic Material
• Transformation of organisms today:
Result is the so-called genetically modified
organisms (GMOs)
• Invaluable tool in modern biotechnology today
• Commercial products that are currently much used • Green fluorescent protein (GFP) can be used as a
marker
– A jellyfish gene codes for GFP
– The jellyfish gene is isolated and then transferred to a bacterium, or the embryo of a plant, pig, or mouse. – When this gene is transferred to another organism, the
organism glows in the dark
Transformation of Organisms
The Genetic Material
• DNA contains:
Two Nucleotides with purine bases
• Adenine (A)
• Guanine (G)
Two Nucleotides with pyrimidine bases
• Thymine (T)
• Cytosine (C)
The Genetic Material
• Chargaff’s Rules:
The amounts of A, T, G, and C in DNA:
• Are constant among members of the same species • Vary from species to species
In each species, there are equal amounts of:
• A and T • G and C
All this suggests that DNA uses
complementary base pairing to store genetic information
Each human chromosome contains, on
average, about 140 million base pairs
The number of possible nucleotide sequences
is 4140,000,000
Nucleotide Composition of DNA
10
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O N N CH CH C C NH2 cytosine (C)
3 C C2
C 1 O HO P O
O H H H H H OH CH3 O HN N C CH C C O HO P O
O H H H H H OH HN N N
C CH
O
C C C
N H2N
C 2 C 2 C 1 C 1 O HO P O
O guanine (G) phosphate H H H H H OH N N N HC CH NH2 C C C N 4
3 C 2 C 1 5 O O O O O O H H H H H OH
c. Chargaff’s data
DNA Composition in Various Species (%) Species
Homo sapiens (human)
Drosophila melanogaster (fruit fly) Zea mays (corn)
Neurospora crassa (fungus) Escherichia coli (bacterium) Bacillus subtilis (bacterium)
31.0 27.3 25.6 23.0 24.6 28.4 31.5 27.6 25.3 23.3 24.3 29.0 19.1 22.5 24.5 27.1 25.5 21.0 18.4 22.5 24.6 26.6 25.6 21.6 A T G C
a. Purine nucleotides b. Pyrimidine nucleotides nitrogen-containing
base
sugar = deoxyribose thymine
(T) adenine
(A)
HO P O CH2
5 CH2 5 CH2 5 CH2 C
4 C
4 C
4 C C
3 C
3 C
The Genetic Material
• X-Ray diffraction:
Rosalind Franklin studied the structure of DNA using X-rays.
She found that if a concentrated, viscous solution of DNA is made, it can be separated into fibers.
Under the right conditions, the fibers can produce an X-ray diffraction pattern
• She produced X-ray diffraction photographs.
• This provided evidence that DNA had the following features: – DNA is a helix.
– Some portion of the helix is repeated.
X-Ray Diffraction of DNA
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© Photo Researchers, Inc.; c: © Science Source/Photo Researchers, Inc.
X-ray beam
b. c.
Rosalind Franklin
diffraction pattern
Crystalline DNA diffracted
X-rays
The Genetic Material
• The Watson and Crick Model (1953)
Double helix model is similar to a twisted ladder
• Sugar-phosphate backbones make up the sides
• Hydrogen-bonded bases make up the rungs
Complementary base pairing ensures that a purine is always bonded to a pyrimidine (A with T, G with C)
Received a Nobel Prize in 1962
Watson and Crick Model of DNA
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P P P P c . P
S G C S
P P S S A T G C C G T T A A C G P 0.34 nm 3.4 nm sugar-phosphate backbone a. b. d.
5′ end 3′ end
3′ end 5′ end
complementary base pairing hydrogen bonds sugar 2 nm
12.2 Replication of DNA
•
DNA replication
is the process of copying
a DNA molecule.
•
Semiconservative replication
-
each
strand of the original double helix (
parental
molecule) serves as a
template
(mold or
model) for a new strand in a daughter
molecule.
Semiconservative Replication
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old strand new
strand
A A A A A A T T T G G G G G G G C C C C C
region of parental DNA double helix
region of replication: new nucleotides are pairing with those of parental strands region of completed replication old strand new strand
daughter DNA double helix
daughter DNA double helix DNA
polymerase enzyme
5′ 3′
3′
17
Replication of DNA
• Replication requires the following steps:
Unwinding, or separation of the two strands of the parental DNA molecule
Complementary base pairing between a new
nucleotide and a nucleotide on the template strand
Joining of nucleotides to form the new strand
Replication of DNA
• Prokaryotic Replication
Bacteria have a single circular loop of DNA
Replication moves around the circular DNA molecule in both directions
Produces two identical circles
The process begins at the origin of replication
Replication takes about 40 minutes, but the cell divides every 20 minutes
• A new round of replication can begin before the previous round is completed
Replication of DNA
• Eukaryotic Replication
DNA replication begins at numerous points
along each linear chromosome
DNA unwinds and unzips into two strands
Each old strand of DNA serves as a template
for a new strand
Complementary base-pairing forms a new
strand paired with each old strand
• Requires enzyme DNA polymerase
Replication of DNA
• Eukaryotic Replication
Replication bubbles spread bidirectionally until they meet
The complementary nucleotides are joined to form
new strands. Each daughter DNA molecule contains an old strand and a new strand.
Replication is semiconservative:
• One original strand is conserved in each daughter molecule, i.e., each daughter double helix has one parental strand and one new strand.
Prokaryotic versus Eukaryotic Replication
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replication fork replication bubble
parental strand
daughter strand
new DNA duplexes a. Replication in prokaryotes
b. Replication in eukaryotes
replication is occurring in two directions
Aspects of DNA Replication
22
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G C A T G C G C P P P P P P P P P P P P 5′ 4′C
3′C C2′ C 1′ H H H HH O
5′ end
3′ end Deoxyribosemolecule
3′ 3′ 3′ 5′ 5′ 3′ 5′ 3 5 2 4 6 7 1
OH Is attached here base is attached here
helicase at replication fork DNA polymerase template strand Okazaki fragment template strand lagging strand Direction of replication
template strand
parental DNA helix DNA polymerase
Replication fork introduces complications DNA ligase RNA primer 3 ′end OH CH2 OH
5′ end new strand
leading new strand DNA polymerase
Replication of DNA
• Accuracy of Replication
DNA polymerase is very accurate, yet makes
a mistake about once per 100,000 base pairs.
• Capable of identifying and correcting errors
12.3 The Genetic Code of Life
• Genes Specify Enzymes
Beadle and Tatum:
• Experiments on the fungus Neurospora
crassa
• Proposed that each gene specifies the synthesis of one enzyme
• One-gene-one-enzyme hypothesis
The Genetic Code of Life
• The mechanism of gene expression
DNA in genes specify information, but
information is not structure and function
Genetic information is expressed into
structure and function through protein synthesis
• The expression of genetic information into
structure and function:
DNA in a gene determines the sequence of
nucleotides in an RNA molecule
RNA controls the primary structure of a
The Central Dogma of Molecular Biology
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C G
G C A
G C C
G
C
G T
T
A G
C G
C
DNA
3' 5'
The Central Dogma of Molecular Biology
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nontemplate strand
template strand
C G
G C A
G C C
G
C
G T
T
A G
C G
C
G C
A G A C C C C
DNA
transcription in nucleus
mRNA
3 5
3 5
The Central Dogma of Molecular Biology
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codon 1 codon 2
nontemplate strand
template strand
codon 3
C G
G C A
G C C
G
C
G T
T
A G
C G
C
G C
A G A C C C C
DNA
transcription at ribosome
mRNA
3 5
3 3
5
The Central Dogma of Molecular Biology
29
codon 1 codon 2
nontemplate strand
template strand
codon 3
polypeptide N C C N C N C C R1 R2 R3
Serine Aspartate Proline O O O
C G G C A G C C G C G T T A G C G C G C
A G A C C C C
transcription in nucleus translation at ribosome mRN A 3 5 3 5 5 3
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The Genetic Code of Life
• RNA is a polymer of RNA nucleotides
RNA nucleotides contain the sugar ribose instead of deoxyribose
RNA nucleotides are of four types: uracil (U),
adenine (A), cytosine (C), and guanine(G)
Uracil (U) replaces thymine (T) of DNA
• Types of RNA
• Messenger (mRNA) - Takes a message from DNA in the nucleus to ribosomes in the cytoplasm
• Ribosomal (rRNA) - Makes up ribosomes, which read the message in mRNA
• Transfer (tRNA) - Transfers the appropriate amino acid to the ribosomes for protein synthesis
Structure of RNA
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G
U
A
C
S
S
S
S
P
P
P P
base is
uracil instead of thymine
one nucleotide
ribose 3′ end
RNA Structure Compared to
DNA structure
The Genetic Code of Life
• The unit of the genetic code consists of codons, each of which is a unique arrangement of symbols • Each of the 20 amino acids found in proteins is
uniquely specified by one or more codons
The symbols used by the genetic code are the mRNA bases
• Function as “letters” of the genetic alphabet
• Genetic alphabet has only four “letters” (U, A, C, G)
Codons in the genetic code are all three bases (symbols) long
• Function as “words” of genetic information • Permutations:
– There are 64 possible arrangements of four symbols taken three at a time
– Often referred to as triplets
• Genetic language only has 64 “words”
Messenger RNA Codons
34
U C A G
U C A G U C A G U C A G U C A G U C A G Second Base Third
Base First Base CGA arginine CGG arginine AGU serine AGC serine AGA arginine AGG arginine GGU glycine GGC glycine GGA glycine GGG glycine UGG tryptophan CGU arginine CGC arginine UGA stop AUG (start) methionine CAC histidine CAA glutamine CAG glutamine AAU asparagine AAC asparagine AAA lysine AAG lysine GAU aspartate GAC aspartate GAA glutamate GAG glutamate UUU phenylalanine CUU leucine CUC leucine CUA leucine CUG leucine AUU isoleucine AUC isoleucine AUA isoleucine GUU valine GUC valine GUA valine GUG valine UCA serine CCU proline CCC proline CCA proline CCG proline ACU threonine ACC threonine ACA threonine ACG threonine GCU alanine GCC alanine GCA alanine GCG alanine CAU histidine UAA stop UCU serine UAU tyrosine UGU cysteine UUC phenylalanine UCC serine UAC tyrosine UGU cysteine UUA leucine UCG serine UAG stop UUG leucine
The Genetic Code of Life
• Properties of the genetic code:
Universal
• With few exceptions, all organisms use the code the same way
• Encode the same 20 amino acids with the same 64 triplets
Degenerate (redundant)
• There are 64 codons available for 20 amino acids • Most amino acids encoded by two or more codons
Unambiguous (codons are exclusive)
• None of the codons code for two or more amino acids • Each codon specifies only one of the 20 amino acids
Contains start and stop signals
• Punctuation codons
• Like the capital letter we use to signify the beginning of a sentence, and the period to signify the end
12.4 First Step: Transcription
• Transcription
A segment of DNA serves as a template for
the production of an RNA molecule
The gene unzips and exposes unpaired bases
Serves as template for mRNA formation
Loose RNA nucleotides bind to exposed DNA
bases using the C=G and A=U rule
When entire gene is transcribed into mRNA,
the result is a pre-mRNA transcript of the
gene
The base sequence in the pre-mRNA is
complementary to the base sequence in DNA
First Step: Transcription
• A single chromosome consists of one very long molecule encoding hundreds or thousands of genes
• The genetic information in a gene describes the amino acid sequence of a protein
The information is in the base sequence of one side (the “sense” strand) of the DNA molecule
The gene is the functional equivalent of a “sentence”
• The segment of DNA corresponding to a gene is unzipped to expose the bases of the sense strand
The genetic information in the gene is transcribed (rewritten) into an mRNA molecule
The exposed bases in the DNA determine the sequence in which the RNA bases will be connected together
RNA polymerase connects the loose RNA nucleotides together
• The completed transcript contains the information from the gene, but in a mirror image, or complementary form
Transcription
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T C
terminator
gene strand
promoter
template strand
direction of polymerase movement
RNA polymerase
DNA template strand
mRNA transcript
to RNA processing 3′
3′ 5′
5′
RNA Polymerase
39 © Oscar L. Miller/Photo Researchers, Inc.
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a. 200m
b.
spliceosome
DNA
RNA polymerase
First Step: Transcription
• Pre-mRNA is modified before leaving the
eukaryotic nucleus.
Modifications to the ends of the primary
transcript:
• Cap on the 5′ end
– The cap is a modified guanine (G) nucleotide
– Helps a ribosome determine where to attach when translation begins
• Poly-A tail of 150-200 adenines on the 3′ end
– Facilitates the transport of mRNA out of the nucleus – Inhibits degradation of mRNA by hydrolytic enzymes.
First Step: Transcription
• Pre-mRNA, is composed of exons and introns.
The exons will be expressed,
The introns, occur in between the exons.
• Allows a cell to pick and choose which exons will go into a particular mRNA
RNA splicing:
• Primary transcript consists of:
– Some segments that will not be expressed (introns) – Segments that will be expressed (exons)
• Performed by spliceosome complexes in nucleoplasm
– Introns are excised
– Remaining exons are spliced back together
• Result is a mature mRNA transcript
First Step: Transcription
• In prokaryotes, introns are removed by
“self-splicing”—that is, the intron itself has
the capability of enzymatically splicing
itself out of a pre-mRNA
Messenger RNA Processing in Eukaryotes
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Messenger RNA Processing in Eukaryotes
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exon
intron intron
exon exon
Messenger RNA Processing in Eukaryotes
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exon
intron intron
exon exon
DNA
transcription
exon
intron intron
exon exon
pre-mRNA
Messenger RNA Processing in Eukaryotes
46
exon
intron intron
exon exon
transcription
exon
intron intron
exon exon pre-mRNA
5 3
exon
intron intron
exon exon
cap
3 5
DNA
poly-A tail
Messenger RNA Processing in Eukaryotes
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exon
intron intron
exon exon transcription
exon
intron intron
exon exon pre-mRNA
5 3
exon
intron intron
exon exon
exon exon exon
cap poly-A tail spliceosome
cap
3 3
5 5
DNA
Messenger RNA Processing in Eukaryotes
48
exon
intron intron exon exon DNA
transcription
exon
intron intron exon exon
pre-mRNA
5 3
exon
intron intron exon exon
exon
intron RNA exon
pre-mRNA splicing
exon
cap poly-A tail spliceosome
mRNA
cap poly-A tail
cap poly-A tail 3 3
3 5
5
5
Messenger RNA Processing in Eukaryotes
49
exon
intron intron
exon exon
DNA
transcription
exon
intron intron
exon exon
pre-mRNA
5 3
exon
intron intron
exon exon
exon
intron RNA exon
pre-mRNA splicing
exon
cap poly-A tail
spliceosome
mRNA
cytoplasm
cap poly-A tail
cap poly-A tail
3 3
3 5
5
5
Messenger RNA Processing in Eukaryotes
50
exon
intron intron
exon exon
DNA
transcription
exon
intron intron
exon exon
5 3
exon
intron intron
exon exon
exon
intron RNA exon
pre-mRNA splicing
exon
cap poly-A tail
spliceosome
nucleus
mRNA
cytoplasm
nuclear pore in nuclear envelope
cap poly-A tail
cap poly-Atail
3 3
5 5 pre-mRNA
3 5
First Step: Transcription
• Functions of introns:
As organismal complexity increases;
• The number of protein-coding genes does not keep pace • But the proportion of the genome that is introns increases
Possible functions of introns:
• Exons might combine in various combinations
– Would allow different mRNAs to result from one segment of DNA
• Introns might regulate gene expression
• Introns may encourage crossing-over during meiosis
Exciting new picture of the genome is
emerging
12.5 Second Step: Translation
• Translation
The sequence of codons in the mRNA at a ribosome directs the sequence of amino acids into a polypeptide
A nucleic acid sequence is translated into a protein sequence
• tRNA molecules have two binding sites:
One associates with the mRNA transcript
The other associates with a specific amino acid
Each of the 20 amino acids in proteins associates with one or more of 64 types of tRNA
• Translation
An mRNA transcript associates with the rRNA of a ribosome in the
cytoplasm or a ribosome associated with the rough endoplasmic reticulum
The ribosome “reads” the information in the transcript
Ribosome directs various types of tRNA to bring in their specific amino acid “fares”
The tRNA specified is determined by the code being translated in the mRNA transcript
Second Step: Translation
• tRNA molecules come in 64 different kinds
• All are very similar except that
One end bears a specific triplet (of the 64 possible) called the anticodon
The other end binds with a specific amino acid
type
tRNA synthetases attach the correct amino acid
to the correct tRNA molecule
• All tRNA molecules with a specific anticodon
will always bind with the same amino acid
3’
5’
hydrogen bonding amino
acid leucine
G A A
Structure of a tRNA Molecule
Structure of a tRNA Molecule
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3’
5’
hydrogen bonding
amino acid end amino
acid leucine
Structure of a tRNA Molecule
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G A A 3’
5’
hydrogen bonding
amino acid end
anticodon end amino
acid leucine
Structure of a tRNA Molecule
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G G
A
A A C
C
C U U U C C U C
3’
5’
hydrogen bonding
amino acid end
anticodon end
mRNA
5’ 3’
amino acid leucine
Structure of a tRNA Molecule
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G G
A
A A C
C
C U U U C C U C
3’
5’
hydrogen bonding
amino acid end
anticodon end
mRNA
5’ 3’
amino acid leucine
anticodon
a. b.
Second Step: Translation
• Ribosomes
Ribosomal RNA (rRNA):
• Produced from a DNA template in the nucleolus of a nucleus • Combined with proteins into large and small ribosomal
subunits
A completed ribosome has three binding sites to facilitate pairing between tRNA and mRNA
• The E (for exit) site
• The P (for peptide) site, and • The A (for amino acid) site
Ribosome Structure and Function
60
tRNA binding sites
outgoing tRNA
3
mRNA incoming tRNA polypeptide
5
small subunit
mRNA large subunit
a. Structure of a ribosome b. Binding sites of ribosome
c. Function of ribosomes d. Polyribosome
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Second Step: Translation
• Initiation:
Components necessary for initiation are:
• Small ribosomal subunit • mRNA transcript
• Initiator tRNA, and
• Large ribosomal subunit
• Initiation factors (special proteins that bring the above together)
Initiator tRNA:
• Always has the UAC anticodon
• Always carries the amino acid methionine • Capable of binding to the P site
Second Step: Translation
• Small ribosomal subunit attaches to
mRNA transcript
Beginning of transcript always has the START
codon (AUG)
• Initiator tRNA (UAC) attaches to P site
• Large ribosomal subunit joins the small
subunit
Initiation
63 U A C
A U G
A small ribosomal subunit binds to mRNA; an initiator tRNA pairs with the mRNA
start codon AUG. The large ribosomal subunit completes the ribosome. Initiator tRNA occupies the P site. The A site is ready for the next tRNA.
Met
amino acid methionine
initiator tRNA
mRNA
3 5
small ribosomal subunit
large ribosomal subunit
P site A site E site
3 5
Met
Initiation
Second Step: Elongation
• “
Elongation
” refers to the growth in length
of the polypeptide
• RNA molecules bring their amino acid
fares to the ribosome
Ribosome reads a codon in the mRNA
• Allows only one type of tRNA to bring its amino acid
• Must have the anticodon complementary to the mRNA codon being read
• The incoming tRNA joins the ribosome at its A site
Methionine of the initiator tRNA is connected
to the amino acid of the 2nd tRNA by a peptide
Second Step: Elongation
• The second tRNA moves to P site (translocation)
• The spent initiator tRNA moves to the E site and exits
• The ribosome reads the next codon in the mRNA
Allows only one type of tRNA to bring its amino acid
• Must have the anticodon complementary to the mRNA codon being read
• Joins the ribosome at its A site
The dipeptide on the 2nd amino acid is connected to
Elongation
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U A
C A
U
G G A C
3 5
peptide bond Met
Ala Trp Ser
Elongation
67
U A C A
U G
C U G
G A C
A tRNA–amino acid approaches the ribosome and binds at the A site.
3 5
anticodon
tRNA peptide
bond Met
asp
Ala Trp Ser
Val
1
Elongation
U A C A U GC U G
G A C
U A C A
U
G G A C C U G
A tRNA–amino acid approaches the
ribosome and binds at the A site.
Two tRNAs can be at a ribosome at one time; the anticodons are paired to the codons.
anticodon tRNA peptide bond Met asp Ala Trp Ser Val 3
5 5 3
Met
Ala Trp Ser
Val Asp
1 2
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Elongation
69 U A C A U GC U G
G A C
U A C A
U
G GA C C U G
A tRNA–amino acid approaches the ribosome and binds at the A site.
Two tRNAs can be at a ribosome at one time;
the anticodons are paired to the codons.
anticodon tRNA peptide bond Met asp Ala Trp Ser Val Met Ala Trp Ser
Val Asp
1 2
U A C A
U
G GA C C U G
Peptide bond formation attaches the peptide chain to the newly arrived amino acid.
3
5 5 3 5 3
Met Val Asp Ala Trp Ser 3 peptide bond
Elongation
70 U A C A U GCUG
G A C
U A C A
U
G G A C C U G
A tRNA–amino acid approaches the ribosome and binds at the A site.
Two tRNAs can be at a ribosome at one time; the anticodons are paired to the codons. anticodon tRNA peptide bond asp 3
5 5
Asp
1 2 4
U A C A
U
G G A C C U G
G A C C U G A U
G A C C
Peptide bond formation attaches the peptide chain to the newly arrived amino acid.
The ribosome moves forward; the “empty” tRNA exits from the E site; the next amino acid–tRNA complex is approaching the ribosome. 3 5 Met Val Asp Ala Trp Ser
3 5 3
Met Val Asp Ala Trp Ser 3 peptide bond Met Ala Trp Ser Val Met Ala Trp Ser Val
Elongation
71 U A C A U GCUG
G A C
U A C A
U
G G A C C U G
A tRNA–amino acid approaches the ribosome and binds at the A site.
Two tRNAs can be at a ribosome at one time; the anticodons are paired to the codons. anticodon tRNA peptide bond asp 3
5 5
Asp
1 2 4
U A C A
U
G G A C C U G
G A C C U G A U
G A C C
Peptide bond formation attaches the peptide chain to the newly arrived amino acid.
The ribosome moves forward; the “empty” tRNA exits from the E site; the next amino acid–tRNA complex is approaching the ribosome. 3 5 Met Val Asp Ala Trp Ser
3 5 3
Met
Val Asp Ala
Trp
Ser Thr
3
peptide bond
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Elongation
72
Elongation
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U A C A
U G
CUG
G A C
U A C A
U
G G A C C U G
A tRNA–amino acid approaches the ribosome and binds at the A site.
Two tRNAs can be at a ribosome at one time; the anticodons are paired to the codons. anticodon tRNA peptide bond asp 3
5 5
Asp
1 2 4
U A C A
U
G G A C C U G
G A C C U G A U
G A C C
Peptide bond formation attaches the peptide chain to the newly arrived amino acid.
The ribosome moves forward; the “empty” tRNA exits from the E site; the next amino acid–tRNA complex is approaching the ribosome. 3 5 Met Val Asp Ala Trp Ser
3 5 3
Met
Val Asp Ala
Trp
Ser Thr
Second Step: Translation
• Termination:
Previous tRNA moves to the P site
Spent tRNA moves to the E site and exits
Ribosome reads the STOP codon at the end of the mRNA
• UAA, UAG, or UGA
• Does not code for an amino acid
A protein called a release factor binds to the stop
codon and cleaves the polypeptide from the last tRNA
The ribosome releases the mRNA and dissociates into subunits
The same mRNA may be read by another ribosome
Termination
74
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The ribosome comes to a stop codon on the mRNA. A release factor binds to the site.
The release factor hydrolyzes the bond between the last tRNA at the P site and the polypeptide, releasing them. The ribosomal subunits dissociate.
release factor
U A U
A U G A
Termination
stop codon
Trp Trp
Val Val
3′
5′
Summary of Protein Synthesis in Eukaryotes
75 5 5 3 mRN A pre-mRN A DN Aintrons
6. During elongation, polypeptide synthesis takes place one amino acid at a time.
7. Ribosome attaches to rough ER. Polypeptide enters lumen, where it folds and is
modified.
3. mRNA moves into cytoplasm and becomes associated with ribosomes.
4. tRNAs with anticodons carry amino acids to mRNA. TRANSLATION TRANSCRIPTION nuclear pore mRNA
large and small ribosomal subunits amino acids anticodon tRNA peptide codon ribosome 5 3 3 CC GG G C G C G C G U A U A U A U A U A A U C G
1. DNAin nucleus serves as a template for mRNA.
2. mRNA is processed before leaving the nucleus.
5. During initiation, anticodon-codon complementary base pairing begins as the ribosomal subunits come together at a start codon.
8. During termination, a ribosome reaches a stop codon; mRNA and ribosomal subunits disband.
12.6 Structure of the
Eukaryotic Chromosome
• Each chromosome contains a single linear DNA molecule, but is composed of more than 50% protein.
• Some of these proteins are concerned with DNA and RNA synthesis
• Histones play primarily a structural role
The most abundant proteins in chromosomes
Five primary types of histone molecules
Responsible for packaging the DNA
• The DNA double helix is wound at intervals around a core of eight histone molecules (called a nucleosome)
• Nucleosomes are joined by “linker” DNA.
Structure of Eukaryotic Chromosomes
77
a: © Ada L. Olins and Donald E. Olins/Biological Photo Service; b: Courtesy Dr. Jerome Rattner, Cell Biology and Anatomy, University of Calgary; c: Courtesy of Ulrich Laemmli and J.R. Paulson, Dept. of Molecular Biology, University of Geneva, Switzerland; d: © Peter Engelhardt/Department of Pathology and Virology, Haartman Institute/Centre of Excellence in Computational Complex Systems Research,
Biomedical Engineering and Computational Science, Faculty of Information and Natural Sciences, Helsinki University of Technology, Helsinki, Finland Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.
1. Wrapping of DNA around histone proteins.
2. Formation of a three-dimensional zigzag structure via histone H1 and other DNA-binding proteins.
3. Loose coiling into radial loops .
4. Tight compaction of radial loops to form heterochromatin.
5. Metaphase chromosome forms with the help of a protein scaffold.
DNA double helix
nucleosome
euchromatin c. Radial loop domains
d. Heterochromatin
e. Metaphase chromosome
1,400 nm 700 nm 300 nm 30 nm
histone H1 histones 11 nm
2nm
a. Nucleosomes (“beads on a string”)