BJT Circuit Configurations
R
LV
cc~
~
~
R
sv
sV
ccv
sR
sR
LR
LV
ccR
sv
sCommon base Common emitter Common collector
BJT Current-Voltage Characteristics
Very small base current (~5-75
μA)
causes much higher collector current (up to 7.5 mA).
The current gain is ~ 100
VCE, V
BJT amplifier circuit analysis: Operating point
Collector current depends on two circuit parameters: the base current and the collector voltage.
At high collector voltage the collector current depends on the base current only.
For Ibase = 40 μA, Icoll = 4 mA for any EC-E greater than 1.5 V RL
BJT amplifier circuit analysis: Operating point
For an arbitrary collector voltage, collector current can be found using the KVL. The KVL for the collector – emitter circuit, VCC = IRL×RL + VCE;
VCE, V CC CE RL L
V
V
I
R
−
=
The RL current depends linearly on the collector voltage VCE Resistor RL and the C-E circuit of BJT are connected in series, henceI
RL= I
CFor Ib = 40 μA and VCC = 13V, the collector current IC = 4 mA For Ib = 75 μA and VCC = 14V, the collector current IC = 4 mA
VCE RL VCC
BJT amplifier gain analysis: 1
1. Input circuit
The input voltage has two components: the DC bias and the AC signal Vin
Time DC bias
AC signal amplitude
DC voltage component biases the base-emitter p-n junction in the forward direction AC component is the input signal to be amplified by the BJT.
BJT amplifier gain analysis: 2
2. Output circuit
The collector current has two components too. IC
Time DC current
AC current amplitude
DC and AC collector currents flow through the BJT in accordance with its I-V characteristics
VCE, V
BJT amplifier gain analysis: 3
The resistance of the B-E junction is very low when V
BE≥ V
BE0≈ V
bi≈ 0.7 V.
Hence the base current I
B≅ (V
in-V
BE0)/R1 = (V
inDC-V
BE0+V
inAC)/R
1The collector current I
Cdoes not depend on the collector voltage if the latter is high
enough.
Hence, I
C≅ β I
B;
The voltage drop across the load resistance R
2: V
2= I
CR
2;
The output voltage V
out= V
CC- V
2= V
CC- I
CR
2;
V
out= V
CC- I
CR
2= V
CC-
β I
BR
2= V
CC-
β R
2(V
inDC-V
BE0+V
inAC)/R
1;
In signal amplifiers only AC component of the output voltage is important:
V
outAC= -
β R
2V
inAC/R
1;
The amplifier voltage gain:
k
V= V
outAC/V
inAC= -
β R
2/R
1;
BJT amplifier gain analysis: 4
Common emitter gain summary:
Current gain: k
I=
β
Voltage gain:
k
V= V
outAC/V
inAC= -
β R
2/R
1;
Power gain: k
P= k
V× k
I=
-
β
2×
R
2/R
1Base resistance and emitter current crowding in BJTs
The voltage drop along the base layer
Vbb = rbb Ib,where rbb is called the base spreading resistance.
1
TH1
V qV V kT S SI
=
I
⎛
⎜
e
− =
⎞
⎟
I
⎛
⎜
⎜
e
−
⎞
⎟
⎟
⎝
⎠
⎝
⎠
The length of the edge region, Δde, where most of the emitter current flows may be estimated from:
The p-n junction current decreases rapidly when the voltage drops by ΔVbb ~ Vth = kT/q max e th b b b b e
d
V
I R
I
t W
ρ
Δ
=
≈
ΔdeEmitter current crowding in BJTs (cont.)
1
b b bqN
ρ
μ
=
From these,
th e th e b b e b b b bV t W
V
d
q N
t W
I
ρ
I
μ
Δ ≈
=
max e th b b b b ed
V
I R
I
t W
ρ
Δ
=
≈
Δdeth e b b e b b
V
d
q N
t W
I
μ
Δ ≈
ExampleEstimate the effective emitter
length, Δd
efor the BJT having
the following parameters:
I
b= 50 μA;
N
b= 10
17cm
-3μ
b= 400 cm
2/V-s
W
b= 0.1 μm
t
e= 100 μm
Δd
e= 3.33 e-4 cm = 3.33 μm
ΔdeBase narrowing (Early effect)
The depletion width of the p-n junction depends on the applied voltage:
(Here W is the depletion region width not the width of the base as in BJT!)
In the BJT, this effect means that the effective width of the base is less than W
b:
W
eff= W
b- X
deb- X
dcbwhere W
bis the physical thickness of the base,
x
deband x
dcbare the depletion region widths from the emitter and collector sides.
The depletion widths are given by (N
e>>N
b):
2
/
1
0
(
)
2
⎥
⎦
⎤
⎢
⎣
⎡
−
=
b
be
bi
deb
N
q
V
V
x
εε
2
/
1
2
0
(
)
2
⎥
⎥
⎦
⎤
⎢
⎢
⎣
⎡
+
=
b
c
cb
bi
dcb
qN
N
V
V
x
εε
x
dcbis usually the most important factor since the voltage applied to collector is
high.
The doping level in collector, N
DChas to be lower than that of the base, N
AB, to
reduce the Early effect:
Due to Early effect the effective base thickness depends on the collector voltage.
In the gain expression, W should be replaced with W
eff:
The Early effect decreases the output resistance, and hence the voltage
gain of BJTs.
2 22
p rec effL
W
β
=
The punch-through breakdown voltage V
pt:
Punchthrough breakdown in BJTs
-- the result of the Early effect
W = x
dcb
(
)
c b c b ptN
N
N
N
W
q
V
=
+
0 22
εε
BJT Model
• Gummel-Poon model used in SPICE and other
simulators
I
e
= I
c
+ I
b
1
c bI
α
I
α
=
−
Hence,
where
α
is called a common base current gain
Ie Ic
Ib
Applying KCL to the BJT terminals:
Collector – emitter current relationship:
c e
I
=
α
I
(
)
c
c
b
I
=
α
I
+
I
c bI
=
β
I
Common emitter current
gain is defined as:
β =
α
1
− α
α =
β
1
+ β
Simplified Gummel-Poon BJT equivalent circuit
• Emitter junction:
exp
1
se be be F F thI
V
I
n V
β
⎡
⎛
⎞
⎤
=
⎢
⎜
⎟
−
⎥
⎝
⎠
⎣
⎦
• Collector junction:
exp
1
sc bc bc R R thI
V
I
n V
β
⎡
⎛
⎞
⎤
=
⎢
⎜
⎟
−
⎥
⎝
⎠
⎣
⎦
α
i
I
c
α
n
I
e
I
c
I
e
Base
Emitter
Ideal diode
Ideal diode
Collector
Leakage diode
Leakage diode
α
i
I
c
α
n
I
e
I
c
I
e
Base
Emitter
Ideal diode
Ideal diode
Collector
Leakage diode
Leakage diode
Gummel-Poon BJT equivalent circuit accounting
for the leakage currents
•Emitter –base leakage
diode
:
_exp
1
be Leak be se E thV
I
I
n V
⎡
⎛
⎞
⎤
=
⎢
⎜
⎟
−
⎥
⎝
⎠
⎣
⎦
Collector –base leakage diode
:_