Available online throug
ISSN 2229 – 5046
COMMON FIXED POINT THEOREMS
FOR FOUR SELF MAPS ON A MULTIPLICATIVE METRIC SPACE
K. P. R. SASTRY
1, K. K. M. SARMA
2, S. LAKSHMANA RAO
3*1
8-28-8/1, Tamil Street, Chinna Waltair Visakhapatnam - 530 017, India.
2
Department of Mathematics, Andhra University, Visakhapatnam - 30 003, India.
3
Department of Mathematics, Andhra University, Visakhapatnam - 530 003, India.
(Received On: 26-10-16; Revised & Accepted On: 27-02-17)
ABSTRACT
I
n this paper we improve and extend theorem 3.1 of Khan and Imdad[9] replacingλ
byϕ
,
where+
1
: R
0,
2
ϕ
→
is an increasing and continuous function. We also show that the example 4.1 mentioned in Khanand Imdad does not illustrate theorem 3.1 of Khan and Imdad. However an example to illustrate theorem 3.1 of Khan and Imdad is given.
Key words: Multiplicative metric space, multiplicative contraction, Coincidence point, Coincidentally Commuting
mappings, Common fixed point.
Mathematics Subject Classification (2010): 54H25, 47H10.
1. INTRODUCTION AND PRELIMINARIES
The study of fixed points of mappings satisfying certain contractions has many applications and has been at the center of various research activities. In the past years many authors generalized Banach's fixed point theorem in various spaces such as Quasi metric space, Fuzzy metric space, Z-metric space, Partial metric space, probabilistic metric space and generalized metric spaces. On the other hand, in 2008 Bashirov et al. [1] defined a new distance so called a multiplicative distance by using the concept of multiplicative absolute value. After than, in 2012, by using the same idea of multiplicative distance, M.Ozavsar and A.C.Civikel [7] investigate multiplicative metric space and introduced the concept of a multiplicative contraction mappings and proved some fixed point theorems for multiplicative contraction, such mappings on a complete multiplicative metric spaces. In 2014, He et al. [12] proved a Common fixed point theorem for four self mappings in complete multiplicative metric space.
Recently motivated by the concept of compatible mappings, compatible mapping of type(A), and R-Weak commutativity given by G.Jungck et al. [4,5,6], B.C.Dhage [2] termed a pair of self mappings to be Coincidentally Commuting(Weakly commuting), and proved some fixed point theorems for these mappings.
In this paper we improve the result 3.1 of Q.H.Khan and M.Imdad in [9]. Also the example 4.1 mentioned in [9] does not illustrate the result 3.1 of Q.H.Khan and M.Imdad [9], however, we gave an example to illustrates the result 3.1 of Q.H.Khan and M.Imdad [9].
The following one way implications are obviously true but their converse are not true.
Commuting maps
⇒
Weakly Commuting maps⇒
Compatible maps⇒
Coincidentally Commuting maps.Corresponding Author: S. Lakshmana Rao
3*Definition 1.1 (A.E.Bashirov, E.M.Kurplnara, A.Ozyapici [1]): Let
X
be a nonempty set. A multiplicative metricis a mapping
d X
:
×
X
→
+ satisfying the following conditions: (i)d x y
( , )
≥
1
for allx y
,
∈
X
andd x y
( , )
=
1
, if and only ifx
=
y
.(ii)
d x y
( , )
=
d y x
( , )
for allx y
,
∈
X
.(iii)
d x y
( , )
≤
d x z d z y
( , ). ( , )
for allx y z
, ,
∈
X
. (Multiplicative triangle inequality)Definition 1.2 (M.Ozavsar, A.C.Civikel [7]): Let
( , )
X d
be a multiplicative metric space, { }x
n be a sequence inX
andx
∈
X
. the sequence { }x
n is called a multiplicative Cauchy sequence if, for eachε
>
1
, there existsN
∈
N
such thatd x x
(
n,
m)
<
ε
, for allm n
,
≥
N
.Definition 1.3 (M.Ozavsar, A.C.Civikel [7]): A multiplicative metric space
X
is complete, if every multiplicative Cauchy sequence in it is multiplicative convergent tox
∈
X
.Definition 1.4 (F.Gu, L.M.Cui, Y.H.Wu [3]): Suppose that
S
andT
are two self mappings of a multiplicativemetric space
( , )
X d
;S
,T
are called commutative mappings if,STx
=
TSx
for allx
∈
X
.Definition 1.5 (F.Gu, L.M.Cui, Y.H.Wu [3]): Suppose that
S
andT
are two self mappings of a multiplicativemetric space
( , )
X d
; The pair (S
,T
) are called weak commutative mappings ifd STx TSx
(
,
)
≤
d Tx Sx
(
,
)
for allx
∈
X
.Definition 1.6 (F.Gu, L.M.Cui, Y.H.Wu [3]): Suppose that
S
andT
are two self mappings of a multiplicativemetric space
( , )
X d
; A pointx
∈
X
is said to be a coincident point ofS
andT
ifd Sx Tx
(
,
)
=
1
.Definition 1.7 (M.Ozavsar, A.C.Civikel [7]): Let
( , )
X d
be a multiplicative metric space. A mappingf
:
X
→
X
is called a multiplicative contraction if there exists a real constant
λ
∈
[0,1)
such thatd fx fy
(
,
)
≤
d x y
( , )
λ for all,
x y
∈
X
.Definition 1.8 (M.Ozavsar, A.C.Civikel [7])(Multiplicative continuity): Let
( ,
X d
X)
and( ,
Y d
Y)
be two multiplicative metric spaces andf
:
X
→
Y
be a function. If for everyε
>
1
, there existsδ
>
1
such that(
( ))
( ( ))
f B x
δ⊂
B
εf x
, then we callf
multiplicative continuous atx
∈
X
.Definition 1.9 (M.Ozavsar, A.C.Civikel [7])(Semi-Multiplicative continuity): Let
( , )
X d
be a multiplicativemetric space, and
( , )
Y d
be a metric space andf
:
X
→
Y
be a function. If for allε
>
0
, there existsδ
>
1
suchthat
f B x
(
δ( ))
⊂
B
ε( ( ))
f x
, then we callf
Semi multiplicative continuous atx
∈
X
. Similarly a function:
g Y
→
X
is also said to be semi multiplicative continuous aty
∈
Y
if it satisfies a similar requirement.Definition 1.10 (M.Ozavsar, A.C.Civikel [7])(Multiplicative convergence): Let
( , )
X d
be a multiplicative metricspace,
{ }
x
n be a sequence inX
andx
∈
X
. If for every multiplicative open ball( )
{ / ( , )
},
1
B x
ε=
y d x y
<
ε ε
>
there exists a natural numberN
such thatn
≥
N
,x
n∈
B x
ε( )
. The sequence{ }
x
n is said to be multiplicative converging tox
, denoted byx
n→
x
(
n
→ ∞
)
.Lemma 1.11 (M.Ozavsar, A.C.Civikel [7]): Let
( , )
X d
be a multiplicative metric space, { }x
n be a sequence inX
andx
∈
X
thenx
n→
x
(
n
→ ∞
)
if and only ifd x x
( , )
n→
1
(
n
→ ∞
)
Lemma 1.13 (M.Ozavsar, A.C.Civikel [7]): Let
( ,
X d
X)
and( ,
Y d
Y)
be two multiplicative metric spaces and:
f
X
→
Y
be a mapping and{ }
x
n be any sequence inX
. Thenf
is multiplicative continuous at the pointx
∈
X
if and only iff x
(
n)
→
f x
( )
for every sequence{ }
x
n withx
n→
x
(
n
→ ∞
)
.Theorem 1.14 (M.Ozavsar, A.C.Civikel [7]): Let
( , )
X d
be a multiplicative metric space and{ }
x
n be a sequence inX
. If the sequence is multiplicative convergent, then it is multiplicative Cauchy sequence.Lemma 1.15 (M.Ozavsar, A.C.Civikel [7]): Let
( , )
X d
be a multiplicative metric space and { }x
n be a sequence inX
. Then { }x
n is multiplicative Cauchy sequence if and only ifd x
(
m,
x
n)
→
1
( ,
m n
→ ∞
)
Theorem 1.16 (M.Ozavsar, A.C.Civikel [7]): Let
( , )
X d
be a multiplicative metric space and letf
:
X
→
X
be amultiplicative contraction. If
( , )
X d
is complete, thenf
has a unique fixed point.In 2014, X.He, M.Song and D.Chen [12] proved the fixed point theorem for two pairs of of weak commutative mappings on a multiplicative metric space.
Theorem 1.17 (X.He, M.Song, D.Chen [12]): Let
S T A
, ,
andB
be self mappings of a complete multiplicativemetric space
X
, satisfying the following conditions: (i)S X
(
)
⊂
B X T X
(
),
(
)
⊂
A X
(
),
(ii)
A
andS
are weak commutative,B
andT
also are weak commutative, (iii) One ofS T A
, ,
andB
is continuous,(iv)
d Sx Ty
(
,
) {
≤
max d Ax By d Ax Sx d Ty By d Sx By d Ax Ty
{ (
,
), (
,
), (
,
), (
,
), (
,
)}}
λ(0, )
1
2
λ
∈
,
∀
x y
∈
X
.Then
S T A
, ,
andB
have a unique common fixed point.Now we given below the examples of multiplicative metrics.
Example 1.18 (M.Ozavsar, A.C.Civikel [7]): Let
X
= ∞
[1, )
, defined X
:
×
X
→
+ by d x y( , ) max x y,y x
=
then
d
is a multiplicative metric onX
.Example 1.19 (M.Sarwar and R.Badsahah-e [8]): Let
( , )
X d
be a metric space, let a > 1, define:
d
′
X
× →
X
+ by( , )
( , )1 if
.
0 if
y.
d x y
x
y
d x y
a
x
=
′
=
=
≠
for allx y
,
∈
X
. Then d' is a multiplicative metricon
X
and( ,
X d
′
)
is known as the discrete multiplicative metric space .Example 1.20: (M.Sarwar and R.Badsahah-e [8]): Let
d
:
× → ∞
[1, )
be defined asd x y
( , )
=
a
x y−,
where,
x y
∈
and a>1. Thend
is a multiplicative metric and( , )
d
is a multiplicative metric space. We may call it usual multiplicative metric space.Recently, Q.H.Khan and M.Imdad improved theorem 1.17 by relaxing the continuity requirement of the maps completely and to reduce the commutativity requirement of the maps to coincidence point only.
Theorem 1.21: (Q.H.Khan, M.Imdad [9]). Let
A B I
, ,
andJ
be self mappings of a multiplicative metric space( , )
X d
, satisfyingA X
(
)
⊂
J X
(
)
,B X
(
)
⊂
I X
(
)
and(
,
)
{ ( ,
), ( ,
), (
,
), (
,
), ( ,
)}
d Ax By
≤
max d Ix Jy d Ix Ax d By Jy d Ax Jy d Ix By
λ(0, ) , ,
1
.
2
x y z
X
λ
∈
∀
∈
If one of
A X
(
), (
B X
), (
I X
), (
J X
)
is a complete subspace ofX
, then the following conclusions hold.(i)
( , )
A I
has a coincidence point;Further if the pairs
( , )
A I
and( , )
B J
are coincidentally commuting, thenA I
,
,B
andJ
have a unique common fixed point.2. MAIN RESULT
In this section we mainly improve and extend the theorem 1.21, in [9], replacing
λ
byϕ
, where: R
+0,
1
2
ϕ
→
is an increasing and continuous function.Theorem 2.1: Let
A B I
, ,
andJ
be self mappings of a multiplicative metric space( , )
X d
, satisfying(
)
(
)
A X
⊂
J X
,B X
(
)
⊂
I X
(
)
and define: R
+0,
1
2
ϕ
→
such thatϕ
is continuous and increasing and( ( , ))
(
,
)
[
( , )]
M x yd Ax By
≤
M x y
ϕ (2.1.1) whereM x y
( , )
=
max d Ix Jy d Ix Ax d By Jy d Ax Jy d Ix By
{ ( ,
), ( ,
), (
,
), (
,
), ( ,
)}
∀
x y z
, ,
∈
X
.
If one of
A X
(
), (
B X
), (
I X
), (
J X
)
is a complete subspace ofX
, then the following conclusions hold.(i)
( , )
A I
has a coincidence point;(ii)
( , )
B J
has a coincidence point;Further if the pairs
( , )
A I
and( , )
B J
are coincidentally commuting, thenA B I
, ,
andJ
have a unique common fixed point.Proof: Let
x
0∈
X
, sinceA X
(
)
⊂
J X
(
)
, then∃
a pointx
1∈
X
such thatAx
0=
Jx
1.Also since
B X
(
)
⊂
I X
(
)
,∃
x
2∈
X
such thatBx
1=
Ix
2.Using this argument repeatedly, we can construct a sequence
{ }
z
n inX
such that2n 2n 2n 1
z
=
Ax
=
Jx
+ andz
2n+1=
Bx
2n+1=
Ix
2n+2Suppose
z
2n+1=
z
2n for somen
.2 1 2 2
(
n,
n)
d z
+z
+ =d Bx
(
2n+1,
Ax
2n+2)
=d Ax
(
2n+2,
Bx
2n+1)
2 1 2 2
(
n,
n)
d z
+z
+ =d Ax
(
2n+2,
Bx
2n+1)
≤
( ( 2 2,2 1))2 2 2 1
{
(
,
)}
M xn xnn n
M x
x
ϕ + ++ + (2.1.2)
where
2 2, 2 1
(
n n)
M x
+x
+=
m x
a
{ (
d Ix
2n+2,
Jx
2n+1), (
d Ix
2n+2,
Ax
2n+2), (
d Bx
2n+1,
Jx
2n+1), (
d Ax
2n+2,
Jx
2n+1), (
d Ix
2n+2,
Bx
2n+1)}
=
max
{ (
d z
2n+1,
z
2n), (
d z
2n+1,
z
2n+2), (
d z
2n+2,
z
2n), (
d z
2n+2,
z
2n), (
d z
2n+1,
z
2n+1)}
=
max
{1, (
d z
2n+1,
z
2n+2)}
=d z
(
2n+1,
z
2n+2)
∴
d z
(
2n+1,
z
2n+2)
≤
( (2 1,2 2))2 1 2 2
{ (
,
)}
d zn znn n
d z
z
ϕ + ++ +
<
d z
(
2n+1,
z
2n+2)
, ifz
2n+1≠
z
2n+2. a contradiction.2n 1 2n 2
z
+z
+∴
=
.Again
d z
(
2n+2,
z
2n+3)
=d Ax
(
2n+2,
Bx
2n+3)
≤
( (2 2, 2 3))2 2 2 3
{
(
,
)}
M xn xnn n
M x
x
ϕ + ++ + (2.1.3)
where
2 2, 2 3
(
n n)
M x
+x
+=
m
ax d Ix
{ (
2n+2,
Jx
2n+3), (
d Ix
2n+2,
Ax
2n+2), (
d Bx
2n+3,
Jx
2n+3), (
d Ax
2n+2,
Jx
2n+3), (
d Ix
2n+2,
Bx
2n+3)}
=
max
{ (
d z
2n+1,
z
2n), (
d z
2n+1,
z
2n+2), (
d z
2n+3,
z
2n+2), (
d z
2n+2,
z
2n+2), (
d z
2n+1,
z
2n+3)}
=max
{1, (
d z
2n+2,
z
2n+3)}
=
d z
(
2n+2,
z
2n+3)
∴
d z
(
2n+2,
z
2n+3)
≤
( (2 2,2 3))2 2 2 3
{ (
,
)}
d zn znn n
d z
z
ϕ + ++ +
2n 2 2n 3
z
+z
+∴
=
.Similarly we get
z
2n+3=
z
2n+4 = ....2 2 1 2 2 2 3
...
z
z
nz
n+z
n+z
n+∴ =
=
=
=
=
(2.1.4)
Since
z
2n=
Ax
2n=
Jx
2n+12n 1 2n 1 2n 2
z
+=
Bx
+=
Ix
+Also
z
2n+2=
Ax
2n+2=
Jx
2n+3...
∴
Bx
2n+1=
Jx
2n+1⇒
BJx
2n+1=
JBx
2n+1( ( , )
B J is coincidently commuting
)
⇒
Bz
2n=
Jz
2n i.e.,Bz
=
Jz
and
Ax
2n+2=
Ix
2n+2⇒
AIx
2n+2=
IAx
2n+2( ( , )
A I is coincidently commuting
)
⇒
Az
2n=
Iz
2n i.e.,Az
=
Iz
Az
Iz
Bz
Jz
∴
= =
=
Now
d Az B AZ
(
, (
))
≤
{
M z Az
( ,
}
ϕ(M z Az( , ))( ,
)
M z Az
=max d Iz J Az
{ ( , (
)), ( ,
d Iz Az d B Az J Az
), ( (
), (
)), (
d Az J Az
, (
)), ( , (
d Iz B Az
))}
=
max d Az B Az
{ (
, (
)), (
d Az Az d B Az B Az
,
), ( (
), (
)), (
d Az B Az
, (
)), (
d Az B Az
, (
))}
=
d Az B AZ
(
, (
))
(
, (
))
d Az B AZ
∴
≤
( ( , ( ))){ (
d Az B Az
, (
))}
ϕ d Az B Az<
d Az B Az
(
, (
))
, ifAz
≠
BAz
.a contradiction.∴
Az
=
B Az
(
)
.∴
Az
is a fixed point ofB
.Also
d A Bz BZ
( (
),
)
≤
{
M Bz z
(
, }
ϕ(M Bz z( , ))(
, )
M Bz z
=max d I Bz Jz d I Bz A Bz
{ ( (
),
), ( (
), (
)), (
d Bz Jz d A Bz Jz d I Bz Bz
,
), ( (
),
), ( (
),
)}
=
max d A Bz Bz d A Bz A Bz
{ ( (
),
), ( (
), (
)), (
d Bz Bz d A Bz Bz d A Bz Bz
,
), ( (
),
), ( (
),
)}
=
d A Bz Bz
( (
),
)
∴
d A Bz Bz
( (
),
)
≤
{ ( (
d A Bz Bz
),
)}
ϕ( ( (d A Bz Bz), ))<
d A Bz Bz
( (
),
)
, ifABz
≠
Bz
.a contradiction.∴
A Bz
(
)
=
Bz
.∴
Bz
is a fixed point ofA
.Similarly we can proved
I
andJ
.∴
A B I
, ,
andJ
have unique common fixed point.Suppose
z
2n+1≠
z
2n for everyn
.2 1 2 2
(
n,
n)
d z
+z
+ =d Bx
(
2n+1,
Ax
2n+2)
=d Ax
(
2n+2,
Bx
2n+1)
2 1 2 2
(
n,
n)
d z
+z
+ =d Ax
(
2n+2,
Bx
2n+1)
≤
( ( 2 2,2 1))2 2 2 1
{
(
,
)}
M xn xnn n
M x
x
ϕ + ++ + (2.1.5)
Where
2 2 2 1
(
n,
n)
max
M x
+x
+=
{ (
d Ix
2n+2,
Jx
2n+1), (
d Ix
2n+2,
Ax
2n+2), (
d Bx
2n+1,
Jx
2n+1), (
d Ax
2n+2,
Jx
2n+1),
d Ix
(
2n+2,
Bx
2n+1)}
=
max
{ (
d z
2n+1,
z
2n), (
d z
2n+1,
z
2n+2), (
d z
2n+1,
z
2n), (
d z
2n+2,
z
2n), (
d z
2n+1,
z
2n+1)}
From (2.1.5)
2 1 2 2
(
n,
n)
{
d z
+z
+≤
max
{ { (2 ,2 1), ( 2 1,2 2), ( 2 ,2 2)}}2 2 1 2 1 2 2 2 2 2
{ (
,
), (
,
), (
,
)}}
ma xd znzn d zn zn d znznn n n n n n
d z
z
d z
z
d z
z
ϕ + + + ++ + + +
Claim:
d z
(
2n+1,
z
2n+2)
<( (
d z
2n,
z
2n+1)
( )
i
Ifd z
(
2n+1,
z
2n+2)
is maximum ofd z
(
2n,
z
2n+1)
,d z
(
2n+1,
z
2n+2)
andd z
(
2n,
z
2n+2)
.then
d z
(
2n+1,
z
2n+2)
≤
( (2 1,2 2))2 1 2 2
[
,
]
d zn znn n
d z
z
φ + ++ +
<
d z
(
2n+1,
z
2n+2)
. a contradiction.Hence
d z
(
2n+1,
z
2n+2)
is not a maximum.( )
ii
Ifd z
(
2n,
z
2n+1)
is maximum of( (
d z
2n,
z
2n+1)
,d z
(
2n+1,
z
2n+2)
andd z
(
2n,
z
2n+2)
.then
d z
(
2n+1,
z
2n+2)
≤
( ( 2 ,2 1))2 2 1
[ (
,
)]
d znznn n
d z
z
ϕ ++ <
( (
d z
2n,
z
2n+1)
. Hence the claim established.( )
iii
ifd z
(
2n,
z
2n+2)
is maximum of( (
d z
2n,
z
2n+1)
,d z
(
2n+1,
z
2n+2)
andd z
(
2n,
z
2n+2)
.then
d z
(
2n+1,
z
2n+2)
≤
( ( 2 ,2 2))2 2 2
[ (
,
)]
d zn znn n
d z
z
ϕ ++ .
We have
( (
d z
2n,
z
2n+2)
≤
d z
(
2n,
z
2n+1). (
d z
2n+1,
z
2n+2)
Now
d z
(
2n+1,
z
2n+2)
≤
( (2 ,2 2))2 2 2
[ (
,
)]
d znznn n
d z
z
ϕ ++
≤
( ( 2 ,2 2))2 2 1 2 1 2 2
[ (
,
). (
,
)]
d znznn n n n
d z
z
d z
z
ϕ ++ + +
≤
( 2 ,2 2)2 1 2 2 2 1 2 2
[ (
,
). (
,
)]
d znznn n n n
d z
z
d z
z
ϕ ++ + + +
(
Suppose d z
(
2n,
z
2n+1)
≤
(
d z
2n+1,
z
2n+2))
∴
d z
(
2n+1,
z
2n+2)
≤
2. ( 2 ,2 2)2 1 2 2
[ (
,
)]
d znznn n
d z
z
ϕ ++ +
<
d z
(
2n+1,
z
2n+2)
. a contradiction.∴
d z
(
2n+1,
z
2n+2)
<
d z
(
2n,
z
2n+1)
(2.1.7)Again
d z
(
2n+2,
z
2n+1)
=d Ax
(
2n+2,
Bx
2n+1)
2 2 2 1
(
n,
n)
d z
+z
+≤
( ( 2 2,2 1))2 2 2 1
{
(
,
)}
M xn xnn n
M x
x
ϕ + ++ + (2.1.8)
Where
2 2 2 1
(
n,
n)
M x
+x
+ =max
{ (
d Ix
2n+2,
Jx
2n+1), (
d Ix
2n+2,
Ax
2n+2), (
d Bx
2n+1,
Jx
2n+1), (
d Ax
2n+2,
Jx
2n+1), (
d Ix
2n+2,
Bx
2n+1)}
=
max
{ (
d z
2n+1,
z
2n), (
d z
2n+1,
z
2n+2), (
d z
2n+1,
z
2n), (
d z
2n+2,
z
2n), (
d z
2n+1,
z
2n+1)}
=
max
{ (
d z
2n+1,
z
2n), (
d z
2n+1,
z
2n+2), (
d z
2n,
z
2n+2)}
From (2.1.8)
d z
(
2n+2,
z
2n+1)
≤
{
max
{ { (2 1,2 ), (2 1,2 2), (2 ,2 2)}}2 1 2 2 1 2 2 2 2 2
{ (
,
), (
,
), (
,
)}}
ma xd zn zn d zn zn d znznn n n n n n
d z
z
d z
z
d z
z
ϕ + + + ++ + + +
(2.1.9)
Claim:
d z
(
2n+2,
z
2n+1)
<( (
d z
2n+1,
z
2n)
( )
i
Ifd z
(
2n+1,
z
2n+2)
is maximum ofd z
(
2n+1,
z
2n)
,d z
(
2n+1,
z
2n+2)
andd z
(
2n,
z
2n+2)
. then2 2 2 1
(
n,
n)
d z
+z
+≤
( ( 2 2,2 1))2 2 2 1
[
,
]
d zn znn n
d z
z
ϕ + ++ +
<
d z
(
2n+2,
z
2n+1)
. a contradiction.Hence
d z
(
2n+2,
z
2n+1)
is not a maximum.( )
ii
Ifd z
(
2n+1,
z
2n)
is maximum of( (
d z
2n+1,
z
2n)
,d z
(
2n+1,
z
2n+2)
andd z
(
2n,
z
2n+2)
. then2 2 2 1
(
n,
n)
d z
+z
+≤
( ( 2 1,2 ))2 1 2
[ (
,
)]
d zn znn n
d z
z
ϕ ++ <
( (
d z
2n+1,
z
2n)
.( )
iii
ifd z
(
2n,
z
2n+2)
is maximum of( (
d z
2n+1,
z
2n)
,d z
(
2n+1,
z
2n+2)
andd z
(
2n,
z
2n+2)
. Then
d z
(
2n+2,
z
2n+1)
≤
2 2 2
( ( , ))
2 2 2
[ (
,
)]
d zn znn n
d z
z
ϕ ++ .
We have
( (
d z
2n,
z
2n+2)
≤
d z
(
2n,
z
2n+1). (
d z
2n+1,
z
2n+2)
Now
d z
(
2n+2,
z
2n+1)
≤
( (2 ,2 2))2 2 2
[ (
,
)]
d znznn n
d z
z
ϕ ++
≤
( (2 ,2 2))2 2 1 2 1 2 2
[ (
,
). (
,
)]
d znznn n n n
d z
z
d z
z
ϕ ++ + +
≤
( 2 ,2 2)2 1 2 2 2 1 2 2
[ (
,
). (
,
)]
d zn znn n n n
d z
z
d z
z
ϕ ++ + + +
(
Suppose d z
(
2n,
z
2n+1)
≤
(
d z
2n+1,
z
2n+2))
∴
d z
(
2n+2,
z
2n+1)
≤
2. ( 2 ,2 2)2 1 2 2
[ (
,
)]
d znznn n
d z
z
ϕ ++ +
<
d z
(
2n+1,
z
2n+2)
. a contradiction.∴
d z
(
2n+2,
z
2n+1)
<
d z
(
2n+1,
z
2n)
(2.1.10)
From (2.1.7) and (2.1.10)
d z
(
n+1,
z
n)
<
d z z
( ,
n n−1)
forn
=
1, 2, 3...∴
d z
(
n+1,
z
n+2)
<
d z z
( ,
n n+1)
forn
=
1,2,3... (2.1.11)∴
{ ( ,
d z z
n n+1)}
is a strictly decreasing sequence of positive numbers.Suppose
d z
(
n+1,
z
n+2)
→ ≥
r
1
We show that
r
=
1
.From (2.1.6) and (2.1.9)
2 2 2 1
(
n,
n)
d z
+z
+≤
{
max
{ { (2 ,2 1), (2 1,2 2), (2 ,2 2)}}2 2 1 2 1 2 2 2 2 2
{ (
,
), (
,
), (
,
)}}
ma xd znzn d zn zn d znznn n n n n n
d z
z
d z
z
d z
z
ϕ + + + ++ + + +
As
n
→ ∞
,
r
≤
{
max
{ , , }}
r r r
2 ϕ{ma xr r r{ , , }}2
r
≤
{ }
r
2 ϕ(r2) =2
2. (r )
r
φ <r
, ifr
>
1
,
a contradiction
.
∴
r
=
1.
∴
lim (
2n 2,
2n 1)
n→∞
d z
+z
+= 1. i.e.,
lim (
2n 1,
2n 2)
n→∞
d z
+z
+= 1.
Now we show that { }
z
n is a Cauchy sequence.Given
ε
>
1,
∃
a natural numberN
such thatn
≥
N
( ,
n n k)
d z z
+≤
d z z
( ,
n n+1). (
d z
n+1,
z
n+2)... (
d z
n k+ −1,
z
n k+)
(2.1.12)We have
2 1 2 2
(
n,
n)
d z
+z
+≤
{
max
{ { (2 ,2 1), ( 2 1,2 2), ( 2 ,2 2)}}2 2 1 2 1 2 2 2 2 2
{ (
,
), (
,
), (
,
)}}
ma xd znzn d zn zn d znznn n n n n n
d z
z
d z
z
d z
z
ϕ + + + ++ + + +
=
{
max
{ { ( 2 ,2 1), ( 2 ,2 2)}}2 2 1 2 2 2
{ (
,
), (
,
)}}
ma xd znzn d zn znn n n n
d z
z
d z
z
ϕ + ++ +
(
d is decreasing sequence
)
d z
(
2n+1,
z
2n+2)
≤
2 [ (2 ,2 1) ]22 2 1
[ (
,
) ]
d znznn n
d z
z
ϕ ++
∴
d z
(
2n+1,
z
2n+2)
≤
2. [ ( 2 ,2 1) )]22 2 1
[ (
,
)]
d znznn n
d z
z
ϕ ++
Similarly
d z
(
2n,
z
2n+1)
≤
2. [ ( 2 1,2 ) ]22 1 2
[ (
,
)]
d zn znn n
d z
z
ϕ −− and
1 2
(
n,
n)
d z
+z
+≤
2. [ ( , 1) ]21
[ ( ,
)]
d z zn nn n
d z z
ϕ +Put
λ
=
2. [ ( ,
ϕ
d z z
n n+1) ].
22 3
(
n,
n)
d z
+z
+≤
2. [ ( 1, 2) ]21 2
[ (
,
)]
d zn znn n
d z
z
ϕ + ++ +
≤
2. [ ( 1, 2) ]21
[[ ( ,
)] ]
d zn znn n
d z z
λ ϕ + ++
(
d is decreasing and
ϕ
is increasing
)
≤
[[ ( ,
d z z
n n 1)] ]
λ λ +
≤
[ ( ,
d z z
n n+1)]
λ2Similarly
d z
(
n+3,
z
n+4)
≤
2. [ ( 2, 3) ]22 3
[ (
,
)]
d zn znn n
d z
z
ϕ + ++ +
≤
2 2. [ ( 2, 3) ]21
[[ ( ,
)] ]
d zn znn n
d z z
λ ϕ + ++
≤
[[ ( ,
d z z
n n+1)] ] .
λ λ2
≤
[ ( ,
d z z
n n+1)] .
λ3 ... ...(2.1.12)
From
d z z
( ,
n n k+)
≤
[ ( ,
d z z
n n+1)].[ ( ,
d z z
n n+1)] .[ ( ,
λd z z
n n+1)] .[ ( ,
λ2d z z
n n+1)] ...[ ( ,
λ3d z z
n n+1)]
λn k+ −1
2 3 1
1 ... 1
[ ( ,
=
d z z
n n+)]
+ + +λ λ λ +λn k+ −
1 1
1 1
1
[ ( ,
=
d z z
n n+)]
−λ<
( )
δ
−λ<
ε
if
n
≥
N
Given
ε
>
1
, chooseδ
such that1 1 λ
δ
−<
ε
. .,
i e
δ ε
<
1−λ∴
11
< <
δ ε
−λ∴
1 1 λ
δ
−<
ε
∴
d z z
( ,
n n k+)
→
1
, (n k
,
→ ∞
).∴
{ }z
n is a multiplicative Cauchy sequence.Now suppose that
I X
( )
is a complete subspace ofX
, then we observe that the subsequence{
z
2n+1}
which is contained inI X
( )
has a limit pointz
inI X
( )
.∴
∃ ∈
u
X
such thatIu
=
z
.Now we prove that
Au
=
z
.
Takex
=
u and y
,
=
x
2n+12 1
(
,
n)
d Au Bx
+≤
( ( ,2 1))2 1
{
( ,
)}
M u xnn
M u x
ϕ ++
where
M u x
( ,
2n+1)
=
max
{ (
d Iu Jx
,
2n+1), (
d Iu Au d Bx
,
), (
2n+1,
Jx
2n+1), (
d Au Jx
,
2n+1), (
d Iu Bx
,
2n+1)}
=
max
{ ( ,
d z z
2n), ( ,
d z Au d z
), (
2n+1,
z
2n), (
d Au z
,
2n), ( ,
d z z
2n+1)}
{ ( ,
d z z
2n), ( ,
d z Au d z
), (
2n+1,
z
2n),
2 1
(
,
n) {
d Au z
+max
∴
≤
( { ( ,2 ), ( , ), (2 1,2 ), ( ,2 ), ( ,2 1)})2 2 1
(
,
), ( ,
)}}
ma xd z zn d z Au d zn zn d Au zn d z z nn n
d Au z
d z z
ϕ + ++
On letting
n
→ ∞
.(
, ) {
d Au z
≤
max
( { ( , ), ( , ), ( , ), ( , ), ( , )}{ ( , ), ( ,
d z z d z Au d z z d Au z d z z
), ( , ), (
, ), ( , )}}
ϕ ma xd z z d z Au d z z d Au z d z z( ( , ))
(
, ) { ( ,
)}
d z Aud Au z
≤
d z Au
φ<
d z Au
( ,
)
, ifz
≠
Au
, a contradiction.∴
Au
=
z
∴
Au
= =
z
Iu
∴
u
is a coincident point ofA
andI
.
Now we prove that
Bv
=
z
.
Takex
=
x
2n+2 andy
=
v
2 2
(
n,
)
d Ax
+Bv
≤
( ( 2 2, ))2 2
{
, )}
M xn vn
x
v
ϕ ++
where
M x
(
2n+2, )
v
=
max
{ (
d Ix
2n+2,
Jv d Ix
), (
2n+2,
Ax
2n+2), (
d Bv Jv d Ax
,
), (
2n+2,
Jv d Ix
), (
2n+2,
Bv
)}
=
max
{ (
d z
2n+1, ), (
z d z
2n+1,
z
2n+2), (
d Bv z d z
, ), (
2n+2, ), (
z d z
2n+1,
Bv
)}
2 2
(
n,
) {
d z
+Bv
max
∴
≤
{ (
d z
2n+1, ), (
z d z
2n+1,
z
2n+2), (
d Bv z
, ),
2 1 2 1 2 2 2 2 2 1
( { ( , ), ( , ), ( , ), ( , ), ( , )}
2 2 2 1
(
, ), (
,
)}}
ma xd zn z d zn zn d Bv z d zn z d zn Bvn n
d z
z d z
Bv
ϕ + + + + ++ +
On letting
n
→ ∞
.( ,
) {
d z Bv
≤
max
( { ( , ), ( , ), ( , ), ( , ), ( , )}{ ( , ), ( , ), (
d z z d z z d Bv z d z z d z Bv
, ), ( , ), ( ,
)}}
ϕ ma xd z z d z z d Bv z d z z d z Bv( ( , ))
( ,
) { ( ,
)}
d z Bvd z Bv
≤
d z Bv
ϕ<
d z Bv
( ,
)
, ifz
≠
Bv
, a contradiction.∴
Bv
=
z
∴
Bv
= =
z
Jv
.∴
v
is a coincident point ofB
andJ
.∴
Au
=
Iu
=
Bv
=
Jv
=
z
.Suppose
( , )
A I
is coincidentally commuting. ThenAIu
=
IAu
⇒
Az
=
Iz
Suppose
( , )
B J
is coincidentally commuting. ThenBJv
=
JBv
⇒
Bz
=
Jz
∴
d Au Bz
(
,
)
≤
{
M u z
( , )}
ϕ(M u z( , ))where
M u z
( , )
=
max
{ (
d Iu Jz d Iu Au d Bz Jz d Au Jz d Iu Bz
,
), (
,
), (
,
), (
,
), (
,
)}
=
max d z Bz d z z d Bz Bz d z Bz d z Bz
{ ( ,
), ( , ), (
,
), ( ,
), ( ,
)}
=
max
{1, ( ,
d z Bz
)}
=
d z Bz
( ,
)
.( ,
)
d z Bz
≤
{ ( ,
d z Bz
)}
ϕ( ( ,d z Bz)<
d z Bz
( ,
)
, ifz
≠
Bz
, a contradiction.∴
Bz
= =
z
Jz
.∴
z
is a fixed point ofB
andJ
.Now
d Az Bz
(
,
)
≤
{
M z z
( , )}
ϕ(M z z( , ))where
M z z
( , )
=
max d Iz Jz d Iz Az d Bz Jz d Az Jz d Iz Bz
{ ( ,
), ( ,
), (
,
), (
,
), ( ,
)}
=
max d Az Bz d Az Az d Bz Bz d Az Bz d Az Bz
{ (
,
), (
,
), (
,
), (
,
), (
,
)}
=
max
{1, (
d Az Bz
,
)}
=
d Az Bz
(
,
)
.∴
d Az Bz
(
,
)
≤
{ (
d Az Bz
,
)}
ϕ( (d Az Bz, ) <d Az Bz
(
,
)
, ifAz
≠
Bz
, a contradiction.∴
Az
=
Bz
=
z
.∴
Az
=
Bz
=
Jz
= =
Iz
z
.∴
z
is a fixed point of A,B,I andJ
.Suppose
w
is another fixed point ofA B I
, ,
andJ
.( , )
d z w
=d Az Bw
(
,
)
≤
{
M z w
( , )}
ϕ(M z w( , ))where
M z w
( , )
=
max d Iz Jw d Iz Az d Bw Jw d Az Jw d Iz Bw
{ ( ,
), ( ,
), (
,
), (
,
), ( ,
)}
=
max
{ ( , ), ( , ), ( , ), ( , ), ( , )}
d z w d z z d w w d z w d z w