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Math 3 Sem 1 Review

Multiple Choice

Identify the choice that best completes the statement or answers the question.

____ 1. Four bowls with the same height are constructed using quadratic equations as their shapes. Which bowl has the narrowest opening?

A Bowl 1:18x2 C Bowl 3:5x2

B Bowl 2:1 4x

2 D Bowl 4:7x2

____ 2. Which function is NOT a translation of f x  x217?

A f x   x4217 C f x   x217

B f x  x24

D f x  x 12

  

  

2

____ 3. Which is the average rate of change over the interval [0, 4]?

Equation A

Equation B f(x)2x1

A A: 4, B: 2 C A: 8, B: 16

B A: 4, B: 4 D A: 8, B: 4

____ 4. Which is the average rate of change over the interval [2,3]?

Equation A

Equation B f(x) x2

A A: 7, B: 1 C A: 3, B:1

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Name: ________________________ ID: A

____ 5. The table shows the height of a sassafras tree at each of two ages. What was the tree’s average rate of growth during this time period?

Age (years) Height (meters)

4 2

10 5

A 0.4 meter per year B 0.5 meter per year C 2 meters per year D 2.5 meters per year

____ 6. The graph shows the height h, in feet, of a football at time t, in seconds, from the moment it was kicked at ground level. Estimate the average rate of change in height from t1.5 seconds to t1.75 seconds.

A 20 feet per second B 12 feet per second C 12 feet per second D 20 feet per second

____ 7. On which of the following intervals is the average rate of change of the function f x  x34x the greatest?

A From x  3 to x  1 B From x  1 to x 1 C From x 1 to x 3 D From x 3 to x 5

____ 8. The table shows the sizes of an artist’s paintings and the price of each painting. Painting Size (in.2) 48 64 144 48 100

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____ 9. Without using graphing technology, sketch the parent graph and translate it to obtain a graph of y4 x5.

A C

B D

____ 10. Solve (13x7)2= 110.

A 7 110

26 ,

7 110

26 C

7 110

13 ,

7 110

13

B 7 110

13 ,

7 110

13 D

7 110

26 ,

7 110 26

____ 11. What are the solutions of the equation x2 232x?

A x  12 6 C x 1 22

B x 12 6 D x1 22

____ 12. Which of the following is equivalent to 121?

A 11 B 11 C 11i D 121i

____ 13. The graph of which equation would be a circle with a center at (9, 9) and a radius of 13? A x92y92 13 C x92y92 169

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Name: ________________________ ID: A

____ 14. Which is the equation of a circle that has a diameter with endpoints 1,3 and 3,1?

A x12y22 10 C x12y22 5

B x12y22 20 D x12y22 5

____ 15. Solve the system. y x25x4 y 8x8

    

A (4, 0), (1, 16) C (1, 0), (4, 40) B (1, 0), (4, 0) D (1, 16), (4, 40)

____ 16. Which ordered pair is a solution of the system formed by the equations below? 2x212xy2540

y3x5

A (0, 5) C (1, 8)

B (0, 54) D (1, 8)

____ 17. What is the distance between the points of intersection of the graphs of y x2 and y 6x?

A 26

B 5 2

C 2 37

D 170

____ 18. How many times do the graphs of y  x25x6 and 2xy16 intersect?

A 0

B 1

C 2

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____ 19. Which is the graph of the polynomial function p x  x1x1x4?

A C

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Name: ________________________ ID: A

____ 20. Which of the following polynomial functions could have the graph shown?

A p(x)(x1)(x2)(x5) B p(x)(x1)2(x2)(x5) C p(x)(x1)(x2)(x5) D p(x)(x1)2(x2)(x5)

____ 21. Which of the following is a true statement about the graph of p(x) x4x23x26x

 ?

A The graph crosses the x-axis four times and is never tangent to the x-axis. B The graph crosses the x-axis three times and is never tangent to the x-axis. C The graph crosses the x-axis two times and is tangent to the x-axis once. D The graph crosses the x-axis three times and is tangent to the x-axis once.

____ 22. Multiply (2x)(2x).

A 4x2 C 44xx2

B 42x D 44xx2

____ 23. Subtract. x32x3

 

  – 3x2 4x3

 

A 2x36x6 C x33x22x

B x33x26x6 D x33x26x6

____ 24. Find the product. x22x3

 

 3x24x1

 

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____ 25. Which expression represents the perimeter of the triangle below?

A 34m C 5  4m

B 3  6m D 5  6m

____ 26. A farmer has kept careful track of his orange grove’s output over the years. The number of oranges produced can be modeled by the polynomial t2100t200. The average weight of the oranges over this same time can be modeled by the polynomial 0.0001t20.02t0.5. Which polynomial below models the total weight of oranges produced by this grove?

A 0.0001t40.02t30.5t24t50 C 0.0001t40.03t31.48t254t100 B 0.0001t40.01t31.98t24t50 D 0.0001t40.02t31.50t24t100

____ 27. Carlita has a rectangular swimming pool in her back yard that has a length of 24 feet and a width of 12 feet. She wants to install a concrete walkway of width c around the pool. Surrounding the walkway, she wants to have a wood deck that extends w feet on all sides. Find an expression for the perimeter of the wood deck.

A 36 + 4c + 4w C 72 + 8c + 8w

B 64 + 8c + 8w D 288 + 6c + 2w

____ 28. A rectangular garden has a length of 5a + 17 feet and a width of 4a feet. Which expression represents the area of the garden in square feet?

A 20a + 68 C 20a2 + 17

B 20a2 + 68a D 25a2 + 64a

____ 29. Write an equivalent expression for x22xyy2.

A (xy)2 C (xy)(xy)

B (xy)2 D x2y2

____ 30. Write an equivalent expression for (xy)(xy).

A x2 2xyy2 C (xy)2

B x2 2xyy2 D x2y2

____ 31. Completely factor 3x415x318x2. A x2 3x 22

 1x9 C 3x2x1x6

B 3x21

 x26

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ID: A

Math 3 Sem 1 Review

Answer Section

MULTIPLE CHOICE

1. ANS: D PTS: 1 DIF: DOK 1 NAT: F-BF.B.3

STA: F-BF.3

2. ANS: C PTS: 1 DIF: DOK 1 NAT: F-BF.B.3

STA: F-BF.3

3. ANS: A PTS: 1 DIF: DOK 2 NAT: F-IF.B.6

STA: F-IF.6

4. ANS: B PTS: 1 DIF: DOK 2 NAT: F-IF.B.6

STA: F-IF.6 5. ANS: B

average rate of growth change in heightchange in age10524  36 0.5 meter per year

Feedback

A You need to find the rate of change in height to change in age. B That’s correct!

C You found the rate of change in age to change in height. You need to find the rate of change in height to change in age.

D You need to find the rate of change in height to change in age.

PTS: 1 DIF: DOK 1 NAT: F-IF.B.6* | MP.4

STA: F-IF.6* | MP.4 KEY: average rate of change from a table | modeling NOT: Data taken from height-versus-age graph of sassafras tree number 2 at

http://www.yale.edu/fes519b/totoket/allom/allom.htm 6. ANS: A

average rate of change h1.751.75h1.51.5  70.2512  0.255  20 feet per second

Feedback A That’s correct!

B You found the average rate of change from t1.25 seconds to t1.5 seconds. C You found the average rate of change from t0.5 seconds to t0.75 seconds.

D Remember to subtract the values associated with t1.5 from the values associated with

t1.75.

PTS: 1 DIF: DOK 2 NAT: F-IF.B.6* | MP.4

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7. ANS: D

From x 3 to x 1: average rate of change f(11) f 33

  

3  15

2 

18 2 9

From x 1 to x1: average rate of change f(1)1 f 11

  

3 3

2 

6 2  3

From x1 to x3: average rate of change f(3)3f1 1  15 2 3  182 9

From x3 to x5: average rate of change f(5)5f3 3  105215  902 45

So, the average rate of change is greatest on the interval from x 3 to x 5.

Feedback

A Compare the average rate of change on this interval with the average rate of change on

an interval even farther from 0.

B Compare the average rate of change on this interval with the average rate of change on

an interval far from 0.

C Compare the average rate of change on this interval with the average rate of change on

an interval even farther from 0.

D That’s correct!

PTS: 1 DIF: DOK 1 NAT: F-IF.B.6* STA: F-IF.6* KEY: average rate of change from a function rule | polynomial functions

8. ANS: A PTS: 1 DIF: DOK 2 NAT: S-ID.B.6

STA: S-ID.6

9. ANS: B PTS: 1 DIF: Level B REF: MAL20308

TOP: Lesson 2.7 Use Absolute Value Functions and Transformations

KEY: translate | graph | absolute value | equation | parent MSC: Comprehension NOT: 978-0-618-65615-8

10. ANS: B PTS: 1 DIF: DOK 2 NAT: A-REI.B.4a

STA: A-REI.4a TOP: Complete the Square KEY: square | solve | complex | quadratic

11. ANS: B PTS: 1 DIF: DOK 2 NAT: A-REI.B.4b

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ID: A

12. ANS: C

121  (121)(1)  121 1 11i

Feedback

A Factor 121 as 121(1) and then apply the rule ab  a  b.

B That’s correct!

C Factor 121 as 121(1) and then apply the rule ab  a  b. D Factor 121 as 121(1) and then apply the rule ab  a  b.

PTS: 1 DIF: DOK 1 NAT: N-CN.A.1 STA: N-CN.1

KEY: imaginary numbers

13. ANS: C PTS: 1 DIF: DOK 1 NAT: G-GPE.A.1

STA: G-GPE.1

14. ANS: C PTS: 1 DIF: DOK 2 NAT: G-GPE.A.1

STA: G-GPE.1

15. ANS: C PTS: 1 DIF: DOK 1 NAT: A-REI.C.7

STA: A-REI.7

16. ANS: D PTS: 1 DIF: DOK 1 NAT: A-REI.C.7

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17. ANS: B

To find the points of intersection, set the expressions x2 and 6x equal to each other and solve for x.

x2 6x x2x60 x3

 x20 x  3 or 2

Substitute each x-value into one of the equations and solve for y.

y 6  3

63

9

y 62

4

The points of intersection are 2, 4 and 3, 9. Now use the distance formula,

D x2x1 2

y2y1 2

.

D 322942

  5 252

 50

5 2

Feedback

A It seems you added the x-coordinates instead of subtracting them in the distance

formula.

B That’s correct!

C Remember that the distance formula uses the differences between the x-values and the

y-values, not the difference between each x-value and its corresponding y-value.

D Remember that the pairs of coordinates are subtracted in the distance formula, not

added.

(12)

ID: A

18. ANS: C

Solve 2xy 16 for y. 2xy 16

y  2x16

Substitute 2x16 for y in y x25x6.

2x16 x25x6 0 x27x10

  x5x2

x 2 or 5

There are two distinct solutions, so there are two points of intersection.

Feedback

A The parabola and the line have at least one point of intersection.

B Find the number of solutions by solving the system of equations. C That’s correct!

D A parabola and a line cannot have three points of intersection.

(13)

19. ANS: B

The zeros of the function are x 1, x1, and x4, and these are the x-intercepts of the function’s graph. The result of expanding x1x1x4 is x34x2 x4. The leading term, x3, has a positive coefficient and an odd exponent, so p x  approaches  as x approaches , and p x  approaches  as x approaches . Of the four given graphs, only the one shown below has these characteristics.

Feedback

A Check the zeros of p x .

B That’s correct!

C Check the end behavior of p x .

D Check the zeros and end behavior of p x .

PTS: 1 DIF: DOK 1 NAT: F-IF.C.7c* STA: F-IF.7c* KEY: graphs of polynomial functions | zeros | end behavior

20. ANS: D

The function p(x)(x1)2(x2)(x5) has 3 zeros, 1, 2, and 5. Since x1 is a factor twice, 1 is a zero twice, so the function’s graph would be tangent to the x-axis at x 1. Since x2 and x5 are factors once, 2 and 5 are zeros once, so the function’s graph would cross the x-axis at x2 and x 5.

Feedback

A Make sure you have identified the zeros of the function correctly.

B Make sure you have identified the zeros of the function correctly.

C This function is cubic, so its end behavior will not be the same at both ends of the graph.

D That’s correct!

(14)

ID: A

21. ANS: C

The number of unique real zeros that a polynomial function has is equal to the number of times the graph of the function intersects the x-axis.

p(x) x4x23x26x

  3x x 4x2x2

This function has 3 unique real zeros, 0, 4, and 2, so the graph intersects the x-axis three times. Since two of those zeros, 0 and 4, each occur once, the graph crosses the x-axis at x 0 and x 4. Since one of those zeros, 2, occurs twice, the graph is tangent to the x-axis at x 2.

Feedback

A Identify all of the zeros of the function and how many times each zero occurs. B Identify all of the zeros of the function and how many times each zero occurs.

C That’s correct!

D Identify all of the zeros of the function and how many times each zero occurs.

PTS: 1 DIF: DOK 1 NAT: A-APR.B.3 STA: A-APR.3 KEY: zeros of polynomial functions | graphs of polynomial functions

22. ANS: A PTS: 1 DIF: DOK 1 NAT: A-APR.A.1

STA: A-APR.1

23. ANS: D PTS: 1 DIF: DOK 1 NAT: A-APR.A.1

STA: A-APR.1

24. ANS: A PTS: 1 DIF: DOK 1 NAT: A-APR.A.1

STA: A-APR.1

25. ANS: A PTS: 1 DIF: DOK 2 NAT: A-APR.A.1

STA: A-APR.1

26. ANS: C PTS: 1 DIF: DOK 2 NAT: A-APR.A.1

STA: A-APR.1

27. ANS: C PTS: 1 DIF: DOK 2 OBJ: Application

NAT: A-APR.A.1 STA: A-APR.1

LOC: MTH.C.10.05.08.004 | MTH.C.12.11.02.002 | MTH.C.10.05.08.03.001 TOP: Adding Polynomials KEY: polynomial | addition

28. ANS: B PTS: 1 DIF: DOK 2 NAT: A-APR.A.1

STA: A-APR.1

LOC: MTH.C.10.05.08.03.02.002 | MTH.C.10.05.08.004 | MTH.C.10.02.03.002 | MTH.C.12.12.02.002 TOP: Multiplying Polynomials by Monomials

KEY: polynomial | monomial | multiplication

29. ANS: A PTS: 1 DIF: DOK 1 NAT: A-APR.C.4

STA: A-APR.4 KEY: polynomial identities

30. ANS: D PTS: 1 DIF: DOK 1 NAT: A-APR.C.4

STA: A-APR.4 KEY: polynomial identities

31. ANS: C PTS: 1 DIF: DOK 1 NAT: A-SSE.A.2

References

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