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Self adaptive subgradient extragradient method with inertial modification for solving monotone variational inequality problems and quasi nonexpansive fixed point problems

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R E S E A R C H

Open Access

Self-adaptive subgradient extragradient

method with inertial modification for solving

monotone variational inequality problems

and quasi-nonexpansive fixed point problems

Ming Tian

1*

and Mengying Tong

1

*Correspondence: [email protected] 1College of Science, Civil Aviation

University of China, Tianjin, China

Abstract

In this paper, we introduce a new algorithm with self-adaptive method for finding a solution of the variational inequality problem involving monotone operator and the fixed point problem of a quasi-nonexpansive mapping with a demiclosedness property in a real Hilbert space. The algorithm is based on the subgradient

extragradient method and inertial method. At the same time, it can be considered as an improvement of the inertial extragradient method over each computational step which was previously known. The weak convergence of the algorithm is studied under standard assumptions. It is worth emphasizing that the algorithm that we propose does not require one to know the Lipschitz constant of the operator. Finally, we provide some numerical experiments to verify the effectiveness and advantage of the proposed algorithm.

Keywords: Variational inequality problem; Fixed point problem; Extragradient method; Subgradient extragradient method; Inertial method; Self-adaptive method

1 Introduction

Throughout this paper, letHbe a real Hilbert space with the inner product·,·and norm · . LetCbe a nonempty, closed and convex subset ofH. LetNandRbe the sets of positive integers and real numbers, respectively.

The variational inequality problem (VIP) is the problem to find a pointx∗∈Csuch that

Ax∗,xx∗≥0, ∀xC. (1)

The solution set of VIP is denoted byVI(C,A). The variational inequality problem is an important branch of the nonlinear problem and it has received a lot of attentions by many authors in recent years (see [1–3] and the references therein). Under appropriate condi-tions, there are two general approaches for solving the variational inequality problem, one is the regularized method and the other is the projection method. Now, we mainly study the projection method.

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For every pointxH, there exists a unique point inCsuch that

xPCx=infxy:yC,

wherePC:HCis called the metric projection fromHintoC.

We know that the variational inequality problem can be turned into the fixed point prob-lem, which means (1) is equivalent to

x∗=PC(IλA)x∗, (2)

wherePC:HCis the metric projection andλ> 0. Thus we generate{xn}in the follow-ing manner:

xn+1=PC(IλA)xn. (3)

This simple algorithm is an extension of the projection gradient method. However, the convergence of this method requires a slight assumption that the operatorA:HHis strongly monotone or inverse strongly monotone.

To avoid this strong assumption, Korpelevich [4] proposed an algorithm which was called the extragradient method:

⎧ ⎨ ⎩

yn=PC(xnλAxn),

xn+1=PC(xnλAyn),

(4)

for eachn= 1, 2, . . . , whereλ∈(0, 1/L). At the beginning, this method was used to solve saddle point problems. Soon, this method was extended to Euclidean spaces and Hilbert spaces. In particular, this method only requires that the operatorAis monotone andL -Lipschitz continuous in a Hilbert space. IfVI(C,A)=∅, the sequence{xn}generated by

(4) converges weakly to an element ofVI(C,A).

However, the extragradient method needs to calculate two projections fromHonto the closed convex setCand it is applicable to the case thatPChas a closed form which means thatPChas an explicit expression. In fact, in some cases, the projection onto the nonempty closed convex subsetCmight be difficult to calculate. To overcome this drawback, it has received great attentions by many authors who had improved it in various ways.

To our knowledge, there were four kinds of methods to overcome this drawback. The first one was the modification of the extragradient method by Tseng [5] who proposed it in 2000 with the following remarkable scheme:

⎧ ⎨ ⎩

yn=PC(xnλAxn),

xn+1=ynλ(AynAxn),

(5)

(3)

2011: ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩

yn=PC(xnλAxn),

Tn={wH| xnλAxnyn,wyn ≤0},

xn+1=PTn(xnλAyn),

(6)

whereAis monotone,L-Lipschitz continuous andλ∈(0, 1/L). The key operation of the subgradient extragradient method replaces the second projection ontoCof the extragra-dient method by a projection onto a special constructible half-space, which significantly reduces the difficulty of calculations.

Before explaining the third method, let us take a look at the inertial method. In 2001, Al-varez and Attouch [7] applied the inertial technique to obtain an inertial proximal method to solve the problem of finding zero of a maximal monotone operator, which works as fol-lows:

findxn+1∈H, such that 0∈λnA(xn+1) +xn+1–xnθn(xnxn–1),

wherexn–1,xnH,θn∈[0, 1) andλn> 0. It also can be written in the following form:

xn+1=JλAn

xn+θn(xnxn–1)

, (7)

where JA

λn is the resolvent ofA with parameter λn and the inertia is induced by the

termθn(xnxn–1). Recently, considerable interest has been shown in studying the

iner-tial method by many authors. They constructed fast iterative algorithms by using ineriner-tial method. The third method which was studied by Q.L. Dong et al. [8] in 2017:

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

wn=xn+αn(xnxn–1),

yn=PC(wnλAwn),

d(wn,yn) = (wnyn) –λ(AwnAyn),

xn+1=wnγ βnd(wn,yn),

(8)

for eachk≥1, whereγ ∈(0, 2),λ> 0,

βn:= ⎧ ⎨ ⎩

ϕ(wn,yn)/d(wn,yn)2, ifd(wn,yn)= 0,

0, ifd(wn,yn) = 0,

ϕ(wn,yn) =wnyn,d(wn,yn).

This algorithm incorporate the inertial terms in the projection and contraction algorithm, which does not need the summability condition for the sequence. The fourth one was a self-adaptive algorithm which was based on Tseng’s extragradient method [9] and it was proposed by Duong Viet Thong and Dang Van Hieu [9] in 2017. The algorithm is described as follows.

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Algorithm 1A SA-Tseng’s EGM for monotone variational inequality problem Step 1: Choosex0∈H,γ > 0,l∈(0, 1),μ∈(0, 1).

Step 2: Given the current iteratexn, compute

yn=PC(xnλnAxn),

whereλnis chosen to be the largestλ∈ {γ,γl,γl2, . . .}satisfying

λAxnAynμxnyn.

Ifyn=xn, then stop andxnis the solution of the variational inequality problem. Otherwise,

Step 3: Compute the new iteratexn+1via the following iterate formula:

xn+1=ynλn(AynAxn).

Setn:=n+ 1 and return to Step 2.

∅, the sequences{xn}generated by (5), (6), (8) and Algorithm1all converge weakly to an

element ofVI(C,A). For Algorithm1, it does not require to know the Lipschitz constant, but the step size may involve computation of additional projections.

In 2016, Mainge and Gobinddass [10] gotxn+1by the following algorithm:

⎧ ⎨ ⎩

yn=xn+θn(xnxn–1),

xn+1=PC(xnλnAyn),

(9)

whereθn=δλλnn–1,λnknεδ( √

2 – 1),λnkλn–1(δ+λλnn–1–2) 1

2,{λn} ⊂[μ,ν] and

kn:= ⎧ ⎨ ⎩

AynAyn–1

ynyn–1 , ifynyn–1= 0, 0, ifynyn–1= 0.

In this iterative algorithm, it does not require either additional projection for the determi-nation of the step-sizes or the knowledge of the Lipschitz constant of the operator.

The fixed point problem is the problem to findx∗∈Hsuch that

Tx∗=x∗, (10)

where x∗ is called a fixed point ofT :HH. The set of fixed points ofT is denoted byFix(T). Recently, many iterative methods have been proposed (see [6,11–21] and the references therein) for finding a common element ofFix(T) andVI(C,A) in a real Hilbert space.

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point problem of a quasi-nonexpansive mapping with a demiclosedness property in a real Hilbert space. Then the weak convergence theorem will be proved in Sect.3.

This paper is organized as follows. In Sect.2, we list some lemmas which will be used for further proof. In Sect.3, we proposed a new algorithm, then the weak convergence the-orem is analyzed. In Sect.4, we give some numerical examples to illustrate the efficiency and advantage of our algorithm.

2 Preliminaries

In this section, we introduce some lemmas which will be used in this paper. AssumeHis a real Hilbert space andCis a nonempty closed convex subset ofH. In the following of the paper, we use the symbolxnxto denote the strong convergence of the sequence{xn}to

xasn→ ∞and use the symbolxnxto denote the weak convergence of the sequence

{xn}toxasn→ ∞. If there exists a subsequence{xni}of{xn}converging weakly to a point z, thenzis called a weak cluster point of{xn}and the set of all weak cluster points of{xn}

is denoted byωw(xn).

Lemma 2.1([22]) Let H be a real Hilbert space,for each x,yH andλ∈R,we have

(i) x+y2=x2+y2+ 2x,y;

(ii) λx+ (1 –λ)y2=λx2+ (1 –λ)y2λ(1 –λ)xy2.

In the following, we gather some characteristic properties ofPC.

Lemma 2.2([23]) Let H be a real Hilbert space and C be a nonempty closed subset of H.

Then

(i) PCxPCy2≤ xy,PCxPCy,∀x,yH;

(ii) xPCx2+yPCx2xy2,xH,yC.

Lemma 2.3 Let H be a real Hilbert space and C be a nonempty closed subset of H.Given xH and zC,then z=PCx if and only if there hold the inequalityxz,yz ≤0, ∀yC.

Next, we present some concepts of an operator.

Definition 2.4([24]) An operatorA:HHis said to be: (i) monotone, if

xy,AxAy ≥0, ∀x,yH;

(ii) L-Lipschitz continuous withL> 0, if

AxAyLxy, ∀x,yH;

(iii) nonexpansive, if

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(iv) quasi-nonexpansive, if

Axpxp, ∀xH,pFix(A),

whereFix(A)=∅.

Remark2.5 ([25]) It is well that every nonexpansive mapping with a nonempty set of fixed point is quasi-nonexpansive. However, a quasi-nonexpansive mapping may not be a non-expansive mapping.

Lemma 2.6([23]) Assume that T:HH is a nonlinear operator withFix(T)=∅.Then IT is said to be demiclosed at zero if for any{xn}in H,the following implication holds:

xnx and (IT)xn→0⇒x∈Fix(T).

Remark2.7 We know that the Lemma2.6is clearly established when the operatorT is nonexpansive. However, there exists a quasi-nonexpansive mapping T butIT is not demiclosed at zero. Therefore, in this paper, we need to emphasize thatT :HHis a quasi-nonexpansive mapping such thatITis demiclosed at zero.

Example1 LetHbe the line real andC= [0,32]. Define the operatorTonCby

Tx=

⎧ ⎨ ⎩ x

2, ifx∈[0, 1],

xcos2πx, ifx∈(1,32].

Indeed, it is easy to see thatFix(T) ={0}. On the one hand, for anyx∈[0, 1], we have

|Tx– 0|=x 2– 0

≤ |x– 0|.

On the other hand, for anyx∈(1,32], we have

|Tx– 0|=|xcos2πx– 0|=|xcos2πx– 0| ≤ |x|=|x– 0|.

Thus, the operatorTis quasi-nonexpansive.

By taking{xn} ⊂(1,32] andxn→1 asn→ ∞, we have

(IT)xn=|xnTxn|=|xnxncos2πxn|=|xn| · |1 –cos2πxn| →0 (n→ ∞).

But 1 /∈Fix(T), soIT is not demiclosed at zero.

Lemma 2.8([7]) Let{ϕn},{δn}and{αn}be sequences in[0, +∞)such that

ϕn+1≤ϕn+αn(ϕnϕn–1) +δn, ∀n≥1,

+∞

n=1

δn< +∞,

(7)

(i) +n=1∞[ϕnϕn–1]+< +∞,where[t]+:=max{t, 0};

(ii) there existsϕ∗∈[0, +∞)such thatlimn+ϕn=ϕ∗.

Lemma 2.9([26]) Let A:HH be a monotone and L-Lipschitz continuous mapping on C.Let S=PC(IμA),whereμ> 0.If{xn}is a sequence in H satisfying xnq and xnSxn→0,then qVI(C,A) =Fix(S).

Lemma 2.10([27]) Let C be a nonempty closed and convex subset of a real Hilbert space H and{xn}be a sequence in H.The following two properties hold:

(i) limn→∞xnxexists for eachxC;

(ii) ωw(xn)⊂C.

Then the sequence{xn}converges weakly to a point in C.

3 Main results

In this section, we propose a new iterative algorithm with self-adaptive method for solving monotone variational inequality problems and quasi-nonexpansive fixed point problems in a Hilbert space. Meanwhile, we combine subgradient extragradient method and inertial modification for the algorithm. Under the assumptionFix(T)∩VI(C,A)=∅, we prove the weak convergence theorem. LetHbe a real Hilbert space. LetCbe a nonempty closed convex subset inH. LetA:HHbe a monotone andL-Lipschitz continuous operator. In particular, the information of the Lipschitz constantLdoes not require to be known. LetT:HHbe a quasi-nonexpansive mapping such thatIT is demiclosed at zero. The algorithm is described as follows.

Before giving the theorem and its proof, we propose several useful lemmas firstly.

Lemma 3.1 The sequence{λn}generated by Algorithm2is a monotonically decreasing sequence,and its lower bound ismin{μL,λ0}.

Proof It is obvious that the sequence{λn}is a monotonically decreasing sequence.

SinceAisL-Lipschitz continuous withL> 0, we have

AxnAynLxnyn.

In the case ofAxnAyn= 0, we have

μxnyn

AxnAyn

μ

L.

Clearly, the lower bound of the sequence{λn}ismin{μL,λ0}.

Lemma 3.2 If wn=yn=xn+1,then wn∈Fix(T)∩VI(C,A).

Proof Ifwn=yn, we havewnVI(C,A).

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Algorithm 2A ISA-SEGM for monotone variational inequality problem Step 1: Choosex0,x1∈H,μ∈(0, 1),λ0> 0.

Step 2: Setwn=xn+αn(xnxn–1), compute

yn=PC(wnλnAwn).

Step 3: Compute

zn=PTn(wnλnAyn),

whereTn={xH|wnλnAwnyn,xyn ≤0}.

Step 4: Compute

xn+1= (1 –βn)wn+βnTzn

and

λn+1:=

⎧ ⎨ ⎩

min{ μxnyn

AxnAyn,λn}, ifAxnAyn= 0,

λn, otherwise.

Ifwn=yn=xn+1, thenwn∈Fix(T)∩VI(C,A).

Setn:=n+ 1 and return to Step 2.

On the other hand, ifwn=yn=xn+1, byxn+1= (1 –βn)wn+βnTzn, we have

wn= (1 –βn)wn+βnTwn,

through deformation, we can getTwn=wn, which meanswn∈Fix(T).

Therefore,wn∈Fix(T)∩VI(C,A).

Lemma 3.3 Let{zn}be a sequence generated by Algorithm2,then,for all pVI(C,A),and for n sufficiently large,we have

znp2≤ wnp2– (1 –μγ)ynwn2

– (1 –μγ)znyn2– 2λnAp,ynp. (11)

Proof SincepVI(C,A) andVI(C,A)⊂CTn, we have

znp2=PTn(wnλnAyn) –p

2

PTn(wnλnAyn) –PTnp,wnλnAynp

=znp,wnλnAynp

= 1

2znp

2+1

2wnλnAynp

21

2znwn+λnAyn

2

= 1

2znp

2+1

2wnp

2+1

2λ

2

(9)

wnp,λnAyn–1

2znwn

21

2λ

2

nAyn2

znwn,λnAyn

= 1

2znp

2+1

2wnp

21

2znwn

2z

np,λnAyn.

It implies that

znp2≤ wnp2–znwn2– 2znp,λnAyn.

Because the operatorAis monotone andλn> 0, we have

2λnAynAp,ynp ≥0.

So

znp2≤ wnp2–znwn2– 2znp,λnAyn

+ 2λnAynAp,ynp

=wnp2–znwn2+ 2λn

AynAp,ynp

znp,Ayn

=wnp2–znwn2+ 2λn

Ayn,ynpAp,ynp

znp,Ayn

=wnp2–znwn2+ 2λn

Ayn,ynznAp,ynp

=wnp2–znwn2+ 2λnAynAwn,ynzn

+ 2λnAwn,ynzn– 2λnAp,ynp.

Since{λn}is a monotonically decreasing sequence, the limit of{λn}exists andλλnn+1≥1. We denoteλ=limn→∞λn. Therefore, we havelimn→∞=λλnn+1= 1. We haveμ∈(0, 1),

1

μ>

1, letγ=1+ 1

μ

2 , 1 <γ < 1

μ. Therefore,∃N∈N,∀n>N, λn

λn+1<γ. Therefore, 1 –μγ < 1.

2λnAynAwn,ynzn ≤2λnynzn · AynAwn

≤2λnynzn ·

μ λn+1

ynwn

≤2μγynzn · ynwn

μγynzn2+μγynwn2.

SinceznTn, we have

wnλnAwnyn,znyn ≤0.

So

2λnAwn,ynzn ≤2ynwn,znyn

(10)

Therefore

znp2≤ wnp2–znwn2+ 2λnAynAwn,ynzn

+ 2λnAwn,ynzn– 2λnAp,ynp

wnp2–znwn2+μγynzn2+μγynwn2

+znwn2–ynwn2–znyn2– 2λnAp,ynp

=wnp2– (1 –μγ)ynwn2– (1 –μγ)znyn2

– 2λnAp,ynp.

Theorem 3.4 Assume that the sequence{αn}is non-decreasing such that0≤αnα≤14 and the sequence{βn}is a sequence of real numbers such that0 <ββn≤ 12.Then the sequence{xn}generated by Algorithm2converges weakly to an element ofFix(T)∩VI(C,A).

Proof Letp∈Fix(T)∩VI(C,A).

From Lemma3.3, we have∃N≥0,∀n>N,znpwnp.

SinceTis quasi-nonexpansive, by Lemma2.1, we have∀n>N

xn+1–p2=(1 –βn)wn+βnTznp2

=(1 –βn)(wnp) +βn(Tznp)

2

= (1 –βn)wnp2+βnTznp2–βn(1 –βn)Tznwn2

≤(1 –βn)wnp2+βnznp2–βn(1 –βn)Tznwn2

≤(1 –βn)wnp2+βnwnp2–βn(1 –βn)Tznwn2

=wnp2–βn(1 –βn)Tznwn2. (12)

Sincexn+1= (1 –βn)wn+βnTzn, we can write it as

Tznwn= 1 βn

(xn+1–wn). (13)

Combining (12) and (13), withβn≤12, we have

xn+1–p2≤ wnp2–

1 –βn

βn

xn+1–wn2

wnp2–xn+1–wn2. (14)

Besides,

wnp2=xn+αn(xnxn–1) –p 2

=(1 +αn)(xnp) –αn(xn–1–p)2

= (1 +αn)xnp2–αnxn–1–p2

(11)

and

xn+1–wn2 =xn+1–

xn+αn(xnxn–1)2

=xn+1–xn2+αn2xnxn–12– 2αnxn+1–xn,xnxn–1

xn+1–xn2+αn2xnxn–12

– 2αnxn+1–xn · xnxn–1

xn+1–xn2+αn2xnxn–12–αnxn+1–xn2

αnxnxn–12

= (1 –αn)xn+1–xn2+

αn2–αn

xnxn–12. (16)

Combining (14), (15), (16), and{αn}being non-decreasing, we obtain

xn+1–p2≤(1 +αn)xnp2–αnxn–1–p2+αn(1 +αn)xnxn–12

– (1 –αn)xn+1–xn2–

α2nαn

xnxn–12

= (1 +αn)xnp2–αnxn–1–p2– (1 –αn)xn+1–xn2

+αn(1 +αn) –

αn2–αn

xnxn–12

= (1 +αn)xnp2–αnxn–1–p2– (1 –αn)xn+1–xn2

+ 2αnxnxn–12

≤(1 +αn+1)xnp2–αnxn–1–p2– (1 –αn)xn+1–xn2

+ 2αnxnxn–12. (17)

Therefore,

xn+1–p2–αn+1xnp2+ 2αn+1xn+1–xn2

xnp2–αnxn–1–p2+ 2αnxnxn–12

+ 2αn+1xn+1–xn2– (1 –αn)xn+1–xn2

=xnp2–αnxn–1–p2+ 2αnxnxn–12

+ (2αn+1– 1 +αn)xn+1–xn2. (18)

PutΓn:=xnp2–αnxn–1–p2+ 2αnxnxn–12.

From (18), we obtain

Γn+1–Γn≤(2αn+1– 1 +αn)xn+1–xn2. (19)

We have 0≤αnα≤14, –(2αn+1– 1 +αn)≥14.

SoΓn+1–Γn≤–δxn+1–xn2≤0, whereδ=14, which implies that the sequence{Γn}is

(12)

Besides,

Γn=xnp2–αnxn–1–p2+ 2αnxnxn–12

xnp2–αnxn–1–p2 (20)

and

Γn+1 =xn+1–p2–αn+1xnp2+ 2αn+1xn+1–xn2

≥–αn+1xnp2. (21)

Therefore,

xnp2≤αnxn–1–p2+Γn

αxn–1–p2+Γ1

≤. . .

αnx0–p2+

1 +· · ·+αn–1Γ1

αnx0–p2+

Γ1

1 –α. (22)

This implies that the sequence{xn}is bounded. Combining (21) and (22), we have

Γn+1≤αn+1xnp2

αxnp2

αn+1x0–p2+

αΓ1

1 –α. (23)

From (19), we have

δ

k

n=1

xn+1–xn2≤Γ1–Γk+1

Γ1+αk+1x0–p2+

αΓ1

1 –α

=αk+1x0–p2+

Γ1

1 –α

x0–p2+

Γ1

1 –α, (24)

which means

n=1

xn+1–xn2< +∞ (25)

and

lim

(13)

Besides, sinceαnα, we have

xn+1–wn=xn+1–xnαn(xnxn–1)

xn+1–xn+αnxnxn–1

xn+1–xn+αxnxn–1. (27)

Therefore, by (26) and (27), we can obtain

xn+1–wn →0 (n→ ∞). (28)

We have

xn+1–p2≤(1 +αn)xnp2–αnxn–1–p2– (1 –αn)xn+1–xn2

+ 2αnxnxn–12

≤(1 +αn)xnp2–αnxn–1–p2+ 2αnxnxn–12. (29)

Therefore, by (29) and Lemma2.8, we have

lim

n→∞xnp

2=l (30)

by (15), we have

lim

n→∞wnp

2=l (31)

and we also have

lim

n→∞xnwn

2= 0. (32)

We have

xn+1–p2≤(1 –βn)wnp2+βnznp2–βn(1 –βn)Tznwn2

≤(1 –βn)wnp2+βnznp2,

which means

znp2≥

xn+1–p2–wnp2

βn

+wnp2. (33)

Combining (30), (31) and (33), the sequence{βn}being bounded, we have

lim inf

n→∞ znp

2 lim

n→∞wnp

2=l.

By (11), we have

lim sup

n→∞

znp2≤ lim

n→∞wnp

(14)

Therefore, we have

lim

n→∞znp

2=l. (34)

From Lemma3.3, we can obtain∀n>N

znp2≤ wnp2– (1 –μγ)ynwn2

and

znp2≤ wnp2– (1 –μγ)znyn2.

By (31) and (34), we have

lim

n→∞ynwn= 0 (35)

and

lim

n→∞znyn= 0. (36)

So

lim

n→∞znwnnlim→∞

znyn+ynwn= 0,

which implies

lim

n→∞znwn= 0. (37)

Therefore, by (12), (30) and (31), we have

lim

n→∞Tznwn= 0. (38)

So

lim

n→∞Tznznlim→∞

Tznwn+wnzn= 0,

which implies

lim

n→∞Tznzn= 0. (39)

Since {xn} is bounded, there exist a subsequence{xnk} of {xn} andqH such that

xnkq.

So, by (32) we haveωnkqand by (37) we haveznkq.

Sinceznk qandITis demiclosed at zero, by Lemma2.6, we haveq∈Fix(T).

On the other hand, for alln∈R, we haveλn>μL. We haveωnkqand

(15)

By Lemma2.9, we haveqVI(C,A). Therefore,q∈Fix(T)∩VI(C,A).

By Lemma2.10, we get the conclusion that the sequence{xn}converges weakly to an element ofFix(T)∩VI(C,A).

This completes the proof.

4 Numerical experiments

In this section, we give some numerical examples to illustrate the efficiency and advantage of our algorithm in comparisons with the well-known algorithm. We compare Algorithm2

with the weakly convergent Algorithm1[19].

We chooseαn=14,βn=12,μ=12,λ0=17. The starting point isx0=x1= (1, 1, . . . , 1)∈Rm.

In order to show the converges of the algorithm, we illustrate the behavior of the sequence

Dn=xnx∗2,n= 0, 1, 2, . . . , when the execution time in second elapses wherexis the

solution of the problem and{xn}is the sequence generated by the algorithms. Now we

introduce the examples in detail.

Example2 LetAbe a Lipschitz continuous and monotone mapping. LetT be a quasi-nonexpansive mapping. AssumeFix(T)∩VI(C,A)=∅andC= [–2, 5],H=R. LetAand

T be given by

Ax:=x+sinx,

Tx:=x 2sinx.

In the following, let us verify ifAandTmeet the requirements of the topic. First, for allx,yH, we have

AxAy=x+sinxy–sinyxy+sinx–siny ≤2xy,

AxAy,xy= (x+sinxy–siny)(xy) = (xy)2+ (sinx–siny)(xy)≥0.

Therefore,AxAyLxy, whereL= 2 andAxAy,xy ≥0. Therefore,Ais

L-Lipschitz continuous and monotone.

Second, forTx=x2sinx, ifx= 0 andTx=x, then we havex=x2sinx, andsinx= 2, which is impossible. Therefore, we obtainx= 0, which meansFix(T) ={0}.

For allxH,

Tx– 0=x 2sinx

x

2

<x=x– 0,

which meansTis quasi-nonexpansive. Besides, takex= 2πandy=32π, we have

TxTy=2π

2 sin2π– 3π

4 sin 3π

2

=3π

4 >

2π–3π 2

=π

2,

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[image:16.595.119.478.78.354.2]

Figure 1Experiment for Example2

Therefore,AandT meet the requirements of the topic. The numerical results for the example are shown in Fig.1.

From Fig.1, we can see that the Algorithm2converges for a shorter time than the pre-viously studied Algorithm1[19].

Example3 We consider the operatorT :HH withTx= –12xand a linear operator

A:Rm→Rmin the formA(x) =Mx+q[28,29], where

M=NNT+S+D,

Nis am×mmatrix,Sis am×mskew-symmetric matrix,Dis am×mdiagonal matrix which its diagonal entries are nonnegative, andq∈Rmis a vector, thereforeMis positive definite. The feasible set is

C=x= (x1, . . . ,xm∈Rm

: –2≤xi≤5,i= 1, 2, . . . ,m}.

It is obvious thatAis monotone and Lipschitz continuous. For experiments,qis equal to zero vector, all the entries ofN,Sare generated randomly and uniformly in [–2, 2], and the diagonal entries ofDare in (0, 2).

We can easily see that the solution of the algorithm in this case isx∗= 0. In order to illustrate the effectiveness of the algorithm, we show the behavior ofDnwhen execution time elapses(in second) by Figs.2,3,4inR20,R50,R100respectively.

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[image:17.595.115.482.81.707.2]

Figure 2Experiment withm= 20 for Example3

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[image:18.595.118.478.79.336.2]

Figure 4Experiment withm= 100 for Example3

5 Conclusion

In this paper, we introduce a new algorithm with self-adaptive method for finding a so-lution of the variational inequality problem involving monotone operator and the fixed point problem of a quasi-nonexpansive mapping with a demiclosedness property in a real Hilbert space. We combine a subgradient extragradient method and inertial modification for the algorithm. Under some suitable conditions, we have proved the weak convergence of the algorithm. In particular, it is worth emphasizing that the algorithm that we propose does not need any additional projections of the Lipschitz constant. Finally, some numeri-cal experiments are performed to verify the convergence of the algorithm and compared with previously known Algorithm1[19].

Funding

This work was supported by the Financial Funds for the Central Universities (No. 3122018L004) and Scientific research project of Tianjin Municipal Education Commission (No. 2018KJ253).

Competing interests

The authors declare that they have no competing interests.

Authors’ contributions

All the authors read and approved the final manuscript.

Publisher’s Note

Springer Nature remains neutral with regard to jurisdictional claims in published maps and institutional affiliations. Received: 29 October 2018 Accepted: 3 January 2019

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Figure

Figure 1 Experiment for Example 2
Figure 3 Experiment with m = 50 for Example 3
Figure 4 Experiment with m = 100 for Example 3

References

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