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Volume 2011, Article ID 274820,19pages doi:10.1155/2011/274820

Research Article

Hybrid Algorithm for Finding Common

Elements of the Set of Generalized Equilibrium

Problems and the Set of Fixed Point Problems of

Strictly Pseudocontractive Mapping

Atid Kangtunyakarn

Department of Mathematics, Faculty of Science, King Mongkut’s Institute of Technology Ladkrabang, Bangkok 10520, Thailand

Correspondence should be addressed to Atid Kangtunyakarn,[email protected]

Received 8 November 2010; Accepted 14 December 2010

Academic Editor: Qamrul Hasan Ansari

Copyrightq2011 Atid Kangtunyakarn. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

The purpose of this paper is to prove the strong convergence theorem for finding a common element of the set of fixed point problems of strictly pseudocontractive mapping in Hilbert spaces and two sets of generalized equilibrium problems by using the hybrid method.

1. Introduction

Let C be a closed convex subset of a real Hilbert spaceH, and let F : C ×C → R be a bifunction. Recall that the equilibrium problem for a bifunctionFis to findxCsuch that

Fx, y≥0,yC. 1.1

The set of solutions of1.1is denoted by EPF. Given a mappingT : CH, letFx, y

Tx, yx for allx, yC. Then,z ∈ EPFif and only ifTz, yz ≥ 0 for all yC; that is,zis a solution of the variational inequality. LetA : CHbe a nonlinear mapping. The variational inequality problem is to find auCsuch that

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for allvC. The set of solutions of the variational inequality is denoted by VIC, A. Now, we consider the following generalized equilibrium problem:

Find zCsuch thatFz, yAz, yz≥0,yC. 1.3

The set ofzCis denoted by EPF, A, that is,

EPF, A zC:Fz, yAz, yz≥0,yC. 1.4

In the case of A ≡ 0, EPF, Ais denoted by EPF. In the case ofF ≡ 0, EPF, Ais also denoted by VIC, A. Numerous problems in physics, optimization, variational inequalities, minimax problems, the Nash equilibrium problem in noncooperative games, and economics are reduced to find a solution of1.3; see, for instance,1–3.

A mappingAofCintoHis called inverse strongly monotone mapping, see4, if there exists a positive real numberαsuch that

xy, AxAyαAxAy2 1.5

for allx, yC. The following definition is well known.

Definition 1.1. A mappingT : CCis said to be aκ-strict pseudocontraction if there exists

κ∈0,1such that

TxTy2

xy2κITxITy2,x, yC. 1.6

A mappingTis called nonexpansiveif

TxTyxy 1.7

for allx, yC.

We know thatκ-strict pseudocontraction includes a class of nonexpansive mappings. Ifκ 1,T is said to be a pseudocontractivemapping.T is strong pseudocontraction if there exists a positive constantλ ∈ 0,1such thatT λI is pseudocontraction. In a real Hilbert spaceH,1.6is equivalent to

TxTy, xyxy2−1−κ

2 ITxITy

2

,x, yDT. 1.8

Tis pseudocontraction if and only if

TxTy, xyxy2,x, yDT. 1.9

Then,Tis strong pseudocontraction if there exists positive constantλ∈0,1

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The class ofκ-strict pseudocontractions falls into the one between classes of nonex-pansive mappings, and the pseudocontraction mappings, and the class of strong pseudocon-traction mappings is independent of the class ofκ-strict pseudocontraction.

We denote byFTthe set of fixed points ofT. IfCHis bounded, closed, and convex, andTis a nonexpansive mapping ofCinto itself, thenFTis nonempty; for instance, see5. Browder and Petryshyn6show that if aκ-strict pseudocontractionThas a fixed point inC, then starting with an initialx0∈C, the sequence{xn}generated by the recursive formula:

xn1αxn 1−αTxn, 1.11

whereαis a constant such that 0< α <1, converges weakly to a fixed point ofT. Marino and Xu7have extended Browder and Petryshyns above-mentioned result by proving that the sequence{xn}generated by the following Manns algorithm8:

xn1αnxn 1−αnTxn 1.12

converges weakly to a fixed point ofT provided the control sequence{αn}∞n0 satisfies the conditions thatκ < αn<1 for allnand ∞n0αnκ1−αn ∞. In 1974, S. Ishikawa proved the following strong convergence theorem of pseudocontractive mapping.

Theorem 1.2see9. LetCbe a convex compact subset of a Hilbert spaceH, and letT : CC

be a Lipschitzian pseudocontractive mapping. For any x1 ∈ C, suppose that the sequence {xn} is

defined by

yn

1−βn

xnβnTxn,

xn1 1−αnxnαnTyn,n∈N,

1.13

where{αn},{βn}are two real sequences in0,1satisfying

iαnβn, for alln∈N,

iilimn→ ∞βn0 ,

iii ∞n1αnβn.

Then{xn}converges strongly to a fixed point ofT.

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Theorem 1.3see7. LetCbe a closed convex subset of a Hilbert spaceH. LetT : CCbe aκ-strict pseudocontraction for some0 ≤ κ < 1, and assume that the fixed point setFTofT is nonempty. Let{xn}∞n1be the sequence generated by the followingCQalgorithm:

x1∈C,

ynαnxn 1−αnTxn,

Cn

zC:ynz2≤1−αnκαnxnTxn2

,

Qn{zC:xnz, x1−xn},

xn1PCnQnx1.

1.14

Assume that the control sequence {αn}∞n1 is chosen so that αn < 1 for all n ∈ N. Then {xn}

converges strongly to PFTx1. Very recently, in 2010, [10] established the hybrid algorithm for Lipschitz pseudocontractive mapping as follows:

ForC1C, x1PC1x1,

yn 1−αnxnαnTzn,

zn

1−βn

xnβnTxn,

Cn1

zCn :αnITyn2≤2αn

xnz,ITyn

2αnβnLxnTxnynxnαnITyn,

xn1PCn1x1,n∈N.

1.15

Under suitable conditions of{αn}and {βn}, they proved that the sequence {xn}defined by 1.15

converges strongly toPFTx1.

Many authors study the problem for finding a common element of the set of fixed point problem and the set of equilibrium problem in Hilbert spaces, for instance, [2,3,11–15]. The motivation of

1.14,1.15, and the research in this direction, we prove the strong convergence theorem for finding solution of the set of fixed points of strictly pseudocontractive mapping and two sets of generalized equilibrium problems by using the hybrid method.

2. Preliminaries

In order to prove our main results, we need the following lemmas. LetCbe closed convex subset of a real Hilbert spaceH, and letPC be the metric projection ofHontoC; that is, for

xH,PCxsatisfies the property

xPCxmin yC

xy. 2.1

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Lemma 2.1 see5. Given thatxHand yC, thenPCx yif and only if the following

inequality holds:

xy, yz≥0,zC. 2.2

The following lemma is well known.

Lemma 2.2. LetH be Hilbert space, and letCbe a nonempty closed convex subset ofH. LetT :

CCbeκ-strictly pseudocontractive, then the fixed point setFTofTis closed and convex so that the projectionPFTis well defined.

Lemma 2.3demiclosedness principle see16. IfTis aκ-strict pseudocontraction on closed

convex subsetCof a real Hilbert spaceH, thenIT is demiclosed at any pointyH.

To solve the equilibrium problem for a bifunctionF : C×C → R, assume that F

satisfies the following conditions:

A1Fx, x 0 for allxC,

A2F is monotone,that is, Fx, y Fy, x≤0, for allx, yC,

A3for allx, y, zC,

lim t→0F

tz 1−tx, yFx, y, 2.3

A4for allxC, yFx, yis convex and lower semicontinuous.

The following lemma appears implicitly in1.

Lemma 2.4see1. LetCbe a nonempty closed convex subset ofH, and letFbe a bifunction of

C×CintoRsatisfyingA1–A4. Letr >0, andxH. Then, there existszCsuch that

Fz, y1 r

yz, zx, 2.4

for allxC.

Lemma 2.5see11. Assume thatF :C×C → RsatisfiesA1–A4. Forr >0andxH,

define a mappingTr : HCas follows:

Trx

zC:Fz, y 1 r

yz, zx≥0,yC

, 2.5

for allzH. Then, the following hold:

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2Tr is firmly nonexpansive, that is,

TrxTry2

TrxTr

y, xy,x, yH, 2.6

3FTr EPF;

4EPFis closed and convex.

Lemma 2.6see17. LetCbe a closed convex subset ofH. Let{xn}be a sequence inHanduH.

LetqPCu; if{xn}is such thatωxnCand satisfy the condition

xnuuq,n∈N, 2.7

thenxnq, as n → ∞.

Lemma 2.7see7. For a real Hilbert space H, the following identities hold: if{xn}is a sequence

in H weak convergence toz, then

lim sup n→ ∞

xny2

lim sup n→ ∞

xnz2zy2, 2.8

for allyH.

3. Main Result

Theorem 3.1. Let Cbe a nonempty closed convex subset of a Hilbert space H. LetF and G be

bifunctions fromC×CintoRsatisfyingA1–A4, respectively. LetA:CHbe anα-inverse strongly monotone mapping, and letB : CHbe a β-inverse strongly monotone mapping. Let T :CCbe aκ-strict pseudocontraction mapping withFFTEPF, AEPG, B/. Let {xn}be a sequence generated byx1∈CC1and

Fun, u Axn, uun 1

rnuun, unxn ≥0,uC,

Gvn, v Bxn, vvn 1

snvvn, vnxn

0,vC,

znδnun 1−δnvn,

ynαnzn 1−αnTzn,

Cn1zCn:ynzxnz

,

xn1PCn1x1,n≥1,

3.1

where {αn}∞n0 is sequence in 0,1,rna, b ⊂ 0,2α, and snc, d ⊂ 0,2β satisfy the

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ilimn→ ∞δn δ∈0,1,

ii0≤καn<1, for alln≥1.

Thenxnconverges strongly toPFx1.

Proof. First, we show thatIrnAis nonexpansive. Letx, yC. SinceAisα-inverse strongly monotone mapping andrn<2α, we have

IrnAxIrnAy2

xyrn

AxAy2

xy2−2rn

xy, AxAyrn2AxAy

2

xy2−2αrnAxAy2rn2AxAy

2

xy2rnrn−2αAxAy2

xy2.

3.2

ThusIrnAis nonexpansive, so areIsnB,TrnIrnA, andTsnIsnB. Since

Fun, u Axn, uun 1

rnuun, unxn

0,uC, 3.3

then we have

Fun, u 1

rnuun, unIrnAxn

0. 3.4

By Lemma2.5, we haveun TrnIrnAxn. By the same argument as above, we conclude

thatvnTsnIsnBxn.

Letz∈F. ThenFz, y yz, Az ≥0 andGz, y yz, Bz ≥0. Hence

Fz, y 1 rn

yz, zzrnAz

≥0,

Gz, y 1 sn

yz, zzsnBz

≥0.

3.5

Again by Lemma2.5, we havez TrnzrnAz TsnzsnBz. By nonexpansiveness of TrnIrnAandTsnIsnB, we have

unzTrnIrnAxnTrnIrnAz

xnz,

vnzTsnIsnAxnTsnIsnAz

xnz.

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By3.6, we have

znzxnz. 3.7

Next, we show thatCn is closed and convex for everyn∈ N. It is obvious thatCnis closed. In fact, we know that, forzCn,

ynzxnz is equivalent toynxn22

ynxn, xnz

≤0. 3.8

So, we have that for allz1, z2∈Cnandt∈0,1, it follows that

ynxn2

2ynxn, xntz1 1−tz2

t2ynxn, xnz1

ynxn2

1−t2ynxn, xnz2

ynxn2

≤0.

3.9

Then, we have thatCn is convex. By Lemmas2.5and2.2, we conclude thatFis closed and convex. This implies thatPFis well defined. Next, we show thatF⊂Cnfor everyn∈N.

Takingp∈F, we have

ynp2

αn

znp

1−αn

Tznp2

αnznp2 1−αnTznp2−αn1−αnznTzn2

αnznp2 1−αn

znp2κITznITp2

αn1−αnznTzn2

αnznp2 1−αnznp2κ1−αnznTzn2

αn1−αnznTzn2

znp2 καn1−αnznTzn2

znp2

xnp2.

3.10

It follows thatpCn. Then, we haveF⊂Cn, for alln∈N. SincexnPCnx1, for everywCn,

we have

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In particular, we have

xnx1 ≤ PFx1−x1. 3.12

By3.11, we have that{xn}is bounded, so are{un},{vn},{zn},{yn}. Sincexn1 PCn1x1 ∈

Cn1⊂CnandxnPCnx1, we have

0≤ x1−xn, xnxn1

x1−xn, xnx1x1−xn1

≤ −xnx12xnx1x1−xn1.

3.13

It is implied that

xnx1 ≤ xn1−x1. 3.14

Hence, we have that limn→ ∞xnx1exists. Since

xnxn12xnx1x1−xn12

xnx122xnx1, x1−xn1x1−xn12

xnx122xnx1, x1−xnxnxn1x1−xn12

xnx12−2xnx122xnx1, xnxn1x1−xn12

x1−xn12− xnx12,

3.15

it is implied that

lim

n→ ∞xnxn10. 3.16

Sincexn1PCn1x1∈Cn1, we have

ynxn1xnxn1, 3.17

And by3.16, we have

lim

n→ ∞ynxn10. 3.18

Since

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by3.16and3.18, we have

lim

n→ ∞ynxn0. 3.20

Next, we show that

lim

n→ ∞unxn0, nlim→ ∞vnxn0. 3.21

Letp∈F, by3.10and3.7, we have

ynp2

αn

znp

1−αn

Tznp2

αnznp2 1−αnTznp2−αn1−αnznTzn2

αnznp2 1−αn

znp2κITznITp2

αn1−αnznTzn2

αnznp2 1−αnznp2κ1−αnznTzn2

αn1−αnznTzn2

αnznp2 1−αnznp2 καn1−αnznTzn2

αnxnp2 1−αnznp2

αnxnp2 1−αn

δnunp2 1−δnvnp2

.

3.22

SinceunTrnIrnAxn,pTrnIrnAp, we have

unp2

TrnIrnAxnTrnIrnAp

2

IrnAxnIrnAp2

xnrnAxnprnAp2

xnprn

AxnAp2

xnp2rn2AxnAp2−2rn

xnp, AxnAp

xnp2rn2AxnAp2−2rnαAxnAp2

xnp2rnrn−2αAxnAp2.

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SincevnTsnIsnBxn,pTsnIsnBp, we have

vnp2

TsnIsnBxnTsnIsnBp

2

IsnBxnIsnBp2

xnsnBxnpsnBp2

xnpsn

BxnBp2

xnp2sn2BxnBp2−2sn

xnp, BxnBp

xnp2s2nBxnBp2−2snβBxnBp2

xnp2sn

sn−2βBxnBp2.

3.24

Substituting3.23and3.24into3.22,

ynp2

αnxnp2 1−αn

δnunp2 1−δnvnp2

αnxnp2

1−αn

δn

xnp2rnrn−2αAxnAp2

1−δn

xnp2sn

sn−2βBxnBp2

αnxnp2

1−αn

δnxnp2δnrnrn−2αAxnAp2

1−δnxnp2sn1−δn

sn−2βBxnBp2

αnxnp2 1−αn

×xnp2δnrnrn−2αAxnAp2sn1−δn

sn−2βBxnBp2

αnxnp2 1−αnxnp2 1−αnδnrnrn−2αAxnAp2

sn1−αn1−δn

sn−2βBxnBp2

xnp2 1−αnδnrnrn−2αAxnAp2

sn1−αn1−δn

sn−2βBxnBp2.

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It is implied that

1−αnδnrn2αrnAxnAp2≤xnp2−ynp2

sn1−αn1−δn

sn−2βBxnBp2

xnpynpxnyn.

3.26

By3.20and conditioni, we have

lim

n→ ∞AxnAp0. 3.27

By using the same method as3.27, we have

lim

n→ ∞BxnBp0. 3.28

By Lemma2.5and firm nonexpansiveness ofTrn, we have

unp2

TrnIrnAxnTrnIrnAp

2

IrnAxnIrnAp, unp

1

2

IrnAxnIrnAp2unp2

IrnAxnIrnAp

unp2

1

2

IrnAxnIrnAp2unp2

xnunrn

AxnAp2

1

2

IrnAxnIrnAp2unp2

xnun2rn2AxnAp2−2rn

xnun, AxnAp

≤ 1

2

xnp2unp2− xnun2−rn2AxnAp2

2rn

xnun, AxnAp

.

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By3.29, it is implied that

unp2

xnp2− xnun2−rn2AxnAp2

2rn

xnun, AxnAp

xnp2− xnun2−rn2AxnAp2

2rnxnunAxnAp.

3.30

Again, by Lemma2.5and firm nonexpansiveness ofTsn, we have

vnp2

TsnIsnBxnTsnIsnAp

2

IsnBxnIsnBp, vnp

1

2

IsnBxnIsnBp2vnp2

IsnBxnIsnBp

vnp2

1

2

IsnBxnIsnBp2vnp2−xnvnsn

BxnBp2

1

2

IsnBxnIsnBp2vnp2

xnvn2s2nBxnBp2−2sn

xnvn, BxnBp

≤ 1

2

xnp2vnp2− xnvn2−s2nBxnBp2

2sn

xnvn, BxnBp

.

3.31

By3.31, it is implied that

vnp2

xnp2− xnvn2−s2nBxnBp22sn

xnvn, BxnBp

xnp2− xnvn2−s2nBxnBp22snxnvn BxnBp.

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Substituting3.30and3.32into3.22, we have

ynp2

αnxnp2 1−αn

δnunp2 1−δnvnp2

αnxnp2 1−αn

×δn

xnp2− xnun2−rn2AxnAp22rnxnunAxnAp

1−δn

xnp2− xnvn2−s2nBxnBp2

2snxnvnBxnBp

αnxnp2

1−αn

δn

xnp2− xnun22rnxnunAxnAp

1−δn

xnp2− xnvn22snxnvnBxnBp

αnxnp2

1−αn

δnxnp2−δnxnun22δnrnxnunAxnAp 1−δn

×xnp2−1−δnxnvn221−δnsnxnvnBxnBp

αnxnp2 1−αn

×xnp2−δnxnun22δnrnxnunAxnAp−1−δnxnvn2

21−δnsnxnvnBxnBp

xnp2−1−αnδnxnun22δnrnxnunAxnAp

−1−αn1−δnxnvn221−δnsnxnvnBxnBp,

3.33

which implies that

1−αnδnxnun2≤xnp2−ynp22δnrnxnunAxnAp

−1−αn1−δnxnvn221−δnsnxnvnBxnBp

xnynxnpynp2δnrnxnunAxnAp

−1−αn1−δnxnvn221−δnsnxnvnBxnBp

xnynxnpynp2δnrnxnunAxnAp

21−δnsnxnvnBxnBp,

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and by3.27,3.28,3.20, and conditionsi,ii, we have

lim

n→ ∞xnun0. 3.35

By using the same method as3.35, we have

lim

n→ ∞xnvn0. 3.36

Since

znxnδnunxn 1−δnvnxn, 3.37

from3.35,3.36, and conditioni, we have

lim

n→ ∞znxn0. 3.38

By3.20and3.38, we have

lim

n→ ∞ynzn0. 3.39

Since

ynzn 1−αnTznzn, 3.40

from3.39and conditionii, we have

lim

n→ ∞Tznzn0. 3.41

Letωxnbe the set of all weaksω-limit of{xn}. We will show thatωxn ⊂ F. Since{xn} is bounded, then ωxn/∅. Letting qωxn, there exists a subsequence {xni} of {xn}

converging toq. By3.35, we haveuni qasi → ∞. Since un TrnIrnAxn, for any yC, we have

Fun, y

Axn, yun

1

rn

yun, unxn

≥0. 3.42

FromA2, we have

Axn, yun

1

rn

yun, unxn

Fy, un

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This implies that

Axni, yuni

1

rni

yuni, unixni

Fy, uni

. 3.44

Putzt ty 1−tqfor allt∈ 0,1andyC. Then, we haveztC. So, from3.44, we have

ztuni, Aztztuni, Aztztuni, Axni

ztuni,

unixni rni

Fzt, uni

ztuni, AztAuniztuni, AuniAxni

ztuni,

unixni rni

Fzt, uni.

3.45

Sinceunixni → 0, we haveAuniAxni → 0. Further, from monotonicity ofA, we have

ztuni, AztAuni ≥0. So, we have

ztq, Azt

Fzt, q

asi−→ ∞. 3.46

FromA1,A4, and3.46, we also have

0Fzt, zttF

zt, y

1−tFzt, q

tFzt, y

1−tztq, Azt

tFzt, y

1−ttyq, Azt

.

3.47

Thus

0≤Fzt, y

1−tyq, Azt

. 3.48

Lettingt → 0, we have, for eachyC,

0≤Fq, yyq, Aq. 3.49

This implies that

q∈EPF, A. 3.50

From3.36, we havevni q. SincevnTsnIsnBxn, for anyyC, we have

Gvn, y

Bxn, yvn

1

sn

yvn, vnxn

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By using the same method as3.50, we have

q∈EPG, B. 3.52

Sincexni qasi → ∞and 3.38, we havezni qasi → ∞. By Lemma2.3,IT is

demiclosed at zero, and by3.41, we have

qFT. 3.53

From3.50,3.52, and 3.53, we haveq ∈ F. Henceωxn ⊂ F. Therefore, by3.12and Lemma2.6, we have that{xn}converges strongly toPFx1. The proof is completed.

4. Applications

By using our main result, we have the following results in Hilbert spaces.

Theorem 4.1. Let Cbe a nonempty closed convex subset of a Hilbert space H. LetF and G be

bifunctions fromC×C intoRsatisfyingA1–A4, respectively. LetT : CCbe aκ-strict pseudocontraction mapping withFFTEPFEPG/. Let{xn}be a sequence generated

byx1∈CC1and

Fun, u 1

rnuun, unxn ≥0,uC,

Gvn, v 1

snvvn, vnxn

0,vC,

znδnun 1−δnvn,

ynαnzn 1−αnTzn,

Cn1zCn:ynzxnz

,

xn1PCn1x1,n≥1,

4.1

where{αn}∞n0is sequence in0,1,rna, b, andsnc, dsatisfy the following conditions:

ilimn→ ∞δn δ∈0,1,

ii0≤καn<1, for alln≥1.

Thenxnconverges strongly toPFx1.

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Theorem 4.2. LetCbe a nonempty closed convex subset of a Hilbert spaceH. LetFbe bifunctions fromC×CintoRsatisfyingA1–A4, respectively. LetA : CHbe anα-inverse strongly monotone mapping, and let{xn}be a sequence generated byx1∈CC1and

Fun, u Axn, uun 1

rnuun, unxn

0,uC,

ynαnun 1−αnTun,

Cn1zCn:ynzxnz

,

xn1PCn1x1,n≥1,

4.2

where{αn}∞n0is sequence in0,1,rna, b⊂0,2α, and0≤καn<1, for alln≥1. Thenxn

converges strongly toPFx1.

Proof. PuttingGF,AB, andun vn, for alln≥1, in Theorem3.1, we have the desired conclusions.

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