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Volume 2009, Article ID 656534,17pages doi:10.1155/2009/656534

Research Article

Fixed Points Approximation and Solutions of Some

Equilibrium and Variational Inequalities Problems

Bashir Ali

1, 2

1Mathematics Stream, African University of Science and Technology, Abuja, Nigeria

2Department of Mathematical Sciences, Bayero University, Kano, P.M.B. 3011, Nigeria

Correspondence should be addressed to Bashir Ali,[email protected]

Received 28 September 2009; Accepted 16 December 2009

Recommended by Asao Arai

We prove a new strong convergence theorem for an element in the intersection of the set of common fixed points of a countable family of nonexpansive mappings, the set of solutions of some variational inequality problems, and the set of solutions of some equilibrium problems using a new iterative scheme. Our theorem generalizes and improves some recent results.

Copyrightq2009 Bashir Ali. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

LetH be a real Hilbert space; a mapping B : DBH is said to be monotone if for all

x, yDB

BxBy, xy ≥0. 1.1

For someλ >0,the mappingBis said to beλ-inverse strongly monotone if

BxBy, xyλBxBy2. 1.2

Aλ-inverse strongly monotone map is some time calledλ-cocoercive. A mapBis said to be

relaxedλ-cocoercive if there exists a constantλ >0 such that

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Bis said to be relaxedλ, γ-cocoercive, if there existλ, γ >0 such that

BxBy, xy ≥ −λBxBy2γxy2. 1.4

A mapB:HHis said to beλ-Lipschitzian if there exists a real numberλ≥0 such that

BxByλxyx, yH. 1.5

Bis a contraction map, if in the above inequalityλ∈0,1and nonexpansive ifλ1.

LetKbe a nonempty, closed, and convex subset of a real Hilbert spaceH.A variational inequality problem is searched forx∗∈Ksuch that

Bx, yx0 yK, 1.6

whereB is some nonlinear mapping of K intoH. Inequality1.6 is called the variational inequality.

Recall that for eachxH there exists a unique nearest point inK toxdenoted by

PKx.That is,xPKxxyfor allyK.PKis called a metric projection ofHontoK.

The mappingPKis nonexpansive in this setting, that is,PKxPKyxyfor allx, yH. It is also known thatPKsatisfies the following inequalityPKxPKy2≤ xy, PKxPKy.

The solution set of the problem1.6is denoted by VIK, B.It is well knownsee1 thatx∗∈VIK, Bif and only if

xPKxλBx, λ >0. 1.7

A monotone mapBis said to be maximal if the graphΓBofBis not properly contained in the graph of any other monotone map, whereΓB {x, y ∈ H×H : yBx}for a multivalued mapB.It is also known thatBis maximal monotone if and only if forx, f ∈

H×H,xy, fg ≥0 for everyy, g∈ΓBimpliesfBx.LetBbe a monotone mapping defined fromKintoHand letNKqbe a normal cone toKatqK,that is,NKq{pH:

qu, p, for alluK}.Define a mapMby

Mq

⎧ ⎨ ⎩

BqNKq, qK,

, q /K. 1.8

Then,Mis maximal monotone andx∗∈M−10xVIK, B,see, for example,2.

LetG : K×K → Rbe a bifunction on a closed convex nonempty subsetK of a real Hilbert spaceH.An equilibrium problem is searched forx∗∈Ksuch that

Gx, y0 yK. 1.9

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Several physical problemssuch as the theories of lubrications, filterations and flows, moving boundary problems, see, e.g., 1, 3 can be reduced to variational inequality or equilibrium problems. Consequently, these problems have solutions as the solutions of these resultant variational inequality or equilibrium problems.

Maing´e 4 introduced a Halpern-type scheme and proved a strong convergence theorem for family of nonexpansive mappings in Hilbert space.

Recently, S. Takahashi and W. Takahashi5introduced an iterative scheme which they used to study the problem of approximating a common element of the set of solutions of an equilibrium problem and the set of fixed points of a nonexpansive mapping.

More recently, Kumam and Katchang6, W. Kumam and P. Kumam7, Li and Su8 and many otherssee, e.g.9–12and the references contained in themstudied the problem of fixed point approximations and solutions of some equilibrium and, or solutions of some variational inequalities problems.

In this paper we introduce a new iterative scheme for approximation of a common element in the intersection of the set of fixed points of some countable family of nonexpansive mappings, the set of solutions of some equilibrium problem, and the set of solutions of some variational inequality problem and prove a new theorem. Our theorem generalizes and improves some recent results.

2. Preliminaries

For a sequence {xn} the notation xnx∗ and xn x∗ means that the sequence {xn} converges strongly and weakly to x∗, repectively. A Banach space E is said to satisfy an Opial’s conditionor in other words is an Opial’s space if for a sequence{xn}in Ewith xn x,then

lim inf

n→ ∞ xnx

<lim inf

n→ ∞ xny for any yE y /x

.

2.1

It is well known that Hilbert spaces are Opial’s spacessee13. In the sequel we shall make use of the following results.

Lemma 2.1see14. LetKbe a nonempty closed convex subset ofHand letGbe a bifunction of

K×KintoR satisfying

A1Gx, x 0 forallxK;

A2Gis monotone, i.e.Gx, y Gy, x0 forallx, yK;

A3forallx, y, zK,limsupt0Gtz 1tx,y≤Gx,y;

A4forall xK,Gx, .is convex and lower semicontinuous.

Letr >0 andxH.Then there existszKsuch that

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Lemma 2.2see15. LetKbe a nonempty closed convex subset ofHand letGbe a bifunction of

K×KintoRsatisfyingA1A4.Forr >0 andxHdefine a mapTr :HKby

Trx

zK:Gz, y1

ryz, zx ≥0,yK

. 2.3

Then, the following holds:

1Tr is single-valued;

2Tr is firmly nonexpansive, that is, for anyx, yH

TrxTry2 ≤TrxTry, xy; 2.4

3FixTr EPG;

4EPGis closed and convex.

Lemma 2.3see16. LetHbe a real inner product space. Then, the following inequality holds:

xy2x22y, xyx, yH. 2.5

Lemma 2.4see17. Let{xn}and{yn}be bounded sequences in a Banach spaceEand let{βn}

be a sequence in0,1with 0<lim infβn ≤lim supβn <1. Supposexn1 βnyn 1−βnxnfor

all integersn0 and lim supyn1−ynxn1−xn0. Then, limynxn0.

Lemma 2.5see18. Let{an}be a sequence of nonnegative real numbers satisfying the following

relation:

an1≤1−αnanαnσnγn, n≥0, 2.6

Wherei{αn} ⊂ 0,1,αn;iilim supσn0;iiiγn ≥ 0;n ≥ 0,γn <.Then,

an0 asn → ∞.

3. Main Results

In the sequel we assume that the sequences{αn},{σi,n}i⊂0,1satisfyi≥1σi,n1−αn.

Theorem 3.1. LetKbe a nonempty, closed, and convex subset of a real Hilbert spaceH.LetGbe a

bifunction fromK×KtoRwhich satisfies conditionsA1A4.Let{Ti, i1,2,3, . . .}be family

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KintoHsuch thatF:∞i1FixTi∩EPG∩VIK, B/.For an arbitrary but fixedδ ∈0,1,

let{xn}and{yn}be sequences generated by

x1, uH,

Gyn, ηrn1ηyn, ynxn ≥0,ηK,

xn1αnu 1−δ1−αnxnδ

i≥1

σinTiPKIsnByn, n≥1,

3.1

where{αn}and{σin}are sequences in0,1and{rn}and{sn}are sequences in0,satisfying

C1limn→ ∞αn0, C2∞n1αn,

C3{sn} ⊂a, bfor somea, bsatisfying 0ab≤2γ−λμ2/μ2,

C4limn→ ∞|sn1−sn|0, limn→ ∞|rn1−rn|0, limn→ ∞i≥1|σi,n1−σi,n|0, C5lim infn→ ∞rn>0.

Then, both{xn}and{yn}converge strongly toPFu.

Proof. First, we show thatI−snBis nonexpansive, actually, using the property ofBwe have

forx, yH,

I−snBx−I−snBy2xysnBxBy2

xy22snxy, BxBys2

nBxBy2

xy22s n

λBxBy2γxy2s2

nBxBy2

xy22s

2λxy2−2snγxy2μ2s2nxy2 12snμ2λ−2snγμ2s2nxy2

xy2,

3.2

and thusI−snBis nonexpansive.

Letx∗ ∈F; sinceyn Trnxn,n∈ Nand the fact thatTrn is firmly nonexpansiveand

hence nonexpansivewe have the following:

ynxTrnxnTrnx∗ ≤ xnx. 3.3

We claim that{xn}satisfies

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We prove this by induction. Cearly the result is true forn1.Assume that the result holds fornkfor somek∈N.Then, fornk1 we have

xk1−xαkux∗ 1−δ1−αkxkxδ

i≥1

σikTiPKIskBykx

αkux 1δ1αkxkx

δ i≥1

σikTiPKIskBykTiPKIskBx

αkux 1αkxkx

≤max{ux,xkx∗}.

3.5

Hence the result, and so{xn}is bounded. Furthermore,{yn},{TiPKynsnByn}and{Byn}

are each bounded.

We now show that limn→ ∞xn1−xn 0.Note thatyn Trnxn,yn1 Trn1xn1,so

that

Gyn, ηrn1ηyn, ynxn ≥0 ∀ηK,

Gyn1, η

r1 n1

ηyn1, yn1−xn1 ≥0 ∀ηK.

3.6

Using3.6andA2,we have

yn1−yn,ynrxn

n

yn1−xn1 rn1

≥0. 3.7

which implies that

yn1−yn, ynyn1yn1−xnrrn n1

yn1−xn1

≥0. 3.8

from which we get

yn1−yn2≤ yn1−yn

xn1−xn1−rrn n1

yn1−xn1

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If, without loss of generality M,m are real numbers such that rn > m > 0 for all nand

M:supn,i{ynxn,TiPKIsnByn,Byn}we then have

yn1−ynxn1−xn1−rrn n1

yn1−xn1

xn1−xnMm|rn1−rn|.

3.10

Now, define two sequences{βn}and{zn}byβn: 1−δαnδandzn: xn1−xnβnxn/βn.

Then,

zn

αnuδi≥1σi,nTiPKIsnByn

βn . 3.11

Observe that{zn}is bounded and that

zn1−znxn1−xnαnβ 1 n1 −

αn βn

u

δ1βαn1 n1

yn1−ynxn1−xn

βδ n1

i≥1

|σi,n1−σi,n|TiPKIsn1Byn

β δ n1βn

βnβn1 i≥1

σi,n1TiPKIsn1Byn

δ1−αβnByn

n |snsn1|.

3.12

Using3.10we have that

zn1−znxn1−xnαnβ 1 n1 −

αn βn

u

δ1βαn1 n1 −

1xn1−xnδ

1−αn1M

βn1m |

rn1−rn|

βδM n1

i≥1

|σi,n1−σi,n| δM βn1βn

βnβn1δ

1−αnM

βn |snsn1|. 3.13

This implies

lim sup

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and by Lemma2.4, limn→ ∞znxn0.Hence,

xn1−xnβnznxn −→0 asn−→ ∞. 3.15

Using3.10we have

yn1−yn −→0 as n−→ ∞. 3.16

We now have

ynx∗2 TrnxnTrnx∗2

TrnxnTrnx, xnx

ynx, xnx

1

2

ynx∗2xnx∗2− xnyn2

,

3.17

so that

ynx2xnx2xnyn2. 3.18

But,

xn1−x∗2

αnux 1δ1αnxnx

δ

i≥1

σinTiPKIsnBynTiPKIsnBx∗ 2

αnux∗2 1−δ1−αnxnx∗2 δ

i≥1

σinTiPKIsnBynTiPKIsnBx∗2

αnux2 1δ1αnxnx2δ1αnynx2.

3.19

Putting3.18in3.19, we have

δ1−αnxnyn2≤αnux∗2xnx∗2− xn1−x∗2

αnux∗2 xnx∗ − xn1−xxnxxn1−x

αnux2 xnxn

1xnxxn1−x∗,

(9)

and hence,

lim

n→ ∞xnyn0. 3.21

Observe also that ifwn:PKIsnByn,then

wnx∗2PKIsnBynPKIsnBx∗2

ynxsnBynBx2

ynx22snynx, BynBxs2

nBynBx∗2

ynx22snλBynBx2γynx2s2

nBynBx∗2 ynx∗22snλBynBx∗2−2snγynx∗2s2nBynBx∗2

ynx2

2snλs2n−2snγ

μ2

BynBx2.

3.22

Also,

xn1−x∗2

αnux 1δ1αnxnx

δ

i≥1

σinTiPKIsnBynTiPKIsnBx∗ 2

αnux2 1δ1αnxnx2

δ i≥1

σinTiPKIsnBynTiPKIsnBx∗2

αnux∗2 1−δ1−αnxnx∗2δ

i≥1

σinTiwnx∗2

αnux2 1δ1αnxnx2δ1αnwnx2

αnux2 1δ1αnxnx2

δ1−αn

ynx∗2

2snλs2n−2snγμ2

BynBx∗2

αnux∗2 1−αnxnx∗2δ1−αn

2snλs2n−2 snγ μ2

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which implies

δ1−αn

2snλs2n−2snγ

μ2

BynBx2αnux2xnx2xn

1−x∗2 3.24

so that

lim

n→ ∞BynBx

0.

3.25

We go further to prove that for eachi∈N,

lim

n→ ∞TiPKIsnBynyn0. 3.26

Consider the following estimates:

TiPKI−snBynyn2TiPKIsnBynxxyn2

xyn22TiPKIsnBynx, xyn TiPKIsnBynx∗2

≤2x∗−yn22TiPKI−snBynynynx, x∗−yn

2ynx∗22TiPKIsnBynyn, x∗−yn −2ynx∗2 2TiPKI−snBynyn, x∗−yn.

3.27

Using3.1, we have

xn1−x, ynxαnux, ynx∗ 1−αn1−δxnx, ynxδ

i≥1

σi,nTiPKIsnBynynynx, ynx

αnux, ynx∗ 1−αn1−δxnynynx, ynx

δ i≥1

σi,nTiPKIsnBynyn, ynxδ1−αnynx∗2

αnux, ynx∗ 1−αn1−δxnyn, ynx

δ i≥1

σi,nTiPKIsnBynyn, ynx∗ 1−αn1−δynx∗2

δ1−αnynx∗2,

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which implies

δ

i≥1

σi,nTiPKI−snBynyn, xynαnux, ynx

1−αn1−δxnyn, ynx

1−αnynx, ynx

xn1−x, ynxαnuxn1, ynx

1−αn1−δxnyn, ynx

1−αnynxn1, ynx.

3.29

Using this and3.27, we get

δ

2

i≥1

σi,nTiPKIsnBynyn2≤αnuxn1, ynx

1−αn1−δxnyn, ynx

1−αnynxn1, ynx.

3.30

Since{xn},{yn}are each bounded and using3.21, we have that

lim

n→ ∞TiPKIsnBynyn0 ∀i∈N. 3.31

Using this and3.21, we also have

lim

n→ ∞TiPKIsnBynxn0 ∀i∈N. 3.32

Next we show that lim supn→ ∞uw, xnw ≤0,wherew P

i1FixTi∩EPG∩VIK,Bu.Let

{xnj}be a subsequence of{xn}such that lim supn→ ∞uw, xnwlimj→ ∞uw, xnjw.

Since{yn}is bounded, there exists a subsequence {ynj}of {yn}such that ynj z.

Then,z∈∞i1FixTiPKI−snB,otherwise, fori∈N,we have

lim inf

j→ ∞ ynjz<lim infj→ ∞

yn

jTiPK

IsnjB

z

≤lim inf

j→ ∞

y

njTiPK

IsnjB

ynj TiPK

IsnjB

ynjTiPK

IsnjB

z

≤lim inf

j→ ∞ ynjz,

3.33

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Next we show thatz∈EPG.Sinceyn Trnxn,we have

Gyn, η r1

yn, ynxn ≥0,ηK. 3.34

It follows fromA2that

ηyn,ynrxn n

Gη, yn, 3.35

and so

ηyni,

ynixni

rni

Gη, yni

. 3.36

Sinceynixni/rni → 0,yni zand usingA4,we haveGη, z ≤0 for allηK.For a

real numbert, 0< t≤1 andηK,letηttη 1−tz.ClearlyηtK,so that usingA1and

A4,we have

0Gηt, ηttGηt, η 1−tGηt, ztGηt, η. 3.37

This impliesGηt, η≥0,and using this andA3we have thatGz, η≥0 for allηKand

hencez∈EPG.

Next we show thatz∈VIK, B. Letx∗∈Fthen, we have the following:

wnx∗2PKIsnBynPKIsnBx∗2

ynsnBynx∗−snBx, wnx

ynx, wnxsnBynBx, wnx

≤ 1

2

wnx2ynx2wnyn2snBynBx, wnx,

3.38

so that

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We then have

xn1−x∗2αnux∗ 1−αn1−δxnxδ

i≥1

σi,nTiwnx∗2

αnux∗2 1−αn1−δxnx∗2 1−αnδwnx∗2

αnux∗2 1−αn1−δxnx∗2

1−αnδynx∗2− wnyn2−2snBynBx, wnx

αnux∗2 1−αn1−δxnx∗2

1−αnδxnx∗2− wnyn2−2snBynBx, wnx

αnux2 1αnxnx2δ1αnwnyn2

−2snδ1−αnBynBx, wnx,

3.40

so that

δ1−αnwnyn2≤αnux∗2xnx∗2− xn1−x∗2

−2δsn1−αnBynBx, wnx,

3.41

and asαn → 0,xnxn1 → 0 andBynBx∗ → 0 asn → ∞,we get

lim

n→ ∞ynwn0. 3.42

Using this and3.21we also have

lim

n→ ∞xnwn0. 3.43

AsBis a relaxedλ, γ-cocoercive and using conditionC3we have forx, yH

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and soBis monotone. If

Mq

⎧ ⎨ ⎩

BqNKq, qK,

, q /K, 3.45

thenMis maximal monotone. LetΓMdenote the graph ofM.

Letq, p∈ΓM.SincepBqNKqandwnK,we havepBq, qwn ≥0 by definition ofNKq.Also, aswn PKynsnByn using property of the projectionPK, we

have

wnynsnByn, qwn ≥0, 3.46

and hence

wnyn

sn Byn, qwn

≥0. 3.47

Using this, we obtain the following estimates:

p, qwniBq, qwni

Bq, qwni

wn

iyni

sni

Byni, qwni

Bqwniyni

snByni, qwni

BqBwni, qwniBwniByni, qwni

wn

iyni

sn , qwni

BwniByni, qwni

w

niyni

sn , qwni

,

3.48

which impliesp, qz ≥0lettingi → ∞.

SinceMis maximal monotone, we obtained thatzM−10and hencez∈VIK, B. We mention here that since we proved that z ∈ ∞i1FixTiPKIsnB and z

VIK, B,thenz∈∞i1FixTi.So, clearlyz∈∞i1FixTi∩EPG∩VIK, B. SincewP

i1FixTi∩EPG∩VIK,Bu, we have

lim sup

n→ ∞ uw, xnwilim→ ∞uw, xniwuw, zw ≤0. 3.49

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From the recursion formula3.1and Lemma2.3, we have

xn1−w2

αnuw 1−αn1−δxnw

δ i≥1

σi,nTiPKIsnBynw

2

≤ 1−αn1−δxnw δ

i≥1

σi,nTiPKIsnBynw 2

2αnuw, xn1−w

1−αn1−δxn

i≥1

σi,nTiPKIsnBynw

2

2αnuw, xn1−w

≤1−αnxnw22αnuw, xn1−w.

3.50

Using Lemma2.5, we have that{xn}and consequently{yn}converge towand the proof is complete.

The following corollaries follow from Theorem3.1.

Corollary 3.2. LetK, GandBbe as in Theorem3.1and let{Ti, i1,2,3, . . . , N}be finite family of

nonexpansive mappings ofKintoH.LetF:Ni1FixTi∩EPG∩VIK, B/. For an arbitrary

but fixedδ∈0,1,let{xn}and{yn}be sequences generated by

x1, uH,

Gyn, ηrn1ηyn, ynxn ≥0,ηK,

xn1αnu 1−δ1−αnxnδ N

i1

σinTiPKIsnByn, n≥1,

3.51

where{αn}and{σin}are sequences in0,1and{rn}and{sn}are sequences in0,satisfying

C1limn→ ∞αn0,Ni1σin 1−αn, C2∞n1αn,

C3{sn} ⊂a, bfor somea, bsatisfying 0ab≤2γ−λμ22,

C4limn→ ∞|sn1−sn|0, limn→ ∞|rn1−rn|0, limn→ ∞Ni1|σi,n1−σi,n|0, C5lim infn→ ∞rn>0.

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Corollary 3.3. LetK andGbe as in Theorem3.1. LetT be a nonexpansive map ofK intoH. Let

F : FixT∩EPG/. For an arbitrary but fixed δ ∈ 0,1, let{xn} and {yn} be sequences

generated by

x1, uH,

Gyn, ηrn1ηyn, ynxn ≥0,ηK,

xn1αnu 1−δ1−αnxnδ1−αnTyn, n≥1,

3.52

where{αn}is a sequence in0,1and{rn}is a sequences in0,satisfying

C1limn→ ∞αn0 C2∞n1αn,

C3limn→ ∞|rn1−rn|0, C4lim infn→ ∞rn>0.

Then, both{xn}and{yn}converge strongly toPFu.

Remark 3.4. Prototypes of the sequences{αn}and{σi,n}in our theorem are the following:

αn: n11, σi,n: n

2in1 ∀i∈N. 3.53

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References

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