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BJT Circuit Configurations

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BJT Circuit Configurations

R

L

V

cc

~

~

~

R

s

v

s

V

cc

v

s

R

s

R

L

R

L

V

cc

R

s

v

s

Common base Common emitter Common collector

(2)
(3)

BJT Current-Voltage Characteristics

Very small base current (~5-75

μA)

causes much higher collector current (up to 7.5 mA).

The current gain is ~ 100

(4)

VCE, V

BJT amplifier circuit analysis: Operating point

Collector current depends on two circuit parameters: the base current and the collector voltage.

At high collector voltage the collector current depends on the base current only.

For Ibase = 40 μA, Icoll = 4 mA for any EC-E greater than 1.5 V RL

(5)

BJT amplifier circuit analysis: Operating point

For an arbitrary collector voltage, collector current can be found using the KVL. The KVL for the collector – emitter circuit, VCC = IRL×RL + VCE;

VCE, V CC CE RL L

V

V

I

R

=

The RL current depends linearly on the collector voltage VCE Resistor RL and the C-E circuit of BJT are connected in series, hence

I

RL

= I

C

For Ib = 40 μA and VCC = 13V, the collector current IC = 4 mA For Ib = 75 μA and VCC = 14V, the collector current IC = 4 mA

VCE RL VCC

(6)

BJT amplifier gain analysis: 1

1. Input circuit

The input voltage has two components: the DC bias and the AC signal Vin

Time DC bias

AC signal amplitude

DC voltage component biases the base-emitter p-n junction in the forward direction AC component is the input signal to be amplified by the BJT.

(7)

BJT amplifier gain analysis: 2

2. Output circuit

The collector current has two components too. IC

Time DC current

AC current amplitude

DC and AC collector currents flow through the BJT in accordance with its I-V characteristics

VCE, V

(8)

BJT amplifier gain analysis: 3

The resistance of the B-E junction is very low when V

BE

≥ V

BE0

≈ V

bi

≈ 0.7 V.

Hence the base current I

B

≅ (V

in

-V

BE0

)/R1 = (V

inDC

-V

BE0

+V

inAC

)/R

1

The collector current I

C

does not depend on the collector voltage if the latter is high

enough.

Hence, I

C

≅ β I

B

;

The voltage drop across the load resistance R

2

: V

2

= I

C

R

2

;

The output voltage V

out

= V

CC

- V

2

= V

CC

- I

C

R

2

;

V

out

= V

CC

- I

C

R

2

= V

CC

-

β I

B

R

2

= V

CC

-

β R

2

(V

inDC

-V

BE0

+V

inAC

)/R

1

;

In signal amplifiers only AC component of the output voltage is important:

V

outAC

= -

β R

2

V

inAC

/R

1

;

The amplifier voltage gain:

k

V

= V

outAC

/V

inAC

= -

β R

2

/R

1

;

(9)

BJT amplifier gain analysis: 4

Common emitter gain summary:

Current gain: k

I

=

β

Voltage gain:

k

V

= V

outAC

/V

inAC

= -

β R

2

/R

1

;

Power gain: k

P

= k

V

× k

I

=

-

β

2

×

R

2

/R

1

(10)
(11)

Base resistance and emitter current crowding in BJTs

The voltage drop along the base layer

Vbb = rbb Ib,where rbb is called the base spreading resistance.

1

TH

1

V qV V kT S S

I

=

I

e

− =

I

e

The length of the edge region, Δde, where most of the emitter current flows may be estimated from:

The p-n junction current decreases rapidly when the voltage drops by ΔVbb ~ Vth = kT/q max e th b b b b e

d

V

I R

I

t W

ρ

Δ

=

Δde

(12)

Emitter current crowding in BJTs (cont.)

1

b b b

qN

ρ

μ

=

From these,

th e th e b b e b b b b

V t W

V

d

q N

t W

I

ρ

I

μ

Δ ≈

=

max e th b b b b e

d

V

I R

I

t W

ρ

Δ

=

Δde

(13)

th e b b e b b

V

d

q N

t W

I

μ

Δ ≈

Example

Estimate the effective emitter

length, Δd

e

for the BJT having

the following parameters:

I

b

= 50 μA;

N

b

= 10

17

cm

-3

μ

b

= 400 cm

2

/V-s

W

b

= 0.1 μm

t

e

= 100 μm

Δd

e

= 3.33 e-4 cm = 3.33 μm

Δde

(14)
(15)

Base narrowing (Early effect)

The depletion width of the p-n junction depends on the applied voltage:

(Here W is the depletion region width not the width of the base as in BJT!)

(16)

In the BJT, this effect means that the effective width of the base is less than W

b

:

W

eff

= W

b

- X

deb

- X

dcb

where W

b

is the physical thickness of the base,

x

deb

and x

dcb

are the depletion region widths from the emitter and collector sides.

The depletion widths are given by (N

e

>>N

b

):

2

/

1

0

(

)

2

=

b

be

bi

deb

N

q

V

V

x

εε

2

/

1

2

0

(

)

2

+

=

b

c

cb

bi

dcb

qN

N

V

V

x

εε

x

dcb

is usually the most important factor since the voltage applied to collector is

high.

The doping level in collector, N

DC

has to be lower than that of the base, N

AB

, to

reduce the Early effect:

(17)

Due to Early effect the effective base thickness depends on the collector voltage.

In the gain expression, W should be replaced with W

eff

:

The Early effect decreases the output resistance, and hence the voltage

gain of BJTs.

2 2

2

p rec eff

L

W

β

=

(18)

The punch-through breakdown voltage V

pt

:

Punchthrough breakdown in BJTs

-- the result of the Early effect

W = x

dcb

(

)

c b c b pt

N

N

N

N

W

q

V

=

+

0 2

2

εε

(19)

BJT Model

• Gummel-Poon model used in SPICE and other

simulators

I

e

= I

c

+ I

b

1

c b

I

α

I

α

=

Hence,

where

α

is called a common base current gain

Ie Ic

Ib

Applying KCL to the BJT terminals:

Collector – emitter current relationship:

c e

I

=

α

I

(

)

c

c

b

I

=

α

I

+

I

c b

I

=

β

I

Common emitter current

gain is defined as:

β =

α

1

− α

α =

β

1

+ β

(20)

Simplified Gummel-Poon BJT equivalent circuit

• Emitter junction:

exp

1

se be be F F th

I

V

I

n V

β

=

• Collector junction:

exp

1

sc bc bc R R th

I

V

I

n V

β

=

α

i

I

c

α

n

I

e

I

c

I

e

Base

Emitter

Ideal diode

Ideal diode

Collector

Leakage diode

Leakage diode

(21)

α

i

I

c

α

n

I

e

I

c

I

e

Base

Emitter

Ideal diode

Ideal diode

Collector

Leakage diode

Leakage diode

Gummel-Poon BJT equivalent circuit accounting

for the leakage currents

•Emitter –base leakage

diode

:

_

exp

1

be Leak be se E th

V

I

I

n V

=

Collector –base leakage diode

:

_

exp

1

bc Leak bc sc C th

V

I

I

n V

=

References

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