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ENTIRE POSITIVE SOLUTION TO THE SYSTEM OF

NONLINEAR ELLIPTIC EQUATIONS

LINGYUN QIU AND MIAOXIN YAO

Received 8 November 2005; Revised 12 May 2006; Accepted 15 May 2006

The second-order nonlinear elliptic system Δu= f1(x)+g1(x)u−β+h1(x)uγP(v),

Δv= f2(x)+g2(x)v−β+h2(x)vγP(u) with 0< α,β,γ <1 , is considered inRN.

Un-der suitable hypotheses on functionsfi,gi,hi(i=1, 2), andP, it is shown that this system

possesses an entire positive solution (u,v)C2,θ

loc(RN)×C 2,θ

loc(RN) (0< θ <1) such that bothuandvare bounded below and above by positive constant multiples of|x|2−Nfor

all|x| ≥1.

Copyright © 2006 L. Qiu and M. Yao. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

This paper is concerned with the second-order nonlinear elliptic system

Δu= f1(x)+g1(x)u−β+h1(x)uγP(v),

Δv= f2(x)+g2(x)v−β+h2(x)vγP(u),

x∈RN(N3), (1.1)

whereΔis the Laplacian operator, 0< α,β,γ <1 are constants, the functions fi,gi,hi(i=

1, 2) are nonnegative and locally H¨older continuous with exponentθ∈(0, 1) inRN, and P:R+R+is a continuous differentiable function, whereR+=(0, +∞),R+=[0, +∞).

We are interested in the study of the existence of entire positive solutions (u(x),v(x)) to (1.1) which satisfy the condition that each of its elements decays between two positive multiples of|x|2−Nasxtends to infinity. By an entire solution of (1.1) is meant a pair of

functions (u,v)C2,θ

loc(RN)×C 2,θ

loc(RN) which satisfies (1.1) at every pointxinRN. The existence of entire positive solutions of the equation

Δu+f(x,u)=0, x∈RN,N3, (1.2)

Hindawi Publishing Corporation Boundary Value Problems

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has been proved under various hypotheses, see [6,7,10–12,14,17]. In Particular, for the generalized Emden-Fowler equation

Δu+K(x)uλ=0, x∈RN,N3, (1.3)

whereλis a constant, andK is a positive locallyθ-H¨older continuous function inRN,

Fukagai [7] has proved forλ∈(0, 1) that if +

1 s

N−1−λ(N−2)K(s)ds <+∞, K(s)=max

|x|=sK(x), (1.4)

then there is an entire positive solution of (1.3) that is minimal, that is, bounded below and above, respectively, by a positive constant times|x|2−Nasxtends to infinity.

Equation (1.3) withλ∈(0, 1) is said to be of sublinear type; ifλis negative, then (1.3) is said to be of singular type, and such equations arise from the boundary layer theory of viscous fluids, see [3,13]. In this paper, we focus on elliptic systems of mixed type.

It is well known that some reaction-diffusion equations have been investigated in con-nection with models of population dynamics [2,5,9,15]. To mention some, in [15], the equation∂u/∂t−dΔum=f(x,u) is studied. For some mutualistic symbiosis population

models of two species, it may be necessary to study equation systems such as

∂u ∂t −du

m= f1(x)uρ+g1(x)uσ+h1(x)uμP(v),

∂v ∂t −dv

m= f2(x)vρ+g2(x)vσ+h2(x)vμP(u),

x∈RN, (1.5)

where 0< ρ,μ < m,−m < σ <0, andd1,d2>0. Obviously, the positive equilibrium solu-tions to system (1.5) inRNare corresponding to the entire positive solutions of a system

in the form of (1.1).

Some existence results of elliptic system

Δu+F1(x,u,v)=0,

Δv+F2(x,u,v)=0 (1.6)

have been established in [4,11,16,19–21]. In particular, in [20], the existence of the equilibrium solutions is established for the Volterra-Lotka mutualistic symbiosis model in the case of equal linear birth rates, using the method of upper and lower solutions. However, for so-called mixed type in whichF1andF2involve both singular and sublinear terms, results regarding the existence of positive entire solutions cannot be derived from those in the literature.

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as

Δu= f1(x)+g1(x)u−β+h1(x)uγvδ,

Δv= f2(x)+g2(x)v−β+h2(x)vγuδ,

x∈RN, (1.7)

or

Δu=f1(x)+g1(x)u−β+h1(x)uγc

0+v −δ

,

Δv=f2(x)+g2(x)v−β+h2(x)vγc

0+u −δ

,

x∈RN, (1.8)

with 0< α,β,γ <1,c00, 0< δ <1−γ, and some other kinds of systems even more general (seeRemark 2.2). Moreover, our method can be used to deal with similar systems on a bounded domain.

2. Main results

First, we denote byφthe function defined onR:

φ(t)=1, if 0≤t <1; φ(t)=t2−N, ift1. (2.1)

A solution (u(x),v(x)) for equation system (1.1) is usually called a minimal positive entire solution if bothu(x) andv(x) are between two positive constant multiples of function

φ(|x|) in wholeRN. This term comes from the fact that no positive solution ofΔu0 in

an exterior domain can decay more rapidly than a constant multiple of|x|2−N, see [18].

Theorem2.1. Suppose that0< α,β,γ <1are constants and the functionsgi,hi(i=1, 2), andPsatisfy the following conditions:

(T) fi,gi,hiare locally H¨older continuous with exponentθ∈(0, 1)inRNand

+

1 s

N−1−α(N−2)f

i (s)ds <+∞, fi∗(s)=max|x|=sfi(x),

+

1 s

N−1+β(N−2)g

i (s)ds <+∞, gi∗(s)=max| x|=sgi(x),

+

1 s

N−1−γ(N−2)h

i (s)P∗(s)ds <+∞, h∗i(s)=max| x|=shi(x), P

(s)=max |x|=sP

φ|x|,

fi(s) +gi(s) +hi(s)0 fors≥0,

fi(s)=min

|x|=sfi(x), gi∗(s)=min|x|=sgi(x); hi∗(s)=min|x|=shi(x);

(2.2)

(P)P:R+R+is a continuous differentiable function satisfying that there exists aλ∈ (0, 1−γ)such that for allk≥1andc∈[k−1,k],

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Then the system (1.1) possesses a positive entire solution(u,v)C2,θ

loc(RN)×C 2,θ

loc(RN)such that each ofuandvdecays between two positive constant multiples ofφ(|x|)asxtends to infinity, that is, the solution is minimal.

Remark 2.2. Examples of functionP(s) satisfying the condition (P) are

P(s)=c0+s −δ

, c0>0, 0< δ≤λ

(2.4)

as suggested in (1.8),

P(s)=sδ+s−σ, 0< δ≤λ, 0< σ≤λ (2.5)

or

P(s)=

c0+

, c0>0,δ >0,σ >0, 0< δ+σ≤λ (2.6)

and so on.

3. Proof of results

Lemma3.1. Consider the equation

Δu=f(x)+g(x)u−β+h(x)uγ. (3.1)

Suppose that f,g,hare nonnegative functions defined onRN, and0< α,β,γ <1are

con-stants. If f,g,hare locally H¨older continuous with exponentθ∈(0, 1)inRNand

(T)

+

1 s

N−1−α(N−2)f(s)ds <+∞, f(s)=max |x|=sf(x),

+

1 s

N−1+β(N−2)g(s)ds <+∞, g(s)=max |x|=sg(x),

+

1 s

N−1−γ(N−2)h(s)ds <+∞, h(s)=max |x|=sh(x),

f∗(s) +g∗(s) +h∗(s)0, fors≥0,

f∗(s)=min

|x|=sf(x), g∗(s)=min|x|=sg(x), h∗(s)=min|x|=sh(x),

(3.2)

then (3.1) possesses a unique positive entire solutionu∈C2,θ

loc(RN)such thatudecays be-tween two positive constant multiples ofφ(|x|)asxtends to infinity, that is, the solution is minimal.

Lemma3.2. Suppose that f :RN×R+Ris a continuous function such that one of the following assumptions is satisfied:

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(F2)s−1f(x,s)is strictly decreasing insfor eachxin a subsetΩ

0ofRNand both f(x,s) ands−1f(x,s)are nonincreasing insfor allxin the remainder partRNΩ

0. Letw,v∈C2(RN)satisfy

(a)Δw+ f(x,w)0Δv+f(x,v)inRN,

(b)w,v >0inRNandlim inf

|x|→∞(w(x)−v(x))0,

(c)ΔvinL1(RN).

Thenw≥v∈RN.

The proof of Lemma 3.1 is given for completeness in the appendix of this article.

Lemma 3.2is an extension of [17, Lemma 1], so the proof is omitted here for briefness. Proof ofTheorem 2.1. Consider the equation

Δu= f1(x)+g1(x)u−β+h1(x)uγPφ|x|, x∈RN. (3.3)

In view of (T) andLemma 3.1, we find that there exists, for (3.3), a unique entire positive solutionu0(x)C2,θ

loc(RN). With the same argument, for the equation

Δv=f2(x)+g2(x)v−β+h2(x)vγPφ|x|, x∈RN, (3.4)

there exists a unique entire positive solutionv0(x)C2,θ

loc(RN). Moreover, it is obvious that there is a constantc0>1 such that for anyx∈RN,

c−01φ

|x|≤u0(x)≤c0φ

|x|,

c−1 0 φ

|x|≤v0(x)≤c0φ

|x|. (3.5)

For any constantE≥1, denote

UE≡

u∈C0,θ

loc

RN|E1u0(x)u(x)Eu0(x), xRN,

VE≡

v∈C0,θ

loc

RN|E1v0(x)v(x)Ev0(x),xRN,

Q≡UE×VE.

(3.6)

Obviously,Qis closed and convex. For each (u,v)∈UE×VE, by Poisson equations theory

and (T), the problem

Δu= f1(x)+g1(x)u−β+h1(x)uγP(v), x∈RN, (3.7)

has a unique solutionu∈C2,θ

loc(RN)C 0,θ

loc(RN), and the problem

Δv=f2(x)+g2(x)v−β+h2(x)vγP(u), xRN, (3.8)

has a unique solutionv∈C2,θ

loc(RN)⊂C 0,θ

loc(RN). Defining the mappingsA1:Q→C0,locθ(RN) byA1(u,v)=uandA2:Q→C0,locθ(RN) byA2(u,v)=v, we have thatAi(u,v)C

2,θ

loc(RN),

i=1, 2, and hence

Φ(Q)C2,θ

loc

RN×C2,θ

loc

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We claim that ifEis a positive constant large enough, then

E−1u0(x)u(x)Eu0(x), xRN,

E−1v0(x)≤v(x)≤Ev0(x), x∈RN, (3.10)

hence we haveA1(Q)⊂UEandA2(Q)⊂VE. In fact, we have

Ec0 1

φ|x|≤E−1u0(x)≤u(x)≤Eu0(x)≤Ec0

φ|x|,

Δu= f1(x)+g1(x)u−β+h1(x)uγP(v)

f1(x)Eαu0α+g1(x)Eβu

−β

0 +h1(x)u

γ

0EγP v(x)

φ|x|φ

|x|

f1(x)Euα

0+g1(x)Eu−

β

0 +h1(x)u

γ

0

Ec0 λ

Pφ|x|,

(3.11)

while on the other hand, we have

ΔEu0

=f1(x)Euα0+g1(x)Eu

−β

0 +h1(x)u

γ

0E P

φ|x|. (3.12)

Thus, ifEis so large thatE(1−r−λ)c0, then we haveΔuΔ(Eu0). It follows from the

maximum principle for the operatorΔthat

u(x)≤Eu0(x), x∈RN. (3.13)

Similarly, we have

u(x)≥E−1u(x), x∈RN. (3.14)

With the same argument, we conclude that

E−1v0(x)v(x)Ev0(x), xRN. (3.15)

Fix thisEand defineΦ:Q→Qby

Φ(u,v)=A1(u,v),A2(u,v), ∀(u,v)∈Q, (3.16)

and now we only need to prove thatΦhas a fixed point inQ.

In order to use the Schauder-Tychonofffixed point theorem, we will prove that the operatorΦsatisfies the conditions through three steps.

(1)Φ(Q)⊂Q. This is a direct conclusion of (3.10).

(2)Φ:Q→Qis continuous. Obviously, it suffices to prove thatA1 andA2are both continuous in the sense that forwn→w in Q, it holds true thatAiwn−Aiw0,θ→0, n→ ∞,i=1, 2, here, for any sequence{un} ⊂C0,θ

loc(RN), by writingun0,θ→0,n→ ∞,

we mean that, for any closed bounded domainG⊂RN,un

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Denote

F(x) f1(x)+g1(x)u−β+h1(x)uγP(v),

Fn(x)≡f1(x)n+g1(x)u−nβ+h1(x)uγnP(vn).

(3.17)

We have obviously that FnF

0,θ−→0, asun−u0,θ+vn−v0,θ−→0, n−→ ∞. (3.18)

ByLemma 3.1, we may letube the unique solution of the equationΔu=F(x) and let

unbe the unique solution of the equationΔun =Fn(x). Then by the Schauder estimation theory, we know that for any bounded domainG⊂RN, there exists a constantC>0 such

that

un−uC2,θ(G)CFn−FC0,θ(G), (3.19) and hence

un−uC0,θ(G)CFn−FC0,θ(G). (3.20)

Therefore,

un−u0,θ−→0, asun−u0,θ+vn−v0,θ−→0, n−→ ∞, (3.21)

that is,A1 is a continuous mapping fromQ toUE. Similarly, A2 is also a continuous mapping fromQtoVE.

(3)Φ(Q) is relatively compact inC0,θ

loc(RN)×C 0,θ

loc(RN).

We first recall the gradient estimates for Poisson’s equation (see [8]). For any bounded domainΩRN, ifΔu= f inΩ, then

sup Ω dx

Du(x)Csup

Ω |u|+ supΩ d 2

xf(x)

, (3.22)

wheredx=dist(x,Ω) andC=C(N).

DenoteBm≡ {x∈RN;x< m},m=1, 2,. . . .For eachu∈A1(Q), we have by (3.22)

that

sup

Bm

Du(x)sup

Bm

dxDu(x)sup

Bm+1

dxDu(x)

C

sup

Bm+1

u(x)+ sup

Bm+1

d2xF(x)

C

sup

Bm+1

(x)+ (m+ 1)2sup

Bm+1

F(x)Km,

(3.23)

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Furthermore, by (3.23), we know that u(x)u(y)

|x−y| ≤Du

t0x+1−t0y≤Km, ∀x,y∈Bm. (3.24)

This shows thatA1(Q), restricted onBm, is a bounded subset ofC0,1(Bm). By the compact

embedding result (see [1]);C0,1(Ω) C0,θ(Ω), for any bounded domainΩRN, it is

seen thatA1(Q), restricted onBm, is a relative compact subset ofC0,θ(Bm). Therefore, for

any arbitrary sequence{un}n≥1⊂A1(Q), there exists a subsequence{u(nm)}n≥1⊂A1(Q) which is convergent onBm in the sense of the norm · C0,θ(B

m). The case forA2(Q) is

similar.

Consideringm=1Bm=RN, by the diagonal method, we conclude, fori=1 andi=2, respectively, that for an arbitrary sequence{un}n≥1⊂Ai(Q), there exists a subsequence,

say,{u(nn)}n≥1⊂Ai(Q), which is convergent in the sense of the norm · C0,θ(K) on any

compact subset K of RN, that is, Ai(Q) is relatively compact inC0,θ

loc(RN). Therefore, Φ(Q)=A1(Q)×A2(Q) is a relatively compact subset ofC0,θ

loc(RN)×C 0,θ

loc(RN).

Therefore, by the Schauder-Tychonofffixed point theorem, there exists an element (u,v)∈Qsuch thatΦ(u,v)=(u,v), that is, (u,v) satisfies the system (1.1). This completes

the proof ofTheorem 2.1.

Appendix

Proof ofLemma 3.1. Let

F(x,u)=f(x)+g(x)u−β+h(x)uγ,

G(t,u)=f∗(t)+g∗(t)u−β+h∗(t),

g(t,u)=f∗(t)+g∗(t)u−β+h∗(t),

(A.1)

theng(|x|,u)≤F(x,u)≤G(|x|,u),x∈RN,u >0. It follows from (T) that

0<

+

0 s

N−1gs,φ(s)ds < +

0 s

N−1Gs,φ(s)ds <+∞. (A.2)

Then we define two functions by

y(t)=Gt,φ(t), z(t)=gt,φ(t), t >0, (A.3)

where᏶is the integral operator defined by

᏶[E](t)= 1

N−2 t

0 s

t N−2

sE(s)ds+ +

t sE(s)ds

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By the simple calculation, we have

y+N−1

t y

= −Gt,φ(t), z+N−1

t z

= −gt,φ(t), t >0, (A.5)

l1φ(t)≤y(t), z(t)≤l2φ(t), t >0, (A.6)

for some positive constantsl1andl2.

Takeλ=max{α,β,γ}, then for anyk≥1, ifk−1ck, then

G(t,cu)≤kλG(t,u), t0,u >0,

g(t,cu)≥k−λg(t,u), t0,u >0. (A.7)

Moreover, lettingy∗(x)=k1λy(x), andk1is a number such thatl111, we have

y+N−1

t y

∗= −kλ1G

t,φ(t), t >0,

φ(t)≤y∗(t)≤kλ1l2φ(t), t >0,

(A.8)

by (A.5) and (A.6). Hence,

Gt,y∗=f∗(t)y∗α+g∗(t)y−∗β+h∗(t)y∗γ

≤f∗(t)l21 α

φα+g(t)φ−β+h(t)l

21 γ

φγ

≤kλ1

f∗(t)φα+g∗(t)φ−β+h∗(t)φγ=kλ1G(t,φ),

(A.9)

where we take k1 so big that k1≥l2α/λ(1−α) and k1≥lγ/λ (1−γ)

2 , that is, (l2k1λ)α≤kλ1 and (l21)γ≤kλ1.

Therefore, it follows that

y+N−1

t y

∗≤ −G

t,y∗. (A.10)

Similarly, lettingz∗(x)=k−2λz(x) with constantk2−λl21, we obtain

z+N−1

t z

∗≥ −g

t,z∗, (A.11)

such thatz∗(t)< δfor anyt >0 and

z∗(t)≤y∗(t), t >0. (A.12)

Definey∗(0) andz∗(0) by continuity with (A.3), and letv(x)=y∗(|x|) andw(x)= z∗(|x|) forx∈RN, then from (A.10) and (A.11)vandware, respectively, a supersolution

and a subsolution of (3.1), withv(x)≥w(x) satisfied. Therefore, by super-subsolution principle, (3.1) has a positive entire solutionusuch that

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For proving the uniqueness of such solutions, we suppose thatvandware two positive entire solutions of (3.1), then it is easily seen that the conditions (a) and (b) inLemma 3.2

are satisfied even whenvinterchanges withw.

Moreover, since|Δv|and|Δw|are, respectively, given by f(x,v) andf(x,w), and both

vandware between two constant multiples ofφ(|x|), we have, by (A.5) for somek >0,

Δv(x),Δw(x)kλGx,φ|x|, (A.14)

hence it follows from (A.2) that bothΔvandΔware inL1(RN).

Therefore, usingLemma 3.2, we havev≥was well asw≥vinRN, and hencevw.

References

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Lingyun Qiu: Department of Mathematics, Tianjin University, Tianjin 300072, China

Current address: Liu Hui Center for Applied Mathematics, Nankai University and Tianjin University, Tianjin 300072, China

E-mail address:[email protected]

Miaoxin Yao: Department of Mathematics, Tianjin University, Tianjin 300072, China

Current address: Liu Hui Center for Applied Mathematics, Nankai University and Tianjin University, Tianjin 300072, China

References

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