R E S E A R C H
Open Access
Common coupled fixed point theorems for
Geraghty-type contraction mappings using
monotone property
Zoran Kadelburg
1, Poom Kumam
2,3*, Stojan Radenovi´c
4and Wutiphol Sintunavarat
5**Correspondence:
[email protected]; [email protected]; [email protected]
2Department of Mathematics,
Faculty of Science, King Mongkut’s University of Technology Thonburi, 126 Pracha Uthit Road, Bang Mod, Thung Khru, Bangkok, 10140, Thailand
5Department of Mathematics and
Statistics, Faculty of Science and Technology, Thammasat University, Rangsit Center, Pathumthani, 12121, Thailand
Full list of author information is available at the end of the article
Abstract
In this paper, we prove common coupled fixed point theorems under a Geraghty-type condition using monotone instead of the often used mixed monotone property. Also we give some sufficient conditions for the uniqueness of a common coupled fixed point. An example illustrating our results is provided.
MSC: 47H10; 54H25
Keywords: partially ordered metric space; coupled fixed point; mixed monotone property; Geraghty-type condition
1 Introduction
As the Banach contraction principle (BCP) is a power tool for solving many problems in applied mathematics and sciences, it has been improved and extended in many ways. In particular, Geraghty proved in [] an interesting generalization of BCP which has had a lot of applications.
The notion of a coupled fixed point was firstly introduced and studied by Opoitsev [, ] and then by Guo and Lakshmikantham in []. In , Bhaskar and Lakshmikantham [] were the first to introduce the notion of mixed monotone property. They also studied and proved the following classical coupled fixed point theorems for mappings by using this property under contractive type conditions.
Theorem .([]) Let(X,d,)be a partially ordered complete metric space and let F:
X×X→X be a continuous mapping having the mixed monotone property,i.e.,for any x,y∈X,
x,x∈X, xx ⇒ F(x,y)F(x,y)
and
y,y∈X, yy ⇒ F(x,y)F(x,y)
hold.Assume that there exists k∈[, )such that
dF(x,y),F(u,v)≤k
d(x,u) +d(y,v) (.)
holds for all x,y,u,v∈X with xu and yv.If there exist x,y∈X such that
xF(x,y), yF(y,x),
then there exist x,y∈X such that x=F(x,y)and y=F(y,x),i.e.,F has a coupled fixed point.
Theorem .([]) If the continuity assumption for the mapping F is replaced by the as-sumption that the space(X,d,)has the following properties:
. if{xn}is a non-decreasing sequence with{xn} →x,thenxnxfor alln≥, . if{yn}is a non-increasing sequence with{yn} →y,thenynyfor alln≥. Then the same conclusion as in the previous theorem holds.
Due to the important role of Theorems . and . for the investigation of solutions of nonlinear differential and integral equations, several authors have studied various gener-alizations of these results (see,e.g., papers [–] and the references cited therein). Al-most all of them used the mixed monotone property or, in the case of additional mapping
g:X→X, the so-calledg-mixed monotone property.
Recently, in [–], the author established common coupled fixed point theorems by using (g-)monotone property instead of (g-)mixed monotone property. These kinds of results can be applied in another type of situations, so they give an opportunity to widen the field of applications. In particular the so-called tripled fixed point results (and, more generally,n-tupled results) can be more easily handled using monotone property instead of mixed monotone property (see,e.g., [–]).
The aim of this work is to prove some common coupled fixed point theorems for
Geraghty-type contraction mappings by using monotone and g-monotone property
in-stead of mixed monotone and g-mixed monotone property. An illustrative example is
presented in this work showing how our results can be used in proving the existence of a common coupled fixed point, while the results of many other papers cannot.
2 Preliminaries
In this section, we give some definitions that are useful for our main results in this paper. Throughout this paper (X,) denotes a partially ordered set. Byxy, we meanyx. Letf,g:X→Xbe mappings. A mappingf is said to beg-non-decreasing (resp.,g -non-increasing) if, for all x,y∈X,gxgyimplies fxfy(resp., fyfx). Ifg is an identity mapping, thenf is said to be non-decreasing (resp., non-increasing).
Definition . Let (X,) be a partially ordered set and letF:X×X→Xandg:X→X
be two mappings. The mappingFis said to have theg-monotone propertyifFis monotone
g-non-decreasing in both of its arguments, that is, for anyx,y∈X,
x,x∈X, gxgx ⇒ F(x,y)F(x,y)
and
y,y∈X, gygy ⇒ F(x,y)F(x,y)
Definition .([, ]) LetXbe a nonempty set andF:X×X→X,g:X→Xbe two mappings. An element (x,y)∈X×Xis called:
(C) acoupled fixed pointofFifx=F(x,y)andy=F(y,x);
(C) acoupled coincidence pointof mappingsgandFif
gx=F(x,y) and gy=F(y,x),
and in this case(gx,gy)is called acoupled point of coincidence; (C) acommon coupled fixed pointof mappingsgandFif
x=gx=F(x,y) and y=gy=F(y,x).
Definition .([]) Let (X,d) be a metric space and letg:X→X,F:X×X→X. The mappingsgandFare said to becompatibleif
lim n→∞d
gF(xn,yn),F(gxn,gyn)= and lim n→∞d
gF(yn,xn),F(gyn,gxn)=
hold whenever{xn}and{yn}are sequences inXsuch thatlimn→∞F(xn,yn) =limn→∞gxn
andlimn→∞F(yn,xn) =limn→∞gyn.
3 Main results
Letdenote the class of all functionsθ: [,∞)×[,∞)→[, ) which satisfy the follow-ing conditions:
(θ) θ(s,t) =θ(t,s)for alls,t∈[,∞);
(θ) for any two sequences{sn}and{tn}of nonnegative real numbers, θ(sn,tn)→ ⇒ sn,tn→.
The following are examples of some functions belonging to.
() θ(s,t) =kfors,t∈[,∞), wherek∈[, ). () θ(s,t) =ln(+ks+kslt+lt), s> ort> ,
r∈[, ), s= ,t= , wherek,l∈(, ). () θ(s,t) =ln(+maxmax{s,t{s},t}), s> ort> ,
r∈[, ), s= ,t= .
Now, we will prove our main result.
Theorem . Let(X,d,)be a complete partially ordered metric space and let g:X→X and F:X×X→X be such that F has the g-monotone property.Suppose that the following hold:
(i) gis continuous andg(X)is closed;
(ii) F(X×X)⊂g(X)andgandFare compatible;
(iii) there existx,y∈Xsuch thatgxF(x,y)andgyF(y,x);
(iv) there existsθ∈such that for allx,y,u,v∈Xsatisfyinggxguandgygvor
gxguandgygv,
dF(x,y),F(u,v)≤θd(gx,gu),d(gy,gv)maxd(gx,gu),d(gy,gv) (.)
(v) (a)Fis continuous or(b)if,for an increasing sequence{xn}inX,xn→x∈Xas
n→ ∞,thenxnxfor alln∈N.
Then there exist u,v∈X such that gu=F(u,v)and gv=F(v,u),i.e.,g and F have a cou-pled coincidence point.
Proof Starting fromx,y(condition (iii)) and using thatF(X×X)⊂g(X) (condition (ii)),
we can construct sequences{xn}and{yn}inXsuch that
gxn=F(xn–,yn–) and gyn=F(yn–,xn–) forn= , , . . . .
Ifgxn=gxn–andgyn=gyn–for somen∈N, then (gxn–,gyn–) is a coupled point
of coincidence forgandF. Therefore, in what follows, we will assume that for eachn∈N, gxn=gxn–orgyn=gyn–holds.
By (iii),gxF(x,y) =gxandgyF(y,x) =gy, hence theg-monotone property
ofFimplies thatgx=F(x,y)F(x,y) =gxandgy=F(y,x)F(y,x) =gy.
Pro-ceeding by induction we get thatgxn–gxnandgyn–gynhold for eachn∈N. Hence,
the contractive condition (.) can be used to conclude that
d(gxn,gxn+) =d
F(xn–,yn–),F(xn,yn)
≤θd(gxn–,gxn),d(gyn–,gyn)
maxd(gxn–,gxn),d(gyn–,gyn)
(.)
and
d(gyn,gyn+) =d
F(yn–,xn–),F(yn,xn)
≤θd(gyn–,gyn),d(gxn–,gxn)
maxd(gyn–,gyn),d(gxn–,gxn)
=θd(gxn–,gxn),d(gyn–,gyn)
maxd(gxn–,gxn),d(gyn–,gyn)
(.)
for alln∈N. From (.) and (.), we get
maxd(gxn,gxn+),d(gyn,gyn+)
≤θd(gxn–,gxn),d(gyn–,gyn)
maxd(gxn–,gxn),d(gyn–,gyn)
≤maxd(gxn–,gxn),d(gyn–,gyn)
(.)
for alln∈N. Thus the sequencedn:=max{d(gxn–,gxn),d(gyn–,gyn)}is decreasing. It
fol-lows thatdn→dasn→ ∞for somed≥. Next, we claim thatd= .
Assume on the contrary thatd> ; then from (.) we obtain that
max{d(gxn,gxn+),d(gyn,gyn+)}
max{d(gxn–,gxn),d(gyn–,gyn)}≤
θd(gxn–,gxn),d(gyn–,gyn)
< .
On taking limit asn→ ∞, we get
θd(gxn–,gxn),d(gyn–,gyn)
→ asn→ ∞.
Sinceθ∈, we have
asn→ ∞and hence
dn=maxd(gxn–,gxn),d(gyn–,gyn)
→ asn→ ∞, (.)
which contradicts the assumptiond> . Therefore, we can conclude thatdn=max{d(gxn–,
gxn),d(gyn–,gyn)} → asn→ ∞.
Next, we show that{gxn}and{gyn}are Cauchy sequences. On the contrary, assume that
at least one of{gxn}or{gyn}is not a Cauchy sequence. Then there is> for which we
can find subsequences{gxnk},{gxmk}of{gxn}and{gynk},{gymk}of{gyn}withnk>mk≥k such that
maxd(gxnk,gxmk),d(gynk,gymk)≥ (.)
and
maxd(gxnk–,gxmk),d(gynk–,gymk)
<. (.)
Using (.), (.) and the triangle inequality, we have
≤rk:=maxd(gxnk,gxmk),d(gynk,gymk)
≤maxd(gxnk,gxnk–),d(gynk,gynk–)
+maxd(gxnk–,gxmk),d(gynk–,gymk)
<maxd(gxnk,gxnk–),d(gynk,gynk–)
+.
On taking limit ask→ ∞, we have
rk=maxd(gxnk,gxmk),d(gynk,gymk)→. (.)
By the triangle inequality, we get
rk =maxd(gxnk,gxmk),d(gynk,gymk)
≤maxd(gxnk,gxnk+),d(gynk,gynk+)
+maxd(gxnk+,gxmk+),d(gynk+,gymk+)
+maxd(gxmk+,gxmk),d(gymk+,gymk)
=maxd(gxnk,gxnk+),d(gynk,gynk+)
+maxd(gxmk+,gxmk),d(gymk+,gymk)
+maxd(gxnk+,gxmk+),d(gynk+,gymk+)
≤maxd(gxnk,gxnk+),d(gynk,gynk+)
+maxd(gxmk+,gxmk),d(gymk+,gymk)
+θd(gxnk,gxmk),d(gynk,gymk)
maxd(gxnk,gxmk),d(gynk,gymk)
=dnk++dmk++θ
d(gxnk,gxmk),d(gynk,gymk)
rk
≤dnk++dmk++rk
(the usage of contractive condition (.) was possible since the sequences{gxn}and{gyn}
are increasing). Now, we have
rk≤dnk++dmk++θ
d(gxnk,gxmk),d(gynk,gymk)
On taking limit ask→ ∞and using (.) and (.), we get
θd(gxnk,gxmk),d(gynk,gymk)→.
Using the properties of functionθ, we obtain
d(gxnk,gxmk)→ and d(gynk,gymk)→
ask→ ∞, which imply that
lim
k→∞rk=klim→∞
maxd(gxnk,gxmk),d(gynk,gymk)
= ,
which contradicts with> .
Therefore, we get that{gxn}and{gyn}are Cauchy sequences. Sinceg(X) is a closed subset of a complete metric space, there existu,v∈g(X) such that
lim
n→∞gxn=nlim→∞F(xn,yn) =u and nlim→∞gyn=nlim→∞F(yn,xn) =v.
By condition (ii), the compatibility ofgandFimplies that
lim n→∞d
gF(xn,yn),F(gxn,gyn)= and lim n→∞d
gF(yn,xn),F(gyn,gxn)= . (.)
Consider the two possibilities given in condition (v).
(a) Suppose thatFis continuous. Using the triangle inequality we get that
dgu,F(gxn,gyn)
≤dgu,gF(xn,yn)
+dgF(xn,yn),F(gxn,gyn)
.
Passing to the limit asn→ ∞and using (.) and the continuity ofgandF, we get that
d(gu,F(u,v)) = ,i.e.,gu=F(u,v). In a similar way,gv=F(v,u) is obtained.
(b) In this casegxnu=gxandgynv=gyfor somex,y∈Xand eachn∈N. Using
(.) we get
dF(x,y),gx≤dF(x,y),gxn+
+d(gxn+,gx)
=dF(x,y),F(xn,yn)
+d(gxn+,gx)
≤θd(gx,gxn),d(gy,gyn)
maxd(gx,gxn),d(gy,gyn)
+d(gxn+,gx)
→
asn→ ∞. Hence,gx=F(x,y) and similarlygy=F(y,x).
Note that in this case continuity and compatibility assumptions were not needed in the
proof.
Puttingg =IX, whereIX is an identity mapping onX in Theorem ., we obtain the following.
Corollary . Let(X,d,)be a partially ordered complete metric space and let F:X× X→X have the monotone property.Suppose that the following hold:
(i) there existx,y∈Xsuch thatxF(x,y)andyF(y,x);
(ii) there existsθ∈such that for allx,y,u,v∈Xsatisfying(xuandyv)or(ux
andvy),
dF(x,y),F(u,v)≤θd(x,u),d(y,v)maxd(x,u),d(y,v)
holds true;
(iii) (a)Fis continuous or(b)if{xn}is an increasing sequence inXandxn→xas
n→ ∞,thenxnxfor alln.
Then there exist x,y∈X such that x=F(x,y)and y=F(y,x),i.e.,F has a coupled fixed point.
Takingθ(t,t) =kwithk∈[, ) for allt,t∈[,∞) in Theorem . and Corollary .,
we obtain the following corollary.
Corollary . Let(X,d,)be a complete partially ordered metric space and let g:X→X and F:X×X→X be such that F has the g-monotone property.Suppose that the following hold:
(i) gis continuous andg(X)is closed;
(ii) F(X×X)⊂g(X)andgandFare compatible;
(iii) there existx,y∈Xsuch thatgxF(x,y)andgyF(y,x);
(iv) there existsk∈[, )such that for allx,y,u,v∈Xsatisfying(gxguandgygv)or
(gugxandgvgy),
dF(x,y),F(u,v)≤kmaxd(gx,gu),d(gy,gv) (.)
holds true;
(v) (a)Fis continuous or(b)if{xn}is an increasing sequence inXandxn→xas
n→ ∞,thenxnxfor alln.
Then there exist u,v∈X such that gu=F(u,v)and gv=F(v,u),i.e.,g and F have a coupled coincidence point.
Corollary . Let(X,d,)be a partially ordered complete metric space and let F:X× X→X.Suppose that the following hold:
(i) Fsatisfies the monotone property;
(ii) there existx,y∈Xsuch thatxF(x,y)andyF(y,x);
(iii) there existsk∈[, )such that for allx,y,u,v∈Xsatisfying(xuandyv)or
(uxandvy),
dF(x,y),F(u,v)≤kmaxd(x,u),d(y,v)
(iv) (a)Fis continuous or(b)if{xn}is an increasing sequence inXandxn→xas
n→ ∞,thenxnxfor alln.
Then there exist x,y∈X such that x=F(x,y)and y=F(y,x),i.e.,F has a coupled fixed point.
Remark . Since, fork,l≥,k+l≤,
kd(gx,gu) +ld(gy,gv)≤maxd(gx,gu),d(gy,gv),
Corollary . remains valid if the right-hand side of condition (.) is replaced bykd(gx,
gu) +ld(gy,gv) for somek,l≥,k+l< .
Now, reasoning on Theorem ., some questions arise naturally. To be precise, one can ask the following.
Question Is it possible to find a sufficient condition for the existence and uniqueness of the coupled common fixed point ofgandF?
Motivated by the interest in this research, we give a positive answer to this question adding to Theorem . some hypotheses.
For the given partial orderon the setX, we shall denote also bythe order onX×X
given by
(x,y)(x,y) ⇔ xx and yy.
Theorem . In addition to the hypotheses of Theorem.assume that
(vi) for any two elements(x,y), (u,v)∈X×X,there exists(w,z)∈X×Xsuch that (F(w,z),F(z,w))is comparable to both(F(x,y),F(y,x))and(F(u,v),F(v,u)).
Then g and F have a unique common coupled fixed point,i.e.,there exists unique(p,q)∈
X×X such that p=gp=F(p,q)and q=gq=F(q,p).
Proof Theorem . implies that there exists a coupled coincidence point (x,y)∈X×X, that is,gx=F(x,y) andgy=F(y,x). Suppose that there exists another coupled coincidence point (u,v)∈X×Xand hencegu=F(u,v) andgv=F(v,u). We will prove thatgx=guand
gy=gv.
From condition (vi) we get that there exists (w,z)∈X×Xsuch that (F(w,z),F(z,w)) is comparable to both (F(x,y),F(y,x)) and (F(u,v),F(v,u)). Putw=w,z=zand,
analo-gously to the proof of Theorem ., choose sequences{wn},{zn}inXsatisfying
gwn=F(wn–,zn–) and gzn=F(zn–,wn–)
forn∈N. Starting fromx=x, y=yandu=u, v=v, choose sequences {xn},{yn}
and{un},{vn}satisfyinggxn=F(xn–,yn–),gyn=F(yn–,xn–) andgun=F(un–,vn–),gvn= F(vn–,un–) forn∈N. Taking into account the properties of coincidence points, it is easy
to see that it can be done so thatxn=x,yn=yandun=u,vn=v,i.e.,
Since (F(x,y),F(y,x)) = (gx,gy) and (F(w,z),F(z,v)) = (gw,gz) are comparable, then, for
example,gxgw,gygzand in a similar way,gxgwn,gygzn. Thus, we can apply
the contractive condition (.) to obtain
d(gx,gwn+) =d
F(x,y),F(wn,zn)
≤θd(gx,gwn),d(gy,gzn)maxd(gx,gwn),d(gy,gzn)
and
d(gy,gzn+) =d
F(zn,wn),F(y,x)
≤θd(gy,gzn),d(gx,gwn)maxd(gy,gzn),d(gx,gwn)
=θd(gx,gwn),d(gy,gzn)maxd(gx,gwn),d(gy,gzn).
This implies that
maxd(gx,gwn+),d(gy,gzn+)
≤θd(gx,gwn),d(gy,gzn)maxd(gx,gwn),d(gy,gzn)
<maxd(gx,gwn),d(gy,gzn). (.)
Therefore, we get that the sequence dn:=max{d(gx,gwn),d(gy,gzn)} is decreasing and hencedn→dasn→ ∞for somed≥. Now, we prove thatd= . Assume to the contrary thatd> ; then from (.) we have
max{d(gx,gwn+),d(gy,gzn+)}
max{d(gx,gwn),d(gy,gzn)} ≤θ
d(gx,gwn),d(gy,gzn)< .
Taking the limit asn→ ∞in the above inequality, we have
θd(gx,gwn),d(gy,gzn)
→ asn→ ∞.
By the property (θ) ofθ∈, we get
d(gx,gwn)→ and d(gy,gzn)→
asn→ ∞. Now we have
dn:=maxd(gx,gwn),d(gy,gzn)→ asn→ ∞,
which contradicts with d> . Therefore, we conclude that dn=max{d(gx,gwn),d(gy,
gzn)} → asn→ ∞and then
lim
n→∞d(gx,gwn) = and nlim→∞d(gy,gzn) = .
In a similar way, we have
lim
By the triangle inequality, we have
d(gx,gu)≤d(gx,gwn) +d(gwn,gu) and d(gy,gv)≤d(gy,gzn) +d(gzn,gv)
for alln∈N. Takingn→ ∞in the above two inequalities, we get thatd(gx,gu) = and
d(gy,gv) = . Therefore, we havegx=guandgy=gv. Now we letp:=gxandq:=gy. Hence we have
gp=g(gx) =gF(x,y) and gq=g(gy) =gF(y,x).
By the definition of sequences{xn}and{yn}we have
gxn=F(x,y) =F(xn–,yn–) and gyn=F(y,x) =F(yn–,xn–)
for alln∈N. So we have
lim
n→∞F(xn,yn) =nlim→∞gxn=F(x,y) and nlim→∞F(yn,xn) =nlim→∞gyn=F(y,x).
SincegandFare compatible, we have
lim n→∞d
gF(xn,yn),F(gxn,gyn)= ,
that is,gF(x,y) =F(gx,gy). Therefore, we get
gp=gF(x,y) =F(gx,gy) =F(p,q)
and in a similar way
gq=gF(y,x) =F(gy,gx) =F(q,p).
This implies that (p,q) is another coincidence point. By the property we have just proved, it follows thatgp=gx=pandgq=gy=q. So,
p=gp=F(p,q) and q=gq=F(q,p),
and (p,q) is a common coupled fixed point ofgandF. For the uniqueness of the common
coupled fixed point, we can proceed easily.
Corollary . In addition to the hypotheses of Corollary.assume that
(vi) for any two elements(x,y), (u,v)∈X×X,there exists(w,z)∈X×Xsuch that (F(w,z),F(z,w))is comparable to both(F(x,y),F(y,x))and(F(u,v),F(v,u)). Then g and F have a unique common coupled fixed point.
Theorem . In addition to the hypotheses of Corollary.,let the condition(vi)of Theo-rem.be satisfied.Then the coupled fixed point of F is unique.Moreover,if for the terms of sequences{xn},{yn}defined by xn=F(xn–,yn–)and yn=F(xn–,yn–),xnynholds for
Proof We have only to prove the last statement. Suppose that forn sufficiently large,
xnyn. Then, by (.) (withg=IX), we get
d(xn+,yn+) =d
F(xn,yn),F(yn,xn)
≤θd(xn,yn),d(xn,yn)d(xn,yn). (.)
This implies that
d(xn+,yn+) <d(xn,yn),
that is, the sequencedn:=d(xn,yn) is decreasing. Hencedn→dasn→ ∞for somed≥.
Next, we prove thatd= . Assume to the contrary thatd> ; then from (.) we have
d(xn+,yn+)
d(xn,yn)
≤θd(xn,yn),d(xn,yn)< .
Lettingn→ ∞, we getθ(d(xn,yn),d(xn,yn))→. Sinceθ∈, we haved(xn,yn)→ as n→ ∞, which contradicts withd> . Therefore, we haved(xn,yn)→ asn→ ∞.
By the triangle inequality, we have
d(x,y)≤d(x,xn+) +d(xn+,yn+) +d(yn+,y)
=d(x,xn+) +d
F(xn,yn),F(yn,xn)+d(yn+,y)
≤d(x,xn+) +θ
d(xn,yn),d(xn,yn)d(xn,yn) +d(yn+,y)
<d(x,xn+) +d(xn,yn) +d(yn+,y).
Passing to the limit asn→ ∞, sincexn→x,yn→yandd(xn,yn)→, we get thatd(x,y)≤
and thusx=y. This completes the proof.
Corollary . In addition to the hypotheses of Corollary.,let the condition(vi)of The-orem.be satisfied.Then the coupled fixed point of F is unique.Moreover,if for the terms of sequences{xn},{yn}defined by xn=F(xn–,yn–)and yn=F(xn–,yn–),xnynholds for
all n,then the coupled fixed point of F has the form(x,x).
Finally, we give an example showing that our theorem can be used when many results in this field cannot.
Example . LetX= [, ]⊆Rwith the usual metric and order. Consider the mappings
g:X→XandF:X×X→Xdefined by
gx=x, F(x,y) =ln
+x
+
y
.
Note thatFdoes not satisfy the mixedg-monotone property of [] and []. Indeed, for
y=∈Xandy=∈X, we havegygy. But forx= ∈X, we get
F(x,y) =ln
ln
Hence a lot of results in literature that used theg-mixed monotone property cannot be applied in this example. Moreover,gandFdo not commute as in [].
Next, we show that Theorem . can be used in this example.
Letθ∈be defined by
θ(s,t) = ⎧ ⎨ ⎩
ln(+s+t)
s
+t , s> ort> ,
, s= andt= .
We will show that condition (.) holds with the functionθ. Letx,y,u,vbe arbitrary points inX. We obtain that
dF(x,y),F(u,v)=d
ln
+x
+
y
,ln
+u
+
v
=ln
+x
+
y
–ln
+u
+
v
=ln + x
+
y
+u
+
v
=ln
+( x + y ) – ( u + v )
+u +v ≤ln + x + y – u + v ≤ln +
x
–u+
y
–v
=ln( +
|x–u|+
|y–v|)
(|x–u|+
|y–v|)
x
–u+
y
–v
=ln( +
d(gx,gu) +
d(gy,gv))
(d(gx,gu) +d(gy,gv))
d(gx,gu) +
d(gy,gv)
=θd(gx,gu),d(gy,gv)
d(gx,gu) +
d(gy,gv)
≤θd(gx,gu),d(gy,gv)maxd(gx,gu),d(gy,gv).
This shows that condition (.) holds with the functionθ.
Next, we check thatg andFare compatible. Let{xn}and{yn}be two sequences inX
such that
lim
n→∞gxn=nlim→∞F(xn,yn) =a and nlim→∞gyn=nlim→∞F(yn,xn) =b.
Thenln( +a+b) =aandln( +a+b) =b, wherefrom it follows thata=b= . Then
dgF(xn,yn),F(gxn,gyn)=
ln
+x
n + y n –ln +x
n
+
y
n
→ (n→ ∞),
We can easily check that all other conditions of Theorem . hold. Therefore,g and
F have a unique common coupled fixed point. In this example, we can see that a point (, )∈X×Xis a unique common coupled fixed point ofgandF.
Remark . We conclude remarking that the approach used in this paper (i.e., using
g-monotone instead ofg-mixed monotone mappings) has the advantage when considering
n-tupled common fixed points for oddn. For example, one can consider mappings F:
X→Xandg:X→Xand say that the mappingFisg-monotone ifF(x,y,z) isg
-non-decreasing in all three variables, that is, for allx,y,z∈X,
x,x∈X, g(x)g(x) ⇒ F(x,y,z)F(x,y,z),
y,y∈X, g(y)g(y) ⇒ F(x,y,z)F(x,y,z),
z,z∈X, g(z)g(z) ⇒ F(x,y,z)F(x,y,z).
In particular, ifg=IX,Fis said to be monotone. An element (x,y,z)∈Xis called a tripled
coincidence point ofFandg ifF(x,y,z) =gx,F(y,z,x) =gyandF(z,x,y) =gz. Moreover, (x,y,z) is called a tripled common fixed point ofFandgif
F(x,y,z) =gx=x, F(y,z,x) =gy=y and F(z,x,y) =gz=z.
In particular, forg=IX, the element (x,y,z) is called a tripled fixed point ofF.
Results concerning these notions can be found,e.g., in []. Such an approach is not possible for mixed monotone mappings whenn= (see []).
Open problems
• In Theorem ., can the set{d(gx,gu),d(gy,gv)}be replaced by other sets?
• Can Theorem . be improved by replacing the control functionθby other functions? • Can Theorem . be extended and generalized replacing condition(.)by other
conditions?
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
The main idea of this paper was proposed by ZK, PK, SR and WS prepared the manuscript initially and performed all the steps of the proofs in this research. All authors read and approved the final manuscript.
Author details
1Faculty of Mathematics, University of Belgrade, Beograd, 11000, Serbia.2Department of Mathematics, Faculty of Science,
King Mongkut’s University of Technology Thonburi, 126 Pracha Uthit Road, Bang Mod, Thung Khru, Bangkok, 10140, Thailand.3Theoretical and Computational Science Center (TaCS), Science Laboratory Building, Faculty of Science, King
Mongkut’s University of Technology Thonburi (KMUTT), 126 Pracha Uthit Road, Bang Mod, Thung Khru, Bangkok, 10140, Thailand.4Faculty of Mathematics and Information Technology, Teacher Education, Dong Thap University, Cao Lanh City,
Dong Thap Province, Vietnam. 5Department of Mathematics and Statistics, Faculty of Science and Technology,
Thammasat University, Rangsit Center, Pathumthani, 12121, Thailand.
Acknowledgements
The first author is thankful to the Ministry of Education, Science and Technological Development of Serbia, Project No. 174002. The second author was supported by the Higher Education Research Promotion and National Research University Project of Thailand, Office of the Higher Education Commission (NRU) and Theoretical and Computational Science Center (TaCS). The fourth author would like to thank the Thailand Research Fund and Thammasat University under Grant No. TRG5780013 for financial support during the preparation of this manuscript.
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