CRM/McGill Applied Mathematics Seminar
On analysis and numerical treatment of Einstein’s constraint equations
Gantumur Tsogtgerel
University of California, San Diego
Part 1: Joint with M. Holst and G. Nagy Part 2: Joint with M. Holst
March 13, 2009
Gravitational wave astronomy
Recently constructed gravitational wave detectors: LIGO, VIRGO, GEO600, TAMA300.
The two L-shaped LIGO observatories (in Washington and Louisiana), with legs at 4km, have phenomenal sensitivity, on the order of10−15m to10−18m. effective ranges (1.4Sol): 7-15MPc
Initial value formulation of the Einstein equations
The Lorentzian manifold(M, g)satisfies
G(g) := Ric(g) −12R(g)g = 0.
SupposeM = R × Σ, eachΣt={t} × Σis spacelike. On eachΣt, one has R(g) −|K|2g+ (trgK)2=0,
divgK − d(trgK) =0. (C) Conversely, if (C) holds on some Riemannian manifold(Σ, g), then there are
• a Lorentzian manifold(M, g)
• and an embeddingθ : Σ→ M
such thatG(g) = 0and thatθ∗gandθ∗Kare the first and second fundamental forms ofθΣ⊂ M[Choquet-Bruhat ’52].
The conformal method
Let(Σ, ˆg)be a Riemannian manifold,σbe a symmetric tensor withdivgˆσ =0, trgˆσ =0, and letτ∈ C∞(Σ). Withφa positive scalar, andwa vector field, put
g = φ4g,ˆ K = φ−2(σ + Lgˆw) + 13τφ4g,ˆ whereLgˆw =£wg −ˆ 23gˆdivgˆw. Then (C) is equivalent to
−8∆gˆφ + R(ˆg)φ +23τφ5−
σ + Lgˆw
2 ˆ
gφ−7=0,
−divgˆLgˆw +32φ6dτ =0.
Let us rewrite the above as
Aφ + Rφ +23τφ5− a(w)φ−7=: Aφ + f(w, φ) = 0, Bw + φ6dτ =0.
Note thattrgK = τand that ifτ =constthe system decouples.
Constant mean curvature solutions
[York, O’Murchadha, Isenberg, Marsden, Choquet-Bruhat, Moncrief, Maxwell, et al.]
Aφ + f(w, φ) = 0, Bw =0.
Sub- and super-solutions, or barriers:
Aφ−+ f(w, φ−)6 0, Aφ++ f(w, φ+)> 0.
For anys >0, the constraint equation is equivalent to
Aφ + sφ = sφ − f(w, φ) ⇔ φ = (A + sI)−1(sφ − f(w, φ)).
Ifs >0is sufficiently large, the map
T : [φ−, φ+]→ [φ−, φ+] : φ7→ (A + sI)−1(sφ − f(w, φ)) is monotone increasing. Also,T (φ−)> φ−andT (φ+)6 φ+. The iteration
φn+1= T (φn), φ0= φ−, converges to a fixed point ofT.
Super-solution
We want to findφ >0such that
Aφ + f(w, φ) = Aφ + Rφ +23τφ5− a(w)φ−7> 0.
Recalla(w) =
σ + Lgˆw
2
gˆ, and assume thatwis fixed (w =0in CMC case).
Assume thatτ =const > 0,R =const, and letφ =const > 0. Rφ +23τφ5− a(w)φ−7 > 23τφ5+ Rφ − φ−7sup a(w)
= φ−7 23τφ12+ Rφ8−sup a(w) Choosingφ >0sufficiently large one can ensure that the above is nonnegative.
Near constant mean curvature solutions
[Isenberg, Moncrief, Choquet-Bruhat, York, Allen, Clausen, et al.]
Aφ + f(w, φ) = 0, Bw + φ6dτ =0.
WithS : φ7→ −B−1(φ6dτ)this can be written as Aφ + f(S(φ), φ) = 0.
Sub- and super-solutions make sense, but in general T : φ7→ (A + sI)−1(sφ − f(S(φ), φ))
is not monotone. Nevertheless, whendτis smallTis almost monotone, and the iterationφn+1= T (φn)converges.
Now one needs global sub- and super-solutions, e.g.,φ+>0such that Aφ++ f(w, φ+)> 0,
for allw∈ S([0, φ+]).
Global super-solution
We want to findφ >0such that
Aφ + f(w, φ) = Aφ + Rφ +23τφ5− a(w)φ−7> 0.
for allw∈ S([0, φ]). Recall thata(w) =
σ + Lgˆw
2 ˆ
g. Elliptic estimates give a(w)6 p + qkφk12C0, with q∼ |dτ|2
Assume thatτ =const > 0,R =const, and letφ =const > 0, sokφkC0= φ. Rφ +23τφ5− a(w)φ−7> 23τφ5+ Rφ − pφ−7− qφ−7φ12
= (23τ − q)φ5+ Rφ − pφ−7.
Ifq < 23τ, choosingφ >0sufficiently large one can ensure that the above is nonnegative.
Fixed point approach
[Holst, Nagy, GT ’07, ’08]
Let0 < φ−6 φ+<∞be global barriers, i.e.,
Aφ−+ f(w, φ−)6 0, Aφ++ f(w, φ+)> 0, for allw∈ S([φ−, φ+]). Then fors >0large, and anyw∈ S([φ−, φ+])
Tw: φ7→ (A + sI)−1(sφ − f(w, φ)) is monotone increasing onU = [φ−, φ+], and forφ∈ U
T (φ)≡ TS(φ)(φ)6 TS(φ)(φ+)6 φ+, T (φ)> φ−, soT : U→ U. SinceTis compact, there is a fixed point inU.
Global super-solution
[Holst, Nagy, GT ’07, ’08]
We want to findφ >0such that
Aφ + f(w, φ) = Aφ + Rφ +23τφ5− a(w)φ−7> 0.
for allw∈ S([0, φ]). Recall that
a(w)6 p + qkφk12C0
Assume thatR =const > 0,τ =const, and letφ =const > 0. Rφ +23τφ5− a(w)φ−7> 23τφ5+ Rφ − pφ−7− qφ−7φ12
> φ−7 Rφ8− (q −23τ)φ12− p
Ifpis small enough (depending on how largeqis), choosingφ >0sufficiently small one can ensure that the above is nonnegative.
Extensions
• The framework is extended to allow for rough data, e.g., metrics inHswith s > 52
• The global super-solution construction is extended to all metrics in the positive Yamabe class (closed manifolds)
Ongoing work / wish list
• Asymptotically flat manifolds
• Manifolds with boundary, black hole initial data
• Zero and negative Yamabe classes, large data
• Full parameterization of the solution space
Finite element methods
Model problem:−∆u = f, or
a(u, v) := (∇u, ∇v) = (f, v) for all v ∈ H LetS⊂ Hbe a linear subspace. Consideru˜∈ Ssuch that
a(˜u, v) = (f, v) for all v ∈ S This gives the Galerkin orthogonality
a(u − ˜u, v) = 0 for all v ∈ S
oru − ˜u⊥aS.u˜is called the Galerkin approximation ofufromS.
Typical finite element mesh
Sis the space of continuous functions which are linear on each triangle.
-5 0 5
X -6
-4 -2 0 2 4 6
Z
Linear vs. nonlinear approximation
LetS0⊂ S1⊂ . . . ⊂ Hwith corresponding meshesT0, T1, . . ., and Galerkin approximationsu0, u1, . . ..
ku − uika=dist(u, Si)6 Chs−1i kukHs
wherehiis the maximum diameter of the triangles inTi. IfTj+1is the uniform refinement ofTj, thenhi∼ 2−iand the number of vertices ofTiisNi∼ 2inin n-dimension.
ku − uika=dist(u, Si)6 C2−i(s−1)kukHs6 CN−(s−1)/ni kukHs
IsTioptimal among meshes withNivertices?
Given a mesh, letS(T )be the corresponding FE space. Let ΣN=∪{S(T) : T is a refinement of T0and #T 6 N}
Then withp1 = 12+s−1n
dist(u, ΣN)6 CN−(s−1)/nkukWs,p
Adaptive finite element methods
In a typical AFEM, the sequenceuiis generated as follows. Start with some initial meshT0. Seti =0, and repeat
• Solve forui
• Estimate the distribution ofui− uover the triangles ofTi
• Refine the triangles ofTiwith largest error, to getTi+1
• i + +
We say the method is optimal if
kui− uka6 CN−(s−1)/nkukWs,p
Linear convergence
From the Galerkin orthogonality
a(u − ui+1, v) = 0 for all v ∈ Si+1, takingv = ui+1− ui, we have
ku − uik2a=ku − ui+1k2a+kui+1− uik2a. So if
kui+1− uika> cku − uika, with constantc∈ (0, 1), we have
ku − ui+1k2a=ku − uik2a−kui+1− uik2a6 (1 − c2)ku − uik2a.
Quasi-orthogonality for semilinear problems
Let us consider
a(u, v) + (f(u), v) = 0, ∀v ∈ H We have
ku − uik2a=ku − ui+1k2a+kui+1− uik2a+2a(u − ui+1, ui+1− ui)
a(u − ui+1, ui+1− ui) = (f(u) − f(ui+1), ui+1− ui) 6 Ckf(u) − f(ui+1)kkui+1− uik 6 Cku − ui+1kkui+1− uik
6 Chi+1ku − ui+1kH1kui+1− uikH1
Ongoing work / Open problems
• Geometry
• Boundary conditions
• Coupled system
• Fast solution of the discretized system
• Higher order elements, flexible mesh
• Problems with genuinely critical exponent
Manuscripts, Collaborators, Acknowledgments
HNT2 M. HOLST, G. NAGY,ANDGT, Far-from-constant mean curvature solutions of Einstein’s constraint equations with positive Yamabe metrics. Phys. Rev. Let., 100:161101, 2008. Also available as arXiv:0802.1031[gr-qc]
HNT1 M. HOLST, , G. NAGY,ANDGT, Rough solutions of the Einstein constraint equations on closed manifolds without near-CMC conditions. arXiv:0712.0798[gr-qc]. To appear in Comm. Math. Phys..
HT1 M. HOLST,ANDGT, Convergent adaptive finite element approximation of the Einstein constraints. In preparation.
Acknowledgments:
NSF: DMS 0411723, DMS 0715146 (Numerical geometric PDE) DOE: DE-FG02-05ER25707 (Multiscale methods)